Answers
Answer:
I can only see one graph in that screenshot, so I graphed all of them. The one on your screenshot was B.
Related Questions
Order the quotients of these expressions from least to greatest.
42.6 ÷ 70
42.6 ÷ 0.7
426 ÷ 70
42.6 ÷ 0.07
Answers
3rd Problem = 6.0857
2nd Problem = 60.8571
4th Problem = 608.5714 (greatest)
c. Divide 45 into three parts which are in A.P. Such that the pr oduct of last two is 300.
Answers
⟹3a=45
a=15
a(a+b)=300
⟹15(15+b)=300
⟹225+15b=300
⟹15b=300−225
⟹15b15=7515
b=5
a−b=10⟹a=15⟹a+b=20
The three numbers are 10, 15, and 20.
Proof:
10+15+20=45✓
Barn Yard Inc. is a wholesaler that stocks engine components and tests equipment for the commercial aircraft industry. A new customer has placed an order for eight high-bypass turbine engines, which increase fuel economy. The variable cost is $1.6 million per unit, and the credit price is $1.725 million each. Credit is extended for one period, and based on historical experience, payment for about one out of every 200 such orders is never collected. The required return is 1.8% per period.Suppose that customers who don’t default become repeat customers and place the same order every period forever. Further assume that repeat customers never default.
Answers
The NPV is positive, therefore, this order can be placed.
How to calculate the NPV?The calculation of probability of default will be:
= 1 / 200 = 0.005
We use NPV formula to find out whether the order should be filled or not
NPV = -Variable cost per unit +[(1-π)(price of equipment/1+percentage of return)]
= -$1.6 million +[(1-0.005)($1.725m/1.018)]
= -$1.6m + $1.6860
= 0.0860 million
As NPV is positive this order can be placed.
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Problem
A [tex]prime\left trio[/tex] is a collection of three prime numbers [tex]\{p, q, r\}[/tex] in arithmetic progression, with common difference [tex]q-p=r-q[/tex]. For example, the prime trio [tex]\{3, 5, 7\}[/tex] has common difference 2.
Prove that there is no prime trio with common difference 70.
P.S. I want actual proof.
Answers
Answer:
Proof below
Step-by-step explanation:
General outlineLemma regarding remainders of non-small primes divided by 6Check [tex]p=2[/tex] and [tex]p=3[/tex] directlyProof the rest by contradictionLemmaIf [tex]p[/tex] is prime such that [tex]p \neq2[/tex] and [tex]p \neq 3[/tex], then [tex]p[/tex] divided by 6 has remainder of 1 or 5.
Case 1: p/6 has remainder 0, 2, or 4.
Then there exists some natural number [tex]n[/tex] such that either [tex]p=6n[/tex], [tex]p=6n+2[/tex], or [tex]p=6n+4[/tex]. However,
if [tex]p=6n[/tex], then [tex]p=2*3n[/tex],if [tex]p=6n+2[/tex], then [tex]p=2*(3n+1)[/tex], and if [tex]p=6n+4[/tex], then [tex]p=2*(3n+2)[/tex].By definition of divisibility, [tex]p[/tex] is divisible by 2. Since [tex]p \neq2[/tex], [tex]p[/tex] cannot be prime. This contradiction implies [tex]p[/tex] cannot have a remainder of 0, 2, or 4 when divided by 6.
Case 2: p/6 has remainder 3.
Then there exists some natural number [tex]n[/tex] such that [tex]p=6n+3[/tex]. However, if [tex]p=6n+3[/tex], then [tex]p=3*(2n+1)[/tex], so [tex]p[/tex] is divisible by 3. Since [tex]p \neq 3[/tex], [tex]p[/tex] is not prime. This contradiction implies [tex]p[/tex] cannot have a remainder of 3 when divided by 6.
Therefore, if [tex]p[/tex] is a prime number such that [tex]p \neq2[/tex] and [tex]p \neq 3[/tex], then when divided by 6, [tex]p[/tex] must have a remainder of 1 or 5.
Main proof of no prime trio with common difference of 70.Check p=2
Consider [tex]p=2[/tex]. Then [tex]q=2+70=72[/tex]. However, [tex]72=2*36[/tex], so [tex]q[/tex] is not prime. Hence, [tex]p \neq2[/tex].
Check p=3
Consider [tex]p=3[/tex]. Then [tex]q=3+70=73[/tex], and [tex]r=73+70=143[/tex]. However, [tex]143=11*13[/tex], so [tex]r[/tex] is not prime. Hence, [tex]p \neq 3[/tex].
