Let M = {m - 10,2,3,6}, R = {4,6,7,9) and N = {x\x is natural number less than 9} a. Write the universal set b. Find [Mºn (N - R)]xN

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Answer 1

a. The universal set in this context is the set of natural numbers less than 9, denoted as N = {1, 2, 3, 4, 5, 6, 7, 8}. b. To find [Mºn (N - R)]xN, we first need to calculate the sets N - R and Mºn (N - R), and then take the intersection of the result with N. Therefore, [Mºn (N - R)]xN = {2, 3}.

a. The universal set is the set that contains all the elements under consideration. In this case, the universal set is N, which represents the set of natural numbers less than 9. Therefore, the universal set can be written as N = {1, 2, 3, 4, 5, 6, 7, 8}.

b. To find [Mºn (N - R)]xN, we need to perform the following steps:

Calculate N - R: Subtract the elements of set R from the elements of set N. N - R = {1, 2, 3, 5, 8}.

Calculate Mºn (N - R): Find the intersection of sets M and (N - R). Mºn (N - R) = {2, 3, 6} ∩ {1, 2, 3, 5, 8} = {2, 3}.

Take the intersection of Mºn (N - R) with N: Find the common elements between Mºn (N - R) and N. [Mºn (N - R)]xN = {2, 3} ∩ {1, 2, 3, 4, 5, 6, 7, 8} = {2, 3}.

Therefore, [Mºn (N - R)]xN = {2, 3}.

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Related Questions

n the problem of estimating total hospitalization costs for kidney stone patients, suppose Muscat and Dhofar regions were selected as strata because they have very different incident rates for the disease, and the estimates for each region was needed separately. Also, this stratification into geographic regions simplified the sampling procedures. The sample data are summarized as follows: Muscat Dhofar ni=260 12=150 Mean cost ý,=170 RO Mean cost y =125 RO S =3050 $ -2525 G = 745 C-10 RO n 02-680 C2=12 RO A previous study showed the number of kidney stone incidents in the Muscat to be 325 out of 100,000 population and the number in the Dhofar to be 320 out of 100,000. The population of the Muscat was 775,878, and the population of the Dhofar was 249,729, according to the 2010 census. a) Obtain the estimates of N, and N2, the numbers of kidney stone patients expected to be found in the Muscat and Dhofar regions. b) Obtain the average annual cost of hospitalization of the kidney patients of the two region combined with 95% confidence interval and interpret the results. c) Find the appropriate sample size n and stratum sample size ni and n2 for estimating the population mean with a bound on the error of estimation equal to 50 RO, considering proportional allocation.

Answers

The estimated number of kidney stone patients in the Muscat region (N₂) is approximately 447,184, and in the Dhofar region (N₁) is approximately 128,694.

Given,

Estimation of total hospitalization costs for kidney stone patients .

Here,

To obtain the estimates of N and N, the numbers of kidney stone patients expected to be found in the Muscat and Dhofar regions, we can use the stratified sampling formula:

Nᵢ = (nᵢ / n) * N,

where:

- Nᵢ is the estimate of the population size in stratum i.

- nᵢ is the sample size in stratum i.

- n is the total sample size (sum of all stratum sample sizes).

- N is the total population size.

Given the information provided, we have the following data:

For Dhofar region:

- n₁ = 260 (sample size)

- N = 249,729 (population size according to the 2010 census)

For Muscat region:

- n₂ = 150 (sample size)

- N = 775,878 (population size according to the 2010 census)

Using the given formula, we can calculate the estimates for each region:

For Dhofar region:

N₁ = (n₁ / n) * N = (260 / (260 + 150)) * 249,729

For Muscat region:

N₂ = (n₂ / n) * N = (150 / (260 + 150)) * 775,878

To obtain the values, let's calculate them:

For Dhofar region:

N₁ = (260 / (260 + 150)) * 249,729 ≈ 128,694

For Muscat region:

N₂ = (150 / (260 + 150)) * 775,878 ≈ 447,184

Therefore, the estimated number of kidney stone patients in the Muscat region (N₂) is approximately 447,184, and in the Dhofar region (N₁) is approximately 128,694.

