It takes 8. 0 seconds for 12 coulombs of charge to flow through a wire. How much current is flowing through it? 0. 67 a 1. 5 a 4. 0 a.

An example of sport where shoes with a high coefficient of friction would be advantageous : rugby. This is played in deep mud and needs a high level of friction so they don't slip, so boots for this condition are big.

Rugby players play in deep mud so they need  a high level of friction so that they do not slip and fall. Therefore, boots for this condition are also big and rounded studs so they stick and sink into the ground and give grip.

In sports, high friction avoids slipping and permits grip of a surface better. This permits faster movements but, if the friction is excessive, overload is produced in joints and injuries may occur.

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Answer:

Below

Explanation:

Usually, position is given by   x(t) =.......

 if x^2 = 3t^2 - 16t+ 8      then

    x = ( 3t^2 - 16t + 8)^1/2            ( I do not think this is what you want....but it IS what was posted)

    Velocity will be given by the derivative :   (3t-8)  / ( 3t^2-16t+ 8)^1/2

       at t = 4   this equals an imaginary number....

                            so I think your question equation is incorrect

The answer above this one used    x(t) = 3t^2-16t+8 as the position function and is likely the correct way to do it

  then velocity = dx/dt = 6t-16      at t = 4 this is 8

            the particle is stationary when this = 0 at t = 16/6 = 2.67 s   (NOT 4s as posted in the other 'verified' answer !!!!!)

   Acceleration = dv/dt = 6    

 at t= 4 the velocity would be 8  units/s    

            and the accel would be 6  units/s^2

  and when v= 0 would occur at t = 2.67 s

The centripetal force that a child with a mass of 45 kg feel when standing 1.0 m from the outer edge of the carousel is 127.9 N.

The centripetal force of the child is the inward force that must maintain the circular motion of the child at the given point in the circular axis without falling.

Mathematically, the formula for centripetal force is given as;

Fc = ma

where;

The centripetal acceleration of the child is calculated as;

a = v²/r

where;

a = (ω²r²) / r

a = ω²r

where;

ω = 7.2 rev/min = 7.2 rev/min x 2π rad/rev x 1 min/60s = 0.754 rad/s

Fc = ma

Fc = m(ω²r)

Fc = 45(0.754² x 5)

Fc = 127.9 N

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It is true that when weights is normally distributed, students who weigh between 60 kg and 75 kg is 476.

Mean is the average of given observations and we can calculate mean by dividing sum of observation by the total number of observation.

A standard deviation shows how much data is dispersed in relation to mean. Low deviation indicates that data are clustered and high deviation means data are scattered.

Mean weight is 70 kg and standard deviation is given 3 kg.

α1 = 75 - 70 / 3 = 1.67

α2 = 60- 70/3 = 3.33

So, P( α2- α1) = 0.9375- (1- 0.9666)

                      = 0.9371

The number = 500 ×0.9371

                     = 467

So, the statement is true.

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Given the

Half the weight of an SUV

If the mass of the SUV is 2m, the mass of the car is m

An SUV can produce twice as much power as a car, or 2 F.

Experience acceleration in an SUV

;SUV=2F/2m

;SUV=F/m

car acceleration

; car = F/m

They both start with an initial velocity of zero, so after a few seconds they have the same velocity and share the same position.

speed-

Velocity is a vector representation of the displacement an object or particle experiences with respect to time. The standard unit for velocity magnitude (also called velocity) is meters per second (m/s). Alternatively, centimeters per second (cm/s) can be used to express velocity magnitude. The direction of the velocity vector can be expressed in different ways depending on the number of dimensions involved. speed

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1. The atomic mass of the new atom be 223. Option (d) is correct.

2. The atomic number of the new atom be 88. Option (g) is correct.

3. The symbol of the new atom be Ra.  Option (e) is correct.

4. Beta decay is demonstrated here. Option (c) is correct.

A proton inside the radioactive sample's nucleus can change into a neutron or vice versa through a process known as beta decay. Because of processes like beta decay and alpha decay, the radioactive sample's nucleus is able to get as close as practical to the optimum neutron/proton ratio.

A beta particle, which can either be an electron or a positron, is released by the nucleus during this process. Think about the potential for a proton or neutron to decay into another particle. The production of the electron and positron adheres to the law of charge conservation. Beta-decay is the outcome of weak interaction.

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The magnitude of the gravitational force is 7×10⁻⁷ N

Baby weighs (m₁) 4.20 kg.

Father weighs (m₂)  100 Kg.

