Based on the amounts Julia paid and the percentage rates, the missing amounts are:
$124 for social security. $29 for Medicare. 13% for federal income tax. 6% for state income tax. How much tax did Julia pay?Julia's social security taxes were:
= 6.2% x 2,000
= $124.
Medicare amount:
= 1.45% x 2,000
= $29
Federal income tax:
= 260 / 2,000 x 100%
= 13%
State income tax:
= 120 / 2,000 x 100%
= 6%
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Please Help! Give full description on how you did both pls. Giving brainleist.
Answer:
7. m^21n^27
8. a^21b^28
Step-by-step explanation:
7. since m^7 raised to the 3rd power = m^( 7 * 3 ) = m^21
then n^9 raised to the 3rd power = n^( 9 * 3 ) = n^27
your answer is m^21n^27
8. a^3 raised to the 7th power = a( 3 * 7 ) = a^21
b^4 raised to the 7th power = b( 4 * 7 ) = b^28
your answer is a^21b^28
hope this helps:)
3. A is a set of points that extends infinitely in both directions.
ray
point
plane
line
Answer:
line
Step-by-step explanation:
quizlet
cliffnotes
Pamela and her friend went to the taco place with $15.00. they bought 2 burritos for $2.95 each, an order of nachos to share for $2.25, and 2 sodas for $1.75 each. how much money will they have left?
The following data sets can be modeled linearly.
Answer:
last and third
Step-by-step explanation:
Two classes of students took an exam.
Here is a list of the scores in Class A:
65, 70, 70, 80, 80, 85, 85, 85, 90, 90, 100
Here is a box plot that shows the scores in Class B:
Box plot from 55 to 100 by 5’s. Whisker from 60 to 70. Box from 70 to 80 with vertical line at 75. Whisker from 80 to 90.
1. Which class had better overall results on the exam?
2. Which class had greater variability in the results?
The class that had better overall results on the exam is class A.
The class with greater variablity in results is class B.
Which class performed better?The statistics of students in class A:
Maximum score = 100
Minimum score = 65
Median = 85
First quartile = 1/4(n + 1) = 1/4 x 12 = 3rd term = 70
Third quartile = 3/4 x (n + 1) = 3/4 x 12 = 9th term = 90
The statistics of students in class B:
Maximum score = 100
Minimum score = 55
Median = 75
First quartile = 70
Third quartile = 80
Which class had greater variability in the results?The range would be used to determine which class has greater variability.
Range = highest score - lowest score
Class a = 100 - 65 = 35
Class B = 100 - 55 = 45
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THE IMAGE OF TRIANGLE ABC AFTER A 180 DEGREE ROTATION THE ORIGIN IS
The image of triangle ABC is a A'B'C' after rotating about the origin with an angle of 180 degree.
What is geometric transformation?It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.
If we rotate the triangle ABC with the origin (0, 0) about 180 degree it will form an image of the triangle ABC which is A'B'C'
Here the coordinates for ABC are not given so we are assuming the triangle ABC has a image which is A'B'C' (refer attached picture)
Thus, the image of triangle ABC is a A'B'C' after rotating about the origin with an angle of 180 degree.
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The Stock Market Nadia is a stockbroker. She earns 14% commission each week. Last week, she sold $6,800 worth of stocks. How much did she make last week in commission? If she averages that same amount each week, how much did she make in commission in 2011?
Answer:
she earns $1008 in commissions , hope this helps i did it
It’s mathematical and musical at the same time
Answer:
I dont think I can type the answer on keyboard
3
What is the quotient of and 3?
-
O -1/1/2
-100
110
118
The simplified quotient of 300 and 3 is 100
How to determine the quotient?The complete statement is given as:
What is the quotient of 300 and 3?
This is represented as:
Quotient = 300/3
Divide 300 by 3
Quotient = 100
Hence, the quotient of 300 and 3 is 100
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Joaquin is constructing the perpendicular bisector of ab. What should be his first step?
(100 points cuz why not)
Answer:
D. Open the compass so that the distance from the two points of the compass is wider than half the length of [tex]\over{AB}[/tex].