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please help me .......​

Answers

Answer:

A

Step-by-step explanation:

AX and EX are secant segments that intersect at point X.
What is the length of DE?


1 unit

3 units

4.5 units

4 2/3 units

Answers

Answer:

DE=4

Step-by-step explanation:

got it right on edg

The length of DE is given as: 3 Units. (Option B)
A line that joins two points on a curve is called a Secant Line.

What is the Secant Theorem?

Two secant theorem states that if two secant lines are drawn from a point outside a circle a relationship is formed between the line segments.

How do we arrive at the length of DE?

Based on the Secant Theorem, from the figure, we know that:

AX * BX = EX * DX

Assuming that the length of DE equals X,:

AX * BX = EX * DX

Equals

(7+2) X (2) = (x + 3) (3)

To solve for x we expand the brackets to state:

9 * 2= 3x + 9

3x = 18-9

3x= 9

x = 9/3

X which is same as DE = 3 Units.

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-6x - 14 > 10 what is the answer to this problem, please helt

Answers

Answer:

Inequality Form:

x < - 4

Interval Notation:

( − ∞ , − 4 )

Step-by-step explanation:

what is the true solution to 3 l n 2 l n 8 = 2 l n (4 x)x = 1x = 2x = 4x = 8

Answers

The true solution to the equation is x ≈ 0.688. By simplifying the equation and solving for x, we find the approximate value.

To find the true solution to the equation 3ln(2ln8) = 2ln(4x)x = 1x = 2x = 4x = 8, we need to simplify the equation and solve for x.

First, let's break down the equation step by step:

3ln(2ln8) = 2ln(4x)x = 1x = 2x = 4x = 8

By simplifying each expression, we have:

3ln(ln8) = 2ln(4x)x = x = 2x = 4x = 8

Now, let's focus on the middle expression, 2ln(4x)x. Using the properties of logarithms, we can rewrite it as:

ln((4x)^2) = x

Simplifying further:

ln(16x^2) = x

Exponentiating both sides:

16x^2 = e^x

This is a transcendental equation that cannot be solved algebraically. However, using numerical methods or a graphing calculator, we find the approximate solution:

x ≈ 0.688

Therefore, the true solution to the equation is x ≈ 0.688.

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4
Find the area of the figure and type your result in the empty box provided.
13 m
6 m
8 m
7 m
Answer:

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Answer:

I need a picture of the figure to do it

In a large population of college-educated adults, the mean IQ is 112 with standard deviation 50.62. Suppose 30 adults from this population are randomly selected for a market research campaign. The distribution of the sample mean IQ is: a. approximately Normal, with mean 112 and standard deviation 1.443. b. approximately Normal, with mean 112 and standard deviation 4.564. c. approximately Normal, with mean equal to the observed value of the sample mean and standard deviation 25. d. approximately Normal, with mean 112 and standard deviation 9.241.

Answers

Given:  Population mean IQ = 112Population standard deviation IQ = 50.62Sample size (n) = 30To find: Distribution of the sample mean IQ

The Central Limit Theorem states that for a large sample size, the distribution of sample means will be approximately Normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size . Let's calculate the standard deviation of the sample mean IQ:

Standard deviation of sample mean IQ = (Population standard deviation IQ) / √n= 50.62 / √30= 9.241 (approx.)Therefore, the distribution of the sample mean IQ is approximately Normal, with mean 112 and standard deviation 9.241. The correct option is (d).

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HELP ASAP!!! question in picture!!!

Answers

Answer:

Y=3x-17

Step-by-step explanation:

I graphed it

Find the measure of the exterior angle.

