Answer:
mass can be expressed in newtons
What are two factors that must be kept the same (constant) between both groups?
Must be given 30 mL of water for 7 days.
c. What is the independent variable?
d. What is the dependent variable?
e. Which is the experimental group?
f. Which is the control group?
g. What must be done to make this experiment valid?
Answer:
Which is the control group?
g. What must be done to make this experiment valid?
Explanation:
an open steel can of volume 216 L is filled to the top with gasoline at 13.5 C. when it warms to 36.0 C, how much gas spills over? (don't forget, both the can and the gasoline are expanding.)
[tex]\\ \sf\longmapsto Q=mc\Delta T[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{Q}{m\Delta T}[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{1320}{5.61(274)}[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{1320}{1537.14}[/tex]
[tex]\\ \sf\longmapsto c=0.85J/kgK[/tex]
4.44J (creds to commenter on the post, just making it bigger)
How much energy will it take to heat a 8kg object with a specific heat capacity of 820J/kg℃ from 15℃ to 50℃
Explanation:
h=mcƦ
where Ʀ means change in temperature
h=8×820×(50-15)
=8×820×35
=229600j
=229.6kj
Can someone help me with these 3 questions!!!
Answer:
Below
Explanation:
To find the height of a ball thrown upwards we can use this formula :
vf^2 = vi^2 + 2ad
0^2 = 22^2 + 2(-9.8)d
484 = 19.6d
24.69 = d
25 m = d
To find the time of the phone dropped we can use this formula :
t = √2d/g
t = √2(15) / 9.8
t = √30/9.8
t =√3.142857
t = 1.749
t = 1.7 seconds
For a) since this object is free falling we know that it will accelerate towards earth at a rate of 9.8 m/s^2. The slope of a velocity time graph gives us the acceleration of the object. So in this case the slope would be 9.8 m.s^2
Hope this helps!
A projectile is launched horizontally from a height of 25m and it is observed to land 50m from the base. What was the launch velocity?
The initial horizontal velocity of the projectile is 22.1 m/s.
The given parameters;
height of the projectile, h = 25 mhorizontal distance of the object, R = 50 mThe time of motion of the object is calculated as follows;
h = ut + ¹/₂gt²
where;
u is the initial vertical velocity = 0h = ¹/₂gt²
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 25}{9.8} } \\\\t = 2.26 \ s[/tex]
The initial horizontal velocity of the projectile is calculated as follows;
R = vₓt
[tex]v_x = \frac{R}{t} \\\\v_x = \frac{50}{2.26} \\\\v_x = 22.1 \ m/s[/tex]
Thus, the initial horizontal velocity of the projectile is 22.1 m/s.
Learn more here:https://brainly.com/question/20349275
Two waves travel through ocean, one with wavelength 3 m, one with 6 m. Which one has greater speed?
Answer: 6m
Explanation: 6 is more than 3 and their both being measured by m
A dog walks 100m at a bearing of 175 degrees. a) How far did it walk East?
1 kilometer
Explanation:
hope it helps
Answer:
275m
Explanation:
hope it helps
pls give me brainliest
Which does not take the direction of the motion into account?
Displacement
Distance
velocity
Velocity and displacement take direction of motion into account while distance does not take direction of motion into account.
Vector quantities take into account both magnitude and direction of motion while scalar quantities only take the magnitude of motion into account. In describing the motion of an object, we use terms such as; velocity, distance, displacement etc.
Looking at the options provided in the question, displacement and velocity are vectors hence they take the direction of motion into account. Distance is a scalar quantity hence it does not take direction of motion into account.
Learn more: https://brainly.com/question/1527403
An airplane during departure has a constant acceleration of 3 m / s².
a. What is the speed that the plane reaches in 4 s?
b. If the plane passes at a flight point of
at a speed of 20 m / s, what is the speed 8 s later?
Constant acceleration of plane = 3m/s²
a) Speed of the plane after 4s
Acceleration = speed/time
3m/s² = speed/4s
S = 12m/s
The speed of the plane after 4s is 12m/s.
b) Flight point will be termed as the point the plane got initial speed, u, 20m/s
Find speed after 8s, v
a = 3m/s²
from,
a = v - u
t
3 = v - 20
8
24 = v - 20
v = 44m/s
After 8s the plane would've 44m/s speed.
what is physical change
Answer:a usually reversible change in the physical properties of a substance, as size or shape:
Freezing a liquid is a physical change.
Explanation:
Please help me to solve this question .
Answer:
P1 = momentum before collision = .5 kg * .32 m/s = .16 kg-m/s
Momentum is conserved
P1 = P2 = V * (M + m) = .16 kg-m/sec
V = .16 kg-m/sec / (.5 kg + .3 kg) = .2 m/sec
what is the equation for newton’s second law of motion, in terms of mass, velocity and time, when the mass of the system is constant?
Answer:
Newton's second law of motion is F = ma, or force is equal to mass times acceleration.
WHAT IS THE VOLUME OF A 5.71 G PLASTIC CUBE THAT HAS A DENSITY OF 1.15 G/CM3
Answer:4.96[tex]cm^{3}[/tex]
Explanation: Density is [tex]\frac{Mass}{Volume}[/tex]
so you are now looking for volume.
Volume= Density x Mass so
Volume = (5.78g) x(1.15g/ [tex]cm^{3} \frac{x}{y}[/tex]) =4.96[tex]cm^{3}[/tex]
Two motorcycles travel along a straight road heading due north. At t = 0 motorcycle 1 is at x = 50 m and moves with a constant speed of 6.50 m/s; motorcycle 2 starts from rest at x = 0 and moves with constant acceleration. Motorcycle 2 passes motorcycle 1 at the time t = 10.08.
Part B What is the position of the two motorcycles when motorcycle 2 passes motorcycle 1? Express your answer to three significant figures and include the appropriate units.
Part C What is the acceleration of motorcycle 2? Express your answer to three significant figures and include the appropriate units.
Answer:
Vf = 23 m/s
Explanation:
First we need to find the distance covered by the motorcycle 2 when it passes motorcycle 1. Using the uniform speed equation for motorcycle 1:
s₁ = v₁t₁
where,
s₁ = distance covered by motorcycle 1 = ?
v₁ = speed of motorcycle 1 = 6.5 m/s
t₁ = time = 10 s
Therefore,
s₁ = (6.5 m/s)(10 s)
s₁ = 65 m
Now, for the distance covered by motorcycle 2 at the meeting point. Since, the motorcycle started 50 m ahead of motorcycle 2. Therefore,
s₂ = s₁ + 50 m
s₂ = 65 m + 50 m
s₂ = 115 m
Now, using second equation of motion for motorcycle 2:
s₂ = Vi t + (1/2)at²
where,
Vi = initial velocity of motorcycle 2 = 0 m/s
Therefore,
115 m = (0 m/s)(10 s) + (1/2)(a)(10 s)²
a = 230 m/100 s²
a = 2.3 m/s²
Now, using 1st equation of motion:
Vf = Vi + at
Vf = 0 m/s + (2.3 m/s²)(10 s)
Vf = 23 m/s
Paula has walked in a straight line, 30.5° north of west, for 1650 meters. How far south and east should she walks to return to her original location
What is the correct answer and try to explain if can.
Answer:
C. Electrical
Explanation:
C because the lamp is plugged into a "Electrical" outlet meaning it uses electrical energy to produce light 'pls can i have brainliest i need it for my goal'
what is occurring when a light wave goes through a pane of glass in a window?
Answer:
transmission: the passing of a wave through an object
Explanation:
in addition to studies of the body system of corals what studies in earth science might increased scientists understanding of an ability to predict coral bleaching
Answer: they could get a piece of the coral and run tests on it
Explanation:
identity the organelle that found in a plant cell but not in an animal cell.
a) cell membrane
b) mitochondria
c) Ribosome
d) chloroplast
Answer:
Chloroplast
Explanation:
The plant cell has a cell wall, chloroplasts, plastids, and a central vacuole—structures not found in animal cells. Plant cells do not have lysosomes or centrosomes.
Answer:
d
Explanation:
pls mark as brainliest
have a great day
According to newtons third law if an eighth grader pushed against a large boulder with a force of 8 N how much force would the boulder exert on the eighth grader
Answer:
8n
Explanation
what is the energy of light for a single photon that has a wavelength of 347 nm?
