in anova, the linearity assumption is assessed using a qq-plot of the residuals. t/f

Answer:

Georgio has to earn $1,800 and borrow $2,700.

The equation that states (x, y) is equidistant from (4, 1) and the x-axis is -8x - 2y + 17 = 0.

To express that the point (x, y) is equidistant from both the point (4, 1) and the x-axis, we can set up an equation using the distance formula.

The distance formula states that the distance between two points (x₁, y₁) and (x₂, y₂) is given by:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

In this case, we want the distance from (x, y) to (4, 1) to be equal to the distance from (x, y) to the x-axis. The x-axis can be represented by the equation y = 0.

Let's set up the equation:

√((x - 4)² + (y - 1)²) = √((x - x)² + (y - 0)²)

Simplifying, we get:

√((x - 4)² + (y - 1)²) = √(x² + y²)

To remove the square roots, we can square both sides of the equation:

((x - 4)² + (y - 1)²) = (x² + y²)

Expanding and simplifying further, we have:

x² - 8x + 16 + y² - 2y + 1 = x² + y²

Combining like terms, we obtain:

-8x - 2y + 17 = 0

Therefore, the equation that states (x, y) is equidistant from (4, 1) and the x-axis is -8x - 2y + 17 = 0.

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Answer:

-4 + -6 = -10

Step-by-step explanation:

From the line at negative 4 it goes to negative 10 you need to add six to four to make ten. Though since it is negative numbers we add a negative 6

Given that X₁, X₂, ..., Xₙ are iid according to a uniform continuous distribution over the open interval (0,0+1).

Now, we have to find a sufficient statistics for 8.Let T = ∑Xᵢ, then T ~ U(n*0,n).Thus, T is a sufficient statistic for θ.Hence, T is a sufficient statistics for 8.

Given that X₁, X₂, ..., Xₙ are iid according to a uniform continuous distribution over the open interval (0,0+1).

We have to find a minimally sufficient statistics for

Let T = (X(n), X(1)), where X(n) = max{X₁,X₂, .... Xₙ} and X(1) = min{X₁,X₂, .... Xₙ}.As Xᵢ follows uniform distribution, so T can take any value in [0, 1].

Let Y = nX(n)/(1-X(n)), thenY = (nX(n))/(1-X(n)) = (nX(n))/(X(n)-X(1)) = 1/[(X(n)-X(1))/n].Now, 0 < X(1) ≤ X(n) < 1. Therefore, 0 < (X(n)-X(1))/n ≤ 1/n. Then, Y takes values in [0,∞).Thus, Y is a one-to-one function of T.

Hence, T is a minimally sufficient statistics for 8.

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Step-by-step explanation:

True

false

false

true

i think its that I'm sorry if its wrong

The value of ∠FGJ = x⁰ is 45⁰.

Linear pair of angles are formed when two lines intersect each other at a single point. The angles are said to be linear if they are adjacent to each other after the intersection of the two lines. The sum of angles of a linear pair is always equal to 180°.

Here, we know that sum of angles on linear pair is 180⁰.

        ∠FGJ = x⁰ and ∠JGH = 135⁰

∠FGJ + ∠JGH = 180⁰

    x⁰ + 135⁰ = 180⁰

    x⁰ = 180⁰ - 135⁰

    x⁰ = 45⁰

Thus, the value of ∠FGJ = x⁰ is 45⁰.

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Answer:

it's just a angle that is 3D

Step-by-step explanation:

Answer:

Hello, Brainly users, hi hows your day going. Great. Yeah thanks for asking. Anyway, the answer is 5.2.

Step-by-step explanation:

Will provide step-by-step explanation as to how I figured it out if I can get brainliest *HINT HINT*. Have a good day. And keep good vibes amid the pandemic

:D

Answer:

5.2

Plz mark me as brainliest.

Answer: -9

2 to the power of 0 = 1 then all you have to do is plug in the numbers and simplify

Answer:

-9

Step-by-step explanation:

Well you just subsitute it all and solve from there

s^0= 2^0

p^-2= -3^-2

Anything squared to the power of 0 is 1

so its already 1/smth

the second part is just 3^-2 first which is 1/9 then the negative sign which is -1/9

Answer:

B) y=3.5x^2 +0.5

Step-by-step explanation:

the (0,0.5) tells you what the y-intercept is :)

hope this helps :)

Answer:

The experimental probability should get closer to the theoretical probability of 1/6 with more trials.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Experimental probability:

The number of desired outcomes is taken from the results of an experiment.

Theoretical probability:

Found before the experiment happens.

For a large number of trials, the experimental probability will be closer to the theoretical probability.

In this question:

A standard die has 6 sides, one which is 3. So the theoretical probability of rolling a 3 is 1/6.

After six rolls of a standard die, the experimental probability of rolling a 3 is 2/6.

The experimental probability, after six rolls, is 2/6 = 1/3.

What do you expect will happen to the experimental probability if the die is rolled 90 more times?

As the number of trials increase, the experimental probability is expected to get closer to the theoretical probability, which in this case is 1/6.

Answer:

13.9%

Step-by-step explanation    :

Converting from a decimal to a percentage is done by multiplying the decimal value by 100 and adding %.

 0.138613961 ------ when multiplying by 100 you move two spots the decimal point:     13.8613961 %

The tenth digit is 8 the number after that is 6  

If the digit after tenth is greater than or equal to 5, add 1 to tenth. Else remove the digit.

6 is greater than 5 so we add 1 to 8 and becomes 9

If the digit  after the tenth was 4 instead 6, for example,then it would be 13.8%

Answer:

1±√2=q

or

q=2.41, -0.41

Step-by-step explanation:

we are given the equation q²-2q-1=0, and we want to use the quadratic equation, which is (-b±√(b²-4ac))/2a

a is 1 (there is a 1 in front of q²)

b is -2

c is -1

substitute into the equation:

q=(2±√(4-4*1*-1))/2

solve for the discriminant:

√(4-4(1*-1))

√8

now the equation:

(2±√8)/2=q

simplify:

1±√2=q

or if your application asks for a decimal:

√2≈1.41

so:

1+1.41=2.41=q

or

1-1.41=-0.41=q

Hope this helps!

Answer:

Step-by-step explanation:

x+3 - x = 3 = width

2(x+3) = 2x + 6 = length

2x + 6 +2x +6 +3 +3 = 4x + 18 = Perimeter of T

Answer:

Step-by-step explanation:

a. annual premium: 79.35

b. monthly premium: 7.14

Marcie Ann Weber, age 32, takes out $15,000 of a term insurance for a ten-year term. Annual premium = $1,500 per year and monthly premium = $125 per month.

One type of operation is division in mathematics. In this procedure, the phrases or numbers are divided into the same number of components.

Given: Marcie Ann Weber,

insured amount of term insurance plan = $15,000.

Number of year = 10 year

To find the amount of annual premium:

Divide the total insured amount by number of years.

Annual premium = Insured amount of term insurance plan / Number of year

Annual premium = $15,000 / 10

Annual premium = $1,500 per year

To find the amount of monthly premium:

Monthly premium = Insured amount of term insurance plan / Number of month in 10 year

Monthly premium = 15,000 / (10 x 12)

Monthly premium = 15,000 / 120

Monthly premium = $125 per month.

Therefore, annual premium = $1,500 per year and monthly premium = $125 per month.

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Answer:

Number 1 is correct

4.5 x 12 = 54

Number 3 is wrong,

Formula of a triangle:

BH x 1/2(basically dividing by 2)

8 x 15 = 120,

120 DIVIDED BY 2 = 60 is your area, not 120.

Your plug in would be for the triangle:

8 x 15 x 1/2

Number 5 is wrong.

11 + 4 = 15

15 x 6 (you forgot to multiply by the height!) = 90

90 divided by 2 ( x 1/2) = 45 is your area, NOT 90.

Your formula for a trapezoid is:

(b1 + b2) x h x 1/2 Don't forget your height next time!

Plug in: (4 + 11) x 6 x 1/2

Answer:

I think! 3.5 feet wide

Step-by-step explanation:

the area of the pool is 240 square feet. divide by 68 square feet gives you 3.539= 3.5 feet wide. dont shoot me if I'm wrong lol

The width of the deck is approximately 2.65 feet.

To solve the problem, we need to first find the total area of the pool and deck combined, and then subtract the area of the pool to find the area of the deck.

