The initial velocity of Julia's jump in the vertical direction is 8 m/s.
What was the initial vertical velocity of Julia's jump?The initial vertical velocity of Julia's jump is determined using the given parameters and the relevant equation of motion.
The given parameters in Julia's jump are as follows:
Taken upward direction as positive;
Acceleration due to gravity (upward direction against gravity) = -3.7 m/s²
Time, t = 3 s
Final velocity, v (downward direction) = -3.1 m/s
Initial velocity, u = ?
Using the equation: v = u + at
u = v - at
u = -3.1 - (-3.7 * 3)
u = 8 m/s
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If the acceleration of a school bus over a given time interval is zero, how does the instantaneous velocity of that school bus at any instant during that interval compare to its average velocity over the interval?.
Both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.
What is instantaneous velocity?Instantaneous velocity is the rate of differential change of displacement with respect differential change in time. Mathematically -
v = dx/dt
Given is the acceleration of a school bus over a given time interval as zero.
For acceleration over a given time interval to be zero, it must be ensured that the the velocity of the object should remain constant. Mathematically-
a = (v - u)/(t₂ - t₁)
For acceleration [a] = 0, v = u. Therefore -
a = 0
The instantaneous velocity for zero acceleration between the time interval t₁ to t₂ will be equal to initial velocity only -
dx/dt = u
This will be the instantaneous velocity and is equal to (u) at any instant.
Now -
dx = u dt
Integrating both sides, we get -
∫dx = ∫u dt
x = ut
Therefore, the average velocity will be =
v(avg) = x/Δt = ut/Δt
Now -
t = Δt for any specific time interval. Therefore -
v(avg) = ut/t = u
This is the average velocity and it is equal to (u).
Therefore, both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.
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Alex brings a bag of trail mix to school. He empties the bag and measures the total mass of the trail Then he separates the nuts, chocolate, and raisins into individual piles. He eats the chocolate and then measures the mass of the remaining two piles. He records his data in the table
What was the mass of the chocolate that Alex ate?
The mass of the chocolate from the table that we can find in the question is 11 grams.
What was the mass of the chocolate that Alex ate?
We can see that the table as it have been shown gives us both the total number of the trail mix that Alex has brought to the school as well as the various individual components of the trail mix that he has. Looking at this over view would be of a lot of help as we are trying to find out now the number of the mass of the chocolate that Alex ate.
We have the following information;
Mass of nuts = 24 grams
Mass of raisins = 10 grams
Mass of chocolate = unknown grams
We can now have;
Total mass = Mass of nuts + Mass of raisins + Mass of chocolate
Mass of chocolate = Total mass - (Mass of nuts + Mass of raisins)
Mass of chocolate = 45 - (10 + 24)
Mass of chocolate = 11 grams
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Max is golfing and he hits a ball 235 meters 15.9° west of north. From that location he hits the ball 29.5 meters 41.1° east of north. What is the final displacement vector for Max's golf ball?
The final displacement vector for Max's golf ball is d. 246 m, 29.1 degrees north of east.
displacement 1 = 235 m 15.9° west of north.
displacement2 = 29.5 meters 41.1° east of north.
resultant vector = [tex]\sqrt{235{^{2} + 29.5^{2} }[/tex]
= 246.84 m, 29.1 degrees north of east
A vector is an object that has both importance and direction. Geometrically, we are able to image a vector as a directed line section, whose duration is the importance of the vector, and with an arrow indicating the direction. The direction of the displacement vector is from its tail to its head.
Vector is a term that refers colloquially to a few quantities that can not be expressed via an unmarried variety, or to elements of a few vector spaces. Vectors are geometrical or physical portions that own both value and direction wherein the item is moving. The importance of a vector shows the length of the vector. it's far normally represented by means of an arrow pointing within the course of the vector.
Disclaimer:- your question is incomplete, please see below for the complete question.
Max is golfing and he hits a ball 235 meters 15.9° west of north. From that location, he hits the ball 29.5 meters 41.1° east of north. What is the final displacement vector for Max's golf ball?
a. 246 m, 29.1 degrees east of north
b. 252 m, 10.3 degrees west of north
c. 252 m, 10.3 degrees north of west
d. 246 m, 29.1 degrees north of east
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This question is kinda tricky
The speed of the ball is "50.4 m/s"
The structure is 130 meters high.
64 meters across the horizontal
Gravity causes an acceleration of 9.8 m/s.
Using the equation of motion s = ut + (0.5at2) and presuming that air resistance is not taken into account, we first calculate how long it takes for the object to strike the ground.
where s = distance (height of the building)
initial speed is u. (which is 0 in this case )
Time t equals (130/4.9) where an is the gravitational acceleration (0 x t) + (0.5 x 9.8 x t2) = 130 4.9 x t2.