Answers

the sum of all interior angles must be 180, we know that angle t increases by 10 therefore t is equal to 50° and angle t + 20° is equal to 70°

next we can see that the two angles form a 180° angle meaning the measure of the exterior angle is 180° - 70° or 110°

A metal bar weighs 24 ounces. 15% of the bar is gold. How many ounces of gold are in the bar? *​

Answers

Answer:

7.6 ounces of silver

Step-by-step explanation:

Hope this helps :)

There ae 3.6 ounces of Gold in the metal bar.

What is mean by Percentage?

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

To Calculate the percent of a number , divide the number by whole number and multiply by 100.

Given that;

A metal bar weighs 24 ounces.

And, 15% of the bar is gold.

Now, We can formulate as;

Amount of gold in the bar is,

⇒ 15% of 24

⇒ 15/100 × 24

⇒ 3.6 ounces

Hence, There ae 3.6 ounces of Gold in the bar.

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T or F:
When finding the percentage of each section, you have to divide the part by the whole or total amount.

Answers

Answer:

true because you can do that in a amound of the total

what is a shape that has no sides the same length that is a quadrilateral

Answers

Answer:

Step-by-st

Bitly: URL Shortener - Short URLs & Custom Free Link ...bitlep explanation:

Which of the expressions below is equal to 10x+30? Select all that apply.

Answers

The answer is a because you have to put it in parenthesis

(3/2)^4= in fraction form help pls

Answers

Answer:

81/16

Step-by-step explanation:

4 out of the 80 students at a school assembly were first-grade students. What percentage of the students at the assembly were first-graders?

Answers

Answer:5

Step-by-step explanation:

Answer:

5 percent

Step-by-step explanation:

4/80 = 5 percent

What is the ratio of yellow butterflies to total butterflies? Choose the correct option

Answers

Answer:2/3

Step-by-step explanation: there is 2 yellow out of 3 butterfiles

ayudaaaaaaaaaaa por favor

Answers

Answer:

ayuda te solo no eres tonto o si?

Step-by-step explanation:

[5 points) X is places in an account which carries a nominal annual interest rate of 2.5% compounded monthly. After five years, the accumulated value is places in an account which earns a nominal annual interest rate of 3.2% compounded quarterly. The value of this account in eight years is $10,000. Find X.

Answers

The initial value of X can be determined using compound interest calculations. X is invested in an account with a nominal annual interest rate of 2.5%, compounded on a monthly basis, for a period of five years. After the initial period, X is then transferred to another account with a nominal annual interest rate of 3.2%, compounded on a quarterly basis, for a total duration of eight years. The approximate value of X at the end of this investment period is $6,573.83.

To solve for X, we will substitute the first equation into the second equation and solve for X. Let's proceed with the calculations:

The first equation is: FV = X(1 + 0.025/12)^(12*5)

The second equation is: $10,000 = X(1 + 0.032/4)^(48)(1 + 0.025/12)^(125)

We can substitute the first equation into the second equation:

$10,000 = [X(1 + 0.025/12)^(125)] * (1 + 0.032/4)^(48)

$10,000 = X * (1 + 0.025/12)^(125) * (1 + 0.032/4)^(48)

Now we can simplify the equation:

$10,000 = X * (1.002083)^60 * (1.008)^32

Divide both sides of the equation by [(1.002083)^60 * (1.008)^32] to solve for X:

X = $10,000 / [(1.002083)^60 * (1.008)^32]

Using a calculator, we can find the value of X:

X ≈ $10,000 / (1.138877 * 1.335893)

X ≈ $10,000 / 1.521364

X ≈ $6,573.83

Therefore, the value of X is approximately $6,573.83.

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Which property of equality would be used to solve 3x=81

Answers

Answer:

Division

Step-by-step explanation:

Sophia drove 63 miles. Sophia's car used 2 gallons of gas. How many miles per gallon did Sophia car get?

Answers

Answer:

31.5 mi/gal

Step-by-step explanation:

[tex]63[/tex]÷[tex]2[/tex][tex]=31.5[/tex]

So, Sophia got 31.5 miles per gallon

Answer: 31.5 I think.

