If the height is tripled, then which of the following statements about its volume will be true

The option (3) is correct the quotient is −5x³ + x + 3.

To solve quadratic equations by factoring, we first express the quadratic polynomial into a product of factors by using middle term splitting or different identities and then set each factor equal to 0. The equation a x 2 + b x + c = 0 ( a ≠ 0 ) can be written as.

According to given question

To divide[tex]15x^5[/tex] − 3x³ − 9x² by −3x² using the factorization method, we can factor out −3x² from the expression and simplify to get:

[tex]15x^5[/tex]− 3x³ − 9x²= −3x²(−5x³ + x + 3)

Therefore, the quotient is −5x³ + x + 3.

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The highest point of a normal curve, also known as a Gaussian distribution or bell curve, always occurs at the mean. This is because the normal curve is symmetrical around the mean, with the same number of values on either side of the mean. Therefore, the peak of the curve must be directly above the mean.

The standard deviation is a measure of how spread out the values in a distribution are. For a normal distribution, approximately 68% of the values fall within one standard deviation of the mean, 95% fall within two standard deviations of the mean, and 99.7% fall within three standard deviations of the mean. Therefore, while the highest point of the normal curve occurs at the mean, the curve does extend out to both sides of the mean, with the height of the curve gradually decreasing as the distance from the mean increases.

Specifically, the point at which the curve begins to flatten out on either side of the peak is approximately one standard deviation away from the mean. At two standard deviations away from the mean, the curve has flattened out significantly, and at three standard deviations away from the mean, the curve is almost entirely flat. This is known as the empirical rule, or the 68-95-99.7 rule.

Understanding the normal curve and its characteristics is important in statistics and data analysis, as many real-world phenomena can be approximated using a normal distribution. By knowing the mean and standard deviation of a distribution, we can make predictions about the likelihood of various outcomes occurring.

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The width of the parking lot in the drawing is 16 centimeters

Gabby made a scale drawing of the town library. She used the scale 1 centimeter : 5 meters. The actual width of the parking lot is 80 meters.

If the scale is 1 centimeter : 5 meters, then 1 centimeter on the drawing represents 5 meters in real life.

To find the width of the parking lot in the drawing, we need to set up a proportion

1 cm : 5 m = x cm : 80 m

Where x is the width of the parking lot in the drawing.

To solve for x, we can cross-multiply and simplify

1 cm * 80 m = 5 m * x cm

80 cm = 5x

x = 16 cm

Therefore, the width of the parking lot in the drawing is 16 centimeters.

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The height of the cuboid is 14cm.

What is the perimeter?

A closed path that covers, encircles, or outlines a one-dimensional length or a two-dimensional shape is called a perimeter. A circle's or an ellipse's circumference is referred to as its perimeter. There are numerous uses in real life for perimeter calculations.

Here, we have

Given: Joe has 784 one-centimeter cubes.

He arranges all of the cubes into a cuboid.

The perimeter of the top of the cuboid is 30 cm.

Each side of the cuboid has a length greater than 2 cm.

We have to find the height of the cuboid.

1. a = 7, b = 8

V = 784

We know that

height = V/s

h = 784/56

h = 14cm

Hence, the height of the cuboid is 14cm.

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The solution to this system of equations can be found by equating f(x) and g(x) and solving for x:

3x = x + 2

2x = 2

x = 1

Based on the given table data, we can see that the number of imports (f(x)) and the number of exports (g(x)) follow a linear relationship with respect to the month (x). The data shows that as the month progresses, both the number of imports and exports increase.

The system of equations can be represented as follows:

f(x) = 3x

g(x) = x + 2

The first equation f(x) = 3x represents the number of imports, where the coefficient of x is 3, indicating that the number of imports increases by 3 units for every increase of 1 unit in the month.

The second equation g(x) = x + 2 represents the number of exports, where the coefficient of x is 1, indicating that the number of exports increases by 1 unit for every increase of 1 unit in the month. Additionally, there is a constant term of 2, which represents the initial number of exports in the month of January.

The solution to this system of equations can be found by equating f(x) and g(x) and solving for x:

3x = x + 2

2x = 2

x = 1

The solution x = 1 represents the month of January, where both the number of imports and exports are equal to 3. This implies that in the month of January, there were 3 units of imports and 3 units of exports.

