If someone was to
place a cool lid on this
pot of boiling water,
what would happen?
A. The water particles will lose energy once they touch
the lid.
B. The water particles will gain energy once they touch
the lid.
C. The water particles will get locked in place once they
touch the lid.

The electric field due to charge q1 and q2 at the middle point of the line joining the charges q1 and q2 is 8.64*10^(4) N/C.

Note: You have not given the point where the resultant magnetic field has to be calculated. Most probably it is asked to find the electric field at the middle point of the line joining the point charges.

Electric field: The electric force exerted on a unit charge is called the electric field. Electric field due to a charge is calculated using the formula,

E=kq/r^2

where k is a constant whose value is 9*10^(9) N m^2/ C^(2), q is the charge and r is the distance from the charge to the point where the electric field has to be calculated. In the given case, the electric field has to be calculated at the middle point of the line joining charges q1 and q2.

Calculation of electric field due to charge q1:

Given that q1=+12 nC or q1=+12*10^(-9) C and the distance of the charge q1 from the center d1=10.0/2 cm or d1=5*10^(-2) m, the magnitude of the electric field E1 due to charge q1 is,

E1=kq1 /d1^(2)

E1=9*10^(9)*12*10^(-9) / (5*10^(-2))^2

E1=4.32*10^(4) N/C

The direction of the electric field E1 at the middle point is towards the negative charge.

Calculation of electric field due to charge q2:

Given that q2=-12 nC or q1=-12*10^(-9) C and the distance of the charge q2 from the center d2=10.0/2 cm or d2=5*10^(-2) m, the magnitude of the electric field E2 due to charge q2 is,

E2=kq2 /d2^(2)

E2=9*10^(9)*12*10^(-9) / (5*10^(-2))^2

E2=4.32*10^(4) N/C

The direction of the electric field E2 at the middle point is towards the negative charge.

Total electric field:

The total electric field is given by the addition of the electric field. The direction of the electric field is the same for both charges, hence total electric field E is,

E=E1+E2

E=4.32*10^(4) +4.32*10^(4)

E=8.64*10^(4) N/C

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Applications of Magnetic Effect of ELectric Current:

Electrical appliances such as the electric doorbell, electric fan, electric engines work on the principle of electromagnets. They are used in lifting weighty iron gears and iron scrap.

Magnetic field exercises a force on a current carrying conductor. The force exerted on the current carrying conductor depends upon the demand of current and movement of magnetic field acting on it.

Examples of magnetic force is a compass, a motor, the interests that hold stuff on the refrigerator, train tracks, and new roller coasters. All moving costs give rise to a magnetic field and the charges that move through its regions, share a force.

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The frictional force exerted by the road on the car is 3000N

Given the mass of the car is 1000 kg , the velocity of the car is 20m/s

and the time is 6.6s

We need to find the frictional force exerted by the road on the car

We know that Force = mass * acceleration

Now here Mass is given but acceleration is not given

So, we will find acceleration by using the formula v = u+at

Where u = 0

v = 20m/s

a = ?

t = 6.6

Substitute the values in the formula We get

v = u+at

20 = 0+(a)(6.6)

20/6.6 = a

∴ a = 3.03 m/s^2

Rounding to nearest tenth is 3m/s^2

Hence the acceleration is 3m/s^2

Now substituting the value of acceleration in F = ma

Where m = mass

a = acceleration

F = 1000*3

∴ F = 3000N

Hence the frictional force exerted by the road on the car is 3000 N

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Answer:

Mechanical advantage

Explanation:

Machines help us in giving more output than the input incurred so it only increases mechanical advantage, all the other quantities are dependent on the mechanical advantage.

Answer:

The decrease in energy for a lightning flash, with a potential difference between a cloud and the ground, is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C is [tex]$3.555 \times 10^{10} \text{ J}$[/tex].

Explanation:

In a lightning flash, the potential difference between a cloud and the ground is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C.

It is required to determine the decrease in energy of the transferred charge.

It is known that the decrease in energy is calculated by multiplying the potential difference by the quantity of charge. Mathematically it is expressed as:

[tex]\Delta U=q \Delta V[/tex]

In this problem, the value of q is 23.7 C and the value of [tex]\Delta V[/tex] is [tex]1.5 \times 10^{9}\text{ V}[/tex].

