Answer:
224.6 N
Explanation:
We can use first the formula to calculate the centripetal acceleration, given by:
[tex]a_c=\frac{v_t^2}{R}[/tex]
where the Vt is the tangential velocity, and R is the radius of the circular motion.
Then, for our case we have:
[tex]a_c=\frac{v_t^2}{R}=\frac{3.5^2}{0.6}\approx 20.42\,\,\frac{m}{s^2}[/tex]
And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:
[tex]F_c=11 \,*\,20.42\,N = 224.6\,\,N[/tex]
Answer:
225 N
Explanation:
Just answered the question
In which direction does centripetal force act on an object? in the opposite direction of the tangential speed of the object in the same direction of the tangential speed of the object toward the outside of the circle in which the object is moving toward the center of the circle in which the object is moving
Answer:
towards the center of the circle
(which appears to be the last option in your list of possible answers)
Explanation:
The centripetal force points always towards the center of the circle described by the object moving.
The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.
The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.
In other words, the centripetal force is also known termed as the force that tends to act on a body moving in a circular path and is directed towards the centre around which the body is moving.For example - Motion of merry go round and the motion of roller skates on the rink floor are the examples of centripetal force, where the force always acts in the direction, center of the circular track.Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.
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What exerts the thrust force acting on the cart?
Answer:
This question appears incomplete
Explanation:
The question appears incomplete. However, a thrust can be described as a force or a push. A cart can be described as a vehicle (usually with two wheels) that is used to transport load from one point/place to another.
Newton first law of motion (law of inertia) states that a body will continue to be in a state of rest or if in motion, remains in motion (at constant velocity) unless acted upon by an external force. Hence, a cart will continue to be in a state of rest unless acted on by an external force which can be exerted by animals or humans (depending on the type of cart).
c) A sample of substance of volume 10 cm3 was brought back to Earth from the Moon.
The weight of the sample on the Moon was 0.13 N. The gravitational field strength
on the Moon is 1.6 N kg-1.
(1)
Calculate the density of the sample.
Answer:
8125
Explanation:
[tex]P=0,13 N\\a=1,6 N/kg\\m=P/a=0,13/1,6=0,08125\\V=10(cm)^{3} =10^{-5} meters^{3} \\p=m/V=0,08125/10^{-5} =0,08125*100000=8125kg/meters^{3}[/tex]
the two forces acting on a boat or some other floating object _______are and gravity
Answer:
The two forces acting on a boat or some other floating object are buoyancy and gravity
Answer: buoyant forceExplanation:two forces acting on a boat or some other floating object are buoyant force and gravityhi friend your answerI hope it will be helpful for you
mark as brainest answer
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- Over the weekend you go for an urban hike, traveling 3 miles north then 4 miles west before stopping to take a break. If this hike takes 1 hour, what is your average velocity during that time? - You leave your house to go for a drive to clear your head, driving 10 miles over the course of 30 minutes before arriving back home. What is your average velocity?
Answer:
A.) 5 mph
B.) 20 mph
Explanation:
Given that you are traveling 3 miles north then 4 miles west before stopping to take a break. If this hike takes 1 hour,
Let's first calculate the displacement be using pythagorean theorem
D = sqrt ( 3^2 + 4^2 )
D = sqrt ( 9 + 16 )
D = sqrt ( 25 )
D = 5
Average velocity = displacement/time
Average velocity = 5/1
Average velocity = 5 mph
Therefore, your average velocity during that time is 5 mph
- You leave your house to go for a drive to clear your head, driving 10 miles over the course of 30 minutes before arriving back home.
Average velocity = 10/ 0.5
Average velocity = 20 mph
Please help me slow this I don't understand how this works
Answer:
[tex]A=90^0-B\\B+C=180^0-90^0=90^0\\C=90^0-B\\A=C[/tex]
Explanation:
Question: A) A car is driving too fast on a flat non-banked curve. The car cannot stay on the road. What path will the car take as it leaves the road? See Image. (a) (b) B) The driver wants to go faster around the same curve mentioned above and not run off the road. He adds sandbags to his car to make it weigh more so that the friction force between the tires and the road will be increased. Will this work? Explain your answer.
Explanation:
(a) The car will leave tangentially to the road, so it will take path d.
