Is the answer A or D?
Two identical cars, car 1 and car 2, are moving in opposite directions on a straight road. The position of each car as a function of time is represented in the graph. What is the speed of the center of mass of the two-car system?
O Zero
O 10 m/s
O 20 m/s
O 40 m/s

Answers

Answer 1

The required  speed of the center of mass of the two-car system is 10 m/s.

Option(2) is corret.

What is speed?

The reason is simple. Velocity is the percentage of time an object moves along a path, and Velocity is the speed and direction of an object's movement.

The mathematical calculation of velocity is relatively simple, the average velocity of an object is calculated by dividing the distance traveled by the time it took the object to travel that distance. Velocity, on the other hand, is mathematically complex and can be calculated in different ways depending on what information is available about the object's motion. In its simplest form, the average velocity is calculated by dividing the change in position (Δr) by the change in time (Δt).

According to graph:

Let the mass of cars which is same is M,

Speed (V1) = 30 m/s

Speed (V2) = -10 m/s

Then,

Speed of center of mass = MV1 + MV2/2M

Speed of center of mass = M(30) + M(-10)/2M

Speed of center of mass = 30M - 10M/2M

Speed of center of mass = 20M/2m

Speed of center of mass = 10 m/s

Thus, Speed of center of mass is 10 m/s

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Is The Answer A Or D?Two Identical Cars, Car 1 And Car 2, Are Moving In Opposite Directions On A Straight

Related Questions

How much kinetic energy does an object have that is moving at a rate of 30 m/s and has a mass of 4000 kg ?

Answers

Answer:

K = 1800 kJ

Explanation:

Given that,

The speed of the object, v = 30 m/s

Mass of the object, m = 4000 kg

We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :

[tex]K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ[/tex]

So, the required kinetic energy is equal to 1800 kJ.



Guys can you please help me with this

Answers

False
False
True
True
True
True

Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate View Available Hint(s) Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate four times as fast. at the same rate. one-fourth as fast. twice as fast. one-half as fast.

Answers

Answer:

w = w₀ / 2    the angular velocity is half the initial value.

Explanation:

We can analyze this exercise as if we added another disk to obtain a disk with twice the mass, for which if the system is two disks, the angular tidal wave is conserved

initial instant.

          L₀ = I₀ w₀

final moment

          L_f = I w

the moment is preserved

          L₀ = L_f

          I₀ w₀ = I w

the moment of inertia of a disk is

         I = ½ m R²

we substitute

          ½ m R² w₀ = ½ (2m) R² w

          w = w₀ / 2

for the case of a disk with twice the mass, the angular velocity is half the initial value.

Coherent monochromatic light of wavelength l passes through a narrow slit of width a, and a diffraction pattern is observed on a screen that is a distance x from the slit. On the screen, the width w of the central diffraction maximum is twice the distance x. What is the ratio a>l of the width of the slit to the wavelength of the light

Answers

Answer:

λ = a

Explanation:

This is a diffraction exercise that is described by the expression

          a sin θ = m λ

         sin θ  = m λ/ a

the first zero of the diffraction occurs for m = 1

        sin θ  = λ / a

 

angles are generally very small and are measured in radians

         sin θ  = θ  = y / x

we substitute

         [tex]\frac{y}{x} = \frac{\lambda}{a}[/tex]

the width of the central maximum is twice the distance to zero

         w = 2y

in the exercise indicate that this width is equal to twice the distance to the screen (2x)

          W = 2x

           2y = 2x

we substitute

          1 = λ/ a

          λ = a

we see that the width of the slit is equal to the wavelength used.

What happens when a neutral atom gains an electrons?

Answers

it will become a ion , if it gains a negative electron it becomes a negative ion

Answer:

The neutral atom becomes an anion.

Explanation:

When a neutral atom gains an electron (e−), the number of protons (p+) in the nucleus remains the same, resulting in the atom becoming an anion (an ion with a net negative charge).