Therefore the decrease in energy is:

[tex]$$\begin{aligned}\Delta U&=q \Delta V\\&=23.7\times 1.5 \times 10^{9} \text{ J}\\&=3.555\times 10^{10} \text{ J}\end{aligned}$$[/tex]

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Answer:

,ff

Explanation:

2331552378 added mee

A mechanical wave transfers energy through matter.

A mechanical wave is a wave that is an oscillation of matter and is responsible for the transfer of energy through a medium.

Answer: Like all waves, mechanical waves transport energy. This energy propagates in the same direction as the wave. A wave requires an initial energy input; once this initial energy is added, the wave travels through the medium until all its energy is transferred. In contrast, electromagnetic waves require no medium, but can still travel through one.

A wave is a transmission of a disturbance from one point to another. Wave involves transmission of energy from one point to another through a materials medium.

Mechanical waves vibrate in matter and transfer energy. Explore the production and propagation of mechanical waves and discover the factors that affect mechanical waves including elasticity, tension, temperature, and density

Therefore,

A mechanical wave transfers energy through matter.

A complete question is is given below:

What best describes a possible transfer of energy?

a. A mechanical wave transfers energy through matter.

b. A longitudinal wave transfers energy perpendicular to wave motion.

c. A transverse wave transfers energy parallel to wave motion.

d. A sound wave does not need a medium to transfer energy through.

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Answer:

An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.

Explanation:

Tensions around rocks are increasing, and an earthquake begins at tectonic plates.

The majority of earthquakes begin at or close to tectonic plate borders, where stress and strain gradually build up due to interactions between the plates over time. An earthquake occurs when the amount of accumulated tension surpasses the capacity of the rocks, which causes an abrupt release of energy. When there is an earthquake, seismic waves are released, and we feel and sense shaking as a result.

But even beyond plate borders, within tectonic plates, earthquakes can still happen. These earthquakes, also known as intraplate earthquakes, are frequently connected to old faults or weak spots in the crust of the Earth. Despite being less frequent than those near plate borders, intraplate earthquakes can nevertheless be severe and cause damage in populated regions.

Hence, tensions around rocks are increasing, and an earthquake begins at tectonic plates.

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The power that heat pump draws when running will be 6.55 kj/kg

A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).

Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8

We have to determine the power the heat pump draws when running.

To solve this question we have to assume that the heat pump is at steady state

Let,

Q₁ = 22000 kj/kg

COP = 2.8

Since heat pump used to heat a house runs about one-third of the time.

So,

Q₁ = 3(22000) = 66000 kj/kg

We known the formula for cop of heat pump which is as follow:

COP = Q₁/ω

2.8 = 66000 / ω

ω = 66000 / 2.8

ω = 6.66 kj/kg

Hence the power that heat pump draws when running will be 6.55 kj/kg

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It will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.

Pressure is defined as force applied per unit area of the given surface.

Pressure = Force/Area

The pressure of air inside the bicycle pump is smaller compared to the air pressure inside the tire.

Thus, it will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.

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The work required to compress it another 1 in Btu is 0.02463 Btu.

Work finished is elaborated in the sort of way that it consists of both forces exerted at the frame and the full displacement of the body. This block is preceded by a steady force F. The reason for this pressure is to transport the frame a sure distance d in an instant course in the direction of the force.

To explicit this idea mathematically, the work W is the same as the pressure f instances the distance d, or W = FD. If the pressure is being exerted at a perspective θ to the displacement, the work finished is W = FD cos θ.

The work is executed whenever a force actions something over a distance. you can calculate the electricity transferred, or work completed, by multiplying the force by way of the space moved inside the course of the force.

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The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82 R

What are the Asteroids:

here,

An asteroid experiences acceleration on earth's orbit which is 8.0 times smaller than it on the earth surface.

Free fall acceleration of Asteroid:

so,

g' = GM /(R + x)^2 ------1

g = GM / R^2

g' = 1/8 ( GM / R^2 ) -------1

where G is gravitational constant

M is mass of earth

R is earth's radius

comparing both equations 1 and 2

GM /(R + x)^2 =  1/8 ( GM / R^2 )

8 R^2 = (R + x)^2

2√2 * R = R + x

x = R (2√2 - 1)

x = 1.82*R

hence, The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82*R

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The voltage drop across the circuit, given that 0.05 A flows in the circuit is 1.25 V

This law states as follows:

V = IR

Where

From the question given above, the following data were obtained:

V = IR

V = 0.05 × 25

V = 1.25 V

Therefore, the voltage drop across the circuit is 1.25 V

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Answer:

Gravity and Air resistance.

