Jerry is counting his shirts. he notices that for every 5 black t-shirts in his drawer he has two red t-shirts. if he owns 28 t-shirts how many black t-shirts does jerry own?

Answer:

2x

Step-by-step explanation:

The width of the outer frame - inner frame

= 8 [tex]\frac{3}{4}[/tex] - 4 = 2x

Answer:

Step-by-step explanation:

5000000

+ 2000

5002000 (Answer)

Answer:

-1/2

Step-by-step explanation:

Answer:

common denominator

6

1/3 - 5/6 difference

-1/2

Step-by-step explanation:

hope I wasn't to late

have a good day guys

:)

Answer:

$256

Step-by-step explanation:

240/100*20=48 so then 15m of cloth is $192. To get too 20m you can divide 15 by 3 and then times it by 4. 192/3*4=256. Therefore for 20 metres of cloth it is $256. YAY

Answer:

256

Step-by-step explanation:

Answer:

983000000

Step-by-step explanation:

Answer: angle 1 and 3 measure 29 degrees.

angle 2 and 4 measure 151 degrees.

Step-by-step explanation:

Answer:

c. home health aide

Step-by-step explanation:

Answer:

its C, home health aids

Step-by-step explanation:

Answer:

L =80

w=60

Step-by-step explanation:

P =280

L =w +20

=>L +w=280 :2 =140

w+20+w=140

2w=140 - 20

2w =120

w=120 :2 =60

L=60 +20 =80

P =2L +2w

P =2 ×80 +2 ×60

P=160 +120

P=280

Answer:

L = 80    ,   w=60

Step-by-step explanation:

l= w+20

perimeter: l+w+l+w=280

Plug in the value of L in place of L

(w+20)+w+(w+20)+w=280

Combine Like terms

and then separate the variables and knowns by subracting 40 from both sides

4w+40=280

     -40   -40

Divide by 4 from both sides so (W) would be alone

4w=240

÷4     ÷4

You solved half the question now

               w = 60

Remember the L at the top

we now know the value of W

so

L=(60)+20

L=80

just to be sure

80+80+60+60=280

you are welcome

Answer:

0.000086

Explantion :

Just move the decimal point 5 to the left.

Answer:

x = 1/3

Step-by-step explanation:

Answer:

27.5 is the answer good luck

Step-by-step explanation:

good luck my G

Answer:

Ray, Line, Transversal?, Plane, Segment

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]8c-4-2c+5\\\\\mathrm{Group\:like\:terms}\\=8c-2c-4+5\\\\\mathrm{Add\:similar\:elements:}\:8c-2c=6c\\=6c-4+5\\\\\mathrm{Add/Subtract\:the\:numbers:}\:-4+5=1\\=6c+1[/tex]

Answer:

-6

Step-by-step explanation:

a-2b

-2-2(2)

-2-4

-6

Answer: X=15

Step-by-step explanation:

GH+HJ= GJ

27+27=4x-6

54=4x-6

60=4x

15=x

Answer:

4.2 is your median

Step-by-step explanation:

just o the math

Answer:

4.0

Step-by-step explanation:

[tex]3.8\: \:)4.2\:\:)4.0(\:\:4.2(\:\:4.2[/tex]

Median is the middle number in a given set of data .

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                     →  A = π - (B + C)

                                                     → B + C = π - A

Use the Pythagorean Identity: cos² A + sin² A = 1   →  sin² A = 1 - cos² A

Use Double Angle Identities: cos 2A = 2 cos² A - 1 → cos² A = (cos 2A + 1)/2

                                             → cos A = 1 - 2 sin² (A/2)    

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use Cofunction Identities:  cos (π/2 - A) = sin (A)

                                             sin (π/2 - A) = cos A

                                             cos (-A) = cos (A)

Proof LHS → RHS:

[tex]\text{LHS:}\qquad \qquad \sin^2\bigg(\dfrac{B}{2}\bigg)+\sin^2 \bigg(\dfrac{C}{2}\bigg)-\sin^2\bigg(\dfrac{A}{2}\bigg)[/tex]