So, thus far, we've proven that if there is a prime trio with a common difference of 70, that [tex]p \neq2[/tex] and [tex]p \neq 3[/tex].
Proof of the rest of primes by contradiction
By way of contradiction, assume that there does exist some prime trio [tex]\{ p,q,r \}[/tex] such that [tex]q-p=r-q=70[/tex], and [tex]p \neq2[/tex] and [tex]p \neq 3[/tex].
Then, by the Lemma proven earlier, when [tex]p[/tex] is divided by 6, it must have a remainder of 1 or 5.
Case 1: p/6 has remainder 5
Assume that [tex]p[/tex] has remainder 5 when divided by 6. Then, there exists some natural number [tex]n[/tex], such that [tex]p=6n+5[/tex].
[tex]q=p+70\\q=(6n+5)+70\\q=6n+75\\q=3*(2n+25)[/tex]
Since [tex]n[/tex] was a natural number, and the natural numbers are closed over multiplication and addition (meaning, multiplying and adding more natural numbers results in another natural number), then [tex]q[/tex] is divisible by 3.
Since [tex]p[/tex] is prime, [tex]0 < p[/tex], which implies [tex]0+70 < p+70[/tex]
Since [tex]q=p+70[/tex], [tex]70 < q[/tex], so [tex]q[/tex] cannot equal 3. Since [tex]q[/tex] is divisible by 3, but [tex]q \neq 3[/tex], [tex]q[/tex] is not prime, which is a contradiction to the existence of this prime trio.
Therefore, either [tex]p[/tex] cannot have a remainder of 5 when divided by 6, or the prime trio does not exist.
Case 2: p/6 has remainder 1
Assume that [tex]p[/tex] has remainder 1 when divided by 6. Then, there exists some natural number [tex]n[/tex], such that [tex]p=6n+1[/tex].
[tex]q=p+70\\q=(6n+1)+70\\r=q+70\\r=((6n+1)+70)+70\\r=6n+141\\r=3*(2n+47)[/tex]
Since [tex]n[/tex] was a natural number, and the natural numbers are closed over multiplication and addition (meaning, multiplying and adding more natural numbers results in another natural number), [tex]r[/tex] is divisible by 3.
Since [tex]q[/tex] is prime, [tex]0 < q[/tex], implying [tex]0 +70 < q+70[/tex].
Since [tex]r=q+70[/tex], then [tex]70 < r[/tex]. Therefore, [tex]r\neq 3[/tex].
Since [tex]r[/tex] is divisible by 3, but [tex]r\neq 3[/tex], [tex]r[/tex] is not prime, which is a contradiction to the existence of this prime trio (with a common difference of 70). Therefore, either [tex]p[/tex] cannot have a remainder of 1 when divided by 6, or the prime trio does not exist.
Since [tex]p[/tex] was prime, by our lemma [tex]p[/tex] must have either a remainder of 1 or 5. Since both remainder possibilities resulted in a contradiction, our contradiction assumption is false, so there cannot exist a prime trio such that their common difference is 70.
Which of the following are geometric sequences?
Check all that apply.
A. 5, 10, 15, 20, 25
B. 10, 5, 2.5, 1.25, 0.625, 0.3125
C. 1, 1, 2, 3, 5, 8, 13
D. -9, -3, -1, -1/3, -1/9, -1/27
Answers
Answer: B and D
Step-by-step explanation:
A is not, it's an arithmetic sequence where each term is +5 greater than the previous
B is because each term is 1/2 the previous term (common ratio of 1/2) thus making it a geometric sequence
C is not, it's the Fibonnaci sequence which is neither an arithmetic or geometric sequence
D is because each term is 1/3 the previous term (common ratio of 1/3) thus making it a geometric sequence
Can someone please help me
Answers
Answer:
Number 4
Standard form - Not sure if right
y = − 0.2734375x^2 − 1.09375x +11.40625
Factored form - Not sure if right
y= 0.0390625 (−7x^2 −28x+292)
Number 5
Either form of the equation other than standard form
Vertex form : y = −(x +3)^2 + 25
Vertex of the parabola
(-3,25)
X and Y intercepts
x-intercept(s): (2,0) ,(−8,0)
y-intercept(s): (0,16)
What’s one of the goals set out by the Healthy People 2010 program?:
a)
Ensuring that complaints against unfair billing are addressed
b)
Ensuring that private hospitals accept payment from any health insurance company
c)
Encouraging all employers to provide health insurance to their employees
d)
Eliminating the difference between the healthcare available to low and high income persons
Answers
Answer:
d i did the thing
Step-by-step explanation:
What are the solutions of the equation x4 + 3x² + 2 = 0? Use u substitution to solve.
