In regard to exercise, which of the following statements about safety consideration is correct?
A.
In hot weather, exercising between 10 a.m. and 4 p.m. is best.
B.
Exercising at 100% of your maximum heart rate is best.
C.
Exercising one hour before eating is best.
D.
Remaining well-hydrated while exercising is best

Answers

Answer 1

Answer:

the correct answer is

D.Remaining well-hydrated while exercising is best


Related Questions

What is the formula for freefall?

Answers

Answer: vf = g * t

Explanation:

G represents the acceleration of gravity.

T represents time so multiply the acceleration of gravity times time.

which type of energy is released when a nucleus is split apart?

a. kinetic energy
b. elastic energy
c. chemical energy
d. nuclear energy

Answers

Answer:

D. Nuclear energy

Explanation:

A nucleus is the result of nuclear energy if it is split into an other the same result shall happen it being nuclear energy.

Which of the following is strenuous?
Atraining for an athletic competition
Bsharing a candy bar with a friend
Creading an exciting mystery
Dforgetting to complete your homework

Answers

Answer:

I think it c

Explanation:

Answer:

Atraining for an athletic competition

plz answer this...its urgent!!
its about gravitation..only 3 questions

Answers

Answer: For #1, 7.3 m/s2.

Explanation: See this wikipedia screenshot for explanation, it's complicated.

What is the average translational KE of 5 moles of gas molecules at 300 K?

a.
2.1 x 103 J

b.
1.87 x 104 J

c.
1.78 x 105 J

d.
1.68 x 106 J


Answers

Answer:

What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

Explanation:

The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

There is a spot of paint on the front wheel of the bicycle. Take the position of the spot at time t=0 to be at angle θ=0 radians with respect to an axis parallel to the ground (and perpendicular to the axis of rotation of the tire) and measure positive angles in the direction of the wheel's rotation. What angular displacement θ has the spot of paint undergone between time 0 and 2 seconds?

Answers

Here is the missing information.

An exhausted bicyclist pedal somewhat erraticaly when exercising on a static bicycle. The angular velocity of the wheels takes the equation ω(t)=at − bsin(ct) for t≥ 0, where t represents time (measured in seconds), a = 0.500 rad/s2 , b = 0.250 rad/s and c = 2.00 rad/s .

Answer:

0.793 rad

Explanation:

From the given question:

The angular velocity of the wheel is expressed by the equation:

[tex]\omega (t) =\dfrac{d\theta}{dt}[/tex]

The angular velocity of the wheels takes the description of the equation ω(t)=at−bsin(ct)

SO;

[tex]\dfrac{d \theta}{dt} = at - b \ sin \ ct[/tex]

dθ = at dt - (b sin ct) dt

Taking the integral of the above equation; we have:

[tex]\int \limits^{\theta}_{0} \ d \theta = \int \limits ^{t=2}_{0} at \ dt - (b \ sin \ ct) \dt[/tex]

[tex][\theta] ^{\theta}_{0} = a \bigg [\dfrac{t^2}{2} \bigg]^2_0 - \bigg[ -\dfrac{b}{c} \ cos \ ct \bigg] ^2_0[/tex]

where;

a = 0.500 rad/s2 ,

b = 0.250 rad/s and

c = 2.00 rad/s

[tex]\theta = (0.500 \ rad/s^2 ) \bigg [\dfrac{(2s)^2}{2} \bigg] - \bigg[ -\dfrac{0.250 \ rad/s}{2.00 \ rad/s} \ cos \ (2.00 \ rad/s )( 2.00 \ s) \bigg] - \bigg [ \dfrac{0.250 \ rad/s}{2.00 \ rad/s}\bigg ] cos 0^0[/tex]

[tex]\mathbf{\theta = 0.793 \ rad}[/tex]

Hence, the angular displacement after two seconds = 0.793 rad

HELLO PLEASE HELPPP!! WILL GIVE BRAINIEST

Answers

Answer: Wavelength

Explanation:

Answer:

C) wavelength

Explanation:

I hope this is right, have a nice day!

La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el piso. NOTA: Se debe encontrar la fuerza, para lo cual, se debe obtener el peso utilizando la fórmula de masa por gravedad que es 9.8 m / s2

Answers

Answer:

11025 N / m²

Explanation:

Los siguientes datos se obtuvieron de la pregunta:

Área (A) = 400 cm²

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Presión (P) =?

A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Fuerza (F) =.?

F = m × g

F = 45 × 9,8

F = 441 N

A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:

1 cm² = 0,0001 m²

Por lo tanto,

400 cm² = 400 cm² × 0,0001 m² / 1 cm²

400 cm² = 0,04 m²

Por tanto, 400 cm² equivalen a 0,04 m².

Finalmente, determinaremos la presión ejercida de la siguiente manera:

Área (A) = 0.04 m².

Fuerza (F) = 441 N

Presión (P) =?

P = F / A

P = 441 / 0,04

P = 11025 N / m²

Por tanto, la presión ejercida es 11025 M / m²

newtons second law of physics, solve the chart

Answers

Answer:

(from top to bottom)

350 N, 80 kg, 10 m/s^2, 80 kg, -15 m/s^2, -3000 N

Explanation:

Force = Mass*Acceleration (aka F = ma)

Using algebra, you can find the variables/unknown values.

