Is it possible for a diprotic acid to have Ka1?

Answers

Answer 1

Answer:

Yes, it is possible.

Explanation:

A diprotic acid is an acid that can release two protons. That's why it is called diprotic.

Monoprotic → Release one proton, for example Formic acid HCOOH

Triprotic → Releases three protons, for example H₃PO₄

Polyprotic → Release many protons, for example EDTA

it is a weak acid.

In the first equilibrum, it release proton, and the second is released in the second equilibrium. So the first equilibrium will have a Ka1

H₂A  +  H₂O  ⇄  H₃O⁺  +  HA⁻                Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺  +  A⁻²               Ka₂

The HA⁻ will work as an amphoterous because, it can be a base or an acid, according to this:

HA⁻   +  H₂O  ⇄  H₃O⁺   + A⁻²      Ka₂

HA⁻   +  H₂O  ⇄  OH⁻   + H₂A       Kb₂


Related Questions

When measuring solid NaOH in pellet form, explain why you won’t be able to measure exactly 1.000 grams. What are the consequences of this?

Answers

Answer:

Explanation:

Pellet form of NaOH is highly hygroscopic . It absorbs moisture from air and its weight is increased by the time one tries to weigh one gram of it . Moreover it also reacts with carbon dioxide gas of atmosphere to form sodium carbonate .

2 NaOH + CO₂ = Na₂CO₃ + H₂0.

It also increases its weight .

An unknown substance from planet X has a density of 10 g/ml. It occupies a volume of 80 ml. What is the mass of this unknown substance? *

Answers

Answer:

The answer is

800 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

density = 10 g/ml

volume = 80 ml

The mass of the substance is

mass = 10 × 80

We have the final answer as

800 g

Hope this helps you

13 C4- has _______ electrons.​

Answers

Answer:

10 electrons

Explanation:

What is the answer? Please

Answers

Answer:

true

Explanation:

what is the answer? please

What angle is needed to spread 4 bonds as far apart as possible?

Answers

Answer:

109°

Explanation:

According to Valence Shell Electron Pair Repulsion Theory, electron pairs on the valence shell of the central atom of a molecule must be positioned as far apart in space as possible to minimize repulsion between valence shell electron pairs.

The shape of a molecule depends on the number and type of electron pairs on the valence shell of its central atom. Lone pairs generally cause more repulsion than bond pairs of electrons.

The ideal bond angle for a molecule with four bonds is 109° which corresponds to a tetrahedral geometry. This enables the four bonds to spread as far apart in space as possible.

Express 2.99 x 108 m/s (the speed of light) in decimal notation (i.e., express the

number without using scientific notation

Answers

Answer:

speed of light = 299,000,000 m/s

Explanation:

The speed of light in vacuum, denoted as c,  is a universal physical constant which unlike space and time, is independent of the observer. It is a constant that is important in many fields of science. Its exact value is given as 299,792,458 metres per second.

In scientific notation, it is approximately given as 2.99 x 10⁸ metres per second.

2.99 x 10⁸ metres per second = 2.99  x 100000000 = 299,000,000 m/s

Therefore, when expressed in decimal notation, the speed of light = 299,000,000 m/s.

Be sure to answer all parts. Calculate the mass of each product formed when 70.76 g of diborane (B2H6) reacts with excess water: B2H6(g) + H2O(l) → H3BO3(s) + H2(g) [unbalanced] Mass of H3BO3: g Mass of H2: g

Answers

Answer:

A. 313.37 g of H3BO3.

B. 30.33 g of H2.

Explanation:

We'll begin by writing a balanced equation for the reaction. This is given below:

B2H6 + 6H2O → 2H3BO3 + 6H2

Next, we shall determine the mass of B2H6 that reacted and the masses of H3BO3 and H2 produced from the balanced equation equation. This can be obtained as follow:

Molar mass of B2H6 = (2×11) + (1×6) = 22 + 6 = 28 g/mol

Mass of B2H6 from the balanced equation = 1 × 28 = 28 g

Molar mass of H3BO3 = (1×3) + 11 + (3×16) = 3 + 11 + 48 = 62 g/mol

Mass of H3BO3 from the balanced equation = 2 × 62 = 124 g

Molar mass of H2 = 2×1 = 2 g/mol

Mass of H2 from the balanced equation = 6 × 2 = 12 g

From the balanced equation above:

28 g of B2H6 reacted to produce 124 g of H3BO3 and 12 g of H2.

