Answer: the answer is 4
Step-by-step explanation: good luck
Is a triangle with sides of 5 meters, 12 meters, and 13 meters a right triangle? Explain/Show your work.
Answer:
yes it is if you bisect 5m on a 12m line
Luis's cedar chest measures 4 ft long 2 ft wide and 2 1/4 ft high. What is the volume of the chest? PLEASE USE THE FORMULA IN THE STEP BY STEP EXPLANATION! I REALLY NEED HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
PLEASE HELP MEE‼️‼️
Tell me which each 3 boxes should I pick for each one of them PLEASE READ them I beg (proportional relationships)
number one take the second
NO LINKS!! URGENT HELP PLEASE!!!!
Express the statement as an inequality. Part 3a^2
The inequalities for the given word problems are:
g) p/q ≤ 6
h) 1/w ≥ 9
How to solve Inequality word problems?Inequality word problems are statements or words used to describe specific inequalities.
g) We are told that the quotient of p and q is at most 6. Thus, it is a maximum of 6. Therefore, we can write the inequality as:
p/q ≤ 6
h) We are told that the reciprocal of w is at least 9. Thus, the inequality is expressed as:
1/w ≥ 9
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Fred's science class is going to the Ancient Dig adventure park. His teacher got the school group package, which costs $308. The package covers the entrance fee for the group, a private dig site, and an activity guide. Fred's teacher upgraded the package to include a fossil tool kit for each of the 22 students, bringing the total to $440. Which equation can you use to find k, the cost of each tool kit?
Answer: (440-308) ÷ 22 = The cost of each tool kit is 6 dollars
Step-by-step explanation:
The original price of the field trip was $308 after the price fof each tool kit was added the price was $440.
The total costs of all the tool kits was 132
440-308=132
the total cost of the tool kits divided by the number of kids will get the price of each tool kit
132÷22 =
K=
Use the expression below to complete the following tasks.
(3a2 - 5ab + b2) - (-3a2 + 2b2 + 8ab)
What is the additive inverse of the polynomial being subtracted?After you rewrite subtraction as addition of the additive inverse, how can the like terms be grouped?
With additive inverse and by grouping like terms the simplified form of the expression is 6a²-13ab-b².
The given expression is 3a²-5ab+b²-(-3a²+2b²+8ab).
Here,
3a²-5ab+b²+3a²-2b²-8ab
Group like terms, that is
(3a²+3a²)+(-5ab-8ab)+(b²-2b²)
= 6a²-13ab-b²
Therefore, with additive inverse and by grouping like terms the simplified form of the expression is 6a²-13ab-b².
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Write 2:7 in the form 1: n
Answer:
7 ÷ 2 = 3.5, so 2:7 = 1:3.5 (1 to 3.5).
Answer:
1 : 3.5
Step-by-step explanation:
2: 7 written in the ratio 1 : n...
2:7
1:n
To get to 1 from 2 you have to divide by 2.
So do the same for 7.
Therefore the answer is 1: 3.5
I need some assistance with this ?
Answer:
[tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm i\sqrt{\frac{2}{7}}[/tex]
(real solution) (imaginary solution)
Step-by-step explanation:
Substitution:For these type of questions, where the exponent is even, it helps to try to rewrite the equation into a quadratic equation as we have a closed formula (quadratic formula) to solve for the zeroes, and it's also just easier to deal with in general.
Let's say that: [tex]u=x^2[/tex], now if we square both sides, [tex]u^2=x^4[/tex], so from here we can substitute in u squared as x to the power of four.
This results in our following equation: [tex]49u^2-4[/tex], from here we could use the quadratic formula, but you may notice a pattern here. We have a difference of squares: [tex]a^2-b^2=(a-b)(a+b)[/tex]
[tex]49u^2[/tex] can be written as [tex](7u)^2[/tex] and [tex]4[/tex] can be written as [tex]2^2[/tex], this gives us our equation: [tex](7u)^2-2^2\implies (7u-2)(7u+2)[/tex]. If we use this definition of the equation on the left side, it gives us: [tex](7u-2)(7u+2)=0[/tex] and this is very convenient as we can solve both of them individually.