[tex]\text{Pythagorean:}\qquad 1-\cos^2 \bigg(\dfrac{B}{2}\bigg)+1-\cos^2 \bigg(\dfrac{C}{2}\bigg)-\bigg[1-\cos^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1-\cos^2 \bigg(\dfrac{B}{2}\bigg)-\cos^2 \bigg(\dfrac{C}{2}\bigg)+\cos^2 \bigg(\dfrac{A}{2}\bigg)[/tex]

[tex]\text{Double Angle:}\quad 1-\bigg(\dfrac{\cos(2\cdot \frac{B}{2})+1}{2}\bigg)-\bigg(\dfrac{\cos (2\cdot \frac{C}{2})+1}{2}\bigg)+\bigg(\dfrac{\cos (2\cdot \frac{A}{2})+1}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1-\dfrac{\cos B}{2}-\dfrac{1}{2}-\dfrac{\cos C}{2}-\dfrac{1}{2}+\dfrac{\cos A}{2}+\dfrac{1}{2}\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}[1-(\cos B+\cos C)+\cos A][/tex]

[tex]\text{Sum to Product:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\cos \bigg(\dfrac{B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]

[tex]\text{Given:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\cos \bigg(\dfrac{\pi -A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]

[tex]\text{Cofunction:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]    

[tex]\text{Double Angle:}\qquad \dfrac{1}{2}\bigg[1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)+1-2\sin^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg[2-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)-2\sin^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1-\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin^2 \bigg(\dfrac{A}{2}\bigg)[/tex]

[tex]\text{Factor:}\qquad \qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin \bigg(\dfrac{A}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad \qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin \bigg(\dfrac{\pi -(B+C)}{2}\bigg)\bigg][/tex]

[tex]\text{Cofunction:}\qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)+\cos \bigg(\dfrac{B+C}{2}\bigg)\bigg][/tex]

[tex]\text{Sum to Product:}\ 1-\sin \bigg(\dfrac{A}{2}\bigg)\cdot 2 \cos \bigg(\dfrac{(B-C)+(B-C)}{2\cdot 2}\bigg)\cdot \cos \bigg(\dfrac{(B-C)-(B+C)}{2\cdot 2}\bigg)\\\\\\.\qquad \qquad \qquad =1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(-\dfrac{C}{2}\bigg)[/tex][tex]\text{Cofunction:}\qquad =1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{LHS = RHS:}\quad \checkmark\\\\\quad 1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)=1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)\quad[/tex]

Answer:

1/3

Step-by-step explanation:

There are 12 boys and 6 girls, meaning there are 18 students. The girls are 1/3 out of those 18.

Answer:

81

Step-by-step explanation:

A perfect square has all side lengths the same so...

9*9=81

[tex](-3)^{2} + 5(-3) = - 4\\9 - 15 = - 4\\-6 \neq -4[/tex]

This is not possible, as -6 is not equal to -4.

Answer:

Yes!

Step-by-step explanation:

Answer:

Answer:

b=y-mx

Step-by-step explanation:

the equation of the line is y = 4x - 12 with the slope being 4 and y-intercept is -12. The equation we used is b = y-mx

Answer:

Step-by-step explanation:

Collinear points A, B, and C and point B being midpoint of AC means:

AB = BC

12x - 398  =  22

   + 398      + 398

 12x = 420

  ÷12    ÷12  

    x = 35

Answer:

(n)*(x+y)(x-y)

Step-by-step explanation:

First of all, you take the n out, and then you use the formula of x²- y² and it will equal to (x+y)(x-y).

Answer:

n(x+y)(x−y)

Step-by-step explanation:

1. To factor this equation, first, you can see that both the x^2 and the y^2 have an n next to them.  So, you can take out the n.  You get this: n(x^2-y^2)

2. After you take the n out, you can also factor the (x^2-y^2) since they are both squared (to the second power).  To do this, you simply split the two apart and make sure to include the negative.  You get this, the final answer:

n(x+y)(x-y)

3. You can check it by multiplying out the answer, and once multiplied out, you get the original expression of x^2n-y^2n.

Hope this helped!  Feel free to ask any questions :)

this is what I found hope its correct!‍♀️