Answer:
m₂ = 4 kg
Explanation:
The moment of inertia is defined by
I = ∫ r² dm
for bodies with high symmetry it is tabulated, for a spherical shell
I = 2/3 m r²
in this case the first sphere has a radius of r₁ = 2m and a mass of m₁ = 1 kg, the second sphere has a radius r₂ = 1m.
They ask what is the masses of the second spherical shell so that the moment of inertia of the two is the same.
I₁ = ⅔ m₁ r₁²
I₂ = ⅔ m₂ r₂²
They ask that the two moments have been equal
I₁ = I₂
⅔ m₁ r₁² = ⅔ m₂ r₂²
m₂ = (r₁ / r₂) ² m₁
let's calculate
m₂ = (2/1) ² 1
m₂ = 4 kg
What drives waves?
Soda
Carbohydrates
Energy
6. A lumberjack is standing on a log floating on a lake. She starts from rest, then runs along the log to the end, when she jumps from the first log onto a second. After landing safely on the second log, she slows down and ends up standing on the second log. Both logs both have masses of 150 kg each and the mass of the lumberjack is 70 kg. The lumberjack reaches a speed of 7.0 m/s relative to the shore during her jump. What are the speeds of the two logs and of the lumberjack after she has stopped on the second log
Answer:
a) -3.267 m/s
b) 2.227 m/s
Explanation:
As per the conservation of momentum
m1v1 + m2v2=0
m1= mass of log
m2 = mass of lumber jack
v1 = velocity of log
v2 = velocity of lumber jack
a) Velocity of first log
[tex]-\frac{70*7}{150} = -3.267[/tex] m/s
b) m1v1 + m2v2 = m3v3
Velocity of log
= [tex]\frac{70*7}{150+70} \\2.227[/tex]
A drawback of burning biomass to produce electricity is that it is ___.
A. Nonrenewable
B. Very costly to use
C. A source of air pollution
D. Not available in many areas
Answer: Unsustainable wood harvesting can lead to deforestation, soil erosion, and desertification.
Explanation: you welcome
A drawback of burning biomass to produce electricity is that it is very costly to use. Option B is correct.
What is biomass?Biomass is a low-carbon fuel that is renewable, since a fresh crop can be planted after each harvest.
The chemical formula for biomass is about CHO. It's comparable to coal, except with the addition of an oxygen atom.
The drawbacks of biomass Energy
1. It's not quite clean.
2. High prices in comparison to other options.
3. Deforestation is a possibility.
4. Water is required.
5. It is inefficient.
A drawback of burning biomass to produce electricity is that it is very costly to use.
Hence, option B is correct.
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8. Consider a capacitor that is made of two large conducting plates that are rectangular in shape (1 cm by 6 cm), aligned parallel to each other, and separated by an air-filled gap of 0.001 cm. This capacitor is included in a circuit where a battery provides 15,000 V of potential difference. When the capacitor is fully charged in this circuit, what is the c
Answer: [tex]7.96\ \mu C[/tex]
Explanation:
Given
The dimension of the plate is [tex]1\ cm\times 6\ cm[/tex]
The gap between the plate is [tex]0.001\ cm[/tex]
Voltage applied [tex]V=15,000\ V[/tex]
The capacitance of the capacitor is
[tex]C=\dfrac{\epsilon_o A}{d}\\\\C=\dfrac{8.85\times 10^{-12}\times 1\times 6\times 10^{-4}}{10^{-5}}\\\\C=53.1\times 10^{-11}\ F[/tex]
Charge acquired by the capacitor
[tex]\Rightarrow Q=CV\\\Rightarrow Q=53.1\times 10^{-11}\times 15,000\\\Rightarrow Q=796.5\times 10^{-8}\\\Rightarrow Q=7.96\times 10^{-6}\ C[/tex]
What happened to the combined energy of the two sleds when they collided?
Combined energy of the two sleds will be conserved when they collides.
What is Energy ?Energy is nothing but the ability to do work. there are different energies in different form which are thermal energy, mechanical energy, electric energy and sound energy etc.
According to first law of thermodynamic, Energy neither be created nor be destroyed. it can only be transferred from one form into another form. Energy is expressed in joule (J). its dimensions are [M¹ L² T⁻²].
