Joe plays basketball for the Wildcats and missed some of the season due to an injury. He did soune calculations that showed the mean number of points scored by his team was greater when he played than when he did not play. Here we test whether or not the mean was significantly greater The table summarizes this data where the i's are actually population means but we treat them like sample means. The degrees of freedom (d.f.) is given to save calculation time if you are not using software The Test: Test the claim that the mean points scored by the team was significantly greater when Joe played. Use a 0.05 significance level With Joe () 12 74.1 12.5 6.52 Without Joe (865.7 38.2 6.18 d.. 16 1 • Example 1: Using the given data, test the claim that the mean cholesterol level for all men who is the drug is less than the mean for those who do not use the drug. Assume both populations are normally distributed and use a 0.05 significance level. men Cholesterol Levels in mg/dL. No Drug (13) 237 289 257 228 303 275 262 304 214 233 263.2 811.1 28.6 Drug (12) 194 210 230 186 266 222 242 281 240 212 231.2 864.0 29.4 1. Here we are claiming that which means > Or-2 > 0.

Answers

Answer 1

The t-test allows us to evaluate whether the mean points scored by the team were significantly different between the scenarios with and without Joe.

To test the claim that the mean points scored by the team were significantly greater when Joe played, we can perform a t-test for independent samples.

Let's denote the mean number of points scored by the team when Joe played as mu1 and the mean number of points scored when Joe did not play as  mu2. The null hypothesis (H0) is that μ1 is not significantly greater than mu2, and the alternative hypothesis (H1) is that μ1 is significantly greater than mu2.

To perform the t-test, we need the sample means, standard deviations, and sample sizes for both scenarios (with Joe and without Joe). From the given data, we have the following:

With Joe:

Sample mean (x1) = 74.1

Sample standard deviation (s1) = 12.5

Sample size (n1) = 12

Without Joe:

Sample mean (x2) = 65.7

Sample standard deviation (s2) = 38.2

Sample size (n2) = 16

Now we can calculate the test statistic using the formula:

t = (x1 - x2) / sqrt((s1^2 / n1) + (s2^2 / n2))

Plugging in the values, we get:

t = (74.1 - 65.7) / sqrt((12.5^2 / 12) + (38.2^2 / 16))

Next, we determine the degrees of freedom (df) for the t-distribution. Since the sample sizes are different for the two scenarios, we use the approximate formula:

df = ((s1^2 / n1 + s2^2 / n2)^2) / ((s1^2 / n1)^2 / (n1 - 1) + (s2^2 / n2)^2 / (n2 - 1))

Plugging in the values, we get:

df = ((12.5^2 / 12 + 38.22 / 16)^2) / ((12.5^2 / 12)^2 / (12 - 1) + (38.2^2 / 16)^2 / (16 - 1))

After calculating the t-value and degrees of freedom, we can compare the t-value to the critical value from the t-distribution at the desired significance level (0.05). If the t-value is greater than the critical value,  and reject the null hypothesis and conclude that the mean points scored by the team were significantly greater when Joe played.

The specific calculations will depend on the actual data provided, but this explanation provides a general framework for performing the test.

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Related Questions

5 + 5
A)3
B)6
C)10
;D

Answers

Answer:

C) 10

Step-by-step explanation:

lol

The answer is C which is 10

In the exercise, X is a binomial variable with n = 5 and p = 0.4. Compute the given probability. Check your answer using technology. HINT [See Example 2.] (Round your answer to five decimal places.) P(X ≤ 2)

Answers

The probability of P(X ≤ 2) is  0.0135

We have the information available from the question:

Binomial variable is X

the value of n = 5

and, the value of p = 0.4

We are given to compute the probability P(X [tex]\leq[/tex] 2) and round the answer to five decimal places.

The binomial distribution formula is given by:

[tex]P(X)=nCx(p)^x(1-q)^n^-^x[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)!x!}[/tex]

We have to find the probability:

P(X [tex]\leq[/tex] 2) = P(X=1) + P(X=2)

P(X = 1) = [tex]5C1(0.4)^1(1-0.4)^5^-^1[/tex] = 0.0026

P(X= 2) =[tex]5C2(0.4)^2(1-0.4)^5^-^2[/tex] = 0.0109

P(X [tex]\leq[/tex] 2) = P(X=1) + P(X=2)

P(X [tex]\leq[/tex] 2) = 0.0026 + 0.0109

P(X [tex]\leq[/tex] 2) =  0.0135

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Milton Industries expects free cash flows of $20 million each year. Milton's corporate tax rate is 22%, and its unlevered cost of capital is 16%. Milton also has outstanding debt of $26.48 million, and it expects to maintain this level of debt permanently. a. What is the value of Milton Industries without leverage? b. What is the value of Milton Industries with leverage? a. What is the value of Milton Industries without leverage? The value of Milton Industries without leverage is $ million. (Round to two decimal places.) b. What is the value of Milton Industries with leverage? The value of Milton Industries with leverage is $ million. (Round to two decimal places.)

