Jaden has $6,000.00 to invest for 2 years. The table shows information about two investments Jaden can make. Investments Investment Rate Type of Interest X 4.5% Y 4% Simple Compound Jaden makes no additional deposits or withdrawals. Which investment earns the greater amount of interest over a period of 2 years? What amount of interest?​

Answers

Answer 1
For Investment X, the interest rate is 4.5%, which is a compound interest. For Investment Y, the interest rate is 4%, which is a simple interest.

To calculate the amount of interest Jaden will earn over two years, we will use the following formulas:

For Investment X: A = P(1 + r/n)^(nt), where A is the total amount, P is the principal amount, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time in years.

For Investment Y: I = P*r*t, where I is the interest earned, P is the principal amount, r is the annual interest rate, and t is the time in years.

Using these formulas, we can calculate the amount of interest earned for each investment:

For Investment X: A = 6000(1 + 0.045/12)^(12*2) = $6,566.34 (rounded to the nearest cent)

Interest earned = $6,566.34 - $6,000 = $566.34

For Investment Y: I = 6000 * 0.04 * 2 = $480

Therefore, Investment X earns the greater amount of interest over a period of 2 years, which is $566.34.

Related Questions

solve the separable differential equation dy/dx = x2 1/25, and find the particular solution satisfying the initial condition x(0) = 7

Answers

The particular solution is: y = e^(1/75 x^3 + ln(7)) or equivalently: y = 7e^(1/75 x^3) This is the solution to the separable differential equation dy/dx = x^2/25 that satisfies the initial condition x(0) = 7.

the separable differential equation and find the particular solution.

First, let's rewrite the given equation as a separable equation:
dy/dx = x^2/25

To separate the variables, divide both sides by x^2 and multiply by dx:
(1/x^2) dx = (1/25) dy

Now, integrate both sides with respect to their respective variables:
∫(1/x^2) dx = ∫(1/25) dy

The integrals are:
-1/x = y/25 + C

To find the particular solution satisfying the initial condition x(0) = 7, we need to correct the initial condition, as x(0) should be in the form of y(0) for it to be relevant to our equation. Assuming the correct initial condition is y(7) = 0, let's plug in the values for x and y:

-1/7 = 0/25 + C

Solve for C:
C = -1/7

Now, plug C back into the equation to get the particular solution:
-1/x = y/25 - 1/7

This is the particular solution to the given separable differential equation with the initial condition y(7) = 0.

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Find the tangent plane to the surface z = 1+y 1+2 at the point P (1,3,2). Type in the equation of the plane with the accuracy of at least 2 significant figures for each coefficient. 2=( ) x + c Dy to D

Answers

The equation of the tangent plane to the surface z = 1 + y at the point P(1, 3, 2) is z = y - 1 with coefficients accurate to at least 2 significant figures.

To find the tangent plane to the surface z = 1 + y at the point P(1, 3, 2), we need to calculate the partial derivatives with respect to x and y, and then use the equation of the plane.

Step 1: Find the partial derivatives.
∂z/∂x = 0 (since there's no x term in the equation)
∂z/∂y = 1 (the coefficient of y is 1)

Step 2: Use the point-slope form of the equation of the plane.
z - z0 = (∂z/∂x)(x - x0) + (∂z/∂y)(y - y0)

Step 3: Substitute the point P(1, 3, 2) and the partial derivatives into the equation.
z - 2 = (0)(x - 1) + (1)(y - 3)

Step 4: Simplify the equation.
z - 2 = y - 3

Step 5: Rearrange the equation to find the equation of the tangent plane.
z = y - 1

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how to calculate sum of squared residuals from sst and sse

Answers

The SSR can be calculated as:

SSR = SST - SSE

How to determine the SSR?

The linear regression analysis i.e., sum of squared residuals (SSR) can be calculated as the difference between the total sum of squares (SST) and the explained sum of squares (SSE).

SST represents the total variation in the data and is calculated as the sum of the squared differences between each data point and the mean of the data:

SST = ∑([tex]yi[/tex] - ȳ)²

where [tex]yi[/tex] is the [tex]i-th[/tex] data point and ȳ is the mean of the data.

SSE represents the variation in the data that is explained by the model and is calculated as the sum of the squared differences between each predicted value and the actual value:

SSE = ∑(yi - ŷi)²

where yi is the i-th actual data point and ŷi is the i-th predicted value from the model.

Then, the SSR can be calculated as:

SSR = SST - SSE

This represents the unexplained variation in the data that is not accounted for by the model.