In all, the solution to the system of equations indicates that in the month of January (x = 1), the number of imports (f(x)) and the number of exports (g(x)) were both 3 units, as per the given data in the table.

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There are 144 ways to arrange the letters in UNIVERSALLY so that no two vowels occur consecutively and the consonants appear in alphabetical order

To solve this problem, we can break it down into two parts:

Part 1: Arranging the consonants in alphabetical order
The consonants in UNIVERSALLY are N, R, S, V, and Y. Since we want them to appear in alphabetical order, there is only one way to arrange them: NRSVY.

Part 2: Arranging the vowels so that no two occur consecutively
There are four vowels in UNIVERSALLY: E, I, U, and A. To arrange them so that no two occur consecutively, we can use the following strategy:

1. Start with the two consonants N and R. There are three spaces between them where we can place the vowels: _N_R_. We can place the vowels in these spaces in 4! = 24 ways.

2. Next, we add the consonant S to the left of N. There are now four spaces between S and R: S _ N _ R _. We can place the vowels in these spaces in 3! = 6 ways.

3. We continue adding consonants in alphabetical order and placing the remaining vowels in the available spaces. After adding V and Y, we end up with the following arrangement:

S U N I V E R S A L L Y R

There are 24 ways to arrange the vowels between the consonants at step 1, 6 ways to arrange them at step 2, and only 1 way to arrange them after all the consonants have been added. Therefore, the total number of arrangements that satisfy both conditions is:
24 x 6 x 1 = 144

So there are 144 ways to arrange the letters in UNIVERSALLY so that no two vowels occur consecutively and the consonants appear in alphabetical order.

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Step-by-step explanation:

oh you have to do is that you have to see 15 / 18 ft * 15 / 1

Hence, the correct answer are Function  f(x)  is  translated  6  units  to  the left and Function  f(x)  is translated 8 units down.

Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are ubiquitous in mathematics and are essential for formulating physical relationships in the sciences.

The absolute value of a number refers to the distance of a number from the origin of a number line. It is represented as |x|,  which defines the magnitude of any integer ‘x’. The absolute value of any integer, whether positive or negative,  will be the real numbers,  regardless of which sign it has.   It is represented by two vertical lines  |x|,  which is known as the modulus of x.

Function  f(x) = ||x||  is  transformed  to  create function  g(x) =  ||x+6||-8.

To  get  from  f(x)  to  g(x),

we  need  to  perform  the  following  transformations:

Therefore,  the correct  statements  are:

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The area of each of the missing faces is 40 m².

The length of each of the missing faces is 10 m.

The missing dimension is 10 m by 4 m.

Area is the region bounded by a plane shape.

To calculate the area of each missing face, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

And the length of each of the missing edge can be calculated using the formula below

Formula:

Where:

From the diagram in the question,

Given:

Substitute into equation 2

Hence, the length is 10 m.

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The expansion of the polynomial (-p²+4p-3)(p²+2) would be is -p⁴ + 4p³ - 5p² + 8p - 6  

Here we need to expand the polynomial (-p²+4p-3)(p²+2)

To do so we need to multiply each of the term with the first bracketby the each term of second bracket.

So, the expansion of the polynomial (-p²+4p-3)(p²+2) would be,

(-p² + 4p - 3)(p² + 2)

= [p² × (-p² + 4p - 3)] + [2 × (-p² + 4p - 3)]

= [p² × (-p²) + p² × 4p - p² × 3] + (-2p² + 8p - 6)

= (-p⁴ + 4p³ - 3p²) + (-2p² + 8p - 6)

= -p⁴ + 4p³ - (3 + 2)p² + 8p - 6       .......(add like terms)

=  -p⁴ + 4p³ - 5p² + 8p - 6  

Therefore, the required polynomial is -p⁴ + 4p³ - 5p² + 8p - 6  

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10% of 2-digit positive integers have a tens digit that is one greater than the ones digit.

To solve this problem, we first need to determine how many 2-digit positive integers there are. Since the smallest 2-digit integer is 10 and the largest is 99, we have a total of 90 integers (99-10+1).