The total area of the pool and deck can be represented as follows:

(12 + 2x) x (20 + 2x)

where x is the width of the deck.

The area of the pool is:

12 x 20 = 240

So, the area of the deck can be found by subtracting the area of the pool from the total area:

(12 + 2x) x  (20 + 2x) - 240 = 68

Expanding the left side and simplifying, we get:

4x²+ 64x - 208 = 0

Dividing both sides by 4, we get:

x²+ 16x - 52 = 0

Using the quadratic formula, we get:

x = (-b ± √(b² - 4ac)) / 2a

Where a = 1, b = 16, and c = -52.

Plugging in these values, we get:

x = (-16 ± √(16² - 4(1)(-52))) / 2(1)

x = (-16 ± √(960)) / 2

x = (-16 ± 4√(15)) / 2

x = -8 ± 2√(15)

Since the width of the deck cannot be negative, we can discard the negative solution, and we are left with:

x = -8 + 2√(15)

So, the width of the deck is approximately 2.65 feet.

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The given second-order linear differential equation, 1y'' + 4y' + y = x^2 - 4x, can be solved using the method of undetermined coefficients. The particular solution is obtained by assuming a form for the solution and determining the coefficients based on the right-hand side of the equation.

To solve the given differential equation by undetermined coefficients, we first consider the homogeneous equation, which is obtained by setting the right-hand side equal to zero: 1y'' + 4y' + y = 0. The characteristic equation associated with this homogeneous equation is [tex]r^2[/tex]+ 4r + 1 = 0, where r represents the roots of the equation. Solving this quadratic equation, we find two complex conjugate roots: r = -2 ± i.

Since the right-hand side of the original equation is a polynomial of degree 2, we assume a particular solution of the form y_p = A[tex]x^{2}[/tex] + Bx + C. Substituting this assumed form into the original equation, we differentiate it twice to obtain the expressions for y''_p and y'_p, and substitute them back into the original equation. This allows us to equate the coefficients of like powers of x on both sides of the equation.

By comparing coefficients, we find that A = 1 and B = -2. However, the term C is a constant and does not contribute to the differential equation. Hence, the particular solution is y_p = [tex]x^{2}[/tex] - 2x.

Finally, the general solution of the differential equation is given by the sum of the homogeneous solution and the particular solution: y = y_h + y_p. Since the homogeneous solution contains complex roots, it can be expressed as y_h =[tex]e^{-2x}[/tex](C_1cos(x) + C_2sin(x)), where C_1 and C_2 are arbitrary constants. Thus, the complete solution is y = [tex]e^{-2x}[/tex]C_1cos(x) + C_2sin(x)) + [tex]x^2[/tex] - 2x.

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Answer:

1256 square inches

Step-by-step explanation:

Area of a circle:

A = πr²

Given:

r = 20

Work:

A = πr²

A=(3.14)20²

A = 3.14(400)

A = 1256

Answer:

1256 square inches.

Step-by-step explanation:

20 squared * π = 1256 square inches

 The answer is not provided in the given options.

To simplify the expression (4x^3 - 3x - 7)(3x^3 + 5x + 3), we can use the distributive property of multiplication.

Multiplying each term in the first expression by each term in the second expression, we get:

(4x^3)(3x^3) + (4x^3)(5x) + (4x^3)(3) + (-3x)(3x^3) + (-3x)(5x) + (-3x)(3) + (-7)(3x^3) + (-7)(5x) + (-7)(3)

Simplifying each term, we have:

12x^6 + 20x^4 + 12x^3 - 9x^4 - 15x^2 - 9x - 21x^3 - 35x - 21

Combining like terms, we get:

12x^6 + (20x^4 - 9x^4) + (12x^3 - 21x^3) + (-15x^2) + (-9x - 35x) + (-21)

Simplifying further, we have:

12x^6 + 11x^4 - 9x^3 - 15x^2 - 44x - 21

Therefore, the correct simplification of (4x^3 - 3x - 7)(3x^3 + 5x + 3) is:

12x^6 + 11x^4 - 9x^3 - 15x^2 - 44x - 21.

Therefore, the answer is not provided in the given options.

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The given arguments are proved using logical inference rules.

To show that each of the following arguments is valid, we need to construct a proof using logical inference rules. Here is a proof for the given arguments:

Argument 1:

1. C ⊃ D (Premise)

2. ~(A ∨ B) ∨ C (Premise)

3. ~B ∨ D (Premise)

4. ~(A ∨ B) (Assumption)

5. ~A ∧ ~B (De Morgan's Law, 4)

6. ~B (Simplification, 5)

7. D (Disjunctive Syllogism, 3, 6)

8. ~(A ∨ B) ∨ D (Disjunction Introduction, 7)

9. C (Disjunction Elimination, 2, 8)

10. ~(A ∨ B) ∨ C (Disjunction Introduction, 9)

Therefore, the argument is valid.

Argument 2:

1. C ⊃ D (Premise)

2. ~(A ∨ B) ∨ C (Premise)

3. ~B ∨ D (Premise)

4. ~A ∨ ~B (Assumption)

5. ~(A ∨ B) (De Morgan's Law, 4)

6. C (Disjunction Elimination, 2, 5)

7. C ⊃ D (Premise)

8. D (Modus Ponens, 6, 7)

9. ~B ∨ D (Disjunction Introduction, 8)

10. ~(A ∨ B) ∨ D (Disjunction Introduction, 9)

Therefore, the argument is valid.

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The total number of elements in an array is indeed equal to the product of its number of rows and columns. In this case, since the array has 4 rows and 7 columns, the total number of elements is 4 x 7 = 28.

The total number of elements in an array is equal to the product of its number of rows and columns. In this case, the array has 4 rows and 7 columns, so the total number of elements is:

4 x 7 = 28

Therefore, the answer is (c) 28.

The total number of elements in an array is indeed equal to the product of its number of rows and columns. In this case, since the array has 4 rows and 7 columns, the total number of elements is 4 x 7 = 28.

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Answer:

The factors of x²-64 is equal to (x-8)(x+8).

Step-by-step explanation:

The given expression is:

x²-64

we know that, 8² = 64

So,

(x²-8²) = (x-8)(x+8) [As (a-b)(a+b) = a²-b²]

So, the factors of x²-64 i equal to (x-8)(x+8).

Answer:

400

Step-by-step explanation:

The area of sides and add then up

Answer:

angle 3=angle (vertical opposite angle)

angle 3 +angle 2=180°(by linear pair)

136°+angle 2=180°

angle 2=180°-136°

angle 2=44°

angle 2=angle 4(by vertical opposite angle)

Given the random variable X with specific expected values and the equation Y = a + bx + cX, we are asked to find the correlation coefficient p(X,Y).

The correlation coefficient between two random variables X and Y is given by the formula:

p(X,Y) = Cov(X,Y) / sqrt(Var(X) * Var(Y))

To calculate the correlation coefficient, we need to find the covariance (Cov(X,Y)) and the variances (Var(X) and Var(Y)).

Given the expected values, we can calculate the required values as follows:

Cov(X,Y) = E[XY] - E[X]E[Y]

Var(X) = E[[tex]X^2[/tex]] - [tex](E[X])^2[/tex]

Var(Y) = E[tex][(Y - E[Y])^2][/tex]

Using the provided expected values, we can substitute them into the formulas:

Cov(X,Y) = E[XY] - E[X]E[Y] = E[(a + bx + cX)X] - (0)(E[a + bx + cX]) = E[aX + b[tex]X^2[/tex] + c[tex]X^2[/tex]] = a(E[X]) + b(E[[tex]X^2[/tex]]) + c(E[[tex]X^3[/tex]])

Var(X) = E[[tex]X^2[/tex]] - [tex](E[X])^2[/tex] = 1 - [tex](0)^2[/tex] = 1

Var(Y) = E[(Y - [tex]E[Y])^2[/tex]] = E[(a + bx + cX - [tex](E[a + bx + cX]))^2[/tex]] = E[[tex](a + bx + cX)^2[/tex]]

Using the provided values for E[[tex]X^3[/tex]] and E[[tex]X^4[/tex]], we can simplify the expressions further and calculate the values.

Once we have the values of Cov(X,Y), Var(X), and Var(Y), we can substitute them into the correlation coefficient formula to find p(X,Y).

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