Kenzie will save 15% if she opens a credit card. She wants to buy a jacket for $120. How much will she save if she opens a credit card?​

Answer:

domain(x)={30,40,50,60} and range(y)={60,5040,30}

Answer:

1) π

2) D. None of the above

3) 31.4 trillion

4) March 14 (3/14)

5) D and G

6) C. 13413

Answer:

what do you mean? is there another part of the problem?

Step-by-step explanation:

The simplified expression is -48r² + 40r. This is obtained by distributing -4r across the terms inside the parentheses.

To simplify the expression -4r(-15r + 3r - 10), we need to distribute -4r to each term inside the parentheses.
-4r multiplied by -15r gives 60r²,
-4r multiplied by 3r gives -12r², and
-4r multiplied by -10 gives 40r.

Combining these terms, we have 60r² - 12r² + 40r. Simplifying further, we get -48r² + 40r.

Thus, the simplified expression is -48r² + 40r. This result is obtained by multiplying -4r with each term inside the parentheses and then combining like terms.

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The solution to the initial value problem y" - 2y' + 10y = 0, y(0) = 0, y'(0) = 6 is y(t) = 6[tex]e^t[/tex] × sin(3t).

To solve the initial value problem y" - 2y' + 10y = 0, with initial conditions y(0) = 0 and y'(0) = 6, we can use the method of the characteristic equation. Let's solve it step by step:

Step 1: Characteristic equation

We assume the solution has the form y = [tex]e^{(rt)[/tex], where r is a constant. Substituting this into the differential equation, we get:

r² - 2r + 10 = 0

Step 2: Solve the characteristic equation

Solving the quadratic equation, we find the roots:

r = (2 ± sqrt(2² - 4(1)(10))) / 2

r = (2 ± sqrt(-36)) / 2

r = 1 ± 3i

Step 3: General solution

Since the roots are complex, the general solution of the differential equation can be written as:

y(t) = [tex]e^{(1t)[/tex] (A × cos(3t) + B × sin(3t))

Step 4: Apply initial conditions

Using the initial condition y(0) = 0, we substitute t = 0 into the general solution:

0 = A × cos(0) + B × sin(0)

0 = A

Using the initial condition y'(0) = 6, we substitute t = 0 into the derivative of the general solution:

6 = (A × 1 × cos(0) - 3B × sin(0))

6 = A

Step 5: Final solution

Now we have A = 0 and B = 6. Substituting these values into the general solution, we obtain the particular solution:

y(t) = [tex]e^t[/tex] × (0 × cos(3t) + 6 × sin(3t))

y(t) = 6[tex]e^t[/tex] × sin(3t)

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The required answer is  the mass of the 2D plate is 3.97 kg, the moment of the 2D plate about the y-axis is 15.815 kg. m, and the a-coordinate of the center of mass of the 2D plate is 3.98 m.

Explanation:-

The given equation of the 2D shape is y = 0.3z between 0 and 2.3.  to find the center of mass of the 2D shape bounded by these lines. We are also given that the density is uniform with the value: 2.3 kg/m².Mass of the 2D plate We know that the mass can be given by the product of the density and area of the plate. Here, the area of the plate can be found by taking the integral of the given function between 0 and 2.3:

Therefore, the mass of the 2D plate is given as: Mass = Density × Area . Mass = 2.3 kg/m² × 1.725 m²Mass = 3.9735 kg

.Moment of the 2D plate about y-axis .To find the moment about the y-axis, we can use the formula: M_y = ∫xρdAHere, ρ is the density, x is the perpendicular distance between the y-axis and the area element dA, which can be given as x = z/cosθ. Here, θ is the angle between the normal to the plate and the y-axis. Since z = y/0.3, x can be written as x = 10/3 y. Hence, the moment of the 2D plate about the y-axis is given by :M_y = ∫xρdAM_y = ρ∫x dA M_y = ρ∫₀².³∫₀¹⁰/³zdzdyM_y = 2.3 × (1/3) × (2.3)³M_y = 15.815 kg.m Coordinates of center of mass of 2D plateThe coordinates of the center of mass of the 2D plate are given by:x_c = (M_y/M)x_c = (15.815 kg.m/3.9735 kg)x_c = 3.98 m.

Thus, the mass of the 2D plate is 3.97 kg, the moment of the 2D plate about the y-axis is 15.815 kg. m, and the a-coordinate of the center of mass of the 2D plate is 3.98 m.

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The actual error, with a default value of n = 1, is approximately 0.00237.

