mass and weight the standard metric unit for mass is and the stanard metric unit for weight is worksheet. t/f

Answer: To solve this problem, we can use the principle of conservation of energy. Energy is a property of an object or system that is related to its ability to do work, and can take many different forms. In the case of a skateboarder being launched off a ramp, the energy of the system is made up of two forms: kinetic energy and potential energy.

Kinetic energy is the energy of motion, and is equal to one half of an object's mass times its velocity squared. In this case, the skateboarder has a kinetic energy of 0.5 * 50 kg * (10 m/s)^2 = 2500 J when it is launched off the ramp.

Potential energy is the energy of position, and is equal to an object's mass times the acceleration due to gravity times its height. In this case, the skateboarder has a potential energy of 50 kg * 9.8 m/s^2 * h, where h is the height above the ramp.

Since energy is conserved, the sum of the kinetic and potential energy of the system must be constant. Therefore, at the peak of the skateboarder's motion, his kinetic energy must be 0, and all of the energy of the system must be in the form of potential energy. This means that the maximum height that the skateboarder can reach is equal to the kinetic energy of the system divided by the acceleration due to gravity times the mass.

For a skateboarder with a mass of 50 kg, the maximum height that he can reach is 2500 J / (9.8 m/s^2 * 50 kg) = 5.1 m. For a skateboarder with a mass of 100 kg, the maximum height that he can reach is also 5.1 m. This is because the maximum height that an object can reach is only dependent on its initial kinetic energy, not its mass. However, if the skateboarder is moving at a higher initial velocity, such as 20 m/s, then the maximum height that he can reach will be higher. In this case, the maximum height will be 0.5 * 50 kg * (

Explanation:

The distance of the pivot point from the center of mass of the object = 0.85 m

Oscillatory motion is any motion that is repeated at the same time interval and through the same trajectory in its motion.

The simplest oscillatory motion is harmonic motion or simple harmonic motion (SHM).

The simple harmonic motion is a periodic motion that occurs at the same time interval.

We have,

Mass of point = 2.40 kg ⇒ m

Moment of inertia = 1.24 kgm² ⇒ I

Frequency = 0.640 Hz ⇒ f

Acceleration due to gravity = 9.8 m/s² ⇒ g

Now, find the angular velocity first,

ω = 2[tex]\pi[/tex]f

= 2[tex]\pi[/tex] (0.640)

= 4.0192 rad/s

So, the distance of the pivot point from the center of mass of the object is:

ω = [tex]\sqrt{\frac{mgd}{I} }[/tex]

4.0192 =   [tex]\sqrt{\frac{(2.40)(9.8)(d)}{1.24} }[/tex]

d = (4.0192)² (1.24) / (2.40)(9.8)

= 20.0309211/23.52

= 0.85 m

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The statements that is true about the car and the truck is "The car's measurement is a scalar, and the truck's measurement is a vector"

third option is the correct answer.

Scalar quantities are those quantities that can be described by magnitude only.

These type of quantity has no direction, but can be effectively described by direction only.

Examples of scalar quantities include the following;

Vector quantities are those type of quantity which can be described by both quantity and direction.

Examples of vector quantities include the following:

Speedometer is a device used in measuring the speed of a car, hence the measurement of the car is scalar. The speed of the truck has direction (next lane), so it can be effectively regarded as vector quantity.

Thus, the speed of the truck has both magnitude and direction and can be called vector measurement.

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At position p a is positive distance x is positive velocity will be negative as A is positive acceleration also negative.

Equation of graph is x(t) = Acos (wt + ∅)

dx/dt = -Asin(wt + ∅)w

Velocity v =  -Asin(wt + ∅)w

acceleration a = -Aw² cos(wt + ∅)

At position p a is positive distance x is positive velocity will be negative as A is positive acceleration also negative.

The rate at which a moving object's velocity changes is known as acceleration. It gauges the speed of velocity changes. Examples of acceleration include riding a carousel and traveling at a constant speed around a bend in a road. You might feel the velocity change if you are accelerating. Uneven acceleration, uneven acceleration, and average acceleration are the three different types of accelerated motions.