Step-by-step explanation:
To construct a perpendicular for [tex]\over{AB}[/tex], we must first take a compass & take the distance of its arms wider than half the length of [tex]\over{AB}[/tex].
This is done in order to get two intersecting arcs in the top & bottom of [tex]\over{AB}[/tex] so that a perpendicular bisector can be drawn through it.
After two intersecting lines are drawn below & above [tex]\over{AB}[/tex], draw a line joining these 2 points through their points of intersection. The point where it intersects [tex]\over{AB}[/tex] is the middle-most point of [tex]\over{AB}[/tex] & now a perpendicular bisector of [tex]\over{AB}[/tex] is constructed.
[tex]\rule{150pt}{2pt}[/tex]
Answer:
D
Step-by-step explanation:
Find the product of 3.145 by 3
Answer:
9.435
Step-by-step explanation:
Simplify this for me please!
Answer:
Step-by-step explanation:
6 / 3√5
= 2/√5
= 2√5/5
Answer:
[tex]\frac{2\sqrt{5} }{5}[/tex]
Step-by-step explanation:
First, you can take a factor of (3) out of the numerator and denominator. This simplifies to equal 1, so you are left with 3/√5.
6 / 3√5 -----> (3/3) x 2/1√5 ---> (1) x 2/√5 ---> 2/√5
Because radicals should not be kept in the denominator, multiply both the numerator and denominator by the radical of 5. This removes the radical from the denominator while altering both the numerator and denominator equally. Remember, the square root of a number is technically the number raised to the 1/2 power. The 1/2 power times the 1/2 power equals the power of one, essentially "eliminating" the radical.
2/√5 ---> 2/√5 x √5/√5 ---> 2√5 / 5
As there is not way to simplify further, your final answer should be [tex]\frac{2\sqrt{5} }{5}[/tex].
Solve the right triangle. Round all answers to the nearest tenth.
The trigonometric function gives the ratio of different sides of a right-angle triangle. The length of the side KL is 30.81 units.
What are Trigonometric functions?The trigonometric function gives the ratio of different sides of a right-angle triangle.
[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\[/tex]
where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.
The measure of ∠J can be written as,
Cos(∠J) = JK/JL
Cos(∠J) = 7/31.6
∠J = 77.2°
Similarly the length of side KL can be written as,
Tan(∠J) = KL/JK
Tan(77.2°) = KL/7
KL = 30.81 units
Hence, the length of the side KL is 30.81 units.
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** PLS HELP **
BRAINLIEST!
Answer:
a and d
or
c and b
Step-by-step explanation:
supplementary angles are angles that add up to 180 degrees
when looking at the rectangle you see two possible answers
Which ordered pairs represent the equivalent ratios in the table? check all that apply.
(1, 2)
(1, 4)
(2, 8)
(4, 1)
(3, 12)
Answer:
(1,4) and (2,8)
Step-by-step explanation:
If you write these 2 ordered pairs as a fraction: 1/4 and 2/8 you can see that they are both equivalents.
Answer:
B, C and D
Step-by-step explanation:
Edge 2022/2023
Which fraction is equal to 0.370 (with the line over 370)
A. 37/100
B. 370/999
C. 37/99
D. 37/9
=========================================================
Explanation:
Let x = 0.370370370...
The "370" block repeats forever, due to the horizontal bar up top.
Multiply both sides by 1000 so that the decimal point moves three spots to the right.
x = 0.370370370...
1000x = 1000*0.370370370...
1000x = 370.370370370...
Then notice both x and 1000x involve the *exact* same decimal string of "370" repeating forever. This perfect match lets us cancel the decimal portions out when we subtract, and allows us to isolate x to get some fraction of integers.
1000x - x = 370.370370370... - 0.370370370...
999x = 370
x = 370/999
You can use your calculator to confirm that 370/999 = 0.370370370...
----------------
In fact, you can use your calculator to determine the following:
A) 37/100 = 0.37
B) 370/999 = 0.370370370...
C) 37/99 = 0.373737...
D) 37/9 = 4.1111111....
This allows us to see fairly quickly that choice B is the final answer and that we can rule out the others.