O x=+√√√2 and x = +1
Ox=ti√√2 and x = ti
Ox=± √√2 and x = ti
Ox=+√√2 and x = +1
Answers
Answer:
[tex]\pm i\sqrt{2}\text{ and } \pm i[/tex]
Step-by-step explanation:
[tex]\text{let u = } x^2[/tex] so then [tex]u^2=x^4[/tex].
This gives you the equation: [tex]u^2+3u+2=0[/tex].
Now factor the equation by looking for factors of 2 that add up to 3, which is just 2 and 1. Use these to rewrite the equation: [tex](u+2)(u+1)[/tex]. So now just set each factor equal to 0:
[tex]u+2=0\\u=-2[/tex]
Now substitute x^2 back in as u
[tex]x^2=-2[/tex]
Take the square root of both sides
[tex]x=\pm \sqrt{-2}[/tex]
Separate the radical into sqrt(-1) * sqrt(2)
[tex]x=\pm \sqrt{-1}*\sqrt{2}[/tex]
Rewrite using i
[tex]x=\pm i\sqrt{2}[/tex]
Now set the other factor equal to 0
[tex]u+1=0\\u=-1[/tex]
substitute x^2 back in as u
[tex]x^2=-1[/tex]
Take the square root of both sides
[tex]x=\pm\sqrt{-1}[/tex]
rewrite using i
[tex]x=\pm i[/tex]
Please help! Consider the following subset of the real number line. How can this set be expressed using inequalities?
Answers
Answer:
-2 ≤ x ≤10
Step-by-step explanation:
Notice that x can never be less than -2 and can never exceed.
-2 and 10 are all inclusive thus the last answer is not correct as it tries to leave them out
What is the simplified value of the exponential expression
Answers
the simplified value of the exponential expression is 1/9
Hope this helped :)
Find the product of the given polynomials
(5r+8-6r)(4+2r-7)
A.2r^2+13r-24
B.-2r^2-24r+19
C.-2r^2+19r-24
D.2r^2+19r+24
Answers
Answer:
C
Step-by-step explanation:
(5r + 8 - 6r)(4 + 2r - 7) ← collect like terms inside each parenthesis
= (8 - r)(2r - 3)
each term in the second factor is multiplied by each term in the first factor.
8(2r - 3) - r(2r - 3) ← distribute parenthesis
= 16r - 24 - 2r² + 3r ← collect like terms
= - 2r² + 19r - 24
To raise funds for a new fire truck, a fire department is conducting a raffle. Residents can purchase a raffle ticket for $10.00 each. After writing his/her name on the ticket, the resident will place it in a container. Later on, a fire department official will randomly select one ticket from the container. The resident who purchased the selected ticket will win a prize of $2,000.00.
a. Suppose at the time of the drawing there are a total of 1000 purchased raffle tickets in the container. If a particular resident has purchased 10 tickets, what is his/her probability of winning the prize?
b. Compute the expected profit (winnings − cost) for a particular resident who purchased 10 raffle tickets.
c. After paying out the $2,000.00 prize, how much money has the fire department raised for its new fire truck? Other than the prize, ignore any other raffle costs incurred by the fire department.
Answers
a. The probability of winning the prize by the resident who purchased 10 tickets is 1% (10/1,000).
b. The expected profit (winnings - cost) for the resident who purchased 10 raffle tickets is $1,900 ($2,000 - $100).
c. The amount raised by the fire department after paying out the $2,000 prize (ignoring other raffle costs) is $8,000 ($10,000 - $2,000).
What is a raffle?A raffle is a gambling competition or lottery organized to raise money for a purpose.
A raffle involves the sale of tickets which are drawn randomly to select some winners.
Data and Calculations:Price of a raffle ticket = $10
Prize = $2,000
Cost of purchasing 10 tickets = $100 ($10 x 10)
Number of raffle tickets sold = 1,000
Total revenue realized = $10,000 ($10 x 1,000)
Thus, if a resident purchases 10 tickets, the chance of winning the raffle is 1%.
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A tennis ball can in the shape of a right circular cylinder holds four tennis balls snugly. If the radius of a tennis ball is 3.5 cm, what percentage of the can is not occupied by tennis balls?
