In what way would a digital thermometer be preferable to those from a liquid-based thermometer? digital thermometer readings are easier to use when performing calculations. digital thermometer readings can be more readily combined with computer software. digital thermometer are inexpensive. digital thermometer are less prone to fluctuation.

The pH of the solution is 1.52 and the concentration of C6H6O62- is 2.2 * 10^-7 M.

We know that;

H₂C6H6O6 ⇔HC6H6O6^-(aq)    +   H^+(aq) ----- (1)

Ka1 = 7.9 x 10^-5

Again;

HC6H6O6^-(aq) ⇔ C6H6O6^2-(aq)  +   H^+(aq) ------- (2)

Ka2 = 1.6 x 10^-12

Given that Ka2 <<<< Ka1 we have to apply equation 1 to obtain H^+ hence;

Ka1 = [HC6H6O6^-] [H^+]/[H₂C6H6O6]

Let  [HC6H6O6^-] = [H^+] =x

7.9 x 10^5 =x^2/0.1 - x

But x <<< 0.1 thus;

7.9 x 10^5 =x^2/0.1

x = √7.9 x 10^-5  * 0.1

x = 0.03 M

pH = -log(0.03 M)

pH = 1.52

To obtain  C6H6O6^2-;

Ka2 = [ C6H6O6^2-] [ H^+]/[HC6H6O6^-]

Also;

[ C6H6O6^2-] = [ H^+]= x

Now;

1.6 x 10^-12 = x^2/0.03 -x

But x<<<0.3

Hence;

1.6 x 10^-12 = x^2/0.03

x = √1.6 x 10^-12 * 0.03

x = 2.2 * 10^-7 M

The concentration of C6H6O6^2- is  2.2 * 10^-7 M.

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The percent yield of [tex]MgO[/tex] is 58.79%

According to the following balanced reaction, magnesium interacts with oxygen to generate magnesium oxide:

[tex]2Mg + O_2 \rightarrow 2MgO[/tex]

Given mass of solid magnesium = 0.261g

Molar mass of Mg = 24g/mol

Using formula , [tex]Number of moles =\dfrac {mass} {molar mass} = \dfrac {0.261g} {24g/mol} = 0.0108mole[/tex]

We could theoretically make 0.0108 moles of [tex]MgO[/tex] since the reaction yields an equimolar quantity of [tex]MgO[/tex]. It is clear from the above reaction that 2 moles of magnesium result in 2 moles of magnesium oxide.

Hence, mass of [tex]MgO[/tex] = Number of moles [tex]\times[/tex] Molar mass of MgO

mass of [tex]MgO[/tex]  = [tex]0.0108mole \times 40g/mole = 0.432g[/tex]

Percent yield =  [tex]\dfrac{Actual mass of MgO} {Theoretical mass of MgO} \times 100[/tex]

                       =  [tex]\dfrac{0.254} {0.432} \times 100 = 58.79percentage[/tex]

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The compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

An ionic compound is  compound that is composed of ions. We know that a poly atomic ion is an ion that contains more than one atom.

Looking at the options that have been provided, we know that the correct formula for the compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

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P=20707.7 atm

The ideal gas law is a straightforward formula that describes the relationship between an ideal gas's pressure P, volume V, and temperature T. Unless there is a strong reason to treat gases differently, we normally treat gases as ideal because of how straightforward this relationship is:-

PV=nRT

where ;

P= Pressure=?

V= Volume= 10.5 L

n= no.of mol.= 82.5 mol

R=Ideal gas constant= 8.314 joule / mol kelvin

T=Temperature= 317 K

using Given value:-

P= nRT/ V

P=(82.5 x 8.314 x 317) / 10.5

P=20707.7 atm

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Answer:   " 4, 1, 2, 3."

_______________
  " In molecules, C, H, O, and N atoms  usually make _4_, _1_, _2_, and  

_3_ bonds, respectively."
_______________
Note the following mnemonic device:

" H O N C " —>  "Honc" if you love molecules!"