A. Determination of the mass of H3BO3 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

28 g of B2H6 reacted to produce 124 g of H3BO3.

Therefore, 70.76 g of B2H6 will react to produce = (70.76 × 124)/28 = 313.37 g of H3BO3.

Therefore, 313.37 g of H3BO3 were obtained from the reaction.

B. Determination of the mass of H2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

28 g of B2H6 reacted to produce 12 g of H2.

Therefore, 70.76 g of B2H6 will react to produce = ((70.76 × 12)/28 = 30.33 g of H2.

Therefore, 30.33 g of H2 were obtained from the reaction.

The elemental analysis of an organic solid extracted from gum arabic showed that it contained 40.0% C, 6.7% H, and 53.3% O. A solution of 0.650 g of the solid in 27.8 g of the solvent diphenyl gave a freezing point depression of 1.56 °C. Calculate the molar mass and determine the molecular formula of the solid (kf for diphenyl is 8.00 °C/m). To earn full credit, clearly show your work with units and proper significant figures

Answers

Answer:

The molar mass of the organic solid is 119.9g/mol.

The molecular formula of an organic solid is C4H8O4

Explanation:

Step 1

We find the Molar mass

From the above question, we are given:

A solution of 0.650 g of the solid in 27.8 g of the solvent diphenyl gave a freezing point depression of 1.56 °C. Calculate the molar mass and determine the molecular formula of the solid (kf for diphenyl is 8.00 °C/m)

A freezing point depression = 1.56 °C.

Mass of organic solid= 0.650 g

Mass of diphenyl = 27.8 g

Converting to kilograms

1000g = 1kg

27.8g =

Cross Multiply

= 27.8g × 1 kg/1000g

= 0.0278kg

Boiling point constant = 8.00 °C/m

Molar mass of the organic compound = Boiling point constant × Mass of solid /Freezing point depression × Mass of diphenyl

Molar mass of the organic compound =

8.00 °C/m × 0.650g/1.56°C × 0.0278kg

= 5.2 g°C/m ÷ 0.043368 g°C

= 119.9040767 g/mol

Approximately = 119.9 g/mol

Step 2

Find the Molecular formula

Molecular formula = CxHyOz

Let x = Carbon, y = Hydrogen, z = Oxygen

For x = Carbon

Atomic mass of Carbon = 12.01078

x = % of Carbon in the compound × Molar mass of the organic compound/atomic mass of Carbon

x = 40% × 119.9 g/mol / (12.01078

x = 3.99

x = Approximately = 4

For y = Hydrogen

Atomic mass of Hydrogen = 1.007947

y = % of Hydrogen in the compound × Molar mass of the organic compound/Atomic mass of Hydrogen

x = 6.7% × 119.9 g/mol) / 1. 007947

x = 7.97

x is Approximately = 8

For z = Oxygen

Atomic mass of Oxygen = 15.99943

z = % of Oxygen in the compound × Molar mass of the organic compound/Atomic mass of Oxygen

z = 53.3% × 119.9 g/mol /15.99943

z = 3.99

z is approximately ≈ 4

Therefore,

The molar mass of the organic solid is 119.9 g/mol.

The molecular formula of an organic solid is C4H8O4

A peregrine falcon dives 176 meters through the air in 8 seconds. Its
average speed during the dive is 22 m/s. *

Answers

Answer:

This question is asking to find the average speed during the dive. The answer is 22m/s.

Explanation:

Average speed of a substance can be calculated knowing it's distance over a particular amount of time.

The formula for average speed is:

Average speed (s) = Distance (d) / time (t)

In the case of this question where A peregrine falcon dives 176 meters through the air in 8 seconds, the distance of the falcon is 176m, while the time is 8s. Hence;

Average speed = 176/8

Average speed = 22

Therefore, the average speed of the falcon diver is 22m/s.

How many grams are there in 1.00x10 24 molecules of BCI3

Answers

Answer:

194.569 g

Explanation:

6.022×10^23 molecules = 117.17 g

1 molecules = 117.17/ 6.022×10^23

So, 1×10^24 molecules = (117.17×1×10^24)/(6.022×10^23)= 194.569 g

From a 2.875 g sample containing only iron, sand, and salt, 0.660 g of iron and 1.161 g of sand were separated and recovered. What was the percent of salt in the original sample

Answers

Answer:

36.66%

Explanation:

Step 1: Given data

Mass of iron: 0.660 gMass of sand: 1.161 gMass of the sample: 2.875 gMass of salt: ?