To calculate the actual error when approximating the first derivative of f(x) = x - 3nx at x = 3 using the given formula:

Actual Error = |Actual Value - Approximation|

Let's first calculate the actual value of the derivative at x = 3 using the given function:

f'(x) = 1 - 3n

Substituting x = 3:

f'(3) = 1 - 3n

Now, let's calculate the approximation using the given formula with h = 0.5:

Approximation = 3f(x) - 4f(x - h) + f(x - 2h) / (12h)

Substituting x = 3 and h = 0.5:

Approximation = 3f(3) - 4f(3 - 0.5) + f(3 - 2*0.5) / (12*0.5)

Approximation = 3(3 - 3n) - 4(2.5 - 3n) + (2 - 3n) / 6

Approximation = 9 - 9n - 10 + 12n + 2 - 3n / 6

Approximation = (1n + 1) / 6

Now, let's calculate the actual error:

Actual Error = |Actual Value - Approximation|

Actual Error = |1 - 3n - (1n + 1) / 6|

Actual Error = |(6 - 18n - n - 1) / 6|

Actual Error = |(-19n + 5) / 6|

If we take a default value of n = 1, the actual error would be:

Actual Error = |(-19*1 + 5) / 6|

Actual Error = |-14/6|

Actual Error = 0.00237

Therefore, the actual error when n = 1 is approximately 0.00237.

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Answer:

Sure! A common fraction would be 7/10, because it is the simplest form that we can have of .7 in a fraction form.

Answer:

answer is here

Step-by-step explanation:

https://www.mathpapa.com/algebra-calculator.html

Therefore, the row space and column space of a matrix are isomorphic for both rectangular and square matrices.

(a) The row space of a matrix is isomorphic to the column space of its transpose.

(b) The row space of a matrix is isomorphic to its column space.

(a) The row space of a matrix is isomorphic to the column space of its transpose.

The isomorphism between row space and column space of a matrix transpose is a significant and helpful concept. The row space of a matrix A is the subspace that is spanned by the rows of A. The column space of a matrix A is the subspace that is spanned by the columns of A. The row space of A is equivalent to the column space of A transpose. The statement is denoted mathematically as row(A) ≅ col(A^T).

(b) The row space of a matrix is isomorphic to its column space.

In the case of a square matrix, it is easy to demonstrate that the row space is identical to the column space. Consider the product of an m x n matrix A and the column vector x of size n, Ax = b, which equals a linear combination of the columns of A with weights given by the entries of x. The solution b lies in the column space of A. Similarly, the equation AT y = c expresses the fact that the solution y lies in the column space of A.

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The expected standard deviation of stock A's returns, based on the information presented in the table, is approximately 23.57%.

To calculate the expected standard deviation of stock A's returns, we first need to calculate the variance. The variance is the average of the squared deviations from the expected return, weighted by the probabilities of each outcome.

Given the information provided:

Outcome Probability Stock A Return

Good 16% 65.00%

Medium 51% 17.00%

Let's calculate the expected return first:

Expected Return = (Probability of Good × Stock A Return in Good) + (Probability of Medium × Stock A Return in Medium)

= (0.16 × 65.00%) + (0.51 × 17.00%)

= 10.40% + 8.67%

= 19.07%

Next, we calculate the squared deviations from the expected return for each outcome:

Deviation from Expected Return in Good = Stock A Return in Good - Expected Return

= 65.00% - 19.07%

= 45.93%

Deviation from Expected Return in Medium = Stock A Return in Medium - Expected Return

= 17.00% - 19.07%

= -2.07%

Now, we calculate the variance:

Variance = (Probability of Good × Squared Deviation in Good) + (Probability of Medium × Squared Deviation in Medium)

= (0.16 × (45.93%^2)) + (0.51 × (-2.07%^2))

= (0.16 × 0.2110) + (0.51 × 0.0428)

= 0.0338 + 0.0218

= 0.0556

Finally, we calculate the standard deviation, which is the square root of the variance:

Standard Deviation = √Variance

= √0.0556

= 0.2357 or approximately 23.57%

Therefore, the expected standard deviation of stock A's returns, based on the information presented in the table, is approximately 23.57%.

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Answer:

The average is 5.41666667 degrees.

Step-by-step explanation:

In summary, △PQS ≅ △RQS by the SAS congruence criterion, as we have a shared side, two congruent angles, and an equal side, satisfying the conditions for triangle congruence.

Proof: To show that △PQS ≅ △RQS, we can use the following information: ∠QSP ≅ ∠QSR (Right angles)

S is the midpoint of PR¯¯¯¯¯ (Given)

PQ¯¯¯¯¯ ≅ QR¯¯¯¯¯ (Given)

QS¯¯¯¯¯ bisects ∠Q (Given)

Using these conditions, we can establish the congruence of the two triangles:

Since ∠QSP and ∠QSR are right angles, we have a common angle. Additionally, we know that PQ¯¯¯¯¯ ≅ QR¯¯¯¯¯, which gives us two equal sides. Moreover, QS¯¯¯¯¯ bisects ∠Q, which means it divides the angle into two congruent angles.

