Let H be the set of real numbers less than or equal to eleven

Answer:

They both have an infinite number of solutions.

Step-by-step explanation:

Given system of equations:

a) 2x + 4y = 15

b) 6x + 12y = 45

Slope-intercept form: y = mx + b

where:

Rewrite both equations into slope-intercept form:

a) 2x + 4y = 15

⇒ 2x + 4y = 15 [subtract 2x from both sides]

⇒ 2x - 2x + 4y = 15 - 2x

⇒ 4y = - 2x + 15 [divide both sides by 4]

⇒ 4y ÷ 4 = (-2x ÷ 4) + (15 ÷ 4)

[tex]\sf \implies y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75[/tex]

b) 6x + 12y = 45

⇒ 6x + 12y = 45 [subtract 6x from both sides]

⇒ 6x - 6x + 12y = 45 - 6x

⇒ 12y = - 6x + 45 [divide both sides by 12]

⇒ 12y ÷ 12 = (-6x ÷ 12) + (45 ÷ 12)

[tex]\sf \implies y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75[/tex]

New equations:

[tex]\sf a)\ y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75\\\\\sf b)\ y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75[/tex]

Both equations have the same slope (-½), and y-intercept (3.75). Therefore, they both have an infinite number of solutions.

System of equations can have the following:

No Solution: the same slope (both lines will be parallel)

One Solution: different slopes and different y-intercepts

Infinitely Many Solutions: the same slope and y-intercept

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Looking at the given expression, they do not seem to be in the slope-intercept form which is the most common form used for linear expression. Let us convert the equations that were given in the problem statement to follow the slope-intercept form.

Equation #1

Subtract 2x from both sides

Divide both sides by 4

Equation #2

Subtract 6x from both sides

Divide both sides by 12

Since both the first and second equation have the same exact number which means that they will fall exactly on top of each other.  Therefore, there are infinite solutions as they will always continue on top of each other.

Answer:

list five solution to the energy crisis of nepal

The triangle is an isosceles right triangle. Then the value of x will be 1.27 cm.

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

The right-angle triangle is given below.

The given triangle is an isosceles right triangle.

P = B = x

Then we have

1.8² = x² + x²

2x² = 3.24

 x² = 1.62

   x = 1.27 cm

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Answer:

A. 65 degrees

Step-by-step explanation:

The required measure of the angle c in the quadrilateral is given as 65°.

As mentioned in the question,
A quadrilateral is inscribed in a circle o. the angle measures the quadrilateral in degrees is given by the expressions shown in the figure.

Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.

Here,
In a quadrilateral, the sum of the composite angle is equal to 180°,
∠A + ∠C = 180
130 -x + 95 -2x = 180
-3x = 180 - 225
x = 15

Now,
∠c = 95 - 2x
∠c = 95 - 2×15
∠c = 65

Thus, the required measure of the angle c in the quadrilateral is given as 65°.

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Answer:

15.25

Step-by-step explanation:

1/4  is also 0.25 in decimals so add that to your 15 and you get 15.25.

Step-by-step explanation:

the fraction 1/4 is also equivalent to the decimal for of .25 + 15 equals 15.25

Answer: F = - 2/7

Step-by-step explanation:

[tex]f(x) = x + 9\\f(-7) = -7 + 9\\f(-7) = 2\\f = -\frac{2}{7}[/tex]

1d) ↑ (Do the same but turned if that's easier)

1a) 199

1b) 193

1c) 217

1e) Based on the box plot, we can for example, find the lowest and greatest values, the range (largest - smallest), the mean (all values / # values), and the median middle value or q2 given by the second line in the box.

2b) 7

2c) 9.5

2d) ↑

2e) because the data is not ordered, it is difficult to determine the quartile data. Once it is ordered like 6, 7, 7, 7, 8, 8, 9, 10, 10. The data can be visualized alot easier. With the box plot we can determine q3 of the data by looking at the 3rd line, using the whiskers of the box to find the minimum and maximum values.

3)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be: 4,6,8,8,9,11,12,14,14,16.

[4, 6, 8, 8, 9] [] [11, 12, 14, 14, 16]

4 is the minimum, 16 is the maximum, q1 is 8, q3 is 14, and median is 10.

4) ↑

5)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be:

45, 45, 50, 55, 60, 70, 70, 75, 80, 85

[45, 45, 50, 55, 60] [] [70, 70, 75, 80, 85]

45 is the minimum, 85 is the maximum, q1 is 50, q3 is 75, and median is 65.