1. A kettle contains 1.5kg of water at a
temperature of 18°C. How much energy is
needed to bring the water to the boil?

Answers

Answer:

water boiling point is usually 100°C so I think we subtract 18 degrees Celsius from 100 degrees Celsius to get 82 degrees Celsius to be the energy needed

an average net force of 31.6 N is used to accelerate a 15.0 kg object uniformly from rest to 10.0 m/s leftward. What is the change in momentum?​

Answers

Answer:

-150 kg m/s

Explanation:

The change of momentum is calculated as ;

Δp= m*Δv where

where

Δp= change in momentum

Δv = vf-vi

m= mass of the object

Change in momentum is also calculated when using the formula;

Δp = F * Δt   when F is the net force applied and Δt is the time of action.

In this case;

m= 15 kg

vf=  -10 m/s

vi= 0 m/s

Taking rightward direction to be positive, then leftward will be negative.

Applying the formula as;

Δp = m*Δv

Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s

If a small asteroid named ‘B612’ has a radius of only 20 m and mass of
1 × 104 kg, what is the acceleration due to gravity on its surface?

Answers

Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity.

It is a vector quantity and it's SI unit is m/s².

It is usually denoted by the symbol g.

Formula of Acceleration due to Gravity:

[tex] \boxed{ \bf{g = \dfrac{GM}{r^2}}}[/tex]

G → Universal Gravitational Constant [tex] \sf (6.67 \times 10^{-11} \ Nm^2/kg^2) [/tex]

M → Mass of the Asteroid (1 × 10⁴ kg)

R → Radius of the Asteroid (20 m)

By substituting values in the equation, we get:

[tex] \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11} \times 1 \times {10}^{4} }{20^2} \\ \\ \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11 + 4} }{400} \\ \\ \rm \longrightarrow g = 0.016675 \times {10}^{ - 7} \\ \\ \rm \longrightarrow g = 1.6675 \times {10}^{ -9} \: m {s}^{ - 1} [/tex]

[tex] \therefore [/tex] Acceleration due to gravity on the surface of small asteroid named ‘B612’ = [tex] \sf 1.6675 \times 10^{-9} \ m/s [/tex]

Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity. Acceleration due to gravity on the surface of small asteroid named ‘B612’ = 1.776 * 10 9 m/s2.

What is acceleration due to gravity?

A free-falling item is one that is falling solely as a result of gravity, as was discovered in the previous section of this course. A free-falling object experiences a downward acceleration of 9.8 m/s. (on Earth).

The acceleration of any object moving only as a result of gravity is referred to as the acceleration of gravity.

In fact, this quantity, known as the acceleration of gravity, is so significant to physics that it has its own distinctive symbol, the letter g. The most precise measurement of the gravitational acceleration is 9.8 m/s.

To learn more about acceleration due to gravity, refer to the link:

https://brainly.com/question/13860566

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Q: How can variations in the rate of interaction between the hydrosphere and the atmosphere result in global climate change?
A. by causing droughts and floods
B. by producing more greenhouse gases
C. by changing the amount of water on Earth
D. by decreasing the atmospheric temperature

Answers

D is the correct answer on edge

Your task now is to look up the effects of the temperature on an equilibrium and how the reaction will shift when adding or removing heat. Explain in no less than 4 complete sentences the effect of the temperature and list at least on example.

Answers

Answer:

If you increase the temperature, the position of equilibrium will move in such a way as to reduce the temperature again. It will do that by favouring the reaction which absorbs heat. In the equilibrium we've just looked at, that will be the back reaction because the forward reaction is exothermic.

Explanation:  

The energy is different within each wave type across the spectrum true or false

Answers

Answer:

T kinda waky tho -_-----_-----_-////_----_---///

Explanation:

Answer:

true

Explanation:

A block weighing 35 N is resting on a steel table (us = 0.40).
The minimum force to start this block moving is ___ N.

Answers

Answer: 14

Explanation:

Force(normal)*coefficient

The static friction force is a force that prevents motion of an object kept on a surface, due to the interaction of the surface of the object and the surface on which it is kept

The minimum force required to start the block moving is 14 N

Reason:

The known parameter are;

The weight of the block, W = 35 N

The static friction of the surface of the table surface, [tex]\mu_s[/tex] = 0.40

Required:

To find the minimum force to start the block moving

Solution:

The force required to start the block moving is given by the frictional force that needs to be surpassed

Force required, F = Force of friction

Force of friction = Normal reaction × Coefficient of static friction

On a flat surface, the normal reaction = The weight of the object

Force of friction, [tex]F_f[/tex] = Weight of the object × Coefficient of static friction

Which gives;

[tex]F_f = W \times \mu_s[/tex]

[tex]F_f = 35 \, N \times 0.40 = 14 \, N[/tex]

Force required, F = Force of friction, [tex]F_f[/tex] = 14 N

The minimum force required to start the block moving, F = 14 N

Learn more about the static friction force here:

https://brainly.com/question/13877320

An example of a chemical change is water boiling

Answers

Answer:

False, Boiling water is an example of a physical change and not a chemical change

Answer:

yes

Explanation:

cos from the boiling water, you can still get another change

How many
different
elements are
present in
C6H12O6 ? How do you know

Answers

3 elements
C6H12O6 contains 3 elements: carbon, hydrogen, and oxygen.

At its closest approach, a moon comes within 200,000 km of the planet it orbits. At that point, the moon is 300,000 km from the other focus of its orbit, f2. The planet is focus f1 of the moon's elliptical orbit. How far is the moon from the planet when it is 260,000 km from f2?

Answers

Answer:

s₁ = 240,000 km

Explanation:

The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,

s = s₁ + s₂

where,

s = total distance between the focuses = ?

s₁ = distance between f1 and moon = 200,000 km

s₂ = distance between f₂ and moon = 300,000 km

Therefore,

s = 200,000 km + 300,000 km

s = 500,000 km

Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:

s = s₁ + s₂

500,000 km = s₁ + 260,000 km

s₁ = 500,000 km - 260,000 km

s₁ = 240,000 km

How does a second class lever make our work easier?​

Answers

Sorry, please elaborate? And I’ll try to answer in comments:)

A golfer hits a ball at 10.5 m/s at an angle of 25 degrees.
a) How long will the ball be moving?
B) How far will the ball go? C) How high will the ball go?

Answers

Option B is correct!!!

PLSS THIS LOOKS SIMPLE Tina throws a softball up with an initial speed of 25 meters per second. Calculate the maximum height that the ball will reach. ​

Answers

Is 50 because 25+25 is 50,and that’s ur answer

Answer:

31.86m

Explanation:

recall that one of the equations of motion can be written

v² = u² + 2as

where

u = initial velocity = 25m/s

v = final velocity = 0m/s because at maximum height, the ball will momentary stop moving (i.e have zero velocity)

a = acceleration = -9.81m/s²  (i.e a deceleration as it moves upwards equal to the magnitude of the gravitational acceleration)

s = distance (we are asked to find this)

substituting these into the equation:

v² = u² + 2as

0² = 25² + 2(-9.81)s

0 = 625 - 19.62s

19.62s = 625

s = 625 / 19.62

s = 31.86m

[10 POINTS ❗️❗️ and brainlist :)]



Roy throws a ball up in the air. Each time he throws the ball up in any direction, it falls back to the ground as shown in the illustration. The ball comes back to the ground because of the
A) weak electric force of the earth.
B) strong magnetic force of the earth.
C) force of air resistance on the ball.
D) strong gravitational force of the earth.

Answers

The answer to this is D

Answer:

D) Strong gravitational force of the earth

Explanation:

Gravitational force is the force that attracts to objects with mass.This forces tries to pull masses together, that is why attractive in nature.

can anyone help me with this

Answers

Answer:

earth is 4.54 billion years old

for an organism to survive they would have to change ( mutate )

A mutation is any permenant change in dna of a gene or chromosome

some mutations are bad and some can be good

Explanation:

As Derrick is driving around town, he stops at a red-light. When the light turns green, he takes off and travels
212m in 6.7 seconds. What is his average acceleration?

Answers

Answer:

31.6

Explanation:

velocity÷ time

212 ÷ 6.7 = 31.6m/s

Define malleability?

Answers

Answer:

Explanation:

the quality or state of being malleable: such as. a : capability of being shaped or extended by hammering, forging, etc. the malleability of tin.

You pull horizontally on a 50 kg crate with a force of 400N and the friction force on the crate in 150N. What is the acceleration of the crate?

Answers

4 m/s*2 450-250=200 200/50=4

If you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate of 150 N, then the acceleration of the crate would be 5 m / s² .

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem if you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate in 150 N.

The net force acting on the crate = 400 N - 150 N

                                                        = 250 N

The acceleration of the crate = 250 / 50

                                                 = 5 m / s²

Thus, the acceleration of the crate would be 5 m / s² .

Learn more about Newton's second law here, refer to the link given below ;

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what is the temperature of air if the speed of sound is 295m/s?​

Answers

Answer:

Explanation:The speed of sound depends on several variables, but the only independent variable we need to calculate the speed of sound ... Enter your air temp and choose your units: The speed of sound: mph. Fahrenheit, knots. Celsius, m/s. Kelvin, ft/s.

Define kinetic energy in your own words, and write a statement about how kinetic energy is affected as velocity increases.

Answers

Sentence:When something is in motion, it has kinetic energy. Wind and water are examples of things with kinetic energy because they are moving. Electricity is also a form of kinetic energy.

What does is the glenohumeral joint and what does it do? (ANATOMY)

Answers

Glenohumeral joint arthritis is caused by the destruction of the cartilage layer covering the bones in the glenohumeral joint. This creates a bone-on-bone environment, which encourages the body to produce osteophytes (bone spurs). Friction between the humerus and the glenoid increases, so the shoulder no longer moves smoothly or comfortably
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