Answer:
D. and A
Explanation:
logical thought is base on functional fixedness; mental sets while creative problem solving uses insight; algorithms.
Study the venn diagram given below carefully. Which of the following can be placed at B? Options: Clay _ Paper _ Water_ Nitrogen.
Answer:
water and nitrogen can be place at B
The B loop is the element that can be liquid, cas or solid. Water can have three states : solid (ice), liquid, or gas (as a vapor). The same can be said with nitrogen, it's a gas at room temperature, and it also can be a liquid or solid.
A _ system is one in which one subsystem provides services to another subsystem.
A large system is one in which one subsystem provides services to another subsystem.
What is a large system?This is a type of system that contains many subsystems. The subsystem provides independent services to the larger by communicating, or interacting with each other.
What is a subsystem?A subsystem is smaller units of a large system, designed to perform specific task in the large system.
Thus, a large system is one in which one subsystem provides services to another subsystem.
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A chemical reaction produces two new substances and each product has a mass of 25 g what was the total mass of the reactants ?
Answer:
The total mass of the reactants is 50 grams.
Explanation:
[tex]25g+25g=50g\\[/tex]
I hope this helps!
You are out bowling with your friends. Where does the energy come from that will cause the ball to roll down
the alley? Where does the energy in the ball go after it starts rolling down the alley and eventually stops? Would
it be better to choose a heavy or light bowling ball to get a strike?
Answer:
1. Comes from the human us
2. Transfered into the alley floor or if hits a pin transfered to the pin.
3. Heavy
a boat travel due East with at 40metre per second across a river flowing due South 30metre per Second. what is the resultant speed of the boat
Answer:
Explanation:
Use vector addition
v = √(30² + 40²) = 50 m/s as viewed from the shore
Trust me when I say I would never venture onto a river moving at 30 m/s no matter how powerful the boat was.
30 m/s(3600 s/hr / 1000 m/km) = 108 km/hr
The turbulence in water flowing over ground at 108 kilometers per hour would capsize anything ever built...including aircraft carriers.
These numbers are more suitable for a plane flying in air. Even that could be a very rough ride.
Two cars drive on a straight highway. At time t = 0 , car 1 passes ad marker 0 traveling due east with a speed of 20.0 m/s. At the same time, car 2 is 1.0 km east of road marker 0 traveling at 30.0 m/s due west. Car 1 is speeding up, with an acceleration of 2.5 m/s², and car 2 is slowing down, with an acceleration of -3.2 m/s².
(a) Write position-time equations for both cars. Let east be the positive direction.
(b) At what time do the two cars meet?
Answer: (a) Write position-time equations for both cars. Let east be the positive direction.
Explanation:
Hope this helps!
Which statement describes the law of conservation of energy?
A. There is only one form of energy.
B. When an energy transformation happens, no energy is destroyed
or created.
C. The total energy in a system can only increase.
D. Energy can only change from nuclear energy to chemical energy.
SUBMIT
Answer:
B. When an energy transformation happens, no energy is destroyed
or created.
Explanation:
is everyone lowkey turning goth?
Answer:
Yeah it's the new trend lol it's kinda weird
Answer:
it is marked by mystery and ambiguity. If to this fascination for creating tension is added a feeling of fear
Explanation:
do I help you
What happens to the direction of the line joining when the object slows down ?Explain the observations
Answer:
it will be curved as in deceleration
Explanation:
A small bar of pure gold whose density is 19.3g/cm. Displaces 80 cm
Answer:
The mass of the gold bar is 1,544 g
Explanation:
Flag An alpha particle (consisting of two protons and two neutrons) is moving in a circle at a constant speed, perpendicular to a uniform magnetic field applied by some current-carrying coild. The alpha particle makes an clockwise revolution every 88 ns. If the speed is small compared to the speed of light, what is the magnitude B of the magnetic field made by the coils
Answer:
m = 4 At Mass units = 4 * 1.66E-27 kg = 6.64E-27 kg mass of particle
q = 2 * 1.60E-19 C = 3.2E-19 C total charge of alpha particle
T = 8.8E-8 s period of 1 revolution
F = q V B magnetic force
F = m V^2/ R centripetal acceleration
q V B = m V^2 / R
B = m V / (q * R)
T = 2 pi R / V time for 1 revolution
R = V T / (2 pi)
B = (m V / q) * 2 pi / (V T) = 2 pi m / (q T)
B = 2 pi * 6.64E-27 / (3.2E-19 * 8.8E-8) = 1.48
B = 1.48 W/m^2
21)
uses a hypothesis to describe the relationship between dependent and independent variables and
results in advances in scientific knowledge.