Answers

The value of Milton Industries with leverage is $131.52 million.

Milton Industries expects free cash flows of $20 million each year.

Milton's corporate tax rate is 22%, and its unlevered cost of capital is 16%.

Milton also has outstanding debt of $26.48 million and it expects to maintain this level of debt permanently.

a. Value of Milton Industries without leverage: Formula to calculate the value of a firm without leverage is; VL = VU + (PV of Tax shield) Where, VL = Value of the firm with leverage VU = Value of the firm without leverage PV of Tax Shield = Present Value of Tax Shield Expected Free Cashflows of Milton Industries = FCF = $20 million

Corporate Tax rate = T = 22%Unlevered

Cost of Capital = Ku = 16%Debt of Milton Industries = D = $26.48 million

Weighted Average Cost of Capital = WACC = Ku (1 - T)PV of Tax Shield = D x T x (1 - T) = $6.52 million VL = VU + PV of Tax Shield VU = FCF / Ku = $125 million VL = $125 + $6.52 = $131.52 million

b. Value of Milton Industries with leverage: VL = VU + PV of Tax Shield PV of Tax Shield = D x T x (1 - T) = $6.52 million VL = VU + PV of Tax Shield VU = FCF / Ku = $125 million VL = VU + PV of Tax Shield = $125 + $6.52 = $131.52 million. Therefore, The value of Milton Industries without leverage is $125 million. The value of Milton Industries with leverage is $131.52 million.

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1. An exponential function is shown below.
f (x)= -2(2)
Which key attribute does the function not exhibit?

Answers

Sorry I need points lol

This question seems extremely odd to me. I don't really even understand what's being asked.

As far as exponential functions go, it's missing an exponent for one. The dependent variable is missing. This essentially saying f(x) = -4 or y = -4. Which is fine, but is definitely not an exponential function and in a very odd and incomplete form to begin with.

What is the surface area of this right rectangular prism with dimensions of 8 inches by 4 inches by 14 inches?

Answers

Answer:

400 inches

Step-by-step explanation:

Area of all sides and add them

E B A G ord Теа F NOTE: Angles not necessarily drawn to scale.
help ​

Answers

Answer: x = 13

angel bge and angle agf are vertical meaning they’re equivalent

77 + 90 + x = 180 (180 because all of them added together are supplementary)

167 + x = 180

x = 13

Answer:

Step-by-step explanation:

X=13

does someone know the answer?

Answers

Answer:

I think it is the last answer.

Step-by-step explanation:

There can only be one vertex.

which expression is equivalent to (4^2)(4^5)

Answers

Answer: Sorry I don't know the answer but I recommend an app that will help you is called Mathpapa is really helpful and have helped me get A on test and homework

Step-by-step explanation: is htis one https://www.mathpapa.com/algebra-calculator.html

a - 2/3 = 3/5 how much is a?

Answers

Answer:

its 1 4/5  or 19/15

they are both the same

Step-by-step explanation:

so first you need to find the same common factor

A-10/15=9/15

then add 10/15 and 9/15 to find a

19/15-10/15=9/15

or

1 4/15-2/3=3/5

yw :)

a = 19/15 is the answer you’re looking for

You are going to install a 15-metre long fence. If the posts are 3 metres apart, how many fence posts will you need? Select the best way to demonstrate the answer to students

Answers

Answer : 6 fence posts. The best way to demonstrate the answer to students is to use the formula

Explanation: To install a 15-metre long fence, the posts are 3 metres apart, how many fence posts will you need?                         The best way to demonstrate the answer to students is to use the formula:                                                                                        Total number of posts = (Length of fence ÷ Distance between posts) + 1

Where;Length of the fence = 15 metres, Distance between posts = 3 metres

Total number of posts = (15 ÷ 3) + 1                                                                                                                                             Total number of posts = 5 + 1 = 6                                                                                                                                                                        Therefore, you will need 6 fence posts.

The best way to demonstrate the answer to students is to use the formula:      Total number of posts = (Length of fence ÷ Distance between posts) + 1

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How to solve -3x+1<7

Answers

Answer:

x > − 2

Step-by-step explanation:

If your motive was to solve for x thats your answer, if not good luck!

How many solutions does 4(−5x+8)= 4(−5x+8) have?