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Mr. Stevenson wants to cover the patio with concrete sealer. What is the area he will need to cover with concrete sealer? Find the approximation using 3.14

Answers

Mr. Stevenson will need to cover approximately 314 square feet of the patio with concrete sealer.

How to solve

To calculate the area of a circle, we can use the formula:

Area = π * r^2

where π (pi) is around 3.14, and r is the radius of the circle. In this example, the radius is 10 feet.

Area = 3.14 * (10 ft)^2

Area = 3.14 * 100 sq ft

Area ≈ 314 sq ft

So, Mr. Stevenson will need to cover approximately 314 square feet of the patio with concrete sealer.

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What is the area of a circular patio with a radius of 10 feet, using the approximation of pi as 3.14?

A 1:3 scale model of a torpedo is tested in a wind tunnel to determine the drag force. The prototype operates in water, has 533 mm diameter, and is 6.7 m long. The desired operating speed of the prototype is 28 m/s. To avoid compressibility effects in the wind tunnel, the maximum speed is limited to 110 m/s. However, the pressure in the wind tunnel can be varied while holding the temperature constant at 20 C. At what minimum pressure should the wind tunnel be operated to achieve a dynamically similar test? At dynamically similar test conditions, the drag force on the model is measure at 618 N. Evaluate the drag force expected on the full-scale torpedo.

Answers

The wind tunnel should be operated at a pressure that results in an air density of 0.068 kg/m³ to achieve dynamically similar test conditions. The expected drag force on the full-scale torpedo is 7535 N.

To achieve dynamically similar test conditions, the Reynolds number of the model in the wind tunnel should be the same as the Reynolds number of the prototype in water. The Reynolds number is given by:

Re = (ρvL)/μ

where ρ is the density of the fluid (air or water), v is the velocity, L is a characteristic length (diameter for the torpedo), and μ is the dynamic viscosity of the fluid.

For the prototype in water:

ρ = 1000 kg/m³

v = 28 m/s

L = 6.7 m

μ = 0.001 Pa·s (for water at 20°C)

Re = (1000 kg/m³ × 28 m/s × 6.7 m) / 0.001 Pa·s

Re = 1.876 × 10^8

For the model in the wind tunnel:

v = 110 m/s (maximum speed in wind tunnel)

L = 1/3 × 6.7 m = 2.233 m (scaled length)

μ = 0.0000183 Pa·s (for air at 20°C)

We can solve for the density of air required to achieve the same Reynolds number as the prototype:

ρ = (μRe)/(vL)

ρ = (0.0000183 Pa·s × 1.876 × 10^8) / (110 m/s × 2.233 m)

ρ = 0.068 kg/m³

Therefore, the wind tunnel should be operated at a pressure that results in an air density of 0.068 kg/m³ to achieve dynamically similar test conditions.

To find the drag force on the full-scale torpedo, we can use the drag coefficient of the model in the wind tunnel, assuming it is the same as the full-scale prototype. The drag force is given by:

Fd = 1/2 ρ v² Cd A

where Cd is the drag coefficient and A is the cross-sectional area of the torpedo.

For the model in the wind tunnel:

ρ = 0.068 kg/m³

v = 28 m/s (prototype operating speed)

Cd = (measured drag force on model) / (1/2 ρ v² A)

Cd = 618 N / (1/2 × 0.068 kg/m³ × 28 m/s² × π(533/2 mm)²)

Cd = 0.00744

For the full-scale prototype:

ρ = 1000 kg/m³

v = 28 m/s

A = π(533 mm/2)²

Fd = 1/2 × 1000 kg/m³ × 28 m/s² × 0.00744 × π(533/2 mm)²

Fd = 7535 N

Therefore, the expected drag force on the full-scale torpedo is 7535 N.

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Wazin's parents invested $1500 in a mutual fund for his college that compounded
quarterly in 2006. How much money did he have in his colloge account in 2026 if the
rate was 7%?

Answers

Answer:

$6133.19

Step-by-step explanation:

We can use the formula for compound interest to find the amount of money in Wazin's college account in 2026:

A = P(1 + r/n)^(nt)

where A is the amount of money in the account, P is the principal (initial investment), r is the interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time (in years).

In this case, P = $1500, r = 0.07, n = 4 (since the interest is compounded quarterly), and t = 20 (since 2026 is 20 years after 2006). Substituting these values, we get:

A = 1500(1 + 0.07/4)^(4*20) = $6133.19

Therefore, Wazin's college account will have approximately $6133.19 in 2026.

Hope this helps!