Explain how grality and electric charge are different

Answers

A difference between the two forces is the fact that gravitation only attracts, while electrical forces attract when the electrical charges are opposite and repel if the charges are similar. Thus, gravitation is considered a monopole force, while electrostatics is a dipole force. Please mark me as a brainiest!!!

a student practicing for a track meet ran 250 m in 30 seconds. What was her average speed?

Answers

Answer:

8.33 meters/sec.

time = 30 sec. 30 sec. = 8.33 meters/sec.

A 2.50 MHz sound wave travels through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 78 beats per second are detected. The speed of sound in body tissue is 1500 m/s. Part A Calculate the speed of the fetal heart wall at the instant this measurement is made.

Answers

Answer:

the speed of the fetal heart wall at the instant is 0.0325 m/s

Explanation:

Given the data in the question;

f₀ = 2.50 MHz = 1.80 × 10⁶ Hz

f[tex]_B[/tex]  = 78 beat per sec ( Hz )

V = 1500 m/s

the speed of the fetal heart wall at the instant this measurement is made = ?

now, if v is the magnitude of hart wall speed, V is speed of sound and f[tex]_h[/tex] the frequency the heart receives( and reflects), f₀ is original frequency and f, is reflected back;

so

heart is moving observer and device is stationary source

f[tex]_h[/tex] = ((V + v)/v )f₀

Heart is moving source and device is stationary observer

f' = (V/(V-v ))f[tex]_h[/tex]

Beats

f[tex]_B[/tex] = f₀ - f' = f₀ - f₀( V+v / V-v ) = f₀( 2v / V-v )

so we solve for v

v = V( f[tex]_B[/tex] / ( 2f₀ + f[tex]_B[/tex] )

so we substitute

v = 1500 ( 78 / ( (2×1.80 × 10⁶) + 78 )

v = 1500 ( 78 / ( 3,600,000 + 78 )

v = 1500 ( 78 / 3,600,078 )

v = 1500 ( 2.1666 × 10⁻⁵ )

v = 0.0325 m/s

Therefore,  the speed of the fetal heart wall at the instant is 0.0325 m/s

What is the index of refraction of a refractive medium if the angle of incidence in air is 40 degrees and the angle of refraction is 29 degrees?

Answers

N= 1.33
Explanation: (1) sin 40 degrees = n(sin 20 degrees)

The index of refraction is 1.33.

To find the answer, we need to know about index of refraction.

What is index of refraction?

The indication of the light bending ability of a medium is the refractive index of that medium.It determines how much the path of light is bent or refracted.It's a dimensionless number.

What is the mathematical expression of refractive index?

Mathematically, the refractive index(n) is

n= sin∅₁ / sin∅₂

where, ∅₁= angle of incident

             ∅₂= angle of refraction

What is the refractive index,  if the angle of incidence in air is 40 degrees and the angle of refraction is 29 degrees?

n= sin(40) /sin(24) = 1.33

Thus, we can conclude that the index of refraction is 1.33.

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Sometimes a person cannot clearly see objects close up or far away. To correct this type of vision, bifocals are often used. The top half of the lens is used to view distant objects and the bottom half of the lens is used to view objects close to the eye. Bifocal lenses are used to correct his vision. A diverging lens is used in the top part of the lens to allow the person to clearly see distant objects.
1. What power lens (in diopters) should be used in the top half of the lens to allow her to clearly see distant objects?
2. What power lens (in diopters) should be used in the bottom half of the lens to allow him to clearly see objects 25 cm away?

Answers

Answer:

1)   P₁ = -2 D,   2) P₂ = 6 D

Explanation:

for this exercise in geometric optics let's use the equation of the constructor

          [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and the image, respectively

1) to see a distant object it must be at infinity (p = ∞)

          [tex]\frac{1}{f_1} = \frac{1}{q}[/tex]

           q = f₁

2) for an object located at p = 25 cm

            [tex]\frac{1}{f_2} = \frac{1}{25} + \frac{1}{q}[/tex]

We can that in the two expressions we have the distance to the image, this is the distance where it can be seen clearly in general for a normal person is q = 50 cm

we substitute in the equations

1) f₁ = -50 cm

2)  

        [tex]\frac{1}{f_2} = \frac{1}{25} + \frac{1}{50}[/tex]

        [tex]\frac{1}{f_2}[/tex] = 0.06

         f₂ = 16.67 cm

the expression for the power of the lenses is

          P = [tex]\frac{1}{f}[/tex]

where the focal length is in meters

           

1)       P₁ = 1/0.50

        P₁ = -2 D

2)     P₂ = 1 /0.16667

        P₂ = 6 D

What do you mean by physics?