The gravitational force (F) between the body and the earth has a magnitude of 6.67×10⁻

The separation between them is: 0.200 m

The gravitational constant is

F=Gm₁×m₂÷ R²

F= 6.67×10⁻¹¹×4.20×100÷ (0.200)²

F= 7×10⁻⁷ N

Gravitational force: The gravitational force between any two mass-containing objects causes them to be drawn together. The gravitational force is said to as attractive because it continually seeks to unite masses rather than to drive them away. In truth, you and everything else in the universe are being pulled in different directions. It is referred to as Newton's Universal Law of Gravitation.

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Answer:

Below

Explanation:

V = IR

V/R = I  

    Now you can see that if you decrease R, you will need to decrease V to have the same value of I

0.017 is the probability that tab A won’t fit into slot B

Probability is related to possibility. Random event generation is the subject of this branch of mathematics. Values ​​range from 0 to 1. Probabilities are built into mathematics to predict the likelihood of certain events.

P(tab A won't fit into slot B) = P (A>B)

                                                = P( A-B > 0)

Given that, A ≈ N(30,0.5)   B ≈ N(32, 0.8)

Here,

E (A-B) = 30-32 = -2

V(A-B) = V(A) + V(B) = (0.5)² + (0,8)²

                                   = 0.89

SD (A-B) = [tex]\sqrt{0.89}[/tex]

So, (A-B) ≈ N (-2, 0.9433)

P( A-B > 0) = 1 - P(A-B ≤ 0)

= 1 - P [(A - B +2 / 0.9433) ≤ (+2 / 0.9433)]

= 1 - P (Z₁ ≤ 2.12)

= 1 - 0.98300

= 0.017

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The image will still get progressively smaller as we pull the object more and more away. The focal point will draw the image's location ever-closer.

The focal point or point of focus on the axis of the a lens or mirror where parallel light rays converge or appear to split after refraction or reflection.

Contrast can be used by an artist to establish focal points in the following methods: 1) Value—A focus point will naturally develop in the area where there is the greatest disparity between light and dark. 2) Form—If a composition of geometric squares added a circle, the circle would be composition's main point.

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According to the given statement [tex]\sqrt{2h}[/tex] and [tex]2\sqrt{3h}[/tex] and is the angular momentum of a hydrogen atom.

Momentum may be viewed as a body's "power" while it is moving, or the amount of force it can exert on another body. For instance, a slow-moving bowling ball might have the same acceleration as a baseball being thrown fast.

Briefing:

The angular momentum of a hydrogen atom can be defined as:

[tex]L=\sqrt{l(l+1)}h,[/tex]

where l represents the orbital quantum number which defines the subshells s, p, d, f.

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The conclusion about moving the boxes in Max's house is as follows: The boxes will slide more easily on the carpeted floor due to lower friction (option A).

Friction is the force that resists the relative motion or tendency to such motion of two bodies in contact.

According to this question, Max is moving boxes in his house from one room to another. Max has two different floor surfaces in his house, one carpeted and the other wood floor.

The carpeted floor will have a lesser friction than the wooden floor when moving the object. This makes it easier to move the boxes on the carpeted floor.

Therefore, option A is correct.

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The peak out of phase voltage also becomes doubled with increase in frequency .

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Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

In other terms, the distance that an object travels in a unit of time is referred to as its speed. It merely takes into account the magnitude of the object and ignores its orientation. Speed is referred to as a scalar quantity. When referring to velocity, however, it is said that velocity is the rate at which displacement changes. It is a   vector quantity. Speed is a scalar measure of "how quickly an object is moving." The rate at which an object travels a distance can be thought of as its speed. A fast-moving object travels at a high speed and completes a significant distance relatively quickly. A slow-moving object with a low speed, on the other hand, travels a relatively little distance in the same length of time. Zero speed refers to an object that is not moving at all. When evaluating the velocity of an item, one must retain track of direction. It wouldn't be sufficient to merely state that something moves at 80 km/h. To fully define an object's velocity, direction information must be included. For instance, 80 km/h reflects the speed of a car travelling along a road, while 80 km/h east shows the speed of the car.

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Answer:

Even your pencil and a piece of paper attract one another. You can't feel this force because the masses of the pencil and paper are so small. Even you exert a gravitational force on other objects. Because your mass is so much less than the mass of the Earth, you can't feel your gravitational force.

In simple word gravitational force is directly proportional to weight of and objects and indirectly proportional to distance.

