The deflection angle is 37.29º if the prism was made of polystyrene plastic.
What is a laser beam?
Laser beam is a light beam propagating dominantly in one direction.
It is a beam of radiation produced from a laser.
Here given that,
refraction index of glass, n1= 1.52
refraction index of polystyrene plastic, n2 = 1.59
deflection angle, B = 22.6º
For the second surface,
B = 45º - 22.6º
B = 22.40º
Now from the formula of Snell's law:
n1 sinФ = n2 sin B
sin B / sinФ = n1 / n2
sinФ = (sin 22.40º) * ( 1/ 1.59)
Ф = 37.29º
Hence,
The deflection angle is 37.29º if the prism was made of polystyrene plastic.
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A cat falls out of a window 40 m high. what is the speed of the cat 5 m from the sidewalk?
The speed of the cat 5 m from the sidewalk is 7.42 m/s
What is speed:
Speed is scalar quantity that refers to how fast an object is moving. Speed can be derived as the rate of change of distance.The Newton's equation of motion:
h = u*t + 1/2 (a*t^2)here the cat falls from the height,
h = 40 m
since The cat is falling from rest
Initial velocity, u = 0 m/s
acceleration, a = g = 9.8 m/s^2
substituting values in eq.
40 = 0 + ( 9.8 t^2)
t^2 = 40 / 9,8
t^2 = 4.0814
t = 2.02 s
now when cat is 5 m from sidewalk
distance, S = 40 - 5 = 35 m from top
so,
35 = u*2.02 + 1/2 ( 9.8* 2.02^2 )
u = 15 / 2.02
u = 7.4257 m/s
The speed of the cat 5 m from the sidewalk is 7.42 m/s
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A boy pulls on a wagon with a force of 100 N [E]. The wagon pulls on the boy with a
force of
A). zero
B) less than 100 N [E]
C) 100 N [W]
D) Less then 100 N [W]
E) greater than 100 N [W]
Discuss the work done by a pitcher throwing a baseball. What is the approximate distance through which the force acts as the ball is thrown
Due to acceleration, work is done accelerating from rest.
Work done is defined as product of force and displacement. As it explain force then it consist acceleration with itself. So, we can say like this that
work is done mainly due to acceleration of object from rest.
For the approximate distance through which the force act as ball is
thrown is the work is done along effective length of pitcher's arm and he
can extend this distance by taking a step forward.
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the plane of a coil of area 5 m^2 has 100 turns. The plane lies on the X-Y plane and the magnetic field of intensity 3 gauss is in the positive X-direction. Find the magnetic flux linked with it
The magnetic flux associated with the coil is 0 Wb.
Magnetic flux is the total magnetic field that travels through a specific location.
It is a very useful tool for explaining the effects of magnetic force on things in a specific location.
The magnetic flux measurement is location specific.
The magnetic flux through the coil is NBA cosα
where N is number of turns, B is Magnetic field, A is area of coil and α is the angle between normal to the area of coil and the direction of magnetic field.
Magnetic Flux = NBA cosα
We have given number of turns as 100, magnetic field as 3 and area as 5 m².
Also, the value of α will be 90°
Magnetic Flux = NBA cosα Wb
Magnetic Flux = 100 × 3 × 5 × cos90° Wb
Magnetic Flux = 100 × 3 × 5 × 0 Wb
Magnetic Flux = 0 Wb
So we can conclude that the magnetic flux through the coil is 0 wb after applying the above concept.
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A horizontal force, F, acts on a crate weighing 8 N, which moves on a horizontal floor at constant speed. The coefficient of friction between the crate and the surface is 0.25. The work done by F when the crate has moved 12 m is: Group of answer choices 2 J None of the above 24 J 96 J 0 J 10 J
The answer is 24 J
F K =.25*8 N
= 2N
F = f k = 2 N
Since a = 0
W = f * s
2 N * 12 m = 24 J
The coefficient of friction is a ratio used to quantify the friction force among two gadgets when it comes to the everyday pressure this is keeping them collectively. The coefficient of friction is critical attention at some stage in material selection and floor requirement determination.