Answers

Answer:

Explanation:

Physics is the branch of science that studies the natural world and its rules and orders. It is one of the oldest sciences as ancient people study the stars and astronomy is considered part of Physics.

It takes 20 seconds to fill a two-liter bottle with water from your kitchen faucet. What is the mass flow rate from the faucet if water has a density of 1000 fraction numerator k g over denominator m cubed end fraction?
a. 0.1kg/sec.
b. 0.01kg/sec.
c. 1g/sec.
d. 1kg/sec.

Answers

Answer:

0.1 kg/s.

Explanation:

The density of water, d = 1000 kg/m³

Volume, V = 2 L

Time, t = 20 s

We need to find the mass flow rate from the faucet. We know that the density of an object is given by :

[tex]d=\dfrac{m}{V}\\\\m=d\times V\\\\\dfrac{m}{t}=\dfrac{dV}{t}\\\\\dfrac{m}{t}=\dfrac{1000\times 0.002}{20}\\\\=0.1\ kg/s[/tex]

So, the mass flow rate is equal to 0.1 kg/s.

Which one of the statements below is true about mechanical waves?

They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.

Answers

They require a medium to travel through

How much mechanical work is required to catch a 14.715N ball traveling at a velocity of 37.5m/s?

Answers

14.715N ball traveling at a velocity of 37.5m? Is there a picture so I can determine it

To catch a 14.715N ball traveling at a velocity of 37.5m/s, required mechanical work is 1056.10 joule.

What is work?

Physics' definition of work makes clear how it is related to energy: anytime work is performed, energy is transferred.

In a scientific sense, a work requires the application of a force and a displacement in the force's direction. Given this, we can state that

Work is the product of the component of the force acting in the displacement's direction and its magnitude.

Weight of the ball = 14.715 N.

Mass of the ball = 14.715 N ÷ (9.8 m/s²) = 1.502 kg.

Velocity of the ball = 37.5 m/s

Kinetic energy of the ball = 1/2 × 1.502 × 37.5² Joule = 1056.10 Joule.

Hence, to catch a 14.715N ball traveling at a velocity of 37.5m/s, required work is 1056.10 joule.

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The length of stereocilia actually vary from 10 to 50 micrometers. Again, assuming that they behave like simple pendula, over what frequency range of sound waves would they resonate. (The actual frequency range of human hearing is 20 Hz - 20,000 Hz, so there certainly must be other mechanisms involved in determining the frequency of these being the pendular model is rather oversimplified.)

a. About 70 Hz -160 Hz.
b. About 440 Hz - 1000 Hz.
c. About 20 Hz - 50 Hz.
d. About 0.07 to 0.16 Hz.

Answers

Answer:

the frequency range of sound waves is about 70 Hz - 160 Hz

Hence, Option a)  About 70 Hz -160 Hz is the correct answer

Explanation:

Given the data in the question;

L₁ = 10 micrometers = 0.00001 m

so

T₁ = 2π√(L/g)

g = 9.8 m/s

so we substitute

T₁ = 2π√(0.00001 /9.8) = 0.006347

⇒ f₁ = 1 / T₁  = 1 / 0.006347 = 157.55 ≈ 160 Hz

L₂ = 50 micrometers = 0.00005 m

T₂ = 2π√(L/g)

g = 9.8 m/s

so we substitute

T₂ = 2π√(0.00005 /9.8) = 0.0142

f₂ = 1 / T₂ = 1 / 0.0142 = 70.422 ≈ 70 Hz

Therefore, the frequency range of sound waves is about 70 Hz - 160 Hz

Hence, Option a)  About 70 Hz -160 Hz is the correct answer

We say that the mass comes to rest if, after a certain time, the position of the mass remains within an arbitrary small distance from the equilibrium position. Will the mass ever come to rest

Answers

Answer:

No, the mass will never come to rest

Explanation:

It is so because even at arbitrarily small distance it will experience some amount of force (irrespective of how small the value of force is).