Explanation:

A projectile is an object that is launched into the air by the application of an external force and they are able to move freely under the influence of gravity and air resistance.

Therefore,

The 2 forces acting on a projectile are:

Gravity and Air resistance.

Answer:

V = a * t      for uniformly accelerated motion starting at zero speed

V = 4 s * 9.8 m/s^2 = 39.2 m/s

S = V0 t + 1/2 a t^2 = 1/2 a t^2

S = 1/2 * 9.8 m/s^2 * 16 s^2 = 78.4 m

Check:

Average speed = 39.2 / 2 = 19.6 m/s

S = 4 * 19.6 = 78.4 m

For a simple compressible system, the change in the total energy of a system during a process is affected by changes in potential, kinetic, and internal energies.

The conservation of energy principle sometimes referred to as the first law of thermodynamics, offers a reliable framework for researching the connections between the many types of energy and their interactions. The first law of thermodynamics asserts that energy can only change forms during a process; it cannot be created or destroyed, according to experimental data. As a result, during a procedure, every piece of energy should be taken into account.

The evaluation of the system's energy at the start and end of the process, as well as the difference between them, is necessary to calculate the energy change of a system during a process. That is,

Energy change = Energy at final state - Energy at the initial state

                                  Δ[tex]E_{system}[/tex] = [tex]E_{2} - E_{1}[/tex]

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when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, then The core contracts and becomes black hole.

What is degeneracy pressure:

Some neutron stars may have a surface layer of highly degenerate matter that is compressed to great density, but still has some protons

Unlike the main body of the neutron star which is Neutronium, matter compressed until it is all neutrons, packed together. Essentially a huge atomic nucleus.

The star cools and all remaining matter is bound by gravitation into a neutron star.

This object is composed primarily of degenerate neutron matter, this star will collapse into a black hole because gravity will overcome the neutron degeneracy pressure.

hence, when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, The core contracts and becomes a black hole.

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Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

Explanation: To find the answer, we have to know about the Simple Harmonic Motion.

                   [tex]F[/tex]∝[tex]-x[/tex]

                   [tex]F=-kx[/tex] where, k is called the spring constant.

                       [tex]k=-F/x= (230)/ (0.400) =575 N/m.[/tex]

Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.

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The magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.

V = ⁴/₃π(R³ - r³)

V = ⁴/₃π (0.092³ - 0.0655³)

V = 2.085 x 10⁻³ m³

Q = Vσ

where;

Q = 2.085 x 10⁻³ m³  x 7.35 x 10⁻⁴ C/m³

Q = 1.53  x 10⁻⁶ C

E = kQ/R²

E₁ = (9 x 10⁹ x 1.53 x 10⁻⁶)/(0.092)²

E₁ = 1.627 x 10⁶ N/C

E₂ = (9 x 10⁹ x 2.14 x 10⁻⁶)/(0.092)²

E₂ = 2.276 x 10⁶ N/C

Electric field inside the solid at a distance of 9.50cm from the center of the cavity;

E = E₂ - E₁

E =  2.276 x 10⁶ N/C - 1.627 x 10⁶ N/C

E = 6.5 x 10⁵ N/C

Thus, the magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.

Complete question:

A point charge of -2.14uC  is located in the center of a spherical cavity of radius 6.55cm  inside an insulating spherical charged solid. The charge density in the solid is 7.35×10−4 C/m^3.

a) Calculate the magnitude of the electric field inside the solid at a distance of 9.20cm  from the center of the cavity.  

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The truck's velocity is 25 m/s.

It is given that,

                         mass, m= 36,287 kg

               momentum, p =  907,175 kg-m/s

Using the formula of momentum, we know that

                                     p = mv

Plugging in the values

               907,175 kg-m/s = 36,287 kg x v

                           v = 25 m/s

So, the velocity of the truck is 25 m/s.

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Answer:25

Explanation:your welcome!:)

Answer: 167.7702 N (Newtons)

Explanation: I had this type of work, so I hope I am correct.

