In a hydraulic press a force of 200N is applied to a master piston of area 25Cm2.if the press produces 500N determine the area of the piston.​

Answers

Answer 1

Answer:

625                                      GIVE ME BRAINLIEST ANSWER PLEASE

Explanation:

This question is based on pascal's Law.

So By Pascal's Law

=

therefore  =force on input piston =200N

                 = Force on output piston = 5000N

therefore after putting the values we get,

a)  = (25x 5000)/200

    = 625

b) area of the salve piston =  = 625

so  = 625/3.14 = 199

so     r =    = 14.10 cm


Related Questions

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Medicine in Western cultures has not focused on the energy in the body as much as cultures in Asia have.
A.
True

B.
False

PLEASE NO LINKS

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Answer:

A

Explanation:

This is true because culture in Asia focus more on energy that is why we see kung fu and taekwondo etc.

Answer:

A

Explanation:

Got it right.

What is gibbs free energy.

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Answer:

It’s a

Explanation:

Which of the following processes generated heat during earths formation that is still a source of heat in earths interior

Answers

Answer:

There are three main sources of heat in the deep earth: (1) heat from when the planet formed and accreted, which has not yet been lost; (2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elements

This should be pretty easy i think.

Describe the components within the system involved in the collision between pilot and landing zone.

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Answer:

its a sure for not but i think its a 192583

Why are people so rude???

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Answer:

It could be low self-esteem

Explanation:

There probably insecure have problems and issues of their own could be that were abused growing up and weren’t treated right who knows.

Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2

Answers

The magnitude of the acceleration of the box is 2 m/s².

The given parameters;

mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 east

The resultant of the two given forces is calculated as follows;

[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]

The magnitude of the acceleration of the box is calculated as follows;

[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]

Thus, the magnitude of the acceleration of the box is 2 m/s².

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Find the displacement in the time interval 3 seconds to 4 seconds
A. 1m
B.3m
C.7m
D.9m

Answers

Answer:

B. 3m

Explanation:

Took the quiz.

Hope this helps!!

Football players boots have spikes at their sole

Give reason​

Answers

Answer:

it prevents slipping on the grass while playing

Answer:

to keep their grip on the ground so they won't fall

A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to determine the amount of power used?

Answers

Answer:

time

Explanation:

power = work done ÷ time

People who drink coffee are more likely to develop cancer

Answers

Answer:

The answer is False

False

Hope this helps

A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?

Answers

The speed of the man and the chair after the book is thrown is 0.2 m/s.

The given parameters:

mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kg

The total mass of the man and the book is calculated as follows;

m₂ = 70 kg + 9.2 kg

m₂ = 79.2 kg

The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;

[tex]m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s[/tex]

Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.

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someone throws a rubber ball vertically upward from the roof of a building 8.2m in height. the ball rises, then falls.it just misses the edge of the roof, and strikes the ground.if the ball is in the air for 6.2s, what was its initial velocity?(disregard air resistance. a=-g=-10m/s²

Answers

Answer:

H = V t - 1/2 g t^2         V and g are in different directions

-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2

V = 184 / 6.2 = 29.7 m/s

Check: find time for ball to return to zero height

0 = 29.7 T - 5 T^2

T = 29.7 / 5 = 5.94 sec

The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec

S = 29.7 * .26 + 5 * .26^2 = 8.1

When did the objects that we now see as asteroids and comets form in the solar system?.

Answers

Answer:

After solid particles condensed from the gas but before the planets finished forming

How do atoms join together?

Answers

Answer:

Atoms can be joined together by chemical bonds.

Explanation:

When atoms form bonds, they can achieve a stable electron arrangement. To achieve a stable electron arrangement atoms can lose, gain or share electrons. There are many different types of bonds that hold atoms together.

Answer:

Atoms come together to form molecules because of their electrons. Electrons can join (or bond) atoms together in two main ways. When two atoms share electrons between them, they are locked together (bonded) by that sharing. These are called covalent bonds.

Explanation:

A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.

Answers

The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

The given parameters;

initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃Pi

The initial and final momentum of the ball is calculated as;

[tex]P_i = m_ivi[/tex]

[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]

The initial and final kinetic energy of the ball is calculated as;

[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]

The change in the kinetic energy is calculated as;

[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]

Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

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Interpreting Graphics
11. Look at the model of an atom below. Does the
model represent a metal atom or a nonmetal
atom? Explain your answer.
ng

Answers

answer:
This is a metal atom

explanation:
metal atoms have fewer electrons in their outer shells than non-metal atoms do.

By looking at the model shown in the problem one can clearly say that this model represents the metal because there are a total of 12 electrons revolving around the nucleus which clearly represents the Magnesium metal.

What are metalloids?

The elements of the periodic tables that behave as metals, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.

As given in the problem, there is a graphical representation of the model of an atom,

One can see that the model in the problem accurately depicts the metal by looking at the total of 12 electrons circulating around the nucleus, which is a clear representation of the magnesium metal.

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#SPJ5

Help me quick!!! please!!

Calculate the power of an engine which raises a mass of 1000 kg to a height of 40 m in 10 s.

Answers

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]

At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]

Answer:

P=39200W

Explanation:

P=(mgh)/t

P=(40×9.8×1000)/10

P=39200W

A bus slams on its breaks and goes from 30km/hr to 15km/hr in 4 seconds. What is its acceleration?

Answers

Answer:

− 2.08

Explanation:

Note the equation v = v0 + at, where v is the final velocity in meters per second, v0 is the initial velocity in meters per second, a is the acceleration, and t is the time in seconds.

Fist convert the velocities so 30km/hr=8.333m/s and 15km/hr=4.167m/s

Plugging this into the equation, we get
4.167 = 8.333 + a(4)
=> -4.167 = a(4)
=> a = -1.042 m/s^2

what kind of frog species is this

Answers

Answer: i think its a bullfrog forgive me if im wrong i dont exactly know

Explanation:

Answer:

that is an African bullfrog

See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in motion. They are:
**a person standing on the ground **the car **the seat
**another person on the ride **the track **the sun

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

1. According to person standing on ground ~

The person is in motion

2. According to The car ~

The person is not in motion

3. According to the Seat ~

The person is not in motion

4. According to another person on ride ~

The person is not in motion

5. According to the track ~

The person is in motion

6. According to the Sun ~

The person is in motion

I hope that's what you were looking for, goodluck for your assignment ~

A 34. 8 n object is in free fall. What is the magnitude of the net force which acts on the object? answer in units of n.

Answers

Answer:

-34.8n

Explanation:

when object in free fall, only force is the Force by weight,

which is 34.8 and direction is down.

an astronomer looking out into space will observe that

Answers

Answer:

The farther out a galaxy is from Earth, the faster it is moving away.

Explanation:

What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a pressure of 35 lb/in2 Assume that the distance between each floors is 10ft.

Answers

The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

The given parameters;

Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ft

The vertical pressure of the water is calculated as follows;

[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]

The vertical height of the first floor from the 13th floor = 130 ft

The vertical height of the 13 ft floor = 10  ft

[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]

Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

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What is occurring in the umbra?

A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse

Answers

Answer:

A. a total solar eclipse

Explanation:

During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth

Déterminer la charge de noyau d’atome d’oxygène en coulomb C

Answers

Answer:

determine a large mam I have no idea

a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?

Answers

The work done on the given gas in one cycle is -405.3 kJ.

The given parameters;

initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³

Convert the pressure to Pascal (N/m²);

1 atm = 101325

The work done in one cycle is the area of the triangle and it is calculated as follows

[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]

the net work done on the gas = - 405.3 kJ

Thus, the work done on the given gas in one cycle is -405.3 kJ.

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Which of the following is NOT a part of Earth’s atmosphere?

1. mesosphere
2. troposphere
3. asthenosphere
4. stratosphere

Answers

Answer:

3

Explanation:

It is part of the Earth's mantle

Answer:

it is the astenospere number 3

what metaphor most closely describes the nature of space-time?
a. chemistry formula
b.fabric
c. sine wave
d. moebius strip

Answers

Answer:

b.fabric

Explanation:

Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.

Answer:

B. fabric

Explanation:

what is the formula for calculating potentiometer​

Answers

This is the answer, (Vout )=V / (R1 + R2) x R2

1. Look at this data table


What data seems to be inconsistent with the rest? What are 2 different explanations for this data?

Answers

Using visual inspection and knowledge of linear regression , the inconsistent input is the last data point (30, 12.0).

Looking at the data, there is a negative relationship between the depth of water sample and the amount of dissolved oxygen.

As the depth increases, the amount of dissolved oxygen decreases. However, the last data point does not concur with this trend.

This might have been caused by imputation error or error in the measuring device used.

Therefore, the inconsistent data point is (30, 12.0)

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