Answers

Answer:

infinity

Step-by-step explanation:

Which describes the cross section of the square prism that passes through the vertices A, B, C, and D shown below?
A square prism. The front left points are labeled A and D. The back right points are labeled B and C.
a rectangle
a square
a kite
a trapezoid

Answers

A trapezoid

~ hope this helps!

Answer:

its not that i got it wrong

Step-by-step explanation:

???????????
Helppp.

Answers

Answer:

C = 25.12

Step-by-step explanation:

C = 2πr

C = 2(3.14)(4)

C = 6.28(4)

C = 25.12

1. Prove that at any party of 31 people, there’s always a person who knows an even number of others. (Assume that acquaintance is mutual: if Alice knows Zelda, then Zelda knows Alice.)

Answers

To prove that at any party of 31 people, there's always a person who knows an even number of others, we can use the pigeonhole principle.

The pigeonhole principle states that if we distribute more than "n" objects into "n" boxes, then at least one box must contain more than one object. In this case, the "objects" represent the people at the party, and the "boxes" represent the number of people each person knows.

Let's assume, for the sake of contradiction, that every person at the party knows an odd number of others. This means that each person has an odd number of acquaintances.

Now, let's consider the sum of the number of acquaintances for all 31 people. Since each person knows an odd number of others, the sum of odd numbers is also an odd number.

However, if we count the total number of acquaintances in a group, it must be even since each acquaintance involves two people. This creates a contradiction because we cannot have both an odd and an even sum for the total number of acquaintances.

Therefore, our assumption that every person knows an odd number of others must be false. Hence, there must be at least one person at the party who knows an even number of others.

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20. An airport, a factory, and a shopping center are at the vertices of a right triangle formed by three highways. The airport and factory are 6.0 miles apart. Their distances from the shopping center are 3.6 miles and 4.8 miles, respectively. A service road will be constructed from the shopping center to the highway that connects the airport and factory. What is the shortest possible length for the service road? Round to the nearest hundredth​

Answers

Jdbdjs dh hand is su due

Please help, GodBless.

Answers

Answer:

(A) seems to have the least amount of slope with a slope of -6, compred to all, its the least one.

Step-by-step explanation:

Follow slope formula

(y2-y1) / (x2-x1)

Or calculate using rise over run method

Angela bought a dress that cost $22.50. If the sales tax is 6.5%, how much tax did she pay? I need help with this one

Answers

your answer will be $23.96


Please help me with the question

Answers

Answer: 70

Step-by-step explanation: if you look at it hard enough they both look the same, this is called a vertical angle, I'm down for more questions lol. you keep on getting on my fyp

A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the trip. Each small car can hold 4 people and each large car can hold 6 people. The students rented twice as many large cars as small cars, which altogether can hold 48 people. Graphically solve a system of equations in order to determine the number of small cars rented, x,x, and the number of large cars rented, yy.

Answers

Answer:

The students rented 3 small cars and 6 large cars.

Step-by-step explanation:

Since a group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the trip, and each small car can hold 4 people and each large car can hold 6 people, and the students rented twice as many large cars as small cars, which altogether can hold 48 people, to determine the number of small cars rented, X, and the number of large cars rented, Y, the following calculation must be performed:

4X + 6Y = 48

4x4 + 6x8 = 16 + 48 = 64

4x3 + 6x6 = 12 + 36 = 48

Thus, the students rented 3 small cars and 6 large cars.

Solve −2|m|= −10.

What is m?

Answers

Answer:

|m| : -5

Step-by-step explanation:

{ -2|m|= -10= |m| : -5 }

Find the range, median, first and third quartiles, and interquartile range for each data set OF THE NUMBERS 52 72 96 21 58 40 75

Answers

Answer:

Range: 75 Median: 58 1Q: 40 3Q: 75 Interquartile: 35

what is the ratio of 12​

Answers

12 to 1

is the ratio :)

n a contingency table, when all the expected frequencies are equal the oberved frequencies the calculaed chi squared statistic equals zero. True or False

Answers

The given statement "When all the expected frequencies are equal the observed frequencies the calculated chi squared statistic equals zero." is true because chi-squared statistic will be zero in this case.

In a contingency table, the expected frequencies are calculated based on certain assumptions and can be different from the observed frequencies. The chi-squared statistic is used to determine whether there is a significant association between the variables in the contingency table.

When all the expected frequencies are equal to the observed frequencies, it means that there is a perfect match between the observed data and what would be expected under the assumption of independence.

In this case, the chi-squared statistic will be zero, indicating no discrepancy between the observed and expected frequencies.

This scenario is highly unlikely to occur in real-world data because observed frequencies typically deviate from the expected frequencies due to sampling variability or factors influencing the relationship between variables.

