Using trigonometric ratio, the length of the ladder that reached the window is 20.03 feet
What is an equation?
An equation is an expression that shows the relationship between two or more numbers and variables.
Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.
Let l represent the length of the ladder, using trigonometric ratio:
sin(64) = 18/l
l = 20.03 feet
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PLEASE HELP !!!!!!!!
Answer:Angle BCE
Step-by-step explanation:
look across from point C
5. Caroline is 12 years younger than
twice Anna's age.
Caroline is 32 years old. How old is
Anna?
Answer:
10
Step-by-step explanation:
32 - 12 (because C is 12 years younger) = 20
20 / 2 (because twice Anna's age, so we do the inverse) = 10
Anna is 10 years old.
Hope this helps!
Answer:44
Step-by-step explanation:
53. (a) if the symbol [tex]\lbrack\rbrack[/tex] denotes the greatest integer function defined in example 10 , evaluate
(i) [tex]\lim _{x\rightarrow-2^+}\lbrack x\rbrack[/tex]
(ii) [tex]\lim _{x\rightarrow-2}\lbrack x\rbrack[/tex]
(iii) [tex]\lim _{x\rightarrow-2.4}\lbrack x\rbrack[/tex]
If x is between two consecutive integers such that n ≤ x < n + 1, then the greatest integer function [x] maps x to the largest integer smaller than x so that [x] = n.
(i) If x is approaching -2 from above, that means x > -2. As x gets closer to -2, we essentially have -2 < x < -1, so that [x] will approach
[tex]\displaystyle \lim_{x\to-2^+} [x] = \boxed{-2}[/tex]
(ii) However, if x is approaching -2 from below, then x < -2, so that [x] = -3. In other words
[tex]\displaystyle \lim_{x\to-2^-} [x] = -3 \neq -2[/tex]
Because the one-sided limits do not match, the two-sided limit
[tex]\displaystyle \lim_{x\to-2} [x] ~~\boxed{\text{does not exist}}[/tex]
(iii) -2.4 lies between -3 and -2, so
[tex]\displaystyle \lim_{x\to-2.4} [x] = \boxed{-3}[/tex]
how to answer this question ?
The sides
12-3a
12-3a
4(2a-5)=8a-40
so for perimeter we + them
(12-3a)+(12-3a)+(8a-40)
=
2a-16
In City Park, the playground takes up 3/8 of the area. The soccer field area is 1/3 of the playground area. The product 13×38 can be used to find the area of the soccer field. Which is the area of the soccer field?
The area of the city park will be equal to 3952 square units.
What is the area?The Area is defined as the space occupied by the two-dimensional geometry in a plane.
We have the following information:-
In City Park, the playground takes up 3/8 of the area:-
[tex]\rm PGA=\dfrac{3}{8}\times CP[/tex]
The soccer field area is 1/3 of the playground area.
[tex]\rm SF=\dfrac{1}{3}\times PGA[/tex]
The product 13×38 can be used to find the area of the soccer field
SF= 13 x 38=494 square units
Noe the PGA will be:-
PGA =3 x SF
PGA= 3 x494=1482 square unit
Now the area of the city park will be calculated as:-
[tex]\rm CP=\dfrac{8}{3}\times PGA\\\\\\CP=\dfrac{8}{3}\times 1482[/tex]
CP=3952 square unit
Hence the area of the city park will be equal to 3952 square units.
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Find the quotient 16)4.88
Answer:
if this is 4.88/16 then the answer is 0.305.
A cuboid with dimensions 45 cm by 16 cm by 12 cm is cut to form smaller cubes of
length 4 cm. What is the maximum number of cubes that can be obtained?
Answer:
135 cubes
Step-by-step explanation:
Volume of cuboid :
45 x 16 x 12720 x 128,640 cm³Volume of a small cube :
(4)³64 cm³Number of cubes :
n = 8,640/64n = 135 cubesQuestion 1 (1 point)
Consider this right triangle. Determine whether each equation is correct. Select Yes or No fo
each equation
А
5
3
4
4
С
00
B
COS(A)
5
3
O Yes
ONO
Next Page
Yes
Step-by-step explanation:
[tex] \cos( \alpha ) = \frac{base}{hypoteneuse} [/tex]
Its just correct..
Can somebody please help me?
Answer:
1 23/36
Step-by-step explanation:
hope this helped
Please help me find the value of x
Check the picture below.
SOMEONE PLEASE HELP ME
Answer:
A= 77/2 or 38.5 cm^2 and p= 29.5 cm
Step-by-step explanation: Remember the formula for area and perimeter for a triangle A=1/2bh and P= a+b+c. So the equations would look like A=1/2 x 11 x 7 and P= 11 + 11 + 7.5 and that'll result in A= 77/2 or 38.5 cm^2 and p=29.5 cm.