Next, we need to determine how many of these integers have a tens digit that is one greater than the ones digit. To do this, we can create a chart and list out all possible combinations:

10, 21, 32, 43, 54, 65, 76, 87, 98

There are a total of 9 such integers. Therefore, the percentage of 2-digit positive integers that have a tens digit that is one greater than the ones digit is:

9/90 * 100% = 10%

So, 10% of 2-digit positive integers have a tens digit that is one greater than the ones digit.
To answer your question, let's first identify the range of 2-digit positive integers and determine the number of combinations where the tens digit is one greater than the ones digit.

The range of 2-digit positive integers is from 10 to 99. Now, we need to find the pairs of digits where the tens digit is one greater than the ones digit. The possible pairs are:

(1,0), (2,1), (3,2), (4,3), (5,4), (6,5), (7,6), (8,7), and (9,8)

There are 9 pairs that meet the condition. Now we need to find the total number of 2-digit positive integers:

99 (the last 2-digit integer) - 10 (the first 2-digit integer) + 1 = 90

So, there are 90 two-digit positive integers in total.

Now, we can calculate the percentage of the 2-digit positive integers that have a tens digit one greater than the ones digit:

(9 / 90) * 100 = 10%

Therefore, 10% of 2-digit positive integers have a tens digit that is one greater than the ones digit.

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Approximately 4.44% of 2-digit positive integers have a tens digit that is one greater than the ones digit.

Let's consider the possible pairs of tens digit and ones digit that satisfy the condition. There are 4 such pairs: [tex](1, 0)$, $(2, 1)$, $(3, 2)$[/tex], and [tex](4, 3)$.[/tex] For each tens digit, there is exactly one ones digit that satisfies the condition. So, out of the 90 possible two-digit positive integers (ranging from 10 to 99), only 4 of them have a tens digit that is one greater than the ones digit.

Therefore, the percentage of 2-digit positive integers that have a tens digit that is one greater than the ones digit is:

[tex]$\frac{4}{90} \cdot 100% \approx 4.44%$[/tex]

So, approximately 4.44% of 2-digit positive integers have a tens digit that is one greater than the ones digit.

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The x² value lie between 1.42 and 2.37

The formula to calculate the x² value is:

χ² = Σ (Observed frequency - Expected frequency)² / Expected frequency

Here, Σ represents the sum of all the values in the calculation. The observed frequency is the actual frequency of a category in the sample, while the expected frequency is the theoretical frequency based on the null hypothesis.

The x² value is compared to a chi-squared distribution table to determine its significance level. The table shows the probability of obtaining a certain x² value under the null hypothesis for different degrees of freedom. Degrees of freedom (df) are calculated as the number of categories minus 1.

If the calculated x² value is greater than the critical value from the table for a given significance level, the null hypothesis is rejected, and the alternative hypothesis is accepted. This means that there is a significant relationship between the variables. If the calculated x² value is less than the critical value, the null hypothesis is accepted, and no significant relationship is found.

In the context of the problem given, the x² value is used to test the hypothesis that the genes are unlinked. The significance level used is 0.05, which means that there is a 5% chance of rejecting the null hypothesis when it is actually true. If the probability corresponding to the x² value is less than or equal to 0.05, the hypothesis should be rejected. If it is greater than 0.05, the results are not statistically significant, and the hypothesis is accepted.

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Complete Question:

The x² value means nothing on its own- it is used to find the probability that, assuming the hypothesis is true, the observed data set could have resulted from random fluctuations. A low probability suggests that the observed data are consistent with the hypothesis, and thus the hypothesis should be rejected, A standard cutoff point used by biologists is a probability of 0.05(5%). If the probability corresponding to the x² value is 0.05or considered statistically significant, the hypothesis (that the genes are unlinked) should be rejected. If the probability is above 0.05, the results are not statistically significant: the observed data are consistent with the hypothesis.

Determines which values on the df =3 line of the table your calculated x² value lies between.

The value of cos (2theta) will be; 161/289

We are given that tan(A) = -8/15, therefore opposite is 8 and adj is 15

hyp = √8²+15²

= √ 64+225

= √ 289

= 17

Thus, cos (theta) = 8/17 and since theta is in second quadrant, cos tetha will be negative

cos (theta) = -15/17

cos²(theta) = 225/289

sin(theta) = 8/17

sin²(theta) = 64/289

cos(2theta) = cos²(theta) -sin²(theta)

= 225/289 - 64/289

= 161/289

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The expression that represents the relationship between the step number n and the total number of small squares in the pattern is this: (n-1)^2.