----------------
Side note: your calculator may round the last digit by mistake.
find the circumference and the area of a circle with 6m.
write your answer in terms of π, and be sure to include the correct units in your answer
Answer:
C = [tex]12\pi m[/tex]
A = [tex]36\pi m^2[/tex]
Step-by-step explanation:
I'm going to assume that the radius is 6m. The circumference of a circle is [tex]C = 2r\pi[/tex]. So we can plug in 6 for r and we get the circumference is [tex]12\pi m[/tex].
For area, the equation is [tex]A = \pi r^{2}[/tex]. So we can again plug in 6 for r and we get that the area is [tex]36\pi m^2[/tex].
If 6m is the diameter, then the circumference is [tex]6\pi m[/tex] and the area is [tex]9\pi m^2[/tex].
A 2.905x10 B 2.905x10 C 2.95x10
Answer:
a. 29.05 b. 29.05 c. 29.5
common-size analysis is another term used for a ____ analysis
Whats is 184 X 8 = ? In work?
Answer:
23
Step-by-step explanation:
23 ⇔ 23 R 0
184 divided by 8
=
23 with a remainder of 0
0
2
3
8
1
8
4
-
0
1
8
-
1
6
2
4
-
2
4
0
At the sweet stuff fresh produce the price of the bag of grapes… (cont in photo)
Answer:
i think it is D but I am not for shore
Which property is demonstrated below? startfraction 17 over 3 endfraction times startfraction 3 over 17 endfraction = 1 associative property of multiplication inverse property of multiplication identity property of multiplication commutative property of multiplication
The property applied to the expression is (b) inverse property of multiplication
How to determine the property?The expression is given as:
[tex]\frac{17}{3} * \frac{3}{17} = 1[/tex]
The numbers 17/3 and 3/17 are multiplicative inverses.
This means that the property applied to the expression is (b) inverse property of multiplication
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Answer:
Inverse Multiplication
Step-by-step explanation:
If you want the work to be shown, look up, otherwise my answer was B on Edge 2022
Trigonometric Identities:
Verify the identity [tex]\frac{sin(a+b)}{sin(a-b)}[/tex] = [tex]\frac{tan(a)+tan(b)}{tan(a)-tan(b)}[/tex]
Take RHS
[tex]\\ \rm\Rrightarrow \dfrac{tanA+tanB}{tanA-tanB}[/tex]
tanØ=sinØ/cosØ[tex]\\ \rm\Rrightarrow \dfrac{\dfrac{sinA}{cosA}+\dfrac{sinB}{cosB}}{\dfrac{sinA}{cosA}-\dfrac{sinB}{cosB}}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{\dfrac{sinAcosB+cosAsinB}{cosAcosB}}{\dfrac{sinAcosB-cosAsinB}{cosAcosB}}[/tex]
cancel cosAcosB[tex]\\ \rm\Rrightarrow \dfrac{sinAcosB+cosAsinB}{sinAcosB-cosAsinB}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{sin(A+B)}{sin(A-B)}[/tex]
Some important identities
[tex]\boxed{\begin{minipage}{6cm} Important Trigonometric identities :- \\ \\ $\: \: 1)\:\sin^2\theta+\cos^2\theta=1 \\ \\ 2)\:\sin^2\theta= 1-\cos^2\theta \\ \\ 3)\:\cos^2\theta=1-\sin^2\theta \\ \\ 4)\:1+\cot^2\theta=\text{cosec}^2 \, \theta \\ \\5)\: \text{cosec}^2 \, \theta-\cot^2\theta =1 \\ \\ 6)\:\text{cosec}^2 \, \theta= 1+\cot^2\theta \\\ \\ 7)\:\sec^2\theta=1+\tan^2\theta \\ \\ 8)\:\sec^2\theta-\tan^2\theta=1 \\ \\ 9)\:\tan^2\theta=\sec^2\theta-1$\end{minipage}}[/tex]
