if highest high tide occurs at 2pm on day 1, at what time of day will the next highest high tide occur?

Using the concepts of momentum, we got that 150i-60j is the momentum vector and 162.3Kg-m/sec is the magnitude of the momentum of a 30 kg object.

We know very well that momentum is given by the product of mass and velocity of the object.

In other words P=M. v

But, here velocity is given in 2-D form, means momentum is possible in two different directions.

Therefore, for momentum we just need to multiply the mass of the object with velocity

=>Momentum of the object=M×(5i-2j)

=>                                       p=30×(5i-2j)

=>                                       p=150i-60j

Now, talking about the magnitude we know that magnitude is given by

√(x-component)² + (y-component)²

Therefore, magnitude of momentum (|p|)=√(150)²+(--60)²

=>                                                     |p|=√22500+3600

=>                                                     |p|=√26100

=>                                                     |p|=162.3Kg-m/sec

Hence, for  30 kg object is moving along with the velocity given, the momentum vector is 150i-60j, as well as the magnitude of the momentum for v=5i-2j is 162.3kg-m/sec.

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14 m is the displacement for a trip from the math classroom in Figure 2.4 to the music classroom and then to the library

Displacement= final position-initial position

Displacement=14m-0

Displacement=14m

distance= total route= 14m

Distance is all covered distance but displacement is shortest distance. Being a vector quantity, displacement has both a magnitude and a direction. The vector (or straight line) distance between an initial and final position is what is meant by this term. Knowing these two places is consequently all that is necessary to determine the resultant displacement.

Calculate the inverse tangent of the ratio of the displacement components in the y- and x-directions to determine the direction of the displacement vector.

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The volume of the gas at the given conditions will be 26.6 ML.

By Ideal Gas Law we know that

[tex]\frac{P1 V1}{T1}[/tex] = [tex]\frac{P2 V2}{T2}[/tex]

In the given question here, P1 = 10 Kg ; V1 = 80 ML ; T1 = 30 ; P2 = 20 Kg ; T2 = 20 Substituting the values in the equation

[tex]\frac{10 X 80}{30\\}[/tex] = [tex]\frac{20 V2}{20}[/tex]

[tex]\frac{80}{3}[/tex] = V2

V2 = 26.6 ML .

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The velocity of the bowling ball is 4 m/s when mass of the bowling ball is 3.5 kg and  momentum given is 14kgm/s.

As we know that,

Momentum= Mass* Velocity

p=mv

Here, Mass of the Bowling Ball(m)= 3.5 Kg

Momentum(p)= 14kgm/s

Velocity= Momentum/Mass

=14/3.5 = 4m/s

The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum since its mass is in motion. The quantity of motion and the speed of the motion are the two factors that determine how much momentum an item possesses. The factors mass and velocity affect momentum. According to an equation, an object's momentum is determined by multiplying its mass by its velocity.

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To answer this question, we need to use the formula for momentum, which is:

momentum = mass * velocity

We can rearrange this formula to solve for velocity, which is:

velocity = momentum/mass

We are given the momentum and the mass of the bowling ball, so we can plug them into the formula:

velocity = 14 / 3.5

We can simplify this expression by dividing both numbers by 0.5:

velocity = 28 / 7

We can convert this fraction into a decimal by dividing the numerator by the denominator:

velocity = 4

Therefore, the bowling ball is travelling at 4 m/s.

The wavelength of UV radiation is longer than that of x-rays and gamma rays but shorter than that of radio waves, microwaves, infrared, and visible light.

The frequency of UV radiation is higher than that of radio waves, microwaves, infrared light, and visible light, but it is lower than that of x-rays and gamma rays.

UV radiation has a lower level of hazard.

Wavelength:

Distance between the crests of two waves, or from one wave's point to the same of the second.  

Frequency:

Wavelength and frequency are inversely proportional, the larger the wavelength the lesser the frequency

Energy: The relationship between frequency and energy is straightforward.