Energy is conserved throughout the motion,
according to conservation law of energy, initial energy is equal to final energy.
When two sleds coming in opposite direction, it is having mass as well as velocity. hence it has kinetic energy, when they get collide with each other some of total energy gets converted into sound energy as collision cause sound(boom). some of the energy will use to break the material which made the sled and remaining energy will convert in kinetic energy of broken sleds it can be moved in opposite direction or in same direction depending initial energies.
in this collision combined kinetic energy can be converted into sound energy, mechanical energy and again kinetic energy but totally energy is conserved.
Hence combined energy will be conserved.
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what is the reason that causes viewing obstacle and less in sloar radiation?
Answer:
In addition to the sun's angle, atmospheric conditions can affect radiation levels. Cloud cover, air pollution and the hole in the ozone layer all alter the amount of solar radiation that can reach the surface. These factors all cause typical radiation levels to differ.
hope it helps
To solve this, we must be knowing each and every concept behind solar radiation. Therefore, cloud cover, air pollution, and the ozone hole all reduce the quantity of solar energy that reaches the earth's surface.
What is solar radiation?The energy generated by the sun as just a consequence of vast internal processes is known as solar radiation. In a word, the sun's capacity to generate intense nuclear fusion within and around the core enables it to radiate such vast amounts of energy inside the form of both heat and light. The entire process begins at the core of the sun.
Aside from the sun's angle, meteorological variables can influence radiation levels. Cloud cover, air pollution, and the ozone hole all reduce the quantity of solar energy that reaches the earth's surface. All of these variables contribute to variations in normal radiation levels.
Therefore, cloud cover, air pollution, and the ozone hole all reduce the quantity of solar energy that reaches the earth's surface.
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Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the twelve cube edges). If the cube can only be loaded in axial tension such that the force is uniformly applied over - and is normal to - a cube face, what is the lowest possible positive length change the cube can experience under this tension
The question is incomplete. The complete question is :
Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the twelve cube edges). If the cube can only be loaded in axial tension such that the force is uniformly applied over - and is normal to - a cube face, what is the lowest possible positive length change the cube can experience under this tension? The applied tensile force is 102 KN. The unloaded cube edge length is 56 mm. The glass fibers have an elastic modulus of 200 GPa. The epoxy has an elastic modulus of 38 GPa. The cube is comprised of 18 vol% epoxy (the balancing vol % is glass fiber). Hint: The loading axis is intentionally unspecified. Answer Format: Lowest possible length increase (change of length) under tension.
Solution :
Given :
[tex]$E_{glass fibre}$[/tex] = 200 GPa
[tex]$V_{glass fibre} = 82\%$[/tex]
[tex]$E_{epoxy}$[/tex] = 38 GPa
[tex]$V_{epoxy} = 82\%$[/tex]
Edge length = 56 mm
Cube is loaded in axial tension such that the force is uniformly applied over a cube face.
[tex]$E_{\text{composite}}=\frac{E_{glass fibre} \times E_{epoxy}}{(E_{glass fibre .E_{epoxy}})+(E_{fibre}.V_{glass fibre})}$[/tex]
[tex]$E_{composite} = \frac{200 \times 38}{(200 \times 0.18)+(38\times 0.82)}$[/tex]
[tex]$=113.16 $[/tex] GPa
Applied stress [tex]$=\frac{\text{applied load}}{\text{area}}$[/tex]
[tex]$\sigma=\frac{102 \times 10^3 \ N}{56 \times 56 \times 10^{-6} \ m^2}$[/tex]
= 32.5 MPa
By Hooke's law
[tex]$\sigma = E . \epsilon$[/tex]
[tex]$\sigma = E. \frac{\Delta l}{l}$[/tex]
[tex]$\Delta l = \frac{\sigma}{E}\times l$[/tex]
Length change, [tex]$\Delta l =\frac{32.5 \times 10^6 \ Pa}{113.16 \times 10^9 \ Pa}\times 56 \times 10^{-2} \ m$[/tex]
[tex]$\Delta l = \frac{32.5 \times 56}{113.16} \times 10^{-3} \ mm$[/tex]
= 0.016 mm
a space probe with a mass of 4000 kg expels 3,500 of its mass at a velocity of 2000 m/s. what is the velocity of the remaining 500 kg of the probe
Answer:
4.16×103 m/s
Explanation:
A student wants to determine the speed of sound at an elevation of one mile. To do this the student performs an experiment to determine the resonance frequencies of a tube that is closed at one end. The student takes measurements every day for a week and gets different results on different days. Which of the following experiments would help the student determine the reason for the different results?
a. Repeating the experiment on several 10 degree C days and several 20 degree C days
b. Repeating the experiment using a wider range of frequencies of sound
c. Repeating the original experiment for an additional week
d. Repeating the experiment using a longer tube
Answer:
The correct answer is a
Explanation:
The speed of a sound wave depends on the square root of the modulus of compressibility and the density of the medium.