Step-by-step explanation:

Give other person brainliest

i need help please help me​

Answers

84 I believe, a2+b2=c2 is the formula btw

a. Determine whether the Mean Value Theorem applies to the function f(x) 4x^(1/7) on the interval [-128,128). b. If so, find or approximate the point(s) that are guaranteed to exist by the Mean Value Theorem

Answers

To determine if the Mean Value Theorem (MVT) applies to the function f(x) = 4x^(1/7) on the interval [-128, 128), we need to check if the function satisfies the conditions of the MVT.

The Mean Value Theorem states that if a function f(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one point c in (a, b) such that f'(c) = (f(b) - f(a))/(b - a).

In this case, the interval is [-128, 128), which is a closed interval. To check if the MVT applies, we need to ensure that the function is continuous on [-128, 128] and differentiable on (-128, 128).

Continuity: The function f(x) = [tex]4x^(1/7)[/tex] is a power function and is continuous for all x values, including the interval [-128, 128]. Therefore, the function is continuous on the interval.

Differentiability: The function f(x) = [tex]4x^(1/7)[/tex]is differentiable for all x values except at x = 0. Since the interval (-128, 128) does not include x = 0, the function is differentiable on the interval.

Therefore, both conditions for the MVT are satisfied, and we can conclude that the Mean Value Theorem applies to the function f(x) = [tex]4x^(1/7)[/tex] on the interval [-128, 128).

Next, we can find or approximate the point(s) that are guaranteed to exist by the Mean Value Theorem.

The Mean Value Theorem guarantees the existence of at least one point c in (-128, 128) such that f'(c) = (f(128) - f(-128))/(128 - (-128)).

Let's calculate the values:

f(128) = [tex]4(128)^(1/7)[/tex]≈ 4.5534

f(-128) = [tex]4(-128)^(1/7)[/tex]≈ -4.5534

f'(c) = (4.5534 - (-4.5534))/(128 - (-128)) = 9.1068/256 ≈ 0.0356

Therefore, by the Mean Value Theorem, there exists at least one point c in the interval (-128, 128) such that f'(c) ≈ 0.0356.

Please note that the specific value of c cannot be determined without further analysis or calculations. The Mean Value Theorem guarantees its existence but does not provide an exact value.

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I need help with this helpppp :(

Answers

Answer:

Domain: (-∞,+∞)

Range: (-∞,1)

y-intercept: (0,2)

Asymptote: I am not sure (sorry) I know they can be solved using the equation n(x)=0

Step-by-step explanation:

Domain: the set of all x-values

- this graph has arrows which means the domain is from -∞ to +∞ (-∞,+∞)

Range: the set of all y-values

- the graph extend continuously on the negative side so -∞ and it stops at 1 on the positive side  (-∞,1)

Y-intercept: this point is where the graph crosses the y-axis, this is at (0,2)

What is the distance between A(7, 4) and B(2, −8)?

Answers

Answer:

The distance would 13 square units

Step-by-step explanation:

Well follow the formula

=√(2−1)^2+(2−1)^2

Plug in everything and solve, remeber to follow order of operations

solve the following equation on the interval [0°,360°). separate multiple answers with a comma. remember to include a degree symbol. 4cos2xtanx−2tanx=0

Answers

To solve the equation 4cos^2(x)tan(x) - 2tan(x) = 0 on the interval [0°, 360°), we can use algebraic manipulations and trigonometric identities. Let's simplify the equation step by step:

Start with the given equation: 4cos^2(x)tan(x) - 2tan(x) = 0.

Factor out the common term tan(x): tan(x)(4cos^2(x) - 2) = 0.

Set each factor equal to zero and solve separately:

a) tan(x) = 0:

Since tan(x) is zero at x = 0°, 180°, and 360°, we have x = 0°, 180°, 360° as solutions.

b) 4cos^2(x) - 2 = 0:

Add 2 to both sides: 4cos^2(x) = 2.

Divide by 4: cos^2(x) = 1/2.

Take the square root: cos(x) = ±√(1/2).