Please help me solve these problems *all of them solved. I have been struggling the other day doing these. please give me the answers and the explanation.
Step-by-step explanation:
Q1. volume of a cylinder
Ans. The way you find a volume of a regular object is multiplying the base area by height Here the base area is a circle so formula would be pi times r square (πr^2). To get the volume multiply it by 4. Final answer would be π(3)^2*4
find x - and - y intercepts of the following equation. a. 4x - 3y = 12 b. y = 1/3x c. y = 2x + 5 d. y = 6
✒️ Equation
••••••••••••••••••••••••••••••••••••••
A. To find the x - intercept, let y = 0.
[tex]\tt \: \: \large \tt \: \begin{array}{|c|} \hline \tt \: 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4x \: - \: 3(0) \: = \: \tt\underline{\blue{ 12 }} \\ \tt4x \: - \: 0 \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ \: x \: = \: 3 }} \\ \\ \tt \: x ↬\: the \: intercept\\ \tt\\ \hline\end{array} \: \\ [/tex]
[tex] \\ [/tex]
To find the y - intercept, let x = 0
[tex]\large \tt \: \begin{array}{|c|} \hline \tt 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4(0) \: - \: 3y \: = \: \tt\underline{\blue{ 12 }} \\ \tt \: 0 \: - \: 3y \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ y \: = \: - 4 }} \\ \\ \tt \: x ↬\: the \: intercept \\ \ \\ \hline\end{array} \: [/tex]
[tex] \\ [/tex]
B. Replace x with 0 and solve for y. Then replace y with 0 and solve for x.
[tex]\large \tt \: \begin{array}{|c|} \hline \tt y \: - \: intercept: \: y \: = \: \frac{1}{3}(0) \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \tt = \tt\underline{\red{ 0 }} \\ \\ \tt \: x \: and \: y ↬ intercepts: (0,0)\\ \\ \tt \: x \: ↬ \: intercepts: \: 0 = \: \frac{1}{3} x \\ \quad\quad \quad \quad\quad\quad\quad\quad\quad \: \tt \tt\underline{\red{ \: 0 \: = \: x }} \ \\ \\ \hline\end{array} \\ [/tex]
[tex] \\ [/tex]
The equation in b is a linear equation in the form y = mx, where m is any real number. the graph of any equation in the form y = mx is always a line that passes through the origin, which means that both the x - and - y - intercepts are (0,0).
[tex]\large \tt \: \begin{array}{|c|} \hline \tt intercept \: for \: m \: of \: y \: = \: \tt\underline{\red{ mx }} \\ \hline\end{array}[/tex]
[tex] \\ [/tex]
C. Replace y with 0, then solve for the x.
[tex]\large \tt \: \begin{array}{|c|} \hline \tt x ↬ \: intercept : \: 0 \: = \: 2x \: \ + 5 \\ \\ \tt - 5 \: = \: 2x\\ \\ \tt \: \frac{ - 5}{2} \: = \: x\\ \\ \tt \: x \: ↬ \: intercept \ \\ \hline\end{array}[/tex]
Now, replace x with 0, and then solve for y.
[tex]\large \tt \: \begin{array}{|c|} \hline \tt y ↬ \: intercept: \: y \: = \: 2(0) \: + \: 5 \\ \\ \tt \: y \: = \: 0 \: + \: 5 \\ \\ \tt \: y \: = \: 5 \\ \\ \tt y ↬ \: intercept \ \\ \\ \hline\end{array}[/tex]
The equation in 11c is written in the form y = mx + b. note than in the form, when x is replaced by 0 to find the y↬intercept. you are left with the constant b.
[tex]\large \tt \: \begin{array}{|c|} \hline \tt \: the \: y ↬ intercept \: of \: y \: = \: mx \: + \: b \\ \hline\end{array}[/tex]
If the equation is in the form y = mx + b, where m and b are real numbers, then the y ↬intercept is b.
[tex] \\ [/tex]
D. Remember that the graph of y = 6 is horizontally line parallel to the x axis that passes through the y axis at (0,6). since the line is parallel to x axis, it will not incest tha x-axis. Hence, there is no x ↬ intercept.
[tex] \\ \\ \\ [/tex]
[tex]\pmb{(ノ‥)ノ}\qquad\qquad\qquad\qquad\boxed{\tt{[05-12-2022]}} \\ \qquad\qquad\qquad\qquad\qquad\qquad\boxed{\tt{[03:11 \: am]}}[/tex]
Given the following formula, solve for I.