5.15 seconds = t
We now apply the equation Vy = Uy + at to get the speed before it touches the ground (0 in this case)
Vy = 0 + (9.8 x 5.15) (9.8 x 5.15) (9.8 x 5.15)
Vy = 50.4 m/s
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the density of mercury is 13.6g cm‐³. What do you understand by this statement?
Answer:
The relative density of mercury is 13.6, this means that mercury is 13.6 times as heavy as an equal volume of water.
The table shows the mass and net force of two cars
moving down the same road. Without performing any calculations, which car will
experience a greater acceleration? Explain your answer using Newton’s laws.
Car Mass (kg) Net Force (N)
A 800 kg 400 N
B 300 kg 300 N
The car B will experience greater acceleration than car A.
According to the Newton's second law, the acceleration of an object is depends on the net force acting upon the object and the mass of the object. The mathematical form of the law is given below.
F = m*a
Where F = force, m = mass and a = acceleration.
The equation in terms of acceleration is,
a = F/m
From the formula, we can see that the acceleration is directly proportional to force and indirectly proportional to mass. The net force on the car A is greater than car B. But the mass of the car A is larger than almost three times of the mass of car B. Hence the car A will have lower acceleration compared to car B. The larger net force will not increase the acceleration very much. So, the car B will experience greater acceleration than car A.
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If a 0.5 kg pair of shoes weighs 0.3 N on Pluto, what is the strength of gravity on Pluto?
Answer:
0.2
Explanation:
0.5 - 0.3 = 0.2
2. A car initially traveling at a speed of 16 meters per second accelerates uniformly
by 0.22 meters per second squared for 12 seconds. What is the final velocity of
the car?
Answer: Final velocity of car is 18.64 m/s
Explanation:
According to equation of motion,
V=U + at
where,
V is final velocity
U is initial velocity
a is acceleration
T is time
in the question,
U=16 m/s
a=0.22 m/s*s
t=12 seconds
on substituting values,
V = 16+(12*(0.22))
V=18.64
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How do particles of a gas differ from particles of a liquid when in the same container?
A. Gas particles are more spread out
B. Gas particles are closer together
C. Gas particles are smaller
D. Gas particles are larger
Answer:
I believe that it is A) they're more spread out
a line 3km north and 5km east what is the resultant??
Answer:
See below
Explanation:
Use pythag theorem
r^2 = 3^2 + 5^2
r = sqrt (34) = 5.83
angle = arctan (3/5) = 31 degrees north of east
Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
The center of mass of the three mass system is at 83cm
Center of mass definition:A position relative to an object or set of objects is known as the center of mass. It is the system's average location, weighted by the mass of each component.
Given the mass of the meter stick is:
M = 0.5kg.
Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.
Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.
Now a mass m2 = 1kg is attached at 50cm mark.
So the distance of m2 from 0cm is x2 = 50cm = 0.5m.
Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.
Now the position of the three mass system from 0cm is given by,
[tex]X_{CM}=\frac{Mx_{1}+m_{2}x_{2}+m_{3}x_{3}}{M+m_{2}+m_{3}}X_{CM}=\frac{0.5\times 0.5+1\times 0.5+3\times 1}{0.5+1+3}=\frac{3.75}{4.5}=0.83m = 83cm[/tex]
So the center of mass of the three mass system is at 83cm.
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As she starts to move upward, the student pushes down on the surface with a force that is greater than her weight. What can you say about the net force on her?.
As she starts to move upward, the student pushes down on the surface with a force that is greater than her weight. This will cause her net force to be directed upwards, thus, alternative B.
What is net force?Net force is the vectoral sum or the resolution of all the forces acting on a body. Although, more than one force may be acting on a body at the same time, only the resultant force or the net force will have a significant effect on the body. If the net force is equal to zero, the body is said to be in a state of equilibrium, and according to Newton's first law of motion, the body will remain in its state of rest or will continue to move in uniform speed.
As for the student in the question, her net force isn't equal to zero, so she will move in the direction of her net force, which is upwards. Newton's third law of motion states that "to every action, there is an equal but opposite reaction".
When she pushed downwards on the surface of the ground with a force greater than her weight, the ground surface will also produce a force in opposite direction to and equal to the force she used on the ground called a normal force, according to Newton's third law of motion. The normal force is also greater than the weight of the girl, hence, her net force will not be zero, and it will move in an upward direction, causing her to jump off the ground.