  1   2  3  4 ;

{"hydrogen"} H → 1

{"oxygen"} O  → 2

{"nitrogen"} N → 3

{"carbon"} C → 4

___

So:  by using this mnemonic:
H  O  N  C ;

1   2   3   4 ;
___
→ We can answer the question:
" C, H, O,  N " → in sequence:
" 4,  1,  2,  3 " ;

{just use the corresponding numbers as per the mnemonic device.}.
The answer:  " 4, 1, 2, 3 ".

Hope this is helpful to you!  Best wishes!

The amount of oxygen that can be recovered would be 14.37 grams

[tex]Fe(OH)_3[/tex] has 3 atoms of oxygen.

The percentage oxygen composition in the compound can be calculated as:

              mass of oxygen content/total mass

The molar mass of the compound is 106.87 g/mol.

Percent oxygen = 3 x 16/106.87 x 100% = 44.91%

Thus, the amount of oxygen that can be recovered from 32.0 grams of Fe(OH)3 will be:

            44.91/100 x 32 = 14.37 grams

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The freezing point of the solution is - 2.15.

The freezing point is the point at which a liquid is changed to solid. We can use the formula;

ΔT = K m I

ΔT = temperature change

K = freezing constant of benzene

m = molality

i = Van't Hoff factor

Now;

ΔT =  5.12°C/m * 0.655 m  * 1

ΔT = 3.35°C

ΔT = Freezing point of pure benzene - Freezing point of solution  

Freezing point of solution  = ΔT -  Freezing point of pure benzene

= 3.35°C -  5.5 °C = - 2.15

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Answer:

2.143 degrees celsius

Explanation:

The mass lost in the process is 1.4 * 10^-5Kg.

The Einstein equation is able to relate the mass lost to the energy that is evolved in a nuclear process.

Given that;

E = Δmc^2

Δm = E/c^2

Δm =  1.26 × 10^12 J/( 3 * 10^8)^2

Δm = 1.4 * 10^-5Kg

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Carbon fiber Vs Steel:

Steel has a density that is about five times more when compared to carbon fiber.

What is Carbon fiber (CFRC):

Carbon is an element that occurs naturally, and carbon fiber is made of this element. Because of its crystalline structure, carbon fiber possesses excellent tensile strength and stiffness capabilities. It is used to create lightweight composite parts that have great strength by wrapping the fiber in a polymer matrix.

What is steel:

Steel has long been a preferred material due to its high elasticity, which is around 200 GPa. Its relative abundance and stiffness have made it a widely used manufacturing material. However, because of its weight and density of around 8 g/cm3, it can be exceedingly difficult on the machines it is intended to protect. This weighs nearly five times as much as carbon fiber materials which would offer an equivalent or higher level of stiffness.

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The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3

3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)

from the balance equation,

Mole ratio = mole of K₃PO₃ / mole of KNO₂

Mole ratio of K₃PO₃ and KNO₂ = 2 / 6

Mole ratio of K₃PO₃ and KNO₂ = 1 : 3

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Answer:

Sodium atom is larger than Magnesium atom.

Explanation:

Looking at the electronic configurations of Sodium and Magnesium:

[tex]_{11}Na: 1s^2 2s^2 p^6 3s^1\\\\_{12}Mg : 1s^2 2s^2 p^6 3s^2[/tex] ,

we can see that they both have their valence electrons in the 3rd shell.

But because Magnesium has a higher nuclear charge of +12 because of its 12 protons than that of Sodium's +11, the nucleus of Magnesium attracts its outer electrons more strongly than Sodium does. This makes the Magnesium atom smaller.

The number of moles of  b2o3 that will be formed is determined as 4 moles.

The limiting reagent is the reactant that will be completely used up.

4 b + 3O₂ → 2b₂O₃

from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

2 : 1

3O₂  -------------> 2b₂O₃

3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

4 b ------------> 2 moles of  b2o3

8 moles -------> ?

= (8 x 2)/4

= 4 moles

Thus, the number of moles of  b2o3 that will be formed is determined as 4 moles.

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Answer:

Explanation:Matter is anything that has weight and occupies space

Correct option:

The correct name for [tex]P_{2}O_{5}[/tex]  is diphosphorus pentoxide.

