In a triangle ABC, let G denote its centroid and let M,N be points in the interiors of the segments AB,AC, respectively, such that M,G,N are collinear. If r denotes the ratio of the area of triangle AMN to the area of ABC then find r.

a) [tex]\log \left(\dfrac{A^3B}{C} \right) = 3\log A + \log B - \log C[/tex]

b) [tex]\log \left(\dfrac{\sqrt{A}}{B^2} \right) = \frac{1}{2}\log A - 2\log B[/tex]

Answer:

The answer is in the picture.

15cm²

Answer:

[tex]g(t) = 0[/tex]

Step-by-step explanation:

Given

[tex]d = 1000m[/tex]

[tex]f(t) \to[/tex] Tortoise

[tex]g(t) \to[/tex] Hare

Required

Time needed by the Hare to complete the race

The function [tex]g(t)[/tex] implies that the Hare is t seconds from completing the race.

When g(t) = 0, it means that the Hare has completed the race

So, to calculate the time needed by the Hare;

We simply equate g(t) to 0, then solve for t

Answer:

x = 20

Step-by-step explanation:

90° - 76° = 14°

[tex](x-6)=14[/tex]

[tex](x+6)=+6[/tex]         Add 6 to both sides

   x      =   20

Hence, x = 20

Answer: X=20

Right angles are 90 degrees and 90-76=14... X-6=14... add 6 to 14 and get 20. X=20. Don't quote me on it I haven't done this stuff in a year.

Answer:

hygu

Step-by-step explanation:

yg9k

Answer:

The average of rate was of 0.4314 cm/day, which means that on average, during this interval, the plant grew by 0.4314 cm each day.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function f(x), from x = a to x = b, is given by:

[tex]A = \frac{f(b)-f(a)}{b-a}[/tex]

In this question:

[tex]f(x) = 12(1.03)^n[/tex]

From n = 3 to n = 10

[tex]a = 3, b = 10[/tex]

[tex]f(b) = f(10) = 12(1.03)^{10} = 16.13[/tex]

[tex]f(a) = f(3) = 12(1.03)^{3} = 13.11[/tex]

Average rate of change:

[tex]A = \frac{f(b)-f(a)}{b-a} = \frac{16.13-13.11}{10-3} = 0.4314[/tex]

The average of rate was of 0.4314 cm/day, which means that on average, during this interval, the plant grew by 0.4314 cm each day.

Answer:

The height of the tree is 430cm

Step-by-step explanation:

Given

The attached illustration

Required

The height of the tree

Let:

[tex]h \to[/tex]  Hank's height

[tex]H \to[/tex] Tree height

[tex]d \to[/tex] distance between Hank and Mirror

[tex]D \to[/tex] distance between tree and Mirror

From the question, we have:

[tex]\angle 1 = \angle 2[/tex]

This means that:

[tex]\frac{H}{D} = \frac{h}{d}[/tex]

Make H the subject

[tex]H = \frac{h}{d} * D[/tex]

So, we have:

[tex]H = \frac{172cm}{190cm} * 475cm[/tex]

[tex]H = \frac{172* 475cm}{190}[/tex]

[tex]H = \frac{81700cm}{190}[/tex]

[tex]H = 430 cm[/tex]

Answer:

x=22

Step-by-step explanation:

the triangle in which x is in is an equilateral triangle.

44 is an exterior angle to that triangle.

an exterior angle is always equal to tbe sum of the opposite 2 interior angles.

because that triangle is equilateral

x =44 ÷ 2

x=22

Answer:

$24.63

Step-by-step explanation:

Surface area of a sphere = 4πr²

Surface area of the sphere

= 4π7²

= 196π

= 615.752... cm²

The total cost

= 0.04 × 615.752...

= $24.63 (rounded to the nearest hundredth)

Answer:

y = -3x-2

Step-by-step explanation:

3y = -9x-6. y = (-9x-6)/3. y = (-9x/3)+(-6/3). y = -3x-2

Given:

The figure of a quadrilateral ABCD.