Answer:

Step-by-step explanation:

Principal amount, P= $1500 Rate of interest, r = 7%

what is the volume of the rectangular prism shown below?

Answers

The volume of the rectangular prism is 12 3/4 cubic feet. Option C

How to determine the volume

The formula that is used to calculate the volume of a rectangular prism is expressed as;

V = lwh

Such that the parameters are;

V is the volume of the prism.l is the length of the prism.h is the height of the prismw is the width of the prism.

From the information given, we have;

Length = 2 ft

Width = 3/2 feet

height = 17/4 feet

Substitute the values

Volume = 2 × 3/2 × 17/4

volume = 102/8

Volume = 12 3/4 cubic feet

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Find the length of arc AB.

Answers

Answer:

AB ≈ 12.6

Step-by-step explanation:

the length of arc AB is calculated as

AB = circumference of circle × fraction of circle

     = 2πr × [tex]\frac{45}{360}[/tex] ( r is the radius )

    = 2π × 16 × [tex]\frac{1}{8}[/tex]

    = 32π × [tex]\frac{1}{8}[/tex] ( cancel 8 and 32 by 8 )

   = 4π

  ≈ 12.6 ( to the nearest tenth )

Help on c pls it was due like 40 mins ago I’m already in loads of trouble love you lots xxxxx

Answers

Answer:

  1.33×10²⁷ kg

Step-by-step explanation:

You want the difference in masses of Jupiter and Saturn in standard form.

Difference

The difference of numbers in scientific notation is best found by expressing each number with the same exponent of 10. Here, that difference is ...

  [tex]1.898\times10^{27}-5.68\times10^{26}\\\\=1.898\times10^{27}-0.568\times10^{27}\\\\=(1.898-0.568)\times10^{27}=\boxed{1.33\times10^{27}}[/tex]

__

Additional comment

In the US, "standard form" is the "ordinary number". It will have a total of 28 digits.

1,330,000,000,000,000,000,000,000,000

Your calculator can find the difference for you, and express it in whatever form you want.

When would you use the t-distribution procedure to find the confidence interval for the population mean?
Select one:
a. When you do not know the standard deviation of a normally distributed population.
b. When the only thing that you know about a population is its size.
c. When you are working with a population that does not have a normal distribution.
d. Only when you have the standard deviation and the mean of a normally distributed population

Answers

Your answer: a. When you do not know the standard deviation of a normally distributed population.

a. When you do not know the standard deviation of a normally distributed population, you would use the t-distribution procedure to find the confidence interval for the population mean. This is because the t-distribution allows for the estimation of the population standard deviation based on the sample standard deviation.

In statistics, the standard deviation is a measure of the variability or spread of an outcome. [1] A low standard deviation indicates that the value is close to the mean of the cluster (also called the expected value), while a high standard deviation indicates that the results are very interesting.

The standard deviation of can be abbreviated as SD and is often used in mathematics and equations with the Greek letter σ (sigma) for population standard deviation or the Latin letter s for different sample sizes.

The standard deviation of a variable, such as a population, a data set, or a probability, is the basis of its variance. Algebraically it is easier than the mean absolute difference, but in practice, it means a lower absolute difference. The useful feature of standard deviation is that it is expressed in the same unit as the data, not the difference.

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True or false every sequence is either arithmetic or geometric. If this is true, explain. If false, give a counter example to illustrate 

Answers

Answer:

This is false as you can have triangular sequences.

Consider the Boolean functionf=Σ(2,6,8,9,10,12,14,15)

Draw the K-map, and then find all prime implicants.
Based on this K-map determine all minimal forms of f.

Answers

The minimal forms of the Boolean function f=Σ(2,6,8,9,10,12,14,15) are f = A'C + AB' + BC.

To find the minimal forms, follow these steps:

1. Draw a 4-variable Karnaugh map (K-map) with the variables A, B, C, and D.


2. Place 1s in the K-map for each minterm (2,6,8,9,10,12,14,15) and 0s for the remaining cells.


3. Identify prime implicants by grouping 1s in the largest possible power-of-two rectangular groups (1, 2, 4, or 8 cells) with wraparound allowed. The groups must be row- or column-wise adjacent.


4. Determine essential prime implicants by finding groups that contain at least one 1 that is not part of any other group.


5. Combine the essential prime implicants and any additional non-essential prime implicants needed to cover all 1s in the K-map to form the minimal Boolean expressions.

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Alex painted 178 ft2 of his apartment’s walls with one-third gallon of paint. He has 2 gallons of paint in all. If he wants to cover 1,000 ft2 of his apartment, does he have enough paint? Complete a true statement.

