look at the picture
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Answer:

1368.9 [gr].

Explanation:

1. the formula of the required mass is:

m=Mν, where M=[gr/mol] and ν=[moles];

2. M=M(NaCl)=M(Na)+M(Cl)=23+35.5=58.5 [gr/mol];

ν=23.4 [moles] according to the condition, then

3. the required mass:

m=23.4*58.5=1368.9 [gr].

Plastic items are not biodegradable and contaminate the environment, petroleum is a non-renewable resource, and processing and consuming petroleum emits toxins into the environment.

We refer to a substance as being biodegradable if it can be naturally broken down by living things in an environment. Simply explained, the term "biodegradable" refers to a substance that gradually deteriorates into smaller parts like gases and sugar. Microorganisms, such as fungi and bacteria or microbes to be reabsorbed by the surrounding environment, ideally without generating any pollutants, are responsible again for biodegradation.

Examples of biodegradable materials that microbes can break down include food and paper waste.

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a) The percentage of presence in nature of 1st 2nd and 3rd isotopes is 92.2% 4.7 %  and 3.1 %.

b) The chemical symbol for isotopes is ²⁸Si , ²⁹Si , ³⁰Si.

Element with atomic number 14 silicon . chemical symbol is Si.. Four isotopes of silicon's occur in natural environment-  ²⁸Si , ²⁹Si , ³⁰Si ³²Si. The ²⁸Si , ²⁹Si , ³⁰Si is stable isotopes. And the fourth one ³²Si is radiogenic. Silicon atom have mass of 28 amu. ²⁸Si is the most abundant isotope of silicon has percentage of 92.2% . ²⁹Si is 4.7 % and the third is ³⁰Si is 3.1 %.

Thus, An unknown element Y with atomic number 14 is found in nature as a mixture of three isotopes. isotopes 28 has percentage of 92.2 % and isotopes 29 which has percentage of 4.7 %.the third isotopes is 30.

a) The percentage of presence in nature of 1st 2nd and 3rd isotopes is 92.2% 4.7 %  and 3.1 %.

b) The chemical symbol for isotopes is ²⁸Si , ²⁹Si , ³⁰Si.

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To determine the level of radionuclides present is the best reason for consulting with a nuclear chemist before building the processing plant.

The level of radionuclides refers to the concentration in the atmosphere of radioactive compounds, which may be harmful to humans and therefore theirs levels should be monitored in order to maintain well being, especially in nuclear plants where they can be dangerous to the environment.

Therefore, we can conclude that it is required to know the level of radionuclides that are present in a processing plant.

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Answer:a

Explanation:

The number of copper atoms are in 5.33mol CuCl2 =5.33 ​ × 6.023 × 1023 = 3.21 × 1024

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The balanced equation of the reaction is:

Balanced equations are equations in which the moles of atoms on the right-hand side of the equation are equal to the moles of atoms on the left-hand side of the equation.

Balanced equations ensure that the law of the conservation of mass is obeyed such that the mass of reactants is equal to the mass of the products.

In balancing a chemical equation, the following steps are followed:

Considering the given reaction:

In the reaction, methane gas reacts with chlorine gas to produce tetrachloromethane and hydrogen chloride gas.

The balanced equation of the reaction is given below as follows:

CH₄ (g) + 4 Cl₂ (g) ---> CCl₄ (l) + 4 HCl (g)

The reaction is a substitution reaction in which chlorine atoms substitute hydrogen atoms in the methane gas molecule.

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In given ionic compound, Mg(ClO4)2 anion is ClO4⁻, NH4NO³ anion is (NO3)⁻, Cu(CH3CO2)² anion is [CH3COO]⁻, K2SO³ anion is SO3²⁻.

Positively charged ions are known as cations. Ions with negative charges are referred to as anions. A charged molecule or an atom is an ion. A balanced atom will change into a positively charged cation if one or more of its electrons are lost.

When non-metals gain electrons, they are created. They don't lose any protons and gain one or more electrons. They get a negative net charge as a result. The anions iodide (I-), chloride (Cl-), and hydroxide are some examples (OH–).

