If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be​

Answers

Answer 1

Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

Pressure is related to Force, Volume and Density thus :

[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]

Using dimensional analysis :

Pressure, P = ML¯¹T¯²

Substituting the dimension into the relation :

[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]

[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

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Answer 2

The representation of pressure is:

[tex]P=FV^{-\frac{2}{3} }[/tex]

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]

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Related Questions

The Earth system is an example of a(n)

Answers

Dynamic system meaning a combination of interrelated, interdependent or interacting parts forming a collective whole or entity. On a macro level, the Earth system maintains its existence and functions as a whole through the interactions of its parts

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Answers

Answer:

I'm pretty sure it's false

Explanation:

.

Question 1 of 11
The book has a mass of 2.5 kg.
What net force must act on the book to make it accelerate to the left at a rate
of 7.0 m/s2? (Hint: Use F = ma.)
O A. F = 17.5 N right
OB. F = 2.8 N right
O C. F = 2.8 N left
O D. F = 17.5 N left

Answers

Answer:

D. F= 17.5 N left

Explanation:

I just took the quiz and got it correct!

A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The block accelerates to the right and is moving with speed v once it has moved a distance d. Which of the following equations can be used to solve for the force of friction exerted on the block by the surface?

Answers

The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d

The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.

Therefore,

using Newtons third law

F - f = ma

a = v/t

t = d/v

F - f = m × v / t

F- f = m × [tex]\frac{v}{\frac{d}{v} }[/tex]

F- f = m × v²/d

Therefore,

F- f = mv² / d

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1. How much heat is released when a 25 g sample of water (c = 4.184) is cooled from 99 °C
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Answers

you use the following formula Q=mc(T-T) and Q=25x4.184x(75-99) and the final answer is approximately 2500j is lost

What is the net force on a 4,000-kg car
that doubles its velocity from 15 m/s west
to 30 m/s west over 10 seconds?

Answers

Answer:

6000 N toward west

Explanation:

F = ma

a = 30-15/10 = 1.5 m/s^2 towards west

m = 4000 kg

F = 4000 x 1.5 = 6000 N towards west

sports photographers often use large aperture, long focal length lenses. what limitations do these lenses impose on the photographs?

Answers

Answer:

The depth of focus achievable with those lenses is small.

Explanation:

A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.

Hope this helps!

An object of mass 10 kg is moving along positive x- axis with velocity 5 m/s. At some point it breaks into two parts of 6 kg and 4 kg. 6 kg moves making 600 with x –axis and 4 kg moves making -300 with axis. What is velocity of their centre of mass after breaking?

Answers

Explanation:

Correct option is

B

−3m/s

2

Given,

m=10kg

u=10m/s

v=−2m/s

t=4sec

The acceleration is rate of change of velocity,

a=

t

v−u

a=

4

−2−10

a=

4

−12

=−3m/s

2

The correct option is B.

If you drag a 50kg block across the floor which has a coefficient of friction of .30, what is
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Answers

Answer:

750 Newton

Explanation:

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Answer:

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Explanation:

Waves can be refracted.
Explain this term.


HELP PLSSS

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Answer: By "waves can be refracted" they mean that refraction can occur with waves. To better explain, refraction is the "change in direction of a wave passing from one medium to another or from a gradual change in the medium."  You probably know this best when you put a pencil inside a glass of water where the pencil bends a bit. The same can happen with sound or water waves as well!

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Refraction can happen with waves

Which of the following will require most developed countries to
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Answer:

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Explanation:

If you double the pressure of a constant amount of gas at a constant temperature, what happens to the volume

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Explanation:

Please help! Question is attached!​

Answers

Answer:

1. -6m/s

2. 0m/s

3. 3m/s

4.14.38N

5. 25.9 J

Explanation:

1. point A and C same height means velocity will be the same just in opposite direction,  = -6m/s

2. at max height vertical velocity is 0

3. same as point A

4. Weight is mg = 1.438*10 = 14.38N

5. total energy is KE+PE, which never changes

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Answer:

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Answers

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Explanation:

Answer:

the mass is 2.04

Explanation:

The weight of an object is calculated by: W=Mg

Solving for M:  M=W/9

M=20/9.8 = 2.04

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Answer:

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Answer:

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Answers

Given what we know about the Kepler space program, we know that the astronomers discovered that Earth-sized planets are more common than we imagined.

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The idea behind this launch was to discover more Earth-sized planets, preferably within the habitable zone of their central star.

What this mission showed astronomers, is that Earth-sized planets are more common than we could have imagined, Kepler proved this by finding over 2,662 planets to date.

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A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)
To raise this object's temperature from 15 Celsius to 25 Celsius, the object must absorb _______ Joules of heat.

Answers

The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The amount of heat absorbed by an object can be calculated by using the following expression:

Q = m.c.∆T

Where;

Q = amount of heat absorbed or released (J)m = mass of objectc = specific heat capacity (J/g°C)∆T = change in temperature (°C)

According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:

Q = 2 × 1700 × {25 - 15}

Q = 3400 × 10

Q = 34000J

Therefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

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Answer:

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Explanation:

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Answer:

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Calculate the charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts.

Answers

The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb

Potential difference is the amount of work needed to move a unit charge from one point to another. It is given by:

V = E/Q

Where V is potential difference, E is energy and Q is charge. Given that:

V = 15 V, E = 5.25 kJ = 5.25 * 10³ J.

V = E/Q

15 = 5.25 * 10³ /Q

Q = 350 Coulomb

The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb

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Answer:

It is a physical

Explanation:

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Answers

Answer:

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Explanation:

Answer:

300 watts

lol hoped this helped

:)

helpp I'll give brainliest smth
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Answers

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What symbols are these?

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the bottom one is wollsiegel

State the general purpose of an experiment, using the terms dependent and independent variable

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Answer:

Image result for State the general purpose of an experiment, using the terms dependent and independent variable

You can think of independent and dependent variables in terms of cause and effect: an independent variable is the variable you think is the cause, while a dependent variable is the effect. In an experiment, you manipulate the independent variable and measure the outcome in the dependent variable

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