For instance, ice on steel has a low coefficient of friction – the 2 materials slide past each different without problems – whilst rubber on the pavement has an excessive coefficient of friction – the substances no longer slide past each other without difficulty.
The coefficient of friction is dimensionless and it does not have any unit. it is a scalar, meaning the direction of the force does not have an effect on the physical quantity. The coefficient of friction depends on the gadgets that are causing friction.
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In an experiment to determine the acceleration due to gravity, one student drops a tennis ball out of the school’s third floor window. another student starts a timer when the first student lets go and stops the timer when the ball hits the ground. they conduct the experiment once and record the data. is this a valid experiment, why or why not?
No, it is not valid because they did not have any repeat trials.
What is acceleration due to gravity?The acceleration that an object experiences as a result of gravitational force is referred to as the object's acceleration due to gravity. M/s2 is its SI unit. Gravitational acceleration is a vector quantity, which means it has both a magnitude and a direction. The letter g stands for the acceleration due to gravity at Earth's surface. Its standard value is 9.80665 m/s2 (32.1740 ft/s2), according to the formula. A body in free fall actually accelerates differently depending on the location.
Because moving the object, air, or other factors could distort the results of a single instance. There must therefore be repeated experiments in order to obtain precise results.
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In a game of tennis, a ball traveling at is hit by a racket and travels in the opposite direction at . True or False: There is a change in momentum.
The momentum is changed when the ball is hitted by racket in the tennis game.
To find the answer, we need to know about the momentum.
What's momentum?Momentum of an object is given by the product of mass and the velocity of the ball.Also the rate of change of the momentum with time is called as force.How does the momentum change when a ball hitted by racket?In the game of tennis, the ball is hitted by the racket. And at the time of hitting a delta force is given to that ball.As a force is applied to the ball, so we must find a change in momentum in very small time interval.Thus, we can conclude that the momentum is changed when the ball is hitted by racket in the tennis game.
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please solve this asap
Let [tex]\vec u[/tex] and [tex]\vec v[/tex] be the vectors, and let [tex]x=\|\vec u\|=\|\vec v\|[/tex] be their common magnitude.
The resultant [tex]\vec u + \vec v[/tex] is [tex]\sqrt 2[/tex] times larger in magnitude than either vector alone, so [tex]\|\vec u+\vec v\| = \sqrt2\,x[/tex].
Recall the dot product identity
[tex]\vec a \cdot \vec b = \|\vec a\| \|\vec b\| \cos(\theta)[/tex]
where [tex]\theta[/tex] is the angle between the vectors [tex]\vec a[/tex] and [tex]\vec b[/tex]. In the special case of [tex]\vec a=\vec b[/tex], we get
[tex]\vec a \cdot \vec a = \|\vec a\|^2 \cos(0^\circ) \implies \|\vec a\| = \sqrt{\vec a\cdot\vec a}[/tex]
Now, to get the angle between [tex]\vec u[/tex] and [tex]\vec v[/tex], we have
[tex]\vec u \cdot \vec v = \|\vec u\| \|\vec v\| \cos(\theta) \implies \cos(\theta) = \dfrac{\vec u \cdot \vec v}{x^2}[/tex]
To compute the dot product, we take the dot product of the resultant with itself.
[tex](\vec u+\vec v) \cdot (\vec u + \vec v) = \|\vec u + \vec v\|^2[/tex]
Solve for [tex]\vec u\cdot\vec v[/tex].
[tex](\vec u\cdot\vec u) + 2(\vec u\cdot\vec v) + (\vec v\cdot\vec v) = \|\vec u + \vec v\|^2[/tex]
[tex]\|\vec u\|^2 + 2(\vec u\cdot \vec v) + \|\vec v\|^2 = \|\vec u+\vec v\|^2[/tex]
[tex]x^2 + 2(\vec u \cdot \vec v) + x^2 = (\sqrt2\,x)^2[/tex]
[tex]2(\vec u\cdot\vec v) + 2x^2 = 2x^2[/tex]
[tex]2(\vec u\cdot\vec v) = 0[/tex]
[tex]\vec u\cdot\vec v = 0[/tex]
Since their dot product is zero, [tex]\vec u[/tex] and [tex]\vec v[/tex] are perpendicular, so [tex]\theta=90^\circ[/tex].