For the same medium, the speed of sound depends on the temperature of the fora
v = [tex]v_o \ \sqrt{1 + \frac{T}{273} }[/tex]
Therefore, the different results that are obtained are due to changes in temperature. The correct answer is a
since this way it has the values of the speed of sound for each temperature, for which it can compare with the results obtained from the trip.
URGENT
__ mass is the measurement of fat on the body. Fat or lean
[tex] \huge\fbox\red{Lean}\ [/tex]
Lean body mass represents the weight of your muscles, bones, ligaments, tendons, and internal organs.[tex] \small\mid{ \underline{ \overline{ \tt \: －ɪƭ'ꜱ \: ʙᴙᴜᴛᴀʟ \: σʋʇ \: ɦэŗǝ}} \mid} [/tex]
Answer:
[tex]lean \: is \: the \: measure \: of \: fat \\ you \: can \: remembar \: by \: using \\ \: the \: term \: lean \: meat \: usually \: used \: to \: \\ eat \\ thank \: you[/tex]
When you blow across the top of a soda bottle, it acts like a closed pipe. If the inside of the bottle is 0.150 long, what is the fifth harmonic frequency
Answer:
The fifth harmonic frequency is 2.9 KHz.
Explanation:
For a closed tube, the fifth harmonic frequency is also the second overtone. So that;
fifth harmonic frequency = [tex]\frac{5V}{4L}[/tex]
where V is the velocity of the sound in air, and L is the length of the tube.
But L = 0.15 m and V = 343 m/s, then:
fifth harmonic frequency = [tex]\frac{5*343}{4*0.15}[/tex]
= [tex]\frac{1715}{0.6}[/tex]
= 2858.33 Hertz
fifth harmonic frequency = 2.9 KHz
The fifth harmonic frequency of the soda bottle is approximately 2.9 KHz.
Answer:
2828.33
Explanation:
answer for acellus
What is the centripetal force for a roller coaster if the mass is 10 kg and the normal force is 25 N?
Answer:
Fc = 123 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
[tex] Fnet = Fapp + Fg[/tex]
Where;
Fnet is the net force.
Fapp is the applied force.
Fg is the force due to gravitation.
Given the following data;
Normal force = 25N
Mass = 10kg
To find the centripetal force;
From the net force, we have the following formula;
Fc = N + mg
Where;
Fc is the centripetal force.
N is the normal force.
mg is the the weight of the object.
Substituting into the formula, we have;
Fc = 25 + 10(9.8)
Fc = 25 + 98
Fc = 123 Newton
NO LINKS: Which of the following best demonstrates Newton's Third Law?
Gravity is a force pulling down on you.
The ahrder you hit a volleyball the faster it will get over the net
Air resistance slows down a parachutist
Your foot pushing on the floor and the floor pushing back
The best demonstration that applies to Newton's Third Law of motion would be D) When you walk your foot pushes down on the ground while the ground pushes back on your foot.
------------------
Newton's Third Law states that for every action, there is an equal and opposite reaction. This is actually explains that forces come in pairs and forces are an interaction between two objects. As per the correct option given in the question explains Newton’s Third Law.
------------------
When you walk your foot (say object A) pushes down on the ground while the ground (say object Q) pushes back on your foot with the same force but in the opposite direction.
Please please help me please please help please please help me please
Answer:
I think its D, Does the wave travel In a Vaccum?
Answer:
It's C. Does the wave transfer energy?
Which of the following was used to provide the oldest measurement of Earth's age?