P = 2(1 + 6)
PLEASE HELP!!!
Step-by-step explanation
Here ...I'm not too sure about the question as you have written
P = 2 ( 1 + 6 ) and ask to solve for L ...
.So I guess the question you have written is wrong .. ...and I guess there should be L in the place of 1.
...So let me correct the question....
P = 2 ( l + 6 )
P = 2l + 12
P - 2l = 12
- 2l = 12 - P
- 2l = - P + 12
Change the sign of both side of the equation...
2l = P + 12
divide both side by the same number...
L = ( P + 12 ) ÷ 2
[tex]l = \frac{1}{2} p - 12 \times \frac{1}{2} \\ [/tex]
Calculate the product of rational numbers...
[tex]l = \frac{1}{2} p - 6 \\ [/tex]
In circle H with m/GHJ = 82 and GH = 12 units, find the length of arc GJ.
Round to the nearest hundredth.
H
The length of the arc GJ is 17.17 units if the in circle H with m/GHJ = 82 and GH = 12 units.
What is a circle?It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)
We have angle GHJ = 82 units
Length of GH = 12 units
We know:
s = 2πr(θ/360)
s = (2π)12(82/360)
s = 17.17 units
Thus, the length of the arc GJ is 17.17 units if the in circle H with m/GHJ = 82 and GH = 12 units.
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X/3 + 1 = ×/8 + 1/11
solve the question please pls
Answer:
x/3+3=x/8+1/11
x+9/3=11x+8/88
88(x+9)=3(11x+8)
88x+729=33x+24
88x-33x=729-24
55x=705
x=705/55
x=12.80
In how many ways can we color the $8$ vertices of an octagon each red, green, or blue, so that no two adjacent vertices are the same color
There are 258 ways to color the octagon such that no two adjacent vertices are the same color
How to determine the number of ways?The given parameters are:
Sides, n = 8 --- the sides of an octagonColors, r = 3 i.e. red, green and blueSince no two adjacent vertices are the same color, we use the following chromatic polynomial of an octagon equation
Ways = (r - 1)⁸ + (r -1)
Substitute 3 for r
Ways = (3 - 1)⁸ + (3 -1)
Evaluate
Ways = 258
Hence, there are 258 ways to color the octagon
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What is 1/4 of 12? I can’t figure it out.
Answer:
3
Step-by-step explanation:
1/4 of 12 means (1/4) x 12
=> (1/4)x12
=> 12/4
=> 3
Answer: Heyaa! ~
Your Answer would be 3!
Step-by-step explanation:
We can write 1/4 of 12 as 1/4 × 12
To multiply fractions, follow the given steps:
Multiply the numerators.
Multiply the denominators.
Reduce the resultant fraction to its lowest terms.
Now,
1/4 × 12 = (1 × 12) / 4 = 12/4 = 3
Meaning the answer is.. 1/4 of 12 = 3
Hopefully this helps you!
Jar a contains the 8 letters in the word colorado. jar b contains the 11 letters in the word connecticut. what is the probability of randomly drawing an o from jar a, then an o from jar b?
Answer:
4/19
Step-by-step explanation:
Jar a: 3/8
Jar b: 1/11
8+11 = 19
3+1= 4
4/19
simplify PLEASE HELP ASAP
Answer:
[tex]0 < x < 6[/tex]
Step-by-step explanation:
This question asks to solve an inequality which can be written as:
[tex]\sqrt{x^2-6x+9} < 3[/tex]
Solve for x:
[tex]\sqrt{x^2-6x+9} < 3\\x^2-6x+9 < 9\\x^2-6x < 0\\x(x-6) < 0[/tex]
From here we can deduce that the inequality is [tex]0[/tex] when:
[tex]x = 0[/tex] or [tex]x = 6[/tex]
We can write the solution as:
[tex]0 < x < 6[/tex]
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's evaluate ~
[tex]\qquad \sf \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{ {x}^{2} - 3x - 3x+ 9 } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{ {x}^{}(x - 3) - 3(x - 3) } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{ (x - 3)(x - 3) } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{ (x - 3) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: { (x - 3) {}^{} } [/tex]
Now, we have been given that value of x :
[tex]\qquad \sf \dashrightarrow \:x < 3[/tex]
So, let's plug the value of x as 3 in the given expression ~
[tex]\qquad \sf \dashrightarrow \:3 - 3[/tex]
[tex]\qquad \sf \dashrightarrow \:0[/tex]
Therefore, we can conclude that :
[tex]\qquad \sf \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } < 0[/tex]
Value of the expression should be less than 0
NEED HELP IM NOT SURE ILL GIVE BRAINLY !!! PLEASE SOMEONE
divide 9 by 2, then subtract 4 from the result
Answer:
9 / 2 = 4.5
4.5 - 4 = 0.5
Simplify:
2r + 7 + 11r + 3
Answer:
13r+10
Step-by-step explanation:
1. Combine Like Terms
(2r+11r)+(7+3)
13r+10
Answer:
13r+10
Step-by-step explanation:
2r+7+11r+3
collect like terms
2r+11r+7+3
13r+10
The volume of a cone is 48π cm3. If this cone is placed inside of a cylinder with the exact same sized base and height, how much empty space is left in the cylinder?