Anion exchange device applications. They lower the levels of nitrate, arsenic, and sulfate in water. Point-of-use units only filter harmful chemicals out of drinking and cooking water and are connected to a single tap.

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A mass of 0.141 g Ca(OH) is present in a sample if it is  titrated to its equivalence point with 44.02 mL of HNO3.

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0.5 mL of serum with 1/20 dilution will be equivalent to 10 mL of the diluted serum.

A 1/20 dilution means 1 part of the original solution and 19 parts of the solvent that is being used to dilute.

Now, a 1/20 dilution of a 0.5 mL serum means that the 1 part of the stock solution is 0.5 mL. The remaining 19 parts would be in multiples of 0.5 mL.

         19 x 0.5 = 9.5 mL.

This means that 9.5 mL of the diluting solvent will be added to 0.5 mL of the stock solution resulting in a total of 10 mL.

In order words, 1/20 dilution of 0.5 mL of serum will make a total volume of 10 mL.

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Based on the half-lives of the given materials:

The half-life of a substance is the time taken for half the amount present in the original sample of a substance to decay.

The half-life of a substance is constant.

Considering the given questions:

1. the half life of radium-226 is 1,600 years, how long will it take for 93.75% of a sample of radium-226 to decay?

The amount of remaining after 93.75% have decayed = 100 - 93.75 = 6.25%

The number of half-lives that will result in 6.25 % remaining will be:

After first half life = 50% remains

After second half life = 25% remains

After third half life = 12.5% remains

After fourth half life = 6.25% remains

Number of years taken = 4 * 1600

Number of years taken = 6400 years

2. Sodium-24 has a half life of 15 days. What fraction of the original amount of sodium-24 will remain in a sample after 105 days?

Number of half lives after 105 days = 105/15

Number of half lives after 105 days = 7 half lives

Fraction remaining = (¹/₂)⁷

Fraction remaining = 0.78 %

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Answer:

Explanation:

6.78 kg

An object that weighs 10.045 g at room temperature may end up weighing 10.16g when it becomes very cold since the weight will increase slightly.

The relationship between density and temperature is inversely proportional. As the temperature of a substance decreases, the weight of the substance increases, vice versa.

During the process of decrease in temperature, the molecules of the object  come together and becomes very dense, hence increase in the weight of the object.

As the temperature increases, the molecules of the object moves further apart becoming less dense, hence the decrease in the weight of the object.

Thus, an object that is initially at room temperature will weight more when the temperature decreases.

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According to the research, the correct answer is All atoms of a given element must have the same number of protons, neutrons, and electrons. It is the statement about atoms that is NOT correct.

It is a particle that consists of a central nucleus, positively charged with protons and neutrons, in which practically all the mass of the atom is concentrated.

In this sense, in the outer zone are the electrons, which occupy orbits, whose number varies according to the chemical element, also in a given element it can have a different number of neutrons.

Therefore, we can conclude that atoms are distinguished from each other thanks to the configuration of their particles, it is also true that all atoms of the same element are exactly the same, where the number of neutrons can vary.

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0.9541 grams of nickel (ii) hydroxide will be produced if 30.4 mL of 0.673 M KOH react completely and 1.3764 grams of nickel (ii) hydroxide will be produced if the 17.6 mL of 0.841 M NiCl₂ react completely.

According to the balanced chemical equation,

2KOH (aq) + NiCl₂ (aq) → 2 KCI (aq) + Ni(OH)₂ (S)

a. 2 Moles of KOH = one mole of Ni(OH).

As we know,

Molarity = moles/amount of solution(in liters)

For KOH,

0.675 = moles/0.0304

Moles of KOH = 0.02052.

Moles of Ni(OH) = 0.02052/2

Moles of Ni(OH) = 0.01026

We also know,

Moles = formed mass/molar mass

Molar mass of NiOH = 93 grams/mole

0.01026 = formed mass/93

Formed mass of NiOH = 0.9541 grams.

b. 1 Mole of NiCl₂ = one mole of Ni(OH).