From the given information, we can see that the pattern starts with 0 squares at step 1, and each subsequent step adds a square to the pattern. However, the lower right square is always missing. Therefore, the total number of small squares in the pattern at step n can be represented by the expression: (n-1)^2

The reason we subtract 1 from n is that we started counting from step 1, whereas the expression (n-1)^2 assumes that we start counting from 0. Then we square (n-1) to account for the number of squares in the pattern, excluding the missing square in the lower right corner.

Complete Question:

Which expression represents the relationship between the step number n and the total number of small squares in the pattern?

A pattern of small squares. Step 1 has 0 squares. Step 3 has 3 squares: 2 by 2 but missing the lower right square. Step 3 has 8 squares: 3 by 3 but missing the lower right square.

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a) The exact solutions on [0, 2π) are t = π/3, π, and 5π/3. b) The exact solution on the interval [0, π) is t = 2π/3. c) The solutions are θ = π/3 and θ = 5π/3. d) The exact solutions on the interval [0, 2π) are: t = arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4] and t = 2π - arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4] using trigonometric identities.

a) We can rewrite the equation as:

2[tex]cos^{2}t[/tex] + cos(t) - 1 = 0

Using the quadratic formula, we get:

cos(t) = [-1 ± [tex]\sqrt{1-4(2)(-1)}[/tex] ] / (4)

cos(t) = [-1 ± [tex]\sqrt{9}[/tex]]/4

cos(t) = [-1 ± 3]/4

Thus, we have two solutions:

cos(t) = 1/2, which gives us t = π/3 and t = 5π/3

cos(t) = -1, which gives us t = π

Therefore, the exact solutions on [0, 2π) are t = π/3, π, and 5π/3.

b) We can use the identity [tex]tan^{2}t[/tex] + 1 = [tex]sec^{2}t[/tex] to rewrite the equation as:

[tex]tan^{2}t[/tex] = - [tex](3/2)^{2}[/tex]

Taking the square root of both sides and remembering that tan(t) is negative in the third quadrant, we get:

tan(t) = -3/2

Using the identity tan(t) = sin(t)/cos(t), we can rewrite this as:

sin(t)/cos(t) = -3/2

Multiplying both sides by cos(t) and rearranging, we get:

sin(t) = -3cos(t)/2

Squaring both sides and using the identity [tex]sin^{2}t[/tex] + [tex]cos^{2}t[/tex] = 1, we get:

9[tex]cos^{2}t[/tex]/4 + [tex]cos^{2}t[/tex] = 1

Expanding and simplifying, we get:

13 [tex]cos^{2}t[/tex] /4 = 1

[tex]cos^{2}t[/tex]  = 4/13

Taking the square root of both sides and remembering that cos(t) is negative in the third quadrant, we get:

cos(t) = -2[tex]\sqrt{13}[/tex] /13

Using the identity  [tex]sin^{2}t[/tex] +  [tex]cos^{2}t[/tex]  = 1, we can solve for sin(t) as:

sin(t) = -3/2 cos(t) = 3[tex]\sqrt{13}[/tex] /13

Therefore, the exact solution on the interval [0, π) is t = 2π/3.

c) We can use the identity sin(2θ) = 2sin(θ)cos(θ) to rewrite the equation as:

sin(θ) = 2sin(θ)cos(θ)

Dividing both sides by sin(θ) (assuming sin(θ) is non-zero), we get:

1 = 2cos(θ)

cos(θ) = 1/2

Therefore, the solutions are θ = π/3 and θ = 5π/3.

d) We can use the identity cos(2t) = 1 - 2 [tex]sin^{2}t[/tex]  and rearrange the equation as:

2 [tex]sin^{2}t[/tex]  + sin(t) - 5 = 0

Solving this quadratic equation using the quadratic formula, we get:

sin(t) = [-1 ± [tex]\sqrt{41}[/tex]]/4

Since the sine function has a range of [-1, 1], only the positive solution is possible, so we have:

sin(t) = (-1 + [tex]\sqrt{41}[/tex])/4

Using the identity [tex]cos^{2}t[/tex] = 1 -  [tex]sin^{2}t[/tex] , we can solve for cos(t) as:

cos(t) =[tex]\sqrt{1-sin^{2}t}[/tex] = [tex]\sqrt{17-\sqrt{41} }/4[/tex]

Therefore, the exact solutions on the interval [0, 2π) are:

t = arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4] and t = 2π - arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4]

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The relation {(5,0), (0,5), (5,1), (1,5)} is not a function because some inputs have multiple outputs.