(b) Sum of forces on the car in the vertical direction:
∑F = ma
N − mg = 0
N = mg
Sum of forces on the car in the centripetal direction:
∑F = ma
Nμ = m v²/r
mgμ = m v²/r
gμ = v²/r
v = √(grμ)
The maximum velocity is independent of mass, so adding sandbags will not work.
Love, which can't be observed or measured directly, is an example of a psychological construct.
Please select the best answer from the choices provided
О Тrue
O False
Answer:
True
Explanation:
A psychological construct can't be observed and you can feel this,
Example: anxiety, anger, sadness
An object is released from rest from a top of a building 90 meters high. Neglect air friction.
What is the volume of its acceleration?
Calculate the time it takes to reach the floor?
With what velocity does it reach the floor?
How fast is it moving when it is 50 meter above the floor?
Answer:
1. a = 9.8 m/s²
2. t = 4.28 s
3. Vf = 42 m/s
4. Vf = 28 m/s
Explanation:
1.
Since, the body is under free fall motion. Therefore, the value of its acceleration shall be equal to the acceleration due to gravity.
a = 9.8 m/s²
2.
The time taken by the ball to reach the ground can be calculated by using second equation of motion:
h = Vi t + (1/2)gt²
where,
h = height = 90 m
Vi = initial velocity = 0 m/s
t = time taken = ?
Therefore,
90 m = (0 m/s)t + (1/2)(9.8 m/s²)t²
t = √(18.36 s²)
t = 4.28 s
3.
In order to find final velocity we use first equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(4.28 s)
Vf = 42 m/s
4.
when the ball is at height of 50 m, it means it has covered:
h = 90 m - 50 m = 40 m
we use third equation of motion at this point:
2gh = Vf² - Vi²
(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²
Vf = √(784 m²/s²)
Vf = 28 m/s
11. एक समान चुम्बकीय क्षेत्र में लम्बवत प्रवेश करने वाले किसी आवेशित कण द्वारा प्राप्त वृत्तीय पथ की
7 त्रिज्या का सूत्र ज्ञात कीजिए।
2
Find the formula of radius obtained by a charged particle entering perpendicularly
in a uniform magnetic field.
Answer:
r=mv/BeExplanation:
If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule
to derive the radius of the path of the charge we apply
F= mv^2/r=Bev
where
m= mass of the electronic charge
e=charge
B=magnetic field
v=average speed
r=radius
rearranging we have
r=mv^2/Bev
r=mv/Be
27.
In a graph showing how temperature of a material changes over time, temperature
change is the:
A. dependent variable
C. variable with the smallest range
B. independent variable
D. variable with the largest range
Answer:
A. Dependent variable
Explanation:
In a graph showing how temperature of a material changes over time, temperature is taken on y-axis and time is taken on x-axis. It shows how temerature altered as the time changes.
In temperature-time graph, temperature is directly dependent on time. With the increase in time, temperature rises, falls or remains constant. It implies that temperature is dependent variable that depend on time.
Hence, the correct option is (A).
4. What is the momentum of a 78.0 N bowling ball with a velocity of 8.00 m/s?
Momentum = (mass) x (speed)
We don't know the mass of the bowling ball, but we know how much it weighs. So if we knew the acceleration of gravity in the place where the ball is, we could calculate its mass. The question doesn't tell us what planet the bowling ball is on. So if we only use the information given in the question, there's no way to find the answer, and we're stuck here.
But I urgently need the points, so I'm going to go out on a limb here and make a big assumption: I'll assume that the alley where this ball is rolling and bowling is located on planet Earth, where the acceleration of gravity is around 9.8 m/s² everywhere on the planet's surface. NOW I can go ahead and answer the question that I just invented.
weight = m g
Mass = (weight) / (g)
Mass = (78.0 N) / (9.8 m/s²)
Mass = 7.96 kilograms
Momentum = (mass) x (speed)
Momentum = (7.96 kg) x (8.00 m/s)
Momentum = 63.7 kg-m/s
A car moves from rest with an acceleration of 0.2ms
Find its velocity when it has moved a
distance of 50m
From the problem we notice that the question
does not involver. Therefore, the required equation
is)
Explanation:
Given:
Δx = 50 m
v₀ = 0 m/s
a = 0.2 m/s²
Find: v
The problem does not involve time. Therefore, the required equation is:
v² = v₀² + 2aΔx
Plug in values and solve:
v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)
v = 4.47 m/s
The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.
