Match each physical property of matter to the appropriate definition
conductivity
density
buoyant force
solubility
boiling point

Formula: s = d/t

s = speed

d = distance

t = time

Solve using the values we are given.

s = 300/40

s = 7.5m/s

Best of Luck!

Answer:

7.5 m/s

Explanation:

um the answer is A

np :3 i hope this is right

At this point in the story, Beasy has driven his car (2+6+4) = 12 km.

He is parked at the thrift store, (2+4) = 6 km East and 6 km North of his starting point.

As the crow flies, the thrift store is √(6km² + 6km²) in a straight line from the starting point.

That's √(72 km²) , which works out to 8.485 km .  When rounded to the nearest whole km, he can phone up his wife and tell her he's "eight kilometers from home can you hear me now ?".

Displacement is a vector, so to answer the question completely, we also need to state its direction.

The angle from home to the thrift store, relative to East, is arctan(6km/6km).

That's 45 degrees.  

The full displacement vector is 8.485 km Northeast.

From the question, Beasy drives 2km East and 6 km North. He then drives 4 km East of the first errand. An illustrative diagram is shown in the attachment below.

From the diagram S is the starting starting point, C is coffee shop and T is the thrift store.

The displacement of the car from the starting point is giving by /TS/ in the diagram. To calculate /TS/, consider the right-angled triangle TSQ, /TS/ is the hypotenuse.

From The Pythagorean theorem, in a right-angled triangle, the square of the longest side (hypotenuse) equals sum of the squares of the other two sides.

That is,

/TS/² = /SQ/² + /TQ/²

But /TQ/ = /CP/ = 6km

and /SQ/ = /SP/ + /PQ/

/SP/ = 2 km, /PQ/ = 4 km

∴ /SQ/ = 2 km + 4 km

/SQ/ = 6 km

Hence,

/TS/² = 6² + 6²

/TS/² = 36 + 36

/TS/² = 72

/TS/ = [tex]\sqrt{72}[/tex]

/TS/ = 8.485 km

/TS/ ≅ 8 km ( to the nearest km)

Hence, the displacement of the car from the starting point rounded to the nearest km is 8 km.

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Answer:

Ideal machines are said to have parts which are weightless , frictionless and strings if any are inextensible. Practical machines have parts which have weights, friction and it causes some loss of work done.

Explanation:

Answer: Ideal machines are said to have parts which are weightless , frictionless and strings if any are inextensible. Practical machines have parts which have weights, friction and it causes some loss of work done.



Explanation:

Explanation:

Assume that the rock has a constant density,

then the density = volume/mass = 0.25g/cm^3.

Answer:

4 g/cm^3

Explanation:

Density can be found by dividing the mass by the volume.

d=m/v

We know that the mass of the rock is 24 gram. We also know the volume of the rock is 6 cubic centimeters.

m=24 g

v= 6 cm^3

Substitute the values into the formula and divide.

d= 24 g / 6 cm^3

d= 4 g/cm^3

The density of the rock is 4 grams per cubic centimeter.

Answer: A Cytosol

Explanation: Jelly - like fluid that fills the space between cell organelles. Hoped This Helped :) Have a blessed day.

The cytoskeleton, which gives a cell its structure, allows organelles to move inside the cell, and provides a method by which the cell itself can move, is an ordered framework of fibrous molecules found in the cytoplasm. Thus, option A is correct.

The fluid that fills cells is called cytosol. In this water-based solution, organelles, proteins, and other cell components float. Any cell's cytosol is a sophisticated solution whose characteristics allow for the performance of life's essential processes.

The cytoplasm houses all the organelles found in eukaryotic cells, including the nucleus, endoplasmic reticulum, and mitochondria.The portion of the cytoplasm that is not contained in an organelle is known as the cytosol.

Therefore, Although the cytoplasm may not seem to have any shape or organization, it is actually quite well-organized.

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Answer:

Atoms are single neutral particles.

example: Ne, O

Molecules are neutral particles made of two or more atoms bonded together.

example:O2,HCl

Answer:

Atoms are single particles while molecules are particles made of two or more atoms bonded together.

Explanation:

My answer to the question is Velocity.