Step 2: Calculate the mass of salt

The mass of the sample is equal to the sum of the masses of the components.

m(sample) = m(iron) + m(sand) + m(salt)

m(salt) = m(sample) - m(iron) - m(sand)

m(salt) = 2.875 g - 0.660 g - 1.161 g

m(salt) = 1.054 g

Step 3: Calculate the percent of salt in the sample

We will use the following expression.

%(salt) = m(salt) / m(sample) × 100%

%(salt) = 1.054 g / 2.875 g × 100% = 36.66%

The percent of salt in the original sample containing only iron, sand, and salt is 36.66%.

What is salt?

Salt is a mineral made up of primarily sodium chloride.

Seawater contains a vast amount of salt.

Given,

The total mass of the sample is 2.875 g

Mass of iron is  0.660 g

Mass of sand is 1.161 g

Step 1: To find the mass of salt

The total mass of the sample = the sum of the masses of the compounds

m(sample) = m(iron) + m(sand) + m(salt)

2.875 g =  0.660 g + 1.161 g + m(salt)

m(salt) = 2.875 g - 0.660 g - 1.161 g

m(salt) = 1.054 g

Step 2: Calculate the percent of salt in the sample

[tex]\%(salt) = \dfrac{m(salt) }{m(sample)} \times 100\%\\\\\\\%(salt) = \dfrac{1.054 g }{2.875 g} \times 100\% = 36.66\%[/tex]

Thus, the percentage of salt in the sample is 36.66%.

Learn more about salts, here:

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Which technology has helped improve scientists’ ability to gather scientific data about the movement of sea turtles? satellite tracking thermometers probeware microscopes? ​

Answers

Answer:either satellite tracking or probware.

Explanation:probate. Think its satalite tracking hope this helps.

Answer:

its satellite tracking

Explanation:

i got it right on edge

A pure copper penny contains approximately 2.9×1022 copper atoms. Use the following definitions to determine how many ______ of copper atoms are in a penny. 1doz=12 1gross=144 1ream=500 1mol=6.022×1023 Part A dozens Express your answer in dozens to two significant figures.

Answers

Complete question is;

A pure copper penny contains approximately 2.9 × 10^(22) copper atoms.

1 doz = 12

1 gross = 144

1 ream = 500

1 mol = 6.022 × 10^(23)

Use these definitions to determine the following:

A) How many dozens of copper atoms are in a penny.

B) How many gross of copper atoms are in a penny

C) How many reams of copper atoms are in a penny.

D) how many moles of copper atoms are in a penny?

All answers can be rounded to two significant figures

Answer:

A) 2.4 × 10^(21) dozens

B) 2.01 × 10^(20) gross

C) 5.8 × 10^(19) reams

D) 0.048 mol

Explanation:

A) A dozen contains 12.

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/12 dozens = 2.42 × 10^(21).

In 2 significant figures, we have;

2.4 × 10^(21) dozens

B) 1 gross = 144

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/144 gross ≈ 2.01 × 10^(20) gross

C) 1 ream = 500

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/500 reams = 5.8 × 10^(19) reams

D) 1 mol = 6.022 × 10^(23)

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/(6.022 × 10^(23)) = 0.048 mol

Given sulfur has an electron configuration of 1s22s22p63s23p4, what oxidation numbers would you expect for sulfur? (Hint: Think about how to achieve a full outer shell.)

Answers

Explanation:

1s2 2s2 2p6 3s2 3p4

Oxidation number refers to the number of electrons that an atom gains or loses as it forms a chemical bond with another element.

From the electronic configuration above, it is expected that sulphur has oxidation number of 2. This is because the p orbital can hold a maximum of 6 electrons. However, in the electronic configuration it is just holding 4. To complete it, it needs to gain 2 more electrons.

Answer:

+4, +6, –2

Explanation:

How many atoms are in one body-centered cubic unit cell of a metal?
A) 1.
B) 2.
C) 3.
D) 4.

Answers

Answer:

Option B - 2

Explanation:

In Crystal lattices, there are different types of unit cells namely;

- Hexagonal Closest Packed (HCP)

- Face Centred Cubic (FCC)

- Body Centred Cubic (BCC)

- Simple Centred Cubic (SC)

Now, each of them have a coordination number and also number of atoms per unit cell.

For this question, we are restricted to the body-centered cubic (bcc) unit cell which has a coordination number of 8 and contains 2 atoms per unit cell.