Answers

Answer:

One-third gallon of paint covers 178 ft2 of walls, so 2 gallons of paint will cover:

2 gallons * (178 ft2 / one-third gallon) = 11,880 ft2

Since Alex wants to cover 1,000 ft2, we can write the following statement:

1,000 ft2 ≤ 11,880 ft2

This statement is true, so Alex has enough paint to cover his apartment

2 gallons of paint will cover [ 1,068 ] ft, and Alex will needs to cover 1,000 ft, so he [ will ] have enough paint

Based on a survey of 120 of the 1,352 households in a local town, a marketing firm determined that the average number of computers in a household is 2.42 with a margin of error of (plus minus sign)(see in pic) +- 0.4. What is a reasonable estimate of the number of computers owned by residents in the town?






PLEASE HURYY tyyy

Answers

Based on the survey results, a reasonable estimate of the number of computers owned by residents in the town is between 2.02 (2.42 - 0.4) and 2.82 (2.42 + 0.4). The margin of error of ±0.4 indicates that the estimate is likely to be within this range.

Sure! So, the survey of 120 households in the town found that the average number of computers in a household was 2.42. However, because this was a sample survey and not a complete census of all households in the town, there is some level of uncertainty in the estimate.

The margin of error of +-0.4 means that we can be 95% confident interval that the true average number of computers in households in the town falls within the range of 2.02 (2.42 - 0.4) and 2.82 (2.42 + 0.4).

So, a reasonable estimate of the number of computers owned by residents in the town would be around 2.42, but with a range of 2.02 to 2.82.

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The time it takes a person to complete a phone call, X, is exponentially distributed with expected value μ= 3 minutes.
IF 5 persons are chosen and the time it takes them to complete a phone call is observed, what is the probability that they all take more than 1 minute? question Select one: a. 0.77464 b. 0.1888 c. 0.03577 d. 0.6

Answers

The probability that all 5 persons take more than 1 minute is 0.1888.

The probability that one person takes more than 1 minute to complete a phone call is given by:

[tex]P(X > 1) = e^(-1/3)[/tex]

So, the probability that all 5 persons take more than 1 minute is:

P(X1 > 1 and X2 > 1 and X3 > 1 and X4 > 1 and X5 > 1) = P(X > 1)^5

Substituting the value of P(X > 1), we get:

P(X1 > 1 and X2 > 1 and X3 > 1 and X4 > 1 and X5 > 1) = (e^(-1/3))^5

Simplifying, we get:

P(X1 > 1 and X2 > 1 and X3 > 1 and X4 > 1 and X5 > 1) = e^(-5/3)

Using a calculator, we get:

P(X1 > 1 and X2 > 1 and X3 > 1 and X4 > 1 and X5 > 1) ≈ 0.03577

Therefore, the answer is c. 0.03577.
To answer your question, we will use the exponential distribution and its properties.

Given the expected value μ = 3 minutes, we can find the parameter λ by using the formula μ = 1/λ. Thus, λ = 1/3 per minute.

Now, we need to find the probability that a single person takes more than 1 minute to complete a phone call. This is equivalent to finding the probability P(X > 1). We can use the cumulative distribution function (CDF) of the exponential distribution for this purpose: P(X > x) = 1 - P(X ≤ x) = [tex]1 - (1 - e^(-λx)).[/tex]

Plugging in λ = 1/3 and x = 1, we get:

P(X > 1) = 1 - (1 - e^(-1/3)) ≈ 0.71653.

Since the phone calls are independent events, the probability that all 5 persons take more than 1 minute is:

P(All > 1) = [tex](0.71653)^5[/tex] ≈ 0.1888.

So, the correct answer is option b. 0.1888.

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

Rolinda’s first five Spanish test scores are 85, 85, 60, 62, and 59.

a. Find the mean, the median, and the mode of Rolinda’s Spanish test scores. Round your answers to the nearest tenth, if necessary.

b. Which of these measures best supports Rolinda’s claim that she is doing well in her Spanish class?

c. Why is Rolinda’s claim misleading?

Answers

If Rolinda’s first five Spanish test scores are 85, 85, 60, 62, and 59.

a. The mean is 70.2, media is 62.

b. The mean is the measure that best  support Rolinda’s claim

c. Rolinda's claim misleading since the two high scores of 85 inflate her mean score of 70.2.

What is the mean?

a. Mean

Mean = (85 + 85 + 60 + 62 + 59) / 5

Mean = 70.2

We must first rank the scores from lowest to highest in order to find the median:

59, 60, 62, 85, 85

So.

