If JG=JF,GD=13, and mCD=136, find each measure.
Answers
Answer:
[tex]ED = 26[/tex]
[tex]CF = 13[/tex]
[tex]m \overset{\huge\frown}{ED} = 136[/tex]
[tex]m \overset{\huge\frown}{HD} = 68[/tex]
[tex]m \overset{\huge\frown}{CE} =88[/tex]
Step-by-step explanation:
Given
[tex]JG = JF[/tex]
[tex]GD = 13[/tex]
[tex]m \overset{\huge\frown}{CD} = 136[/tex]
See attachment for circle
Solving (a): Length ED
Line JD divides ED into two equal parts, EG and DG.
So:
[tex]ED = EG + GD[/tex]
[tex]ED = GD + GD[/tex]
[tex]ED = 13 + 13[/tex]
[tex]ED = 26[/tex]
Solving (b): Length CF
CF is a reflection of EG.
So:
[tex]CF = EG[/tex]
[tex]EG = GD = 13[/tex]
So:
[tex]CF = 13[/tex]
Solving (c): [tex]m \overset{\huge\frown}{ED}[/tex]
Since ED = CD;
Then:
[tex]m \overset{\huge\frown}{ED} = m \overset{\huge\frown}{CD}[/tex]
So:
[tex]m \overset{\huge\frown}{ED} = 136[/tex]
Solving (d): [tex]m \overset{\huge\frown}{HD}[/tex]
Line HF divides CD to 2 equal parts
So:
[tex]m \overset{\huge\frown}{HD} = \frac{1}{2} * m \overset{\huge\frown}{CD}[/tex]
[tex]m \overset{\huge\frown}{HD} = \frac{1}{2} * 136[/tex]
[tex]m \overset{\huge\frown}{HD} = 68[/tex]
Solving (e): [tex]m \overset{\huge\frown}{CE}[/tex]
[tex]m \overset{\huge\frown}{CE}[/tex] is a minor arc while [tex]m \overset{\huge\frown}{ED} = 136[/tex] + [tex]m \overset{\huge\frown}{CD} = 136[/tex] are the major arcs.
So:
[tex]m \overset{\huge\frown}{CE} + m \overset{\huge\frown}{ED} + m \overset{\huge\frown}{CD}= 360[/tex]
[tex]m \overset{\huge\frown}{CE} + 136+136= 360[/tex]
Collect like terms
[tex]m \overset{\huge\frown}{CE} =- 136-136+ 360[/tex]
[tex]m \overset{\huge\frown}{CE} =88[/tex]
Following are the calculated value " [tex]ED=26, CF=13\ , m \widehat{ED}=136^{\circ}\ , m \widehat{HD}=68^{\circ}\ , m \widehat{CE}=88^{\circ}\\\\[/tex]", and its complete calculation can be defined as follows:
Given value:[tex]\bold{JG=JF,GD=13,} \\\\ m \widehat{CD}=136^{\circ}\\\\[/tex]
When
[tex]m \widehat{CD}= m \widehat{ED}\\\\m \widehat{ED} = 136^{\circ}[/tex]
[tex]HJ \perp CD \\\\IJ \perp ED\\\\[/tex]
SO,
[tex]CF = FD \\\\EG=ED \\\\[/tex]
[tex]m \widehat{HD} = m \widehat{CH} = \frac{1}{2} m \widehat{CD}\\\\[/tex]
[tex]CF=13\\\\ ED = 13 \times 2 =26 \\\\ m \widehat{HD} = \frac{1}{2}\ m \widehat{CD} = 136^{\circ} \div 2 = 68^{\circ}\\\\m \widehat{CE} = 360^{\circ} -136^{\circ} - 136^{\circ} = 88^{\circ}\\\\[/tex]
Using the Vertical theorem and Theorem of the length of tangent to calculate the value:
[tex]ED=26\\\\CF=13\\\\m \widehat{ED}=136^{\circ}\\\\m \widehat{HD}=68^{\circ}\\\\m \widehat{CE}=88^{\circ}\\\\[/tex]
Note:
The given question is incomplete that's why we defined the question in the attached file and then solve it.
Find out more information about the arc of the circle here:
brainly.com/question/1577784
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Answers
Answer:
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2. 32
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Practising and Applying
1. Find the lowest common multiple of
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Multiples of 20:
20, 40, 60, 80, 100, 120, 140, 160, 180
Multiples of 28:
28, 56, 84, 112, 140, 168, 196
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Multiples of 4:
4, 8, 12, 16, 20, 24, 28, 32, 36, 40
Multiples of 8:
8, 16, 24, 32, 40, 48
Multiples of 32:
32, 64, 96
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Multiples of 57:
57, 114, 171, 228
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Multiples of 12:
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Multiples of 22:
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Answers
Answer:
15 is a
Step-by-step explanation:
Parallelogram A B C D is shown. Sides A B and D C are parallel, and sides A D and B C are parallel. Angle C is (3 y + 27) degrees and angle A is (5 y minus 3) degrees. What is the measure of ∠A? ° What is the measure of ∠B? ° What is the length of segment EF? units
Answers
Answer:
m<A = 72 degrees
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Step-by-step explanation:
For the parallelogram ABCD
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y = 15
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m<A = 5y - 3
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From the equation above;
m<B = 180 - m<A
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$2,310
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$672.00
c
$558.38
d
$669.30
Answers
Answer:
The amount in the account after 3 years is $672.00
Step-by-step explanation:
Here, we want to use the compound interest formula
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n is the number of times interest is compounded yearly (since it is annually, n = 1)
t is the time in years = 3
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A = 600(1 + 0.0385/1)^(3 * 1)
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Step-by-step explanation:
Beast_Building on yt
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= 8 pints / 15
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Answers
Answer:
Wait no I apologize. This is the right one.
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