Answer:
20
Step-by-step explanation:
2 lines intersect. Where the 2 lines intersect, 4 angles are created. Labeled clockwise, from uppercase right: angle 1 (3 x minus 1) degrees, angle 2 is blank, angle 3 (2 x + 9) degrees, and angle 4 is blank. What are the numerical measures of each angle in the diagram? ∠1 and ∠3 measure degrees. ∠2 and ∠4 measure degrees.
Answer: angle 1 and 3 measure 29 degrees.
angle 2 and 4 measure 151 degrees.
Step-by-step explanation:
What is the question to b(x)=3x-1.
Answer:
x = 1/3
Step-by-step explanation:
Mark wants to put a fence around his square yard.He knows that his yard is shaped like a square and the area of the yard is 110. What would the perimeter be
Answer:
27.5 is the answer good luck
Step-by-step explanation:
good luck my G
Factor the following polynomial completely. x²n - y²n
Answer:
(n)*(x+y)(x-y)
Step-by-step explanation:
First of all, you take the n out, and then you use the formula of x²- y² and it will equal to (x+y)(x-y).
Answer:
n(x+y)(x−y)
Step-by-step explanation:
1. To factor this equation, first, you can see that both the x^2 and the y^2 have an n next to them. So, you can take out the n. You get this: n(x^2-y^2)
2. After you take the n out, you can also factor the (x^2-y^2) since they are both squared (to the second power). To do this, you simply split the two apart and make sure to include the negative. You get this, the final answer:
n(x+y)(x-y)
3. You can check it by multiplying out the answer, and once multiplied out, you get the original expression of x^2n-y^2n.
Hope this helped! Feel free to ask any questions :)
The perimeter of a rectangular playing field is 280 feet. The length of the field is 20 feet more than the width. What are the dimensions of the playing field? (You need to find the length and the width.)
Answer:
L =80
w=60
Step-by-step explanation:
P =280
L =w +20
=>L +w=280 :2 =140
w+20+w=140
2w=140 - 20
2w =120
w=120 :2 =60
L=60 +20 =80
P =2L +2w
P =2 ×80 +2 ×60
P=160 +120
P=280
Answer:
L = 80 , w=60
Step-by-step explanation:
l= w+20
perimeter: l+w+l+w=280
Plug in the value of L in place of L
(w+20)+w+(w+20)+w=280
Combine Like terms
and then separate the variables and knowns by subracting 40 from both sides
4w+40=280
-40 -40
Divide by 4 from both sides so (W) would be alone
4w=240
÷4 ÷4
You solved half the question now
w = 60
Remember the L at the top
we now know the value of W
so
L=(60)+20
L=80
just to be sure
80+80+60+60=280
you are welcome
f(x) = x – 5x + 2 – 3x + 6
State how many complex and how many zeros the function have?
Evaluate the expression when a = -2 and b=2.
a-2b
Answer:
-6
Step-by-step explanation:
a-2b
-2-2(2)
-2-4
-6
2(3-p)=17=41 show answer.
this is what I found hope its correct!♀️
HELPPPPPPPPPPP!!!!!!
Answer:
2x
Step-by-step explanation:
The width of the outer frame - inner frame
= 8 [tex]\frac{3}{4}[/tex] - 4 = 2x
Hey! I'm not sure what the answer is to this..Mind helping me out?
Answer:
81
Step-by-step explanation:
A perfect square has all side lengths the same so...
9*9=81
Find the median:
3.8, 4.2, 4.0, 4.2, 4.2
Answer:
4.2 is your median
Step-by-step explanation:
just o the math
Answer:
4.0
Step-by-step explanation:
[tex]3.8\: \:)4.2\:\:)4.0(\:\:4.2(\:\:4.2[/tex]
Median is the middle number in a given set of data .
Help pls i need help !!