To find the values of x in the interval [0°, 360°), we need to consider both the positive and negative square root:

cos(x) = √(1/2):

x = 45°, 315° (since cos(45°) = cos(315°) = 1/√2)

cos(x) = -√(1/2):

x = 135°, 225° (since cos(135°) = cos(225°) = -1/√2)

Therefore, the solutions to the equation 4cos^2(x)tan(x) - 2tan(x) = 0 on the interval [0°, 360°) are: x = 0°, 45°, 135°, 180°, 225°, 315°, and 360°.

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A chi-squared test for homogeneity of proportions requires that

A. ni, n2, n3, ... > 30
B. all expected counts are > 5
C. nipi, n2p2, n3p3, ... > 10​

Answers

The answer is Is B
..................

What is the value of b for b' - 36/64

Answers

the value of b is 0.5625

Which of the following statement(s) with regard to a data set's measures of Central Tendency, Dispersion, and Paired Observations is(are) TRUE?

In a very small set of data, i.e. small n, the Sample Standard Deviation is generally smaller than its Population Standard Deviation.

It is possible for the value of the Correlation between a set of paired observations to be greater than 1.

Unlike STDEV.P Excel function for calculating a Population Standard Deviation, Excel has no direct functions for calculating the Range and Midrange values of a data set.

Mode and Range are both measures of central tendency.

In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction.

In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range.

It is possible for Median of a data set to have a value that is not equal to any of the values in the data set.

Answers

The statements that are TRUE with regard to a data set's measures of Central Tendency, Dispersion, and Paired Observations are the following:In a very small set of data, i.e. small n, the Sample Standard Deviation is generally smaller than its Population Standard Deviation.

It is possible for the value of the Correlation between a set of paired observations to be greater than 1.In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction.In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range.Why these statements are true?In a very small set of data, the Sample Standard Deviation is generally smaller than its Population Standard Deviation because when the sample size is smaller, there is less dispersion and thus the value of the sample standard deviation is generally smaller than that of the population standard deviation.It is possible for the value of the Correlation between a set of paired observations to be greater than 1 because the correlation coefficient r ranges from -1 to 1, inclusive of both endpoints.

However, it is practically impossible to get a value of r outside this range in a real dataset.In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction. This is because 0.75 is a strong positive correlation indicating that as the value of one variable increases, the value of the other variable also increases.In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range because the standard deviation takes into account all values in the dataset and is less sensitive to outliers as compared to the range. On the other hand, the range only considers the minimum and maximum values of the dataset and thus is less informative.

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El usuario se registra medio de una temperatura de 8 grados centígrados Sin embargo a las 22 horas la temperatura y ha bajado unos 10 grados centígrados Cuál es la temperatura en este momento

Answers

Answer:

La temperatura en estos momentos es -2 grados centígrados.

Step-by-step explanation:

Dado que conoces que había una temperatura de 8°C y que a las 22 horas esta ha bajado unos 10 grados, tienes que restar estos 10 grados de la temperatura inicial para saber cuál es la temperatura actual:

8-10=-2

De acuerdo a esto, la respuesta es que la temperatura en estos momentos es -2 grados centígrados.

Consider the function represented in the table.

Which point of the given function corresponds with the
minimum value of its inverse function?
X
-10-20
3 8
0
-2.
5 8
4.5-6
A (-20, 8)
B (-10,3)
C (0, -2)
D (8,-6)

HELPPP

Answers

Answer:

The real answer is (-20, 8).

Step-by-step explanation:

I just did the unit test practice or whatever and used the answer above and got it wrong. This is the correct answer.