This does not allow the mass to become stationary or in a equilibrium state as it is still subject to some amount of force.

Hence, the the mass will never come to rest

Which of the following is NOT part of the grain group?

Answers

Answer:

Any food made from wheat, rice, oats, cornmeal, barley, or another cereal grain is a grain product. Anything else is not

Explanation:

Jovian planets have rings because:__________.
a. their thick gaseous atmospheres would disintegrate any small rock that enter them
b. there is too much material to have fit into the ball of each planet
c. tidal forces prevent the material in rings from forming into moons
d. Jovian planets rotate very rapidly, and some material near the equator of these planets was flung outward, forming the rings
e. tidal forces cause volcanic eruptions on some moons, and part of this material subsequently escaped the gravity of the moons, forming the rings.

Answers

Answer:

E

Explanation:

Planets after Mars in our solar system are called Jovian planets. Therefore, Jupiter, Saturn, Uranus and Neptune are Jovian planets. The specialty of these planets is that they mostly made of gases and have ring around them.

They have rings around them because tidal forces cause volcanic eruptions on some moons, and part of this material subsequently escaped the gravity of the moons, forming the rings.

assuming weightless pulleys and 100% efficiency, what is the minimum input force required to lift a 120 N weight using a single fixed pulley?

A. 21 N
B. 61 N
C. 121 N
D. 241 N

Answers

May be b I’m not for sure tho

An object A with mass 200 kg and an another object B with mass 1000 kg are moving with same speed. The ratio of kinetic energy of object A to B is

Answers

Answer:

Ratio of kinetic energy of object A to B = 1:5

Explanation:

Given:

Mass of object A = 200 kg

Mass of object B = 1,000 kg

Find:

Ratio of kinetic energy of object A to B

Computation:

Kinetic energy = (1/2)(m)(v²)

Kinetic energy of object A = (1/2)(200)(v²)

Kinetic energy of object A = (100)(v²)

Kinetic energy of object B = (1/2)(1,000)(v²)

Kinetic energy of object B = (500)(v²)

Ratio of kinetic energy of object A to B = Kinetic energy of object A / Kinetic energy of object B

Ratio of kinetic energy of object A to B = (100)(v²) / (500)(v²)

Ratio of kinetic energy of object A to B = 100 / 500

Ratio of kinetic energy of object A to B = 1/5

Ratio of kinetic energy of object A to B = 1:5

Fluid mechanics questions and answers​

Answers

Answer:

Fluid mechanics is considered one of the toughest subdisciplines within mechanical and aerospace engineering. It is unique from almost any other field an undergraduate engineer will encounter. It requires viewing physics in a new light, and that's not always an easy jump to make.

A charged particle (charge 1.6x10-19 C and mass 1.67x10-27 kg) is initially moving with a velocity of 2x105 m/s and then moves into a region having a magnetic field and an electric field (6x104 V/m). The direction of initial velocity is perpendicular to the electric field and magnetic field. If the charged particle keep moving in the original direction without being deflected, what is the magnitude of the magnetic field

Answers

Answer:

[tex]0.3\ \text{T}[/tex]

Explanation:

q = Charge = [tex]1.6\times 10^{-19}\ \text{C}[/tex]

m = Mass of particle = [tex]1.67\times 10^{-27}\ \text{kg}[/tex]

v = Velocity = [tex]2\times 10^5\ \text{m/s}[/tex]

E = Electric field = [tex]6\times 10^4\ \text{V/m}[/tex]