To find:

The perimeter of the quadrilateral ABCD.

Solution:

In an isosceles triangle, the two sides and base angles are congruent.

In triangle ABD,

[tex]\angle DAB\cong \angle ABD[/tex]               [Given]

[tex]\Delta ABD[/tex] is an isosceles triangle      [Base angle property]

[tex]AD=BD[/tex]                   [By definition of isosceles triangles]    

[tex]8=BD[/tex]                   ...(i)

In triangle BCD,

[tex]\angle BCD\cong \angle CDB\cong \angle CBD[/tex]        [Given]

All interior angles of the triangle BCD are congruent, so the triangle BCD is an equilateral triangle and all sides of the triangle area equal.

[tex]BC=CD=BD[/tex]

[tex]BC=CD=8[/tex]      [Using (i)]               ...(ii)

Now, the perimeter of quadrilateral ABCD is:

[tex]Perimeter=AB+BC+CD+AD[/tex]

[tex]Perimeter=11+8+8+8[/tex]

[tex]Perimeter=35[/tex]

Therefore, the perimeter of the quadrilateral ABCD is 35 units.

Answer:

f(x)=2x³+4x²+5

Step-by-step explanation:

1) the rule of the even function is: f(-x)=f(x)

the rule of the odd function is: f(-x)=-f(x);

2) the function f(x)=2x³+4x²+5 is neither even or odd according to the rules above:

f(-x)= -2x³+4x²+5= -(2x³-4x²-5).

Answer:

ok so we know the amount we know the interest amount but we do know know the period of time so the equation would look like this

28000(0.4)T=I

T=Time

I=interest

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The graph shown with your problem statement does not pass the vertical line test, so is not the graph of a function. (A vertical line intersects the graph in more than one place.) This graph can be rejected immediately.

I find it convenient to look at the domain statements (x≤1 and x>1). This tells you that you can separately evaluate the graph to the left of x=1 and to the right of x=1. Each of those portions of the graph must match the corresponding expression.

Here, it looks sufficient to identify the slope of the line in each domain. (We don't know what graphs you're selecting from, so we don't know what you will need to look at to differentiate the correct one from the rest.)

For x < 1, the coefficient of x is 3, so the line will have a steep upward slope.

For x > 1, the coefficient of x is -2, so the line will have a slightly less steep downward slope.

The value of z(1) is 3(1)-2=1, so (1, 1) is at the top end of the line forming the left side of the graph. The limit as x approaches 1 from the right is -2(1)+3=1. This means the two lines meet at the point (1, 1) and the graph has a generally ∧ shape. The attachment shows the graph you're looking for.

Answer:

The correct answer is:304

Step-by-step explanation:

12? im not sure

i think u need to multiply 6 and 2 to get your answer.

Answer:

56 degrees

Step-by-step explanation:

We know, the sum of the three angles of any triangle is equal to 180 degrees.

63 + 61 = 124

Now, 180 - 124 = 56 degrees

Hope this will help. Please give me brainliest.

Answer:

entonces no habria oxigeno

Step-by-step explanation:

9514 1404 393

Answer:

  (A)  6

Step-by-step explanation:

Divisors of 6 are ...

 1, 2, 3, 6

The sum of all but the last is 1+2+3 = 6.

Then  <<<6>>> = <<6>> = <6> = 6.

_____

Additional comment

Among integers less than 200, only 6 and 28 are solutions to <n> = n.

Answer:

1) 7/2 - 3/2y,

2) 3-y, y

Step-by-step explanation:

See Image below for steps:)

9514 1404 393

Answer:

  -50%

Step-by-step explanation:

Suppose the fraction is f = p/q before any changes.

Decreasing the numerator by 60% multiplies it by (1 -0.60) = 0.4.

Decreasing the denominator by 20% multiplies it by (1 -0.20) = 0.8.

Then the new fraction is ...

  f' = p(0.4)/(q(0.8)) = (p/q)(0.4/0.8) = f(0.5) = f(1 -0.50) = f(1 +(-50%))

The increase in the value of the fraction is -50%.

Answer:

15.8 cm²

Step-by-step explanation:

Please see attached photo for diagram.

We'll begin by calculating the angle A. This can be obtained as follow:

B = 56°

C = 78°

A =?

A + B + C = 180 (Sum of the angle in triangle)

A + 56 + 78 = 180

A + 134 = 180

Collect like terms

A = 180 – 134

A = 46°

Next, we shall determine the value of b by using the sine rule. This can be obtained:

Side opposite angle C (c) = 7.2 cm

Angle C = 78°

Angle B = 56°

Side opposite angle B (b) =?

b/Sine B = c/sine C

b/Sine 56 = 7.2/Sine 78

Cross multiply

b × Sine 78 = 7.2 × Sine 56

Divide both side by Sine 78

b = 7.2 × Sine 56 / Sine 78

b = 6.1 cm

Finally, we shall determine the area of the triangle. This can be obtained as follow:

Side opposite angle C (c) = 7.2 cm

Side opposite angle B (b) = 6.1 cm

Angle A = 46°

Area (A) =?

A = ½bcSineA

A = ½ × 6.1 × 7.2 × Sine 46

A = 15.8 cm²

Therefore, the area of the triangle is 15.8 cm²

Answer:

The joint probability of the two events is one.

Step-by-step explanation:

Complementary events:

If two events are complimentary, these three following things are true:

They are dependent.

The intersection of them is zero.

The joint probability of the two events is one.

The last one is the correct choice.

Answer:

hi, it's b because a+b is 180°

Answer:

17x + 2 = 16x+6

17x-16x= 6-2

x=4

Answer:

5.21212121

Step-by-step explanation:

The first thing to keep in mind is that a line is equal to 180. The first thing you sould start off by doing is write 17x+2+16x+6. Then to make it easier combine the like terms. Both combine 17x + 16x to get 33x, and 6 and 2 to get 8. Now the problem should be 33x + 8 = 180. Next we will take away 8 from both sides. This should eliminate 8 for us and give us 33x=180 as our next problem. Finally you will do the opposite of multiplying which is diving. 33 divided by itself gives us 0. So we will divide 172 by 33 to get 5.21212121.

YOU MAY PLUG THIS NUMBER BACK IN TO CHECK YOUR ANSWER.

Answer:

you first use the coefficients of the letters to times each equation.

Then you either subtract or divide to eliminate the first letter and it coeeffient.

then whatever you get you will divide it with the one with no letter.

then you substitute the answer for the letter in any of the equation.

then you solve it.

I hope this is helpful.

Answer:

20

Step-by-step explanation:

100/5=20

Answer:

[tex]3 \sqrt{2} [/tex]

Step-by-step explanation:

Given

[tex] \frac{ \sin(60) \sec(60) \cot(30) }{ \cos( 45) ) } [/tex]

Using the unit circle, we know that

[tex] \sin(60) = \frac{ \sqrt{3} }{2} [/tex]

[tex] \cos(45) = \frac{ \sqrt{2} }{2} [/tex]

We can find sec and cot by using reciprocal identies.

[tex] \sec(x) = \frac{1}{ \cos(x) } [/tex]

[tex] \cos(60) = \frac{1}{2} [/tex]

So

[tex] \sec(60) = 2[/tex]

[tex] cot(x) = \frac{1}{ \tan(x) } [/tex]

[tex] \tan(30) = \frac{1}{ \sqrt{3} } [/tex]

so

[tex] \cot(30) = \sqrt{3} [/tex]

Plug in the values.

[tex] \frac{ \frac{ \sqrt{3} }{2} \times 2 \times \sqrt{3} }{ \frac{ \sqrt{2} }{2} } [/tex]

[tex] \frac{ \frac{ \sqrt{3} }{2} \times \frac{ \sqrt{12} }{1} }{ \frac{ \sqrt{2} }{2} } [/tex]

[tex] \frac{3}{ \frac{ \sqrt{2} }{2} } [/tex]

[tex]3 \sqrt{2} [/tex]