Answer:

B) 2.

Explanation:

They have 8 1/8 atoms on the edge that add to get 1 atom. Plus one whole atom inside. 1+1=2

Why are atoms usually portrayed as spheres when most orbitals are not spherically shaped?
a. The shape of an atom depends on the shape of its nucleus, not on the shape of its orbitals.
b. The shape of an atom depends on the shape of the outer orbital which always spherical
c. The shape of an atom is obtained by superimposing all of its orbitals.
d. The shape of an atom is not important so it is easier to treat atoms as spheres.

Answers

Answer:

The shape of an atom is not important so it is easier to treat atoms as spheres.

Explanation:

In considering the shape of an atom, we do not consider the shape of the orbitals individually.

Hence, we do not seek to determine the exact shape of the atom, rather we simply treat the atom as spheres. Even though most orbitals are not spherically shaped.

Students observed cells under the microscope. They observed that the cells had a cell wall, cell membrane,
nucleus, and many chloroplasts.
Which observation helps students identify the type of cell observed?
A The presence of a nucleus means the cells are from a plant.
B The presence of a cell membrane means that the cells are from an animal.
C The presence of chloroplasts means that the cells are from a plant.
D The presence of a cell wall means that the cells are from an animal.

Answers

Answer:

option B is the right answer

The correct answer is A, because an animal cell doesn’t have a cell wall

A factor that does no change in an experiment is the.

a. Controlled variable
b. Data
c. Inconstant
d. Independent variable

Answers

Answer:

A. Controlled variable

Explanation:

a controlled variable or a constant variable is a variable that doesnt change during an experiment

Convert a speed of 933 cm/s to units of inches per minute

Answers

Answer:

220000 in/min

Explanation:

Step 1: Write out conversions

1 in ≈ 2.54 cm

60 sec = 1 min

Step 2: Set up dimensional analysis

[tex]\frac{933cm}{s} (\frac{60s}{1min} )(\frac{1in}{2.54cm} )[/tex]

Step 3: Evaluate

220039.4 in/min

Step 4: Sig figs

There are 3 sig figs

220039.4 in/min ≈ 220000 in/min

What is the volume of a sample of matter with a density of 6 and a mass of 6 cm3?

Answers

Answer:

We have the final answer as

1.0 cm³

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 6 g

density = 6 g/cm³

It's volume is

[tex]volume = \frac{6}{6} = 1 \\ [/tex]

We have the final answer as

1.0 cm³

Hope this helps you

a nucleus with 4 protons has a positive charge of _____ PLEASE LET ME KNOW

Answers

Answer:

if were talking about berylium then the answer should be 2 because it wants to move 2 spaces back (losing electrons) to become a nobel gas so the answer is 2+

Explanation:

it has 2 valence electrons YW :)    

A nucleus with 4 protons has a positive charge of +2.

What are Protons?

Protons may be defined as the type of sub-atomic particles that are present in the nucleus of an atom along with the neutrons. These sub-atomic particles possess a positive charge in nature. It may be thought that protons are discovered by Ernest Rutherford.

Beryllium has a nucleus with 4 protons, which means that it has an atomic number of 4. This element belongs to the alkaline earth metals in group 2. Beryllium has the capability to lose two electrons in order to attain a noble gas configuration and occupy stability. It has an electronic configuration [tex]1s^2, 2s^2[/tex]. So, in order to make it octet fulfilled, it loses two electrons and becomes positively charged.

Therefore, a nucleus with 4 protons has a positive charge of +2.

To learn more about Protons, refer to the link:

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Complete hydrolysis of a hexapeptide gives 2 Gly, Leu, Phe, Pro, and Tyr. Reaction of the peptide with phenylisothiocyanate gave the phenylthiohydantoin of Pro. Partial hydrolysis of the peptide gave the following fragments: Phe-Gly-Tyr, Gly-Phe-Gly, Pro-Leu-Gly, Leu-Gly-Phe. What is the structure of the peptide

Answers

Answer:

The complete sequence : Pro-Leu-Gly-Phe-Gly-Tyr

Explanation:

For the formation of phenylisothiocyanate, the four peptide sequences overlap common residue to get the the complete sequence of the hexapeptide as shown in the diagram attached below

Attached below is the structure of the peptide

why is a lot of energy needed to break covalent bonds

Answers

Answer:

The strength of a bond between two atoms increases as the number of electron pairs in the bond increases.