Zero Property of Multiplication:Whenever we multiply any number (assuming it's defined) by zero, we should get.... zero. This intuitively makes sense as no matter how many times we add zero up (multiplication is repeated addition), we're always just going to have zero.
So when we have the equation: [tex]a*b=0[/tex], if "a" is zero then regardless of what "b" is (assuming it's defined), then the product will be zero. If "b" is zero then regardless of what "a" is (assuming it's defined), then the product will be zero.
Now if we look back at our equation: [tex](7u-2)(7u+2)=0[/tex], if [tex]7u-2=0[/tex], then regardless of what [tex]7u+2[/tex] is equal to, the product will be zero. Likewise, if [tex]7u+2=0[/tex] then regardless of what [tex]7u-2[/tex] is equal to, the product will be zero, thus making the equation true.
So to find the solutions to this, we find what makes [tex]7u-2=0 \text{ and }7u+2=0[/tex] true. If we work them both out individually we
get:
[tex]7u-2=0\\7u=2\\u=\frac{2}{7}\\\\7u+2=0\\7u=-2\\u=-\frac{2}{7}[/tex]
So now we have our two solutions right? Well remember we started off with a "x" variable, and the "u" is merely a substitution. If you recall, the "u" value is set equal to "x^2", so we can just plug that back in, so we can find the solutions in terms of x.
[tex]x^2=\frac{2}{7} \text{ and } x^2=-\frac{2}{7}[/tex]
If we take the square root of both sides, we get:
[tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm\sqrt{-\frac{2}{7}}[/tex]
you'll notice in one of them, we're taking the square root of a negative number. This will result in imaginary solutions, if we factor out a "-1" and take the square root of that, we'll just get an "i" infront, giving us the solutions of: [tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm i\sqrt{\frac{2}{7}}[/tex].
The cat____under the table when the veterinarian came into the examining room.
Which of these words would indicate that the
cat was afraid of the veterinarian?
A sulked
B cowered
C reclined
D strolled
Answer: B
Step-by-step explanation:
The word that would indicate that the cat was afraid of the veterinarian is "cowered." "Cowered" means to crouch down in fear or shame. So, the sentence would be: "The cat cowered under the table when the veterinarian came into the examining room."
If f(x)=x^2+10sinx, show that there is a number c such that f(c)=1000.
Answer:
Step-by-step explanation:
ben and david plot the locations of their houses and the park on the grid show below. they r planning to each start at home and travel in a straight line to the park. how many times greater is the distance ben travels to get to the park than the distance david travels?
The distance Ben travels to get to the park is approximately 2.21 times greater than the distance David travels. This is found by using the distance formula to calculate the distances each person travels and then comparing the results.
To solve this problem, we need to find the distance between each person's house and the park using the distance formula
distance = √((x₂ - x₁)² + (y₂ - y₁)²)
For Ben
distance = √((-2 - 4)² + (-2 - 6)²) = √((-6)² + (-8)²) = √(100) = 10
For David
distance = √((-2 - (-7))² + (-2 - (-6))²) = √((5)² + (4)²) = √(41)
So the ratio of Ben's distance to David's distance is
10 / √(41) ≈ 2.21
Therefore, Ben's distance is about 2.21 times greater than David's distance.
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Which of the figures can be folded into a cube?
A, B, C, D, E, F, G, H, I, J
A, B, E, G, I, J
C D, F, H, J
A, B, C, E, G, I
The correct option is (D) A, B, C, E, G, I
What is the cube?
A cube is a three-dimensional solid shape that has six square faces of equal size. It has twelve edges and eight vertices, and all angles between the faces are right angles. The cube is a regular polyhedron, which means that all its faces are congruent and all its edges have the same length.