Why [tex]P_{2}O_{5}[/tex] is called diphosphorus pentoxide?

[tex]P_{2}O_{5}[/tex] is commonly known as diphosphorus pentoxide.

Phosphorus pentoxide has an intriguing property in that [tex]P_{2}O_{5}[/tex] is actually its empirical formula, whereas [tex]P_{4}O_{10}[/tex] is its actual molecular formula.

However, the name of the chemical was obtained from its empirical formula rather than from its molecular formula. The official name for this substance is diphosphorus pentoxide.

Oxygen-containing binary compounds have "oxide" as their "last name." Phosphorus is the "first name."

We list each atom's numbers below:

The di- and Penta- prefixes are used to indicate the presence of two and five oxygen atoms, respectively, in the molecule.

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Answer:

diphosphorus pentoxide

Explanation:

Answer:

3.78 L

Explanation:

The Charles' Law equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the final volume by plugging the give values into the equation and simplifying.

V₁ = 0.30 L                    V₂ = ? L

T₁ = 25 °C                      T₂ = 315 °C

V₁ / T₁ = V₂ / T₂                                          <----- Charles' Law equation

(0.30 L) / (25 °C) = V₂ / (315 °C)                <------ Insert values

0.012 = V₂ / (315 °C)                                  <----- Divide 25 from 0.30

3.78 = V₂                                                   <----- Multiply both sides by 315

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 16.59 g

Volume (v) =  5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

[tex]p = \frac{m}{v}[/tex]

Substitute the values into the formula:

​[tex]p = \frac{16.59 g}{5.81 mL} \\ = 2.8554 g/mL[/tex]

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

Answer:

9.02 moles Na

Explanation:

To find the amount of moles, you need to multiply the given amount by Avogadro's Number. This number allows you to convert from atoms to moles of any substance.

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

5.43 x 10²⁴ atoms Na                    1 mole
--------------------------------  x  ---------------------------------  = 9.02 moles Na
                                             6.022 x 10²³ atoms

The equilibrium constant of the reaction is 0.323.

Equilibrium constant:

It is expressed as the ratio of concentration of the products to the concentration of reactants. It is represented by K.

The relationship of K with G (Gibbs free energy) is expressed as:

G° = -RTlnK

Here R is the gas constant, T is the temperature.

Calculations:

Convert 25°C to K.

25°C = (25 + 273.15) K

= 298.15 K

Substitute the values in the above expression.

2.8 x 1000 J/mol = -8.314 J/mol.K x 298.15 K x ln(K)

lnK = 2800 J/mol/(-8.314 J/mol.K x 298.15 K)

lnK = -1.13

K = e^-1.13

  = 0.323

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Answer:

B. The actual yield of a reaction is the amount of product you expected to make.

Explanation:

The actual yield of a reaction is the quantity of a product that is obtained from a chemical reaction. Therefore part B is the right solution to our question since it is true that actual yield of a reaction is the amount of product you expected to make.

Answer:

0.105 KCl

Explanation:

(Step 1)

If the solution is 32.7% KCl, we can assume that there are 32.7 grams KCl in the solution. This means that there would be 67.3 grams H₂O (100% - 32.7% = 67.3%) in the solution.

32.7% KCl = 32.7 g KCl

67.3% H₂O = 67.3 g H₂O

(Step 2)

Now, we need to convert both the solute (KCl) and the solvent (H₂O) into moles. This can be done by multiply the grams of each substance by their molar masses.

32.7 g KCl              1 mole
------------------  x  --------------------  = 0.439 mole KCl
                               74.55 g

67.3 g H₂O           1 mole
------------------  x  -----------------  =  3.74 moles H₂O
                             18.016 g

(Step 3)

Finally, we can calculate the mole fraction of KCl using the following equation. The final answer should have 3 sig figs to match the given value with the lowest amount of sig figs (32.7 g).

                                             moles of solute
Mole Fraction  =  -----------------------------------------------------  
                              moles of solute + moles of solvent

                                            0.439 mole KCl
Mole Fraction  =  ------------------------------------------------------  
                              0.439 mole KCl + 3.74 moles H₂O

Mole Fraction  =  0.105 KCl

Answer:

Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

Explanation:

Decomposition reaction represents the breakdown of single compound into more products.

A decomposition reaction is a type of reaction in which one reactant breaks down into two or more products. This can be represented by the general equation: H2O2 →  2H + 2O. In this example the breakdown of hydrogen peroxide occurs and  water and oxygen are formed.

Zinc reacts with dilute sulphuric acid to form zinc sulphate and hydrogen This hydrogen goes up into the atmosphere whereas the zinc sulphate remains.

Magnesium ribbon should be cleaned before burning in air because Magnesium metal combines with oxygen to form Magnesium Oxide (MgO) layer, which is a very stable molecule.

Arteries have thick, elastic walls, while veins have thin walls because arteries are under more pressure, as compared to veins that are under less pressure. Arteries are big in size whereas veins are small.

The role of valves in the heart is that these valves prevent the backward flow of blood.

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The oxidation number of an element in a compound is equal to the charge of the atoms if the compound was an ionic compound.

The types of compounds are:

Ionic compounds:

Covalent compound:

Molecular compounds:

Therefore, the oxidation number of an element in a compound is equal to the charge of the ion that would have if the compound was an ionic compound.

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Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

Answer:

nonpolar

Explanation:

A nonpolar solvent has the highest solubility with a nonpolar solute.

Answer:

Bond between N and Br is non polar bond

=> 0.25 M

The question is asking us to find the molarity/concentration of the acid (HCl).

We have been provided with;

12.50 mL of 0.20 M NaOH

10.0 mL of HCl

We know that molarity (M) of a solution is contained in 1 L or 1000 mL or 1000 cm³.

This means that;

0.20 M is contained in 1000 mL.

X mol is contained in 12.50 mL

[tex] x \: mol \: = \frac{12.50 \times 0.20}{1000} \\ = 0.0025 \: moles[/tex]

= 0.0025 moles

These 0.0025 moles is contained in 10 mL of HCl.

To find the molarity of the acid;

0.0025 moles is contained in 10 mL

x mol is contained in 1000 mL

[tex]x \: mol \: = \frac{0.0025 \times 1000}{10} \\ = 0.25 \: mol[/tex]

= 0.25 M

Therefore the Concentration of the acid (HCl) is 0.25 M

Answer:

It is a force acting on the object.

Explanation:

The answer option which is true about the weight of an object is: C. It is a force acting on the object.

Weight can be defined as the force acting on a physical body or an object as a result of gravity. Also, the weight of an object is measured in Newton.

Mathematically, the weight of an object is given by the formula;

Where;

m is the mass of the object.

g is the acceleration due to gravity.

In conclusion, the weight of an object is the force acting on an object due to gravity.

The Answer to the question is 124.66 grams approximately.

It is given that H₂ will react completely

Molar mass of H₂ = 2 × 1 = 2 gm/mol

Given mass of H₂ = 22 gm

Moles of H₂ reacting = given mass of H₂ / molar mass of H₂

Moles of H₂ reacting = 22 / 2 moles = 11 moles

So, 11 moles of H₂ are taking part in reaction.

The Balanced chemical reaction is as follows as:

N₂ + 3 H₂ → 2 NH₃

It is clear from the reaction that 3 moles of H₂ are making 2 mole of NH₃

3 moles of H₂ → 2 mole of NH₃

1 moles of H₂ → 2/3 mole of NH₃

11 moles of H₂ → (2/3)×11 mole of NH₃

11 moles of H₂ → 22/3 mole of NH₃

So, 11 moles of H₂ will make 22/3 mole of NH₃

22/3 mole NH₃ = mass formed NH₃ / molar mass of NH₃

mass formed NH₃ = 22/3 × molar mass of NH₃

mass formed NH₃ = 22/3 × 17

mass formed NH₃ = 22/3 × 17

mass formed NH₃ = 124.66 grams    (approximately)

124.66 grams of NH₃ will be formed.

So, approximately 124.66 grams of NH₃ is formed from 22 grams of H₂.

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Answer:

T

Explanation:

m is mass

q is heat

J is energy