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Complete question:
As she starts to move upward, the student pushes down on the surface with a force that is greater than her weight. What can you say about the net force on her?
A. The net force is zero.
B. The net force is directed upward.
C. The net force is directed downward
Please Help!
Will mark as brainliest
a)
i) the lorry's speed is rising and then stays at a constant speed
ii) it is accelerating but after 40 seconds, it stays at a constant speed
b)
speed= 25m/s
speed= 90km's
Answer:
See below
Explanation:
Lorry starts from rest , then accelerates to reach a constant velocity of 25 m/s
Initial Acceleration = 10 m/s / 20 s = 1/2 m /s^2
Maximum speed is 25 m/s= 25 m/s * 1 km / 1000 m * 3600 s /hr = 90 km/hr
A ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest. What expression shows the change in momentum as observed by the ground observer?.
The change in momentum of the ball travelling along a straight path, perpendicular to a wall, after bouncing off the wall as observed by the ground observer is 0
Δp = [tex]p_{f}[/tex] - [tex]p_{i}[/tex]
Δp = Change in momentum
[tex]p_{f}[/tex] = Final momentum
[tex]p_{i}[/tex] = Initial momentum
p = m v
m = Mass
v = Velocity
Since, [tex]p_{f}[/tex] = [tex]p_{i}[/tex]
Δp = 0
Momentum can be simply defined as a mass in motion. So if an object with mass moves, it will have momentum. It is a vector quantity.
Therefore, the change in momentum as observed by the ground observer is 0
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ASAP what is the unit we use to measure mass
Answer:
mass is measured in kilograms
Two charged objects repel each other with a force of 0.900 N. The charge on one is then tripled and the charge on the other is increased by a factor of 5/3. If the distance between them is then double, determine the magnitude of the resulting force.
The magnitude of the Resulting force calculated is 1.125 N.
The force of repulsion between two objects is calculated by Coulomb's Law which is a quantitative statement between 2-point charges. The equation of Coulomb's Law is,
F = [tex]\frac{ K q^{2} }{r^{2} }[/tex]
where k = Dielectric constant of the medium also called Relative permittivity of medium and is dimensionless.
In the first case, Force is F = 0.900 N
In the second case, given, one q is tripled and the other is increased by a factor of 5/3. Distance between is doubled, Let the final force be F'
[tex]F' = \frac{kq^{2} *5}{r^{2} *4}[/tex]
F' = (0.009 × 5)/4
F' = 1.125
Hence, the Final force is 1.125 N
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What powers a roller coaster after its initial boost
If an astronaut weighs 981 N on Earth and only 160 N on the
Moon, then what is his mass on Earth?
the mass on Moon will be 98.1 kg.
Given - Weight on Earth and moon
Find - Mass on Moon
First, determine the mass of the Earth using its gravitational acceleration.
Taking acceleration due to gravity as 10 m/s².
Mass = weight/acceleration due to gravity
Mass = 981/10
Performing division
Mass = 98.1 kg
As is already common knowledge, the mass is independent of the acceleration caused by the planet's gravity. The mass of the moon will therefore be 98.1 kg.
What is the Earth's mass?The earth weighs 6. 1024 kilograms, while the moon weighs 7.4 1022 kilograms. Calculate the force that the earth would apply on the moon if their distance were 3.84 x 105 miles.
The Moon's mass is not included in the Earth's mass. The Earth+Moon system has a mass of about 6.04561024 kg since the Moon's mass is roughly 1.2% that of the Earth.
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.
What is the radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s2 ?
The radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s² is 9 M m
g = G M / R²
g = Acceleration due to gravity
G = Gravitational constant
M = Mass
R = Radius
g = 4.9 m / s²
G = 6.67 * [tex]10^{-11}[/tex] m³ / kg s²
M = 5.97 * [tex]10^{24}[/tex] kg
R² = ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] ) / 4.9
R² = 81.3 * [tex]10^{12}[/tex].
R = 9 * [tex]10^{6}[/tex] m
R = 9 M m
Acceleration due to gravity is the acceleration produced by a planet. If an object is falling, it will gain some acceleration due to gravitational force.
Therefore, the radius of a planet is 9 M m
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Considering what you have learned in this lab and in class, write a hypothesis to explain why we observe a higher fraction of elliptical galaxies within a cluster and a higher fraction of spiral galaxies in the field. Think about how being in a crowded cluster versus alone might affect the morphology or appearance of a particular galaxy.
We observe a higher fraction of elliptical galaxies within a cluster because they are dim and consist of older stars. So, such type of galaxies affects the closer galaxies, which makes it to be in clusters making the closer galaxies similar.
