Is steel considered matter

Momentum = (mass) x (speed)

We don't know the mass of the bowling ball, but we know how much it weighs.  So if we knew the acceleration of gravity in the place where the ball is, we could calculate its mass.  The question doesn't tell us what planet the bowling ball is on.  So if we only use the information given in the question, there's no way to find the answer, and we're stuck here.

But I urgently need the points, so I'm going to go out on a limb here and make a big assumption:  I'll assume that the alley where this ball is rolling and bowling is located on planet Earth, where the acceleration  of gravity is around  9.8 m/s²  everywhere on the planet's surface.  NOW I can go ahead and answer the question that I just invented.

weight = m  g

Mass = (weight) / (g)

Mass = (78.0 N) / (9.8 m/s²)

Mass = 7.96 kilograms

Momentum = (mass) x (speed)

Momentum = (7.96 kg) x (8.00 m/s)

Momentum = 63.7 kg-m/s

Explanation:

It is given that,

The position of a particle is given by :

[tex]r(t)=(3t^2i+5j-6tk)\ m[/tex]

(a) Velocity of a particle is given by :

[tex]v=\dfrac{dr(t)}{dt}[/tex]

Putting values,

[tex]v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s[/tex]

The acceleration of the particle is given by :

[tex]a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2[/tex]

(b) At t = 0,

Velocity, v = 6k m/s

Acceleration, a = 6i m/s²

Answer:

plz give the question... floor the proper answer

Explanation:

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me and follow ma

Explanation:

(a) The car will leave tangentially to the road, so it will take path d.

(b) Sum of forces on the car in the vertical direction:

∑F = ma

N − mg = 0

N = mg

Sum of forces on the car in the centripetal direction:

∑F = ma

Nμ = m v²/r

mgμ = m v²/r

gμ = v²/r

v = √(grμ)

The maximum velocity is independent of mass, so adding sandbags will not work.

Explanation:

...................,..........

Newton's first law states that at rest the sum of the forces acting on a body is zero

The distance S to which the painter can climb is approximately 2.55 meters

The reason the above value for the distance is correct is as follows:

The given parameter are;

The mass of the painter, m₁ = 90 kg

Length of the ladder, l = 4 m

The mass of the ladder, m₂ = 15 kg

The coefficient pf static friction, μ = 0.25

Friction force, [tex]\mathbf{F_f}[/tex] = Normal reaction, N × μ

Normal reaction (flat surface), N = Weight of painter + Weight of ladder

N = m₁·g + m₂·g

Where;

g = The acceleration due to gravity, g = 9.81 m/s²

N = 90 kg × 9.81 m/s² + 15 kg × 9.81 m/s² = 1,030.05 N

∴ [tex]\mathbf{F_f}[/tex] = 1,030.05 N × 0.25 = 257.5125 N

Friction force, [tex]\mathbf{F_f}[/tex] = 257.5125 N (Horizontal force)

At equilibrium, the sum of the  horizontal forces = 0

∴ Fₓ + [tex]\mathbf{F_f}[/tex] = 0

Fₓ = [tex]-F_f[/tex] = -257.5125 N (Acting opposite to the direction of the friction force)

The height of the top of the ladder from the ground, h = √(4²-1.5²) = √(13.75)

Taking moment about point A gives;

Clockwise moment = Anticlockwise moment

Fₓ × h = m₁·g·s·cos(θ) + m₂·g·(l/2)·cos(θ)

Therefore;

Fₓ × √(13.75) m = 90 kg × 9.81 m/s² × s × (1.5/4) + 15 kg × 9.81 m  × 2 m × (1.5/4)

Fₓ × √(13.75) m = 331.0875 N × s + 110.3625 J

257.5125 N × √(13.75) m = 331.0875 N × s + 110.3625 J

s = (257.5125 N × √(13.75) m - 110.3625 J)/(331.0875 N) ≈ 2.55 m

The distance to which the 90 kg painter can climb without causing the 4 m ladder to slip at its lower end, A, distance S ≈ 2.55 meters

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Answer:Critical Thinking

Explanation:

7.2 in college success text back

Answer:

1. Golf ball is in the range of only particulate detectable range

2, alpha partcle is in ultraviolet range of wavelength

3.bullet is in xray range of wavelength

All in the EMW spectrum

Answer:

A- 12 km

B- 42 minutes

C- 17.14 km per hour

Explanation:

A- The displacement of the total trip is 12 kilometers, which emerges by adding the 10 kilometers traveled by car to the 2 kilometers traveled on foot.