Answers
Answer:
about 33.3%
Step-by-step explanation:
The fraction of space not occupied will be the same as the unoccupied fraction of a cylinder of the same height and diameter as a sphere.
Volume of a cylinderThe volume of a cylinder of diameter d and height d will be ...
V = πr²h = π(d/2)²(d) = (π/4)d³
Volume of a sphereThe volume of a sphere of diameter d is ...
V = 4/3πr³ = 4/3π(d/2)³ = (π/6)d³
Unoccupied spaceThe fraction of space that is occupied is ...
occupied space = (sphere volume)/(cylinder volume)
occupied space = ((π/6)d³) / ((π/4)d³) = 4/6 = 2/3
The fraction of unoccupied space is ...
unoccupied fraction = 1 -2/3 = 1/3
unoccupied fraction ≈ 33.3%
Answer:
Putangina okay
Step-by-step explanation:
#CarryOnLearning
can you please help me with this question? thanks!
Answers
Answer:
Step 2
Step-by-step explanation:
In step 1, Gary had the right idea of multiplying both sides by 4 to eliminate the denominator, but in step 2, Gary makes a mistake since e should equal 10 not 8. 2.5 * 4 = 10 not 8
Answer:
B) Step 2
Step-by-step explanation:
Gary's mistake occurs in Step 2. He was right to multiply both sides of the equation by 4 to find e, but his error is in the multiplication of 2.5*4. 2.5*4 = 10, not 8.
Find f(x-4) if f(x)=-x+2. f(x-4)
Answers
Answer:
= -x+6
Step-by-step explanation:
we can simply substitute (x-4) in x place because when we say function of x , we are basically saying when we substitute a given value in the place of x we will find a given y.so for example if we have a question f(4), we can simply plug 4 to -x +2 so we will find y or f(x) = -2.
so the answer for the above question will be f(x)= -x +6.
Write this in logarithm form √x = y
Answers
The logarithmic form of √x = y is ㏒ₓy = 1/2
How to determine the logarithmic formWe have, logarithmic form as;
㏒ₓ n = bⁿGiven √x = y
Convert the square root to power of 1/2 as that is what it represents, we get
x^1/2 = y
Then compare with the universal logarithmic form, we have
㏒ₓy = 1/2
Thus, the logarithmic form of √x = y is ㏒ₓy = 1/2
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Sandy borrows $1250 from the bank. The loan terms is 18 months with 5% annual interest. How much interest will she pay? How much will she pay back in all?
Answers
Answer:
Step-by-step explanation:
1250x0.05x1.5=93.75
93.75 is the interest
1343.75 is the total ammount.
A line passes through the point (8, -1) and has a slope of
Write an equation in slope-intercept form for this line.
Answers
The equation in slope intercept form is y = - 1 / 4 x + 1
How to find the slope intercept equation?Using slope intercept form,
y = mx + b
where
m = slopeb = y-interceptTherefore,
m = - 1 / 4
it passes through (8, -1)
Hen e,
-1 = - 1 / 4 (8) + b
-1 = - 2 + b
b = -1 + 2
b = 1
Therefore,
y = - 1 / 4 x + 1
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Write the augmented matrix of the system of equations given below. (10 points)
−2 + 2 − = −13
−3 − + = 7
− + 3 − 2 = 0
Answers
The augmented matrix of the system of equations is [tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]
How to determine the augmented matrix?The system of equations is given as:
-2x + 2y - z = 13
-3x - y + z = 7
-x + 3y - 2z = 0
Remove the variables x, y and z
-2 2 -1 13
-3 -1 1 7
-1 3 -2 0
Express as matrix
[tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]
Hence, the augmented matrix of the system of equations is [tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]
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Complete question
Write the augmented matrix of the system of equations given below. (10 points)
-2x + 2y - z = 13
-3x - y + z = 7
-x + 3y - 2z = 0
What is the radius of a sphere that has a surface area of 2903.33 in²?
Answers
Answer:
15.2 in
Step-by-step explanation:
The surface area of a sphere is given by the formula below:
Surface area of sphere= 4πr², where r is the radius
Given that the surface area is 2903.33 in²,
2903.33= 4πr²
Divide both sides by 4π:
[tex] {r}^{2} = \frac{2903.33}{4\pi} [/tex]
Square root both sides:
[tex]r = \sqrt{ \frac{2903.33}{4\pi} } [/tex]
r= 15.2 in (3 s.f.)
