Is (3, 5) a solution to this system of equations?
y = 5
Y= -5/3x+10

yes
E

The geometric means of the pairs of numbers are approximately:

14.85 for 7.16 and 27

13.42 for 5 and 36

22.94 for 10.8 and 48.

It should be noted that to find the geometric mean of two numbers, we multiply them together and then take the square root of the result. So, for each pair of numbers, we can follow these steps:

Multiply the two numbers together.

Take the square root of the product.

Using this formula, we get:

7.16 and 27:

Geometric mean = √(7.16 × 27) ≈ 14.85

5 and 36:

Geometric mean = √(5 × 36) = √180 ≈ 13.42

10.8 and 48:

Geometric mean = √(10.8 × 48) ≈ 22.94

Therefore, the geometric means of the pairs of numbers are approximately:

14.85 for 7.16 and 27

13.42 for 5 and 36

22.94 for 10.8 and 48.

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Answer: (440-308) ÷ 22 = The cost of each tool kit is 6 dollars

Step-by-step explanation:

The original price of the field trip was $308 after the price fof each tool kit was added the price was $440.

The total costs of all the tool kits was 132

440-308=132

the total cost of the tool kits divided by the number of kids will get the price of each tool kit

132÷22 =

K=

The distance Ben travels to get to the park is approximately 2.21 times greater than the distance David travels. This is found by using the distance formula to calculate the distances each person travels and then comparing the results.

To solve this problem, we need to find the distance between each person's house and the park using the distance formula

distance = √((x₂ - x₁)² + (y₂ - y₁)²)

For Ben

distance = √((-2 - 4)² + (-2 - 6)²) = √((-6)² + (-8)²) = √(100) = 10

For David

distance = √((-2 - (-7))² + (-2 - (-6))²) = √((5)² + (4)²) = √(41)

So the ratio of Ben's distance to David's distance is

10 / √(41) ≈ 2.21

Therefore, Ben's distance is about 2.21 times greater than David's distance.

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Answer:

Work smartly not hard.

Step-by-step explanation:

AI

The new mixture contains 34% peanuts.

The correct option is A

We have,

Jenny mixed 4 kg of mixed nuts containing 16% peanuts with 12 kg of mixed nuts containing 40% peanuts.

First, Total weight = 4 kg + 12 kg = 16 kg

Now, Total weight in kilograms is =  (4 kg) (0.16) + (12 kg) (0.40)

= 0.64 kg + 4.80 kg

= 5.44 kg.

Now, the Percent of peanuts

= (Total amount of peanuts / Total weight) x 100%

= (5.44 kg / 16 kg) x 100

= 34%

Thus, the new mixture contains 34% peanuts.

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Answer:f/g=29

Step-by-step explanation:

Answer: (f/g)=29

Hope this helps

The percentage of the people that preferred cooking who where surveyed would be = 87.2%

The total number of people surveyed = 8

The total number of people that preferred cooking = 7

The percentage of people that preferred cooking;

= 7/8×100/1

= 700/8

= 87.2%

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With additive inverse and by grouping like terms the simplified form of the expression is 6a²-13ab-b².

The given expression is 3a²-5ab+b²-(-3a²+2b²+8ab).

Here,

3a²-5ab+b²+3a²-2b²-8ab

Group like terms, that is

(3a²+3a²)+(-5ab-8ab)+(b²-2b²)

= 6a²-13ab-b²

Therefore, with additive inverse and by grouping like terms the simplified form of the expression is 6a²-13ab-b².

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The solution to the given composite function is; C: 4x² - 4x - 2

From the question, we are given the individual functions as;

f(x) = x² - 3

g(x) = 2x - 1

Now when it comes to composite functions, we know that;

(f ° g)(x) = f[g(x)]

Substitute the known values in the above equation, so, we have the following representation

(f ° g)(x) = f(2x - 1) = (2x - 1)² - 3 = 4x² - 2x - 2x + 1 - 3 = 4x² - 4x - 2

This is the final solution of the composite function expression.