A)
Engineering method
1
B)
Architectural design
Eliminate
C)
Technological design
D
Scientific investigation
im not sure if im right or not but maybe its "D scientific investigation" but ldk so
an object starts from rest with a constant acceleration of 8.0m/s^2 along a straight line.find the average speed for 5 second interval
Answer:
40 m/s
Explanation:
If you multiply the acceleration with time you get the average speed.
What is the rotational speed of the hour hand on a clock?
Answer:
π/21600 rad /s.
A 1200-kg car is moving at 17.0 m/s due north. A 1600-kg car is moving at 21.0 m/s due east. The two cars simultaneously approach an icy intersection where, with no brakes or steering, they collide and stick together.
1)
Determine the speed of the combined two-car wreck immediately after the collision. (Express your answer to two significant figures.)
2)
Determine the direction of the combined two-car wreck immediately after the collision. (Express your answer to two significant figures.)
Answer:
f
Explanation:
The speed of the two-car wreck right after the crash is 13.9 m/s, and the direction is 58.4° east of north.
Momentum conservation can address this problem. Before and after the collision, momentum is equal. Calculate the two-car wreck's speed and direction after the collision:
Step 1: Calculate automobile beginning momentum.
Mass (m) times velocity (v) equals momentum (p).
Northbound 1200-kg car:
Initial momentum of the 1200-kg automobile (p₁) = mass (m₁) × velocity (v₁).
p₁ = 1200 kg × 17.0 m/s = 20,400 kg/s (North direction).
1600-kg eastbound car:
The 1600-kg car's initial momentum (p₂) = m₂ × v₂.
p₂ = 1600 kg × 21.0 m/s = 33,600 kg/s (East direction).
Step 2: Calculate the pre-collision momentum.
The vector sum of the two automobiles' momentum before the accident is p[tex]_total[/tex].
p[tex]_total[/tex] = p₁+p₂.
p[tex]_total[/tex] = 20,400 kg m/s (North) + 33,600 (East)
Step 3: Calculate the two cars' combined mass after the collision.
Combined mass (m[tex]_combined[/tex]) = 1200-kg + 1600-kg cars.
m[tex]_combined[/tex] = 1200 + 1600 = 2800 kg
Step 4: Determine the two-car wreck's velocity after the accident.
Total momentum after the collision (p[tex]_combined[/tex]) is the same as before, but it belongs to the combined mass (m[tex]_combined[/tex]) travelling at the velocity (v[tex]_combined[/tex]) in a given direction:
p[tex]_combined[/tex] = m[tex]_combined[/tex] × v[tex]_combined[/tex]
Since the collision is inelastic (cars stick together), momentum remains the same.
= p[tex]_total[/tex]
m[tex]_combined[/tex] × v[tex]_combined[/tex] = 20,400 kg/s (North) + 33,600 kg/s (East).
Step 5: Determine the two-car wreck's speed and direction.
Calculating the resultant vector of the North and East momentum components gives the combined two-car wreck's velocity (speed) (v[tex]_combined[/tex]).
(v[tex]_combined[/tex][tex]_north²[/tex] + v[tex]_combined[/tex][tex]_east²[/tex])
Where:
North velocity is v[tex]_combined[/tex][tex]_north[/tex].