As we know,

Molarity = moles/amount of solution(in liters)

For NiCl₂,

0.841 = moles/0.0176

Moles of NiCl₂ = 0.01480

Moles of Ni(OH) = 0.01480

We also know,

Moles = formed mass/molar mass

Molar mass of NiOH = 93 grams/mole

0.01480 = formed mass/93

Formed mass of NiOH = 1.3764 grams.

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Taking into account the reaction stoichiometry, if 42.9 g of iron is reacted with 27.5 g of oxygen, 61.335 grams of iron(III) oxide are produced.

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 96 grams of O₂ reacts with 223.4 grams of Fe, 27.5 grams of O₂ reacts with how much mass of Fe?

mass of Fe= (27.5 grams of O₂× 223.4 grams of Fe)÷ 96 grams of O₂

mass of Fe= 63.995 grams

But 63.995 grams of Fe are not available, 42.9 grams are available. Since you have less mass than you need to react with 27.5 grams of O₂, Fe will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 223.4 grams of Fe form 319.4 grams of Fe₂O₃, 42.9 grams of Fe form how much mass of Fe₂O₃?

mass of Fe₂O₃= (42.9 grams of Fe×319.4 grams of Fe₂O₃)÷ 223.4 grams of Fe

mass of Fe₂O₃= 61.335 grams

Then, 61.335 grams of Fe₂O₃ are produced.

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The balanced net ionic equation for the reaction is given below:

Pb²⁺ (aq) + S²⁻ (aq) → PbS (s)

Ionic equations are equations that show the ionic species involved i a reaction.

The ionic species in the reaction may undergo reduction or oxidation.

Therefore, ionic equations are usually redox reactions.

In balancing ionic equations, the atoms and the electrons involved in the reaction are balanced on both sides.

Considering the given ionic equation:

Pb²⁺ (aq) + S²⁻ (aq) → PbS (s)

The given equation above is a balanced net ionic equation both in electron transfer as well as in the number of atoms.

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Ionization energy is the minimum energy required to remove an electron from an isolated atom in the gaseous state, that is, in its ground state.

At the periodic table, we can see that there is a pattern for the first ionization energy.

It increases from bottom to top in a group, and from left to right in a period.

So:

Argon and Helium are on the far right of the periodic table, while sodium and potassium are on the far left.

So Argon and Helium have the highest ionization energy in comparison to Potassium and Sodium.

Between Argon and Helium, Helium is above argon in the periodic table, this means that helium has the highest ionization energy.

Answer: Helium

The Net force is 20.12 N  and acts in a direction 26.56° South of East.

A net force is a force that is the vector sum of all the forces acting on an object.

The net force is also known as the resultant force.

The net force produces the same effect as all the forces acting together on an object.

The net force of the given forces in the diagram is calculated as follows:

The forces acting on the object are an 18 N force acting in a direction to the east and a 9 N force acting vertically downward in a direction south of the object.

The two forces form two sides of a right angle triangle.

Net force is calculated using Pythagoras' rule:

Net force = √ (18² + 9²)

Net force = √ (324 + 81)

Net force = √ 405

Net force = 20.12 N

The direction of the Net force = tan⁻¹ (9 / 18)

The direction of the Net force = tan⁻¹ 0.5

The direction of the Net force = 26.56° South of East

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The maximum amount of sulfur dioxide (SO₂) that can be formed is 25.6 g.

The formula for the the limiting reagent is CO

The amount of excess reagent that remains after the reaction is 3.6 g.

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

The limiting reagent is determined by balancing the chemical equation as follows;

S + 2CO  --------> SO₂ +  2C

From the reaction above;

1 mole of sulfur = 2 mole of carbon monoxide = 1 mole of sulfur dioxide

56 g of carbon monoxide (CO)  = 64 g of sulfur dioxide (SO₂ )

22.4 g of CO = ? of SO₂

= (22.4 x 64)/56

= 25.6 g of SO₂

Thus, the maximum amount of sulfur dioxide (SO₂) that can be formed is 25.6 g.