B- The trip, in total, took 42 minutes, which arises from adding the 30 minutes of the journey on foot, plus 12 minutes of travel by car at 72 km / h (72/60 x 10 = 12).

C- While 12 km were covered in 42 minutes, the average speed of the trip was 17.14 km / h. This arises from the following calculation:

42 = 12

60 = X

(60 x 12) / 42 = X

17.14 = X

Answer:

Resultant = 13km

Direction = 67.38° East of North

Explanation:

Given the following :

5km North ; 12km East

Resultant Displacement (r) :

r² = 5² + 12²

r² = 25 + 144

r² = 169

r = √169

r = 13

Direction:

Tangent = opposite / Adjacent

Tanθ = opposite / Adjacent

Opposite = 12 ; adjacent = 5

Tanθ = (12/5)

Tanθ = 2.4

θ = tan^-1(2.4)

θ = 67.38° east of north

Answer:

A) When a wave goes through a substance, _______________ has occurred.

This is refraction or transmission.

Refraction refers to the changes in the wave that occur when it enters a new medium, in this case, the substance.

Transmission refers to the transfer of energy that is now in the medium.

Usually, we have both of those together.

B) When a wave gets trapped or stuck in a substance, ______________ has occurred.

This is total internal reflection. This happens when, by the Snel Law, the angle of the transmited wave is 90° (or larger) which is traduced in no transmitted wave, this is why the wave is "trapped" in the substance.

C) When a wave bounces off of a surface, ______________ has occurred.

This is reflection.

D) The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.

This is the Law of Reflection, that says "when light is reflected from a surface, the angle of reflection is the same as the angle of incidence"

Answer:

8125

Explanation:

[tex]P=0,13 N\\a=1,6 N/kg\\m=P/a=0,13/1,6=0,08125\\V=10(cm)^{3} =10^{-5} meters^{3} \\p=m/V=0,08125/10^{-5} =0,08125*100000=8125kg/meters^{3}[/tex]

Answer:

1. a = 9.8 m/s²

2. t = 4.28 s

3. Vf = 42 m/s

4. Vf = 28 m/s  

Explanation:

1.

Since, the body is under free fall motion. Therefore, the value of its acceleration shall be equal to the acceleration due to gravity.

a = 9.8 m/s²

2.

The time taken by the ball to reach the ground can be calculated by using second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 90 m

Vi = initial velocity = 0 m/s

t = time taken = ?

Therefore,

90 m = (0 m/s)t + (1/2)(9.8 m/s²)t²

t = √(18.36 s²)

t = 4.28 s

3.

In order to find final velocity we use first equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(4.28 s)

Vf = 42 m/s

4.

when the ball is at height of 50 m, it means it has covered:

h = 90 m - 50 m = 40 m

we use third equation of motion at this point:

2gh = Vf² - Vi²

(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²

Vf = √(784 m²/s²)

Vf = 28 m/s

Answer:

[tex]A=90^0-B\\B+C=180^0-90^0=90^0\\C=90^0-B\\A=C[/tex]

Explanation:

Answer:

Newton's first law

Explanation:

Newton's first law of motion says, that an object will stay in its current motion, unless if a force acts upon it.

So an object already at rest, will stay at rest. And the ball rolling will keep rolling, if no other force such as friction slows it down.

Answer:

a) we can form a triangle in order to use the Pythagorean theorem = 3² + 1² = h²

h² = 9 + 1 = 10

h = √10

h = 3.1623 blocks

we must also find the angle at the initial point of the triangle (A):

tan⁻¹ (1/3) = 18.43°    

the position relative to her starting position is 90° - 18.43° = 71.57° north of east

b) total distance traveled = 6 + 3 + 7 = 16 blocks

Explanation:

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.2 m/s²

Find: v

The problem does not involve time.  Therefore, the required equation is:

v² = v₀² + 2aΔx

Plug in values and solve:

v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)

v = 4.47 m/s

The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity (which is 0 in this case as the car starts from rest)

a = acceleration

s = distance traveled

Plugging in the values into the equation:

v² = 0² + 2(0.2)(50)

v² = 0 + 20

v² = 20

Taking the square root of both sides:

v = √20

v = 4.47 m/s

Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

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Answer:

240 meters

Explanation:

He is walking 2 meters per second, and there are 60 seconds per minute. There are 120 seconds in two minutes. So, 120 x 2 = 240. That's your answer!

Answer:

mass of the block is 7.2Kg

Tension on string A = 72N

Tension on the string with an angle is =  108N

Explanation:

The Horizontal string will have the cos component of the force...