East velocity is v[tex]_combined[/tex][tex]_east[/tex].
v[tex]_combined[/tex][tex]_north[/tex] = 20,400 kg m/s, 2800 kg, 7.29 m/s (North).
v[tex]_combined[/tex][tex]_east[/tex] = 33,600 kg m/s < 2800 kg × 12.0 m/s (East).
13.9 m/s = (7.29² + 12.0²)
Step 6: Determine the two-car wreck's direction.
Trigonometry can determine direction:
tan() = v[tex]_combined[/tex][tex]_east/north[/tex]
arctan(v[tex]_combined[/tex][tex]_east/north[/tex]) =
arctan(12.0 / 7.29 m/s) arctan(1.645) 58.4°
The two-car crash faces east at 58.4°.
Results summary:
The two-car disaster shortly after the accident is 13.9 m/s.
The two-car crash lies 58.4° east of north following the collision.
To kow more about speed
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How far will a bus travel if it averages a speed of 65 km/h for 7 hours?
Answer:
the bus travles 65x7=455 km
Explanation:
hope this helps you
Answer:
455 km/h
Explanation:
65km/h x 7 hours = 455 km/h
Correct answer is by. The equiv 48 - (-12) =
Answer:
60
Explanation:
48-(-12)=60
the -(- is like a big plus sign really if you see that then just add the numbers together so do 48 plus 12 it equals 60.
Which group of the periodic table consists of elements that share similar
properties and have a single electron in their outer shells?
A. 18
B. 2
C. 13
D. 1
Answer:
c 13
Explanation:
I took test
Group 18 of the periodic table, also known as the noble gases or Group 18 elements, consists of elements that share similar properties and have a single electron in their outer shells. The correct option is option (A).
These elements include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). They are characterized by having full outer electron shells, making them stable and unreactive under normal conditions.
This stability is due to the fact that they have achieved a full complement of electrons in their outermost energy level, except for helium, which has only two electrons in total.
Group 18 of the periodic table, also known as the noble gases or Group 18 elements, The correct option is option (A).
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an object down, but this is not true. If you place a box of mass 8 kg on a moving horizontal conveyor belt, the friction force of the belt acting on the bottom of the box speeds up the box. At first there is some slipping, until the speed of the box catches up to the speed of the belt, which is 5 m/s. The coefficient of kinetic friction between box and belt is 0.6. (a) How much time does it take for the box to reach this final speed
Answer:
Explanation:
ASSUMING the belt is horizontal
kinetic friction force is μmg = 0.6(8)(9.8) = 47.04 N
Horizontal acceleration is
a = F/m = 47.04 / 8 = 5.88 m/s²
t = v/a = 5.0 / 5.88 = 0.85034...
t = 0.85 s
By any method you choose, determine your average speed of walking. How do you results compare with those of your classmates?
joji sanctuary
slow dancing in the dark
happier by olivia
filipino artist like john cena
How to Convert 20000N/m2 to N/cm2 ? Explain it Step by Step.
Answer:
2N/cm²
Explanation:
1m=100cm so, 1m²= 100×100 cm² = 10000cm².
therefore , 20000N/m²= 20000/10000 N/cm².
= 2N/cm².
hope this helps you.
How can people help stop erosion on beach
Answer:
since erosion is unavoidable the problem becomes discovering ways to prevent it. present beach erosion prevention methods include sand bags,vegetation,seawalls,sand dunes,and sand fences.If you were in a spaceship travelling at 0.80 c away from a star, at what speed would the star's light pass you?
Still travelling at 0.80 c you see another spaceship approaching you, and the star. You measure its speed to be 0.84 c.
What is the other spaceship's speed in the star's frame of reference?
(1) The speed with which the star's light will pass you is 3 x 10⁸ m/s.
