look at the picture above

Answer:

226 feet

Step-by-step explanation:

264^2 + 900^2= c^2

879696= c^2

938= c

900+ 264= 1164

1164- 938= 226

I think this is right

Answer:

25 Fiction books were sold.

Step-by-step explanation:

The total number of books is 60 books in all.

Answer:

Step-by-step explanation:Total number of books sold altogether in the end is 3040.Step-by-step explanation:A book shop sold fiction books and cartoon books at a ratio of 3:5. ... Then, it sold four times as many fiction books and 40% ... 28 fiction books sold 7 non fiction books are sold D. For every 35 fiction books are sold 11 ...

Answer:

2 1/2 < 28/10

Step-by-step explanation:

28/10 simplifies to 2 8/10 which simplifies to 2 4/5

Answer:

a)

Step-by-step explanation:

a)140cm3-60cm3=60cm of solid C

Answer:

a = 480 b = 35

Step-by-step explanation

:) dont forget correct units

Answer:

1m----------3.28084ft

400m---------xft

x=(400*3.28084)/1

x=1,312.33 ft

Step-by-step explanation:

Answer:

Use the Pythagorean theorem.  The answer should be 3.61.

Step-by-step explanation:

Answer:

$110

Step-by-step explanation:

The first step would be to multiply 11 and 5 to get the result of 55.

Then, you would multiply 55 by whatever the cost per square yard is, which in this case is $2.

Finally after multiplying 55 and 2 you would get the answer of $110.

Hope this helped! Have a great day! :)

Answer:

2, 4, and 6

Step-by-step explanation:

Supplementary angles are angles that add to 180°.

We can see that the angles that make a straight line/straight angle with ∠7 are supplementary to it, because a straight line is 180°.

Those numbers would be be 2, which equals to 4, which equals to 6 and also 8, but that number isn't one of the answers

2,4, and 6

Answer:

The answers to these equations are 4 for the left math problem, 4 for the middle math problem, and 10 for the right math problem.

Step-by-step explanation:

Answer above.

Answer:

x = 14

Step-by-step explanation:

Given

[tex]\frac{2}{5}[/tex] x - [tex]\frac{3}{2}[/tex] = [tex]\frac{1}{4}[/tex] x + [tex]\frac{3}{5}[/tex]

Multiply through by 20 ( the LCM of 5, 2 and 4 ) to clear the fractions

8x - 30 = 5x + 12 ( subtract 5x from both sides )

3x - 30 = 12 ( add 30 to both sides )

3x = 42 ( divide both sides by 3 )

x = 14

Answer:

76

Step-by-step explanation:

450/100 = 4.5

342/4.5 = 76

Answer:

The regular price r of a museum ticket before the discount is $60

Step-by-step explanation:

What is discount?

Discount is a reduction made from the gross amount or value of something.

What is regular price?

Regular price means the price at which similar goods or services are regularly sold on the market.

Given,

[tex]54=0.9r\\r=54/0.9\\r=60[/tex]

The regular price r is $60

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Answer:

The regular price r of a museum ticket before the discount is $60

Step-by-step explanation:

hope this helps

Answer:

Yes, that model is a function.

Step-by-step explanation:

A technical definition of a function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

And the model shows that each domain ( x ) only goes to one codomain ( y )  which is what a function is.

Answer:

-375+500d-125c

-125c+500d-375

Answer:

Step-by-step explanation:

6500 is the correct answer

Answer:

you eat 1 chip

Step-by-step explanation:

eat 1 chip and you get 31 oz

Answer:

For question #2 about Teresa, it would cost her $1,004.80 to fence all around the circle garden.

Step-by-step explanation:

C = 2πr

C = 2 x 3.14 x 8

C = 50.24 ft.

50.24 x $20 = $1,004.80

Answer:OC

Step-by-step explanation:

Answer:

a. $90,000

b. 15 advertisement slots

c. 0.53

Step-by-step explanation:

Let the purchase price of the slots, c = 4,500

The salvage value of the slots, s = 2,000

The selling price of the slots, p = 8,000

a. If the store manager sells all the advertising slots in advance, the revenue received, 'R', is given as follows;