B = Magnetic field

Magnetic field is given by

[tex]B=\dfrac{E}{v}\\\Rightarrow B=\dfrac{6\times 10^4}{2\times 10^5}\\\Rightarrow B=0.3\ \text{T}[/tex]

The magnitude of magnetic field is [tex]0.3\ \text{T}[/tex]

The driver of a car wishes to pass a truck that is traveling at a constant speed of 19.3 m/s . Initially, the car is also traveling at a speed 19.3m/s and its front bumper is a distance 25.0m behind the truck's rear bumper. The car begins accelerating at a constant acceleration 0.560m/s^2 , then pulls back into the truck's lane when the rear of the car is a distance 26.5m ahead of the front of the truck. The car is of length 4.50m and the truck is of length 20.7m .
Part A) How much time is required for the car to pass the truck?
Part B ) What distance does the car travel during this time?
Part C) What is the final speed of the car?

Answers

Answer:

A)    t = 10.56 s, B)  x = 235 m, C) v = 25.2 m / s

Explanation:

A) We can solve this problem using kinematics expressions.

The distance traveled by the truck is

       x_c = v_c t

Distance traveled by the car.

The car must travel the distance that separates them from the truck x₀=25.0.   Return to the lane at x₁ = 26.5 m. the length of the truck x₂=20.7m and the length of the car x₃ = 2  4.5 = 9 m, therefore the total length traveled by the car is

          x_t = x₁ + x₂ + x₃

          x_t = 26.5 + 20.7 +9 = 56.2 m

the distance traveled by the car when it returns to the lane is

         x_c + x_t = x₀ + v₀ t + ½ a t²

when the car passes the car the distance traveled by the two vehicles is the same, we substitute

         v_c  t + x_t = x₀ + v₀ t + ½ a t²

         ½ a t² + t (v₀ -v_c) + (x₀ - x_t) = 0

we substitute the values

         ½ 0.560 t² + t (19.3 -19.3) + (25.0 - 56.2) =

         0.28 t² -31.2 = 0

         t = [tex]\sqrt{ \frac{31.2}{0.28} }[/tex]

         t = 10.56 s

This is the time it takes for the car to pass the truck and back into the lane.

B) the distance traveled is

        x = v₀ t + ½ a t²

        x = 19.3 10.56 + ½ 0.560 10.56²

        x = 235 m

C) the final velocity is

         v = v₀ + a t

         v = 19.3 + 0.560 10.56

         v = 25.2 m / s

The plates of a capacitor are charged using a battery, and they produce an electric field across the separation distance d between them. The two plates are now to be pushed together to a separation of d/2. The pushing together can be done either with the battery connected or with it disconnected. In which case, with the battery connected or disconnected. Is the electric field magnitude greater with the battery connected with the battery disconnected?

Answers

Answer:

Explanation:

The equation of the capacitance of the capacitor can be represented as:

[tex]C = \dfrac{\varepsilon_oA}{d}[/tex]

Also, the electric field between the plates  can be expressed as:

[tex]E = \dfrac{\sigma}{\varepsilon_o}[/tex]

[tex]= \dfrac{Q}{A \varepsilon _o} \ \ (surface \ charge\ density \ \sigma =\dfrac{Q}{\varepsilon_o})[/tex]

However;

when pushed to a distance d/2, the new capacitance of the capacitor is:

[tex]C = \dfrac{\varepsilon _oA}{(d/2))}[/tex]

[tex]=\dfrac{2 \varepsilon_oA}{d}[/tex]

[tex]=2C \\ \\ Q' = CV \\ \\ = 2CV \\ \\ =2Q[/tex]

SImilarly, the new electric field between the plates is:

[tex]E' = \dfrac{\sigma'}{\varepsilon_o} \\ \\ = \dfrac{Q'}{A \varepsilon_o} \\ \\ = \dfrac{2Q}{A \varepsilon_o} \\ \\ =2E[/tex]

For Battery disconnected:

The electric field between the plates doesn't rely upon the distance between the plates yet relies upon the magnitude of the charge. At the point when the battery is detached, the charge on the capacitor stays as before, so does the electric field.  