To graph the relation {(5,0), (0,5), (5,1), (1,5)}, we can plot the points on a coordinate plane and connect them to form a scatter plot.

The graph of this relation looks like two intersecting lines that form an "X" shape, where the points (5,0) and (0,5) are on one line and the points (5,1) and (1,5) are on the other line.

Now, to determine whether this relation is a function or not, we need to check if each input (x-value) is associated with exactly one output (y-value).

Looking at the points, we see that both x=5 and y=5 have multiple outputs: (5,0) and (5,1) for x=5, and (0,5) and (1,5) for y=5. This means that the relation is not a function, as there are multiple y-values associated with a single x-value, violating the definition of a function.

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The exact lengths of the missing sides for the right triangle using trigonometric ratio of the respective angles are: a = 4, b = 4√3, c = 4√3, and d = 4√6

The trigonometric ratios is concerned with the relationship of an angle of a right-angled triangle to ratios of two side lengths.

The basic trigonometric ratios includes;

sine, cosine and tangent.

sin 30 = a/8 {opposite/hypotenuse}

a = 8 × 1/2 {sin 30 = 1/2}

a = 4

cos 30 = b/8 {adjacent/hypotenuse}

b = 8 × √3/2 {cos 30 = √3/2}

b = 4√3

sin 45 = 4√3/d

d = 4√3 × 2/√2 {sin45 = √2/2}

d = 4√6

cos 45 = c/4√6

c = 4√6 × √2/2

c = 2√12

c = 4√3

Therefore, the exact lengths of the missing sides for the right triangle using trigonometric ratio of the respective angles are: a = 4, b = 4√3, c = 4√3, and d = 4√6

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Joseph must score at least 32 on exam B to do equivalently well as he did on exam A.

To determine how well Joseph must score on exam B in order to do equivalently well as he did on exam A, we need to find the equivalent z-score for his exam A score and then use it to find the corresponding score on exam B.

First, we find the z-score for Joseph's exam A score:

z = (x - mu) / sigma

z = (516 - 600) / 40

z = -2.1

The z-score of -2.1 indicates that Joseph's exam A score is 2.1 standard deviations below the mean.

To find the equivalent score on exam B, we use the formula:

z = (x - mu) / sigma

Solving for x, we get:

x = z * sigma + mu

x = -2.1 * 20 + 76

x = 32

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We can say with 82% confidence that the true difference in mean times for left-handed and right-handed people is between -0.978 s and -0.222 s and t-distribution is used.

To calculate the certainty interim for the contrast between left-handed and right-handed individuals, we are able to utilize the taking-after equation:

CI = (x1 - x2) ± t*SE 

where:

x1 = the meantime for left-handed people

x2 = the meantime for right-handed people

t = the critical value for the t-distribution with n1+n2-2 degrees of freedom and the desired confidence level (in this case, 82%)

SE = the standard error of the difference in means, which is calculated as:

[tex]SE = sqrt((s1^2/n1) + (s2^2/n2))[/tex]

where:

s1 = the standard deviation for left-handed people

s2 = the standard deviation for right-handed people

n1 = the sample size for left-handed people

n2 = the sample size for right-handed people

Plugging in the given values, we get:

x1 - x2 = 1.1 - 1.7 = -0.6

s1 = 0.4

s2 = 1.4

n1 = 47

n2 = 42

[tex]SE = sqrt((0.4^2/47) + (1.4^2/42)) = 0.261[/tex]

To find the critical value for the t-distribution, we can use a t-table or a calculator. With n1+n2-2 = 87 degrees of freedom and an 82% confidence level, the critical value is approximately 1.360.