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Which of the following irrigation methods is most likely to result in salinization of the soil, especially if the agricultural fields are located in a warm climate with consistent sunlightA Spray irrigationFurrow irrigationFlood irrigationDrip Irrigation I need help with making a theme for a book called more than anything else. Which of the following SELECT statements lists only the book with the largest profit?SELECT title, MAX(retail-cost) FROM books GROUP BY title;SELECT title, MAX(retail-cost) FROM books GROUP BY title HAVING MAX(retail-cost);SELECT title, MAX(retail-cost) FROM books;None of the above HEY LOL PLEASE ANSWER THESE. PLEASE IM BEGGING YOU. HELP ME [The following information applies to the questions displayed below.]You have just been hired as a financial analyst for Lydex Company, a manufacturer of safety helmets. Your boss has asked you to perform a comprehensive analysis of the companys financial statements, including comparing Lydexs performance to its major competitors. The companys financial statements for the last two years are as follows:Lydex CompanyComparative Balance SheetThis Year Last YearAssets Current assets: Cash $ 960,000 $ 1,200,000Marketable securities 0 300,000Accounts receivable, net 2,700,000 1,800,000Inventory 3,600,000 2,000,000Prepaid expenses 260,000 200,000Total current assets 7,520,000 5,500,000Plant and equipment, net 9,520,000 9,050,000Total assets $ 17,040,000 $ 14,550,000Liabilities and Stockholders' Equity Liabilities: Current liabilities $ 4,010,000 $ 2,980,000Note payable, 10% 3,660,000 3,060,000Total liabilities 7,670,000 6,040,000Stockholders' equity: Common stock, $75 par value 7,500,000 7,500,000Retained earnings 1,870,000 1,010,000Total stockholders' equity 9,370,000 8,510,000Total liabilities and stockholders' equity $ 17,040,000 $ 14,550,000Lydex CompanyComparative Income Statement and ReconciliationThis Year Last YearSales (all on account) $ 15,860,000 $ 13,580,000Cost of goods sold 12,688,000 10,185,000Gross margin 3,172,000 3,395,000Selling and administrative expenses 1,006,000 1,604,000Net operating income 2,166,000 1,791,000Interest expense 366,000 306,000Net income before taxes 1,800,000 1,485,000Income taxes (30%) 540,000 445,500Net income 1,260,000 1,039,500Common dividends 400,000 519,750Net income retained 860,000 519,750Beginning retained earnings 1,010,000 490,250Ending retained earnings $ 1,870,000 $ 1,010,000To begin your assigment you gather the following financial data and ratios that are typical of companies in Lydex Companys industry:Current ratio 2.4 Acid-test ratio 1.1 Average collection period 40 daysAverage sale period 60 daysReturn on assets 9.3 %Debt-to-equity ratio .66 Times interest earned ratio 5.9 Price-earnings ratio 10 ReferencesSection BreakProblem 13-15A Comprehensive Ratio Analysis [LO13-2, LO13-3, LO13-4, LO13-5, LO13-6]1.Required informationPart 1Required:1. You decide first to assess the companys performance in terms of debt management and profitability. Compute the following for both this year and last year: (Round your intermediate calculations and final percentage answers to 1 decimal place. i.e., 0.123 should be considered as 12.3%. Round the rest of the intermediate calculations and final answers to 2 decimal places.)a. The times interest earned ratio.b. The debt-to-equity ratio.c. The gross margin percentage.d. The return on total assets. (Total assets at the beginning of last year were $13,070,000.)e. The return on equity. (Stockholders equity at the beginning of last year totaled $7,990,250. There has been no change in common stock over the last two years.)f. Is the companys financial leverage positive or negative?2.Required informationPart 22. You decide next to assess the companys stock market performance. Assume that Lydexs stock price at the end of this year is $94 per share and that at the end of last year it was $62. For both this year and last year, compute: (Round your intermediate calculations and final answers to 2 decimal places. For percentages 0.1234 should be considered as 12.34%.)a. The earnings per share.b. The dividend yield ratio.c. The dividend payout ratio.d. The price-earnings ratio.e. The book value per share of common stock.3.Required informationPart 33. You decide, finally, to assess the companys liquidity and asset management. For both this year and last year, compute: (Use 365 days in a year. Round