Magnesium reacts with iron(III) chloride to form magnesium chloride (which can be used in fireproofing wood and in disinfectants) and iron. A mixture of 43.5 g Mg and 247 g iron(III) chloride is allowed to react. What is the limiting reactant and what is the mass, in grams, of the excess reactant remains

Answer:

Observational evidence is essential for investigating the way disease affects populations, the patterns and distribution of risk within them, and the emergence of trends in health and disease over time.

Answer:

It tests a prediction It supports the results. It asks a testable question It predicts what will happen

Explanation:

Answer:

after millions of years underground the compounds that make up plankton and plants turn into fossil fuels Franklin decomposes into natural gas and oil white plants become cal today humans extract these resources through coal mining and the drilling of Oil and Gas Wells on land and Offshore

Answer:

A) By decreasing the effort needed to do the work

Explanation:

The answer fam is....... A) By decreasing the effort needed to do the work

Hence the word simple Machine

Answer:

6.9428 kg of CO2

Explanation:

1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.

9.5 x 10^25 CO2 molecules[tex]x\frac{1 mole CO2}{6.022 x 10^23}[/tex] = 157.75 moles CO2

2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.

[tex]157.75moles CO2[/tex] [tex]x \frac{44.01g/mol}{1 mole CO2}[/tex] = 6942.79g

3) Convert 6942.79 grams into kilograms (divide by 1000):

6.9428 kg

Answer/Explanation:

This electrical energy now travels through the phone supplying the phone with electricity. Batteries in a cell phone supply chemical energy to electric charges. The electric charges use the energy to be put into motion.

Answer:

Other side

Opposite function

On both sides of the equation

In the numerator and not the denominator

Explanation:

To isolate a single variable when rearranging equations, move all other variables to the other side of the equation by using the opposite function on them and remembering to perform that operation on both sides of the equation. Make sure the rearrangement has the target variable in the numerator, not the denominator.

Answer:

The answer is "0.38 A".

Explanation:

Please find the missing image file in the attachment.

In the given image let:

[tex]R_{12} =R_1+R_2=16 \ \Omega \\\\R_{34} =R_3+R_4=20 \ \Omega \\[/tex]

[tex]R_P=\frac{R_{12} \cdot R_{34}}{R_{12} +R_{34}}[/tex]

     [tex]= \frac{16 \cdot 20 }{16 +20}\\\\= \frac{320 }{36}\\\\= \frac{80 }{9}\\\\= 8.88 \ \Omega[/tex]

similarly,

[tex]R_{eq} =R_p+R_5+R_6\\\\[/tex]

      [tex]=8.88+24+20\\\\=52.89 \ \Omega \\\\[/tex]

calculating the current value through a switch:

[tex]\to I=\frac{V}{R_{eq}} = \frac{20 \ v}{52.89 \Omega }=0.38\ A[/tex]

Answer:

D. 0.38 amperes

Explanation:

Got it correct on Gizmos

Gizmos explanation: This compound circuit contains two parallel branches connected in series to 2 more resistors. Each parallel branch contains 2 resistors in series. The resistance of the first branch is 5+11=16 ohms, and the resistance of the second branch is 20 ohms. Using the equivalent resistance formula, the resistance of this section is

1R=116+120=580+480=980

So R is 809, or 8.89 ohms. This is connected in series to a 24-ohm and a 20-ohm resistor, for a total resistance of 52.89 ohms. The battery voltage is 20 volts, so by Ohm's law

I=VR

I=2052.89=0.38amperes

Answer:

Molecules along the surface of a liquid behave differently than those in the bulk liquid.

Cohesive forces attract the molecules of the liquid to one another.

Water forming a droplet as it falls from a faucet is a primary example of surface tension.

Explanation:

Surface tension is the force that stretches the liquid surface. This force acts normal to the surface. It is the downward force that acts on the surface of the liquids which is due to the cohesive forces of the liquids.

The water molecules are bonded by a strong hydrogen bond force which is between hydrogen atom and the electronegative oxygen atom. At the surface the water molecules are attracted strongly by other water molecules which lies below the surface and are stretched at the surface. Thus the water molecules at the surface acts differently than in the bulk liquid.

Mercury have a strong cohesive force than the water and have a higher surface tension force than the water.

Surface water acquires minimum surface area, hence acquiring spherical shape of water.

Answer:

4.71 g of sodium and 7.25 g of chlorine

Explanation:

Note: The question is incomplete. the complete question is given below:

Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?