Answer:

~ 168 N

Explanation:

F = m a

 = 20.41 * 8.22 = 167.7702 N

The vector force the wall is applying to the boy is -15 N; option D

A reaction force is a force which is equal in magnitude but oppositely directed to a force acting in a particular direction.

The reaction force on the boy is equal in magnitude to the weight of the boy but has an opposite direction.

In conclusion, the vector force applied by the wall on the boy is -15 N.

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The tension on the left wire 642N and the tension on right wire is 208N

Given that the force of scaffold is 200- N and the length of the scaffold is 18m

We need to find the tension in each wire

Tension Force is the force that is transmitted through a cable, rope, wire or string when it is pulled tight by forces acting from opposite ends

Here

∑ [tex]T_b=0[/tex]

∴ [tex]W_B(15m)+W_S(9m)-T_L(18m) = 0[/tex]

∴ [tex]T_L = \frac{W_B(15m)+W_S (9m)}{18m}\\ T_L = \frac{650(15)+200(9)}{18}\\ T_L = 642 N[/tex]

Hence the tension on the left side is 642N

∑[tex]T_a[/tex] = 0

[tex]T_R(18m)-W_B(3m)-W_S(9m)=0[/tex]

∴[tex]T_R =\frac{W_B(3m)+W_S(9m)}{18m}[/tex]

∴[tex]T_R = \frac{650(3)+200(+9)}{18}\\[/tex]

∴[tex]T_R = 208N[/tex]

Hence the tension on the right side is 208N

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The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.

Given information:

The mass of peregrine falcon is,  m = 480

The final speed reached by the peregrine falcon in a vertical dive is, v = 69 m/s

It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s  as the motion starts with rest.

The value of the gravitational acceleration of gravity is, g = 9.80 m/s²

Now, using the third equation of motion, the minimum height  required for the final speed will be,

v² - u² = 2gh

69² - 0² = 2 × 9.8 × h

h = 242.9m.

Therefore, the minimum height of the dive needed to achieve the given speed is 242.9 m.

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16.03 m/s is the initial speed of the cans.

Newton’s equations of motion has to be used to solve it;

He wants collision at height (h) = 4.0 m

The acceleration due to gravity  as,

                                                      g =9.8ms−²

The initial speed of the thrown can is calculated by:

h = vt - ¹/₂gt²

4 = 3t - (0.5)(9.8)(3)²

4 = 3t - 44.1

3t = 48.1

t = 48.1/3

t = 16.03 m/s

Thus, the initial speed of the boy's thrown can is 16.03 m/s.

By measuring the rate at which the velocity varies with regard to the passage of time, one can calculate the acceleration of a body. By calculating the rate at which the displacement varies with regard to the passage of time, the velocity may be calculated. The perpendicular distance between the body's initial and final locations is its displacement. These are all vector quantities, meaning they all have both magnitude and direction.

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Answer:

20m/s

Explanation:

it covers 20 metres in a second

Max Planck utilized the concept of energy quantization in order to develop a model for blackbody radiation that accurately fit experimental results.

Electromagnetic waves emitted by using a blackbody are referred to as blackbody radiation. A blackbody is bodily found out through a small hole within the wall of a hollow space radiator.

The depth of blackbody radiation depends on the wavelength of the emitted radiation and the temperature T of the blackbody.

When the temperature of a black frame increases, it is discovered that the wavelength similar to most electricity changes from 0.26 μm to 0. Thirteen μm Then the ratio of the emissive power of the body at the respective temperature is.

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The total force on the ground due to the bricks is 47,040 N.

The total force on the ground due to weight of the bricks is calculated as follows;

Fₙ = mg

where;

Fₙ = (1500 x 3.2) x 9.8

Fₙ = 47,040 N

Thus, the total force on the ground due to the bricks is 47,040 N.

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a gearbox bru.

The angle of bank needed, measured from the vertical is 86.6⁰.

The angle of bank needed, measured from the vertical is calculated as follows;

v = √(rg tanθ)

where;

400² = (960 x 9.8 x tanθ)

tanθ = 400²(960 x 9.8)

tanθ = 17

θ  = arc tan(17)

θ  = 86.6⁰

Thus, the angle of bank needed, measured from the vertical is 86.6⁰.

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