Answer:

1:25

Explanation:

The force acting on an object is given by :

F = ma ...(1)

m is mass and a is acceleration

It is given that the ratio of force acting on the bus and car 25:1 i.e. [tex]\dfrac{F_1}{F_2}=\dfrac{25}{1}[/tex], 1 is for bus and 2 is for car.

We need to find the ratio of the acceleration produced in the car to the acceleration produced in the bus. From equation (1),

[tex]\dfrac{F_1}{F_2}=\dfrac{a_1}{a_2}[/tex]

[tex]\dfrac{a_2}{a_1}=?[/tex]

[tex]\dfrac{F_1}{F_2}=\dfrac{1}{25}[/tex]

So, the ratio is 1:25.

The average acceleration of the motorcycle is determined as 3 m/s².

The acceleration of the motorcycle is calculated as follows;

a = (v - u)/t

where;

a = (15 - 6)/3

a = 3 m/s²

Thus, the average acceleration of the motorcycle is determined as 3 m/s².

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Answer:

The train stopped for 3 seconds.

Explanation:

D on edge

Answer:

the body has descended a height (4a)

Explanation:

This exercise should use the acceleration given in the graph, but unfortunately the graph is not loaded, but we can build it, using the law of universal gravitation and the fact that you indicate that the movement is near the surface of the planet

           F = m a

f

orce is gravitational force

           G M m / r² = m a

           a = G M / r²

where G is the universal constant of gravitation, M the mass planet and r the distance from the center of the planet of radius R to the body, if we measure the height of the body from the surface of the planet (y), we can write

           r = R + y

for which

           a = G M/R²     (1+ y/R)⁻²

if we use y«R we can expand the function in series

           a = (G M /R²)   (1 -2 y/R - 2 (-2-1) /2!   y² / R² +…)

as the height is small we can neglect the quadratic term and in many cases even the linear term, for this exercise we will remain only constant therefore the acceleration is constant

           a = G M / R²

from this moment we can use the relations of motion with constant acceleration for the exercise

a) they ask us for the position for t = 2s

            y = y₀ + v₀ t - a t²

as the body is released v₀ = 0

            y-y₀ = - a t²

            y-y₀ = - a 2²

             y-y₀ = - a 4

therefore  

therefore the body has descended a height (4a) where a is the acceleration of the planet's gravity

Answer: A they can travel at the speed of light

Explanation: A on EDGE

Answer:

a

Explanation:

got 100

Answer:

E = 27 J

Explanation:

It is given that,

Mass of a kitten is 1.5 kg

Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.

We need to find the kitten's gravitational  potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :

[tex]E=mgh[/tex]

g is acceleration due to gravity

[tex]E=1.5\ kg\times 10\ m/s^2\times 1.8\ m\\E=27\ J[/tex]

So, the kitten's gravitational  potential energy on top of the counter is 27 J.

Answer:

20.7 cm³

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 5 °C

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 30 °C

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

Next we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

Temperature (K) = Temperature (°C) + 273

Initial temperature (T1) = 5 °C

Initial temperature (T1) = 5 °C + 273 = 278 K.

Final temperature (T2) = 30 °C

Final temperature (T2) = 30 °C + 273 = 303 K.

Finally, we shall determine the new volume of the gas as follow:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 278 K

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 303 K

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

P1V1/T1 = P2V2/T2

760 × 20 /278 = 800 × V2/303

Cross multiply

278 × 800 × V2 = 760 × 20 × 303

Divide both side by 278 × 800

V2 = (760 × 20 × 303) / (278 × 800)

V2 = 20.7 cm³

Therefore, the new volume of the gas is 20.7 cm³

Answer:

180

Explanation:

4m/s x 45s=180m

Answer:

a. DNA storage

Explanation:

Answer:

very complex

Explanation:

The answer is D very complex

Answer:

The astronauts will simply have to fire the rocket engines again to keep moving. The spacecraft will keep coasting at the same speed and in the same direction. The spacecraft will slow down until it comes to a complete stop. ... Its speed will be constant except for very slow changes that are part of its orbital motion.

Explanation:

Explanation:

Given that,

The x-component is 8 m/s east and y-component is 14.5 m/s North.