4.71 g of sodium and 3.30 g of chlorine

4.71 g of sodium and 7.25 g of chlorine

4.71 g of sodium and 1.31 g of chlorine

4.71 g of sodium and 13.7 g of chlorine

The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.

This means that irrespective of the source of any sample of a pure chemical compound, the constituents elements are always combined in the same mass ratio.

In the first sample, the mass ratio of Sodium to chlorine is given below:

mass of sodium = 2.55 g

mass of chlorine = 3.93 g

mass ratio; sodium to chlorine = 2.55 / 3.93 = 0.65

From the set of masses give above, we can determine the result of the decomposition of the second sample.

4.71 g of sodium and 3.30 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 3.30 = 1.43

4.71 g of sodium and 7.25 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 7.25 = 0.65

4.71 g of sodium and 1.31 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 1.31 = 3.59

4.71 g of sodium and 13.7 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 13.7 = 0.34

From the results above, the correct set of masses for the second sample is 4.71 g of sodium and 7.25 g of chlorine

Answer:

1.2×10² mmole of Na₂S₂O₃

Explanation:

From the question given above, the following data were obtained:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity is simply defined as the mole of solute per unit litre of water. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the number of mole of Na₂S₂O₃ in the solution as illustrated below:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity = mole /Volume

0.2 = Mole of Na₂S₂O₃ / 0.6

Cross multiply

Mole of Na₂S₂O₃ = 0.2 × 0.6

Mole of Na₂S₂O₃ = 0.12 mole

Finally, we shall convert 0.12 mole to millimole (mmol). This can be obtained as follow:

1 mole = 1000 mmol

Therefore,

0.12 mole = 0.12 mole × 1000 mmol / 1 mole

0.12 mole = 120 = 1.2×10² mmole

Thus, the chemist added 1.2×10² mmole of Na₂S₂O₃

Answer:

yes

Explanation:

yes

Answer: The specific heat of the metal in [tex]1.34J/g^0C[/tex]

Explanation:

[tex]Q_{absorbed}=Q_{released}[/tex]

As we know that,  

[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]

[tex]m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)][/tex]      

where,

[tex]m_1[/tex] = mass of metal = 31.7 g

[tex]m_2[/tex] = mass of water = 100.0 g

[tex]T_{final}[/tex] = final temperature = [tex]24.6^oC[/tex]

[tex]T_1[/tex] = temperature of metal = [tex]96.5^oC[/tex]

[tex]T_2[/tex] = temperature of water = [tex]17.3^oC[/tex]

[tex]c_1[/tex] = specific heat of metal= ?

[tex]c_2[/tex] = specific heat of water =  [tex]4.184J/g^0C[/tex]

Now put all the given values in equation (1), we get

[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex]

[tex]-(31.7\times c_1\times (24.6-96.5)^0C)=(100.0\times 4.184\times (24.6-17.3)][/tex]

[tex]c_1=1.34J/g^0C[/tex]

Therefore, the specific heat of the metal in [tex]1.34J/g^0C[/tex]

Answer:

It would be 151.832775 because one mole is 44.0095*3.45 i hope this helps!

Explanation:

Answer:

Kinetic; attraction; attraction.

Explanation:

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.

In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

Hence, as the temperature of a substance increases, the average kinetic energy of the particles also increases, and movement overcomes forces of attraction more easily. As temperature decreases particles move more slowly and the attraction-forces between particles dominate.

In conclusion, when a substance or an object is heated, a phase change starts to occur only when the average kinetic energy of its particles is great enough to overcome the force of attraction between its particles.

Answer:

decreases a bit then stays constant

Explanation:

Answer:

negative charge

Explanation:

protons have a positive, nuetrons have a neutral charge , and electrons have a negative.

Answer:

Explanation:

Weight = mass x gravity

mass given = 85 kg

gravity = 8.87 m /s²

Weight = 85 x 8.87 = 753.95 N .

Weight on Uranus = 753.95 N .

Answer:

The maximum mass of carbon dioxide, CO₂ produced is 2.64 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

Next, we shall determine the masses of C₈H₁₈ and O₂ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₈H₁₈ = (8×12) + (18×1)

= 96 + 18

= 114 g/mol

Mass of C₈H₁₈ from the balanced equation = 2 × 114 = 228 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 25 × 32 = 800 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 16 × 44 = 704 g

SUMMARY:

From the balanced equation above,

228 g of C₈H₁₈ reacted with 800 g of O₂ to produce 704 g of CO₂.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

228 g of C₈H₁₈ reacted with 800 g of O₂.