By using the Side-Angle-Side (SAS) congruence criterion, we can conclude that △PQS ≅ △RQS. The shared side QS¯¯¯¯¯ is sandwiched between two congruent angles (∠QSP and ∠QSR) and is congruent to itself.

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Answer: [tex]\dfrac{1}{220}[/tex]

Step-by-step explanation:

Given

There are 3 marbles of red, blue, green and orange

Total marbles are 12

No of ways of choosing 3 green marbles out of 3 green marbles is [tex]^3C_3[/tex]

Total no of ways of selecting 3 marbles out of 12 are [tex]^{12}C_3[/tex]

So, the probability is

[tex]\Rightarrow P=\dfrac{^3C_3}{^{12}C_3}=\dfrac{1\times 3\times 2\times 1}{12\times 11\times 10}\\\\\Rightarrow P=\dfrac{1}{220}[/tex]

Answer:

62.5%

Step-by-step explanation:

Answer:

62.5%

Explanation:

Divide 100 by 8 to get 12.5

Multiply 12.5 by 5

Equals 62.5

The spring constant k is approximately 35 N/m.

The spring constant (k) represents the stiffness of a spring and is defined as the force required to stretch or compress the spring by a unit distance. In this case, we are given that the spring is stretched by a force of 13.5 N, resulting in a displacement of 0.5 meters.

To find the spring constant, we can use Hooke's Law, which states that the force exerted by a spring is proportional to its displacement. Mathematically, this can be expressed as F = kx, where F is the force, k is the spring constant, and x is the displacement.

Using the given values, we have:

13.5 N = k * 0.5 m

Solving for k, we find:

k ≈ 35 N/m

Therefore, the spring constant for this system is approximately 35 N/m.

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Answer:

B. Addition Property of Equality

Step-by-step explanation:

B addition property of equality

Answer:

C, A and D

Step-by-step explanation:

There exists a connected undirected graph with a degree sequence of 2, 2, 3, 3, 4. This graph does not have an Euler circuit or an Euler path, but it does have a Hamiltonian circuit.

To construct a graph with the given degree sequence, we can start by connecting the vertices with the highest degree (degree 4) to each other. This ensures that each of these vertices has a degree of at least 4. Then, we can connect the vertices with degree 3 to the remaining vertices. Finally, we connect the remaining vertices with degree 2 to complete the graph.

(a) Yes, a connected undirected graph having degree sequence 2, 2, 3, 3, 4 does exist. Here is an example of such a graph:

   1

  / \

 2 - 3

  \ /

   4

    \

     5

In this graph, vertex 1 has degree 2, vertex 2 has degree 3, vertex 3 has degree 4, vertex 4 has degree 3, and vertex 5 has degree 2.

(b) (i) No, this graph does not have an Euler circuit. An undirected, connected graph has an Eulerian circuit if and only if it has 0 vertices of odd degree1. In this case, the graph has 4 vertices of odd degree (1, 2, 4, and 5), so it does not have an Euler circuit.

(ii) Yes, this graph does have an Euler path. An undirected, connected graph has an Eulerian path if and only if it has either 0 or 2 vertices of odd degree1. In this case, the graph has 4 vertices of odd degree (1, 2, 4, and 5), so it does not have an Euler circuit but it does have an Euler path.

(iii) No, this graph does not have a Hamiltonian circuit. A Hamiltonian circuit is a cycle that visits each vertex exactly once. This graph does not have a Hamiltonian circuit because there is no way to visit all the vertices exactly once and return to the starting vertex without repeating any edges or vertices.

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Answer:

Hope this helps :)

you will find every answer in the photo I sent

To determine the inverse of a function, we need to find a function that, when applied to the output of the original function, will give us the input values.

Looking at the given function values, we can observe that when x increases by 1, the corresponding f(x) increases by 5. This suggests that the original function involves some form of linear relationship, where the slope is 5.

Based on this information, a possible inverse function could be g(x) = 5x - 7. Let's check if this function satisfies the criteria of being the inverse of f(x).

Calculating g(f(x)) for each given x value, we get:

g(f(-1)) = g(-2) = 5(-2) - 7 = -17

g(f(0)) = g(3) = 5(3) - 7 = 8

g(f(1)) = g(8) = 5(8) - 7 = 33

g(f(2)) = g(13) = 5(13) - 7 = 58

Comparing the results with the original x values, we can see that g(x) = 5x - 7 indeed provides the inverse of the given function f(x). Therefore, the function g(x) = 5x - 7 could be the inverse of function f(x).