Median score is 62

We search for the score that shows up most frequently to determine the mode. Two scores 85 appear twice in this instance while the other scores only appear once. Based on this the group of scores does not have a special mode.

b. The mean is the measure that best  support Rolinda’s claim based on the fact that the mean includes all the scores and is influenced by both the high and low scores.

c. Rolinda's claim misleading since the two high scores of 85 inflate her mean score of 70.2.

Therefore the mean is 70.2.

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for a normal distribution, what z-score separates the top 5% from the remainder of the distribution?
a. 1.50
b. 1.65
c. 1.70
d. 1.80

Answers

The final answer is (b), a z-score of 1.645 separates the top 5% from the remainder of the distribution in a normal distribution.

The z-score that separates the top 5% from the remainder of the distribution is found by looking up the area in the standard normal distribution table.

The normal distribution is a continuous probability distribution that is commonly used in statistical analysis. It is a symmetric bell-shaped curve that describes a large number of natural phenomena, such as human heights, test scores, and measurements of physical phenomena. The distribution is characterized by its mean and standard deviation.

The area in the tail of the distribution is 0.05, which corresponds to a z-score of approximately 1.645.

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Estimate ∫10cos(x2)dx∫01cos using (a) the Trapezoidal Rule and (b) the Midpoint Rule, each with n=4. Give each answer correct to five decimal places.
(a) T4=
(b) M4=
(c) By looking at a sketch of the graph of the integrand, determine for each estimate whether it overestimates, underestimates, or is the exact area.
Underestimate Overestimate Exact 1. M4
Underestimate Overestimate Exact 2. T4
(d) What can you conclude about the true value of the integral?
A. T4<∫10cos(x2)dx B. T4>∫10cos(x2)dxand M4>∫10cos(x2)dx
C. M4<∫10cos(x2)dx D. No conclusions can be drawn.
E. T4<∫10cos(x2)dx and M4<∫10cos(x2)dx

Answers

a)Using the Trapezoidal Rule with n=4: T4 = 1.06450

b)Using the Midpoint Rule with n=4: M4 = 1.14750

c)M4 overestimates the area while T4 underestimates the area

d) The true value of the integral is T4<∫10cos(x2)dx and M4<∫10cos(x2)dx

What is Trapezoidal Rule?

The Trapezoidal Rule is a numerical integration method that approximates the area under a curve by approximating it with a series of trapezoids and summing their areas.

According to the given information:

(a) Using the Trapezoidal Rule with n=4:

Δx = (1-0)/4 = 0.25

f(0) = cos(0) = 1

f(0.25) = cos(0.0625) ≈ 0.998

f(0.5) = cos(0.25) ≈ 0.968

f(0.75) = cos(0.5625) ≈ 0.829

f(1) = cos(1) ≈ 0.540

T4 = Δx/2 * [f(0) + 2f(0.25) + 2f(0.5) + 2f(0.75) + f(1)]

≈ 0.25/2 * [1 + 2(0.998) + 2(0.968) + 2(0.829) + 0.540]

≈ 1.06450

(b) Using the Midpoint Rule with n=4:

Δx = (1-0)/4 = 0.25

x1 = 0 + Δx/2 = 0.125

x2 = 0.125 + Δx = 0.375

x3 = 0.375 + Δx = 0.625

x4 = 0.625 + Δx = 0.875

f(x1) = cos(0.015625) ≈ 0.999

f(x2) = cos(0.140625) ≈ 0.985

f(x3) = cos(0.390625) ≈ 0.921

f(x4) = cos(0.765625) ≈ 0.685

M4 = Δx * [f(x1) + f(x2) + f(x3) + f(x4)]

≈ 0.25 * [0.999 + 0.985 + 0.921 + 0.685]

≈ 1.14750

(c) Looking at a sketch of the graph of the integrand, it appears that the function is decreasing on the interval [0,1], so the area under the curve should be decreasing. The Midpoint Rule tends to overestimate the area under a decreasing curve, while the Trapezoidal Rule tends to underestimate it. Therefore, the answers are:

M4 overestimates the area

T4 underestimates the area

(d) We can conclude that the true value of the integral is between the estimates given by the Trapezoidal Rule and the Midpoint Rule, since the Trapezoidal Rule underestimates and the Midpoint Rule overestimates. Therefore, we can say:

E. T4<∫10cos(x2)dx and M4<∫10cos(x2)dx

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In the interval 0° < x < 360°, find the values of x for which tan x = -0. 4452 Give your answers to the nearest degree

Answers

The solutions to the equation tan x = -0.4452 in the interval 0° < x < 360° are approximately: x ≈ 157° and x ≈ 337° (rounded to the nearest degree)

To find the values of x in the given interval for which tan x = -0.4452, we can use the inverse tangent function (tan^-1) or a calculator with an inverse tangent function.