(2) The speed of the other spaceship is -2.943 x 10⁸ m/s.
The given parameters;
speed of the start light, u' = cspeed of spaceship, v = 0.8c(1)
Since you are travelling away from the star (same direction), relative to a third observer, the speed at which the star's light will pass you is calculated using Lorentz velocity addition.
[tex]u = \frac{u'+ v}{1 + \frac{v}{c^2} u'} \\\\u = \frac{c+(-0.8c)}{1 + \frac{-0.8c}{c^2} (c)}\\\\u = \frac{c-0.8c}{1- \frac{0.8c}{c} } \\\\u = \frac{0.2c}{0.2} = c = 3\times 10^{8} \ m/s[/tex]
Thus, the speed with which the star's light will pass you is 3 x 10⁸ m/s.
(2) The speed of the spaceship approaching = 0.84 c
Since you are travelling in opposite direction to second spaceship, relative to a third observer (frame of reference), the speed of the other spaceship is calculated using Lorentz velocity addition.
let the speed of the approaching spaceship u', = 0.84c
[tex]u = \frac{u' + v}{1 + \frac{v}{c^2}u' } \\\\u = \frac{-0.84c - 0.8c}{1 + \frac{(-0.8c)}{c^2}(-0.84c) } \\\\u = \frac{-1.64c}{1.672} = -0.981c \\\\u = -0.981 \times 3\times 10^{8} = -2.943 \times 10^{8} \ m/s[/tex]
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An object with an initial velocity of 2 m/s moves in a straight line under a constant acceleration.
Three seconds later, its velocity is 16 m/s.
(a) How far did the object travel during this time?
(b) What was the acceleration of the object?
Answer:
(a) distance =27m
(b)acceleration =14/3ms-2
Explanation:
s=(u+v)t/2
= (2+16)3/2
=27m
v=u+at
16=2+a*3
a= 14/3ms-2
A racket causes a tennis ball to rebound at a speed of 25 m/s The tennis ball is 0.4 kg and is initially moving at a speed of 12 m/s. A high-speed movie film determines that the racket and ball are in contact for 0.05 s. What is the average net force exerted on the ball by the racket
Hi there!
We know that:
I = Δp = mΔv = m(vf - vi)
Let the positive direction be towards the wall. Plug in the given values:
Δp = 0.4(-25 - 12) = -14.8 Ns
Δp = Ft, so:
Δp/t = F
-14.8/0.05 = -296 N (depending on which direction you assign positive/negative, the answer would be positive/negative)
Hanna tosses a ball straight up with enough speed to remain in the air for several seconds.
A: What is the velocity of the ball when it reaches its highest point?
B: What is its velocity 1 s before it reaches it’s highest point?
C: What is the change in its velocity during this 1-s interval?
D: What is its velocity 1 s after it reaches its highest point ?
E: What is the change in velocity during this 1 s interval?
F: What is the change in velocity during the two second interval?
G: what is the acceleration of the ball during any of these time intervals and the moment the ball has zero velocity?
Answer:
In the free fall motion we have that the acceleration is constant and produced by gravity, this acceleration has a magnitude of 32 ft/s2 or 9.8 m/s2 depending on the units you are working with. This means that every second the speed changes a magnitude of 32 ft/2, the velocity will depend of whether the ball is going upward (positive) or downward (negative).
A) At the highest point the ball stops to start the descend, here v=0 ft/s
B) +32 ft/s. The vector is going up, in the next second the velocity is going to be 0 (negative acceleration)
C) V=vf-vo=0-32=-32 ft/s is the constant change in velocity in projectile motion
D) -32 ft/s. The vector is pointing downward
E) V=vf-vo=-32-0=-32 ft/s is the constant change in velocity in projectile motion, 32 ft/s per second
F) Delta V=vf-vo=-32-32=-72 ft/s
g) gravity acceleration is constant 32 ft/s2 (pointing downward vector)
What is the tension in the string?
