Explanation:
Assuming that there is no air resistance, the given time means that the ball reached its maximum height 3 seconds after throwing it upwards so we can solve its
maximum height by solving for [tex]v_{0y}[/tex] first:
[tex]v_y = v_{0y} - gt \Rightarrow v_{0y} = gt[/tex]
[tex]v_{0y} = (9.8\:\text{m/s}^2)(3\:\text{s}) = 29.4\:\text{m/s}[/tex]
Now that we know [tex]v_{0y},[/tex] we can now solve for [tex]y_{max}:[/tex]
[tex]y_{max} = v_{0y}t - \frac{1}{2}gt^2[/tex]
[tex]\:\:\:\:\:\:=(29.4\:\text{m/s})(3\:\text{s}) - \frac{1}{2}(9.8\:\text{m/s}^2)(3\:\text{s})^2[/tex]
[tex]\:\:\:\:\:\:=44.1\:\text{m}[/tex]
A simple pendulum oscillates 40 times in 20 second. What is the time period of the pendulum?
If a ball is kicked horizontally off of a building at 8.0 m/s, what is the horizontal velocity (vx) after 3
seconds?
The characteristics of the projectile launch allows to find the result for the velocity on the x axis is:
In the horizontal axis there is no acceleration and therefore the speed must be kept constant. The horizontal speed is vₓ = 8.0 m / s
In projectile launching we have an application of kinematics to motion in two dimensions near the surface of the Earth.
In this case, on the vertical axis we have an acceleration directed towards the center of the planet and called the gravity acceleration.
In the horizontal axis or x axis there is not acceleration, except in special cases that we tone is how much the resistance of the air.
Consequently in the horizontal axis there is no acceleration and therefore the speed must be kept constant, the result for the horizontal speed is:
vₓ = 8.0 m / s
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Consider three properties of the net force on an object: a magnitude, direction, and angle with respect to the objects path. For the following situation select the choice that indicates wether these quantities are constant or changing during the course of the motion.
1. The magnitude and the angle of the net force with respect to path are constant, but the direction is changing
2. The direction and the angle of the net force with respect to path are constant, but the magnitude is changing.
3. The magnitude and direction of the net force are changing, but the angle of the net force with respect to path is constant.
4. The magnitude, direction, and angle with respect to path for the net force are constant.
5. The magnitude and direction of the net force are constant, but the angle of the net force with respect to path is changing.
Answer:
Explanation:
yeah i dont know i need the answer too
A 0.038-kg bullet enters a 3.2-kg watermelon and embeds itself in the melon. The melon is immediately set into motion with a speed of 3.82 m/s. The bullet remains lodged inside the melon. What was the entry speed of the bullet (m/s)?
Hi there!
This is an example of a perfectly inelastic collection, so:
mb = mass of bullet
vb = velocity of bullet
mw = mass of watermelon
v = velocity final
mbvb = (mb + mw)v
Rearrange to solve for the velocity of the bullet:
vb = (mb + mw)v/mb
Plug in values:
vb = (0.038 + 3.2)(3.82)/(0.038) = 325.504 m/s
Can air make shadows?
Answer:
Yes, air can indeed make shadows. A shadow occurs when an object in a light beam prevents some of the light from continuing on in the forward direction. When the light beam hits a wall or the ground, a darker shape is visible where less light is hitting the surface. Refraction is responsible.
Explanation:
Here is a clip of an example of air making a shadow
https://www.seeker.com/stories/air-shadows/
What is represented in this picture? (50 points and brainliest for the correct answer!!!!)
Answer:
I don't know
Explanation:
Please give me Brainliest answer
Answer:
PRESSURE ???
If a car accelerates from rest at a constant of rate of 5.5m/s^2 north, how long will it take for the car to reach a velocity of 28 m/s north?
Answer:
Explanation:
vo= 0
a=5.5m/s^2
v= 28 m/s
t=?
v=vo+at
at=v-vo
t=(v-vo)/a
t=28/5.5
t=5.09 seconds
Waves can travel but the medium does not "travel" with it, even though they may move up and down.
False
True
Answer:
TRUE
Explanation:
The statement "Waves can travel but the medium does not "travel" with it, even though they may move up and down." is a true statement
Option A is correct
What are Waves?A wave is simply defined as a disturbance in a medium that carries energy from point to point and can take the form of elastic deformation, a change in pressure, magnetic strength, electric potential, or temperature.
In conclusion, Mediums are the pathways or channel for travelling waves
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how is the ionization, E, related to a period of elements?
Answer:
2 Answers. Ionization energies increase across a Period, and decrease down a Group.
Explanation:
Answer:
The ionization energy of an element increases as one moves across a period in the periodic table.
Explanation:
The electrons are held tighter by the higher effective nuclear charge.
Several lawmakers argue that constructing coal plants is a necessity. Which statement describes scientific evidence people can use to disagree with the lawmakers’ claim?
Burning fossil fuels increases greenhouse gas emissions.
Coal mining creates many kinds of jobs.