F=G(m1 x m2) /r^2

F = force

G = gravitational constant

m_1 = mass of object 1

m_2 = mass of object 2

r = distance between centers of the masses

surface gravity formula

[tex]g=\frac{GM}{r^{2} }[/tex]

[tex]g[/tex] is the surface gravity in m/s²

[tex]G[/tex] is the gravitational constant 6.67408x10⁻¹¹ m³/kgs²

[tex]M[/tex]  is the mass of the object in kg

[tex]r[/tex] is the radius of the object in  m

The Earth’s mass is 5.972x10²⁴kg,

Jupiter’s mass is 1.898x10²⁷ kg,

the Earth’s radius is 6371 km,

Jupiter’s radius is 69911 km

[tex]g=\frac{6.67408X10^{-11}X5.972X10^{24} }{(6.371X10^{6} )^{2} }[/tex]

[tex]g=9.82 m/s^{2}[/tex]

[tex]g=\frac{6.67408X10^{-11}X1.898X10^{27} }{(6.9911X10^{7} )^{2} }[/tex]

[tex]g=25.92 m/s^{2}[/tex]

conclusion

[tex]\frac{25.92}{9.82} = 2.63[/tex]

the surface gravity of Jupiter is 2.63 times that of Earth.

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Both stars A and B will have the same brightness to the earth because luminosity is dependent on the temperature and size where A is hotter but smaller and B is bigger but colder.

There are several factors that determine the luminosity of a star namely, the size, temperature, distance and magnitude. The two main factors that determine luminosity of a star when the distance is the same are temperature and size.

When the temperature of a Star is higher than the other with equal distance from the earth the star is brighter than that with lower temperature. Also, when the size of a star is bigger, it possesses a higher surface area to absorb light and energy. This makes A and B as bright as the other.

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Most substances expands when temperature increases.

At low temperatures, most substances are solids. When the temperature rises, it becomes a liquid. At higher temperatures it becomes gaseous. The process by which a solid becomes a liquid is called melting (an old term you sometimes come across is fusion).

Thermal energy is added to a material during heating. As a result, its particles accelerate and its temperature rises. The loss of thermal energy that occurs during cooling results in a decrease in temperature and slower particle motion in the cooled material. When a substance's temperature rises, its molecules expand because they have more energy and are moving faster and further apart. When a material is heated, the molecules absorb energy. The inter-molecular connections between molecules are first disrupted.

So, most substances expands when temperature increases.

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The complete question is as follows:

What most substances do as temperature increases?

In scientific notation  "thirty two micro meter" can be expressed as 3.2 x 10^-5 m.

Micrometer, often known as micron, is a unit of length in the metric system equal to 0.001 mm, or roughly 0.000039 inch. m is its symbol.

The micrometer is frequently used to gauge the size of small items like colloidal particles and bacteria. Micrometers are also used to describe extremely small distances, like the infrared radiation's wavelengths.

So, 1 micrometer = 10^-6 meter.

∴ thirty two micrometer = 32 × 10^-6 meter = 3.2 × 10^-5 meter.

Hence,  in scientific notation  "thirty two micro meter" can be expressed as 3.2 x 10^-5 m.

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Answer:

35 degrees

Explanation:

The law of reflection states that the angle of incidence = to the angle of reflection

Answer:

The answer is C:

Rays will follow the law of reflection, so the angle of reflection will be 35°.

Explanation:

The action that best describes the camera motion in the scenes directly prior to the Old Man's Defiant hand gesture is: "Zooming in and out" (Option C)

Some interesting camera motions are:

Note that the different camera motions described above are important because they allow filmmakers to convey mood and emotion, create visual interest, and guide the audience's attention within a scene.

For example, a static shot can create a sense of calm or stability, while a handheld shot can create a sense of intimacy or instability. A panning shot can follow the action and keep the audience engaged, while a zoom shot can draw attention to a specific part of the scene.

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Full Question:

What best describes the camera motion in the scenes directly prior to the old man's defiant hand gesture?

O Static and secured on a tripod

O Moving chaotically

O Zooming in and out

O Filming at 96 frames a second

The acceleration of the luggage across the airport is 0.42 m/s².

The acceleration of the luggage across the airport is calculated by applying Newton's second law of motion as follows;

Mathematically, the Newton's second law of motion is given as;

F(net) = ma

where;

F - Ff = ma

where;

33.3  - 12.3  = 50a

21 = 50a

a = 21/50

a = 0.42 m/s²

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The complete question is below:

Jadee pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg. find the acceleration of the luggage.

Answer:

it is a heterogeneous mixture

Explanation:

because it ha s a smooth consistancy and not a thick one.