Therefore, the magnitude of the electric field when the battery is associated is twice however much the magnitude of the electric field when the battery is separated and disconnected.

Hence, the ratio is :

[tex]\dfrac{E_{connected}}{E_{disconnected}} =\dfrac{2E}{E} \\ \\ \dfrac{E_{connected}}{E_{disconnected}} = 2[/tex]

Hence, the ratio is = 2

question is included in the picture!!! PUT REAL ANSWERS OR I WILL REPORT YOU​

Answers

Answer:

Explanation:

this is like rubbing a balloon on your head to make your hair stand up.  Do that to the can.    The balloon is filled , ofc,  and then just rub the balloon on the can.  This will charge the can with static electricity.   :P

A 101 kg basketball player crouches down 0.380 m while waiting to jump. After exerting a force on the floor through this 0.380 m, his feet leave the floor and his center of gravity rises 0.920 m above its normal standing erect position. (a) Using energy considerations, calculate his velocity (in m/s) when he leaves the floor. m/s (b) What average force (in N) did he exert on the floor

Answers

Answer:

[tex]4.25\ \text{m/s}[/tex]

[tex]3391.22\ \text{N}[/tex]

Explanation:

y = Height of compression = 0.38 m

m = Mass of basketball player = 101 kg

h = Height of center of gravity after jump = 0.92 m

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Energy balance of the system is given by

[tex]mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 0.92}\\\Rightarrow v=4.25\ \text{m/s}[/tex]

The velocity of the player when he leaves the floor is [tex]4.25\ \text{m/s}[/tex]

[tex]Fy=mgy+\dfrac{1}{2}mv^2\\\Rightarrow F=\dfrac{mgy+\dfrac{1}{2}mv^2}{y}\\\Rightarrow F=\dfrac{101\times 9.81\times 0.38+\dfrac{1}{2}\times 101\times 4.25^2}{0.38}\\\Rightarrow F=3391.22\ \text{N}[/tex]

The force exerted on the floor is [tex]3391.22\ \text{N}[/tex].

I need help please someone !!!!! Would appreciate it

Answers

Answer:

Yes, it would make it back up.

Explanation:

If it has 100,000 Joules of gravitational potential energy at the top of the hill, by the time the cart gets to the bottom, it will become PE = 0, KE = 90,000 since 10% of 100,000 is 10,000. The cart only requires 80,000J to climb back up so it should easily do so.

I didn't quite understand if the 10% energy loss is total, or every time it goes up or down, but it isn't a problem because 10% of 90,000 is 9,000, which means it would have 81,000J of energy on the way back up IF it loses energy due to friction on the way back up also.

The only physical law you need to prove this is the Law of Conservation of Energy: no energy is lost, only transformed; 10% of the energy becomes heat, the rest remains mechanical energy, which is the reason why the reasoning above works.

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Rank these objects in order of their resistance to change in motion (from greatest to least).
A. pyramid, cone, sphere, cube
B. cube, pyramid, cone, sphere
C. sphere, cone, pyramid, cube
D. None of the above

Answers

Answer:

pyramid, cone, sphere, cube

what happens during subduction

Answers

Answer:

Subduction , Latin for "carried under," is a term used for a specific type of plate interaction. It happens when one lithospheric plate meets another—that is, in convergent zones —and the denser plate sinks down into the mantle.