Answer:
Ray, Line, Transversal?, Plane, Segment
Step-by-step explanation:
What is 8c-4-2c+5= simplified
Answer:
6c+1Step-by-step explanation:
[tex]8c-4-2c+5\\\\\mathrm{Group\:like\:terms}\\=8c-2c-4+5\\\\\mathrm{Add\:similar\:elements:}\:8c-2c=6c\\=6c-4+5\\\\\mathrm{Add/Subtract\:the\:numbers:}\:-4+5=1\\=6c+1[/tex]
find the value of x if h is the midpoint of gj, gj equals 4x-6, and gh=27 - huryyyyyyy please.
Answer: X=15
Step-by-step explanation:
GH+HJ= GJ
27+27=4x-6
54=4x-6
60=4x
15=x
Use the fraction bar interactive to find the difference: One-third minus StartFraction 5 over 6 EndFraction
Answer:
-1/2
Step-by-step explanation:
Answer:
common denominator
6
1/3 - 5/6 difference
-1/2
Step-by-step explanation:
hope I wasn't to late
have a good day guys
:)
I’m order of greatest to least with the numbers .875,.6,.5&.8 would it be .875,.8.6&.5
Answer:
Yes!
Step-by-step explanation:
Answer:
Yes Of course.This always confuses but you are correctIf you need further explanation, don't hesitate to ask mePlease, I need a BrainliestBased on the above table, which occupation listed is projected to have the greatest total number of jobs in 2016? a. Network systems and data communications analysts b. Personal and home care aides c. Home health aides d. Personal finance advisors
Answer:
c. home health aide
Step-by-step explanation:
Answer:
its C, home health aids
Step-by-step explanation:
Evaluate the expression when x=-3.
x^2+5x=-4
[tex](-3)^{2} + 5(-3) = - 4\\9 - 15 = - 4\\-6 \neq -4[/tex]
This is not possible, as -6 is not equal to -4.
( 1.03 x 10^9 ) - ( 4.7 x 10^7 )
Answer:
983000000
Step-by-step explanation:
The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. If Shawn knows that the slope of the line is 4 and the line passes through the point (1,-8), which equation should he use to find the y-intercept and what is the y-intercept of the line? Choices are as follows: b = y + mx b = y - mx b = [tex]\frac{y-m}{x}[/tex] b = -12 b = -4 b = 2
Answer:
b=y-mx
Step-by-step explanation:
We know that y=mx+b is the slope intercept form of a line and we know that the slope of the line is 4. So:y = 4x+bHowever, we need to find the y intercept of the line which is b. Using the point (1,-8), we can find the y intercept. We need to find the equation to find the y-intercept. So:y = mx+b b=y-mxAnd now, we can substitute 4 for m which is the slopeb=y-4xUsing the point (1,-8) we can find the y-intercept b=(-8)-4(1)b=-8-4b=-12the equation of the line is y = 4x - 12 with the slope being 4 and y-intercept is -12. The equation we used is b = y-mx
In a classroom, there are 12 boys and 6 girls. The teacher needs one student to take a note to the
office. What is the probability the teacher randomly picks a girl? Write your answer as a reduced fractior
Answer:
1/3
Step-by-step explanation:
There are 12 boys and 6 girls, meaning there are 18 students. The girls are 1/3 out of those 18.
15 metres cloth cost Rs 240, if the
price is decreased by 20 %. What will
be the cost of 20 metres cloth?
Answer:
$256
Step-by-step explanation:
240/100*20=48 so then 15m of cloth is $192. To get too 20m you can divide 15 by 3 and then times it by 4. 192/3*4=256. Therefore for 20 metres of cloth it is $256. YAY
Answer:
256
Step-by-step explanation:
What is 8.6x10to the -5 power in standard form
Answer:
0.000086
Explantion :
Just move the decimal point 5 to the left.
Points A, B, and C are collinear. Point B is the midpoint of AC. AB=12x-398. BC=22.