6) ↑

Answer:

uhm smhtn

Step-by-step explanation:

i really just want points.

Answer:

(0,infinity)

Step-by-step explanation:

.

Answer:

2,304 inches

Step-by-step explanation:

1 square foot = 144 square inches

16 x 144 = 2,304 square inches

The simplification form of the expression 8 3/8 + 3 3/8 + 2 3/8 + 3/8 is 14 whole 1/2 or 14 1/2 after adding all the terms.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have an expression:

[tex]= 8 \dfrac{3}{8} + 3 \dfrac{3}{8} + 2 \dfrac{3}{8} + \dfrac{3}{8}[/tex]

After simplification:

[tex]= \dfrac{67}{8} + \dfrac{27}{8} + \dfrac{19}{8} + \dfrac{3}{8}[/tex]

[tex]= \dfrac{67+27+19+3}{8}[/tex]

= 116/8

= 29/2

[tex]= 14\dfrac{1}{2}[/tex]

Thus, the simplification form of the expression 8 3/8 + 3 3/8 + 2 3/8 + 3/8 is 14 whole 1/2 or 14 1/2 after adding all the terms.

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Answer:

i dont understand your question

Step-by-step explanation:

Mike's claim that (5,28.6) is a point on the exponential function g(x) is incorrect

The points are given as:

(3,6.5) and (4,17.55)

An exponential equation is represented as:

[tex]y = ab^x[/tex]

Using the given points, we have the following equations:

[tex]ab^3 = 6.5[/tex]

[tex]ab^4 = 17.55[/tex]

Divide both equations:

[tex]ab^4 \div ab^3 = 17.55 \div 6.5[/tex]

Evaluate

b = 2.7

Substitute b = 2.7 in [tex]ab^3 = 6.5[/tex]

[tex]a * 2.7^3 = 6.5[/tex]

Solve for a

[tex]a = \frac{6.5}{2.7^3}[/tex]

Substitute [tex]a = \frac{6.5}{2.7^3}[/tex] and b = 2.7 in [tex]y = ab^x[/tex]

[tex]y = \frac{6.5}{2.7^3} * 2.7^x[/tex]

His point (5,28.6) means that:

x = 5 when y = 28.6

Substitute x = 5 in [tex]y = \frac{6.5}{2.7^3} * 2.7^x[/tex]

[tex]y = \frac{6.5}{2.7^3} * 2.7^5[/tex]

Evaluate

y = 47.385

y = 47.385 and y = 28.6 are not the same

Hence, Mike's claim is incorrect

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Answer:

the answer is 45

see the attachment photo!

Answer:

Area= 288

Perimeter= 72

Step-by-step explanation:

In order to get the area of a rectangle, you multiply the length by the width, 24x12=288.

In order to find the perimeter just add all of the sides, there are 2 sides with a length of 24, and two sides with a width of 12.

24+24+12+12=72

The rate of change of the distance from the particle to the origin at this instant is 3 units per second.

The instantaneous rate of change is the rate of change at a particular instant.

A particle is moving along the curve

[tex]y= 4\sqrt{5x+11} .[/tex]

The rate of change of y is given as:

dy / dx = 2

by differentiating both sides,

[tex]\dfrac{dy}{dx} = 4\dfrac{1}{2\sqrt{5x+11} } 5\dfrac{dx}{dt} \\\\\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\[/tex]

From the question, we have:

(x, y) =  (5,24)

Substitute 5 for x and dy / dx = 2

[tex]\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\\\5= \dfrac{10}{\sqrt{5(5)+11} }\dfrac{dx}{dt}\\\\\\\sqrt{5(5)+11} = 2\dfrac{dx}{dt}\\\\\\\dfrac{dx}{dt} = 6/ 2 = 3[/tex]

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.

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Answer:

1.6e-7, or .00000016

Step-by-step explanation:

70d+2-14d= 79+12d-20

70d-14d-12d= 79-20-2

44d= 57

d= 57/44

Answer:

f(x) = √x + 3

y = √x + 3

√x = y - 3

x = (y - 3)²

Hence inverse of f(x) = (x - 3)² and its domain is x >= 3.

Step-by-step explanation:

hope this helps

Using the image given, the angles that are Alternate Exterior Angles are: 1, 2, 3, 4,13,14, 18, 19.

These are known to be the Alternate exterior angles that are regarded as the pair of angles found on the outer side of the two parallel lines but they are seen on the opposite side of the transversal.

Note that in the image given, there are two parallel lines and two transversal lines.