Using a calculator with an inverse tangent function, we can take the inverse tangent of -0.4452 to get:

tan^-1(-0.4452) ≈ -23.012°

To get the next solution, we can add 180 degrees to -23.012°:

-23.012° + 180° ≈ 156.988°

Therefore, the two solutions in the interval 0° < x < 360° are approximately:

x ≈ -23.012° and x ≈ 156.988°

Since we want our answers in the interval 0° < x < 360°, we can add 360 degrees to the negative solution to get it in the correct range:

x ≈ 360° - 23.012° ≈ 336.988°

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what is the slope of the line?

Answers

Answer: 0

Step-by-step explanation:

The slope of any horizontal line is 0

Evaluate 5c3

Help please and thanks

Answers

The combination expression 5c3 when evaluated has a value of 10

Evaluatong the combination expression 5c3

The notation 5C3 represents the number of ways to choose 3 items from a set of 5 distinct items, without regard to order. This is calculated using the formula:

nCk = n! / (k! * (n-k)!)

where n is the total number of items and k is the number of items to choose.

Using this formula, we have:

5C3 = 5! / (3! * (5-3)!)

= 5! / (3! * 2!)

= (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * (2 * 1))

= 10

Therefore, 5C3 = 10.

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the a priori significance level (alpha) is set at .01; my test statistic has a p-value of .021 what do i do now?
A. Reject null hypothesis
B. Calculate the SEM
C. Accept the alternative hypothesis
D. Fail to reject the null hypothesis

Answers

In this case, the p-value of .021 is greater than the alpha level of .01. Therefore, we fail to reject the null hypothesis. This means that we do not have enough evidence to conclude that the alternative hypothesis is true. The correct answer is D.

When conducting hypothesis testing, the a priori significance level (alpha) is set before the data is analyzed. This level is the threshold for determining whether the test statistic is significant or not. In this case, the alpha is set at .01, meaning that the probability of rejecting the null hypothesis when it is true is 1 in 100.

The test statistic is the calculated value that is used to determine whether the null hypothesis should be rejected or not. In this case, the test statistic has a p-value of .021. The p-value is the probability of obtaining a test statistic as extreme as or more extreme than the observed statistic, assuming the null hypothesis is true.

In other words, it tells us how likely it is that the observed data occurred by chance alone. To determine what to do next, we compare the p-value to the alpha level. If the p-value is less than or equal to the alpha level, then we reject the null hypothesis. If the p-value is greater than the alpha level, then we fail to reject the null hypothesis.

In this case, the p-value of .021 is greater than the alpha level of .01. Therefore, we fail to reject the null hypothesis. This means that we do not have enough evidence to conclude that the alternative hypothesis is true. It is important to note that failing to reject the null hypothesis does not mean that the null hypothesis is true, only that we do not have enough evidence to reject it.

There is no need to calculate the SEM (standard error of the mean) or accept the alternative hypothesis in this scenario. The correct answer is D, fail to reject the null hypothesis.

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what is the probability that z is between -1.54 and 1.89?

Answers

I may or may not be lying. >:^P

Using the standard normal distribution table, we can look up the probability corresponding to a z-score of 1.89 and subtract from it the probability corresponding to a z-score of -1.54, as follows:

P(-1.54 < z < 1.89) = P(z < 1.89) - P(z < -1.54)

Looking up these probabilities in the standard normal distribution table, we find:

P(z < 1.89) = 0.9706

P(z < -1.54) = 0.0621

Substituting these values into the formula, we get:

P(-1.54 < z < 1.89) = 0.9706 - 0.0621 = 0.9085

Therefore, the probability that z is between -1.54 and 1.89 is approximately 0.9085, or 90.85% (rounded to two decimal places).

*IG: whis.sama_ent*

When building a house, the number of days required to build varies inversely with with the number of workers. One house was built in 19 days by 28 workers. How many days would it take to build a similar house with 7 workers?

Answers

The number of days it would take 7 workers to be able to build a similar house would be 76 days.

How to find the number of days ?

Proportionally speaking, more builders means a house will take less time to be built. If the number of workers reduces therefore, the number of days for the house to be built will increase.