Answer:

Below

Explanation:

Using conservation of momentum

m1v1 = m2v2

.4 (8.5)   =  (.40 + .15) v^2

6.18 m/s

The  gravitational field gx at the surface of planet x  (M/m)(r/R)² times the gravitational field gy at the surface of planet y.

A gravitational field, as defined by physics, is the influence a massive body has on the area surrounding it, exerting a force on another huge body. In other words, a gravitational field, which is measured in newtons per kilograms (N/kg), aids in the explanation of gravitational field.

Now, Let planet x has mass M and radius R:  then gravitational field at the surface of planet: gₓ = GM/R².

Let planet y has mass m and radius r:  then gravitational field at the surface of planet: [tex]g_y[/tex] = Gm/r².

Hence, gₓ/[tex]g_y[/tex] = (M/m)(r/R)².

So, the  gravitational field gx at the surface of planet x  (M/m)(r/R)² times the gravitational field gy at the surface of planet y.

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Grand unified force thermodynamically isolated its internal energy as the universe expanded and cooled at an age about.

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if 5ev of energy is supplied to an electron with a binding energy of 2.3ev, with what kinetic energy is [tex]\Rightarrow \mathrm{KE}=5-2.3=\mathbf{2 . 7} \mathrm{eV}[/tex]

What is kinetic energy?

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Photoelectric effect: The photoelectric effect is a phenomenon where electrons are ejected from a metal surface when the light of sufficient frequency is incident on it. These ejected electrons are called photoelectrons.

- When a photon falls on the metal surface, the photon's energy is transferred to the electron.

- Some part of the energy gets utilized in removing the electron from the metal surface, and the remaining goes into giving kinetic energy for the ejected electron.

- Work function [tex](\phi)[/tex]: It is the minimum amount of energy required to cause photo-emission of electrons from a metal surface when light is incident on it.

- Einstein's Photoelectric Equation gives the relationship between work function[tex](\phi)[/tex], the kinetic energy of the emitted electron, and the energy of the photon [tex](E)[/tex]

[tex]$$E=\phi+K E$$[/tex]

Given that:

Energy of incident light, [tex]E=5 \mathrm{eV}[/tex]

Work function,[tex]$\phi=2.3 \mathrm{eV}$[/tex]

Using Einstein's Photoelectric Equation,

[tex]$$\begin{aligned}& \mathrm{E}=\phi+\mathrm{KE} \\& 5=2.3+\mathrm{KE} \\& \Rightarrow \mathrm{KE}=5-2.3=\mathbf{2 . 7} \mathrm{eV}\end{aligned}$$[/tex]

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Answer: 1.72J

Explanation:

hope this helps :)

Free fall motion is motion in which the only force acting on the body is gravity.

A free-falling object is one that moves only due to the effect of gravity, and its motion is defined by Newton's second law of motion. We can use algebra to calculate the acceleration of a free-falling particle.

The student should launch the sphere at 2v₀, for the sphere will land at approximately 1.41D, which is in the 3 point zone

The given parameter are;

The distance covered by the sphere when launched at height, H = D

The velocity with which the ball reaches D = v₀

The current available height of launcher= H/2

The available velocities = v₀, and 2v₀

Now,

From H = ut + (1/2)gt², where, initial velocity of the vertical motion of the ball, u = 0

we know;

H = (1/2)gt²

Therefore, the time it takes the ball to drop from H, t = √(2H/g)

The distance, D = v₀ × √(2H/g)

When the height is H/2, we get;

t = √(2H/(2g)) = √(H/g)

Thus, the distance covered, D₁ = v₀ × √(H/g)

Therefore, D = (√2) × v₀ × √(H/g) = (√(2))D₁

Now, D₁ = D/(√2) ≈ 0.71D

D₁ ≈ 0.71D

At speed 2v₀, we have;

D₂ = 2v₀ × √(H/g) = √2 × v2 × v₀ × √(H/g) = √2 × v₀ × √(2H/g) = √2D₁ ≈ 1.41D

D₂ ≈ 1.41D

The 2 point zone = D/2 < x < D = 0.5D < x < D (Position D₁ ≈ 0.71D is located here)

The 3 Point Zone =  D < x < 3D/2 = D < x < 1.5D (Position D₂ ≈ 1.41D is located here)

Given that at D₂, the ball lands in the 3 Point Zone, the student should launch the sphere at the speed, 2v₀, so that the ball will land at D₂ ≈ 1.41D,  which is in the 3 Point Zone

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The complete question is as follows:

A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.

The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.

When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.

Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.

Answer:

8. 9×10³N/m

Explanation:

k=2U /x²

= 2(25J) / 0.075m²

=8. 9×10³N/m