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a) Energy added = 3.113 × 107 J b)  coefficient of performance 3.70

A) COPhp= QH/Win

Hence QH = (COPhp)Win = 4.70×1.84 = 8.648 kW

Energy added = QH(60×60) = (8.648×103)(3600)

Energy added = 3.113 × 107 J

B)  coefficient of performance = (COP)hp - 1 = 4.70 - 1 = 3.70

Various efficiencies can be used to convert energy between different forms. Transducers are objects that change between these states. Examples of transducers include a battery, which converts chemical energy into electric energy, a dam, which transforms gravitational potential energy into the kinetic energy of moving water (and the turbine blades), and finally into electric energy via an electric generator (from heat to work)

Energy transformation examples include creating electric power from heat energy using a steam turbine or lifting something against gravity while using electrical energy to power a crane motor. When an object is lifted against gravity, mechanical work is done on it and gravitational potential energy is stored inside it. Gravity performs mechanical work on the thing if it falls to the ground.

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In outer space, an astronaut is moving at a constant speed of 0.550c in a spacecraft. She would become heavier and her heart rate would increase, among other things.

The special theory of relativity states that if a particle is traveling at extremely high speeds (some fraction times C)

then,  m= [tex]\frac{m_{o} }{\sqrt{1-\frac{v^{2} }{c^{2} } }}[/tex]

         m=m₀/√(1-(0.55)²

         m=m₀/0.83

         m=1.20 m₀

Equipment or vehicle built to go through space is called a spaceship. Spacecraft, a form of man-made satellite, is employed for a number of tasks, such as communications, Earth observation, meteorology, navigation, space colonisation, planetary exploration, and the transfer of passengers and goods. All spacecraft—aside from single-stage-to-orbit vehicles—need a launch vehicle to travel into space (carrier rocket).

A spacecraft that is performing a sub-orbital spaceflight launches into orbit but then descends to Earth's surface before gaining enough momentum or energy to complete a full orbit. Spacecraft that are on orbital missions orbit the Earth or another celestial body in a confined orbit. Only in orbit (space stations) or during launch do spacecraft used for human spaceflight carry people on board as crew or passengers.

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The velocity of the truck after the collision is 4.47 m/s.

We know that we can be able to use the principle of the conservation of momentum to be able to obtain the velocity of the truck. We know that from this principle, the momentum after collision would be the same as the momentum before collision.

Using this approach we can say that;

Momentum before collision = Momentum after collision

Then;

(3,242 *  11) + (1,413  * 0) = (3,242 * v) + ( 1,413 * 15)

35662 = 3242v + 21195

v = 35662  - 21195/3242

v = 4.47 m/s

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The velocity of the truck immediately after collision is 4.46m/s

?

Conservation of linear momentum states that in a closed system, if two bodies collides ,the momentum is always conserved. Or we can say conservation of linear momentum states that the momentum before collision is equal to the momentum after collision.

Momentum is expressed as : momentum = mass × velocity

The momentum before collision =

3242× 11 + 1413×0

= 35662+0 = 35662kgm/s

The momentum after collision

3242v + 1413× 15

= 3242v + 21195

from conservation of momentum

35662= 3242v+ 21195

3242v = 35662-21195

3242v = 14467

v = 14467/3242

v = 4.46m/s

therefore the velocity of the truck after collision is 4.46m/s

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(a) The ball hits the wall 5.3 meters above the release point.

(b) The horizontal component of its velocity is 17.5 m/s. (c) The vertical component of its velocity is 17.1 m/s.

(d) Yes, it has passed the highest point on its trajectory.

(a) Using the equation for range, we can solve for time:

R = V*t*cosθ =>25*t*cos65 = 12 t = 0.75 s

We can then solve for the height using the equation for vertical displacement:

h = V*t*sinθ - 0.5*g*t^2

h = 25*0.75*sin65 - 0.5*9.8*0.75^2 h

= 5.3 m

(b) We can solve for the horizontal component of the velocity using the equation for range:

R = V*t*cosθ 17.5

    = 25*t*cos65 t

   = 0.7 s V = 17.5 m/s

(c) We can solve for the vertical component of the velocity using the equation for vertical displacement:

h = V*t*sinθ - 0.5*g*t^2 17.1

= 25*0.75*sin65 - 0.5*9.8*0.75^2 V = 17.1 m/s

(d) Yes, the ball has passed the highest point on its trajectory because the ball is traveling downwards when it hits the wall.

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A lab group investigates the maximum weight students can lift with their arms compared to their legs. if their t' value was 0.35, there is difference between the arms and legs data. The correct option is (B).

Difference between the measured value and the targeted true value for the physical quantity?

Measurement error.

The appropriate response to the foregoing question is because_________

The disparity between means was larger than the total uncertainty.

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The complete question is:-

A lab group investigates the maximum weight students can lift with their arms compared to their legs. if their t' value was 0.35, which of the following conclusions would be justified?

a.)There is no significant difference between the arms and legs data.

b.)There is difference between the arms and legs data.

c.)It's unlikely difference between the arms and legs data.

d.)It's likely difference between the arms and legs data.

All four planets contain stable atmospheric layers, a mantle, and a core. One of the following is FALSE regarding the four terrestrial planets (Earth, Mars, Mercury, and Venus).

Terrestrial planets include Mercury, Venus, Earth, and Mars because of their compact, stony surfaces that resemble terra firma on Earth. The four innermost planets in the solar system are the four terrestrial planets.

The four innermost planets are known to as terrestrial planets and feature a moon or moons, valleys, volcanoes, and craters. They also have a liquid heavy-metal core.

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Red giant stars are close to exhausting their supply of hydrogen, the fuel that sustains them. So the correct option is e.

Red giant stars are a type of star that is in the late stages of its life cycle. They are usually several times larger than the sun and have a much lower surface temperature. As the star's core runs out of hydrogen, the star begins to expand, causing its surface temperature to decrease. This causes the star to become a red giant and it will remain in this phase until the majority of its hydrogen is used up.

Once a red giant star has exhausted its supply of hydrogen, it will begin to fuse helium in its core. This will cause the star to become even larger and cooler, eventually turning into a white dwarf. After this, the star will eventually cool off to become a black dwarf.

Red giant stars are an important part of the life cycle of stars and are important for understanding the evolution of our universe. They are a reminder that all stars, including our own sun, will eventually reach the end of their life cycle and eventually become a white dwarf.

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If the disk is released from rest, Angular velocity (ω) of the disk is  [tex]245\frac{rad}{s}[/tex]

In physics, the angular velocity or rotational velocity (ω or Ω) is also known as the angular frequency vector, is the rate at which an object's angular position or orientation changes over time (i.e., the object's rotation speed is a pseudo-vector representation. or spin relative to a point or axis).

The magnitude of the pseudovector represents the angular velocity, i.e. the speed at which the object rotates or rotates, and its direction is perpendicular to the current plane of rotation or angular displacement. Angular velocity direction is conventionally given by the right-hand rule.

Calculation :

Given : M = 2kg, t = 3s, r = 80mm

solution :

[tex]0 + Mgrt = \frac{3}{2} Mr^{2}[/tex]ω

ω = [tex]\frac{2}{3} (\frac{g}{r} ) t[/tex]

ω =         [tex]245\frac{rad}{s}[/tex]

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An air capacitor is made by using two flat plates, each with area a, separated by a distance d, then a metal slab having thickness a (less than d) and the same shape and size as the plates is inserted between them, a capacitor has dielectric material between two plates.

A capacitor is a device that stores electrical energy in an electric field by using the buildup of electric charges on two neighboring surfaces that are electrically insulated from one another. It is a passive electrical component with two terminals. A capacitor's effect is referred to as capacitance. A capacitor is an electrical component designed to increase capacitance, even though there is some capacitance between any two neighboring electrical wires in a circuit. In its early days, the capacitor was referred to as a "condenser," and you may still see it in a few compound names, such "condenser microphone." There are several sorts of practical capacitors that are often used, and they are available in a wide range of physical shapes and constructions. The majority of capacitors include two or more electrical conductors separated by an insulating substance, typically in the form of metallic plates or surfaces. An electrolyte, thin sheet, sintered metal bead, or foil can all function as conductors. The nonconducting dielectric increases the charge capacity of the capacitor.