Therefore, 3.43 g of C₈H₁₈ will react with = (3.43 × 800)/228 = 12.04 of O₂

From the calculations made above, we can see that a higher mass (i.e 12.04 g) of O₂ than what was given (i.e 3 g) is needed to react completely with 3.43 g of C₈H₁₈. Therefore, O₂ is the limiting reactant and C₈H₁₈ is the excess reactant.

Finally, we shall determine the maximum mass of carbon dioxide, CO₂ produced from the reaction.

To obtain the maximum mass of carbon dioxide, CO₂ produced, the limiting reactant will be used because all of it is consumed in the reaction.

The limiting reactant is O₂ and the maximum mass of carbon dioxide, CO₂ produced can be obtained as follow:

From the balanced equation above,

800 g of O₂ reacted to produce 704 g of CO₂.

Therefore, 3 g of O₂ will react to produce = (3 × 704)/800 = 2.64 g of CO₂.

Thus, the maximum mass of carbon dioxide, CO₂ produced is 2.64 g

Answer:

C₃H₉N

Explanation:

The empirical formula of a compound is the fundamental and basic possible formula that shows the mole ratio of the atoms of each element in a molecule of the compound.

mole ratio of carbon = 60.94/12 = 5.078

mole ratio of hydrogen = 15.36/1  = 15.36

mole ratio of nitrogen = 23.70/14 = 1.693

Now; we will divide by the smallest value

So; carbon = 5.078/1.693 = 2.99 ≅ 3.0

hydrogen = 15.36/1.693 = 9.07 ≅ 9.0

nitrogen = 1.693/1.693 = 1 ≅ 1

Thus,  the empirical formula is = C₃H₉N

Answer:

0.03 tons

Explanation:

From the given information, for every 0.500 tons of A and B, the maximum amount on weighing them will be:

1% of 0.5 = 0.005

Thus, for 2 tons of A; we have:

0.005 × 4 = 0.02

and, for 1 ton of B; we have:

0.005 × 2 = 0.01

However, after taking the precision into account;

The number of tons of A that reacted is = (2 - 0.002) = 1.98 tons of A

The number of tons of B that reacted is = ( 1 - 0.01) = 0.99 tons of B

So, 1.98 tons of A reacted with 0.99 tons of B to form 0.99 tons of C.

∴

For unreacted reactants, The maximum possible amount is (0.02 + 0.01) tons = 0.03 tons

Answer:

Part. press. NO₂ in equilibrium is 0.590 atm

Explanation:

First of all, we determine the equilibrium:

N₂O₄ (g) ⇄ 2NO₂ (g)

These is a system of two unknown values.

In the begining we have x pressure of N₂O₄ and no value for NO₂.

During the reaction, y pressure has been released from N₂O₄. As ratio is 1:2, 2y will be the value for the pressure of NO₂. So in the equilibrium we have:

N₂O₄ → x - y

NO₂ → 2y

Data from the excersise states that the total pressure is 1 atm so we know that the sum of partial pressures in a mixture, will be the total one. In the equilibrium, total pressure will be:

(x-y) + 2y = 1 atm

x + y = 1 atm

Let's make the expression for Kp

Kp =  [Partial pressure NO₂]² / [ Partial pressure N₂O₄]

Kp = (2y)² / (x-y)

Kp = 4y² / (x-y)

We split the x value in the first equation:

x + y = 1 atm

x = 1 atm - y

x = 1 - y → we put this in the Kp expression

0.85 = 4y² / ( 1 - y - y)

0.85 = 4y² / 1 -2y

This is a quadractic equation

0.85 - 1.7y - 4y² = 0 where (a = -4, b = -1.7 c = 0.85)

(-b +- √(b² - 4ac)) / (2a)

(1.7 +-√((-1.7)² - 4 (-4) . 0.85) / 2 .(-4) → 0.295 = y

As [ Part. press. NO₂] in equilibrium is 2y → 0.295 . 2 = 0.590 atm

Based on the total pressure at equilibrium, the partial pressure NO₂ of at equilibrium is 0.590 atm.

From the equation of the reaction, the equilibrium is determined:

At equilibrium, N₂O₄ and NO₂ exist in the ratio 1 : 2.

N₂O₄ at x pressure releases y pressure to form NO₂ .