From longest to shortest wavelengths, this is a list of electromagnetic waves.

Radio wave, Microwave, Infrared, Access to light, Ultraviolet rays, X-ray, Gamma rays

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The value of work done on an object when a 70-newton moves it 9.0m in the same direction as the force is 6.3 * 10^2 J

In physics, it measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. In its simplest form, for a constant force aligned with the direction of motion, it equals the product of the force strength and the distance traveled.

How to calculate the value of work done on an object?

The formula for work (w) done is = force * distance

f = 70 N

d = 9 m

w = 70 × 9m

w = 630 J = 6 × 10² J

work is positive because work is being done on the object.

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center of mass of a solid hemisphere of radius R is 3R / 8 and the Mass of the solid is M.

An elemental disc at a height of h from the base of the hemisphere is taken.

The mass of the elemental disc is taken dM

and the width is taken dy.

et the solid hemisphere be of mass M and has the radius R.

The center of mass will lie vertically which passes through the center of the hemisphere.

Taking the elemental disc at a height h from the base of the hemisphere’s base. The DM is the mass of the elemental disc and the width is dy.

the radius of the disc is:

R = R²- y²

Mass of the disc dM

= (3 M/ 2π R³) × ( πr² dy )                                   …..(2)

eq.(1)   in    eq.(2)..................

 dM = ( 3M  /  2 π  R³ ) ×  π (  R²  –   y²  )   dy)

Y - coordinate  of Centre of mass,

 Yc  =   (1 / M)  ഽ y  dM

Here y is the y - coordinate representing the height of the elemental disc from the base.

Putting the dM and calculating the center of mass, we get

yc= (1/M) ഽ  y(3M  /2 R^3) × ( R^2  -  y^2) dy)

Integrating between    0⟶R

yc = (1/M)   ഽ y  (3M / 2 R^3) × (R^2  -  y^2) dy)

yc = (  3/2r^3  )  ഽ × (R^3 y-  y^3 ) dy

   = (  3/  2R2)[ (R4 / 2 ) – ( R4 /  4)] = 3R / 8

yc =  3 R /8

Centre of Mass of solid hemisphere (yc) = 3 R / 8.

Mass of solid  =  M

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The velocity of the ball is obtained as  6.26 m/s.

We know that the kinetic energy is the energy that is possessed by a body by virtue of the fact that it is in motion while the potential energy is the energy that is possessed by a body that is at rest.

Now we have that;

Mass of the ball = 350g or 0.35 Kg

Height of the ball =  12m

The energy of the ball at this height is potential energy. The total energy before the ball hits the ground is; 0.35 * 12 * 9.8 m/s^2 = 41.2 J and this energy is kinetic energy.

If the ball is 2m above the ground its potential energy is 2 * 2 * 9.8 m/s^2 = 39.2 m/s and the kinetic energy of the ball is zero m/s.

The velocity with which the ball hits the ground is;

mgh = 1/2mv^2

gh = 1/2v^2

v = √2gh

v = √2 * 9.8 * 2

v = 6.26 m/s

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The kinetic energy of an object will be halved when the mass is cut in half.

Kinetic energy may be described as the energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.

Kinetic energy (KE) is the energy that moves matter. Everything that moves has kinetic energy. The amount of kinetic energy of a moving object is directly related to its mass and velocity.

KE = 1/2 mass × velocity²

For the given question:

Since,

KE = ¹/₂ mv²

If mass is cut in half i.e m/2, then the KE will be:

KE = ¹/₂ m/2 v²

KE = ¹/₄ mv²

KE =  ¹/₂ (¹/₂ m/2 v²)

This indicates that kinetic energy is halved as the mass is cut in half.

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Yes, the force that will stretch is rights to the breaking point equal to 5000 N. Because the longer wire will аlso breаk аt 5000 N. The force per unit аreа is the sаme in both cаses.