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The solution to the given composite function is; Option D: 2x² - 7

Composite functions are defined as functions where the output of one function is used as the input of another. Wheb we have a function f and another function g, then the function fg(x), said as “ f of g of x”, is the composition of the two functions.

The given functions are:

f(x) = x² - 3

g(x) = 2x - 1

We want to find (g ° f)(x) . We know that:

(g ° f)(x) = g[f(x)]

Thus:

(g ° f)(x) = g(x² - 3)

= 2(x² - 3) - 1

= 2x² - 6 - 1

= 2x² - 7

This is the final result of the composite function expression.

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The distance from the top of the flagpole to the end of its shadow is approximately 10.02 feet.

Explain the term distance

Distance refers to the measurement of the space between two objects or points. It is typically measured in units such as meters, kilometres, miles, or feet. The distance can be calculated using various methods, including using maps, GPS technology, or mathematical formulas.

According to the given information

We can set up the following proportion:

h / 12 = d / 11

We can cross-multiply to get:

h x 11 = 12 x d

Simplifying further:

d = (h x 11) / 12

We need to solve for d, so we need to find the value of h. Using the Pythagorean theorem, we can set up the following equation:

h² + d² = 12²

Substituting d = (h x 11) / 12, we get:

h² + ((h x 11) / 12)² = 12²

Simplifying:

h² + (121h²) / 144 = 144

Multiplying both sides by 144/265:

265h² / 144 = 144

Solving for h:

h² = (144 x 144) / 265

h = √(20736 / 265)

h = √(78.113)

Now we can substitute this value into our earlier equation to find d:

d = (√(78.113) x 11) / 12

d ≈ 10.02 feet

Therefore, the distance from the top of the flagpole to the end of its shadow is approximately 10.02 feet.

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The value of the variable is 3/2

A fraction cam simply be described as an expression that is being used to represent the part of a whole number, a whole variable or element.

There are different types of fractions. They are listed as;

From the information given, we have that;

-7 4/5 divided by X = -5 1/5

convert to improper fractions, we have;

-39/5/x = -26/5

Now, cross multiply the values, we have;

-39/5 = -26x/5

cross multiply

-130x = -195

Divide both sides

x = -195/-130

x = 39/26 = 3/2

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The P-value is between 0.025 and 0.05. and t = -1.85

On the SAT exam a total of 25 minutes is allotted for students to answer 20 math questions without the use of a calculator.

Therefore tests the hypotheses:

[tex]H_0[/tex] : μ = 25 versus Ha: μ < 25,

where μ = the true mean amount of time needed by students at this school to complete this portion of the exam.

The alternative hypothesis is:

[tex]H_1:\mu < 25[/tex]

The test statistic is given by:

[tex]t=\frac{x-\mu}{\frac{s}{\sqrt{n} } }[/tex]

The parameters are:

the values of the parameters are:

x = 23.5 , [tex]\mu=25[/tex] , s = 4.8, n = 35

Plug all the values in above formula of t- statistic is:

[tex]t = \frac{23.5-25}{\frac{4.8}{\sqrt{35} } }[/tex]

t = -1.85

Using a t-distribution , with a left-tailed test, as we are testing if the mean is less than a value and 35 - 1 = 34 df, the p-value is of 0.0365.

t = –1.85; the P-value is between 0.025 and 0.05.

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number one take the second

Answer: B

Step-by-step explanation:

The word that would indicate that the cat was afraid of the veterinarian is "cowered." "Cowered" means to crouch down in fear or shame. So, the sentence would be: "The cat cowered under the table when the veterinarian came into the examining room."

The correct option is (D) A, B, C, E, G, I

What is the cube?

A cube is a three-dimensional solid shape that has six square faces of equal size. It has twelve edges and eight vertices, and all angles between the faces are right angles. The cube is a regular polyhedron, which means that all its faces are congruent and all its edges have the same length.

The net of a cube is the one that has the faces arranged in such a way that it makes a complete cubic structure

A) In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.

B)  In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.

