Last month, a carpenter made 2 tables. This month, he made 50% fewer tables. How many tables did the carpenter make this month?

Answer:

3:4

Step-by-step explanation:

18 = 2 * 3 * 3

24 = 2 * 2 * 2 * 3

HCF = 2 * 3 = 6

Divide by 6

18: 24 = 18÷6  : 24÷6

          = 3 : 4

Answer:

it's 3:4

Step-by-step explanation:

18 ÷ 6 : 24 ÷ 6

3 : 24 ÷ 6

=3:4

Answer:

9. x=102

10. x=56

11. x=104

12. x=138

Step-by-step explanation:

9.  In this problem, they are alternate exterior angles, meaning they are the same value.  x=102

10.  x is a corresponding angle, meaning they are the same. x=56

11. There are consecutive interior angles. The sum of these two angles is 180. to find x, subtract 76 from 180.  180-76 = 104  x = 104

12. These two angles are verticle angles, meaning they are equivalent. x = 138

Answer:

Step-by-step explanation:

all angles are congruent:false

B.consecutive angles are congruent:false

corresponding angles are congruent:true.

c.diagonals bisect eachother:true.

d.diagonals bisect opposite angles:false.

Answer:

step 1: what have you learned?

We cant help you because we do not know what you have learned.

but if you comment your vocab words and what u learned  i can help you  

   Step-by-step explanation:

Answer:

His answer was correct:

(200*0.09)=18

18*16=288

200+288=488

Answer:

X is 120° I hope this helps you

Answer:

(1, 24 )

Step-by-step explanation:

Substitute any value of x into the equation and evaluate for y

x = 1 → y = 3(1) + 21 = 3 + 21 = 24 , then

(1, 24 ) is a a solution to the equation

Answer:

16

Step-by-step explanation:

2^-2=0.25

2^6=64

times

=16

Answer:

$10.91

Step-by-step explanation:

7 gallons cost:

[tex](\frac{7.79}5}) (7)=\frac{(7.79)(7)}{5} =10.906[/tex]  

rounded to cents: 10.91

I hope this help you

To prove that tan(u - v) does not equal tan u - tan v, we start by assuming values for u and v.

To do this, we assume the following values

[tex]\mathbf{u = 75}[/tex]

[tex]\mathbf{v = 45}[/tex]

So, we have:

[tex]\mathbf{tan(u - v) \ne tan(u) - tan(v)}[/tex]

Substitute the assumed values for u and v

[tex]\mathbf{tan(75 - 45) \ne tan(75) - tan(45)}[/tex]

Subtract 45 from 75

[tex]\mathbf{tan(30) \ne tan(75) - tan(45)}[/tex]

Using a calculator, calculate the values of tan(30), tan(45) and tan(75)

So, we have:

[tex]\mathbf{0.5774 \ne 3.7321 - 1}[/tex]

Subtract 1 from 3.7321

[tex]\mathbf{0.5774 \ne 2.7321}[/tex]

Notice that the expression on the left-hand side and the expression on the right-hand side are not equal.

Hence, [tex]\mathbf{tan(u - v) \ne tan(u) - tan(v)}[/tex] is true

Read more about proofs of trigonometry at:

https://brainly.com/question/22698523

Answer:

Interval Notation: [-2, 10]

Set Notation: {x|-2≤x≤10}

Step-by-step explanation:

Answer:

21

Step-by-step explanation:

The average rate of change of function f(x) from x = a to x = b is

[tex] \dfrac{f(b) - f(a)}{b - a} [/tex]

Here we have

a = -1

b = 2

f(a) = f(-1) = 1

f(b) = f(2) = 64

[tex] \dfrac{f(b) - f(a)}{b - a} = [/tex]

[tex] = \dfrac{f(2) - f(-1)}{2 - (-1)} = [/tex]

[tex] = \dfrac{64 - 1}{2 + 1} [/tex]

[tex] = \dfrac{63}{3} [/tex]

[tex] = 21 [/tex]

Answer:

C

Step-by-step explanation:

For a relation to be a function then every value of x must map to exactly one unique value of y.

Here every x- value corresponds to exactly one y- value

Then the ordered pairs represent a function

Let A be a 3×2 matrix, L its left inverse, and R its right inverse. L and R are then matrices such that LA = I₂ (the 2×2 identity matrix) and AR = I₃ (the 3×3 identity matrix). Clearly L must be 2×3 and R must be 3×2 in order for the matrix products to be defined.

To find L and R, we start by introducing a square matrix on the the left sides of either equation above. In particular, we uniformly multiply both sides by the transpose of A, then solve for the inverse.

For the left inverse, we have

[tex]LA=I[/tex]

[tex](LA)A^\top = IA^\top[/tex]

[tex]L\left(AA^\top\right) = A^\top[/tex]

[tex]\left(L\left(AA^\top\right)\right)\left(AA^\top\right)^{-1} = A^\top \left(AA^\top\right)^{-1}[/tex]

[tex]L\left(\left(AA^\top\right)\left(AA^\top\right)^{-1}\right) = A^\top \left(AA^\top\right)^{-1}[/tex]

[tex]LI = A^\top \left(AA^\top\right)^{-1}[/tex]

[tex]L = A^\top \left(AA^\top\right)^{-1}[/tex]

We do the same thing for the right inverse, but take care with how we multiply both sides of AR = I₃.