The weight of a person on Earth is 67.0 N. If the gravitational acceleration on the moon is 1.62 m/s2, calculate the person’s weight on the moon.
Group of answer choices
A) 56.0 N
B) 11.0 N
C) 108 N
D) 4.00 N
Answer:
[tex] \large{ \boxed{ \tt{b) \: 11.0 \: N}}}[/tex]- Please see the attached picture for full solution!:)
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Question )
A snail covers a distance of 90 meter in 24 hours calculate the average speed of the snail.
Answer:
1.042 × 10⁻³ m/s
Explanation:
average speed = [tex]\frac{total \space\ distance \space\ covered}{time \space\ taken}[/tex]
In this case,
• distance covered = 90 m,
• time taken = 24 hours = 24 × 60 = 1440 min = 1140 × 60 = 86400 s
Substituting these values into the formula:
average speed = [tex]\frac{90}{86400}[/tex]
= 1.042 × 10⁻³ m/s
Answer:
3.75 meters per hour
Explanation:
[tex]\boxed{\sf Speed = \dfrac{Distance}{Time}}[/tex]
Given:
Distance = 90 metersTime = 24 hoursSubstitute the given values into the formula to calculated the speed:
[tex]\implies \sf Speed = \dfrac{90\:m}{24\:h}[/tex]
[tex]\implies \sf Speed = 3.75\:m/h[/tex]
Therefore, the average speed of the snail is 3.75 meters per hour.
To calculate the speed in meters per minute, divide by 60:
[tex]\implies \sf Speed = \dfrac{3.75\:m/h}{60}=0.0625\:m/min[/tex]
To calculate the speed in meters per second, divide by 60 again:
[tex]\implies \sf Speed = \dfrac{0.0625\:m/min}{60}=0.001042\:m/s\:\:(4\:s.f.)[/tex]
What is the magnitude of the force that must be applied for the system below to be balanced?
Group of answer choices
20 N
0 N
80 N
30 N
A simple harmonic oscillator has an amplitude of 3. 50 cm and a maximum speed of 26. 0 cm/s. What is its speed when the displacement is 1. 75 cm?.
Answer:
1.) A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm? 2.) Both pendulum A and B are 3.0 m long. The period of A is T. Pendulum A is twice as heavy as pendulum B. What is the period of B? 3.) The time for one cycle of a periodic process is called the _ ? 4.) In simple harmonic motion, the acceleration is proportional to? 5.) The position of a mass that is oscillating on a spring is given by x= (18.3 cm) cos [(2.35 s-1)t]. What is the frequency of this motion?
Explanation:
The magnitudes of two horizontal displacements are 4 m and 9 m, respectively. Given that the vectors may be in either the plus or the minus direction, they cannot be added together to give a total displacement of
The magnitudes of two horizontal displacements are 4 m and 9 m, respectively. Given that the vectors may be in either the plus or the minus direction, they cannot be added together to give a total displacement of 4m.
The attain of the projectile is the horizontal displacement of the projectile and is decided by the object's initial pace.
If a projectile is fired on an equal starting velocity but from complementary tiers of projection, its variety will be equal.
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A 140 g coin sits on a horizontally rotating turntable. the turntable makes one revolution each 1 s. the coin is located 14 cm from the axis of rotation of the turntable. the acceleration of gravity is 9.81 m/s2. what is the frictional force acting on the coin? answer in units of n. the coin will slide off the turntable if it is located more than 24 cm from the axis of rotation. what is the coefficient of static friction?
The frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.
To find the answer, we need to know more about the friction.
How to find the coefficient of static friction?We have given with the following values,[tex]m=140*10^{-3} kg\\w=1 rev/s=2\pi rad/s\\r_1=14*10^{-2}m\\g=9.81m/s^2\\[/tex]
When the coin is at a distance of 14cm from the axis of rotation, it will experience a centripetal force inward, and which is in opposite direction of the frictional force.Thus, the frictional force experience on the coin will be equal to the centripetal force.[tex]f=F_c=ma_c=m*r_1w^2\\f=140*10^{-3}*14*10^{-2}*4*\pi ^2=0.77N[/tex]
The coin will slide off the turntable, if it is located at a distance of 24cm.We have to find the coefficient of static friction when it is at a distance of 24cm from the axis of rotation.We have the expression for static friction as,[tex]f_s=kN,\\\\Where, \\N=mg\\\\k=\frac{f_s}{mg}[/tex]
We have to find the value of static friction at a distance 24 from the center of the table. This will be equal to the Fc at 24cm.[tex]F_c=f_s=mrw^2=140*10^{-3}*24*10^{-2}*4\pi ^2\\f_s=1.325N[/tex]
Thus, the coefficient of static friction will be,[tex]k=\frac{1.325}{140*10^{-3}*9.81}=0.964[/tex]
Thus, we can conclude that, the frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.
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a force of 3600 n is exerted on a piston that has an area of 0.040 m2 what force is exerted on a second piston that has an area of 0.20 m2 use f1 a1= f2 a2
Using the Pascal's principle formula, the force exerted on the second piston is 18000 N.
What is the force exerted on the second piston?The force on the second piston is determined using the formula from Pascal's principle.
The formula is given below:
[tex]\frac{f_{1}}{A_{1}} = \frac{f_{2}}{A_{2}}[/tex]
Solving for the force on the second piston, [tex]{f_{2}[/tex]
[tex]{f_{2} = \frac{A_{2}\times f_{1}}{A_{1}}[/tex]
[tex]{f_{2} = \frac {0.2\times3600}{0.04} = 18000 N[/tex]
In conclusion, the force on the second piston is 18000 N.
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A pendulum takes 4 seconds to make a complete swing. a man walks 100m in a straight line while the pendulum makes 20 complete swings. determine the average velocity of the man.
From the calculation, the man has an average velocity of 1.25 m/s.
What is average velocity?The man travelled a total distance = 100 m
We know that;
1 complete cycle = 4 s
Then
20 complete cycle = ?
= 20 x 4 s
= 80 s
So we can find the average velocity from;
Average velocity = 100 m/80 s
Average velocity = 1.25 m/s
Hence, the man has an average velocity of 1.25 m/s.
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Is the relationship between the appearance of the sample and the ntu value of each sample consistent for all samples
The relation between NTU unit and turbidity is based on appearance for all the samples therefore the values of respective NTU unit for all samples is between low and high.
What is meant by Turbidity?
Haziness or cloudiness in fluids as a result of dissolving two separate particles like totally dissolved solids or dissolved solids is known as Turbidity.
What is meant by NTU value?
The full form of NTU is Nephelometric Turbidity unit. It is the unit used to measure the turbidity of a given fluid, also to detect any presence of suspended particles in water.
The relation between suspended solid and NTU is:
1 mg/l (parts per million, ppm) = 3 NTU
Thus, as the relation between NTU unit and turbidity is based on appearance for all the samples therefore the values of respective NTU unit for all samples is consistent.
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1. A brick is dropped from a high wall. a. What is its velocity after 5.0 s? b. How far does the brick fall during this time?
Answer:
(I) 49m/s
(ii) 122.5m
Explanation:
Data obtained from the question include:
Time (t) = 5 s
Acceleration due to gravity (g) = 9.8 m/s²
(A) Determination of the brick's velocity.Time (t) = 4 s
Acceleration due to gravity (g) = 9.8 m/s²
Velocity (v) =?v = gt
v = 5× 9.8
v = 49 m/s
Thus, the brick's velocity after 4 s is 49m/s
B. Determination of how far the brick fall in 5 s.
Time (t) = 5 s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
h = ½gt²
h = ½ × 9.8 × 5²
h = 5× 16
h = 122.5 m
Thus, the brick fall 122.5m during the time.