To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:
v² = u² + 2as
Where:
v = final velocity
u = initial velocity (which is 0 in this case as the car starts from rest)
a = acceleration
s = distance traveled
Plugging in the values into the equation:
v² = 0² + 2(0.2)(50)
v² = 0 + 20
v² = 20
Taking the square root of both sides:
v = √20
v = 4.47 m/s
Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.
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Suppose that a certain battery produces a voltage of 1.55V without a load connected (open circuit) and a current of 500mA when shorted. According to these specifications, if we were to model this as an ideal voltage source in series with a source resistance, what should the source voltage and internal resistance be? Justify your answer
Answer:
Explanation:
Let the internal resistance be r .
Since in open circuit the volt is 1.55 V , this will be the source voltage .
Source voltage = 1.55
If external resistance be R .
1.55 / (R + r ) = .500
R + r = 3.1 ohm
So sum of internal resistance and external resistance will be 3.1 ohm.
3. A block of mass m is suspended by strings as shown in the figure. The tension in the horizontal string
is 36 N. The angle 0 is 60°. Find the mass of the block and the tension forces in string A and string
B
I am having trouble trying to answer this problem. Any help?
Answer:
mass of the block is 7.2Kg
Tension on string A = 72N
Tension on the string with an angle is = 108N
Explanation:
The Horizontal string will have the cos component of the force...
Hence, mg cos60 = 36
by keeping acceleration due to gravity = 10 m/s^2, we get,
m = 7.2Kg
The tension in String A = mg = 7.2*10 = 72N
since the whole string holding the block is pulled by another string with 36 N
the resultant force will be the tension of the string with an angle.
Hence, 72 +36 = 108 N
Please let me know whether I got this right or not...
Compare the de Broglie wavelength of a golf ball moving at 70.0 miles per hour (31.3 m/s) to that of an alpha particle moving at 3.40E+7 miles per hour (1.52E+7 m/s) and a bullet with a speed of 700 miles per hour (313 m/s). Which region of the electromagnetic spectrum are each of these wavelengths near
Answer:
1. Golf ball is in the range of only particulate detectable range
2, alpha partcle is in ultraviolet range of wavelength
3.bullet is in xray range of wavelength
All in the EMW spectrum
Does the atomic number of an atom change?
Answer:
An elements atomic number will never change, that is because the atomic number is its "identity."
When students were surveyed about the kind of thinking they considered to be most important in their academic studies, the majority chose?
Answer:Critical Thinking
Explanation:
7.2 in college success text back
A student has a displacement of 304 m north in 180 s. What was the student's average velocity?
Given : Unknown: Equation: Substitution: Solve:
Subject is Physics
Answer:
v = 1.69 m/s
Explanation:
Given that,
Displacement of the student is 304 m due North and it takes 180 s.
We need to find the student's average velocity. Using formula of velocity.
Velocity = displacement/time
[tex]v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s[/tex]
Hence, the student's average velocity is 1.69 m/s.
The student's average velocity will be "1.69 m/s".
Displacement and Velocity:The main distinction between velocity as well as speed would be that velocity, like speed, seems to have a direction and therefore it is a vector quantity.
This same distance travelled together along a straight line throughout a particular direction from either the beginning point is defined as displacement. Because displacement has both size as well as the direction, it's a vector quantity.
Given values:
Displacement, d = 304 mTime, t = 180 sWe know,
The velocity (v):
= [tex]\frac{Displacement}{Time}[/tex]
By substituting the values, we get
= [tex]\frac{304}{180}[/tex]
= [tex]1.69 \ m/s[/tex]
Thus the answer above is correct.
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Determine the distance S to which the 90kg painter can climb without causing the 4m ladder to slip at it's lower end A. The top of the 15kg ladder has a small roller, and at the ground the coefficient of static friction is 0.25. The mass center of the painter is directly above her feet.
Explanation:
...................,..........