A) Isotopic dating of fossils from the Cambrian period
B) Isotopic dating of meteor fragments
C) Relative dating of fossils in stratigraphic layers
D) Carbon dating of fossils from the Cambrian period
Answer:
Isotopic dating of meteor fragments
Explanation:
Earth is so old that its age can only be determined using isotopic dating. The oldest measurement of Earth's age was determined using isotopic dating of meteor fragments.
Answer: Isotopic dating of meteor fragments
Explanation:
A column of argon is open at one end and closed at the other. The shortest length of such a column that will resonate with a 200 Hz tuning fork is 42.5 cm. The speed of sound in argon must be: Group of answer choices
Answer:
The speed of sound in the argon is 340 m/s.
Explanation:
Given;
fundamental frequency, f₀ = 200 Hz
length of the pipe, L = 42.5 cm = 0.425 m
A pipe that is open at one end and closed at another end is known as a closed pipe.
The wavelength for the first harmonic is calculated as;
L = Node -------> Antinode
L = λ/4
λ = 4L
The speed of the sound is calculated as;
v = fλ
where;
v is the speed of the sound
v = f x 4L
v = 200 x (4 x 0.425)
v = 340 m/s
Therefore, the speed of sound in the argon is 340 m/s.
A measure of the disorder of a system is called
Answer:
Entropy is typically defined as either the level of randomness (or disorder) of a system or a measure of the energy dispersal of the molecules in the system.
Answer:
entropy
Explanation:
edge2021
A balloon with a charge of 4.0 µC is held a distance of 0.70 m from a second balloon having the same charge. Calculate the magnitude of the repulsive force. (Hint: µ is a metric prefix that means micro or 10 -6 so 4.0 µC means 4.0 microcoulombs
Answer:
Im sorry I do not know how to do this, I hope you will be able to figure it out
Explanation:
3.Which of the following is a derived physical quantitySingle choice.
Length
Mass
Stress
Time
Answer:
length
Explanation:
Legth is derived physical quantity
[tex] \sf{ What \: is \: a \: parallel \: circuit? }[/tex]
[tex] \\ \\ \\ \\ \\ [/tex]
Answer:
parallel circuit is a kind of circuits in which all components are connected between the same two sets of electrically common points, creating multiple paths for the current to flow from one end of the battery to the other:
Answer:
Gadhe hote hai log and usme sabse pehele aati hai Jonain jaise log waah waah xD
Brainliest krdena warna chappal padenge -,-
A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. (a) What is the velocity of the top of the ladder when the base is given below
This question is incomplete, the complete question is;
A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. (a) What is the velocity of the top of the ladder when the base is given below
7 feet away from the wall
15 feet away from the wall
20 feet away from the wall
Answer:
- When x is 7 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -7/12 ft/s
- When x is 15 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -3/2 ft/s
- When x is 20 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -8/3 ft/s
Explanation:
Given the data in the question;
Let [tex]r[/tex]ft and [tex]x[/tex]ft represent the distance of the top of ladder from the ground and the distance of the bottom of ladder from the wall respectively.
Now using the Pythagoras Theorem ( right angled triangle ).
(hypotenuse)² = ( adjacent )² + ( opposite )²
so
r² = ( 25 )² - x²
r² = 625 - x² ------- let this be equation 1
now, we differentiate with respect to t
2r [tex]\frac{dr}{dt}[/tex] = 0 - 2x [tex]\frac{dx}{dt}[/tex]
r [tex]\frac{dr}{dt}[/tex] = -x [tex]\frac{dx}{dt}[/tex]
[tex]\frac{dr}{dt}[/tex] = -x [tex]\frac{dx}{dt}[/tex] × 1/r
[tex]\frac{dr}{dt}[/tex] = -x/r [tex]\frac{dx}{dt}[/tex]
Now, from equation, r² = 625 - x²
r = √( 625 - x² )
Then
[tex]\frac{dr}{dt}[/tex] = -x / √( 625 - x² ) [tex]\frac{dx}{dt}[/tex]
given that, The base of the ladder is pulled away from the wall at a rate of 2 feet per second i.e [tex]\frac{dx}{dt}[/tex] = 2 ft/s
so;
[tex]\frac{dr}{dt}[/tex] = ( -x / √( 625 - x² ) ) × 2
[tex]\frac{dr}{dt}[/tex] = -2x / √( 625 - x² )
∴
When x is 7 feet away from the wall;