A car travels 10.0 meters north in 9.0 seconds. The car then turns around and travels 5.0 meters south in 8.0 seconds. What is the magnitude of the average velocity of the car during this time interval
Magnitude of the average velocity is 0.3 m/s.
To find the answer, we need to know about average velocity.
What's the average velocity?Average velocity of an object is given as the ratio of displacement of the object and time.Mathematically, average velocity= displacement / timeWhat's the average velocity of the car travels 10.0 meters north in 9.0 seconds then turns around and travels 5.0 meters south in 8.0 seconds?Here the displacement of the car = 10m - 5m = 5mTime = 9+8= 17sAverage velocity= 5/17 = 0.3 m/sThus, we can conclude that the average velocity is 0.3 m/s.
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Which of the following best defines unbalanced forces?
O A. The total force on an object after individual forces are added
together
•
B. Forces between two objects in physical contact
•
C. Forces that act in opposite directions and cancel each other out
• D. Unequal forces that do not cancel out but cause a change in
motion
how do you come up with the innovative ideas to fulfil energy demands in pakistan?
Answer:
Pakistan has low rates of non renewable energy thus it is mandatory that the renewable resources be put into use. The vast deserts in punjab and sindh should be used to set up solar panels and the coastal areas of sindh and balochistan should be used as wind power. The northern areas have melting glaciers and high precipitation rates rates thus HYDEL power should be used in the form of dams
A 71.9 Kg mass is placed on an incline plane that is 38 degrees from the horizontal.
Assuming friction is present and the coefficient of friction is 0.61, what is the acceleration of
the mass? If the distance of the incline plane is 4.3 m, how long does it take the mass to
reach the bottom of the plane taking friction into account?
I need the steps on how to solve the problem please. I appreciate your help
Answer:
acceleration, a = 11m/s² ; time, t = 0.84sec
Explanation:
Fw = mass(m) × acceleration due to gravity(g)
Fw = 71.9kg × 10m/s²
Fw = 719N
F = Fw(sintheta+coefficient of friction(costheta))
F = 719(sin38° + 0.61(cos38°)
F = 719(0.615661475+0.480686559)
F = 719(1.096348034)
F = 788.27N
Force(F) = mass(m) × acceleration(a)
Make acceleration the subject
acceleration = Force÷ mass
a = 788.27÷719
a = 11m/s²
using this formula v² = u² +2gh
v² = 0² + 2×10m/s²×4.3m
√v² = √86
v = 9.27m/s
acceleration = velocity/time
make time the subject
time = velocity/acceleration
t = 9.27m/s/11m/s²
t = 0.84sec
A total of 590 C of charge passes through a flashlight in 0.470 h. What is the average current in milliamperes
Answer:
I = Q / t = 590 C / (.47 * 3600 sec) = .349 amperes
.349 amps * 1000 milliamps / amp = 349 milliamperes
If someone was to
place a cool lid on this
pot of boiling water,
what would happen?
A. The water particles will lose energy once they touch
the lid.
B. The water particles will gain energy once they touch
the lid.
C. The water particles will get locked in place once they
touch the lid.
Answer:B. The water particles will gain energy once they touch
the lid.
Explanation:
What will be the kinetic energy of a pile driver ram starting from rest that undergoes a 10- kJkJ decrease in potential energy
Kinetic energy of the pile driver is 10 KJ.
To find the answer, we need to know about the conservation of mechanical energy.
What's the conservation of mechanical energy?Conservation of mechanical energy says that the total energy of a system remains same during a process.
What's mechanical energy?Mechanical energy is the sum of potential energy and kinetic energy. As the mechanical energy is conserved, so when the potential energy is decreased the kinetic energy is increased with same amount that of decreased potential energy.Thus, we can conclude that the increased kinetic energy is 10KJ.
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If the force between the puffed rice pieces is 4 x 10^-23 N when the pieces are 0.03 m apart, what is the charge on each of the pieces?
2 x 10⁻¹⁸ C is the charge on each of the pieces.
What is the charge?In physics, Charge is electric charge, electrical charge, or electrostatic charge and symbolized as q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.
According to the question,
Fс = 4 x 10⁻²³ N
d = 0.03 m , k = 9.0 x 10⁹ N·m²/C²
q =?
The force exerted by one charge q on another charge Q a distance r away is given by:
Coulomb's law:
Fc =[tex]\frac{kq_{1} q_{2} }{d^{2} }[/tex]
By solving the equation:
[tex]q1q2 =\frac{F_{c} d^{2} }{k}[/tex]
[tex]\frac{(4*10^{-23}(0.03m )^{2} }{(9.0*10^{9}N.m^{2}/C^{2}) }[/tex]
= 4 x 10 ⁻³⁶C²
This is the square of the charge on the pieces of puffed rice.
Now, to find the charge on one piece of puffed rice,
take the square root of this number.
q = √4 x 10⁻³⁶ C²
q = 2 x 10⁻¹⁸ C
Therefore,
The charge on each of the pieces is 2 x 10⁻¹⁸ C
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Lamp 2 transfers a total of 18 000J of energy. 13 320 J of energy is
transferred usefully.
Calculate the efficiency of Lamp 2.
The efficiency of the lamp is 74%.
What is the efficiency of the lamp?The efficiency of the lamp is calculated using the formula below is used:
Efficiency = work output/work input × 100%Work input = 18000 J
Work output = 13320 J
Efficiency = 13320/18000 × 100% = 74 %
In conclusion, the efficiency of the lamp is less than 100%.
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Most of the really bright stars in our sky are NOT among the stars that are very close to us. Why then do they look so bright to us
Answer:
stars will emit more light due to their Luminosity, so they look very bright.
Explanation:
Luminous refers to..,
The total amount of energy radiated by a star or other celestial object per second. Therefore it is the power output of a star.Most of the really bright stars in our sky are not that very close to us yet they look bright because of the Luminosity of the star.
These stars are intrinsically so luminous.
A star's power output across all wavelengths is called its bolometric luminosity.
A star with large luminosity will have more measure of radiated electromagnetic power meaning.
so it will emit more light than a low luminosity star.
Hence,
those stars can easily be seen even across great distance.
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A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the weight density of water. Assume that a = 4 m, b = 4 m, c = 18 m, and d = 4 m.)
The answer is W = 1.06 MJ.
Now develop and express of Force required:
F = p*V*g
F = 1000*(2*0.5*x*8*dx)*g
F = 78480*x*dx
- Now, the work done is given by:
W = F.s
Where s is the distance from the top of the hose to the differential volume:
s = (5 - x)
We have the work as follows:
dW = 78400*x*(5-x)dx
Now integrate the following express from 0 to 3 till the tank is empty:
W = 78400*(2.5*x^2 - (1/3)*x^3)
W = 78400*(2.5*3^2 - (1/3)*3^3)
W = 78400*13.5 = 1058400 J
To find the weight of water, begin by way of finding the density(1 kg/L at 39.2°) and the extent of water. Convert the volume of water to liters after which multiply by way of the density to discover the burden.
Density is useful in calculating the load of materials which can be tough to weigh. you may decide its weight without a doubt with the aid of multiplying the density by using the dimensions, or quantity, of the item.
The unique weight, additionally called the unit weight, is the weight in keeping with the unit quantity of cloth. A typically used value is the precise weight of water in the world at 4 °C (39 °F), which is nine.807 kilonewtons consistent with cubic meters or 62. 43 pounds-force in keeping with cubic foot.
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What is electromagnet
Answer:
Electromagnetic is used to describe the electrical and magnetic forces or effects produced by an electric current.