Explanation:

chemical test of acetylene in the laboratory​

Answers

Using tweezers a calcium carbide granule is dropped in the water in the container and bubbles of acetylene gas begin to be produced. A test tube full of water is inverted and placed over the evolving gas. The gas displaces the water and the entire test tube fills with acetylene.
Hope that helps


What is heat?
O Fire
O Hot
O Energy
O Potential

Answers

Answer:

Energy

Explanation:

Heat is a form of energy.

What do metaloids share with nonmetals?

Answers

Answer:

Most metalloids have some physical properties of metals and some physical properties of nonmetals. They fall between metals and nonmetals in their ability to conduct heat and electricity. They are shiny like metals but brittle like nonmetals.

Explanation:

If ΔH vaporization of water (H2O) is 40.7 kJ/mol,
and the ΔS for vaporization of H2O is 109 J/mol K,
what is ΔG for water vaporization at 350K?
Include units.

Answers

Answer:

2.6 kJ/mol

Explanation:

Step 1: Given data

Standard enthalpy of vaporization of water (ΔH°): 40.7 kJ/molStandard entropy of vaporization of water (ΔS°): 109 J/mol.KAbsolute temperature (T): 350 KStandard Gibbs free energy of vaporization of water (ΔG°): ?

Step 2: Calculate ΔG°

We can calculate ΔG° using the following expression.

ΔG° = ΔH° - T × ΔS°

ΔG° = 40.7 kJ/mol - 350 K × 0.109 kJ/mol.K

ΔG° = 2.6 kJ/mol

The change in Gibbs free energy, ΔG for the water is 2.55 KJ/mol

Data obtained from the question

From the question given above, the following data were obtained:

Standard enthalpy of vaporization of water (ΔH°) = 40.7 kJ/molStandard entropy of vaporization of water (ΔS°) = 109 J/Kmol = 109 / 1000 = 0.109 KJ/Kmol Absolute temperature (T) = 350 KStandard Gibbs free energy (ΔG°) =?

How to determine the Gibbs free energy, ΔG°

The Gibbs free energy, ΔG° can be obtained as illustrated below:

ΔG° = ΔH° – TΔS°

ΔG° = 40.7 – (350 × 0.109)

ΔG° = 40.7 – 38.15

ΔG° = 2.55 KJ/mol

Learn more about Gibbs free energy:

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A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?

Answers

Answer:

[tex]Sn_2O[/tex]

Explanation:

Hello,

In this case, given the mass of the sample and mass of tin we can compute the mass of oxygen via:

[tex]m_O=0.534g-0.500g=0.034g[/tex]

Thus, by using the atomic bas of tin and oxygen we can compute their moles:

[tex]n_{Sn}=0.500gSn*\frac{1molSn}{118.8gSn} =0.00421mol\\\\n_O=0.034gO*\frac{1molO}{16gO}=0.002125mol[/tex]

Next, we need to divide both moles by the moles of oxygen as those are the smallest in order to compute the subscript in the chemical reaction:

[tex]Sn=\frac{0.00421}{0.002125}=2\\ \\O=\frac{0.002125}{0.002125}= 1[/tex]

Therefore, empirical formula of the oxide should be:

[tex]Sn_2O[/tex]

Best regards.

Complete the chemical combustion reaction of naphthalene, which
demonstrates the conservation of mass.
C10H8 + 1202 >>

Answers

Answer:

[tex]C_{10}H_{8}+12O_2\rightarrow 10CO_2+4H_2O[/tex]

Explanation:

Hello,

In this case, since combustion reactions yield carbon dioxide and water via the following equation:

[tex]fuel+O_2\rightarrow CO_2+H_2O[/tex]

In such a way, for naphthalene, its combustion reaction is:

[tex]C_{10}H_{8}+12O_2\rightarrow 10CO_2+4H_2O[/tex]

Whereas we see ten carbon atoms, eight hydrogen atoms and twenty four oxygen atoms at both reactants and products as a proof of the law conservation of mass.

Regards.

what were the limitations of Dobereiner's classifcation?​

Answers

Answer:

Dobereiner could find only three triads; . i.e total of 9 elements only. However the total number of elements were more than that of those encompassed in Dobereiner's Triad

Explanation:

Answer:

Dobereiner could find only three triads; . i.e total of 9 elements only. However the total number of elements were more than that of those encompassed in Dobereiner's Triad. Thus, Dobereiner's could not be classify most of the elements known at that time

Explanation:

This work is not my own.... copied from google but hope this helps you.

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