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Velocity is zero, acceleration is non-zero is correct statement.

It is given that a ball is thrown upwards so a ball. So when ball is at maximum height, the condition will be that it's velocity will be zero.

So at maximum height velocity will become zero. No acceleration acting on it, acting on eight will be -G,

then G=-9.8 m/[tex]s^2[/tex]

So this extra acceleration due to gravity will always be same on the ball whether it is moving or it is at maximum height.

When the velocity will be zero only while our city is zero needed and the expiration is not equal to zero.

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When a white dwarf gains enough mass to surpass the Chandra-Sekhar limit, type 1a supernovae are produced.

The importance of the Chandrasekhar limit in Type-1a supernovae has been recognised in astrophysics. The Chandrasekhar limit is thought to be crossed by a white dwarf, causing a catastrophic collapse, which is assumed to be the cause of these supernovae. It is believed that Type Ia supernovae (SNIa) are produced when a carbon-oxygen white dwarf in a binary system reaches the Chandrasehkar limit, either as a result of accretion from a donor or mergers. One of the two stars must be a white dwarf in order to cause a type Ia supernova.

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When the string is properly tuned to 196 Hz, the wave speed on the string is 250 m/s then 75 cm long G string stretched when it's first tuned is 1.833 mm.

Simple harmonic motion (SHM) occurs when the restoring force (the force directed toward a stable equilibrium point) is proportional to the displacement from equilibrium.

Repetitive motion through a central equilibrium point, Symmetry of maximum displacement, Period of each cycle is constant, Force causing the motion is directed toward the equilibrium point (minus sign).

At the equilibrium point x = 0 so, a = 0 also. When the stretch is a maximum, a will be a maximum too. The velocity at the end points will be zero, and it is a maximum at the equilibrium point.

As we know,

v = sqrt(T/mu)

250 = sqrt(T/(1.3*10^-3))

So T = 81.25 N

Young's modulus for steel = 200 x 10^9 Pa

Y = (T/A)/(deltal/l) = T*l/(deltal*A)

So delta l = (T*l)/(Y*A) = 81.25*0.75/(200*10^9*pi*(0.23*10^-3)^2)

              = 1.833*10^-3 m

              = 1.833 mm

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Relatively small waves travel at about 10 km/h and reach shore about every 3 seconds.

In deep waters far offshore, the slowest wave components with the shortest periods and the smallest wave height intervals can travel at less than 5 miles per hour. The component with the longest period could be moving at 35 miles per hour or more.

The Waves is often considered Virginia Woolf's masterpiece. Beginning with six children playing in a seaside garden they experience friendship and love and grow as they deal with the death of their beloved friend Percival. follow the life of the smallest wave height.

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It would take approximately 12 minutes command module to complete one orbit.

The time it takes for the command module to complete one orbit depends on the speed at which it is traveling. For the Apollo missions to the moon, the command module typically orbited at speeds of around 5,600 m/s or 20,000 km/h. It is important to note that the speed at which the command module traveled could vary from mission to mission. Factors such as the gravitational pull of the Earth and Moon and the direction of the burn of the engine could have an effect on the time it takes to complete one orbit. This is why it is important to calculate the speed of the command module for each mission to make sure the spacecraft remains in its optimal orbit.

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Answer:

The North Atlantic Gyre, the South Atlantic Gyre, the North Pacific Gyre, the South Pacific Gyre, and the Indian Ocean Gyre.

Explanation:

The 5 major gyres are:

1. the North Atlantic Gyre

2. the South Atlantic Gyre

3. the North Pacific Gyre

4. the South Pacific Gyre

5. the Indian Ocean Gyre

Hope this helps!

The angular acceleration of the arm is 68.76 rad/s².

We know the formula for angular acceleration as,

α = (ω - ω₀)/t

It is given that the ball is accelerated from rest, so ω₀ = 0.