Newton's first law states that at rest the sum of the forces acting on a body is zero
The distance S to which the painter can climb is approximately 2.55 meters
The reason the above value for the distance is correct is as follows:
The given parameter are;
The mass of the painter, m₁ = 90 kg
Length of the ladder, l = 4 m
The mass of the ladder, m₂ = 15 kg
The coefficient pf static friction, μ = 0.25
Friction force, [tex]\mathbf{F_f}[/tex] = Normal reaction, N × μ
Normal reaction (flat surface), N = Weight of painter + Weight of ladder
N = m₁·g + m₂·g
Where;
g = The acceleration due to gravity, g = 9.81 m/s²
N = 90 kg × 9.81 m/s² + 15 kg × 9.81 m/s² = 1,030.05 N
∴ [tex]\mathbf{F_f}[/tex] = 1,030.05 N × 0.25 = 257.5125 N
Friction force, [tex]\mathbf{F_f}[/tex] = 257.5125 N (Horizontal force)
At equilibrium, the sum of the horizontal forces = 0
∴ Fₓ + [tex]\mathbf{F_f}[/tex] = 0
Fₓ = [tex]-F_f[/tex] = -257.5125 N (Acting opposite to the direction of the friction force)
The height of the top of the ladder from the ground, h = √(4²-1.5²) = √(13.75)
Taking moment about point A gives;
Clockwise moment = Anticlockwise moment
Fₓ × h = m₁·g·s·cos(θ) + m₂·g·(l/2)·cos(θ)
Therefore;
Fₓ × √(13.75) m = 90 kg × 9.81 m/s² × s × (1.5/4) + 15 kg × 9.81 m × 2 m × (1.5/4)
Fₓ × √(13.75) m = 331.0875 N × s + 110.3625 J
257.5125 N × √(13.75) m = 331.0875 N × s + 110.3625 J
s = (257.5125 N × √(13.75) m - 110.3625 J)/(331.0875 N) ≈ 2.55 m
The distance to which the 90 kg painter can climb without causing the 4 m ladder to slip at its lower end, A, distance S ≈ 2.55 meters
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Help please Subject (general psychology)
Answer:
plz give the question... floor the proper answer
Explanation:
plz mark me add the brainliest
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me and follow ma
Suppose a fast-pitch softball player does a windmill pitch, moving her hand through a circular arc with her arm straight. She releases the ball at a speed of 21.3 m/s21.3 m/s (about 47.6 mph47.6 mph ). Just before the ball leaves her hand, the ball's radial acceleration is 871 m/s2871 m/s2 . What is the length of her arm from the pivot point at her shoulder?
Answer:
R = 52.08 cm
Explanation:
given data
tangential velocity v = 21.3 m/s
radial acceleration aR = 871 m/s²
solution
we will get here length of her arm from the pivot point at her shoulder so
here we know aR = [tex]\frac{v^2}{R}[/tex] ........................1
so put here value and we get
871 = [tex]\frac{21.3^2}{R}[/tex]
R = 0.5208840 m
R = 52.08 cm
Answer:
Explanation:
linear speed of ball v = 21.3 m /s
radial acceleration = 871 m /s²
radial acceleration = v² / R
where R is length of arm which acts as radius of circular path of the ball .
Putting the values
21.3² / R = 871
R = .52 m.
The rain gauge has 2 inches of precipitation.
Qualitative or Quantitative
Answer:
Quantitative is the correct term
a mountain climber lies flat on the surface of a glacier (assumed frictionless), which is inclined at 30 degrees to the horizontal. he remains stationary because he is holding on to a rope that is attached to a spoke in the ice further up the slope. THe slope is parallel to the surface of the ice. if the force of the ice on the climber is 210N, what is the tension in the rope
Answer:
181.87 N
Explanation:
Given that a mountain climber lies flat on the surface of a glacier (assumed frictionless), which is inclined at 30 degrees to the horizontal. he remains stationary because he is holding on to a rope that is attached to a spoke in the ice further up the slope.
Since the he slope is parallel to the surface of the ice.
if the force of the ice on the climber is 210N, the tension T in the rope will be
T = 210 cos 30
T = 181.86 N
Therefore, the tension in the rope is 181.86 N
Calculate the length of segment RS with midpoint, M , if RM = 5x and MS = x + 12.