The net of a cube is the one that has the faces arranged in such a way that it makes a complete cubic structure
A) In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.
B) In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.
C) In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.
D) In the given figure, the net can be folded into a cube when its faces are folded one over the other. Therefore, it is a cube net.
Hence, The correct option is (D) A, B, C, E, G, I.
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Is a triangle with sides of 5 meters, 12 meters, and 13 meters a right triangle? Explain/Show your work.
Answer:
Step-by-step explanation:
In a survey 7 out of 8 people preferred cooking to washing dishes what percentage of the people surveyed preferred cooking
The percentage of the people that preferred cooking who where surveyed would be = 87.2%
How to calculate the percentage of people who preferred cooking?The total number of people surveyed = 8
The total number of people that preferred cooking = 7
The percentage of people that preferred cooking;
= 7/8×100/1
= 700/8
= 87.2%
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A flagpole is 12 feet fall. Its shadow is
11 feet long. How far is it from the top of the flagpole to the end of its shadow?
The distance from the top of the flagpole to the end of its shadow is approximately 10.02 feet.
Explain the term distance
Distance refers to the measurement of the space between two objects or points. It is typically measured in units such as meters, kilometres, miles, or feet. The distance can be calculated using various methods, including using maps, GPS technology, or mathematical formulas.
According to the given information
We can set up the following proportion:
h / 12 = d / 11
We can cross-multiply to get:
h x 11 = 12 x d
Simplifying further:
d = (h x 11) / 12
We need to solve for d, so we need to find the value of h. Using the Pythagorean theorem, we can set up the following equation:
h² + d² = 12²
Substituting d = (h x 11) / 12, we get:
h² + ((h x 11) / 12)² = 12²
Simplifying:
h² + (121h²) / 144 = 144
Multiplying both sides by 144/265:
265h² / 144 = 144
Solving for h:
h² = (144 x 144) / 265
h = √(20736 / 265)
h = √(78.113)
Now we can substitute this value into our earlier equation to find d:
d = (√(78.113) x 11) / 12
d ≈ 10.02 feet
Therefore, the distance from the top of the flagpole to the end of its shadow is approximately 10.02 feet.
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On the SAT exam a total of 25 minutes is allotted for students to answer 20 math questions without the use of a calculator. A guidance counselor would like to know if the students in his school are prepared to complete this portion of the exam in the timeframe allotted. To investigate, the counselor selects a random sample of 35 students and administers this portion of the test. The students are instructed to turn in their test as soon as they have completed the questions. The mean amount of time taken by the students is 23.5 minutes with a standard deviation of 4.8 minutes. The counselor would like to know if the data provide convincing evidence that the true mean amount of time needed for all students of this school to complete this portion of the test is less than 25 minutes and therefore tests the hypotheses H0: μ = 25 versus Ha: μ < 25, where μ = the true mean amount of time needed by students at this school to complete this portion of the exam. The conditions for inference are met. What are the appropriate test statistic and P-value?
The P-value is between 0.025 and 0.05. and t = -1.85
On the SAT exam a total of 25 minutes is allotted for students to answer 20 math questions without the use of a calculator.
Therefore tests the hypotheses:
[tex]H_0[/tex] : μ = 25 versus Ha: μ < 25,
where μ = the true mean amount of time needed by students at this school to complete this portion of the exam.
The alternative hypothesis is:
[tex]H_1:\mu < 25[/tex]
The test statistic is given by:
[tex]t=\frac{x-\mu}{\frac{s}{\sqrt{n} } }[/tex]
The parameters are:
'x' is the sample mean. [tex]\mu[/tex] is the value tested at the null hypothesis.s is the standard deviation of the sample.n is the sample size.the values of the parameters are:
x = 23.5 , [tex]\mu=25[/tex] , s = 4.8, n = 35
Plug all the values in above formula of t- statistic is:
[tex]t = \frac{23.5-25}{\frac{4.8}{\sqrt{35} } }[/tex]
t = -1.85
Using a t-distribution , with a left-tailed test, as we are testing if the mean is less than a value and 35 - 1 = 34 df, the p-value is of 0.0365.
t = –1.85; the P-value is between 0.025 and 0.05.