(I’m really having a hard time understanding this topic, and my professor isn’t helping much, so any extra explanation are greatly appreciated). The angles are 54.9205°.
If you look at the sketch I drew for the earlier part of this question, you'll see that, with respect to the positive horizontal (i.e. directly to the right), T₁ makes an angle of 180° - 54.9205° ≈ 125°, while T₂ makes an angle of 54.9205° ≈ 55°.
Split up the force acting on the block into vertical and horizontal components. We have
• net vertical force
∑ F = T₁ sin(125°) + T₂ sin(55°) - mg = 0
where m = 0.56 kg, and
• net horizontal force
∑ F = T₁ cos(125°) + T₂ cos(55°) = 0
Both net forces are 0 because the block is suspended in equilibrium.
Notice that cos(125°) = -cos(55°), so the second equation tells you that T₁ = T₂ and that the tensions in either string are the same. Also, sin(125°) = sin(55°).
Then in the first equation, we have
T₁ sin(125°) + T₂ sin(55°) - mg = 0
2 T₁ sin(55°) = mg
T₁ = mg/(2 sin(55°))
T₁ = (0.56 kg) (9.8 m/s²)/(2 sin(55°))
T₁ ≈ 3.35 N
A350kg car is moving 16m/s north and collides with a 650kg truck going 11m/s east.if it lock bumpers,how fast and in what direction will they are going after the collision
Hi there!
We can begin by breaking the problem up into two directions, horizontal and vertical.
The collision is perfectly inelastic since the two objects stick, so:
1 = car
2 = truck
Momentum in the east direction (positive and horizontal, car NOT going in this direction has a velocity of 0 m/s):
m2v2 = (m1 + m2)v
(650 · 11) / (350 + 650) = 7.15 m/s
Momentum in the north directions (only initial is the northward velocity of the car):
m1v1 = (m1 + m2)v
(350 · 16)/(350 + 650) = 5.6 m/s
Find the overall velocity using the pythagorean theorem:
√(5.6²) + (7.15²) = 9.08 m/s
Find the direction using trigonometry. Use tangent in this situation:
tan Ф = O/A
tan⁻¹(5.6/7.15) = 38° north of east
A 5000 kg train is traveling at a velocity of 100 m/s and hits another train. The two trains stick together and the new velocity is 50m/s. What is the mass of the second train?
Answer:
Explanation:
Conservation of momentum is used to solve
Unfortunately we have a missing piece of information such as the initial velocity of the unknown mass train.
If we ASSUME that the second train is at rest
5000(100) + m(0) = 5000(50) + m(50)
which means m = 5000 kg
However, I'll show you the importance of knowing that initial velocity by finding it assuming the other answers are valid
if m = 15000 kg
5000(100) + 15000(v₀) = (5000 + 15000)(50)
v₀ = 33 ⅓ m/s
if m = 10000 kg
5000(100) + 10000(v₀) = (5000 + 10000)(50)
v₀ = 25 m/s
if m = 8000 kg
5000(100) + 8000(v₀) = (5000 + 8000)(50)
v₀ = 18.75 m/s
So you can see why I had to assume an initial velocity. Any of the masses could work if the initial velocity is chosen correctly.
An airplane travels 250 km due east, then turns and travels 180 km [E 60°S]. Determine the resulting travel displacement for this plane.
Answer:
388.56km[E13degS]
Explanation:
Δdx = Δd1x + Δd2x
Δdx = 250km [E]+ 180sin(60) [E]
Δdx = 405.88 km [E]
Δdy = Δd1y + Δd2y
Δdy = 0 + 160cos(60) [S]
Δdy = 90km [S]
Δdt = √(Δdx)^2+(Δdy)^2
Δdt = √164738.57+8100
Δdt = 398.85km
tanθ = Δdy/Δdx
tanθ = 90/388.56
θ = tan-1(90/388.56)
θ = 13.04 deg