A light bulb has a resistance of 360 . What is the current in the bulb when it has a potential difference of 120 V across it? 0.33 A 3 A 480 A 43,200 A

Answers

Answer:

I=R×V

360×120 V

=43,200 A

Answer:

A.)0.33 A

Explanation:

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1. According to the results of your study, what increases withgreater stress?O A. Optimal health measuresB. Risk of heart diseaseC. Emotional wellnessD. Brain fitness TRAY A tray in a school cafeteria has the dimensions shown. Find the area of the tray. In a lottery, the top cash prize was $642 million, going to three lucky winners. Players pick five different numbers from 1 to 53 and one number from 1 to 46. A player wins a minimum award of $400 by correctly matching two numbers drawn from the white balls (1 through 53) and matching the number on the gold ball (1 through 46). What is the probability of winning the minimum award? :Which is one quality of the entire open-ocean zone?few nutrientslow pressureample sunlightvarying salinity how many moles of sodium phosphate are required to make 7.5 moles of sodium nitrate in 2Na3PO4+3Be(NO3)=6NanO3+Be3(PO4)2 Which is greater 20.903 or 2.209TELL CORRECT A bag of marbles is hanging motionless on a spring scale. What prevents the bag from falling? AB is a midsegment of trapezoid DEFG what is x? Main idea of passage When Juliet arrives in the Friars cell, she threatens to stab herself; what does this mirror from earlier in the play? Directions: Write the similarities and differences of bias and prejudice inthe images below using the Venn diagram. 7. Read the description of the Ottoman Empire.The Ottoman Empire was an important Islamic empire thatlasted from 1299 to 1923. It was known as a "gunpowder empire"because it used advanced military weapons to build andmaintain its influence. At the height of its power, it covered muchof southeastern Europe, Central Asia, and North Africa. Itincluded a powerful central government, state-run educationaland judicial systems, and a strong and ruthless military that usedslaves as the basis for its manpower. It became powerful in partbecause of its geographic position at the center of trade betweenEurope and Asia.In a three-paragraph response, explain how a historian might use each of theorganizing principles of region, period, and theme to construct a historical narrativeof the Ottoman Empire. What questions might the historian ask? What is one valueand one potential limitation of each approach? Be sure to clearly develop andorganize your ideas. (10 points) HELP ME PLS! Customers at the gym pay a membership fee to join and then a fee for each class they attend. Here is a graph that represents the situation Bobbi is maintaining a campfire. She has kept the fire steadilyburning for 12 hours with 18 logs. She wants to know how manyhours she could have kept the fire going with 9 logs. She assumes alllogs are the same. How many hours can Bobbi keep the fire goingwith 9 logs?PLEASE HELPPP!!!! plz helpFor this assignment you will continue your understanding of how to write a synthesis essay by writing a "mini research paper." You will research political cartoons or another form of visual rhetoric, choose two on one subject and then research an article on the same subject. Using these three documents, synthesize them into a cohesive 500 word essay which explains each, and concludes with your own perspective on the subject. Cite all your sources and include a Works Cited page using MLA form. As you write, remember that essays will be graded with a six-point rubric based on the AP* nine-point scale. High-scoring essays will demonstrate that the writer considered the prompt carefully and responded to it insightfully with strong supporting evidence. These essays will also exhibit stylistic sophistication, including purposeful organization, precise diction, and engaging syntax. Whether or not the essay is timed, conforming to the conventions of standard American English is expected. You may use any of the tools available to you, such the Checklist, Spellchecker, or Graphic Organizer English 11-what did members of the lost generation share?a) a childhood marked by poverty and despairb) direct export ended with WW1 c) personal involvement with organized crime d) knowledge of advance tech What figurative language would this be considered?My heart leaps in my throat Plz help Im bad at math Puget Sound Divers is a company that provides diving services such as underwater ship repairs to clients in the Puget Sound area. The companys planning budget for May appears below: Puget Sound Divers Planning Budget For the Month Ended May 31 Budgeted diving-hours (q) 350 Revenue ($390.00q) $ 136,500 Expenses: Wages and salaries ($11,100 + $120.00q) 53,100 Supplies ($5.00q) 1,750 Equipment rental ($2,500 + $25.00q) 11,250 Insurance ($4,100) 4,100 Miscellaneous ($520 + $1.42q) 1,017 Total expense 71,217 Net operating income $ 65,283 During May, the companys actual activity was 340 diving-hours. Required: Prepare a flexible budget for May. (Round your answers to the nearest whole number.) ESTIONSDiscuss FOUR phases of business cycle in detail