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Please help !!
i only need help with the second problem which is:
5. For 0≤x≤ 6, express g(x) in terms of x. Do not include +C in your final answer.
Your help is very appreciated !!
From the calculation, g increases on the interval [-3, 6) and for 0 ≤ x ≤ 6, g(x) = 6 - 1/2(x-2)^2.
What is the interval that g increases?To determine where g is increasing, we need to find where its derivative, g'(x), is positive. We can find g'(x) by differentiating g(x) with respect to x:
g'(x) = f(x)
Since f(x) is a piecewise-defined function, we need to consider each interval separately.
For -3 ≤ x < 0, f(x) = 3, so g'(x) = 3, which is positive.For 0 ≤ x ≤ 6, f(x) = -x + 3, which is a decreasing function, so g'(x) is also decreasing. However, since f(x) is always non-negative on this interval, g'(x) is non-negative as well.For 6 < x ≤ 9, f(x) = -3, so g'(x) = -3, which is negative.Therefore, g is increasing on the interval [-3, 6).
To justify this, note that g'(x) = 0 at x = 0 and x = 6, where g has local maxima. This means that g is increasing on the intervals (-3, 0) and (0, 6) and decreasing on (6, 9]. Since g is continuous, it cannot have any jumps, so it must be increasing or decreasing on each of these intervals. Since g(-3) = 0 and g(6) = 9, we know that g is increasing on the interval [-3, 6).
We can evaluate g(x) on the interval [0, 6] by integrating f(x) with respect to t from -2 to x:
g(x) = ∫_{-2}^{x} f(t) dt
On the interval [-3, 0), f(t) = 3, so we have:
g(x) = ∫_{-2}^{0} 3 dt + ∫_{0}^{x} (-t + 3) dt
Simplifying the integrals, we get:
g(x) = 6 - 1/2(x-2)^2, for 0 ≤ x ≤ 6
(Note that we can drop the "+C" since it's being evaluated at the limits of integration.)
Therefore, for 0 ≤ x ≤ 6, g(x) = 6 - 1/2(x-2)^2.
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HELPPPPPP PLEASEEEEE
Answer: 300
Step-by-step explanation:
10*8*6=480-6*6*5=180=300
Juliet tell her in Israel our volunteer firefighters on Saturday to volunteer fire department hell is annual coin drop fundraiser at street light after one hour Keller had collected $42.50 more than Julia. Israel had collected $15 less than Keller. The three firefighters collected $125.95 in total. How much did each person collect?
Part A: Choose all equations that represents this problem. J= the amount Julia collected, K= the amount Keller collected, I = the amount Israel collected.
Options:
A: 125.95=J+(42.5+J)+(J+15)
B: 125.95=K+42.5+K-15
C: 125.95=I+(1+15)+(I-27.5)
D: 125.95=K+(K-42.5)+(K-15)
Part B: Keller collected 42.50 more than Julia, and Israel had collected 15 less than Keller. The three firefighters collected $125.95 in total. How much did each person collect?
Options:
$125.95
$61.15
$46.15
$42.50
$64.80
$18.65
$15.00
Part A: A
Part B: Julia collected 18.65, Keller collected 61.15, and Israel collected 45.15
HURRY DUE TONIGHT
Jenny mixed 4 kg of mixed nuts containing 16% peanuts with 12 kg of mixed nuts containing 40% peanuts. What percent of the new mixture if peanuts?
A. 34%
B. 13%
The new mixture contains 34% peanuts.
The correct option is A
We have,
Jenny mixed 4 kg of mixed nuts containing 16% peanuts with 12 kg of mixed nuts containing 40% peanuts.
