If I have 2(2.5)³, is it 2.5 to the power of 3? Or is it 2 to the power of 3?​

Answer: Observational study

Step-by-step explanation:

The study illustrated in the question is an observational study. It is referred to as an observational study, because in this case, the price of the individual cereals us not being controlled by the students. They've no control over it.

If it was an experiment, there'll have been a control group and the students will have control over the price. Also, the sampling methods used here is a systematic random sampling.

Answer: 27 gallons

Step-by-step explanation:

Since the car can go 35½ miles in 1½ miles gallons, we need to first calculate the number of miles that the car can go in 1 gallon. This will be:

= 35½ / 1½

= 71/2 / 3/2

= 71/2 × 2/3

= 23⅔ miles per gallon.

Therefore, the amount of gallons that the car need to go 639 miles will be:

= 639 / 23⅔

= 639 ÷ 71/3

= 639 × 3/71

= 27

The car will need 27 gallons.

5x = 7x - 8

7x - 5x = 8

2x = 8

x = 8 ÷ 2

x = 4

Answer:

Step-by-step explanation:

The correct answer is Always

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(1 vote)

1

the correct answer was never. I appreciate your answer though.

.............................................................................................................................................................

P(A and B) means add A and B

if both A and B are both greater then 1/2

then when they are added they will always be greater than 1

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the correct answer was never. I appreciate your answer though.

Answer:The correct answer is Always

Answer:

3

Step-by-step explanation:

(4+y+9+5+2+7)/6=5

(27+y)/6=5

Y=3

The 90% confidence lower bound for u is:  u>4.066

To find the confidence intervals for the true shear strength u, we will use the sample mean, sample standard deviation, and the given sample size.

a. Two-Sided 90% Confidence Interval for u:

The formula for the confidence interval is given by:

x' = z × s/√n  < u <  x' +z × s/√n

Where:

x' is the sample mean (given as 4.25)

s is the sample standard deviation (given as 1.30)

n is the sample size (given as 78)

z is the z-score corresponding to the desired confidence level (90% confidence level has z-score of 1.645)

Plugging in the values and simplifying:

4.25 - 0.184 < u < 4.25 + 0.184

Therefore, the 2-sided 90% confidence interval for u is:

4.066 < u < 4.434

b. 90% Confidence Lower Bound for u:

The formula for the confidence interval lower bound is given by:

x' - z × s/√n < u

Plugging and simplifying the values we get:

Simplifying the expression:

4.25 - 0.184 < u

Therefore, the 90% confidence lower bound for u is:

u > 4.066

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Answer:

I don't know

Step-by-step explanation:

I don't know

Answer:

-2.15

Step-by-step explanation:

Plug it into the calculator and it should give you the same answer.

Answer:

The answer is -2.15.

Step-by-step explanation:

Hope this helped Mark BRAINLIEST!!!

Answer:

-3, -4, -4, 0, 16, 64, 192.

Step-by-step explanation:

I don't know for sure if this is correct, but when i did it theses are the answers i got. You do y=8*2^x. Meaning you substitute the x for the x values such as -3, -2, and -1.  

Also if you have one there's a setting you can go to on an actual calculator and type in this on a Y/X chart. I didn't use one this time because i don't have one, but thought you'd find that information useful.

Answer:

the answer is 4

Step-by-step explanation:

Answer: 13

Step-by-step explanation: the square root is 12.68925

so i rounded up to 13

Answer:

12.6885775404 or 13 if you need to round up

Step-by-step explanation:

Answer:

Function 1 has the greatest rate of change.

Step-by-step explanation:

The rate of change is also known as the slope.

Slope is rise over run: change in y over change in x.

Function 1's slope: 3 / 2

Function 2's slope: (0 - (-4)) / (5 - (-5)) = 4/10 = 2/5

3/2 > 2/5

Function 1 has the greatest rate of change.

The value of ∭E (x² + y²) dv over the region E between the given spheres.

To evaluate the integral ∭E (x² + y²) dv using spherical coordinates, we first need to express the volume element dv in terms of spherical coordinates.