Energy production rates are the highest with the use of coal plants.
Forests are destroyed as storage facilities for electricity are constructed.
Answer:
Burning fossil fuels increases greenhouse gas emissions.
a uniform rod 8m long weighing 5kg is supported horizontally by two vertical parallel strings at p and q and at distance 2m and 6m from one end.
Weight of 1kg, 1.5kg and 2kg are attached at distance of 1m 5m and 7m respectively from the same end.
find the tension in each vertical string
Answer:
Fp = 36 N
Fq = 58 N
Explanation:
Let the left end be the reference end with string p closest to it.
Let CCW moments be positive
Sum moments about p to zero
1(9.8)[2 - 1] + Fq[6 - 2] - 5(9.8)[8/2 - 2] - 1.5(9.8)[5 - 2] - 2(9.8)[7 - 2] = 0
Fq[4] = 23.5(9.8)
Fq = 57.575 ≈ 58 N
Sum moments about q to zero
1(9.8)[6 - 1] - Fp[6 - 2] + 5(9.8)[6 - 8/2] + 1.5(9.8)[6 - 5] - 2(9.8)[7 - 6] = 0
Fp = 35.525 N
or
Sum vertical forces to zero
Fp + 57.575 - (9.8)(1 + 1.5 + 2 + 5) = 0
Fp = 35.525 ≈ 36 N
Once you start pulling your object with less force than friction, what should you expect your object to do? What about when your object is pulled with more force than friction?
#Case -1
If Pulling force is less than frictional force the object won't move .
#Case-2
If Pulling force is greater than frictional force then object will be .
In order to calculate friction force you need Limiting friction first .
[tex]\\ \sf\longmapsto F_L=\mu sN[/tex]
u s is coefficient of static friction and N is normal reactionOr
[tex]\\ \sf\longmapsto F_L=\mu smg[/tex]
how did you get your eye color?
Answer:
Humans get their eye color from Melanin, the protective pigment that also determines skin and hair shades. ... The little that isn't absorbed by the iris is reflected back, producing what we see as eye color. Now, that color depends on the kind and density of melanin a person is born with..
Explanation:
Hope it helps you..
Your welcome in advance..
(ㆁωㆁ)
You throw a ball upward with an initial speed of 3.0 m/s from an initial height of 1.5 m. After you throw the ball, its acceleration is 9.81 m/s downward. Taking upward to be the positive direction, write the position-time equation for the ball's motion
Answer: An object undergoing a constant acceleration can have its motions be described by the kinematic equations. These equations relate the position of the particle, its velocity, acceleration, and time.
Explanation:
Answer:
vf^2=vo^2+2ay(y1-y0)
Explanation:
Weight refers to the pull of _________ on an object.
Question 2 options:
mass
gravity
volume
Answer: Weight refers to the force of gravity acting upon an object.
(Answer B)
HELP ME PLS THIS IS DUE TODAY I NEED HELP!!!!
Explanation:
i wish I could help you but its not clear...
Help ma pls !
As the sun goes down the air contains a certain amount of water vapor in the air then begins to cool and eventually the air reaches the dew point.
What is the dew point and what form at
this point?
please no bs ill mark the crown thingy thingy
A 20 N force pulls to the right and friction pulls 5 N. If the mass is 5 kg, find acceleration.
Answer:
Explanation:
Force - frictional Force = m * a
20N - 5N = 5 * a
15N = 5*a
15N / 5 = a
a = 3 m/s^2
You should note a couple of things.
1. The frictional Force always opposes the direction of motion. In this case it is minus and the 20 N is plus. It makes the acceleration less. If the friction force was not there then 20 N = m * a
20N = 5 kg * a
a = 20/5
a = 4 m/s^2.
For an experiment to produce useful data, what must happen?
A. It must be performed by a famous scientist.
B. It must prove a hypothesis correct.
C. It must be published in a famous journal.
D. It must be repeated several times.
Answer: D
Explanation: It must be repeated several times. (You could have different results everytime. Kind of like a dice. If you only roll it once and get a 3, you will only think it rolls a 3 unless you roll it and get different results or unless you've seen a dice before.)
CEK- 9. If the speed of sound at 0° C is vo, the velocity at 273° C will be (a) 2 vo (b) 0.5 vo b (c) (d) 0.7 vo 1.4 vo
Answer:
D
Explanation:
273 * 0.6=163.8
vo≈331
A 10 g dime and a 200 g gold coin are dropped from the Empire State Building in
New York at the same time.; if there is no air resistance which hits the ground first?
A.They both hit the ground at the same time
B.Which hits first depends on the weather & temperature of the air.
C.The 200 g gold coin hits the ground first
D.The 10 g dime hits the ground first
Answer:
Explanation:
The both hit the ground at the same time. There is no air resistance and that includes the factors brought up in B.
C and D are both eliminated. If you dropped an 800 kg honda Fit it would hit the ground at the same time as the two coins. When you look at the formulas used to derive time, they look like
d = vi * t + 1/2 a* t^2
vi = 0
the distance to fell is the same for all three masses.
a is the same for all 3 masses.