First, Total weight = 4 kg + 12 kg = 16 kg
Now, Total weight in kilograms is = (4 kg) (0.16) + (12 kg) (0.40)
= 0.64 kg + 4.80 kg
= 5.44 kg.
Now, the Percent of peanuts
= (Total amount of peanuts / Total weight) x 100%
= (5.44 kg / 16 kg) x 100
= 34%
Thus, the new mixture contains 34% peanuts.
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Find the volume of the cone below if the radius is 12 height is 12
Answer:
Work smartly not hard.
Step-by-step explanation:
AI
PLEASE HELP QUICK How many clubs have at least 30 members?
A.5 clubs
B.6 clubs
C.8 clubs
D.9 clubs
Answer:
D. 9 clubs
Step-by-step explanation:
Given a stem-and-leaf plot of the number of members in clubs, you want to know the number of clubs with 30 or more members.
Stem and Leaf PlotThe plot shows the club membership to be ...
{10, 13, 15, 24, 26, 30, 36, 39, 50, 55, 59, 61, 66, 78}
The 9 clubs whose member numbers are in bold have at least 30 members.
The number of clubs with at least 30 members is ...
D. 9 clubs
<95141404393>
Find the value of x.
Applying the intersecting secants theorem, the value of x is calculated as: x = 5.
What is the Intersecting Secants Theorem?According to the intersecting secants theorem, if two secant lines intersect outside of a circle, then the product of the length of one secant segment and its external segment is equal to the product of the length of the other secant segment and its external segment.
Using the theorem, the equation below is created to find the value of x:
4(4 + 5) = (x - 2)(x - 2 + x + 4)
4(9) = (x - 2)(2x + 2)
36 = 2x² - 2x - 4
2x² - 2x - 4 - 36 = 0
2x² - 2x - 40 = 0
Factorize:
(x + 4)(x - 5) = 0
x = -4 or x = 5
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Someone pls help me I’m so confused
The number of triangles that are displayed can be found to be 216 triangles.
How to find the number of triangles ?Each rectangular tile has a decorative pattern of 3 equal-sized squares, and each square is divided into 2 same-sized triangles. Therefore, each tile has 3 squares * 2 triangles per square = 6 triangles.
Marnie uses 36 of these tiles on the wall behind her kitchen stove. To find the total number of triangles displayed, multiply the number of triangles per tile by the total number of tiles:
Total triangles = 6 triangles per tile x 36 tiles = 216 triangles
So, there are 216 triangles displayed on the wall behind Marnie's kitchen stove.
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Help!!!!!!!!!!!!
Write the new coordinates of A'B'C' after
the reflection described below
A(5, -1), B(3,-4), C(3, 0)
Reflection across the y-axis
A:
B:
C:
Thus, new coordinates of A'B'C' after the reflection across the y-axis are-
A'(-5, -1), B'(-3,-4), C'(-3, 0).
Explain about the reflection across y-axis:The x-coordinate remains constant when a point is reflected across the x-axis, but the y-coordinate is assumed to be the additive inverse. Point (x, y) is reflected across the x-axis as (x, -y).
The y-coordinate stays the same when a point is reflected across the y-axis, but the x-coordinate is assumed to be the additive inverse. Point (x, y) is reflected across the y-axis as (-x, y).
Given coordinates of ABC.
A(5, -1), B(3,-4), C(3, 0)
Reflection across the y-axis : y coordinates remains same while x coordinate multiplied with -1.
(x,y) -- > (-x, y)
A'(-5, -1), B'(-3,-4), C'(-3, 0)
Thus, new coordinates of A'B'C' after the reflection across the y-axis are-
A'(-5, -1), B'(-3,-4), C'(-3, 0).
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Name:
Date:
2.
5.
Directions: Solve for x
This is a 2-page document
Directions identify the similar triangles in the diagram, then sketch them so the coresponding
sides and angles have the same orientation
1.