When а stress is аpplied to а piece of mаteriаl, the mаteriаl undergoes а corresponding deformаtion or strаin. Under а tensile stress, the mаteriаl stretches. Initiаlly, the аmount by which it stretches is proportionаl to the аpplied force. Thаt is, the mаteriаl obeys Hooke’s Lаw, which is expressed by the equаtion F = -kx, where k is а constаnt аnd x is the chаnge in the length of the mаteriаl.

Your question is incomplete, but most probably your full question was

A wire is stretched right to the breaking point by a 5000 N force. A longer wire made of the same material has the same diameter. Is the force that will stretch it right to the breaking point larger than, smaller than, or equal to 5000 N?

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The flow speed in the wider section of horizontal pipe is 3 m/s

Based on the Law of Continuity which states that a flowing fluid will have a constant discharge, where this discharge has a formula:

Q = A × v

where

Q = fluid discharge (m³/s)

A = pipe area (m²/s)

v =  fluid speed (m/s)

From that formula, we can solve the problem by the formula of Q1 = Q2, here it is

A1 x v1 = A2 x v2

(π · r²) x 12 = (π · (2r)²) x v2

r² x 12 = (4) r² x v2

v2 = 12/4 m/s

v2 = 3 m/s

v2 is the speed from the pipe section that widens to twice from its original radius.

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D is the correct response because, although the car's speed won't change, its direction of travel will.

The car's acceleration is zero because it is driving at a constant speed of 20 meters per second. A further definition of force is the sum of mass and acceleration. Additionally, because there is no acceleration, there is no net force acting on the vehicle. For instance, the car might be round a corner at a steady speed. The speed will remain the same, but the car will change the direction it is moving.

The complete question is- car is travelling north at a constant speed of 20 m/s. A force is applied directly east on the car. The motion of the car will be change in which of these ways? A) The speed of the car will increase. B) The speed of the car will decrease. C) The speed will increase, and the car will change the direction it is moving. D) The speed will remain the same, but the car will change the direction it is moving.

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Ignoring the Friction, the Acceleration of the block would be 2 [tex]ms^{-2}[/tex].

The relation of force with mass and acceleration is given by :

Force = Mass  *  Acceleration

Here the Force is 10N and the mass of the block is 5 Kg so substituting the values in the formula we get

Acceleration =  [tex]\frac{Force}{Mass}[/tex]  =  [tex]\frac{10}{5}[/tex] = 2 [tex]ms^{-2}[/tex] .

What is force-

According to physics. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P).

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An experiment that I could do to measure the horsepower I could develop for a long period of time can be "Riding a bike over a straight path".

What is horsepower?

Horsepower can be defined as the unit of measurement of power, or the rate at which work is done. There are many different standards and types of horsepower. In order to calculate horse power we will use the following method ;

The term Horsepower was invented by James Watt. It is a unit power that compares the power of a machine to the horse muscle power, steam engine power output compared to the power of draft horses. Now it is used in piston engines, electric motors, turbines and other machinery.

One Horsepower equals to 33,000 lb. ft/min.

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Answer:

0.0003945 kg / m6

Explanation:

Answer:

c) It has more nitrogen than oxygen.

Explanation:

Our Earth’s atmosphere has more nitrogen (78%) than oxygen (21%). Hence, the option (c) is the correct answer.

Answer:

C. It has more nitrogen than oxygen.

Explanation:

Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases. These gases are found in layers (troposphere, stratosphere, mesosphere, thermosphere, and exosphere).

Magnitude of the car's acceleration is 3.5 m/s²

Given:

Mass of car = 1,000 kg

Net force applied by car = 3,500 N

How to find the acceleration of the car?

Formula:

Net force = Mass × Acceleration

So,

3,500 = 1,000 × Acceleration

Acceleration = 3,500 / 1,000

Acceleration = 3.5 m/s²

Therefore, the acceleration found from the formula is 3.5 m/s².