In spherical coordinates, the volume element is given by dv = r² sin(φ) dr dφ dθ, where r represents the radial distance, φ represents the polar angle, and θ represents the azimuthal angle.

Since we are integrating over the region E between the spheres x² + y² + z² = 9 and x² + y² + z² = 16, the limits of integration for r, φ, and θ will be as follows:

r: from the lower sphere to the upper sphere, which corresponds to r = 3 to r = 4

φ: from 0 to π (since we are considering the entire range of polar angle)

θ: from 0 to 2π (since we are considering the entire range of azimuthal angle)

Now, let's substitute these values and evaluate the integral:

∭E (x² + y²) dv = ∭E (r² sin(φ) cos²(θ) + r² sin(φ) sin²(θ)) dr dφ dθ

Integrating over θ from 0 to 2π, and integrating over φ from 0 to π, we have:

∭E (x² + y²) dv = ∫[0,2π] ∫[0,π] ∫[3,4] (r² sin(φ) cos²(θ) + r² sin(φ) sin²(θ)) dr dφ dθ

Now, we can evaluate the integral by performing the integration step by step, starting from the innermost integral.

After evaluating the integral, the final result will give us the value of ∭E (x² + y²) dv over the region E between the given spheres.

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I + J is an ideal of R because it satisfies closure under addition and absorption of elements from R.

To show that I + J is an ideal of R, we need to verify two conditions: closure under addition and absorption of elements from R.

Let x, y ∈ I + J. This means that x = a + b and y = c + d, where a ∈ I, b ∈ J, c ∈ I, and d ∈ J. We have:

  x + y = (a + b) + (c + d) = (a + c) + (b + d)

  Since a + c ∈ I and b + d ∈ J (as I and J are ideals), (a + c) + (b + d) ∈ I + J. Therefore, I + J is closed under addition.

Let r ∈ R and x ∈ I + J. This means that x = a + b, where a ∈ I and b ∈ J. We have:

  rx = r(a + b) = ra + rb

  Since ra ∈ I (as I is an ideal) and rb ∈ J (as J is an ideal), ra + rb ∈ I + J. Therefore, I + J absorbs elements from R.

Hence, we have shown that I + J satisfies the conditions of being an ideal of R.

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Hey there!

ASSUMING

2(3r + 4) - 3 (r + 1) = 11

IF SO

2(3r + 4) - 3 (r + 1) = 11

2(3r + 4) - 3 (1r + 1) = 11

DISTRIBUTE

2(3r) + 2(4) - 3(1r) - 1(1) = 11

6r + 8 - 3r - 1 = 11

COMBINE the LIKE TERMS

(6r - 3r) + (8 - 3) = 11

6r - 3r + 8 - 3 = 11

3r + 5 = 11

SUBTRACT 5 to BOTH SIDES

3r + 5 - 5 = 11 - 5

SIMPLIFY!

3r = 11 - 5

3r = 6

DIVIDE 3 to BOTH SIDES
3r/3 = 6/3

SIMPLIFY!

r = 6/3

r = 2

Therefore, the answer should be: r = 2

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

=8x+4

Step-by-step explanation:

=2(4x+2)

a=2,b=4x,c=2

=2 x 4x + 2 x 2

Simplify- 2 x 4x + 2 x 2: 8x + 4

Answer:

5x+3=23

Step-by-step explanation:

Answer:

$4 per smoothie

Step-by-step explanation:

5x+4=23

Answer:

f(x) was translated to the left by 5 units to form g(x)

Step-by-step explanation:

Given the function f(x) = x to g(x)=x-5, if you look at the g(x) function, you will see that 5 was subtracted from the abscissa x that is;

g(x) = f(x) - 5

This shows' that the function f(x) was translated to the left by 5 units to form g(x). This described the required translation

Increasingly, developers are using tools that can quickly create screen mockups, referred to as element Wireframes

Wireframes is a type of tool which is allow designers to quickly and effectively mock up an outline of a design as easily as possible. Designers easily drag the images and drop to placeholder images , header and content also.