We know the formula for velocity as, v = r* ω

ω = v/r

Given that, Velocity v = 8.1 m/s

Time t = 0.38 s

Radius r = 31 cm = 0.31 m

So, α = 8.1/0.31 * 1/0.38 = 26.13 /0.38 = 68.76 rad/s²

Angular acceleration is calculated to be 68.76 rad/s².

The question is incomplete. We should find out the angular acceleration of the arm. The figure is attached in the attachment below.

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Mercury which is 2nd denser planet will sink the first in the given circumstances.

Our solar system is situated in the Milky Way galaxy's outer spiral arm.

The Sun, our star, and everything gravitationally connected to it, including the planets Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, dwarf planets like Pluto, and dozens of moons.

Thousands of planetary systems orbiting other stars in the Milky Way have been found, in addition to our solar system.

Many of the smaller worlds, including the six largest dwarf planets and the six major planets, are orbited by natural satellites, also known as "moons" after the Moon.

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The cable being shown has a 457 N tension.

Mass of scaffold 1, m1 = 50Kg

Mass of lower scaffold 2, m2 = 30kg

Length, = 2m

Mass of nail box, = 20 kg

d = 0.500 m

Length of scaffold 1, = 3m

Tension on right, = 196N

Tension on left, = 196N

Torque at left point Tr × L2 - mgd - m2g×L/2  = 0

Tr = 196N

Fy = 0

Tl + TR -mg -m2g = 0

Tl = 294N

T × L1 - Tl × d - m1g× L1/2 - Tr(L1 - d) = 0

T = 457N

The cable being shown has a 457 N tension.

A rope, string, or cable that is stretched under an applied force develops a force known as a tension force in physics. Along the entire length of the rope or cable, tension is applied in the opposite direction of t. According to the International System of Units, tension is expressed in newtons and can take the form of a transmitted force, an action-reaction pair of forces, or a restoring force (or pounds-force in Imperial units). This mechanical quantity is typical. In the direction of the thread at the point of attachment, the ends of a string or other object conveying tension will apply forces to the objects to which the string or rod is linked. "Passive forces" are another name for these tension-related forces.

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The incident light cause the ejection of an electron, the light impart a certain amount of energy to the electron to overcome the forces that constrain it within the metal.  (V0=E light - ∅/e)

The minimum amount of energy required to overcome these forces is called the work function ∅ Different metals will have different values for ∅. For an electron to reach the detector, the light must impart enough energy for the electron to overcome both the work function and the stopping potential.

Part B

Suppose that the light carries energy E light What is the maximum stopping potential V0 that can be applied while still allowing electrons to reach the detector?

Express your answer in terms, е, E light and ∅,

ANSWER: V0=E light - ∅/e

involving or resulting from electricity-produced magnetism, which is the ability of a thing to attract other objects to it. physics. The term "electromagnetic" also refers to the study of the interaction between electricity and magnetism.

Radio waves, microwaves, infrared rays, visible light, uv light, X-rays, and gamma rays are examples of electromagnetic waves that propagate across space independently of matter.

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What is resistance?

Resistance refers to the quantity that AN object impedes or resists in an electrical current. current refers to the flow of electrons. a better thanks to make a case for resistance is to think about an example of an individual in a very jam-pawncked market troubled to travel from one look to another.

Resistance may be a live of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named once Georg Simon Ohm  a German man of science who studied the connection between voltage, current and resistance.

Equivalent resistance

R= 4 * 12 / 4+12

Req = 3 ohm

From ohm's law

V = IR

V = 2 * 3 = 6V

I4ohm = V/R4

= 6/4 = 1.5 ampere

Hence, final answer is  current through 4ohm is 1.5 ampere

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The value must the product AN have in order for the chip to operate, where A is the coil's surface area and N is number of turns in the coil is NA = 5.87 x 10⁻⁶.