your intermediate calculations and final answer to 2 decimal places.)a. Working capital.b. The current ratio.c. The acid-test ratio.d. The average collection period. (The accounts receivable at the beginning of last year totaled $1,670,000.)e. The average sale period. (The inventory at the beginning of last year totaled $2,030,000.)f. The operating cycle.g. The total asset turnover. (The total assets at the beginning of last year totaled $13,070,000.) Which best describes the appeal Kennedy makes in "Make Gentle the Life of This World"?He mainly appeals to logic by giving examples of how violence does not solve problems.He mainly appeals to emotion by urging his audience to focus on compassion and understanding.He mainly appeals to timeliness by telling audience members not to protest in the coming days.He mainly appeals to his own authority by explaining how he will work for social justice. 5.Put the following fractions in order from smallest to largest: 1/4, 2/3, 4/7, 1/2 Kendra ordered a set of blue and brown pins. She received 100 pins, and 30% of them were blue. How many blue pins did Kendra receive? Which of the following is a noun phrase the movie was boring, across many rivers, around the sun, the choreographer was happy help You arrive at the airport at 1:50 pm and your flight leaves at 5:20 pm. How many MINUTES will you need to wait? Margarita was buying soil for her spring garden. What would be the most reasonable amount of soil she would need to buy for a garden? A. 5 grams B. 50 liters C. 50 kilograms D. 5,000 kilograms *What two kinds of molecules would be used to support evolution ? 4. (Newton's Method). Consider the problem of finding the root of the function f(x)=x+el.812r in [-1,0]. (i) Find the formula of the iteration function g(x) = x- f(x) f'(x) for Newton's method, and then work as instructed in Problem 3, that is, plot the graphs of g(x) and g'(x) on [-1,0] with the use of Wa to show convergence of Newton's method on [-1,0] as a Fixed-Point. Iteration technique. (ii) Apply Newton's method to find an approximation py of the root of the equation x+el.812x = 0 in [-1,0] satisfying RE(PNPN-1 < 10-5) by taking po = -1 as the initial approximation. All calculations are to be carried out in the FPA7. Present the results of your calculations in a standard output table for the method of the form TL Pn-1 Pn RE(pn pn-1) B : (As for Problem 3, your answers to the problem should consist of two graphs, a conclusion on convergence of Newton's method, a standard output table, and a conclusion regarding an approximation PN.) As was discussed during the last lecture, applications of some cruder root-finding methods can, and often do, precede application of Newton's method (and the Bisection method is one that is used most commonly for this purpose). 4. (Newton's Method). Consider the problem of finding the root of the function f(x)=x+-812 in 1-1,0). (1) Find the formula of the iteration function f(x) g(x) = P(x) for Newton's method, and then work as instructed in Problem 3, that is, plot the graphs of g(x) and g'(z) on [-1.0 with the use of Who to show convergence of Newton's method on [-1.0] as a Fixed-Point Iteration technique. (ii) Apply Newton's method to find an approximation py of the root of the equation z+el-813x = 0 in (-1,0 satisfying RE(PNPN-1 when a program needs to save data for later use, it writes the data in a(n) ________. An NMOS transistor which is operating in linear region is found to have a resistance of 1M22. Assume the channel length is 5um, (W/L) = 5, ID = 100A, V th = 0.5V, and VGS = 3V. 1) Find the new channel width to increase the resistance to 4 M2 2) Find the new overdrive voltage to increase the resistance to 6 M2 Solve the equation. 4 2/5 + k = -3 2/11 HELP DUE BY 10AM HELP ASAP School administrators in Boston want to assess the efficacy of a new reading program they wish to put in place. Therefore, they randomly assign some schools in the city to institute the new reading program and other schools to remain on the traditional reading program. When performing the analysis to determine whether students using the new reading program perform better, the educators control for socioeconomic status, a variable known to be related to educational outcomes. What kind of analysis have the educators performed Please help me with 1,2,3,4,5,6,7,8,9,10 write the answers here if u going to send me a file do not send it I prefer it here please help please