Mark reads 42 pages of a book every 3/4hour wright a quation that models the relationship between x ,the number of hours Mark reads, and y, the number of pages of the book he reads

Based on the number of people who are engineers and those who are chemical engineers, the percentage who are chemical engineers is 2.01%

To find the percentage of something out of the total number, the formula is:

= Number of selected variables / Total number of variables x 100%

The selected variable here is chemical engineers so the percentage of chemical engineers out of the total number of engineers is:

= Number of chemical engineers / Total number of engineers x 100%

= 27,860 / 1,326,800 x 100%

= 2.01%

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Answer:

x/36 is what you're looking for my guy

Answer:

5 3/5

Step-by-step explanation:

assuming you are dividing fractions, here are your steps

Answer:

I think the first number is 45 and the second number is 81.

Step-by-step explanation:

45 > 42 but 45 < 55       81 > 80 but 81 < 89

Both figures 1 & 2 are similar

Point S in figure 1 corresponds to Point P in fugure 2

Answer: r

Step-by-step explanation:

The figures are symmetrical about line r.

The probability that the ace of spades will be revealed before any face card (the jack, queen, or king) is 0.0769.

Probability refers to potential.This branch of mathematics deals with the occurrence of a random event. The value's range is 0 to 1. Probability has been applied into mathematics to predict the likelihood of different events.

The likelihood is based on the range of potential outcomes. the total number of possible outcomes. As an illustration, since there is only one way to get a head and a total of two possible results, the likelihood of flipping a coin and getting heads is one in two. a tail or a head.

According to given data;

Let's look at the first few probabilities; we're going to do this in reverse order, in order to find a pattern:

P(O,O,O,AS)=39/52)*(38/51)*(37/50)*(1/49)

                  =(39*38*37/3!)/(52*51*50/3!)*1/49

P(O,O,AS)=(39/3)(52/3)×1/49

        but we know that;

(n/2)=n(n-1)/2!

P,(O,O,AS) =(39/2)/(52/2)  *1/50

P(AS)=(39/0)/(52/0) *(1/52)

We now have

P(AS)+P(O,AS)+P(O,O,AS)+P(O,O,O,AS)

FROM THIS CALCULATE ;

P=0.0769

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The surface area of a cylinder is equal to 208π square units.How to calculate the surface area of right cylinder?The surface area is the sum of the areas of all faces of the solid. In the case of a right cylinder, the surface area is the sum of the two areas of the circular base and the lateral area (A), in square units, whose formula is described below:A = 2π · r² + 2π · r · h           (1)Where:r - Base radiush - HeightIf we know that r = 8 and h = 5, then the surface area of the right cylinder is:A = 2π · 8² + 2π · 8 · 5A = 208πThe surface area of a cylinder is equal to 208π square units.

Since the ​chi-square 27.385 is greater than 13.388 at the provided critical value level value, the null hypothesis is accepted.

For the given question;

The hypotheses for the goodness of fit test are as follows:

The chi-square test has one tail.

The criterion is as follows:

Thus, the null hypothesis is accepted at the provided level of critical value because the ​chi-square 27.385 is more than 13.388.

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Answer:

16 and -16

Step-by-step explanation:

Answer: D. 16 and -16

Step-by-step explanation: I dont think you need an explanation because it is multiple choice.

The probability that fewer than 3 women will deliver prematurely is 1/20.

So, 10% of 20:

Therefore, the probability that fewer than 3 women will deliver prematurely is 1/20.

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The correct question is given below:

A large national study finds that 10% of pregnant women deliver prematurely. a local obstetrician is seeing 20 pregnant women in the next week at their clinic. what is the probability that fewer than 3 of them will deliver prematurely?

The reasons that proves the congruency of the triangles are;

2.7 [tex] \Delta EDF \cong \Delta FGE[/tex] by SSS congruency postulate

2.8 [tex] \Delta AOB \cong \Delta COB[/tex], by SAS congruency rule

[tex] \Delta AOB \cong \Delta COB[/tex], by ASA congruency rule or postulate

The rules that proves two triangles to be congruent is if they satisfy any of the 5 rules of congruency, which are; Side–side–side, or SSS, side–angle–side, or SAS, side–angle–angle, or SAA, angle–side–angle, or ASA, and right angle–hypotenuse–side, or RHS

2.7 The given parameters of the two triangles are;

DE = GF, and DF = GE

Required;

To prove that

[tex] \Delta EDF \cong \Delta FGE[/tex]

Solution;

From the given diagram, we have;

[tex]EF \cong FE[/tex]

Reflexive property

Therefore;

[tex] \Delta EDF \cong \Delta FGE[/tex]

Side–Side–Side, SSS rule of congruency

The Side–Side–Side congruency postulate states that if the three sides of one triangle are congruent to three sides of another triangle, then both triangles are congruent.