A. 3
B. 25
C. 30
D. 36
E. 15
Answer:
the full segment is: 30 units long
which coincides with answer C in your list
Explanation:
If M is the midpoint, then it divides the segment in two equal parts. Then, we can say that:
RM = MS (equality among the two parts of the divided segment)
replacing RM with "5 x" and MS with "x + 12", we get:
5 x = x + 12
solving for x:
5 x - x = 12
4 x = 12
then x = 3
With this info, we can calculate the length of each half of the segment and consequently its full length:
RM = 5 x = 5 (3) = 15
then the full segment is: 30 units long
When a wave goes through a substance, _______________ has occurred.
When a wave gets trapped or stuck in a substance, ______________ has occurred.
When a wave bounces off of a surface, ______________ has occurred.
The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.
Answer:
A) When a wave goes through a substance, _______________ has occurred.
This is refraction or transmission.
Refraction refers to the changes in the wave that occur when it enters a new medium, in this case, the substance.
Transmission refers to the transfer of energy that is now in the medium.
Usually, we have both of those together.
B) When a wave gets trapped or stuck in a substance, ______________ has occurred.
This is total internal reflection. This happens when, by the Snel Law, the angle of the transmited wave is 90° (or larger) which is traduced in no transmitted wave, this is why the wave is "trapped" in the substance.
C) When a wave bounces off of a surface, ______________ has occurred.
This is reflection.
D) The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.
This is the Law of Reflection, that says "when light is reflected from a surface, the angle of reflection is the same as the angle of incidence"
The position of a particle is r⃗ (t)=(3.0t2iˆ+5.0jˆ−6.0tkˆ)m. (a) Determine its velocity and acceleration as functions of time. (b) What are its velocity and acceleration at time t = 0?
Explanation:
It is given that,
The position of a particle is given by :
[tex]r(t)=(3t^2i+5j-6tk)\ m[/tex]
(a) Velocity of a particle is given by :
[tex]v=\dfrac{dr(t)}{dt}[/tex]
Putting values,
[tex]v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s[/tex]
The acceleration of the particle is given by :
[tex]a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2[/tex]
(b) At t = 0,
Velocity, v = 6k m/s
Acceleration, a = 6i m/s²
A car drives 10km with a speed of 72 km/hr and then runs out of gas. Then you walk 2km for the next 30 min until you find a gas station. (A) What is the displacement of the total trip? (B) How long does the entire trip take? (C) What is the average velocity of the entire trip?
Answer:
A- 12 km
B- 42 minutes
C- 17.14 km per hour
Explanation:
A- The displacement of the total trip is 12 kilometers, which emerges by adding the 10 kilometers traveled by car to the 2 kilometers traveled on foot.
B- The trip, in total, took 42 minutes, which arises from adding the 30 minutes of the journey on foot, plus 12 minutes of travel by car at 72 km / h (72/60 x 10 = 12).
C- While 12 km were covered in 42 minutes, the average speed of the trip was 17.14 km / h. This arises from the following calculation:
42 = 12
60 = X
(60 x 12) / 42 = X
17.14 = X
A girl delivering newspapers covers her route by traveling 6.00 blocks west, 3.00 blocks north, and then 7.00 blocks east. HINT (a) What is her final position relative to her starting location? (Enter the magnitude in blocks and the direction in degrees north of east.) magnitude blocks direction ° north of east (b) What is the length (in blocks) of the path she walked?
Answer:
a) we can form a triangle in order to use the Pythagorean theorem = 3² + 1² = h²
h² = 9 + 1 = 10
h = √10
h = 3.1623 blocks
we must also find the angle at the initial point of the triangle (A):
tan⁻¹ (1/3) = 18.43°
the position relative to her starting position is 90° - 18.43° = 71.57° north of east
b) total distance traveled = 6 + 3 + 7 = 16 blocks
Which law applies to the picture?
Newtons 1st Law of Motion
Newtons 2nd Law of Motion
Newtons 3rd Law of Motion
Answer:
Newton's first law
Explanation:
Newton's first law of motion says, that an object will stay in its current motion, unless if a force acts upon it.
So an object already at rest, will stay at rest. And the ball rolling will keep rolling, if no other force such as friction slows it down.