There are three types of wireframes, which is very useful :

Wireframes generally is used for visual designer, developer, business analysts, user experience designers and information architecture and user research.

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By plugging in the values of x and y obtained from the linear programming solution, we can calculate the unused amounts of sugar, flour, and time.

To determine the number of grape and apple pies that will maximize revenues, we can use linear programming. Let's set up the problem:

Let x be the number of apple pies produced.

Let y be the number of grape pies produced.

Objective function:

Maximize Revenue = 4.50x + 3.60y

Constraints:

1.5x + 2y ≤ 2100 (sugar constraint)

3x + 3y ≤ 3000 (flour constraint)

6x + 3y ≤ 60*60 (time constraint, converting hours to minutes)

The problem can be solved using linear programming software or a graphing calculator. The optimal values for x and y will provide the number of apple and grape pies that maximize revenue.

Regarding part b, to determine the amounts of sugar, flour, and time that will be unused, we can compare the amount used with the amount available.

Unused Sugar = 2100 - (1.5x + 2y)

Unused Flour = 3000 - (3x + 3y)

Unused Time = (60*60) - (6x + 3y)

By plugging in the values of x and y obtained from the linear programming solution, we can calculate the unused amounts of sugar, flour, and time. Remember to round the final answers to the nearest whole number.

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Answer:

Length of window = 9 inch

Width of window = 7 inch

Step-by-step explanation:

Given;

Area of window and frame = 195 inch²

Frame width = 3 inch

Length of window = x + 2

Width of window = x

Find:

Value of x

Computation:

Length of window and frame = x + 2 + 3 + 3

Length of window and frame = x + 8

Width of window and frame = x + 3 + 3

Width of window and frame = x + 6

Area of window and frame = (l)(b)

(x + 8)(x + 6) = 195

x² + 6x + 8x + (8)(6) = 195

x² + 14x + 48 = 195

x² + 14x - 147 = 0

x² + 21x - 7x - 147 = 0

x(x + 21) - 7(x + 21) = 0

So,

x + 21 = 0 and x - 7 = 0

So,

X = 7

Value of x = 7

Length of window = 9 inch

Width of window = 7 inch

2(19-7) im pretty sure

a) Variables strongly/weakly positively/negatively correlated in the "airquality" data set can be identified through correlation analysis.

b) The t-test can be used to check if the temperature variable in the "airquality" data set is significantly different from 79.

c) The t-test can be used to check if the temperature variable is significantly different between samples A and B (observations 1 to 77 and 78 to 153, respectively) in the "airquality" data set.

a) To identify variables that are strongly/weakly positively/negatively correlated in the "airquality" data set, correlation analysis can be performed.

Correlation analysis measures the strength and direction of the linear relationship between variables.

By calculating correlation coefficients (such as Pearson's correlation coefficient), it is possible to determine if variables have a strong positive correlation (close to +1), weak positive correlation (between 0 and +1), strong negative correlation (close to -1), or weak negative correlation (between 0 and -1).

This analysis helps identify the nature of the relationships between variables in the dataset.

b) To check if the temperature variable in the "airquality" data set is significantly different from 79, a t-test can be conducted.

The t-test assesses whether the mean of a sample is significantly different from a hypothesized value (in this case, 79).

By comparing the t-statistic calculated from the sample data to the critical t-value at a given significance level, such as 0.05, it can be determined if the temperature is significantly different from 79.

If the calculated t-value falls outside the critical t-value range, the temperature variable is considered to be significantly different.

c) To check if the temperature variable is significantly different between samples A (observations 1 to 77) and B (observations 78 to 153) in the "airquality" data set, a t-test can also be used.

This comparison aims to determine if the means of temperature in samples A and B are significantly different.

By calculating the t-statistic and comparing it to the critical t-value at a chosen significance level, such as 0.05, it can be determined if the temperature variable differs significantly between the two samples.

If the calculated t-value falls outside the critical t-value range, it indicates a significant difference in temperature between samples A and B.