The formula for the the limiting reagent is CO because it will be completely used up.

56 g of CO = 32

22.4  of CO  = ?

= (22.4 x 32)/56

= 12.8 g

Excess mass of the sulfur that remains = 16.4 g - 12.8 g = 3.6 g

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The  frequency of light is the ratio of speed to the wavelength. Then, the frequency of range light with the wavelength of 605 nm is 4.95 × 10¹⁴ Hz.

Frequency of light refers to the number of waves of electromagnetic radiation (such as light) that pass a given point per second. It is typically measured in Hertz (Hz), which represents the number of cycles per second.

The frequency of light determines its color and is directly related to its energy. Light with higher frequency has more energy and shorter wavelengths, while light with lower frequency has less energy and longer wavelengths.

Speed of light = 3 × 10⁸ m/s

wavelength = 605 nm = 605 × 10⁻⁹ m.

then frequency =  3 × 10⁸ m/s / 3 × 10⁸ m/s = 4.95 × 10¹⁴ Hz

Therefore, the frequency of the orange light is 4.95 × 10¹⁴ Hz.

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A standard electrode potential is required in order to determine the reduction potential of a half-unique cell. The standard hydrogen electrode is used as a reference electrode for the measurement

A standard electrode potential is required in order to determine the reduction potential of a half-unique cell. The standard hydrogen electrode is used as a reference electrode for the measurement (abbreviated to SHE). SHE has an electrode potential of zero volts.

By deducting the standard reduction potential for the reaction occurring at the cathode from the standard reduction potential for the reaction occurring at the anode, the standard reduction potential can be computed. Because oxidation is the polar opposite of reduction, the minus sign is required.

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Answer:

107 g

Explanation:

The theoretical yield of All3 obtain from the reaction is 121g.

2Al + 3I₂ —> 2AlI₃

Molar mass of I₂ = 2 × 127 = 254 g/mol

Molar mass of I₂ from the equilibrium equation = 3 × 254 = 762 g

Molar mass of AlI₃ = 27 + (3 × 127) = 408 g/mol

Mass of AlI3 from the equilibrium equation = 2 × 408 = 816 g

762 g I₂

From the balanced formula above,

762 g I 2 is The reaction produced by 816 g of All3.

From the balanced equation above,

gives 762 g of I2, which reacts to form 816 g of AlI3 121g.

Convert grams to moles using molar ratios to crosslink products and reactants and convert moles back to grams. Calculated on a stoichiometric basis. Actual yield is determined experimentally. The yield rate is determined by calculating the ratio of actual yield/theoretical yield.

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Explanation:

Molality is the ratio of the amount of substance of a solute (in moles – n) to the mass in kilograms of the solvent (m).

The symbol for molality is usually W and it can be calculated by the following formula:

W = n/m

here, we need to calculate n of NaCl using the formula:

n = m/MM

where MM of NaCl is 58.5 g/mol

n = 120/58.5

n = 2.05 moles

W = 2.05/30

W = 0.068 mol/Kg

Answer: A) 0.068

The substances would look as follows;

Let us recall that just like solids, the density of the solids is important in the determination of how the mixture of the substances would appear. The substances that are denser would tend to appear below while the substances that are less dense would tend to appear above.

Let us remind ourselves the densities of each of the substances as a hep to where we are going;

Water - 1 g/cm³

Mercury - 5.43 g/cm³

Kerosene - 0.82 g/cm³

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From the data provided and the equation of reaction:

The maximum amount of the product that can be formed is calculated from the equation of reaction as follows:

From the equation of reaction, the mole ratio of hydrogen to nitrogen is 3 : 1

From the given data:

mass of hydrogen reacting = 4.65 grams

mass of nitrogen reacting = 4.67 grams

The moles of the reactants is determined as follows:

molar mass of hydrogen gas = 2.0 g

molar mass of nitrogen gas = 28.0 g

Moles of hydrogen = 4.65/2 = 2.325 moles

Moles of nitrogen = 4.67/28 = 0.1667 moles

mole ratio of hydrogen to nitrogen is 2.325 : 0.1667 = 14 : 1

The limiting reagent is nitrogen while the excess reagent is hydrogen.