C) In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.

D) In the given figure, the net can be folded into a cube when its faces are folded one over the other. Therefore, it is a cube net.

Hence, The correct option is (D) A, B, C, E, G, I.

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Thus, new coordinates of A'B'C' after the reflection across the y-axis are-

A'(-5, -1), B'(-3,-4), C'(-3, 0).

The x-coordinate remains constant when a point is reflected across the x-axis, but the y-coordinate is assumed to be the additive inverse. Point (x, y) is reflected across the x-axis as (x, -y).

The y-coordinate stays the same when a point is reflected across the y-axis, but the x-coordinate is assumed to be the additive inverse. Point (x, y) is reflected across the y-axis as (-x, y).

Given coordinates of ABC.

A(5, -1), B(3,-4), C(3, 0)

Reflection across the y-axis : y coordinates remains same while x coordinate multiplied with -1.

(x,y) -- > (-x, y)

A'(-5, -1), B'(-3,-4), C'(-3, 0)

Thus, new coordinates of A'B'C' after the reflection across the y-axis are-

A'(-5, -1), B'(-3,-4), C'(-3, 0).

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Answer:

  D.  9 clubs

Step-by-step explanation:

Given a stem-and-leaf plot of the number of members in clubs, you want to know the number of clubs with 30 or more members.

The plot shows the club membership to be ...

  {10, 13, 15, 24, 26, 30, 36, 39, 50, 55, 59, 61, 66, 78}

The 9 clubs whose member numbers are in bold have at least 30 members.

The number of clubs with at least 30 members is ...

  D.  9 clubs

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Applying the intersecting secants theorem, the value of x is calculated as: x = 5.

According to the intersecting secants theorem, if two secant lines intersect outside of a circle, then the product of the length of one secant segment and its external segment is equal to the product of the length of the other secant segment and its external segment.

Using the theorem, the equation below is created to find the value of x:

4(4 + 5) = (x - 2)(x - 2 + x + 4)

4(9) = (x - 2)(2x + 2)

36 = 2x² - 2x - 4

2x² - 2x - 4 - 36 = 0

2x² - 2x - 40 = 0

Factorize:

(x + 4)(x - 5) = 0

x = -4 or x = 5

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Answer: 300

Step-by-step explanation:

10*8*6=480-6*6*5=180=300

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

yes it is if you bisect 5m on a 12m line

The number of triangles that are displayed can be found to be 216 triangles.

Each rectangular tile has a decorative pattern of 3 equal-sized squares, and each square is divided into 2 same-sized triangles. Therefore, each tile has 3 squares * 2 triangles per square = 6 triangles.

Marnie uses 36 of these tiles on the wall behind her kitchen stove. To find the total number of triangles displayed, multiply the number of triangles per tile by the total number of tiles:

Total triangles = 6 triangles per tile x 36 tiles = 216 triangles

So, there are 216 triangles displayed on the wall behind Marnie's kitchen stove.

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The inequalities for the given word problems are:

g) p/q ≤ 6

h) 1/w ≥ 9

Inequality word problems are statements or words used to describe specific inequalities.

g) We are told that the quotient of p and q is at most 6. Thus, it is a maximum of 6. Therefore, we can write the inequality as:

p/q ≤ 6

h) We are told that the reciprocal of w is at least 9. Thus, the inequality is expressed as:

1/w ≥ 9

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Answer:

[tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm i\sqrt{\frac{2}{7}}[/tex]

(real solution)       (imaginary solution)

Step-by-step explanation:

For these type of questions, where the exponent is even, it helps to try to rewrite the equation into a quadratic equation as we have a closed formula (quadratic formula) to solve for the zeroes, and it's also just easier to deal with in general.

Let's say that: [tex]u=x^2[/tex], now if we square both sides, [tex]u^2=x^4[/tex], so from here we can substitute in u squared as x to the power of four.