R = The number of slots, n × The purchase price for selling immediately, c

∴ R = 20 × $4,500 = $90,000

The revenue the station will receive by selling all the advertising slots in advance, R = $90,000

b. The Cost of Overage, [tex]C_o[/tex] = Purchase price - Salvage value

∴ The Cost of Overage, [tex]C_o[/tex] = 4,500 - 2,000 = 2,500

The Cost of Underage, [tex]C_u[/tex] = Selling price - Purchase price

∴ The Cost of Underage, [tex]C_u[/tex] = 8,000 - 4,500 = 3,500

P; 0.03, 0.05, 0.1, 0.15, 0.2, 0.15, 0.1, 0.05, 0.05, 0.05, 0.05, 0.02

With help of MS Excel, we get the following cumulative frequency

F(Q); 0.03, 0.08, 0.18, 0.33, 0.53, 0.68, 0.78, 0.83, 0.88, 0.93, 0.98, 1

The expected monetary value for the decision to sell the 8th slot at the last minute is given by the following relation;

[tex]C_u[/tex] × [1 - F(Q)] - [tex]C_o[/tex] × F(Q)

Where F(Q) = The cumulative frequency for the 8th stock

Therefore, we have;

3,500 × (1 - 0.03) - 2,500 × 0.03 = 3,300

For the 8th slot, the TV station is expected to make an extra $3,300

Using MS Excel, we get;

For the 9th slot, the profit over the purchase price = $3,020

Fot the 10th slot, the profit over the purchase price = $2,420

The profit over the purchase price for the 11th slot = $1,520

The profit over the purchase price for the 12th slot = $320

The profit over the purchase price for the 13th slot = $(-580)

The 14th = $(-1,180)

15th = $(-1,480)

16th = $(-1,780)

17th = $(-2,080)

18th = $(-2,380)

19th = $(-2,500)

Therefore, to maximize profit, only the 8th, 9th, 10th, 11th, and 12th, slots which are 5 slots should be sold late while 20 - 5 = 15 slots should be sold in advance

c. The probability that the total revenue will exceed the identified amount in part 'a' is the cumulative probability at the 12th slot which is given as follows;

P(D ≤ 12) = F(12) = 0.53.

The probability that the total revenue will exceed the identified amount in part 'a' is the cumulative probability at the 12th slot is 0.53.

Probability refers to a possibility that deals with the occurrence of random events. The probability of all the events occurring need to be 1.

Given information

The demand for these last minute slots is estimated

8 9 10 11 12 13 14 15 16 17 18 19

Probability 0.03 0.05 0.1 0.15 0.2 0.15 0.1 0.05 0.05 0.05 0.05 0.02

The purchase price of the slots = 4,500

The salvage value of the slots = 2,000

The selling price of the slots = 8,000

a. The revenue received

R = The number of slots × The purchase price of the slot

R = 20 × $4,500 = $90,000

The revenue the station will receive by selling all the advertising slots in advance, R = $90,000

b. The Cost of Overage = Purchase price - Salvage value

The Cost of Overage,  = 4,500 - 2,000 = 2,500

The Cost of Underage,  = Selling price - Purchase price

The Cost of Underage,  = 8,000 - 4,500 = 3,500

Probability 0.03, 0.05, 0.1, 0.15, 0.2, 0.15, 0.1, 0.05, 0.05, 0.05, 0.05, 0.02

Cumulative frequency

F(Q); 0.03, 0.08, 0.18, 0.33, 0.53, 0.68, 0.78, 0.83, 0.88, 0.93, 0.98, 1

The expected monetary value for the decision to sell the 8th slot at the last minute

The Cost of Underage × [1 - F(Q)] -  × F(Q)

Where F(Q) = The cumulative frequency for the 8th stock

Therefore, we get

3,500 × (1 - 0.03) - 2,500 × 0.03 = 3,300

For the 8th slot, the TV station is expected to make an extra $3,300

For the 9th slot, the profit over the purchase price = $3,020

For the 10th slot, the profit over the purchase price = $2,420

Similarly,

The profit over the purchase price for the 11th slot = $1,520

The profit over the purchase price for the 12th slot = $320

The profit over the purchase price for the 13th slot = $(-580)

The profit over the purchase price for the 14th = $(-1,180)

The profit over the purchase price for the 15th = $(-1,480)

The profit over the purchase price for the 16th = $(-1,780)

The profit over the purchase price for the 17th = $(-2,080)

The profit over the purchase price for the 18th = $(-2,380)

The profit over the purchase price for the 19th = $(-2,500)

Therefore, only the 8th, 9th, 10th, 11th, and 12th slots should be sold in advance to maximize profit.

c. The probability that the total revenue will exceed the identified amount in part 'a' is the cumulative probability at the 12th slot.