52
48
Per
20
9.24 and 32
طلال سلال
kl ma jkk
Jkm-kim
Unit 7: Right Triangles & Trigonometry
Homework 3: Similar Right Triangles
& Geometric Mean
X=4.8
6.
22.4
13.2
26
Directions: Find the geometric mean of each pair of numbers.
7.16 and 27
8. 5 and 36
10.8 and 48
The geometric means of the pairs of numbers are approximately:
14.85 for 7.16 and 27
13.42 for 5 and 36
22.94 for 10.8 and 48.
How to calculate the meanIt should be noted that to find the geometric mean of two numbers, we multiply them together and then take the square root of the result. So, for each pair of numbers, we can follow these steps:
Multiply the two numbers together.
Take the square root of the product.
Using this formula, we get:
7.16 and 27:
Geometric mean = √(7.16 × 27) ≈ 14.85
5 and 36:
Geometric mean = √(5 × 36) = √180 ≈ 13.42
10.8 and 48:
Geometric mean = √(10.8 × 48) ≈ 22.94
Therefore, the geometric means of the pairs of numbers are approximately:
14.85 for 7.16 and 27
13.42 for 5 and 36
22.94 for 10.8 and 48.
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In a spring, the tension (Tnewtons) is directly proportional to its extension ( x cm). When the tension is 150 newtons, the extension is 6 cm. (a) Find a formula for T' in terms of x. T = AD
The formula for tension (T) in terms of extension (x) is T = 25x.
The given statement is T = kx, where T is the tension, x is the extension, and k is the proportionality constant.
To solve this problem, we need to find the value of k. We can do that by substituting the given values of T and x into the equation:
T = kx
150 = k×6
k = 25
Therefore, the formula for tension (T) in terms of extension (x) is T = 25x.
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100 Points! Algebra question, photo attached. Only looking for an answer to B. Please show as much work as possible. Thank you!
Answer:f/g=29
Step-by-step explanation:
Answer: (f/g)=29
Hope this helps
50 Points! Multiple choice algebra question. Photo attached. Thank you!
The solution to the given composite function is; C: 4x² - 4x - 2
How to solve composite functions?From the question, we are given the individual functions as;
f(x) = x² - 3
g(x) = 2x - 1
Now when it comes to composite functions, we know that;
(f ° g)(x) = f[g(x)]
Substitute the known values in the above equation, so, we have the following representation
(f ° g)(x) = f(2x - 1) = (2x - 1)² - 3 = 4x² - 2x - 2x + 1 - 3 = 4x² - 4x - 2
This is the final solution of the composite function expression.
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The solution to the given composite function is; Option D: 2x² - 7
How to solve composite functions?Composite functions are defined as functions where the output of one function is used as the input of another. Wheb we have a function f and another function g, then the function fg(x), said as “ f of g of x”, is the composition of the two functions.
The given functions are:
f(x) = x² - 3
g(x) = 2x - 1
We want to find (g ° f)(x) . We know that:
(g ° f)(x) = g[f(x)]
Thus:
(g ° f)(x) = g(x² - 3)
= 2(x² - 3) - 1
= 2x² - 6 - 1
= 2x² - 7
This is the final result of the composite function expression.
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-7 4/5 divided by X = -5 1/5
The value of the variable is 3/2
What is a fraction?A fraction cam simply be described as an expression that is being used to represent the part of a whole number, a whole variable or element.
There are different types of fractions. They are listed as;
Improper fractionsProper fractionsComplex fractionsSimple fractionsMixed fractionsFrom the information given, we have that;
-7 4/5 divided by X = -5 1/5
convert to improper fractions, we have;
-39/5/x = -26/5
Now, cross multiply the values, we have;
-39/5 = -26x/5
cross multiply
-130x = -195
Divide both sides
x = -195/-130
x = 39/26 = 3/2
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