We need k which is the constant of proportionality:

k = 19 x 28 = 532

The number of days it would take 7 workers is:

532 = d x 7

d = 532 / 7

= 76 days

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Find the absolute extrema of the function on the closed interval.g(x)=3x²/x-2, [-2,1]Minimum (x,y) = ( ) (smaller x-value,)Minimum (x,y) = ( ) (smaller x-value,)Maximym (x,y) = ( )

Answers

The absolute extrema of the function g(x) = 3x²/(x - 2) on the closed interval [-2, 1] are

a) Minimum: (1, -9)

b) Maximum: (4, 24)

To find the absolute extrema of the function g(x) = 3x²/(x - 2) on the closed interval [-2, 1], we need to evaluate the function at the critical points and endpoints of the interval.

First, we need to find the critical points of the function, which occur when the derivative of g(x) is equal to zero or undefined. We have

g(x) = 3x²/(x - 2)

g'(x) = (6x(x - 2) - 3x²)/ (x - 2)²

g'(x) = (3x(x - 4))/ (x - 2)²

Setting g'(x) equal to zero, we get

3x(x - 4) = 0

x = 0 or x = 4

Note that x = 2 is not in the domain of the function, so it is not a critical point.

Next, we need to evaluate the function at the critical points and endpoints of the interval. We have

g(-2) = 12

g(0) = 0

g(1) = -9

g(4) = 24

Therefore, the absolute maximum of the function on the interval is g(4) = 24, which occurs at x = 4. The absolute minimum of the function on the interval is g(1) = -9, which occurs at x = 1.

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The given question is incomplete, the complete question is:

Find the absolute extrema of the function on the closed interval.g(x)=3x²/x-2, [-2,1].

A cashier at the local bank served for customers in 20 minutes select all the equivalent rates

Answers

The equivalent rates of the cashier are  4 customers/20 minutes and 0.2 customers/minutes

Selecting all the equivalent rates

From the question, we have the following parameters that can be used in our computation:

Served four customers in 20 minutes

This means that

Customers = 4

Time = 20 minutes

So, the rate is

Rate = customers/Time

Substitute the known values in the above equation, so, we have the following representation

Rate = 4 customers/20 minutes

When converted to equivalent rates, we have

Rate = 0.2 customers/minutes

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The pdf of x is f(x) = 0.1, 3 < x < 13. Find P(5 < X < 8).

Answers

The probability of X falling between 5 and 8 is 0.3, and this probability is proportional to the length of the interval.

To find P(5 < X < 8), we need to integrate the probability density function (PDF) of X over the interval [5, 8]. Since the PDF of X is given by f(x) = 0.1, 3 < x < 13, we know that the PDF is zero outside this interval.
Thus, we have:
P(5 < X < 8) = ∫5^8 f(x) dx
= ∫5^8 0.1 dx
= 0.1(x)|5^8
= 0.1(8 - 5)
= 0.3Therefore, the probability that X falls between 5 and 8 is 0.3. This means that if we were to draw a random sample from this distribution, there is a 30% chance that the value of X would fall between 5 and 8.It is important to note that since the PDF of X is constant over the interval [3, 13], the probability of X falling between any two values within this interval is proportional to the length of the interval. For example, the probability of X falling between 3 and 10 would be three times greater than the probability of X falling between 5 and 8, since the former interval is three times as long as the latter.In summary, the probability of X falling between 5 and 8 is 0.3, and this probability is proportional to the length of the interval.

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the cube with 2.00 m wide and 2.00 m long and 2.00 m high has a weight of 900.00 n. what pressure does it exert?

Answers

If the cube with 2.00 m wide and 2.00 m long and 2.00 m high has a weight of 900.00 n, then the cube exerts a pressure of 225 N/m².

To calculate the pressure exerted by the cube, follow these steps:

Step 1: To calculate the pressure exerted by the cube,  you need to consider its weight and the area over which it is exerting the force. The cube has a weight of 900 N and dimensions of 2.00 m x 2.00 m x 2.00 m.

Step 2: To find the pressure, we will use the formula:

Pressure (P) = Force (F) / Area (A)

Step 3: In this case, the force is the weight of the cube (900 N), and the area is the base of the cube (2.00 m x 2.00 m).

A = 2.00 m * 2.00 m = 4.00 m²

Step 4: Now, you can calculate the pressure:

P = 900 N / 4.00 m² = 225 N/m²

So, the cube exerts a pressure of 225 N/m².

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If DOG is 29, BAG is 13, and FEE is 19, then what is DAB? OA. 15 OB. 18 OC. 27 OD. 22 OE. 10 OF. 12

Answers

The answer is 10, which corresponds to option (E).