2.8 The circle information are;

The midpoint (center) of the circle = Point O

Segment OB is perpendicular to segment AC, [tex] OB \perp AC [/tex]

OB bisects AC

Required;

To prove that [tex] \Delta AOB \cong \Delta COB[/tex]

Solution;

Segment OA and OC are the radius of circle O

Therefore;

[tex] OA \cong OC[/tex] by the properties of the radius of a circle

The angle [tex] \angle OAB \cong \angle OCB [/tex] ; Base angles of isosceles triangle ∆OAC

[tex] AB \cong BC[/tex], Segments formed by the perpendicular bisector OB

Given that AB, [tex] \angle OAB [/tex] and OA in [tex] \Delta AOB [/tex] are congruent to BC, [tex] \angle OCB [/tex] and OB in [tex] \Delta COB [/tex], we have;

Second proof;

Given that OB is the perpendicular bisector of AC, we have;

[tex] \angle OBA \cong \angle OBC = 90^{\circ} [/tex], definition of angles formed by perpendicular lines

[tex] AB \cong BC[/tex]

Therefore;

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Answer:

domain: all x-values

Step-by-step explanation:

Answer:

870,000

Step-by-step explanation:

Ten thousand is 10,000.

The ten thousand value here is 6

The thousand value here is 7.

Using rounding rules, 5 and up goes up therefore the ten thousand value becomes 7.

867,000 --> 870,000

Hope that helps

The scale factor for the model of the elephant is 1 : 30 (option A).

A scale drawing is either a smaller or a larger version of an original image. For example, a map is a smaller version of a city, country or area.

A scale factor provides information on the relationship that exists between the scale drawing and the actual image. The scale factor shows the rate of reduction or enlargement of the original image.

Scale factor = actual length of the elephant / length of the elephant in the model

216 / 7.2 = 30

The scale factor is 1 : 30

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Answer:

Step-by-step explanation:

The required two odd numbers are 3 and 5.

We have to determine,  It is a factor of 30 and a multiple of 3 what are 2 numbers.

To obtain the factor of 30 and 2 numbers is calculated in the following steps.

The Factors of 30 are,

30 = 2 , 3 , 5 ,

And multiply the terms by 2,

After multiply by 2 all the term become even.

Then,

The 2 odd numbers are: 3, 5

Hence, The required two odd numbers are 3 and 5.

The greatest common factor of the given terms is 2a⁴b

From the question, we are to determine the greatest common factors of the given terms

The given terms are

18a^4b^9c^2 and 34a^6b^5 and 22a^8bc^7

That is,

18a⁴b⁹c² and 34a⁶b⁵ and 22a⁸bc⁷

We will express each of the given terms as a product of their factors

18a⁴b⁹c² = 2 × 3 × 3 × a⁴ × b⁸ × b × c²

34a⁶b⁵ = 2 × 17 × a⁴ × a² × b⁴ × b

22a⁸bc⁷ = 2 × 11 × a⁴ × a⁴ × b × c⁷

Hence, the GCF is 2 × a⁴ × b = 2a⁴b

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Answer:

2. 14.42

3. 17.69

6. 12.8

9. 10.29 (I cant see your answer)

Rest is correct ;D

Step-by-step explanation:

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]y = \stackrel{\stackrel{m}{\downarrow }}{3} x + 3\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{3\implies\cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}[/tex]

so we're really looking for the equation of a line whose slope is -1/3 and that is passes through (3 , 2)

[tex](\stackrel{x_1}{3}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{- \cfrac{1}{3}}(x-\stackrel{x_1}{3}) \\\\\\ y-2=- \cfrac{1}{3}x+1\implies {\Large \begin{array}{llll} y=- \cfrac{1}{3}x+3 \end{array}}[/tex]

Answer: The answer could be 28 but I need to know what is the length and what is the height.

Step-by-step explanation:

I will just name the points for simplicity:

A - (3, -5)

B - (7, -5)

C - (7, 2)

D - (3, 3)

A to B - 4

B to C - 7

C to D -  4.1231

***

Distance (d) = √(3 - 7)^2 + (3 - 2)^2

= √(-4)^2 + (1)^2

= √17

= 4.1231056256177

***

D to A - 8

4 * 7 = 28

The volume of the cereal box is 144 square inches its width is two inches, its length is six inches and its height is 12 inches.

The top, bottom, and lateral faces of a rectangular prism are all rectangles, and all the pairs of opposing faces are congruent. A rectangular prism is a three-dimensional structure with six faces.

The rectangular prism's base area is equal to lw (using the area of a rectangle formula)

The height of the rectangle prism is equal to h.

Thus, V = lw ×h = lwh is the formula for the rectangular prism's volume.

Given,

width = 2 inches

length = 6 inches

height = 12 inches

The volume of a rectangular prism is simply length× width× height.

Volume = 6× 2× 12

= 144 square inches.

Therefore, the volume of the cereal box is 144 square inches.

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The equivalent fraction of 1 2/3 + 1 1/2 is 1 4/6 + 1 3/6

Expressions are mathematical statements that are represented by variables, coefficients and operators.

The fraction expression is given as

1 2/3 + 1 1/2

Express the mixed numbers as improper fractions

So, we have

1 2/3 + 1 1/2 = 5/3 + 3/2

Rewrite as equivalent fractions

1 2/3 + 1 1/2 = 10/6 + 9/6

Express the improper fractions as mixed numbers

So, we have

1 2/3 + 1 1/2 = 1 4/6 + 1 3/6

Hence, the value of the expression is 1 4/6 + 1 3/6

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Answer:

Domain: { -5, -1, 1, 3, 4}
Range: { -2, 1, 5}

Step-by-step explanation:
Domain = X-Values

Range = Y-Values

Every possible X-Value is the domain, and likewise with the Range.