The energy of light for a single photon that has a wavelength of 347 nm is 5.698 × 10-¹⁹ J
HOW TO CALCULATE ENERGY:
The energy of a photon of light can be calculated by using the following formula:E = hf
Where;
E = energy of photon (J)h = Planck's constant (6.626 × 10-³⁴J/s)f = frequency (Hz)However, the frequency must first be calculated using the formula as follows:λ = v/f
Where;
λ = wavelengthv = speed of light (3 × 10⁸m/s)f = frequencyf = v ÷ λf = 3 × 10⁸ ÷ 347 × 10-⁹f = 3/347 × 10⁸+⁹f = 0.0086 × 10¹⁷ Hzf = 8.6 × 10¹⁴ HzE = 6.626 × 10-³⁴ × 8.6 × 10¹⁴E = 56.98 × 10-²⁰E = 5.698 × 10-¹⁹ JTherefore, the energy of light for a single photon that has a wavelength of 347 nm is 5.698 × 10-¹⁹ J.Learn more at: https://brainly.com/question/13407202?referrer=searchResults
Someone help me please I don’t even know if that’s physics or not I just need help
Answer:
1. the robber carrying the metal safe will hurt more because the metal safe is heavier, so the heavier will be the force on the opposite direction from the one he was running when he hit the wall
2. ???
Explanation:
1. 3rd newton law: "If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction"
2. I don't know
Rahul is carrying a load of 80 kg along a distance of 200 meters in 5 minutes. But the same load is carried by reena to the same distance in 4 minutes. Who had more power? Also show by calculation .
Answer:
Reena
Explanation:
200 / 5 = 40 metres in a minute
200 / 4 = 50 metres in a minute,
Therefore Reena is faster
Why are some fibers spun together to form yarns?
Answer:
Spun yarns are produced by placing a series of individual fibres or filaments together to form a continuous assembly of overlapping fibres, usually bound together by twist. This operation is required in wool spinning because different parts of the fleece contain fibres of different length and thickness.
A 0.80-kg ball is thrown with a velocity of 13 m/s. The ball hit a 0.12-kg bowling pin. When the ball hits the pin, the pin goes flying forward at 6 m/s. What is the velocity of the ball after it hits the pin?
When the ball of mass 0.80kg hits a bowling pin of 0.12 kg, the velocity of the ball after it hits the pin = 12.1 m/s
The mass of the ball, [tex]m_1=0.80 kg[/tex]
The initial speed of the ball, [tex]u_1=13 m/s[/tex]
The mass of the bowling pin, [tex]m_2=0.12kg[/tex]
The initial speed of the bowling pin, [tex]u_2=0m/s[/tex]
The final speed of the bowling pin, [tex]v_2= 6m/s[/tex]
The final speed of the ball after collision, [tex]v_1 = ?[/tex]
According to the law of momentum conservation
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\0.80(13)+0.12(0)=0.80v_1+0.12(6)\\\\10.4+0=0.8v_1+0.72\\\\0.8v_1=10.4-0.72\\\\0.8v_1=9.68\\\\v_1=\frac{9.68}{0.8} \\\\v_1=12.1m/s[/tex]
The velocity of the ball after it hits the pin = 12.1 m/s
Learn more here: https://brainly.com/question/22257327
at what speed does a tropical storm become a hurricane
Answer:
74 mph is the answer
Explanation:
an empty boat floats in water with 10% of its volume submerged. and when it is loaded with 1200kg , the volume submerged will increase to 70% of the total volume . calculate the mass of the empty boat
Let volume of empty boat be = 100% = 1V
and mass of boat be M
In water 10%, 0.1V of the volume is submerged.
Mass, m of 1200kg increases the submerging from 10%, 0.1V to 70%, 0.7V
M leads to 0.1V boat submerging
boat submerging.
M + 1200kg leads to 0.7V boat submerging.
This is 60%, 0.6 V increase
By comparison
(M+1200kg) * 0.1V = 0.7V * M
0.1M + 120kg = 0.7M
120kg = 0.7M - 0.1M
120kg = 0.6M
M = (120/0.6)kg
M = 200kg.
The mass of the boat is 200kg.
What do you think will happen to current if we increase or decrease the resistance of the connecting wire?
Answer:
If resistance is increased, the current decreases and if the resistance is decreased, the current flowing through the wire increases.
Explanation:
V = IR is ohm's law which implies I = V/R, where I is the current and V is the voltage and R is the resistance. Hence, I is inversely proportional to R.
Acetylene welding goggles are worn because they protect the eyes from
Answer:
wala
Explanation:wala
1.concave lens
A.distance between two waves
B.can be captured on screen
C.light of a wavelength
D.scattered incident light
E.convex lenses
F. distance to the focal point
G.light swinging in one direction
H.heat radiation
What to do here tell please.......