So when you solve for t, there is no mention of the mass of the object falling. Therefore t is dependent only on the height.
100k points pls solve asap or no points
Answer:
Explanation:
You have given us a very weird question. Things do not mesh
If the mass is 500 kg and sits 25 m above the lowest spot on the track, the potential energy is
PE = mgh = 500(9.8)(25) = 122500 Joules,
not the reported 61250 Joules
So either the Joules is incorrect or the mass is supposed to be 250 kg.
In either case, in the absence of friction, the potential energy will convert to kinetic energy.
½mv² = mgh
v = √2gh
which does not involve the use of either Joules or kilograms.
Maximum velocity when starting from rest is
v = √(2(9.8)25) = √490 = 22.135943...
v = 22 m/s
A train slows down for 40 m/s to 10 m/s in 60 seconds how far does it travel in that time
Answer:
It will travel a distance of 1500 m within the time of 60 seconds.
The weight of an astronaut plus his space suit on the Moon is only 260 N.
how much is the weight on earth assuming the gravity on the moon is 1.67?
Answer:
2.68
Explanation:
sana maka tulong heheWhich are characteristics of matter? (Select all that apply.)
It has mass.
It only has one type of atom in it.
It is the smallest part of an element.
It takes up space.
Answer:
It has mass, it takes up space
Explanation:
How much gravitational potential energy is stored in a 2.0kg object that has been raised up to a height of 3.5m
Answer:
68.6 joules
Explanation:
g.p.e=mass × gravity × height
= 2 × 9.8 × 3.5
=68.6 joules
The gravitational field strength on earth is 10n/kg. find the weight of an object of mass 25kg
Answer:
250N
Explanation:
weight = Mass(in kg) × Gravitational field strength
25 × 10 = 250N
Answer:
250 N
Explanation:
Refer the attachment for explanation.
Questions
Q1. In this lab the centripetal force is provided by
a) the person’s hand
b) the tube
c) the hanging weight
d) the spinning motion
Q2. If the mass of the stopper were doubled but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled
Q3. If the velocity of the stopper were doubled, but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled
Answer:
just doing your module wag asa brainly ok malaki kna
you hit a ball with a bat. the ball acts on the bat, and the bat exerts equal and opposite force on the ball. This will cause the ball to be in (equilibrium or acceleration). Explain your answer.
Answer:
equilibrium because its equal force on the ball.
Explanation:
Answer:
good
Explanation:
A snowboarder drops from rest into a halfpipe of radius R and slides down its frictionless surface to the bottom
(a) Show that the snowboarder's speed at the bottom of the halfpipe is
v = 2gR (use conservation of energy)
(b) Show that the snowboarder's centripetal acceleration at the bottom is
ac = 2g (Apply the expression for centripetal acceleration)
(c) Show that the normal force on the snowboarder at the bottom of the halfpipe has a magnitude of 3mg (Use Newton's second law of motion)
A snowboarder drops from rest into a halfpipe of radius R and slides down its frictionless surface to the bottom, the snowboarder's speed is [tex]\mathbf{v = \sqrt{2gR}}[/tex]
The snowboarder's centripetal acceleration at the bottom is [tex]\mathbf{a_c = 2g}[/tex]. The normal force acting on the snowboarder at the bottom of the halfpipe = 3mg
According to the conservation of energy, at any given point of motion, the energy of a system will always be constant.
Using the conservation of energy at rest and also at the bottom of the pipe.
Total potential energy of the person(since its at rest = Total kinetic energy at the bottom of the pipe.[tex]\mathbf{mgR = \dfrac{1}{2}mv^2}[/tex]
The objective is to make the velocity (v) the subject of the formula:
[tex]\mathbf{gR = \dfrac{1}{2}v^2}[/tex]
[tex]\mathbf{2gR = v^2}[/tex]
[tex]\mathbf{v = \sqrt{2gR}}[/tex]
(b)
Using the expression for centripetal acceleration;
[tex]\mathbf{a_c = \dfrac{v^2}{R}}[/tex]
here,
let's replace [tex]\mathbf{v \ \ \ with \ \ \sqrt{2gR}}[/tex];
Then;
[tex]\mathbf{a_c = \dfrac{(\sqrt{2gR})^2}{R}}[/tex]
[tex]\mathbf{a_c =2g}[/tex]
From the image attached below;
Provided that:
n = normal forcew = mg weight of the person[tex]\mathbf{F_c}[/tex] = centripetal forceThen, we can infer that the normal net force acting on the person can be computed as:
[tex]\mathbf{F_c = n -mg}[/tex]By rearrangement;
[tex]\mathbf{n =F_c +mg}[/tex]where;
[tex]\mathbf{F_c = 2 mg}[/tex]∴
n = 2mg + mgn = 3mg
Therefore, we can conclude that the snowboarder's speed, centripetal force, and normal force are proved.
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