P(D ≤ 12) = F(12) = 0.53.

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Answer:

lol lol lol lol lol lol lol lol

Step-by-step explanation:

Answer:

Hello Answer: V = 20

Step-by-step explanation:

Hope this helps!

9514 1404 393

Answer:

  v = 20 ft

Step-by-step explanation:

The similarity statement tells you the proportional sides:

  IH/IK = IG/IJ

  v/(10 ft) = (16 ft)/(8 ft)

  v = 10 ft × (16 ft)/(8 ft) = 10 ft × 2

  v = 20 ft

Answer:

there aint no figure

Step-by-step explanation:

Answer:

yea there ain't no figure

Step-by-step explanation:

lololololololololol

Answer:

5625 bald eagles

Step-by-step explanation:

Given

[tex]y = 312.5x + 1562.5[/tex]

Required

Predict the numbers in 1998

First, we calculate the value of x

[tex]x = 1998 - 1985[/tex] ---- years since 1985

[tex]x = 13[/tex]

So, we have:

[tex]y = 312.5x + 1562.5[/tex]

[tex]y = 312.5*13 + 1562.5[/tex]

[tex]y = 4062.5 + 1562.5[/tex]

[tex]y = 5625[/tex]

Answer:

625/100,000,000 or 6.25 out of one million

Step-by-step explanation:

(0.005)^4 = .000000000625  =  625/100,000,000

The probability that all four computers fail on one day is =6.3*[tex]10^{-10}[/tex].

It is a branch of mathematics that deals with the occurrence of a random event.

The probability that a computer fails on any single day is 0.005.

Let X denotes no. of computers fail on day

So, n = 4 , p = 0.05, q= 1-0.05=0.995

P (X = x) = [tex]^{n} C_x \;p^{x} \;q^{n-x}[/tex]

P (X = 4)

= [tex]^{4} C_4 \;(0.005)^{4} \;(0.995)^{4-4}[/tex]

=1* 0.00000000063*1

=0.00000000063

=6.3*[tex]10^{-10}[/tex]

Hence, the probability that all four computers fail on one day is

=6.3*[tex]10^{-10}[/tex].

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Answer:

Step-by-step explanation:

Domain of a function defines the input values (x-values) of the function.

Given linear function is,

y = -2x - 5

Domain of the function is,

{-6, -5, -2, 0, 1}

By substituting the values of x in the equation we can get y-values (output values).

Input-output table for the function,

x            -6            -5            -2             0             1

y             7             5             -1             -5           -7

Now we can plot these points of the graph.        

Answer:

Cost of each ticket bought by Peter = $8 for each ticket

Step-by-step explanation:

Given:

Number of ticket bought by Peter = 9 tickets

Amount paid by Peter for tickets = $72

Find:

Cost of each ticket bought by Peter

Computation:

Cost of each ticket bought by Peter = Amount paid by Peter for tickets / Number of ticket bought by Peter

Cost of each ticket bought by Peter = 72 / 9

Cost of each ticket bought by Peter = $8 for each ticket

Answer:

The answer is C. 80%

Step-by-step explanation:

Hope this helped:)

Answer:

0

Step-by-step explanation:

Assuming the problem is:

"lim x-> 4 f(x)=5 lim x-> 4 g(x)=0 and lim x-> 4 h(x)=-2, then find lim x->4 (fg)(x)"

lim x->4 (fg)(x)

Since we know the limits of f and g at x=4 exist we can write the limit as:

lim x->4 f(x) lim x->4 g(x) (since fg(x) means f times g of x.)

5(0)

0

if lim x-> 4 f(x)=5 lim x-> 4 f g(x)=0 and lim x-> 4 f h(x)=-2, then lim (fg)(x) 0

inequality the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.

Assuming the problem is:

"lim x-> 4 f(x)=5 lim x-> 4 g(x)=0 and lim x-> 4 h(x)=-2, then find lim x->4 (fg)(x)"

lim x->4 (fg)(x)

Since we know the limits of f and g at x=4 exist we can write the limit as:

lim x->4 f(x) lim x->4 g(x) (since fg(x) means f times g of x.)

=5(0)

=0

Hence the lim x-> 4 f(x)=5 lim x-> 4 f g(x)=0 and lim x-> 4 f h(x)=-2, then lim (fg)(x) 0

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