[tex]AR=I[/tex]

[tex]A^\top(AR)=A^\top I[/tex]

[tex]\left(A^\top A\right)R = A^\top[/tex]

[tex]\left(A^\top A\right)^{-1} \left(\left(A^\top A\right)R\right) = \left(A^\top A\right)^{-1} A^\top[/tex]

[tex]\left(\left(A^\top A\right)^{-1} \left(A^\top A\right)\right) R = \left(A^\top A\right)^{-1} A^\top[/tex]

[tex]IR = \left(A^\top A\right)^{-1} A^\top[/tex]

[tex]R = \left(A^\top A\right)^{-1} A^\top[/tex]

Answer:

C. y= -2x^2 + 4

Step-by-step explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex:  

(

0

,

−

4

)

Focus:  

(

0

,

−

33

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

−

31

8

x

y

−

2

−

12

−

1

−

6

0

−

4

1

−

6

2

−

12

________________

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex:  

(

0

,

4

)

Focus:  

(

0

,

33

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

31

8

x

y

−

2

12

−

1

6

0

4

1

6

2

12

______________

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex:  

(

0

,

4

)

Focus:  

(

0

,

31

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

33

8

x

y

−

2

−

4

−

1

2

0

4

1

2

2

−

4

_______________

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex:  

(

0

,

−

4

)

Focus:  

(

0

,

−

31

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

−

33

8

x

y

−

2

4

−

1

−

2

0

−

4

1

−

2

2

4

Answer:

Step-by-step explanation:

Answer:

c i think

Step-by-step explanation:

I'm sorry if not

Answer:

Below!

Step-by-step explanation:

First, let's simplify the roots for each.

Please check out the file so you can see the graphed points on the line. I apologize for the bad mouse-writing.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer:

Step-by-step explanation:

The point on the circumference of the circle with the equation (x+10)^(2)+(y+1)^(2) = 25 is (-6 , 2).

If a circle O has radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane,

then, its equation is given as:

(x-h)^2 + (y-k)^2 = r^2

The given equation is

(x+10)^(2)+(y+1)^(2)=25

Where,

h = - 10

k = -1

r = 5

If x = -6 and y = 2

then the given equation of circle is stidfy the given points.

Hence, the point on the circumference of the circle with the equation (x+10)^(2)+(y+1)^(2) = 25 is (-6 , 2).

Learn more about equation of a circle here:

https://brainly.com/question/10165274

#SPJ2

Step-by-step explanation:

the general slope intercept form is

y = ax + b

a is the slope.

b is the y-intercept (the point, where the line crosses the y-axis, meaning the y value when x=0).

we get b by using the point coordinates in the equation and solve for b :

-8 = -3×3 + b = -9 + b

1 = b

so, the full line equation is

y = -3x + 1

Answer:

B

Step-by-step explanation:

He added 4 to 2 instead of multiplying.

The second differential of the function is 3/7

Given the differential function [tex](x +2y)=\frac{dy}{dx} (2x-y)[/tex]

Differentiate both sides with respect to x implicitly

[tex](x +2y)=\frac{dy}{dx} (2x-y)[/tex]

[tex]1+2y'=y"(2x-y)+y'(2-y') \\y''=\frac{1+2y'}{(2x-y)+y'(2-y') }[/tex]

Get the first derivative at the point (3, 0)

[tex]y'=\frac{2x-y}{x+2y} \\y'=\frac{2(3)-0}{0+2(3)}\\y'=\frac{6}{6} \\y'=1[/tex]

Substitute into the second derivative to have:

[tex]y''=\frac{1+2y'}{(2x-y)+y'(2-y') }\\y''=\frac{1+2(1)}{(2(3)-0)+(1)(2-(1)) }\\y''=\frac{3}{6+1} \\y''=\frac{3}{7}[/tex]

Hence the second differential of the function is 3/7

learn more on differential equation here; https://brainly.com/question/18760518

Complete question:

If (x 2y)dy/dx=2x-y what is the value of [tex]\frac{d^2y}{dx^2}[/tex] the point (3,0)

Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x

Table 1:

y = k × x

30 = k × 5

30 = 5k

k = 30/5

k = 6

So,

y = 30

y = 30 k = 6

y = 30 k = 6x = 5

y = 30 k = 6x = 5Equation: y = 6x

y = k × x

y = 10 × 8

y = 80

So,

y = 80

y = 80 k = 10

y = 80 k = 10x = 8

y = 80 k = 10x = 8Equation: y = 10x

y = 3x

18 = 3x

x = 18/3

x = 6

So,

y = 18

y = 18k = 3

y = 18k = 3x = 6

y = 18k = 3x = 6Equation: y = 3x

y = 2x²

72 = 2x²

x² = 72/2

x² = 36

x = √36

x = 6

So,

y = 72

y = 72k = 2

y = 72k = 2x = 6

y = 72k = 2x = 6Equation: y = 2x²

Table 2:

y = k/x

5 = k/6

5 × 6 = k

30 = k

So,

y = 5

y = 5k = 30

y = 5k = 30x = 6

y = 5k = 30x = 6Equation: y = 30/x

y = k/x

y = 36/4

y = 9

So,

y = 9

y = 9k = 36

y = 9k = 36x = 4

y = 9k = 36x = 4Equation: y = 36/x

y = 60/x

20 = 60/x

20x = 60

x = 60/20

x = 3

So,

y = 20

y = 20k = 60

y = 20k = 60x = 3

y = 20k = 60x = 3Equation: y = 60/x

y = 24/x

y = 24/12

y = 2

So,

y = 2

y = 2k = 24

y = 2k = 24x = 12

y = 2k = 24x = 12Equation: y = 24/x

Read more:

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