This results in our following equation: [tex]49u^2-4[/tex], from here we could use the quadratic formula, but you may notice a pattern here. We have a difference of squares: [tex]a^2-b^2=(a-b)(a+b)[/tex]

[tex]49u^2[/tex] can be written as [tex](7u)^2[/tex] and [tex]4[/tex] can be written as [tex]2^2[/tex], this gives us our equation: [tex](7u)^2-2^2\implies (7u-2)(7u+2)[/tex]. If we use this definition of the equation on the left side, it gives us: [tex](7u-2)(7u+2)=0[/tex] and this is very convenient as we can solve both of them individually.

Whenever we multiply any number (assuming it's defined) by zero, we should get.... zero. This intuitively makes sense as no matter how many times we add zero up (multiplication is repeated addition), we're always just going to have zero.

So when we have the equation: [tex]a*b=0[/tex], if "a" is zero then regardless of what "b" is (assuming it's defined), then the product will be zero. If "b" is zero then regardless of what "a" is (assuming it's defined), then the product will be zero.

Now if we look back at our equation: [tex](7u-2)(7u+2)=0[/tex], if [tex]7u-2=0[/tex], then regardless of what [tex]7u+2[/tex] is equal to, the product will be zero. Likewise, if [tex]7u+2=0[/tex] then regardless of what [tex]7u-2[/tex] is equal to, the product will be zero, thus making the equation true.

So to find the solutions to this, we find what makes [tex]7u-2=0 \text{ and }7u+2=0[/tex] true. If we work them both out individually we

get:

[tex]7u-2=0\\7u=2\\u=\frac{2}{7}\\\\7u+2=0\\7u=-2\\u=-\frac{2}{7}[/tex]

So now we have our two solutions right? Well remember we started off with a "x" variable, and the "u" is merely a substitution. If you recall, the "u" value is set equal to "x^2", so we can just plug that back in, so we can find the solutions in terms of x.

[tex]x^2=\frac{2}{7} \text{ and } x^2=-\frac{2}{7}[/tex]

If we take the square root of both sides, we get:

[tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm\sqrt{-\frac{2}{7}}[/tex]

you'll notice in one of them, we're taking the square root of a negative number. This will result in imaginary solutions, if we factor out a "-1" and take the square root of that, we'll just get an "i" infront, giving us the solutions of: [tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm i\sqrt{\frac{2}{7}}[/tex].

The formula for tension (T) in terms of extension (x) is T = 25x.

The given statement is T = kx, where T is the tension, x is the extension, and k is the proportionality constant.

To solve this problem, we need to find the value of k. We can do that by substituting the given values of T and x into the equation:

T = kx

150 = k×6

k = 25

Therefore, the formula for tension (T) in terms of extension (x) is T = 25x.

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From the calculation, g increases on the interval [-3, 6) and for 0 ≤ x ≤ 6, g(x) = 6 - 1/2(x-2)^2.

To determine where g is increasing, we need to find where its derivative, g'(x), is positive. We can find g'(x) by differentiating g(x) with respect to x:

g'(x) = f(x)

Since f(x) is a piecewise-defined function, we need to consider each interval separately.

Therefore, g is increasing on the interval [-3, 6).

To justify this, note that g'(x) = 0 at x = 0 and x = 6, where g has local maxima. This means that g is increasing on the intervals (-3, 0) and (0, 6) and decreasing on (6, 9]. Since g is continuous, it cannot have any jumps, so it must be increasing or decreasing on each of these intervals. Since g(-3) = 0 and g(6) = 9, we know that g is increasing on the interval [-3, 6).

We can evaluate g(x) on the interval [0, 6] by integrating f(x) with respect to t from -2 to x:

g(x) = ∫_{-2}^{x} f(t) dt

On the interval [-3, 0), f(t) = 3, so we have:

g(x) = ∫_{-2}^{0} 3 dt + ∫_{0}^{x} (-t + 3) dt

Simplifying the integrals, we get:

g(x) = 6 - 1/2(x-2)^2, for 0 ≤ x ≤ 6

(Note that we can drop the "+C" since it's being evaluated at the limits of integration.)