Answer:
[tex]\boxed{\begin{minipage}{6 cm}\underline{Trigonometric Identities}\\\\$\sin (A \pm B)=\sin A \cos B \pm \cos A \sin B\\\\ \dfrac{\sin A}{\cos A}=\tan A$\\\end{minipage}}[/tex]
[tex]\dfrac{\sin (a+b)}{\sin (a-b)} & = \dfrac{\sin(a) \cos (b) + \cos (a) \sin (b)}{\sin(a) \cos (b) - \cos (a) \sin (b)}[/tex]
[tex]\dfrac{\sin (a+b)}{\sin (a-b)} & = \dfrac{\sin(a) \cos (b) + \cos (a) \sin (b)}{\sin(a) \cos (b) - \cos (a) \sin (b)} \times \dfrac{\dfrac{1}{\cos (a) \cos (b)}}{\dfrac{1}{\cos (a) \cos (b)}}[/tex]
[tex]\dfrac{\sin (a+b)}{\sin (a-b)} & = \dfrac{\dfrac{\sin(a) \cos (b)}{\cos (a) \cos (b)} + \dfrac{\cos (a) \sin (b)}{\cos (a) \cos (b)}}{\dfrac{\sin(a) \cos (b)}{\cos (a) \cos (b)} - \dfrac{\cos (a) \sin (b)}{\cos (a) \cos (b)}}[/tex]
[tex]\dfrac{\sin (a+b)}{\sin (a-b)} & = \dfrac{\dfrac{\sin(a)}{\cos (a)} + \dfrac{\sin (b)}{\cos (b)}}{\dfrac{\sin(a)}{\cos (a)} - \dfrac{\sin (b)}{\cos (b)}}[/tex]
[tex]\dfrac{\sin (a+b)}{\sin (a-b)}=\dfrac{\tan(a)+\tan(b)}{\tan(a)-\tan(b)}[/tex]
IMPORTANT HELP PLEASE ANSWER IMMEDIATELY!!!!!
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Solve the following equation. Show all your work.
(x/(x−2))+((x−1)/(x+1))=−1
Answer:
Step-by-step explanation:
20% tip on a bill of $53.18
Answer:
$10.64
Step-by-step explanation:
20% out of $53.18 is $10.636 rounded to $10.64
what is the value of the underlined digit
9,603
Answer:nine thousand six hundred and three
Step-by-step explanation:
Answer:
nine thousand six hundred and three
Step-by-step explanation:
Help me quick!!!!!!!!!!!!!!
Answer: 2.99914cm Rounds up to 3
Step-by-step explanation:
A rectangle has a perimeter of 60m. Find the
length of the rectangle if its breadth is
12m
Find the cube root of
0.027
Answer:
the cube root of 0.027 is 0.3
¾ - (-⅞)= i need help please solve
Answer:
1 5/8
Step-by-step explanation:
3/4 - -7/8
3/4 + 7/8
6/8 + 7/8
13/8 = 1 5/8
Answer:
1 5/8 or 13/8
Step-by-step explanation:
Remove parentheses.
[tex]\frac{3}{4}+\frac{7}{8}[/tex]
Find the Least Common Denominator (LCD) of [tex]\frac{3}{4},\frac{7}{8}[/tex] . In other words, find the Least Common Multiple (LCM) of 4,8.
Method 1: By Listing Multiples
List the multiples of each number.
Multiples of 4 : 4, 8, ...
Multiples of 8 : 8, ...
Find the smallest number that is shared by all rows above. This is the LCM.
LCM = 8
Method 2: By Prime Factors
List the prime factors of each number
Prime Factors of 4 : 2, 2
Prime Factors of 8 : 2, 2, 2
Find the union of these primes.
2, 2, 2
Multiply these numbers: 2 * 2 * 2 = 8 ---> This is the LCM.
LCM = 8
---> LCD = 8
Make the denominators the same as the LCD.
[tex]\frac{3\times 2}{4\times 2}+\frac{7}{8}[/tex]
Simplify. Denominators are now the same.
[tex]\frac{6}{8}+\frac{7}{8}[/tex]
Join the denominators.
[tex]\frac{6+7}{8}[/tex]
Simplify.
[tex]\frac{13}{8}[/tex]
Convert to mixed fraction.
[tex]1\frac{5}{8}[/tex]