To solve it, let's first analyze the given terms and find a pattern:

1. DOG = 29
2. BAG = 13
3. FEE = 19

Now, let's convert each letter to its corresponding position in the alphabet:
- D = 4, O = 15, G = 7
- B = 2, A = 1, G = 7
- F = 6, E = 5, E = 5

Next, let's look for a pattern in the sums:
1. 4 + 15 + 7 = 26 → 26 + 3 = 29
2. 2 + 1 + 7 = 10 → 10 + 3 = 13
3. 6 + 5 + 5 = 16 → 16 + 3 = 19

It appears that after summing the positions of each letter, we add 3 to get the final result.
Now, let's find the value for DAB:
- D = 4, A = 1, B = 2
- 4 + 1 + 2 = 7 → 7 + 3 = 10
So, the answer is 10, which corresponds to option (E).

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The Queen City Nursery manufactures bags of potting soil from compost and topsoil. Each cubic foot of compost costs 12 cents and contains 4 pounds of sand, 3 pounds of clay, and 5 pounds of humus. Each cubic foot of topsoil costs 20 cents and contains 3 pounds of sand, 6 pounds of clay, and 12 pounds of humus. Each bag of potting soil must contain at least 12 pounds of sand, at least 12 pounds of clay and at least 10 pounds of humus. Solve the problem and show work, and describe the following: 1. Formulate the problem as a linear programming. 2. Plot the constraints and show the feasible region. 3. Identify the optimal solution. 4. Interpret the optimal solution.

Answers

1. The equations for Sand, Clay, and Humus, we get: x = (12 - 3y)/4, x = (12 - 6y)/5, x = (10 - 12y)/5 2. The feasible region is the shaded region above the line Sand = 3 and to the left of the line Clay = 2.

What is linear programming?

Linear programming is a mathematical method used to optimize a linear objective function subject to linear constraints.

1. Formulating the problem as a linear programming:

Let x and y be the number of cubic feet of compost and topsoil, respectively, used to make one bag of potting soil.

We want to minimize the cost of the potting soil, which is given by:

Cost = 0.12x + 0.2y

We want to ensure that each bag of potting soil contains at least 12 pounds of sand, 12 pounds of clay, and 10 pounds of humus. The amount of each ingredient in one bag of potting soil can be calculated as follows:

Sand = 4x + 3y

Clay = 5x + 6y

Humus = 5x + 12y

We can now formulate the constraints as follows:

Sand ≥ 12

Clay ≥ 12

Humus ≥ 10

Solving for x and y in the equations for Sand, Clay, and Humus, we get:

x = (12 - 3y)/4

x = (12 - 6y)/5

x = (10 - 12y)/5

We also have the non-negativity constraints:

x ≥ 0

y ≥ 0

2. Plotting the constraints and showing the feasible region:

We can graph the constraints by plotting the equations for Sand, Clay, and Humus, and shading the region that satisfies all the constraints. The resulting feasible region is shown below:

The feasible region is the shaded region above the line Sand = 3 and to the left of the line Clay = 2.

3. Identifying the optimal solution:

We can find the optimal solution by finding the point in the feasible region that minimizes the cost of the potting soil. This point occurs where the cost function is minimized.

Cost = 0.12x + 0.2y

Substituting x = (12 - 3y)/4 and x = (12 - 6y)/5, we get:

Cost = 0.12[(12 - 3y)/4] + 0.2y

Cost = 0.12[(12 - 6y)/5] + 0.2y

Simplifying, we get:

Cost = 0.6 - 0.09y

Cost = 0.72 - 0.044y

We can now find the minimum value of Cost by setting its derivative to zero:

dCost/dy = -0.09 + 0.044 = 0

Solving for y, we get:

y = 2

Substituting y = 2 into x = (12 - 3y)/4 and x = (12 - 6y)/5, we get:

x = 3/4

x = 6/5

Therefore, the optimal solution occurs at x = 3/4 and y = 2, and the minimum cost of the potting soil is:

Cost = 0.12x + 0.2y = 0.12(3/4) + 0.2(2) = 0.39 dollars.

4. Interpreting the optimal solution:

The optimal solution indicates that the Queen City Nursery should use 3/4 cubic feet of compost and 2 cubic feet of topsoil to make one bag of potting soil, which will cost 39 cents. This solution satisfies all the constraints and minimizes the cost of the potting soil. The optimal solution also indicates that the potting soil should contain 3 cubic feet of sand, 12 cubic feet of clay, and 11 cubic feet of humus, which satisfies the minimum requirements for each ingredient.

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