The proportion of the low-income group who are social networking users is 0.6514.
The proportion of the high-income group who are social networking users is 0.6144.
We have the following information from the question:
A research organization found that 228 of the 350 respondents who reported earning less than $30,000 per year said they were social networking users.
Another income scale, 290 of the 472 respondents reporting earnings of $75,000 or more were social networking users.
We have to find proportions of each income group who are social networking users.
Low-income group:
228 users / 350 respondents = 0.6514
The proportion of the low-income group who are social networking users is 0.6514.
High-income group:
290 users / 472 respondents = 0.6144
The proportion of the high-income group who are social networking users is 0.6144.
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According to a recent survey, the probability that the driver in a fatal vehicle accident is female (ovont F) is 0.2907 The probability that the driver is 24 years old or less (event A) is 0.1849. The probability that the driver is female and is 24 years old or less is 0.0542.
a. Find the probability of FUA
b. Find the probability of F'UA
The probability of F'UA is 0.9458.
According to the given data; the probability of ovont F is 0.2907, the probability of event A is 0.1849 and the probability of the driver is female and is 24 years old or less is 0.0542.
Here are the required probabilities;
a. The probability of FUA:F: Female U: 24 years old or less A: Fatal vehicle accident We can find the probability of FUA using the formula; P(FUA) = P(F ∩ U ∩ A)
We know that the probability of the driver in a fatal vehicle accident is female is 0.2907P(F) = 0.2907 Also, we know that the probability that the driver is 24 years old or less is 0.1849.P(U) = 0.1849
We also know that the probability that the driver is female and is 24 years old or less is 0.0542.P(F ∩ U) = 0.0542Now we can use the formula; P(FUA) = P(F ∩ U ∩ A)= P(F) x P(U) x P(A|FU)= 0.2907 × 0.1849 × (0.0542 / 0.2907)= 0.0542
So, the probability of FUA is 0.0542.
b. The probability of F'UA: It can be calculated by using the complement of FUA.P(F'UA) = 1 - P(FUA)= 1 - 0.0542= 0.9458
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Answer:
Step-by-step explanation:
Given data: The probability that the driver in a fatal vehicle accident is female (event F) is 0.2907. The probability that the driver is 24 years old or less (event A) is 0.1849. The probability that the driver is female and is 24 years old or less is 0.0542.
a) The probability of FUA is 0.4214.
b) The probability of F'UA is 0.5786.
a) The probability of FUA can be calculated as follows:
P(FUA) = P(F) + P(A) - P(F ∩ A) [By Addition Law], Where P(F) = 0.2907, P(A) = 0.1849, P(F ∩ A) = 0.0542.
By putting these values in the above equation we get:
P(FUA) = P(F) + P(A) - P(F ∩ A)
= 0.2907 + 0.1849 - 0.0542
= 0.4214
Therefore, the probability of FUA is 0.4214.
b) The probability of F'UA can be calculated as follows:
P(F'UA) = P(F' ∩ A') [By Complement Law], Where
P(F' ∩ A') = 1 - P(FUA)
= 1 - 0.4214
= 0.5786
Therefore, the probability of F'UA is 0.5786.
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How to write 0.00080 as a power of 10?
Answer:
8 × 10⁻⁴
Step-by-step explanation:
The figures are similar. find x.
What is the value of s?
_____units
Answer:
17
Step-by-step explanation:
by Pythagoras
[tex]8 {}^{2} + 15 {}^{2} = {x}^{2} [/tex]
x=17
Bridget has captured many purple-footed bog frogs. She weighs each one
and then counts the number of yellow spots on its back. This trend line is a
fit for these data.
$
Number of spots
NA DONN
1 2 3 4 5 6 7 8 9 10 11 12
Weight (g)
A. strong
B. parabolic
c. negative
D. weak
Answer:
A. Strong
Step-by-step explanation:
I took the test
Have a great day! ;)
This trend line is a strong fit for these data. Then the correct option is A.
What is the linear system?A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
Bridget has captured many purple-footed bog frogs.
She weighs each one and then counts the number of yellow spots on its back.
This trend line is a strong fit for these data.
Because all the points are closer to the line.
Then the correct option is A.
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Scuba tanks arrive at a pressure test station for testing prior to shipment. The arrival rate is 16mins and the station test time averages 8 minutes per tank. Poisson distributions are assumed
A. What is the utilization of the test station?
B. What is the probability that a tank have to wait in the queue prior to testing?
C. What is the mean time a tank will spend in queue?
D. What is the mean time that a tank will spend in the system ?
E. What is the mean number of tanks that might be expected to be in queue at any time?
F. What is the mean number of tanks that might be expected to be in the system at any time ?
G. What is the probability of finding four or more tanks in the system at any time ?
H. Find the probability of 6 or more in the system
The probability of finding four or more tanks in the system at any time is approximately 0.95. The probability of having 6 or more tanks in the system is approximately 0.77.
A. The utilization of the test station is calculated by dividing the average service rate (1 tank per 8 minutes) by the arrival rate (1 tank every 16 minutes). Utilization = Service rate / Arrival rate = 1/2 = 0.5 or 50%.
B. The probability that a tank has to wait in the queue prior to testing can be calculated using the queuing theory formula for the M/M/1 queue. In this case, the utilization (ρ) is 0.5. The formula for the probability of waiting in the queue (Pw) is Pw = ρ^2 / (1 - ρ) = 0.5^2 / (1 - 0.5) = 0.25 / 0.5 = 0.5 or 50%.
C. The mean time a tank spends in the queue can be calculated using Little's Law, which states that the mean number of customers in a stable system (L) is equal to the arrival rate (λ) multiplied by the mean time spent in the system (W). In this case, L = λ * W. The mean number of tanks in the queue (Lq) can be calculated using Lq = λ * Wq, where Wq is the mean time spent in the queue. Given λ = 1/16 tanks per minute and Lq = 8 tanks, we can rearrange the equation to solve for Wq: Wq = Lq / λ = 8 / (1/16) = 128 minutes / 16 = 8 minutes.
D. The mean time a tank spends in the system (queue + test) is equal to the mean time spent in the queue (Wq) plus the mean service time (1/8 tanks per minute). Therefore, the mean time in the system (Ws) is Ws = Wq + 1/μ = 8 + 1/8 = 8.125 minutes.
E. The mean number of tanks expected to be in the queue at any time can be calculated using Little's Law: Lq = λ * Wq. Given λ = 1/16 tanks per minute and Wq = 8 minutes, we can calculate Lq: Lq = (1/16) * 8 = 0.5 tanks.
F. The mean number of tanks expected to be in the system at any time can be calculated using Little's Law: L = λ * Ws. Given λ = 1/16 tanks per minute and Ws = 8.125 minutes, we can calculate L: L = (1/16) * 8.125 = 0.507 tanks.
G. The probability of finding four or more tanks in the system at any time can be calculated using the Poisson distribution formula. By summing the probabilities for four, five, and more tanks, we get 0.043.
H. The probability of having 6 or more tanks in the system can also be calculated using the Poisson distribution formula, which results in a probability of 0.002.
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Emily played softball all weekend. She was wondering the difference in time between the shortest game and the longest game. Can you help her figure it out?
Answer:
hh
Step-by-step explanation:
What is the range of the absolute value function shown in the graph?
A. 3 ≤ y < ∞
B. -∞ < y ≤ 3
C. -6 ≤ y < ∞
D. -∞ < y < ∞
Answer:
C. -6 ≤ y < ∞
C is correct
Step-by-step explanation:
edmentum
please soon aaaaaaaaaaaaaaaaaaaaaaa
Answer:
3
Step-by-step explanation:
Jordan runs to the end of his street and back home every day. The total distance of a trip to the end of the street and back home is 7/8 mile.
How many miles has Jordan run after 6 days?
Jordan has run 21/4 miles after 6 days.
Jordan runs to the end of his street and back home every day and the total distance of a trip to the end of the street and back home is 7/8 mile.
Since Jordan runs to the end of the street and back home every day, the distance he runs in one day is given by;
2 × (distance to the end of the street)
= 7/8 mile (distance to the end of the street)
= 7/16 mile
The distance Jordan runs in 6 days is;
6 × (distance to the end of the street and back home)
= 6 × 7/8 miles
= 42/8 miles
= 21/4 miles
Therefore, Jordan has run 21/4 miles after 6 days.
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Please answer the question in the picture
Answer:
Hey kid stop cheating XDDDDDDDDDDDDDDDDDDD
Step-by-step explanation:
Carrie sewed a square blanket with an area of 225 in^2
What is the length of each side of the blanket?
A. 56.25 in
B. 15 in
C. 112.5 in
D. 10 in
Answer:
The answer is A 56.25
Step-by-step explanation:
Since a square has 4 sides, divide 225 by 4 to get 56.25. To check your answer multiply 56.25 x 4 to get 225 in^2.
Hope this helps! Pls mark Brainliest!
Answer:
a.56.25
Step-by-step explanation:
A party store sold a total of 4,032 balloons since they open 42 days ago.they sold the same amount of balloons each day how many balloons did the party store sell each day since it opened?
A 86 balloons
B 90 balloons
C 92 balloons
D 96 balloons
Answer:
D)
Step-by-step explanation:
Sana maka tulong po
shout out tga pagadian
Write two sentences to explain what taxes are.
Answer:
Taxes are money paid to the government, you need to pay these for the army , teachers, and it forms a better economy etc.!:) Have a nice day friend.
Step-by-step explanation:
rylee1015, it does matter because you are copying answers just to get points, and it might be wrong which is not fair, so stop it!!!:(
the figures are similar find X
Answer:
X=14.4Step-by-step explanation:
As triangles are similar
The ratio of the sides must be equal
so..
[tex]\frac{x}{8} =\frac{9}{5}[/tex]
[tex]x=\frac{9*8}{5}[/tex]
[tex]x=14.4[/tex]
hope it helps...
have a great day!!
y=-3 - x, how to draw the graph
Answer: See attachment below (graphing)
Step-by-step explanation:
INFORMATION:
The slope-intercept is when y=mx+b
mx=the slope
b=y-intercept
REPHRASE EQUATION:
y=mx+b
y=-3-x
y=(-1)x-3
CONCLUSION:
Slope=-1
Y-intercept=-3
Hope this helps!! :)
Please let me know if you have any questions
Answer:
the graph: y = -3 - x
The mean and standard deviation of a population are 200 and 20, respectively. What is the probability of selecting one data value less than 190?
A. 42%
B. 58%
C. 31%
D. 69%
When the variances of the population distribution and the sampling distribution of means are compared, the:
A. variances have the same degrees of freedom.
B. population variance is larger than the sampling distribution variance.
C. population variance is smaller than the sampling distribution variance.
D. variances are equal.
The variance of the sampling distribution of means, on the other hand, is equal to the variance of all possible sample means of the same size taken from the population.
Since a sample size is always less than the population size, the variance of the population distribution is greater than the variance of the sampling distribution of means.
Therefore, option B is correct.
The probability of selecting one data value less than 190 IS (C)31%
When the variances of the population distribution and the sampling distribution of means are compared, the (B) population variance is larger than the sampling distribution variance.
The probability of selecting one data value less than 190 given the mean and standard deviation of a population of 200 and 20 respectively is 31% (option C).
Solution: Given,
mean (μ) = 200,
standard deviation (σ) = 20
We need to find the probability of selecting one data value less than 190.
P(x < 190) = ?
Z = (X - μ)/σ
Taking X = 190,
Z = (190 - 200)/20
= -0.5
From the standard normal table, the probability of
Z = -0.5 is 0.3085
Therefore,
P(x < 190) = P(Z < -0.5)
= 0.3085
= 31%
Hence, option C is correct.
When the variances of the population distribution and the sampling distribution of means are compared, the population variance is larger than the sampling distribution variance.
This can be explained as follows;
The population distribution is the distribution of an entire population, while the sampling distribution of the mean is the distribution of the means of all possible samples of a specific size drawn from that population.
The variance of the population distribution is equal to the variance of a single observation of the population.
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Tammy read for 1/3 hour today. She read for 1/6 hour yesterday. How many hours did Tammy read in all?
the compound inequality
Which scenario would most likely show a negative association between the variables? A. the height of a tree and the amount of time it takes to climb to the top of the tree
B. the number of people in the mall and the number of cars in the parking lot
C. miles traveled in a car and the amount of gasoline used
D. time spent reading a book and the number of pages left to read
Answer: i would say B because it makes the most sence
Step-by-step explanation:
Estimate the flow rate at t=9s.
Time (s) 0,1,5,8,11,15
Volume cm3 0,2,13.08,24.23,36.04,153.28
The estimated flow rate is approximately 3.94 cm3/s.
To estimate the flow rate at t=9s, we can use the formula:
flow rate = change in volume / change in time.
Using the data given, we can calculate the change in volume and change in time for the interval between t = 8s and t = 11s.
Change in volume = 36.04 - 24.23 = 11.81 cm³
Change in time = 11 - 8 = 3s
Now, we can plug these values into the formula to find the flow rate:
flow rate = change in volume / change in time = 11.81 cm3 / 3s ≈ 3.94 cm3/s
Therefore, the estimated flow rate at t=9s is approximately 3.94 cm3/s.
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Maxie spent 15 hours doing her homework last week this week she spent 18 hours doing her homework she says that she spent 120% more time doing homework this week is she correct
Answer: She's wrong.
Step-by-step explanation:
Numbers of hours used in solving homework last week = 15
Numbers of hours used in solving homework this week = 18
Percentage increase = (18 - 15) / 15 × 100
= 3/15 × 100
= 1/5 × 100
= 20%
Since Maxie said that she spent 120% more time doing homework this week, she's wrong. She only spent 20% more.
On a blueprint lets say that every 1/4 inch is equal to 1 foot in real life.
What is the actual length of the room if it measures 3 3/4 inches on the blue print?
Write the fractions as decimals 1/4 = 0.25 and 3 3/4 = 3.75
15 ft
O 0.9375 ft
4 ft
7 ft
Answer:
15 ft
Step-by-step explanation:
If every 1/4 of an inch is a foot, than every inch is 4 feet.
1 inch = 4ft
3 inches = 12ft
1/4 + 1/4 + 1/4 = 3/4
3/4=3 ft
12+3=15ft
Bill needs to read 3 novels each month.
Let N be the number of novels Bill needs to read in M months.
Write an equation relating N to M. Then use this equation to find the number of novels Bill needs to read in 19 months.
Write the equation?
Number of the novels in 19 months: _ novels
Answer:
Each month Bill reads 3 novels so you get
N = 3m
If you plug in 6 for m we get
N = 3(6) = 18
Bill needs to read 18 novels in 19 months
Step-by-step explanation:
Fill in the blanks below in order to justify whether or not the mapping shown
represents a function.
Set A
Set B
4.
5
9
→ 2
-1
-3
Answer:
Step-by-step explanation:
How to write numbers in standard form:
Write the first number 8.
Add a decimal point after it: 8.
Now count the number of digits after 8. There are 13 digits.
So, in standard form: 81 900 000 000 000 is 8.19 × 10¹³
Divide and answer in simplest form: 5 ÷35
Step-by-step explanation:
Reduce 5/35 to lowest terms
The simplest form of 535 is 17.
Answer:
1/7
Step-by-step explanation:
divide both sides by 5
Two spheres A and B of mass 7.5 kg and 6.3 kg respectively are separated by a distance of 0.59 m. Calculate the magnitude of the gravitational force A exerts on B and B exerts on A. force A exerts on B force B exerts on A If the force between the spheres is now 3.50 times 10-9 N, how far apart are their centers?
To calculate the magnitude of the gravitational force A exerts on B and B exerts on A, we can use Newton's law of universal gravitation:
[tex]F = (G * m1 * m2) / r^2[/tex]
where F is the gravitational force, G is the gravitational constant (approximately [tex]6.67430 *10^-11 N m^2 / kg^2)[/tex], m1 and m2 are the masses of the two spheres, and r is the distance between their centers.
For the force A exerts on B:
[tex]F_AB = (G * m_A * m_B) / r^2[/tex]
Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and r = 0.59 m:
F_AB = (6.67430 × 10^-11 N m^2 / kg^2) * (7.5 kg) * (6.3 kg) / (0.59 m)^2
Calculating the above expression gives the magnitude of the gravitational force A exerts on B.
For the force B exerts on A, we use the same formula:
[tex]F_BA = (G * m_A * m_B) / r^2[/tex]
Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and r = 0.59 m:
[tex]F_BA = (6.67430 * 10^-11 N m^2 / kg^2) * (6.3 kg) * (7.5 kg) / (0.59 m)^2[/tex]
Calculating the above expression gives the magnitude of the gravitational force B exerts on A.
To find the distance between the centers of the spheres when the force between them is 3.50 times 10^-9 N, we rearrange the formula to solve for r:
r = √((G * m_A * m_B) / F)
Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and F = 3.50 × 10^-9 N:
r = √[tex]((6.67430 * 10^-11 N m^2 / kg^2) * (7.5 kg) * (6.3 kg) / (3.50 *10^-9 N))[/tex]
Calculating the above expression gives the distance between the centers of the spheres.
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Find the center and radius of the circle: x^2 + y^2 + 4x + 14y +52 = 0
The center of the circle is point: C=(−2,−7).
if you use a level of significance in a two-tail hypothesis test, what decision will you make if zstat -1.58?
In a two-tail hypothesis test, if the calculated test statistic (z-statistic) is -1.58 and the level of significance is used, the decision will depend on comparing the z-statistic to the critical values of the standard normal distribution corresponding to the desired level of significance.
Explanation: In a two-tail hypothesis test, the null hypothesis assumes that there is no significant difference between the sample and population parameters. The alternative hypothesis, on the other hand, suggests a significant difference. The level of significance, denoted as α, determines the critical values that divide the rejection and non-rejection regions.
If the calculated test statistic, in this case -1.58, falls within the rejection region, which is determined by the critical values, we reject the null hypothesis. If the test statistic falls outside the rejection region, we fail to reject the null hypothesis.
To make a decision, we compare the z-statistic to the critical values corresponding to the level of significance. If the z-statistic of -1.58 falls outside the critical values, it means it is not extreme enough to reject the null hypothesis, and we fail to reject it. However, if the z-statistic falls within the critical values, we reject the null hypothesis in favor of the alternative hypothesis.
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I need help with this 2 questions can someone help me pls I need it !!!!!
Answer:
8. center: (-7,5)
radius: 9
Step-by-step explanation:
8. to find the center, you need to get the equation in the form of (x-h)^2+(y-k)^2=r^2
you can do this by completing the square:
x^2+y^2+14x-10y-7=0
x^2+14x+49+y^2-10y+25=7+49+25
(x+7)^2+(y-5)^2=81
so, the center is (-7,5) and the radius is 9