[tex]\frac{dr}{dt}[/tex] = -2(7) / √( 625 - (7)² )
[tex]\frac{dr}{dt}[/tex] = -14 / √( 625 - 49 )
[tex]\frac{dr}{dt}[/tex] = -14 / √576
[tex]\frac{dr}{dt}[/tex] = -14 / 24
we simplify
[tex]\frac{dr}{dt}[/tex] = -7/12 ft/s
Therefore, When x is 7 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -7/12 ft/s
When x is 15 feet away from the wall
[tex]\frac{dr}{dt}[/tex] = -2(15) / √( 625 - (15)² )
[tex]\frac{dr}{dt}[/tex] = -30 / √( 625 - 225 )
[tex]\frac{dr}{dt}[/tex] = -30 / √400
[tex]\frac{dr}{dt}[/tex] = -30 / 20
we simplify
[tex]\frac{dr}{dt}[/tex] = -3/2 ft/s
Therefore, When x is 15 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -3/2 ft/s
When x is 20 feet away from the wall
[tex]\frac{dr}{dt}[/tex] = -2(20) / √( 625 - (20)² )
[tex]\frac{dr}{dt}[/tex] = -40 / √( 625 - 400 )
[tex]\frac{dr}{dt}[/tex] = -40 / √225
[tex]\frac{dr}{dt}[/tex] = -40 / 15
we simplify
[tex]\frac{dr}{dt}[/tex] = -8/3 ft/s
Therefore, When x is 20 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -8/3 ft/s
1. What exactly is science?
Write the definition of
science in your own words.
Answer:
A practical activity about the study of the structure of the natural and physical world that can be shown thorough experiments and study's.
Explanation:
An electron is accelerated through 1.90 103 V from rest and then enters a uniform 1.80-T magnetic field.
(a) What is the maximum magnitude of the magnetic force this particle can experience?
Answer:
https://www.slader.com/discussion/question/an-electron-is-accelerated-through-240-times-103-v-from-rest-and-then-enters-a-uniform-170-t-magnetic-field-what-are-a-the-maximum-and-b-the-9e425fbd/
( Here is solution)
Please please help me please please help
Answer:
A. The medium through which it travels
Hoover Dam on the Colorado River is the highest dam in the United States at 221 m, with an output of 1300 MW. The dam generates electricity with water taken from a depth of 100 m and an average flow rate of 640 m3/s
(a) Calculate the power in this flow in watts. 627200000XW Enter a number
(b) What is the ratio of this power to the facility's average of 680 MW? Additional Materials Reading
Answer:
a) 627840000 W
b) 0.9233
Explanation:
The rate at which energy flows through the dam for the generation of electricity is proportional to the volulme flow rate times the potential energy per unit volume.
Mathematically,
P = Q(ρgh)
Where, ρ is water density, g is accelaration due to gravity, h is height through which water falls over the turbine and Q is the discharge.
a) The power can be calculated as
P = 640(1000×9.81×221)
P = 627840000 W
b) The ratio = Calculated power / avarage power
= 62784×10^4/680×10^6
= 0.9233
A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing through the cross-sectional area in 10s is
Each electron has a charge of :
[tex]1.6 \times 10 {}^{ - 19} \: C[/tex]
For producing 1 Cuolomb charge we need :
[tex] \mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }[/tex][tex] \dfrac{10 {}^{19} }{1.6} [/tex][tex] \dfrac{10\times 10 {}^{19} }{16} [/tex][tex] \dfrac{100 \times 10 {}^{18} }{16} [/tex][tex] \mathrm{6.24 \times 10 {}^{18} \: \: electrons}[/tex]Now, for producing 0.009 C of charge, the number of electrons required is :
[tex]0.009 \times 6.24 \times {10}^{18} [/tex][tex]0.05616 \times 10 {}^{18} [/tex][tex] \mathrm{5.616 \times 10 {}^{16} \: \: electons}[/tex]_____________________________
So, Number of electrons passing through the cross section in 3.6 seconds is :
[tex] \mathrm{5.616 \times 10 {}^{16} \: \: electrons} [/tex]
Number of electrons passing through it in 1 Second is :
[tex] \dfrac{5.616 \times {10}^{16} }{3.6} [/tex][tex] \mathrm{1.56 \times 10 {}^{16} \: \: electrons}[/tex]Now, in 10 seconds the number of electrons passing through it is :
[tex]10 \times \mathrm{1.56 \times 10 {}^{16} \: \: }[/tex][tex] \mathrm{1.56 \times 10 {}^{17} \: \: electrons}[/tex]_____________________________
[tex]\mathrm{ \#TeeNForeveR}[/tex]
Which of the following best explains the greater difficulty in stopping a 1000-kg car
moving at 174 km/h compared to an identical 1000-kg car moving at 100 km/h?