(a) As both x and y components are perpendicular to each other. Their resultant is given by :

[tex]R=\sqrt{x^2+y^2} \\\\R=\sqrt{(8)^2+(14.5)^2} \\\\R=16.56\ m/s[/tex]

(b) Let [tex]\theta[/tex] is the resultant vector. So,

[tex]\tan\theta=\dfrac{y}{x}\\\\\theta=\tan^{-1}(\dfrac{y}{x})\\\\\theta=\tan^{-1}(\dfrac{14.5}{8})\\\\\theta=61.11^{\circ}[/tex]

Hence, the resultant is 16.56 m/s and the angle of the resultant vector is 61.11 degrees.

Answer:

13.069 g/cm^3

Explanation:

to get density, simply divide the mass by the volume. Your equation would look like this; p=562/43

'P' represents density in this equation. Never forget to add your units!

Hope this helps!

Answer:

Explanation:

In this problem, we are going to solve for the average speed and average velocity for the entrire trip made by the dolphin.

Given data

speed v= 2 m/s

time t= 24s

the distance travelled by the dolphin is

speed= distance/time

distance= speed*time

distance= 2*24

distance= 48m

now the dolpine made a reverse and covered this 48m in 8s to return to it initial position

the speed it took is

speed= distance/time

speed= 48/8

speed= 6m/s

It average speed is the total distance divided by the total time taken

average speed= (48+48)/(24+8)= 96/32= 3m/s

average speed= 3 m/s

it average velocity is the sum of the initial and final velocity is divided by 2 to find the average

(2+6)/2= 8/2= 4m/s

average velocity is 4m/s

Answer: Because a compound is formed by at least two elements, and here we have only one.

Explanation:

A compound is defined as:

"A substance that is formed when two or more elements are chemical bonded together"

And in this case, we have two hydrogen atoms bonded together, so we have the bond, but there is only one element, and we need to have at least two elements to have a compound.

Two hydrogen atoms bonded together are not considered a compound.

A compound is formed when two are more different elements form a chemical bond with each other and make a substance.

For any substance to be categorized as a compound it is necessary that it contains at least two different elements.

A substance that is formed by the chemical combination or bonding of the atoms of the same element is not considered a compound.

In the given case we have two hydrogen atoms bonded together, which is very clear that the substance contains the atoms of the same element bonded together.

Therefore it can not be considered a compound.

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Answer:

The mass of a single paper  is approximately 0.047 lb/paper which in SI Units is approximately 21.77  g/paper

Explanation:

The given information on the size and the weight of paper are;

The mass of a box of 500 sheets of paper = 24 lb

The number of sheets in the paper = 500 sheets

The dimensions of the paper = 17 in. × 22 in., which is equivalent to  43.18 cm × 55.88 cm

The mass of a single paper = The mass of the box of paper/(The number of sheets of paper present in the box)

The mass of a single paper = 24 lb/500 = 0.047 lb/paper

Given that 1 lb = 453.6 g, we have;

0.047 lb/paper = 0.047 lb/paper×453.6 g/(lb) = 21.77  g/paper

The mass of a single paper  = 0.047 lb/paper = 21.77  g/paper.

Answer:

5.349g

Explanation:

The other post forgot about the differing answer. They wanted the answer for 21.59cm*27.94cm. when they get that 0.047=43.18cm*55.88cm we can set a ratio;

0.047/43.18*55.88=X/21.59*27.94=0.01179

then we do the same;

0.01179lb(453.6g/1lb)=5.349

(*the number is bigger but we have 4 sig figs*)

Answer:

Omnidirectional antennas are inadvisable to be used because when oriented vertically they radiate radio power equally in all horizontal directions, but heir radio power varies with the angle to the axis, reducing to zero at the axis.

Explanation:

Omnidirectional antennas radiates equal radio power in all directions perpendicular to an axis, with power varying with the elevation angle. This means that their power declines to zero on the axis. This is unlike the isotropic antennas that radiates equal power in all directions, without any reduction in radio power with angle to the axis. Omnidirectional antennas are mostly used for radio broadcasting antennas in mobile devices that use radio such as cell phones, FM radios, walkie-talkies, wireless computer networks etc.