Consequently, we also observe a higher fraction of spiral galaxies in the field because spiral galaxies consist of big arms with most of the young stars. These are less in the universe as per our observation. So, such type of galaxies appears in a field because of their high brightness and structure.
According to the observations, elliptical galaxies are more in comparison to the spiral galaxies.
These elliptical galaxies are dim and consist of older stars. So, such type of galaxies affects the closer galaxies, which makes it to be in clusters. It makes the closer galaxies similar.
Spiral galaxies consist of big arms with most of the young stars. These are less in the universe as per our observation. So, such type of galaxies appears in a field because of their high brightness and structure.
If the cluster is crowded, there would be more elliptical galaxies as the collision of spiral galaxies forms elliptical galaxies. The spiral arms of the spiral galaxies are most affected by the collision and the morphology of the galaxy changes. It goes from spiral to elliptical. Probability of such collisions is more in crowded clusters in comparison to alone galaxies.
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99. An airplane with an airspeed of 120 km/h encounters a
90-km/h crosswind. Convince your classmates that the
plane's groundspeed is 150 km/h.
The resultant speed of the airplane is 150 km/h, and this is the speed relative to the ground.
What is the resultant speed of the airplane?
The resultant speed of the airplane is the single speed of the airplane that will produce same effect as the two speeds acting together.
To convince your classmate about the ground speed of the airplane we need to calculate the resultant speed of the airplane.
R² = Vp² + Vw²
where;
R is the resultant speed of the airplaneVp is the speed of the airplaneVw is the speed of the windR² = Vp² + Vw²
R = √[Vp² + Vw²]
R = √[120² + 90²]
R = 150 km/h
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a certain superconducting magnet in the form of a solenoid of length 0.50 m can generate a magnetic field of 9.0 t in its core when its coils carry a current of 75 a. the windings, made of a niobium-titanium alloy, must be cooled to 4.2 k. find the number of turns in the solenoid.
The solenoid is the component that converts electrical energy into magnetic energy. It is created with the aid of a wire coil.
This gadget generates a magnetic field, which is then put to use in a variety of ways. Inside the solenoid, the magnetic field's direction remains constant. The device that transforms electrical energy into magnetic energy is a solenoid. It is made possible by a wire coil. This device creates a magnetic field that is subsequently used in a number of different ways. The magnetic field has a consistent direction inside the solenoid.
To calculate how many turns into gloomy oid there are. The magnetic field equation for the solenoid is the simplest method to remember how to achieve that. Mu not N times I times L, where mu naught is the constant N, gives us B.
I have taken how many turns. is the solenoid's length, and is the current. Our Bs nine Tesla RL is 90.50 m mu not four pi times 10 to the negative seven and I 75 amps, so we may rearrange this so that the end will be equal to B times L divided by mu naught times I.
We'll therefore obtain 4.5 divided by 9.42 multiplied by 10 to the negative 5.
And we will receive several phrases of 47746. hence, um,.4. We will thus have this many turns to bother this cell.
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Luka Modric kicks the ball with a velocity of 367km/h at an angle of 45 degrees above the horizontal.
a) how long will the ball be in the air?
b) how far downfield will it land as it hits the back of the net?
c) how high did the ball go at its highest point over the Italian defense?
A. The time spent by the ball in the air is 14.7 s
B. The ball will land at 1060.47 m as it hits the net.
C. The maximum height reached by the ball is 265.12 m
A. How to determine the time
The time spent by the ball in the air can be obtained as follow:
Initial velocity (u) = 367 Km/h = 367 / 3.6 = 101.944 m/sAngle of projection (θ) = 45 °Acceleration due to gravity (g) = 9.8 m/s²Time (T) = ?T = 2uSineθ / g
T = [2 × 101.944 × Sine 45] / 9.8
T = 14.7 s
B. How to determin the distance
Initial velocity (u) = 367 Km/h = 367 / 3.6 = 101.944 m/sAngle of projection (θ) = 45 °Acceleration due to gravity (g) = 9.8 m/s²Range (R) =?R = u²Sine(2θ) / g
R = (101.944)² × Sine (2×45) / 9.8
R = 1060.47 m
C. How to determine the maximum height
The maximum height reached by the ball can be obtained as follow:
Initial velocity (u) = 367 Km/h = 367 / 3.6 = 101.944 m/sAngle of projection (θ) = 45 °Acceleration due to gravity (g) = 9.8 m/s²Maximum height (H) =?H = u²Sine²θ / 2g
H = [(101.944)² × (Sine 45)²] / (2 × 9.8)
H = 265.12 m
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how do you apply newtons laws to solve problems?