Answer:
32π cm^3.
Step-by-step explanation:
The volume of a cone is 1/3 of the volume of a cylinder with the same base area and height.
So the empty space = 2/3 * 48π
= 32π cm^3.
Juanita has 2 rolls of film with 36 exposures and 3 rolls of film with 24 exposures. How many photos can she take with this film? She can take ____ pictures
Answer:
65 pictures because 24+36+3+2
Pls answer I’ll mark brainly
Answer:
52 miles
Step-by-step explanation:
since 1 unit is 26 miles and the distance from Daytona beach to Orlando on the map is 2 units just multiply 26 by 2 to get 52 miles
A D Show that 4h² - 4dh + x² = 0 T: Join OA, the radius of the centre and use the Pythagoras theorem. Express OA and OB in terms of d and/or h. B 11
See below for the proof of the equation 4h² - 4dh + x² = 0 using the Pythagoras theorem
How to prove the equation?The Pythagoras theorem states that:
Hypotenuse² = Opposite² + Adjacent²
The question is incomplete, as the figure is not given.
So, I will complete the proof using the following parameters:
Hypotenuse = 2√dhOpposite = xAdjacent = 2hSubstitute the above values in the following equation
Hypotenuse² = Opposite² + Adjacent²
So, we have:
(2√dh)² = x² + (2h)²
Evaluate the exponents
4dh = x² + 4h²
Subtract 4dh from both sides
0 = x² + 4h² - 4dh
Rewrite as:
4h² - 4dh + x² = 0
Hence, the equation has been proved
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Question 1 of 10
List all the factors of 34 from least to greatest. Enter your answer below,
using a comma to separate each factor.
Answer here
I
SUBMIT
Answer:
Hope the picture will help you.....................
find the volume of the compound shape.
[tex]v = \frac{4}{3} \pi {r}^{3} [/tex]
[tex]v = \frac{4}{3} \times \pi \times {2}^{3} [/tex]
[tex]v = 33.51 \: {m}^{3} [/tex]
Volume of the cylinder:[tex]v = \pi {r}^{2} h[/tex]
[tex]v = \pi \times {2}^{2} \times 6[/tex]
[tex]v = 75.40 \: {m}^{3} [/tex]
Total volume:[tex]v = 75.40 + 33.51[/tex]
[tex]v = 108.91 \: {m}^{3} [/tex]
Hence, the volume of the given compound shape is 108.91 cubic meters.
sphere:
= 33.51 m^3
cylinder:
= 75.40 m^3
all together:
= 108.91 m^3
Which of the following functions is represented in the graph shown?
f(x) = −2cos(2x) + 1
f(x) = −4cos(2x) − 1
f(x) = −2cos(x) − 1
f(x) = −4cos(x) + 1
Answer:
[tex]f(x)=-2\cos(2x)+1[/tex]
Step-by-step explanation:
Recall the general cosine equation
Function: [tex]f(x)=a\cos(bx+c)+d[/tex]Amplitude: [tex]|a|[/tex]Period: [tex]\frac{2\pi}{|b|}[/tex]Vertical Shift: [tex]-\frac{c}{b}[/tex]Midline: [tex]y=d[/tex]Identify amplitude
[tex]\text{Amplitude}=\frac{\text{Max-Min}}{2}=\frac{3-(-1)}{2}=\frac{4}{2}=2[/tex]
Identify period and solve for b
[tex]\frac{3\pi}{2}-\frac{\pi}{2}=\pi\\ \\\frac{2\pi}{|b|}=\pi\\ \\2\pi=b\pi\\\\2=b[/tex]
Identify midline
[tex]y=d=1[/tex]
Final Equation
[tex]f(x)=-2\cos(2x)+1[/tex]
Also, the reason why [tex]a=-2[/tex] is because a cosine function starts at its maximum, but since it starts at its minimum, the value of [tex]a[/tex] must be negative and causes the wave to flip about the midline.