Thus, the 82% confidence interval for the difference in left-handed or right-handed people is:

CI = (-0.6) ± (1.360*0.261) = (-0.978, -0.222)

hence, we can say with 82% confidence that the true difference in mean times for left-handed and right-handed people is between -0.978 s and -0.222 s.

Note that we used the t-distribution because the sample sizes for both groups are relatively small (n1 = 47, n2 = 42).

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x - 4/3 ≤ 0 is equivalent to x ≥ 4/3, and they both represent the same set of values for x. My friend is correct.

The relationship between two values that are not equal is defined by inequalities.

When we subtract 4/3 from both sides; x ≤ 4/3 can be rewritten as:

x - 4/3 ≤ 0

-6x ≤ -8 can be simplified by dividing both sides by -6 and reversing the inequality which gives:

x ≥ 4/3.

Full question "Your friend says that the inequalities x ≤ 4/3 and -6x ≤ -8 is your friend correct? Explain the reason"

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Analyst input the function, they follow a predetermined structure that includes all required information for the function and its proper placement. so, syntax  of a function does this describe.

Syntax is a predetermined structure that includes all required information and its proper placement.

A formula in Excel is used to do mathematical calculations. Formulas always start with the equal sign = typed in the cell, followed by your calculation.

In the syntax of all Excel functions, an argument enclosed in [square brackets] is optional, other arguments are required. Meaning, your Sum formula should include at least 1 number, reference to a cell or a range of cells. For example: =SUM(B2:B6) - adds up values in cells B2 through B6.

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Answer: The answer to

sinΘ = 7/7√2

cosΘ = 7/7√2

tanΘ = 7/7

cosecΘ = 7√2/7

secΘ = 7√2/7

cotΘ = 7/7

Step-by-step explanation:

The given triangle consists of three sides namely, hypotenuse, opposite and adjacent.

The value of the hypotenuse is 7√2 and the value of the adjacent is 7.

We will calculate the value of the adjacent.

By Pythagoras' theorem,  (hypotenuse)^2=(opposite)^2+(adjacent)^2

Putting the given values, (7√2)^2=(opposite)^2+(7)^2

                                         (opposite)^2=(7√2)^2-(7)^2

                                         (opposite)^2=98-49

                                         (opposite)^2=49

Therefore, the value of the opposite is 7.

Now, we can put the following values in the trigonometric table.

sinΘ = opposite/hypotenuse = 7/7√2

cosΘ = adjacent/hypotenuse = 7/7√2

tanΘ =  opposite/adjacent = 7/7

cosecΘ = hypotenuse/opposite = 7√2/7

secΘ = hypotenuse/adjacent = 7√2/7

cotΘ = adjacent/opposite = 7/7

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The polar form of the rectangular coordinates (-3√3, 0) is r = 3√3 and θ = 0

To convert the rectangular coordinates (-3√3, 0) into polar form, we can use the following equations:

r = √(x² + y²)

θ = tan⁻¹(y/x)

In this case, x = -3√3 and y = 0, so we have:

r = √((-3√3)² + 0²) = 3√3

θ = tan⁻¹(0/(-3√3)) = tan⁻¹(0) = 0

Since the angle is given in radians over the interval 0 ≤ θ < 2π (which is equivalent to 0 ≤ θ < 6.28318), we need to add 2π to θ if it is negative, to ensure that θ is in the specified interval.

However, in this case, θ is already equal to 0, which is within the specified interval.

Therefore, the polar form of the rectangular coordinates (-3√3, 0) is:

r = 3√3

θ = 0 (in radians, over the interval 0 ≤ θ < 2π)

To know more about the conversion of coordinates into other forms visit:

brainly.com/question/31442898

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Answer:

1,760m

Step-by-step explanation:

The side of the smaller triangle is multiplied by 4, which got 44 in the bigger triangle. So you would multiply the base of the smaller by 4 as well, resulting in 80. Now you need to multiply the base and the side of the triangle, and divide that answer by half.

FORMULA FOR A TRIANGLE:

A= 1/2( L x W )

A= 1/2 (44 x 80)

A= 1/2 (3520)

A= 1760

Therefore, the area of the shaded triangle is 1,760m.

SORRY IF THIS DID NOT MAKE SENSE!

Answer:

sugger

Step-by-step explanation:

because she bought 34.15 super and 34.144 pepper