In most cases, the expected frequencies will differ from the observed frequencies, resulting in a non-zero chi-squared statistic, indicating a significant association or departure from independence between the variables.

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47. Brainliest will be given, need answer asap

Answers

Answer:

Look below.

Step-by-step explanation:

45. B

46. D

47. B

Answer:

45.A   46. Bike A    47.C

Step-by-step explanation:

A vending machine that dispenses coffee into cups must fill the cups with 7.8 ounces of liquid. Before selling the machine to a college or business, the company tests the machine to be sure it dispenses an average of 7.8 ounces. A sample of 20 amounts is listed here:
7.78 7.79 7.82 7.82 7.87 7.84 7.80 7.82 7.80 7.78
7.83 7.75 7.85 7.83 7.84 7.73 7.82 7.87 7.81 7.88
(1) Set up the null and the alternative hypotheses to test whether the average amount of coffee dispensed is different from 7.8 ounces.
(2) Complete the remaining hypothesis-testing steps using α= .05.
(3) Find the p value.
(4) Based on the p value what can the company conclude about the average amount of coffee dispensed by the machine.

Answers

The null hypothesis states that the average amount of coffee dispensed by the machine is equal to 7.8 ounces, while the alternative hypothesis states that the average amount is different from 7.8 ounces.

In this scenario, the null hypothesis (H0) is that the average amount of coffee dispensed by the machine is 7.8 ounces, while the alternative hypothesis (Ha) is that the average amount differs from 7.8 ounces. To test these hypotheses, the next step is to calculate the test statistic.

Using the given sample of 20 amounts, we can compute the mean of the sample, which is 7.816 ounces. The standard deviation of the sample is 0.044 ounces. With these values, we can calculate the t-test statistic.

The t-test statistic is calculated by subtracting the hypothesized value (7.8) from the sample mean (7.816) and dividing it by the standard deviation (0.044), multiplied by the square root of the sample size (20). The resulting t-value is approximately 1.818.

To determine the p-value associated with this t-value, we compare it to the t-distribution with n-1 degrees of freedom (19 degrees of freedom in this case). Using a statistical table or software, we find that the p-value is approximately 0.085.

Since the p-value (0.085) is greater than the significance level (α = 0.05), we fail to reject the null hypothesis. This means that there is insufficient evidence to conclude that the average amount of coffee dispensed by the machine is different from 7.8 ounces. Therefore, based on the p-value, the company cannot conclude that the average amount of coffee dispensed is significantly different from 7.8 ounces.

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Compare the two functions below in two complete sentences.

Help

Answers

Answer:

I guess we have the table:

x     f(x)

-4      7

-2      5

0       3

2       1

4      - 1

To find the slope of this, we need to select two different points (x1, y1) and (x2, y2) and use the relation:

slope = (y2 - y1)/(x2 - x1)

let´s use the first two:

(-4,7) and (-2, 5)

Slope = (5 - 7)/(-2 - (-4)) = -2/2 = -1

Now, if we want to be sure that this is a linear equation, we should do the same for other two pairs of points, now use the first and the third:

(-4, 7) and (0,3)

S = (3 - 7)/(0 -(-4)) = -4/4 = -1

Now, for the function g(x) we can see a constant line, that is parallel to the x-axis.

This means that the slope of this function is equal to zero.

This means that the slope of g(x) is bigger than the slope of f(x), because 0 > 1 i guess

What is the answer for |-12| is positive or negative

Answers

Answer:

postitive

Step-by-step explanation:

|-a| = a, a>0

Find the coordinates of the endpoint of the image?

Answers

Given:

The graph of a line segment.

The line segment AB translated by the following rule:

[tex](x,y)\to (x+4,y-3)[/tex]

To find:

The coordinates of the end points of the line segment A'B'.

Solution:

From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).

We have,

[tex](x,y)\to (x+4,y-3)[/tex]

Using this rule, we get

[tex]A(-2,-3)\to A'(-2+4,-3-3)[/tex]

[tex]A(-2,-3)\to A'(2,-6)[/tex]

Similarly,

[tex]B(4,-1)\to B'(4+4,-1-3)[/tex]

[tex]B(4,-1)\to B'(8,-4)[/tex]

Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).

write an equivilent expression that is equivilent to 4(w+3)-2

Answers

Answer:

4w + 10

Step-by-step explanation:

If you have any questions feel free to ask

answer: 4w+10

explanation:: distribute;

= (4)(w)+(4)(3)+−2

= 4w+12+−2

combine like terms;

= 4w+12+−2

= (4w)+(12+−2)

= 4w+10

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