The formula of nitrogen is N₂.

Hence, the maximum moles of ammonia (NH₃ ) that can be formed is 0.1667 moles.

mass of ammonia formed = 0.1667 * 17 grams

mass of ammonia formed = 2.83 g

The moles of the excess reagent remaining after the reaction is complete = 2.335 - (0.1667 * 3) = 1.835

moles of the excess reagent remaining = 1.825 moles

mass of the excess reagent remaining = 1.825 * 2

mass of the excess reagent remaining = 3.65 grams

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The volume of the cube that has an edge length of 0.017m is 4.9 × 10-⁶m³.

Volume is a three-dimensional measure of space that comprises a length, a width and a height. It is measured in units of cubic centimeters in metric, cubic inches or cubic feet.

The volume can be calculated by multiplying the length, breadth and height of a three-dimensional shape such as cube.

According to this question, a cube has an edge length of 0.017m. The volume can be calculated as follows:

Volume = 0.017 × 0.017 × 0.017

Volume = 0.000004914

Volume = 4.9 × 10-⁶m³

Therefore, 4.9 × 10-⁶m³ is the volume of the cube

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The balanced chemical equation of the chemical reaction of hydrogen and oxygen is:

2 H₂ (g)  + O₂ (g)  →  2H₂O (l)

A balanced chemical equation is an equation in which the number of atoms of each element on the left side of the arrow (reactant side) is equal to the number of atoms of each element on the right side (product side) of the arrow.

A chemical equation is a way to express the chemical reaction in terms of symbols of the substances. It is very important that a balanced chemical equation must obey the law of conservation of mass.

By following the law, the total mass of the elements left side or reactant side should be equal to the total mass of elements on the right side (product side) in a balanced chemical equation.

Given, the chemical reaction of the water formation is as follows:

H₂ (g)  + O₂ (g)  →  2H₂O (l)

The number of oxygen on both sides is equal but the number of hydrogens is unequal. So multiply the hydrogen gas on the left side by 2.

So the balanced chemical equation of water formation becomes:

2 H₂ (g)  + O₂ (g)  →  2H₂O (l)

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Answer:

Explanation:

Here's a quick review of the types of reactions.
Synthesis:
Two or more chemicals combine to make a new one.
Ie: A+B => AB or A+B => C

Decomposition:
The opposite of synthesis.
Ie: AB => A+B, C => A+B

Combustion:
Usually something reacting with oxygen. That something usually being a carbohydrate.
Ie: CH4 + 2O2 => CO2 + 2H2O

Single replacement:
One atom or molecule of a compound is knocked out of place and replaced by another chemical
Ie: A+BC => AB + C (note how the bond between B and C break while a bond between A and B form)

Double replacement:
A little like a single replacement, but two bonds break and two new bonds form between two reactants.
Ie: AB+CD => AC+BD

The actual answer

The first equation (2C3H7OH + 9O2....)
Is a combustion reaction because it contains oxygen and the oxygen is oxidizing something.

The second equation (2Al + 3 ZnCl2...)
Is a single replacement reaction because only one type of bond is being broken (the Zn---Cl bond) and only another one type of bond is formed (The Al---Cl bond)

The third equation (NaCl + AgNO3...)
Is a double replacement reaction because two types of bonds are being broken (Na---Cl and Ag---NO3) and two new bonds are forming (Ag---Cl and Na---NO3)

The fourth equation (N2H8CO3...)
Is a decomposition reaction because there is only one reactant and it is splitting into multiple pieces

The fifth equation (2Al + 3Br2...)
Is a synthesis reaction because two elements/ compounds are being combined to make a singular new compound

Answer: what?

Explanation:

Answer: Huh?

Explanation: