A dependent means t-test determines if the differences between scores on the pretest and posttest measures differ significantly from:
A dependent means t-test determines if the differences between scores on the pretest and post-test measures differ significantly from Zero(0).
Benefits of pre-test measurements
This design is superior to the post-test-only control design because it adds pre-tests. Addition of pre-test: Improve your design ability to detect effects. You can investigate the impact of interventions on various sublevels of pretesting.
The design of the pre-test and post-test is similar to the in-subject experiment. In this experiment, each participant is first tested in control conditions and then in therapeutic conditions.
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HELP HELP HELP
HELP HELP HELP
Answer:
Step-by-step explanation:
HELP PLS I NEED 28 and 29 I DONT NEED THE WORK JUST THE ANSWERS FAST ILL MARK BRAINLIEST
Answer:
28) Y=1x+c
29)-2/3x+c
Step-by-step explanation:
Drag each expression to show whether the expression is equivalent to 12x - 6,
24x+12, or neither.
Answer:
Drag and drop 6(2x-1) to 12x-6.
Drag and drop 6(4x-2) to Neither.
Drag and drop 3(8x+4) to 24x+12.
Drag and drop 6(4x+2) to 24x+12.
Drag and drop 2(6x-3) to 12x-6.
Step-by-step explanation:
To check these, use distributive property to solve each one.
6(2x-1) = 12x-6
6(4x-2) = 24x-12
3(8x+4) = 24x+12
6(4x+2) = 24x+12
2(6x-3) = 12x-6
Hope this helps!
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Angle B is a complement of angle A and the measurement of angle A = 65.2°. Find the measurement of angle B
Answer:
24.8°
Step-by-step explanation:
Complementary angles sum 90°
65.2° + B° = 90°
B° = 90° - 65.2°
B° = 24.8
Angle B from the information given is 24. 8°
How to determine the angleNote that complementary angles sum up to 90°
From the information given, we have that
Angle A + Angle B = 90°
If angle A = 65. 2°
Angle B = 90 - 65. 2
Angle B = 24.8°
Thus, angle B from the information given is 24. 8°
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Ellen is currently twice as old as Maria, but in 6 years, Maria will be 2/3 as old as Ellen. How old is Ellen now?
Identify the range of the function shown in the graph.
The range of a function is all possible y values that a function can take on.
In the case of the given function, the y values fluctuate between -1 and 1. Therefore, the range of the function is -1 <= y <= 1 (Option A).
Hope this helps!
Find the area and the perimeter of the shaded regions below. Give
your answer as a completely simplified exact value in terms of T (no
approximations). The figures below are based on semicircles or
quarter circles and problems b), c), and d) are involving portions of
a square.
Pls explain as best as you can i cant understand this stuff
Based on the definition of composite figure, the area of the composite figure ABC formed by a semicircle and right triangle is approximately 32.137 square centimeters.
How to find the area of the composite figure
The area of the composite figure is the sum of two areas, the area of a semicircle and the area of a right triangle. The formula for the area of the composite figure is described below:
A = (1/2) · AB · BC + (π/8) · BC² (1)
If we know that AB = 6 cm and BC = 6 cm, then the area of the composite figure is:
A = (1/2) · (6 cm)² + (π/8) · (6 cm)²
A ≈ 32.137 cm²
Based on the definition of composite figure, the area of the composite figure ABC formed by a semicircle and right triangle is approximately 32.137 square centimeters.
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i need help with this page
Michelangelo was starving for a slice of pizza. he started at -50 feet in the sewers, climbed the ladder to the street, and ran 20 feet to the pizza restaurant. how many feet did michelangelo go for pizza?
Michelangelo went 30 feet for a pizza to a pizza restaurant.
How to calculate the distance traveled for pizza?It is given that,
Michelangelo was starving for a slice of pizza. He started -50 feet in the sewer, climbed the ladder to the street, and ran 20 feet to the pizza restaurant.
So, the total feet he traveled is,
= -50 feet + 20 feet = 30 feet.
Therefore, Michelangelo went 30 feet for pizza.
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If the center of the circle were moved from the origin to the point (h, k) and point p at (x, y) remains on the edge of the circle, which could represent the equation of the new circle? (h x)2 (k y)2 = r2 (x – h)2 (y – k)2 = r2 (k x)2 (h y)2 = r2 (x – k)2 (y – h)2 = r2
[tex]{(x-h)}^2 + {(y-k)}^2 = {r}^2[/tex] represent the equation of the new circle.
Given: (h,k) is center of circle
and (x,y) remains on edge of circle.
The distance formula is used to determine the distance, d, between two points. If the coordinates of the two points are (x1, y1) and (x2, y2), the distance equals the square root of x2 − x1 squared + y2 − y1 squared.
The distance formula is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points.
In a Cartesian grid, to measure a line segment that is either vertical or horizontal is simple enough. You can count the distance either up and down the y-axis or across the x-axis
Using Distance formula which says,
[tex]\sqrt{{({x}_2 - {x_1})}^2 + {({y}_2 - {y}_1)}^2} = r\\\sqrt{{(x - h)}^2 + {(y - k)}^2} = r\\\\{(x - h)}^2 + {(y - k)}^2 = r^2[/tex]
Hence, the equation of the new circle will be [tex]\\{(x - h)}^2 + {(y - k)}^2 = r^2[/tex]
Formula used:[tex]\sqrt{{({x}_2 - {x_1})}^2 + {({y}_2 - {y}_1)}^2} = r[/tex]
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Answer: B
Step-by-step explanation:
TG and TH are tangent to circle Z. If TG measures 4.2 cm, what is the measure of TH?
Based on the two-tangent theorem, the measure of TH is also: 4.2 cm.
What is the Two-Tangent Theorem?According to the two-tangent theorem, the length of two tangents (TG and TH) that are drawn from a circle to intersect at an external point are equal. That is, they are congruent to each other.
Thus, we are given that, TG = 4.2 cm. Therefore, based on the two-tangent theorem, the measure of TH is also: 4.2 cm.
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The figure below is not drawn to scale. ABCD is a parallelogram, Find
LAEB and L CDE.
A
B
[tex]\angle BAD=100^{\circ}[/tex] (opposite angles in a parallelogram)
[tex]\angle EAD=80^{\circ}[/tex] (subtraction)
[tex]\angle ADE=65^{\circ}[/tex] (angles in a triangle add to 180 degrees)
[tex]\angle CDA=80^{\circ}[/tex] (adjacent angles in a parallelogram are supplementary)
[tex]\boxed{\angle CDE=15^{\circ}}[/tex] (subtraction)
[tex]\angle CED=65^{\circ}[/tex] (angles in a triangle add to 180 degrees)
[tex]\boxed{\angle AEB=80^{\circ}}[/tex] (angles on a straight line add to 180 degrees)
The graph shows the depth, y, in meters, of a shark from the surface of an ocean for a certain amount of time, x, in minutes:
Part A: Describe how you can use similar triangles to explain why the slope of the graph between points A and B is the same as the slope of the graph between points A and C.
Part B: What are the initial value and slope of the graph, and what do they represent? (6 points) Please try to explain it as simply as possible
The answers are:
Part A: The slope of AB and BC are the same.Part B :The initial value is 60 m and the slope is 40 m/min.What is the triangles about?Note that the graph depict the depth, y, in meters, of a shark that moves from the surface of an ocean for a given amount of time, x, in minutes.
So:
Part A :
We look at the two right triangles: Δ ABD and Δ BCE, and where D(2,100) and E(1,60) points.
Since the triangle are the same and thus, the slope of line segment AB: tan θ = AD/BD
= 140 - 100 / 2 - 1
= 40
Since the the slopes of line segment BC will be:
tan a = BE/CE
= 100 - 6 / 1 - 0
= 40
So, θ = α and the slope of AB and BC are similar.
Part B :
Using the graph, one can see that the initial value of the graph is 60 m and it stands for the initial position of the shark
e.g. at point t = 0 min, the shark was seen at a depth of 60 m from the water surface.
So therefore, since the slope of the graph is 40 it implies that the rate of change of distance from the Ocean surface of the shark in regards to the time in minutes have to be 40 m per min.
Therefore, The answers are:
Part A: The slope of AB and BC are the same.
Part B :The initial value is 60 m and the slope is 40 m/min.
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HELPPPPPP please !!!!!!!!!!!!!
Answer:
B
Step-by-step explanation:
On a coordinate plane, a curved line with a minimum value of (negative 1.25, negative 3.25) and a maximum value of (0.25, negative 1.75), crosses the x-axis at (negative 2.25, 0), and crosses the y-axis at (0, negative 2). The line exits the plane at (negative 2.75, 6) and (1.5, 6).
Which statement is true about the end behavior of the graphed function?
As the x-values go to positive infinity, the function's values go to negative infinity.
As the x-values go to zero, the function's values go to positive infinity.
As the x-values go to negative infinity, the function's values are equal to zero.
As the x-values go to positive infinity, the function's values go to positive infinity.
The correct option is:
As the x-values go to positive infinity, the function's values go to positive infinity.
What is the end behavior of the function?
By the description, We know that the function has the points:
(-1.25, -3.25), (0.25, -1.75) (-2.25, 0), (0, -2), (-2.75, 6), (1.5, 6)
Notice that from x = 0.25 to x = 1.5 the function goes upwards, then in the right side, the function goes up, so as x goes to positive infinity, also does f(x).
On the left side, we can see that from x = -2.75 to x = -2.25 the function goes downwards.
So, as x goes to the left (negative infinity) f(x) goes upwards.
Then as x tends to negative infinity, f(x) tends to infinity.
The correct option is:
As the x-values go to positive infinity, the function's values go to positive infinity.
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Answer:
D
Step-by-step explanation:
edge 23
PLEASE HELP I HAVE 45 min to SUBMIT WILL GIVE BRAINLESSLY
Answer:
Step-by-step explanation:
Using f(x) = 2x + 7 and g(x) = x-3, find f(g(-2)).
Answer:
f(g(-2)) = -3
Step-by-step explanation:
g(-2) = -2 - 3 = -5
f(-5) = 2(-5) + 7 = -10 + 7 = -3
Q={1,3,6,9,10,15} then rewrite in set builder method
Answer:
{x:x is a multiple of 3, x ≤ 15}
In set builder notation, the set Q is written as
Q = {x | x ∈ N, 1 ≤ x ≤ 15, x ∈ {1, 3, 6, 9, 10, 15}}
How to write in set builder in notationThe set Q can be rewritten using the set-builder notation as:
Q = {x | x ∈ N, 1 ≤ x ≤ 15, x ∈ {1, 3, 6, 9, 10, 15}}
In the set-builder notation, the expression "x |" indicates that x belongs to the set being defined.
The vertical bar (|) is read as "such that." The condition "x ∈ N" specifies that x is a natural number, and the condition "1 ≤ x ≤ 15" indicates that x must be greater than or equal to 1 and less than or equal to 15.
Finally, the expression "{1, 3, 6, 9, 10, 15}" specifies the specific elements that belong to the set Q.
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A young sumo wrestler decided to go on a special diet to gain weight rapidly. He gained weight at a constant rate.
The table compares the wrestler's weight (in kilograms) and the time since he started his diet (in months).
The wrestler's weight before he went on his diet is 78 kg
How to find the y-intercept?
The formula for slope is;
m = (y2 - y1)/(x2 - x1)
Thus, using two points we have;
m = (93.6 - 85.8)/(3 - 1.5)
m = 5.2
At the start of his diet, time in months = 0 months and so x = 0. Thus;
5.2 = (85.8 - y0)/(1.5 - 0)
5.2 * 1.5 = 85.8 - y0
y0 = 85.8 - (5.2 * 1.5)
y0 = 85.8 - 7.8
y0 = 78 kg
Thus, the wrestler's weight before he went on his diet is 78 kg
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Which scatter plot represents the data in the table?
Questions in the picture
Enter the correct answer in the box.
Simplify the expression (6^2)4.
Answer:
1679616
Step-by-step explanation:
Answer:
it's 6^8 (6 to the 8th power)
Step-by-step explanation:
put 8 in the box
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Given △qrs ~ △xyz, what is the value of tan(q)? three-fifths three-fourths four-fifths four-thirds
The value of tan(Q) = 3/4, given that ΔQRS ~ ΔXYZ. Computed using properties of similar triangles. Hence, the second option is the best choice.
According to the properties of similar triangle, the corresponding sides of similar triangles are in proportion.
In the question, we are given that ΔQRS ~ ΔXYZ.
By properties of similar triangles, we know that:
QR/XY = RS/YZ = SQ/ZX.
From this, we can show that:
RS/SQ = YZ/ZX ...(i).
We are asked to find the value of tan(Q).
By trigonometric ratios, we know that:
tan(Q) = Perpendicular/Base = RS/SQ.
From (i), we know that RS/SQ = YZ/ZX.
From figure, we know that YZ = 9, and ZX = 12.
Thus, YZ/ZX = 9/12 = 3/4.
Thus, tan(Q) = RS/SQ = YZ/ZX = 3/4.
Hence, the value of tan(Q) = 3/4, given that ΔQRS ~ ΔXYZ. Computed using properties of similar triangles. Hence, the second option is the best choice.
The question is incomplete. The complete question can be seen in the figure.
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The reflexive property makes triangle XYW congruent or equal to ZWY by
a SAS
b ASA
c AAS
d SSS
Answer: D: SSS Congruency
Step-by-step explanation:
- SSS congruency stands for side-side-side congruency
- if the 3 side lengths are equal for both triangles they are equivalent
- the reflexive property states that an angle, line segment, or shape is always congruent to itself
- so the reflexive property is just saying that WY = YW, therefore creating 3 equal sides for both triangles
- so the triangles are congruent by SSS
hope this helps :)
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each graph to the inequality it represents.
The graphs and their inequalities are
Graph 1 ⇒ 3x + 4y > 6Graph 2 ⇒ 2x - 7y ≥ 14Graph 3 ⇒ 3x + 4y < 6Graph 4 ⇒ 7x + 2y ≥ 14How to match the inequalities?The inequalities are given as:
2x - 7y ≤ 14
7x + 2y ≥ 14
2x - 7y ≥ 14
3x + 4y < 6
4x - 3y > 6
3x + 4y > 6
To represent the inequalities on a graph, we use the following guides:
> uses a dotted line, and the upper parts are shaded< uses a dotted line, and the lower parts are shaded≥ uses a thick line, and the upper parts are shaded≤ uses a thick line, and the lower parts are shadedUsing the above as a guide, we have:
Graph 1 ⇒ 3x + 4y > 6
Graph 2 ⇒ 2x - 7y ≥ 14
Graph 3 ⇒ 3x + 4y < 6
Graph 4 ⇒ 7x + 2y ≥ 14
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Triangle RST is circumscribed about the circle below. What is the
perimeter of the triangle?
Answer:
I think the answer is B.36
Step-by-step explanation:
hope this helps if not let me know have a blessed day
(1/2 + 3/2)² + (2/3 x 1/2)³
The result of the mathematical expression given as follows: (1/2 + 3/2)² + (2/3 x 1/2)³ is 5.59 or 5⅔.
How to calculate mathematical expressions?According to this question, the following expression is given to solve: (1/2 + 3/2)² + (2/3 x 1/2)³
First, we solve the both parts as follows:
½ + 3/2 = 2⅔ + ½ = 1..16Next, we solve the exponential function as follows:
= (2)² + (1.16)³
= 4 + 1.59
= 5.59 or 5⅔
Therefore, the result of the mathematical expression given as follows: (1/2 + 3/2)² + (2/3 x 1/2)³ is 5.59 or 5⅔.
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Quick algebra 1 question for 50 points!
Only answer if you know the answer, Tysm!
Answer:
x=0. The explanation is below.
Step-by-step explanation:
So, it is run 2 rise 6. We can fact-check that with 1 to 3 to 5 and 1 to 7 to 13. So, the slope is 3 because of rise over run. So, we can make an equation with y = mx + b. m = 3 because that is the slope. 1=3(1) + b. b=-2. So, the equation is y=3x-2. We can find any x using y and vice versa if we find the equation.
For this part, -2=3x-2. 3x=0. x=0.
Find equation of line
(1,1)(3,7)Slope
m=7-1/3-1m=6/2m=3Equation
y-1=3(x-1)y-1=3x-3y=3x-2Now
put y=-2
3x-2=-23x=0x=044. Each child born to a particular set of parents has a probability of 0.25 of having blood type O. If these parents have 5 children.
What is the probability that
a. Exactly two of them have blood type O
b. At most 2 have blood type O
c. At least 4 have blood type O
Using the binomial distribution, the probabilities are given as follows:
a. 0.2637 = 26.37%.
b. 0.8965 = 89.65%.
c. 0.0148 = 1.48%.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.The values of the parameters for this problem are:
n = 5, p = 0.25.
Item a:
The probability is P(X = 2), hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637[/tex]
Item b:
The probability is:
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]
In which:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{5,0}.(0.25)^{0}.(0.75)^{5} = 0.2373[/tex]
[tex]P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955[/tex]
[tex]P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637[/tex]
Then:
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2373 + 0.3955 + 0.2637 = 0.8965[/tex]
Item c:
The probability is:
[tex]P(X \geq 4) = P(X = 4) + P(X = 5)[/tex]
In which:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0147[/tex]
[tex]P(X = 5) = C_{5,1}.(0.25)^{5}.(0.75)^{0} = 0.0001[/tex]
Then:
[tex]P(X \geq 4) = P(X = 4) + P(X = 5) = 0.0147 + 0.0001 = 0.0148[/tex]
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