Thus at equilibrium:

N₂O₄ → x - y

NO₂ → 2y

Ptotal = 1 atm

Thus:

(x-y) + 2y = 1 atm

x + y = 1 atm

Also, Kp = 0.85

From the equation of the reaction:

Kp =  [Partial pressure NO₂]² / [ Partial pressure N₂O₄]

Kp = (2y)² / (x-y)

Kp = 4y² / (x-y)

Solving for x from the first equation:

x + y = 1 atm

x = 1 atm - y

Substitute x = 1 - y in the Kp expression

0.85 = 4y² / ( 1 - y - y)

0.85 = 4y² / 1 -2y

0.85 - 1.7y - 4y² = 0

Solving the quadractic equation:

where a = -4, b = -1.7 c = 0.85

y = (-b +- √(b² - 4ac)) / (2a)

y =(1.7 +-√((-1.7)² - 4 (-4) × 0.85) / 2 × (-4)

y = 0.295 or y = -0.720

We take positive value of y only.

Since partial pressure of NO₂ in equilibrium is 2y

Partial pressure of NO₂ = 0.295 × 2

Partial pressure of NO₂ = 0.590 atm

Therefore, the partial pressure of at equilibrium is 0.590 atm.

Learn more about about equilibrium partial pressure at: https://brainly.com/question/7183826

Answer:

Typical injury mechanism: Direct impact on the head is by far the most common mechanism of concussion. It may be caused by stable objects such as the floor or objects in motion (such as baseball bats or hockey sticks).

Answer:

[tex]M_{HCl} = 1.12M[/tex]

Explanation:

Hello!

In this case, for the first reaction we need to focus on, the neutralization of magnesium hydroxide by phosphoric acid, we can write up the following equation:

[tex]3Mg(OH)_2+2H_3PO_4\rightarrow Mg_3(PO_4)_2+6H_2O[/tex]

Whereas the acid and base react in a 3:2 mole ratio; thus, we can write:

[tex]2M_{Mg(OH)_2}V_{Mg(OH)_2}=3M_{H_3PO_4}V_{H_3PO_4}[/tex]

Now, solving for the concentration of the magnesium hydroxide solution we get:

[tex]M_{Mg(OH)_2}=\frac{3M_{H_3PO_4}V_{H_3PO_4}}{2V_{Mg(OH)_2}} \\\\M_{Mg(OH)_2}=\frac{3*0.20M*0.0300L}{2*0.050L}=0.18M[/tex]

Now, for the reaction between hydrochloric acid and magnesium hydroxide we have:

[tex]Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O[/tex]

[tex]2M_{Mg(OH)_2}V_{Mg(OH)_2}=M_{HCl}V_{HCl}[/tex]

Therefore, solving for the concentration of the hydrochloric acid solution we get:

[tex]M_{HCl}=\frac{2M_{Mg(OH)_2}V_{Mg(OH)_2}}{V_{HCl}} \\\\M_{HCl}=\frac{2*0.18M*0.078L}{0.025L}\\\\M_{HCl} = 1.12M[/tex]

Best regards!

Answer:

Mass =  142.25 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Number of moles of Ca(OH)₂ = 1.92 mol

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of Ca(OH)₂ = 74.09 g/mol

by putting values,

Mass = 1.92 mol × 74.09 g/mol

Mass =  142.25 g

Answer:

See explanation

Explanation:

Synthesis reaction and decomposition reactions are two opposing processes.

While a synthesis reaction has to do with the formation of a substance from its constituents, decomposition deals with the breakdown of a substance into its constituents.

While decomposition requires energy and is an endothermic process, synthesis is usually an exothermic process in which energy is given off as stable products are formed.

Answer:

Explanation:

From the information given;

Consider using Lande's Interval rule which can be expressed as:

[tex]\Delta E = E_{j+1} - E_jj \ = \alpha (j+1)[/tex]

here;

[tex]j+1[/tex]  = highest level of j

and

[tex]\dfrac{\Delta E_1}{\Delta E_2} = \dfrac{(j+2)}{(j+1)}[/tex]

[tex]\dfrac{5}{3} = \dfrac{(j+2)}{(j+1)}[/tex]

[tex]5(j+1) = 3(j+2)[/tex]

[tex]5j+5 = 3j+6[/tex]

[tex]2j = 1\\ \\ j = \dfrac{1}{2}[/tex]

recall that:

[tex]j = |S-L| \ \to \ |S+L |[/tex]

So;

[tex]S-L = \dfrac{1}{2} --- (1)[/tex]; &

[tex]S+L = \dfrac{5}{2} --- (1)[/tex]

Using the elimination method, we have:

[tex]2S = \dfrac{6}{2}[/tex]

[tex]S = \dfrac{3}{2}[/tex]

Since [tex]S = \dfrac{3}{2}[/tex]; then from (1)

[tex]\dfrac{3}{2} -L = \dfrac{1}{2}[/tex]

[tex]L = \dfrac{2}{2}[/tex]

[tex]L = 1[/tex]