Therefore, for 0 ≤ x ≤ 6, g(x) = 6 - 1/2(x-2)^2.

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Based on the information given, there are a total of 118 solutions.

This is a problem of solving a Diophantine equation subject to some conditions. Let's introduce a new variable y4 = 20 - (x1 + x2 + x3 + x4). Then the problem can be restated as finding the number of solutions to:

x1 + x2 + x3 + y4 = 20

Subject to the following conditions:

0 ≤ x1 < 3

0 ≤ x2 < 4

0 ≤ x3 < 5

0 ≤ y4 < 6

We can solve this problem using the technique of generating functions. The generating function for each variable is:

(1 + x + x^2) for x1

(1 + x + x^2 + x^3) for x2

(1 + x + x^2 + x^3 + x^4) for x3

(1 + x + x^2 + x^3 + x^4 + x^5) for y4

The generating function for the equation is the product of the generating functions for each variable:

(1 + x + x^2)^3 (1 + x + x^2 + x^3 + x^4 + x^5)

We need to find the coefficient of x^20 in this generating function. We can use a computer algebra system or a spreadsheet program to expand the product and extract the coefficient. The result is: 1118

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Answer: This problem involves finding the number of non-negative integer solutions to the equation x₁ + x₂ + x3 + x₁ = 20 subject to the given constraints. We can use the stars and bars method to solve this problem.

Suppose we have 20 stars representing the sum x₁ + x₂ + x3 + x₁. To separate these stars into four groups corresponding to x₁, x₂, x₃, and x₄, we need to place three bars. For example, if we have 20 stars and 3 bars arranged as follows:

**|**||

then the corresponding values of x₁, x₂, x₃, and x₄ are 2, 4, 6, and 8, respectively. Notice that the position of the bars determines the values of x₁, x₂, x₃, and x₄.

In general, the number of ways to place k identical objects (stars) into n distinct groups (corresponding to x₁, x₂, ..., xₙ-₁) using n-1 separators (bars) is given by the binomial coefficient (k+n-1) choose (n-1), which is denoted by C(k+n-1, n-1).

Thus, the number of non-negative integer solutions to the equation x₁ + x₂ + x3 + x₁ = 20 subject to the given constraints is:

C(20+4-1, 4-1) = C(23, 3) = 1771

However, this count includes solutions that violate the upper bounds on x₁, x₂, x₃, and x₄. To eliminate these solutions, we need to use the principle of inclusion-exclusion.

Let Aᵢ be the set of non-negative integer solutions to the equation x₁ + x₂ + x3 + x₁ = 20 subject to the given constraints, where xᵢ ≥ mᵢ for some integer mᵢ. Then, we want to find the cardinality of the set:

A = A₀ ∩ A₁ ∩ A₂ ∩ A₃

where A₀ is the set of all non-negative integer solutions to the equation x₁ + x₂ + x3 + x₁ = 20, and Aᵢ is the set of solutions that violate the upper bound on xᵢ.

To find the cardinality of A₀, we use the formula above and obtain:

C(20+4-1, 4-1) = 1771

To find the cardinality of Aᵢ, we subtract the number of solutions that violate the upper bound on xᵢ from the total count. For example, to find the cardinality of A₁, we subtract the number of solutions where x₂ ≥ 4 from the total count. To count the number of solutions where x₂ ≥ 4, we fix x₂ = 4 and then count the number of solutions to the equation x₁ + 4 + x₃ + x₄ = 20 subject to the constraints 0 ≤ x₁ < 3, 0 ≤ x₃ < 5, and 0 ≤ x₄ < 6. This count is given by:

C(20-4+3-1, 3-1) = C(18, 2) = 153

Similarly, we can find the cardinalities of A₂ and A₃ by fixing x₃ = 5 and x₄ = 6, respectively. Using the principle of inclusion-exclusion, we obtain:

|A| = |A₀| - |A

Step-by-step explanation:

Part A: A

Part B: Julia collected 18.65, Keller collected 61.15, and Israel collected 45.15