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A child who is 44.39 inches tall is one standard deviation above the mean. Approximately 50.58% of children are between 41.25 and 44.29 inches tall.

To find the percentage of children between 41.25 and 44.29 inches tall, we need to calculate the area under the normal distribution curve within this range.

Given that the child's height of 44.39 inches is one standard deviation above the mean, we can infer that the mean height is 44.39 - 1 = 43.39 inches.

Next, we need to determine the standard deviation. Since the child's height of 44.39 inches is one standard deviation above the mean, we know that the difference between the mean and 41.25 inches is also one standard deviation.

Let's denote the standard deviation as σ. We have:

43.39 - 41.25 = σ

Simplifying the equation:

σ = 2.14

Now, we can calculate the percentage of children between 41.25 and 44.29 inches tall using the z-scores.

The z-score formula is given by:

z = (x - μ) / σ

For the lower bound, x = 41.25 inches:

z₁ = (41.25 - 43.39) / 2.14 = -0.997

For the upper bound, x = 44.29 inches:

z₂ = (44.29 - 43.39) / 2.14 = 0.421

We need to find the area under the normal distribution curve between z₁ and z₂. Using a standard normal distribution table or a calculator, we can find the corresponding probabilities.

Let P₁ be the probability associated with z₁, and P₂ be the probability associated with z₂. Then, the percentage of children between 41.25 and 44.29 inches tall is given by:

Percentage = (P₂ - P₁) * 100

Using the z-score table or a calculator, we find that P₁ ≈ 0.1587 and P₂ ≈ 0.6645.

Substituting these values into the formula:

Percentage = (0.6645 - 0.1587) * 100 ≈ 50.58%

Therefore, approximately 50.58% of children are between 41.25 and 44.29 inches tall.

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To determine whether the boxplot represents the information given in the histogram, we need to examine the characteristics of both the boxplot and the histogram.

The boxplot provides a visual representation of the distribution of a dataset, showing the minimum, first quartile, median, third quartile, and maximum values. It also displays any outliers that may be present. On the other hand, a histogram provides a graphical representation of the frequency or count of data values within specified intervals or bins.

Without specific information or visuals of the boxplot and histogram in question, it is not possible to directly compare them and determine their compatibility. Therefore, it is not possible to answer the question based on the information provided.

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The properties of the Fourier transform stated in (1) and (2) are incorrect.

The properties of the Fourier transform stated in (1) and (2) are incorrect.

Let's examine each property:

(1) (Fu)(E) = 27 (F-\u) (-):

The expression on the left side, (Fu)(E), represents the Fourier transform of a function u evaluated at frequency E.

However, the expression on the right side, 27 (F-\u) (-), is not a valid representation of the Fourier transform.

The notation (F-\u) (-) is unclear and does not align with the standard conventions of the Fourier transform.

(2) (F(t,0))(E) - (FU)(8 + a):

Similarly, the expression on the left side, (F(t,0))(E), suggests the Fourier transform of a function F evaluated at time t and frequency E.

However, the subtraction of (FU)(8 + a) is not a well-defined operation in the context of the Fourier transform. The relationship between F(t,0) and FU is not clear, and the addition of 8 + a lacks proper justification.

Therefore, both properties (1) and (2) provided for the Fourier transform are inaccurate.

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Answer:

3

Step-by-step explanation:

-(-5) -2

5 - 2

3

Answer:

-7

Step-by-step explanation:

Hope this helps

Answer:

Distance= 15.3

Step-by-step explanation:

The surface area of the right prism cone is,

⇒ 1960 units²

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

A right prism shown in image.

Now, We get;

Base area of cone = 14 x 10

                            = 140

And, Height of cone = 6

And, Perimeter of the base = 2 (10 + 14)

                                           = 280

Thus, WE know that;

The surface area of the right prism cone is,

⇒ 2B + hP

⇒ 2 × 140 + 6 × 280

⇒ 280 + 6 × 280

⇒ 280 + 1680

⇒ 1960 units²

Thus, The surface area of the right prism cone is,

⇒ 1960 units²

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