Answer:
✨Hello mark as branlist Identify the physical principles involved by listing the givens and the quantities to be calculated
Explanation:
A bubble of gas is released from the mud at the bottom of the pond. It’s initial volume is 0.5cm^3. Ignoring any temperature differences in the water calculate the volume of the bubble as it reaches the surface
The volume of the bubble of gas when it reaches the surface is 1 cm³.
What is Boyle's law?
Boyle's law states that the pressure of a given mass of a gas is inversely proportional to its volume provided that the temperature of the gas is constant.
Mathematically, Boyle's law is given as;
P₁V₁ = P₂V₂
where;
P₁ is the initial pressure of the gasP₂ is the final pressure of the gasV₁ is the initial volume of the gasV₂ is the final volume of the gasWhen the pressure at the bottom is double the pressure at the surface, then the pressure at the surface is half the pressure at the bottom.
V₂ = P₁V₁/P₂
Let the pressure at the surface = P
V₂ = (2PV₁)/P
V₂ = 2V₁
V₂ = 2(0.5 cm³)
V₂ = 1 cm³
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The complete question is below:
A bubble of gas is released from the mud at the bottom of the pond. It’s initial volume is 0.5cm^3. Ignoring any temperature differences in the water calculate the volume of the bubble as it reaches the surface if the pressure at the bottom is twice the pressure at the surface.
In a feedback loop, the Creates an That impacts the original event
In a feedback loop, the stimulus Creates an set point that impacts the original event.
What is feedback loop?A system component known as a feedback loop is one in which all or a portion of the output is used as input for subsequent operations. A minimum of four stages comprise each feedback loop.
Input is produced in the initial phase. Input is recorded and stored in the subsequent stage. Input is examined in the third stage, and during the fourth, decisions are made using the knowledge from the examination.
Both negative and positive feedback loops are possible. Insofar as they stay within predetermined bounds, negative feedback loops are self-regulating and helpful for maintaining an ideal state. One of the most well-known examples of a self-regulating negative feedback loop is an old-fashioned home thermostat that turns on or off a furnace using bang-bang control.
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Is the change created by melting a physical change or chemical change? Explain.
The change created by melting is known to be called a physical change.
Is melting a physical change or chemical change?A physical change happens when a given substance's physical characteristics alters without undergoing a kind of chemical composition.
Note that Melting, changes in size, as well as in volume, color, also density, and crystal shape are said to be an examples of common physical changes.
Physical changes, like melting or the act of boiling, are usually simple to undo even though the final result might not always look exactly the same as the original. Aside from gaining or losing energy, particles do not change during physical changes and no new materials are created.
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You place a box weighing 355.9 N on an inclined plane that makes a 36◦ angle with the horizontal. Compute the component of the gravitational force acting down the inclined plane. Answer in units of N.
The component of the gravitational force acting down the inclined plane has a magnitude of 209.98 N
Eventhough the box is at an inclined plane which makes 36° with the horizontal, the gravitational force will still act straight down perpendicular to the horizontal. Resolving the force due to gravity into its horizontal and vertical components. The vertical component makes 36° with the gravitational force and is at right angles with the horizontal component.
The component of the gravitational force acting down the inclined plane is the horizontal component.
W = 355.9 N
In a right angled triangle,
sin θ = Opposite side / Hypotenuse
sin 36° = [tex]W_{x}[/tex] / W
[tex]W_{x}[/tex] = 355.9 * 0.59
[tex]W_{x}[/tex] = 209.98 N
Therefore, the component of the gravitational force acting down the inclined plane is the horizontal component with a magnitude of 209.98 N
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A rocket travels 220 meters directly upward with an average acceleration of 14.7 meters per second squared.
How has the velocity of the rocket changed after 220 meters?
The change in the velocity of the rocket after 220 meters is 80.42 m/s.
What is the velocity of the rocket?
The change in the velocity of the rocket at the given time of motion is calculated as follows;
Apply the following kinematic equation to determine the velocity of the rocket.
v² = u² + 2as
where;
v is the final velocity of the rocketu is the initial velocity of the rocket = 0a is the acceleration of the rockets is the distance travelled by the rocketv² = 2as
v = √2as
v = √(2 x 14.7 x 220)
v = 80.42 m/s
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A bird is flying with a speed of 13.8 m/s over water when it accidentally drops a 1.60 kg fish. The acceleration of gravity is 9.81 m/s 2 . If the altitude of the bird is 7.80 m and air resistance is disregarded, what is the speed of the fish when it hits the water? Answer in units of m/s.
Answer: 69
Explanation: 160 divided by 2 is 69