Solve for x. *
Answer:
x = 35Step-by-step explanation:
Collinear points A, B, and C and point B being midpoint of AC means:
AB = BC
12x - 398 = 22
+ 398 + 398
12x = 420
÷12 ÷12
x = 35
solve inequality and show work please
Alex's wardrobe is 2 yards tall. How tall is the wardrobe in feet?
feet
what is cross products
Simplify the following: (-83)2
What is 5000000+2000
Answer:
Step-by-step explanation:
5000000
+ 2000
5002000 (Answer)
Please help me to prove this!
Answer: see proof below
Step-by-step explanation:
Given: A + B + C = π → A = π - (B + C)
→ B + C = π - A
Use the Pythagorean Identity: cos² A + sin² A = 1 → sin² A = 1 - cos² A
Use Double Angle Identities: cos 2A = 2 cos² A - 1 → cos² A = (cos 2A + 1)/2
→ cos A = 1 - 2 sin² (A/2)
Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]
Use Cofunction Identities: cos (π/2 - A) = sin (A)
sin (π/2 - A) = cos A
cos (-A) = cos (A)
Proof LHS → RHS:
[tex]\text{LHS:}\qquad \qquad \sin^2\bigg(\dfrac{B}{2}\bigg)+\sin^2 \bigg(\dfrac{C}{2}\bigg)-\sin^2\bigg(\dfrac{A}{2}\bigg)[/tex]
[tex]\text{Pythagorean:}\qquad 1-\cos^2 \bigg(\dfrac{B}{2}\bigg)+1-\cos^2 \bigg(\dfrac{C}{2}\bigg)-\bigg[1-\cos^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1-\cos^2 \bigg(\dfrac{B}{2}\bigg)-\cos^2 \bigg(\dfrac{C}{2}\bigg)+\cos^2 \bigg(\dfrac{A}{2}\bigg)[/tex]
[tex]\text{Double Angle:}\quad 1-\bigg(\dfrac{\cos(2\cdot \frac{B}{2})+1}{2}\bigg)-\bigg(\dfrac{\cos (2\cdot \frac{C}{2})+1}{2}\bigg)+\bigg(\dfrac{\cos (2\cdot \frac{A}{2})+1}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1-\dfrac{\cos B}{2}-\dfrac{1}{2}-\dfrac{\cos C}{2}-\dfrac{1}{2}+\dfrac{\cos A}{2}+\dfrac{1}{2}\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}[1-(\cos B+\cos C)+\cos A][/tex]
[tex]\text{Sum to Product:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\cos \bigg(\dfrac{B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]
[tex]\text{Given:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\cos \bigg(\dfrac{\pi -A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]
[tex]\text{Cofunction:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]
[tex]\text{Double Angle:}\qquad \dfrac{1}{2}\bigg[1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)+1-2\sin^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg[2-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)-2\sin^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1-\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin^2 \bigg(\dfrac{A}{2}\bigg)[/tex]
[tex]\text{Factor:}\qquad \qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin \bigg(\dfrac{A}{2}\bigg)\bigg][/tex]
[tex]\text{Given:}\qquad \qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin \bigg(\dfrac{\pi -(B+C)}{2}\bigg)\bigg][/tex]
[tex]\text{Cofunction:}\qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)+\cos \bigg(\dfrac{B+C}{2}\bigg)\bigg][/tex]
[tex]\text{Sum to Product:}\ 1-\sin \bigg(\dfrac{A}{2}\bigg)\cdot 2 \cos \bigg(\dfrac{(B-C)+(B-C)}{2\cdot 2}\bigg)\cdot \cos \bigg(\dfrac{(B-C)-(B+C)}{2\cdot 2}\bigg)\\\\\\.\qquad \qquad \qquad =1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(-\dfrac{C}{2}\bigg)[/tex][tex]\text{Cofunction:}\qquad =1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)[/tex]
[tex]\text{LHS = RHS:}\quad \checkmark\\\\\quad 1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)=1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)\quad[/tex]