Calculation:

B(t) = [tex]B_{peak}[/tex]sin(ωt)B(t) = (0.006) sin(8.52 x 10⁷t)taking derivative relative to "t" on both sidesdB(t) / dt = (51.12 x 10⁴) Cos(8.52 x 10⁷t)Induced EMf is given asE = NBA w3 = (NA) (0.006) (8.52 x 10⁷)NA = 5.87 x 10⁻⁶All

you need is to measure the outer diameter inner diameter and thickness of the coil. Volumes are given in cubic millimeters. To get the length of the coil, we need to divide the result by the cross-sectional area of the coil, which is determined by the width and thickness of the coil.

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The coefficient of kinetic friction between the grindstone and the blade is 0.8. Thus, 602.88 W is the power provided by the motor to keep the grindstone at the constant rotation rate

The resistive friction force (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), a numerical value. The following formula represents it: fr = Fr/N. The velocity has no effect on kinetic friction. In comparison to kinetic friction, static friction has a higher coefficient.

For instance, kinetic friction will be present between the wood surface and the floor while a wooden block is moving over it.

First, we calculate the torque (τ) with the given normal force (N) and the coefficient of friction (μk).

τ = FR

or, τ = μk × N × R

or, τ = (0.8) × (10) × (1.5)

or, τ = 12 N.m

Then, we proceed to calculate the power (P). Note that we have multiplied the angular speed by 2π in order for its units to be radian per second.

P = τ × ω

or, P = (12) × (8.0 × 2π)

or, P = 602.88 W

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The mirror is polished smooth, so that regular reflection occurs. the soda can, however, has a rougher surface, so that irregular reflection occurs. That's why,  she can see her face in a mirror but not in a soda can.

The reflected rays of a parallel light beam that strikes a smooth, planar surface will also be parallel. Regular reflection is the name given to this sort of reflection. The angle of light reflection in this instance is equal to the angle of incidence and is situated on the side of the normal that is furthest from the point of incidence. Regular reflection is what we refer to as reflection off a polished surface.

The reflected light rays scatter in various directions when a parallel light beam impacts a rough surface. Reflection of this kind is referred to as diffuse or irregular reflection. The angle of light reflection in this situation is the same as the angle of light incident. Diffuse reflection is the term for reflection off of a rough surface.

Hence, The mirror has a smooth surface, allowing for regular reflection. However, the surface of the soda can is rougher, causing an irregular reflection.

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I = 1.82 kg/m2 is the flywheel's moment of inertia. The highest amount of energy that can be stored by a flywheel-based energy storage system (a revolving disc) is 3.6 mj.

The torque required to achieve a desired angular acceleration is determined by the rigid body's moment of inertia, also referred to as the mass moment of inertia, angular mass, second moment of mass, or, more precisely, rotational inertia.

Given that, E = 3.6 MJ = 3.6*106J is the maximum energy that can be stored in the flywheel.

Flywheel angular velocity is w = 12000 revs per second, or 12094.39 rads per second.

the flywheel's moment of inertia must be determined. In rotational kinematics, the energy of a flywheel is given by I = 2E/W2.

I = 1.82 kg - m^2

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The total drag force acting on a sphere with a diameter of 12 cm and exposed to airflow at 1 atm and 5°C is therefore measured to be 5.2 N. Therefore, the friction drag coefficient is 0.0115.

When determining whether a flow pattern is laminar or turbulent while passing through a pipe, Reynolds number, a dimensionless quantity, is used. The relationship between inertial and viscous forces is what determines the Reynolds number. Friction is caused by surface irregularity, according to observations made at the microscopic level. Variety of Friction Friction can be divided into two categories, which are as follows: internal rubbing

Cdf = 0.2*0.3/5.2

Cdf = 0.06/5.2

Cdf = 0.0115

when 5.2/0.3 = 0.2

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In relation to the radius R of the Earth, the new planet's radius is √2R.

The value, represented by r earth, equates to roughly 6,371,000 meters (6.371 x 106 m). This equates to 3,960 statute miles or around 6,371 kilometers (km). The formula r = (A/) can be used to determine the radius of a circle using area.

The period of a planet's orbit (P) squared is equal to the size of the semi-major axis of the orbit (a) cubed when it is stated in astronomical units because P2 = a3 according to Kepler's Third Law. If the mass of the planet is known, Kepler's Third Law can be applied to determine the planet's orbital radius.

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