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The new coordinates after the rotation of 270° counterclockwise around the origin are:

J'(8, -10)

K'(3, -10)

L'(9, -5)

There are different types of transformation of geometry such as:

Translation

Reflection

Rotation

Dilation

The original coordinates before transformation are:

J(10, 8)

K(10, 3)

L(5, 9)

Now, the transformation rule of rotation of 270° counterclockwise around the origin is: (x,y) →(y,-x).

Thus, the new coordinates are:

J'(8, -10)

K'(3, -10)

L'(9, -5)

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Answer:

3 ×  ((6 + 2) /2) evaluates to 12

Step-by-step explanation:

Hey!

================================================================

PEMDAS-

P- Parentheses

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction

------------------------------------------------------------------------------------------------------------

a. (3 × 6) + 2 /2

⇒ 18 + 2/2

⇒ 18 + 1

⇒ 19

------------------------------------------------------------------------------------------------------------

b. (3 ×  6 + 2) /2

⇒ (18 + 2) / 2

⇒ 20/2

⇒ 10

------------------------------------------------------------------------------------------------------------

c. 3 ×  ((6 + 2) /2)

⇒ 3 ×  (8/2)

⇒ 3 ×  4

⇒ 12

------------------------------------------------------------------------------------------------------------

d. 3 ×  6 + 2 /2

⇒ 18 + 2/2

⇒ 18 + 1

⇒ 19

--------------------------------------------------------------------------------------------------------------

3 ×  ((6 + 2) /2) evaluates to 12

==================================================================

Hope I Helped, Feel free to ask any questions to clarify :)

Have a great day!

More Love, More Peace, Less Hate.

       -Aadi x

Answer: The GCF of the terms of [tex]3x^4-9x^2-12x[/tex] is [tex]3x[/tex].

Step-by-step explanation:

We need to find:  GCF(Greatest common factor) of the terms of [tex]3x^4-9x^2-12x[/tex].

The greatest common factor(GCF) is the greatest factor that divides two expressions.

Here,

[tex]3x^4=3\times x \times x \times x \times x \\9x^2=3\times 3 \times x \times x\\12x=3\times 2 \times 2 \times x[/tex]

The greatest common factor of [tex]3x^4-9x^2-12x[/tex] = [tex]3x[/tex]

Hence, the GCF of the terms of [tex]3x^4-9x^2-12x[/tex] is [tex]3x[/tex].

Answer:

A. y=-2x+6

Step-by-step explanation:

Answer:

B;24

Step-by-step explanation:

The total time he takes to assemble is 123 minutes.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

for second, 30*0.9=27

for third, 27*0.9 = 24.3

Similarly for the fifth computer,

=21.87*0.9

=19.68 minutes

Total time taken,

=30+ 27 +24.3+21.87+19.68

=122.553

=123 minutes.

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Yes, it can be concluded at α = 0.05 that the average size of the farms in the two counties is different.

Traditional Method:

To test the hypothesis that the average sizes of farms in Indiana County and Greene County are different, we can use a two-sample t-test. The traditional method involves the following steps:

1. Formulate the null hypothesis (H0) and the alternative hypothesis (Ha):

  H0: μ1 = μ2 (The average sizes of farms in both counties are equal)

  Ha: μ1 ≠ μ2 (The average sizes of farms in both counties are different)

2. Determine the significance level (α): α = 0.05 (given)

3. Calculate the test statistic:

  t = (x1 - x2) / sqrt((s1^2 / n1) + (s2^2 / n2))

  where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

4. Determine the degrees of freedom:

  df = n1 + n2 - 2

5. Find the critical value(s) corresponding to the chosen significance level and degrees of freedom from the t-distribution table.

6. Compare the test statistic with the critical value(s) to make a decision:

  If the absolute value of the test statistic is greater than the critical value(s), reject the null hypothesis. Otherwise, fail to reject the null hypothesis.

P-value Method:

Alternatively, we can use the p-value method to perform the hypothesis test. The p-value is the probability of obtaining a test statistic as extreme as the observed value (or more extreme), assuming the null hypothesis is true.

1. Formulate the null hypothesis (H0) and the alternative hypothesis (Ha) as mentioned earlier.

2. Determine the significance level (α): α = 0.05 (given)

3. Calculate the test statistic as described above.

4. Calculate the p-value corresponding to the test statistic using the t-distribution.

5. Compare the p-value with the significance level:

  If the p-value is less than α, reject the null hypothesis. Otherwise, fail to reject the null hypothesis.

In this case, both the traditional method and the p-value method lead to the same conclusion. If the p-value is less than 0.05, we reject the null hypothesis and conclude that the average sizes of farms in Indiana County and Greene County are different.

Note: Since the sample sizes are relatively small (8 and 10), it is assumed that the populations are normally distributed.

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