Note also that to get the Alternate exterior angles, it has to be the angles seen on the seen on the opposite side of the transversal that has crossed the parallels lines and from the image given, only angle 1, 2, 3, 4,13,14, 18, 19 fit into the description.

Therefore, Using the image given, the angles that are Alternate Exterior Angles are: 1, 2, 3, 4,13,14, 18 19.

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Answer:

2/52 so the chance is unlikely.

Step-by-step explanation:

well I think I’m right because sometimes when my family has time we play blackjack in my house for fun or another card game so I should be right.

The modal class is 70 - 80 and the mean speed is 66.4

The table of values is given as:

Speed    Frequency

40 - 50          10

50 - 60          16

60 - 70          19

70 - 80          23

80 - 90          12

The modal class is the class with the highest frequency

The class 70 - 80 has the highest frequency of 23

Hence, the modal class is 70 - 80

Rewrite the frequency table to include the class midpoints

x             f

45          10

55          16

65          19

75          23

85          12

The estimate of the mean speed is then calculated as:

[tex]\bar x =\frac{\sum fx}{\sum f}[/tex]

So, we have:

[tex]\bar x = \frac{45* 10 + 55 * 16 + 65 * 19 + 75 * 23 + 85 * 12}{80}[/tex]

Evaluate

[tex]\bar x = 66.4[/tex]

Hence, the mean speed is 66.4

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no I dont feel like it is the answer

236/100, 59/25, or 2 9/25

Step-by-step explanation:

There are 100 cents in a dollar, so 236/100 is your starting fraction. The simplest improper fraction would be 59/25. But if you're looking for a mixed number, you get 2 9/25.

236 cents is equivalent to 118/50 or 2.36 dollars as a fraction of a dollar.

To solve this problem,

We need to convert 236 cents into dollars.

Since there are 100 cents in one dollar,

we can divide 236 by 100 to get the equivalent dollar value.

⇒ 236 cents ÷ 100 cents per dollar = 2.36 dollars

Now that we know that 236 cents is equivalent to 2.36 dollars,

we can express it as a fraction of a dollar.

To do this, we'll use the fact that one dollar is equivalent to 100 cents, which means that one dollar can be expressed as the fraction 100/100.

To find the fraction of a dollar that 2.36 dollars represents,

we'll divide 2.36 by 1.

⇒ 2.36 ÷ 1 = 2.36/1

To express this as a fraction of a dollar,

Multiply both the numerator and denominator by 100 to get,

⇒ (2.36 x 100) / (1 x 100) = 236/100

Simplifying this fraction, we get,

⇒ 236/100 = 118/50

Therefore,

236 cents is equivalent to 118/50 or 2.36 dollars as a fraction of a dollar.

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Answer:

7 3/5

Step-by-step explanation:

2 x 3 4/5

2 x 19/5

2x19/1x5 = 38/5 = 7 3/5

Answer:

A.264

Step-by-step explanation:

((Area Of triangle*height)=Volume

Area of triangle is the base of the triangle multiplied by height of triangle divided by 2

((8*6)/2)*11=264

Answer:

 x = -2

Step-by-step explanation:

Prime factorize, 27 and 9

27 = 3 *3 * 3 = 3³

  9 = 3*3 = 3²

[tex]\sf \left(\dfrac{1}{27}\right)^{2-x}=9^{3x}\\\\[/tex]

 [tex]\left(\dfrac{1}{3^3}\right)^{2-x}=9^{3x}\\\\(3^{-3})^{2-x}=(3^2)^{3x}\\\\3^{(-3)*(2-x)}=3^{2*3x}\\\\3^{-6+3x} = 3^{6x}[/tex]

Bases are same, so now compare the exponents

     -6 + 3x = 6x

            3x = 6x + 6

       3x - 6x = 6

             -3x = 6

               x  = 6/(-3)

               [tex]\sf \boxed{\bf x = -2}[/tex]

         [tex](x^m)^n=x^{m*n}\\\\\left(\dfrac{1}{a^{m}}\right)=a^{-m}\\[/tex]

Answer:

see the attachment photo!

Using the binomial distribution, it is found that approximately 156 cards must be drawn from the deck before players' tokens move forward 50 times.

It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.

The expected number of trials until q successes is:

[tex]E_s(X) = \frac{q}{p}[/tex]

In this problem, the parameters are given as follows:

q = 50, p = 0.32.

Hence:

[tex]E_s(X) = \frac{50}{0.32} = 156[/tex]

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