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https://brainly.com/question/16882587If n + 2, 5, and 9 represent the lengths of the sides of a triangle then < n
Answers
Answer:
n>2 (see below)
Step-by-step explanation:
Triangle side rule says n+2 + 5 must be greater than 9
n+2 +5 > 9
n > 2
(but it must be less than 12 o/w 5 + 9 will not be greater than n+2)
Maria spends $19 on lottery tickets every week and spends $122 per month on food.On an annual basis, the money spent on lottery tickets is ______% of the money spent to buy food.
Answers
The money spent on lottery tickets is 15.6% of the money spent to buy food.
How to determine the proportion?The given parameters are:
Food = $122
Lottery = $19
The proportion of the lottery tickets is:
Proportion = Lottery/Food * 100%
This gives
Proportion = 19/122* 100%
Evaluate
Proportion = 15.6%
Hence, the money spent on lottery tickets is 15.6% of the money spent to buy food.
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Translate and solve: the product of
p
and
−
2.5
is
4.8
Answers
Answer:
p = 7.3
Step-by-step explanation:
Equation: p - 2.5 = 4.8
add 2.5 to both sides:
P - 2.5 + 2.5 = 4.8 + 2.5
simplify
P = 7.3
hope that helps! :)
Divide by 2.5 on both sides.
P=1.92
Hope this helped!
I need help with this question please!!
Answers
Answer:
31465
Step-by-step explanation:
n!/((n-r)! r!)
= 31!/(31-4)! 4!
= 31!/ 27! 4!
= 31465
If the cost of milk is $3 per gallon, what is the amount of money a farmer can make by selling the milk produced by the cow in the month of April?
Answers
The amount of money a farmer can make by selling the milk produced by the cow in the month of April is $90
How to determine the amountFrom the equation given, we have that
$3 = I gallon
Let's take it that the farmer sells one gallon by per day
We know that the month of April has 30 days
So if he makes $3 in 1 day
He would make x in 30 days
Collect like terms
$30 × 30 days = amount
Multiply through
Amount = $90
Thus, the amount of money a farmer can make by selling the milk produced by the cow in the month of April is $90
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A town has population of 5000 and grows at 3.5% every year. To the nearest tenth
of a year, how long will it be until the population will reach 7300?
Answers
It would take approximately 11 years for this population to reach 7300.
How to calculate the time?Based on the information provided, the future size of the population can be modelled by using an exponential function:
F = Pe^rt
Substituting the given parameters into the formula, we have;
7300 = 5000e^{0.035 × t}
7300/5000 = e^{0.035t}
1.46 = e^{0.035t}
Taking the ln of both sides, we have:
ln(1.46) = ln(e^{0.035t})
0.378 = 0.035t
t = 0.378/0.035
Time, t = 10.8 ≈ 11 years.
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find the values of m&n if x
2
−2
[tex]f(x) = mx ^{4} + 2x ^{3} - 3x ^{2} + nx - 4[/tex]
Answers
The values of m and n from the given equation are 1/4 and -2
Polynomial functionsGiven the polynomial function below
f(x) = mx^4+2x^3-3x^2+nx-4
If the zeros are 2 and -2, hence;
0 = 16m+16-12+2n-4
0 = 16m-16+12-2n-4
_______________
16m+2n = 0
16m - 2n = 8
Subtract
2n+2n = -8
4n = -8
n = -2
Substitute for "m'
16m + 2(-2) = 0
16m = 4
m = 1/4
Hence the values of m and n from the given equation are 1/4 and -2
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BRAINLIEST!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
Move all the points on the graph two points to the right
Step-by-step explanation:
f(x-2) is just a translation to the right by 2. The whole formula is typically y = a f(b(x + c)) + d. In this case, the C value is the one being changed and that indicates a translation left or right. -2 indicates 2 to the right.
Answer:
The Slope: 0
The y-intercept: (0,0_
x y
0 0
1 0 (there is supposed to be a line between the x and y that goes down all the way down the numbers but i cannot type that)
Step-by-step explanation:
What will sue pay for 18 oranges if the cost 0.49 for 6 show the process
Answers
Answer:
[tex]\huge\boxed{\sf \$ \ 1.47}[/tex]
Step-by-step explanation:
Given that,6 oranges = $0.49
Multiply 3 to both sides
6×3 oranges = $0.49 × 3
18 oranges = $1.47
[tex]\rule[226]{225}{2}[/tex]
Work out the reciprocal of 0.0005. Give your answer in standard form. 7 Work out the reciprocal of 0.0005 . Give your answer in standard form .
Answers
Answer:
that's all I could do. hope it helps.
good day.