Meaning if it was a line that went on forever through Y-1 the the Domain would be X = {-[infinity], +[infinity]} and the range would be Y = {1}

Hope this helps.

Answer:

[tex]f(x)=x^4(x-a)(x-b)^2[/tex]

Step-by-step explanation:

The graph of a polynomial function will:

The zero at the origin (0, 0) touches the x-axis and so it has an even multiplicity (exponent).  Therefore, we can immediately discount the first two answer options as both have x as a zero (x = x¹ so its exponent is odd).

The end behavior of the graphed function means the leading coefficient is positive and the degree of the polynomial is odd.

The sum of the multiplicities is the degree of the polynomial function.

[tex]f(x)=x^4(x-a)(x-b)^2 \implies \textsf{Sum of multiplicities}: 4+1+2=7[/tex]

[tex]f(x)=x^2(x-a)^5(x-b) \implies \textsf{Sum of multiplicities}: 2+5+1=8[/tex]

Therefore, the only function that could represent the given graph is

[tex]\boxed{f(x)=x^4(x-a)(x-b)^2}[/tex]

as its degree is odd and it has a zero at the origin with even multiplicity.

Answer:

19

Step-by-step explanation:

The square value of the measure of hypotenuse is equal to the square measure of sum of two legs.

Let x represent the missing leg:

[tex] {20}^{2} = {7}^{2} + {x}^{2} [/tex]

400 = 49 + x^2 subtract 49 from both sides

351 = x^2 find the root for both sides

The root of 351 is between 18 and 19 but it is closer to 19 since 19×19 = 361 and since we are asked to round to the nearest tenth the answer is 19.

Answer:

Step-by-step explanation:

(12 nights)($184) = $2208

(9 nights)($6) = $54

(6 taxi rides)($27) = $162

$2208 + $54 + $162 = $2424

We will use a ratio to calculate American dollars to pounds

2424/x = 1.83/1

Cross multiply

1.83x=2424

Divide

= ~£1324.59

£1324.59 + £1600 = £2924.59

The answer is ~2924.59 pounds

The total cost of the flights, the hotel room, the wifi, and 6 taxi journeys for Tony's holiday in Canada is approximately £2925.13.

Given that Tony is vacationing in Canada, his flight cost is £1600, he stayed for 12 nights, his hotel cost $184 per night, Tony used wifi for 9 days. Wifi cost $6 per day. Tony took a taxi 6 times costing a mean average of $27 per taxi journey.

The exchange rate was $1.83 to £1.

We need to find the total cost his spend in the vacation.

To calculate the total cost of Tony's holiday, we need to convert all the expenses to pounds and then sum them up.

Flights cost: £1600

Hotel cost per night: $184

Hotel cost for 12 nights: 12 nights x $184/night = $2208

Wifi cost per day: $6

Wifi cost for 9 days: 9 days x $6/day = $54

Taxi cost per journey (mean average): $27

Total taxi cost for 6 journeys: 6 journeys x $27/journey = $162

Now, we need to convert the costs from dollars to pounds using the exchange rate of $1.83 to £1.

Flights cost in pounds: £1600

Hotel cost in pounds: $2208 / $1.83 = £1207.10

Wifi cost in pounds: $54 / $1.83 = £29.51

Taxi cost in pounds: $162 / $1.83 = £88.52

Finally, we can calculate the total cost in pounds:

Total cost = Flights cost + Hotel cost + Wifi cost + Taxi cost

Total cost = £1600 + £1207.10 + £29.51 + £88.52

Total cost = £2925.13

So, the total cost for Tony's holiday in Canada is approximately £2925.13.

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a) Jeffrey needs an extra amount of $40,357.5 for buying a car.

b) After 20 years fund is worth $1364.

c) After 20 years $1200 interest had been earned.

a) P = $500

r = 12% = 12 ÷ 100 = 0.12

n = 12 because it was compounded 12 times in a year.

t = 5 years

Therefore,

A = 500 × [tex](\frac{1 + 0.12}{12})^{60}[/tex]

A = 500 × [tex](\frac{1 + 0.12}{12})^{60}[/tex]

A = 500 × 1.285

A = $ 642.5

Jeffrey needs an extra $40,357.5 for buying a car.

b) P = $500

r = 12% = 12 ÷ 100 = 0.12

n = 12 because it was compounded 12 times in a year.

t = 20 years

Therefore,

A = 500 × [tex](\frac{1 + 0.12}{12})^{240}[/tex]

A = 500 × [tex](\frac{1 + 0.12}{12})^{240}[/tex]

A = 500 × 2.728

A = $1364

After 20 years fund is worth $1364.

c) Simple interest = P × R × T ÷ 100

Simple interest = 500 × 12 × 20 ÷ 100

Simple interest = $1200

After 20 years $1200 interest had been earned.

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