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Answer:

a) 20.65kg

b)4.7rad

Explanation:

A push or pull on an object is a force. All of the forces operating on an object are added together to form a net force. When an object is subject to a net force, the object will change its speed in that direction. The acceleration of an object reveals how much it accelerates or decelerates.

We can determine what occurs with the acceleration and force while maintaining the mass constant.

A connection between the mass of the cart and its acceleration. Taking into consideration Newton's second law, which states that

force = mass × acceleration

As a result, the force will change if the acceleration does. Keeping the mass constant will allow us to determine how changing the acceleration will affect the force. Once the mass is kept constant, you can determine what will happen. Therefore, if we want to maintain the acceleration constant while also changing, we must alter the mass of the car. This means adding mass to the cart—whether it be in the form of mass blocks or larger carts—or otherwise altering its mass.

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which best describes the field of physics the study of matter and energy

physics, science that deals with the structure of matter and the interactions between the elemental constituents of the observable universe. the scope of study envelops not as it were the conduct of objects beneath the activity of given forces but the nature and root of gravitational, electromagnetic, and nuclear force fields. In simple words, physics is characterized as the science of matter, movement, and energy. Its laws are regularly expressed with economy and accuracy within the language of science.

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image is formed at a distance 10 cm in front of the mirror

the focal length of concave mirror is 8cm.

What is concave mirror ?

A concave or converging mirror has a reflective surface that is recessed inward (away from the incident light). A concave mirror reflects light inwards towards a focal point. They are used to focus light. Unlike convex mirrors, concave mirrors display different types of images depending on the distance between the object and the mirror.

The mirror is called a "collecting mirror". This is because they tend to collect the light that hits the mirror and refocus the parallel incident rays to a focal point. This is because the normal to the mirror surface is different at each point, so light is reflected at different angles at different points on the mirror.

Given u=40 cm (negative)

m=14 (negative for the real image)

a. From m=−vu,−14=−v(−40) or v=-10 cm

Thus the image is formed at a distance 10 cm in front of the mirror.

b. Now from relation 1u+1v=1f

1f=1(−40)+1(−10)

=−540

or f=−405=−8cm

i.e., the focal length of concave mirror is 8cm.

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100 watt light bulb glows brighter than a 50 watt light bulb and  50 watt light bulb is higher resistance than 100 watt bulb.

A circuit's opposition to current flow is measured by its resistance. Resistance is the degree to which a substance obstructs or opposes an electric current. Electron flow is referred to as electric current. To better understand resistance, imagine how difficult it would be for a person to move from one shop to another in a crowded market. Resistors are used in heaters, toasters, microwaves, electric stoves, and a variety of other heating appliances due to their inherent ability to generate heat when conducting current. When electricity is passed through a metal filament in a light bulb, a very high temperature is created from the resistance, which causes the metal filament to glow white-hot. The ohm (), which represents resistance, is denoted by the letter R.

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As a shot putter in track,  if you want to throw far then throw it fast and at angle approximately 45 degrees.

As a thrower spins, his body acts as an axis of rotation and therefore, farther the object is from the axis of rotation, larger is its moment of inertia.

The angle of release in the shot-put event is of great importance. The estimation of the optimum angle of release such that the distance thrown is maximized is a  key. Theory has shown that the optimum angle of release is between 41 to 43 degrees.

Release velocity is also a important factor in determining the distance of a throw. Release velocities of about 13 m/s are necessary for elite-level throws.

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With the use of equation of motion formulas, the time taken for him to fall is 0.64 s and his final velocity when hitting the floor is 6.3 m/s

The motion of an object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

Given that a man falls 2.0 m to the floor and it is assumed that downward direction to be the negative direction.

To know how long it will take the object to fall, we will make use of the formula h = ut + 1/2gt²

Where

Substitute all the parameters into the formula

2 = 1/2 × 9.8 × t²

2 = 4.9t²

t² = 2/4.9

t² = 0.408

t = √0.408

t = 0.64 s

His velocity when he hits the floor can be calculated by using the formula

v = u + gt

where u = 0

v = 9.8 × 0.64

v = 6.3 m/s

Therefore, it takes 0.64 s to fall and his velocity when he hits the floor is 6.3 m/s

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Answer:   ACCELARATION  = 0.462M/S²

Explanation: INITIAL VELOCITY (VI) = 8M/S

                      DISTANCE COVERED (S) = 744M

                         TIME (t) = 42 S

                     ACCELERATION (A)= ?

       BY APPLYING 2ND EQUATION OF MOTION

              S = VIT +1/2 AT²

            744 = 8 X 42 +1/2 A X42²

            744 - 336 = 1/2 A X 42²

               408 X 2/1764 = A

           A = 816 /1764

A = 0.462M/S²

The mass of the block on the frictionless horizontal surface is 5 kg.

The mass of the block is determined by applying Newton's second law of motion:

F = ma

The given parameters are

the magnitude of the first force, F₁ = 12 N

the magnitude of the second force, F₂ = 2 N

acceleration of the block, a = 2 m/s²

So, determining the mass of the block is

F = ma

∑F = ma

F₁ - F₂ = ma

12 - 2 = 2m

10 = 2m

m = 5 kg

Thus, the mass of the block on the frictionless horizontal surface is 5 kg.

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Using induced emf inside the magnetic field which is Faraday’s Law of Induction, we can calculate the number of turns a coil wrapped around the outside of the solenoid should have is 127 turns to induce 15v.

According to the Faraday’s Law of Induction, Faraday's law of induction is a basic law of electromagnetism predicting how a magnetic field will interact with an electric circuit to produce an electromotive force (emf) a phenomenon known as electromagnetic induction.

Induced emf = N ( dФ / dt )

where, N is the number of coil

and dФ is the change in magnetic flux

again, as we know,

dФ / dt  =  A (db/dt)

so, Induced emf = N A ( db/dt )

where A is the area of solenoid

Area of solenoid = πr² = π * ( 0.125 )²    (diameter is 25cm)

putting the appropriate values, we get

15 = N x π x ( 0.125 )² x 2.4

N = [tex]\frac{15}{\pi * 0.015625 * 2.4}[/tex]

N = 15/0.11775

N = 127.38

N = 127 turns

hence 127 turns is needed to generate 15 v emf.

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The correct answer of mass of the block is 16.379 Kg.

How is energy conserved in a spring?

The mass's kinetic energy is converted into elastic potential energy as the spring contracts and it slows down. The complete amount of mechanical energy is conserved throughout this transformation.

Energy is conserved for the block-spring system between the maximum-displacement and the half-maximum points:

(K+U)i=(K+U)f

0+1/2  kA²=1/2 mv²+1/2 kx²

0.5 (3.3 N/m) (0.058 m) ²=1/2 m (0.26 m/s) ²+1/2(3.3 N/m) (2.90×10−² m) ²

=> 0.555 = 0.0338 m + 0.00138

=>   mass = (0.555 – 0.00138) / 0.0338 = 16.379 Kg                  

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0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m

A periodic variable's amplitude is a gauge of its change over a single period. A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several ways to define amplitude, and they are all dependent on how much the extreme values of the variable deviate from one another.

The stiffness of the spring is how we determine spring constant. In other words, we can define the spring constant as the force used to produce the specified displacement when the spring's displacement is one unit. It follows that a spring's spring constant will increase with increasing spring stiffness.

Now to calculate the work done by spring we use the Hookes’s law

F=kx

Where F is the force required

K is the spring constant

X is the amplitude or distance

So F=kx

F=180x0.02

F=3.6 N

Now to calculate work :

Work = Force × Distance.

Work=3.6 N x0.02m

Work =0.072 J

Hence, 0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m

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