Stopping a 1000 kg car moving at a speed of 174 km/h will be more difficult than stopping an identical car moving at 100 km/h.
This can be explained by using Newton's second law of motion which says that the rate of change of momentum of a body is equal to the force applied.
We know that momentum of a body is the product of its mass and velocity.The momentum of the car moving at 174 km/h = [tex]1000\, kg \times 174\, km/h = 174000 \, kg.km/h[/tex].The momentum of the car moving at 100 km/h = [tex]1000\, kg \times 100\, km/h=100000 kg.km/h[/tex].Therefore, the car moving at 174 km/h has higher momentum and from Newton's second law of motion, a higher force would be required to stop this car.
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Monochromatic light with lambda equals 630 space n m is incident on a single slit. The slit width is 0.8 mm. If the distance between the screen and slit is 1.8 m, what is the width of the central bright fringe on the screen
Answer:
The angular width is "[tex]1.575\times 10^{-3} \ rad[/tex]" and the linear width is "[tex]2.835\times 10^{-3} \ m[/tex]".
Explanation:
Given:
Wavelength,
[tex]\lambda = 630 \ nm[/tex]
or,
[tex]=630\times 10^{-9} \ m[/tex]
Slit width,
[tex]a = 0.8 \ mm[/tex]
or,
[tex]=0.8\times 10^{-3} \ m[/tex]
Distance between slit and screen,
[tex]D = 1.8 \ m[/tex]
As we know,
The central bright fringe's angular height,
⇒ [tex]\theta = \frac{2 \lambda}{a}[/tex]
[tex]= \frac{2\times 630\times 10^{-9}}{0.8\times 10^{-3}}[/tex]
[tex]=1.575\times 10^{-3} \ rad[/tex]
and,
The linear width will be:
⇒ [tex]x_o=\frac{2D \lambda}{a}[/tex]
By substituting the values, we get
[tex]=\frac{3\times 1.8\times 630\times 10^{-9}}{0.8\times 10^{-3}}[/tex]
[tex]=2.835\times 10^{-3} \ m[/tex]
This is 100 points. When i find out how i will put the first person to answer as brainiest.
i have no question. God bless you all
Answer:
Thank you so much! Have a great day!
A charged rod is brought near one end of a long, uncharged metal block. Students want to experimentally measure the resulting charge distribution along the entire length of the block. They have a small, positively charged sphere on a string that can be used as a test charge with negligible effect on the other charges. They will observe whether the sphere is attracted or repelled when held near the rod. Which of the following describes and justifies a procedure that will provide data to determine the entire charge distribution?
a. Hold the sphere near the end of the block closest to the rod, because that will give experimental data about both ends of the block.
b. Hold the sphere near each end of the block, because that will give experimental data about both ends of the block.
с. Hold the sphere near each end of the block and near the block's middle, because that will give experimental data about the area along the length of the block.
d. Hold the sphere near each end of the block and at a number of points along the length of the block, because that will give experimental data for the whole block.
Answer:
d
Explanation:
The sphere is positively charged so that when it comes in contact with the rod, its positive charges will repel to the other end. Hence, Hold the sphere near each end of the block, because that will give experimental data about both ends of the block.
What is polarization?Polarization is the separation of charges into two poles due electrostatic repulsion. Two similar charges will repel and opposite charges attracts each other.
When a charged or polar substance get in contact with a non-polar substance, the nonpolar one will deform in such a way that the electrons from the polar one will repel the electrons of nonpolar and there occurs a temporary charge separation in non polar substance creating an induced polarity.
Here, when the positive sphere comes in contact with the charged rod, the positive charges will align to the opposite pole of the rod away from the sphere and the negative charges will align near the sphere.
Thus there occurs an attractive force at one end and repulsion at the other end. Thus, holding the sphere at each end will data about charge distribution.
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