Hence, mg cos60 = 36

by keeping acceleration due to gravity = 10 m/s^2, we get,

m = 7.2Kg

The tension in String A = mg = 7.2*10 = 72N

since the whole string holding the block is pulled by another string with 36 N

the resultant force will be the tension of the string with an angle.

Hence, 72 +36 = 108 N

Please let me know whether I got this right or not...

Answer:

A. Dependent variable

Explanation:

In a graph showing how temperature of a material changes over time, temperature is taken on y-axis and time is taken on x-axis. It shows how temerature altered as the time changes.

In temperature-time graph, temperature is directly dependent on time. With the increase in time, temperature rises, falls or remains constant. It implies that temperature is dependent variable that depend on time.

Hence, the correct option is (A).

Answer:

This question appears incomplete

Explanation:

The question appears incomplete. However, a thrust can be described as a force or a push. A cart can be described as a vehicle (usually with two wheels) that is used to transport load from one point/place to another.

Newton first law of motion (law of inertia) states that a body will continue to be in a state of rest or if in motion, remains in motion (at constant velocity) unless acted upon by an external force. Hence, a cart will continue to be in a state of rest unless acted on by an external force which can be exerted by animals or humans (depending on the type of cart).

Answer:

the full segment is:  30 units long

which coincides with answer C in your list

Explanation:

If M is the midpoint, then it divides the segment in two equal parts. Then, we can say that:

RM = MS (equality among the two parts of the divided segment)

replacing RM with "5 x" and MS with "x + 12", we get:

5 x = x + 12

solving for x:

5 x - x = 12

4 x = 12

then x = 3

With this info, we can calculate the length of each half of the segment and consequently its full length:

RM = 5 x = 5 (3) = 15

then the full segment is:  30 units long

Answer:

C

Explanation:

The 15N object has more mass than the 10N object.

A 15 N object has more mass than the 10 N object due to their weight differences.

Weight is defined as the force exerted by the earth on an object on the surface of earth. The direction of this force is directed towards the center of earth. Mathematically -

W = mg

Where -

m is the mass of body

g is the acceleration due to gravity

Weight can also be written as -

W = ρVg     [ρ is density and V is volume]

Given is a person who dropped two objects from the same height. One object weighs 15 N and the other weighs 10 N.

We can write -

Weight of Object 1 [W1] = 15 N

Weight of Object 2 [W2] = 10N

We know that -

W = m x g

We can write it as -

m = W/g

Therefore -

Mass of Object 1 [M1] = 15/9.8 = 1.53 Kg

Mass of Object 2 [M2] = 10/9.8 = 1.02 Kg

Clearly -

M1 > M2

So, the 15 N object has more mass than the 10 N object.

Therefore, a 15 N object has more mass than the 10 N object due to their weight differences.

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Answer:

R = 52.08 cm

Explanation:

given data

tangential velocity v = 21.3 m/s

radial acceleration aR = 871 m/s²

solution

we will get here length of her arm from the pivot point at her shoulder so

here we know aR = [tex]\frac{v^2}{R}[/tex]     ........................1      

so put here value and we get

871 = [tex]\frac{21.3^2}{R}[/tex]  

R = 0.5208840 m

R = 52.08 cm

Answer:

Explanation:

linear speed of ball v = 21.3 m /s

radial acceleration = 871 m /s²

radial acceleration = v² / R

where R is length of arm which acts as radius of circular path of the ball .

Putting the values

21.3² / R = 871

R = .52 m.

Answer:

Explanation:

If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule

to derive the radius of the path of the charge we apply

F= mv^2/r=Bev

where

m= mass of the electronic charge

e=charge

B=magnetic field

v=average speed

r=radius

rearranging we have

r=mv^2/Bev

r=mv/Be

Answer:

An elements atomic number will never change, that is because the atomic number is its "identity."

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

Answer:

Explanation:

Let the internal resistance be r .

Since in open circuit the volt is 1.55 V , this will be the source voltage .

Source voltage = 1.55

If external resistance be R .

1.55 / (R + r ) = .500

R + r = 3.1 ohm

So sum of internal resistance and external resistance will be 3.1 ohm.

Answer:

towards the center of the circle

(which appears to be the last option in your list of possible answers)

Explanation:

The centripetal force points always towards the center of the circle described by the object moving.

The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.

The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.

Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.

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Answer:

c

Explanation:

Answer:

the answer is c i just did it

Explanation: