In a lab, Andrew is studying the growth of a particular species of bacteria. The bacteria in the petri dish started at 300. After 2 days he realizes that the number of bacteria is about 480. After another 2 days he realizes that the number of bacteria in the dish is 288 more than what it was two days ago. a.) Give an equation to estimate the amount of bacteria in the dish after every day. b.) At what rate would the bacteria be growing c.) How many days would it take for the bacteria to reach almost 1229. d.) Find the average rate of change between 6 days and the first day

Answer:

Step-by-step explanation:

Sum of given angles:

Sum of given angles:

Answer: The zeros of the  quadratic function  are: 5/2+(1/2)*sqrt(31), 5/2-(1/2)*sqrt(31)

Step-by-step explanation:

The statement "Some unsound arguments are valid" is false.

The statement "Some unsound arguments are valid" is false.

A valid argument is a statement that follows the rules of logic.

An argument is known to be sound when it is valid and has true premises. When the premises of an argument are correct, the argument is considered sound. When an argument is valid, it follows logically from its premises, which are the statements that provide evidence or support for the argument's conclusion.

The unsound argument is the one that contains at least one false premise.

The sound argument is the one that contains only true premises and is valid (that is, follows logically from the premises).

If an argument is unsound, it can never be valid because it contains at least one false premise.

Therefore, the statement "Some unsound arguments are valid" is false.

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Answer:

Step-by-step explanation:

Given:Standard deviation, s = $2000Confidence level = 96%Margin of error, E = $500We have to find the sample size, n.

Sample size formula is given as:\[n={\left(\frac{z\text{/}2\times s}  {E}\right)}^{2}\]Where, z/2 is the z-score at a 96% confidence level. Using the standard normal table, we can get the value of z/2 as follows:z/2 = 1.750Incorporating all the values in the formula, we get:\[n={\left(\frac{1.750\times 2000}{500}\right)}^{2}\] Simplifying,\[n=21\]Therefore, a sample size of 21 is required if we wish to be 96% confident that our mean will be within $500 of the true mean salary of college instructors.

To determine the sample size needed to be 96% confident that the mean salary will be within $500 of the true mean salary, we can use the formula for sample size in a confidence interval.

The formula is:

n = (Z * σ / E)^2

Where:

n is the required sample size

Z is the z-score corresponding to the desired confidence level (in this case, 96% confidence level)

σ is the standard deviation of the population (given as $2000)

E is the maximum error tolerance (given as $500)

First, we need to find the z-score corresponding to a 96% confidence level. The remaining 4% is split evenly between the two tails of the distribution, so we look up the z-score that corresponds to the upper tail of 2% (100% - 96% = 4% divided by 2).

Using a standard normal distribution table or a calculator, the z-score for a 2% upper tail is approximately 2.05.

Now we can substitute the values into the formula:

n = (Z * σ / E)^2

n = (2.05 * 2000 / 500)^2

Calculating this expression:

n = (4100 / 500)^2

n = 8.2^2

n = 67.24

Rounding up to the next whole number, the required sample size is approximately 68.

Therefore, a sample size of 68 is needed to be 96% confident that the mean salary will be within $500 of the true mean salary of college instructors.

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Given information: The starting salaries of college instructors have a standard deviation (SD) of $2000. The sample size that is needed if we want to be 96% confident that our mean will be within $500 of the true mean salary of college instructors is to be calculated.

Hence, 49 is the sample size that is needed if we want to be 96% confident that our mean will be within $500 of the true mean salary of college instructors.

The formula for the sample size required is as follows:

[tex]n = [(Z \times \sigma) / E]^{2}[/tex]

Here, Z is the value from the normal distribution for a given confidence level, σ is population standard deviation, E is the maximum error or the margin of error, which is [tex]\$500n = [(Z \times \sigma) / E]^2[/tex]

On substituting the given values, we get:

[tex]n = [(Z \times \sigma) / E]^2[/tex]

[tex]n= [(Z \times \$2000) / \$500]^2[/tex]

[tex]n = [(1.7507 \times \$2000) / \$500]^2[/tex]

[tex]n = (7.003 \times 7.003)[/tex]

n = 49 (rounded off to the next whole number)

Hence, 49 is the sample size that is needed if we want to be 96% confident that our mean will be within $500 of the true mean salary of college instructors.

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The quantity f divided by g of 8 is 5, which is answer choice D.

To find f divided by g of 8, we need to plug in x = 8 into both f(x) and g(x), then divide f(8) by g(8).

f(x) = 3x + 1

f(8) = 3(8) + 1

f(8) = 25

g(x) = x - 3

g(8) = 8 - 3

g(8) = 5

Now, we can divide f(8) by g(8) to get:

f(8) / g(8) = 25 / 5

f(8) / g(8) = 5

Alternatively, we can find f divided by g of x generally by first applying the functions to x:

f(x) / g(x) = (3x + 1) / (x - 3)

We can then plug in x = 8 and simplify:

f(8)  g(8) = (3(8) + 1) / (8 - 3)

f(8) / g(8) = 25 / 5

f(8) / g(8) = 5

Regardless of the method we use, we find that f divided by g of 8 is 5.(option-d)

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Answer:

about 10 hershy kisses

Step-by-step explanation:

Sorry If wrong :(

The value of the expression 6x(y^2 - z) when x = 0, y = -1, and z = 2 is 0.

To find the value of the algebraic expression 6x(y^2 - z) when x = 0, y = -1, and z = 2, we substitute the given values into the expression.

First, let's evaluate the inner expression (y^2 - z):

Substituting y = -1 and z = 2, we have (-1)^2 - 2 = 1 - 2 = -1.

Now, we substitute x = 0 and the result of the inner expression (-1) into the outer expression:

6x(y^2 - z) = 6(0)(-1) = 0.

Therefore, when x = 0, y = -1, and z = 2, the value of the expression 6x(y^2 - z) is 0.

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Answer:

x ≈ 36.09

Step-by-step explanation:

Complete question

Use △DEF, shown below, to answer the question that follows: Triangle DEF where angle E is a right angle. DE measures x. DF measures 55. Angle D measures 49 degrees. What is the value of x rounded to the nearest hundredth? Type the numeric answer only in the box below.

According to the diagram

m<E = 90 degrees

m<D = 49 degrees

DF = 55 = hypotenuse

DE = x = adjacent

EF = opposite

According to SOH CAH TOA identity;

Cos theta = adj/hyp

Cos m<D = DE/DF

Cos 49 = x/55

x = 55cos49

x = 55(0.6561)

x = 36.0855

x ≈ 36.09 (to the nearest hundredth)

Answer:

x ≈ 36.09

correct on khan

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

took the test good luck

Answer:

Explained below

Step-by-step explanation:

I shall explain this

Add all the numbers together and divide by the number of numbers

[tex]78 + 81 + 89 + 75 + 76 + 91 + 10963 + 80 + 87 + 91 + 95 = answer \div 11 [/tex]

Answer:

x = 5

x = 2

Step-by-step explanation:

2(2x + 4) = 8x - 12

2x + 4 = 4x - 6

x + 2 = 2x - 3

x = 5

Question 17

8/4 = (x + 2)/(2x - 2)

2(2x - 2) = x + 2

4x - 4 = x + 2

3x = 6

x = 2

If Bryan receives a 15% tip, then he will receive an amount of approximately $16.55 as a tip.

In order to calculate the tip-amount, we need to multiply the total-bill by the tip percentage. In this case, the "bill-amount" is $110.31, and the tip percentage is 15%.

To find the tip amount, we can use the formula:

Tip amount = (Total bill) × (Tip percentage),

Simplifying further,

We get,

Tip amount = $110.31 × 0.15,

= $16.5465 (rounded to the nearest cent)

Therefore, Bryan will receive approximately $16.55 as a tip.

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Answer:

x=6

Step-by-step explanation:

[tex]\frac{9}{3} =\frac{6}{2}[/tex]      

To build a binary search tree using alphabetical order for the given words, we start with an empty tree and insert each word in the appropriate position based on its alphabetical order.

Here's the step-by-step process:

Start with an empty tree.

Insert the first word, "banana," as the root of the tree.

Insert the second word, "peach," comparing it to the root. Since it comes after "banana," it becomes the right child of the root.

Insert the third word, "apple." Comparing it to the root, it comes before "banana," so we traverse to the left child of the root. Since the left child is empty, "apple" becomes the left child of "banana."

Insert the fourth word, "pear." Comparing it to the root, it comes after "banana," so we traverse to the right child. Comparing it to "peach," it comes before "peach," so we traverse to the left child of "peach." Since the left child is empty, "pear" becomes the left child of "peach."

Insert the fifth word, "coconut." Comparing it to the root, it comes before "banana," so we traverse to the left child. Comparing it to "apple," it comes after "apple," so we traverse to the right child. Comparing it to "pear," it comes before "pear," so we traverse to the left child of "pear." Since the left child is empty, "coconut" becomes the left child of "pear."

Insert the sixth word, "mango." Comparing it to the root, it comes after "banana," so we traverse to the right child. Comparing it to "peach," it comes before "peach," so we traverse to the left child. Comparing it to "pear," it comes after "pear," so we traverse to the right child. Comparing it to "coconut," it comes after "coconut," so we traverse to the right child. Since the right child is empty, "mango" becomes the right child of "coconut."

Insert the seventh word, "papaya." Comparing it to the root, it comes after "banana," so we traverse to the right child. Comparing it to "peach," it comes after "peach," so we traverse to the right child. Comparing it to "pear," it comes after "pear," so we traverse to the right child. Comparing it to "coconut," it comes after "coconut," so we traverse to the right child. Comparing it to "mango," it comes after "mango," so we traverse to the right child. Since the right child is empty, "papaya" becomes the right child of "mango."

The resulting binary search tree will look like this:

        banana

       /      \

   apple    peach

       \        \

      pear  papaya

      /

 coconut

      \

      mango

Note: The tree might have different structures depending on the order of insertion, as long as it maintains the binary search tree property.

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Answer:

[tex] {x}^{3} {y}^{3} [/tex]

Step-by-step explanation:

Given,

Width of the rectangular prism

= x

Length of the rectangular prism

[tex] = {x}^{2} y[/tex]

Height of the rectangular prism

[tex] = {y}^{2} [/tex]

Therefore,

Volume of the rectangular prism

= Width × Length × Height

[tex] = x \times {x}^{2} y \times {y}^{2} [/tex]

[tex] = {x}^{3} {y}^{3} [/tex]

Hence,

The required volume of the rectangular prism is

Option J:

[tex] {x}^{3} {y}^{3} [/tex]

Answer:

pt B: (-1, -8)

Step-by-step explanation:

(x - 7)/2 = -4

x - 7 = -8

x = -1

(y-6)/2 = -7

y - 6 = -14

y = -8

Answer:

" Pythagoras established the first Pythagorean community in Crotone, Italy. Early Pythagorean communities spread throughout Magna Graecia. "

"was an ancient Ionian Greek philosopher and the eponymous founder of Pythagoreanism . " <---------- Credits to: Yahoo

He was born in about 570 BC on the Greek island of Samos

He died in 495 BC

Answer:

I don't understand the language

Step-by-step explanation:

am not form Paris

Nike reported total revenues of $44.5 billion for the year ending in May 31, 2021. Footwear accounted for 66% of Nike's total revenues in 2021, the percentage of Nike's total revenues that relates to sales of footwear is 66%.

The balance sheet shows that accounts receivable increased by $1,714 during the year, but some of that amount relates to mergers and acquisitions rather than additional credit sales. You will get the right amount of increased receivables from additional credit sales during the year by looking at the operating section of the statement of cash flows.

The operating section of the statement of cash flows shows that Nike collected $42.8 billion from customers in the year ending May 31, 2021. This is the amount of cash that Nike received from customers for the sales of its products and services.

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Answer:

is there an equation to find y? Because all you gave was x=-1

To solve the initial value problems using the Laplace transform, we can apply the Laplace transform to the given differential equations and initial conditions.

For the first problem, the Laplace transform of the differential equation is s^2Y(s) + 5sY(s) + 2Y(s) = 0. Solving for Y(s), we find Y(s) = -3/(s+1).

Taking the inverse Laplace transform, we obtain the solution y(t) = -3e^(-t). For the second problem, the Laplace transform of the differential equation is sY(s) + 4Y(s) + 3/(s+1) = -2. Solving for Y(s), we find Y(s) = (-2s - 1)/(s^2 + 4s + 3). Taking the inverse Laplace transform, we obtain the solution y(t) = (-2t - 1)e^(-t).

a) The Laplace transform of the given differential equation is:

s^2Y(s) + 5sY(s) + 2Y(s) = 0

Using the initial condition Y(0) = -1 and Y'(0) = 3, we can apply the initial value theorem to obtain:

Y(s) = -1/s + 3

Taking the inverse Laplace transform of Y(s), we find:

y(t) = -3e^(-t)

b) The Laplace transform of the given differential equation is:

sY(s) + 4Y(s) + 3/(s+1) = -2

Using the initial condition Y(0) = -1, we can apply the initial value theorem to obtain:

Y(s) = (-2s - 1)/(s^2 + 4s + 3)

Taking the inverse Laplace transform of Y(s), we find:

y(t) = (-2t - 1)e^(-t)

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If a student obtained the standard value z= 1.8, then the exam grade is 680.

Given, a placement exam has a measure of x = 500 and a standard deviation of s = 100, and a student obtained the standard value z = 1.8, and we are to find the exam grade.

In order to find the exam grade, we can use the formula, z = (x - μ) / σ where x is the score, μ is the mean, and σ is the standard deviation.

Substituting the given values, we get1.8 = (x - 500) / 100

Multiplying both sides by 100, we get180 = x - 500

Adding 500 to both sides, we get680 = x

Therefore, the exam grade is 680.So, the correct option is d. 680.

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Answer:

the answer is I think 2/3

Fraction of boys brought lunch today is 16/25.

Here,

Given that:

The ratio of boys at certain school = 8/9

And 2/5 of boys brought lunch today

We have to find fraction of boys brought lunch today.

What is fraction?

Fractions denote the parts of a whole or collection of objects.

Now,

The ratio of boys at certain school = 8/9

And 2/5 of boys brought lunch today

Since, the ratio of boys 8/9 denotes 8 boys out of 9 students

Therefore, number of boys = 8

Thus, Fraction of boys brought lunch today = 8 x 2/5

                              = 16/25

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The total cost of seeded avocadoes is $1.52 (approx).

Given data:

As-purchased unit cost of avocado = $1.21 per pound

Yield percentage = 72%

Convert the given quantity of avocadoes into pounds.

1 ounce = 1/16 pounds28 ounces = (28/16) pounds= 1.75 pounds

Find out the cost of 1 pound of avocado

As per the given data, the as-purchased unit cost of Avocado's is $1.21 per pound.

Find out the cost of 1.75 pounds of avocado= (1.75 x 1.21) dollars= $2.1175.

Calculate the yield amount.

After calculating the yield percentage, we can find the amount of avocado we can use after we remove the peel and seed.

Yield amount = (yield percentage × amount as purchased)/100Yield amount

= (72 × 1.75) / 100= 1.26 pounds.

Find out the cost of yield amount

Cost of yield amount = (cost of 1.75 pounds of avocado × yield amount)/1.75

Cost of yield amount = ($2.1175 × 1.26) / 1.75

Cost of yield amount = $1.5246

Hence, the total cost of 28 ounces of peeled and seeded avocadoes is $1.52 (approx).

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Answer:

1196 cm3

Step-by-step explanation:

Answer:

1196

Step-by-step explanation:

Answer:

I am not able to answer your question because I am unsure of what to solve for. :/

Step-by-step explanation:

Answer:

30%

Step-by-step explanation:

Answer:

y=3x+2

Step-by-step explanation:

y=mx+b

b=2

m=3

plug in

y=3x+2