Answer:
So, at moon g’=1.62 m/s^2
Therefore, mg’=99N (as given , where m is the mass )
so, m=99/1.62 =61.11 kg
hence, weight on earth will be mg( where g is the acceleration due to gravity at earth, 9.8m/s^2)
61.11*9.8=598.878 N will be the weight on earth
Explanation:
hope it helps
A particle that has zero momentum must also have zero kinetic energy.Select one:O TrueO False
The kinetic energy of an object is the energy possessed by the object due to its motion. That is when the velocity of the object is zero, i.e., when the object is at rest, the kinetic energy of the object will be zero.
The linear momentum is the product of the mass and the velocity of an object. When the momentum of the object is zero, the velocity of the object is also zer.
Thus whenever a particle has a zero momentum, its velocity and hence its kinetic energy will also be equal to zero.
Therefore, the given statement is true.
Based on this law, if a collapsing cloud is isolated in space with no external forces, what must happen to it as its size decreases?.
Based on law of conservation of angular momentum if a collapsing cloud is isolated in space with no external forces, the cloud will spin faster, the size will go on decreasing and the angular momentum will go on increasing that is reduction in radius and it will start spinning faster.
What is Nebular Theory?According to the nebular theory, a cloud of gas and dust must gravitationally collapse into a disk in order for planets to form inside. The disk must flatten out to fit observations. what causes this flattening to happen? Take the law of conservation of angular momentum, which states that an amount related to an object's size(its moment of inertia) times the rate at which rotates (angular speed) must always remain constant if no external forces are acting on the object.
Therefore, if a collapsing cloud is isolated in space with no external forces, the cloud will spin faster the size will go on decreasing and the angular momentum will go on increasing that is reduction in radius and it will start spinning faster.
What is law of conservation of angular momentum?Principle of conservation of angular momentum states that, if no external torque acts on a system, the total angular momentum of the system remains constant. If I be the momentum of inertia of a body about a given axis of rotation and w be its angular velocity, then I w= constant
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help please i have a 17 as a grade :)
Given
A 50kg boy
A 100 kg father
Speed (both) 5 m/s
Procedure
Kinetic energy is a form of energy that an object or a particle has by reason of its motion
For the boy
[tex]\begin{gathered} K_b=\frac{1}{2}mv^2 \\ K_b=\frac{1}{2}\cdot50\operatorname{kg}\cdot(5m/s)^2 \\ K_b=625J \end{gathered}[/tex]For the father
[tex]\begin{gathered} K_f=\frac{1}{2}mv^2 \\ K_f=\frac{1}{2}\cdot100\operatorname{kg}\cdot(5m/s)^2 \\ K_f=1250J \end{gathered}[/tex]Now, let's compare the kinetic energy between father and boy
[tex]\begin{gathered} \frac{father^{\prime}s\text{ KE}}{boy^{\prime}s\text{ KE}} \\ \frac{1250J}{625J} \\ \frac{father^{\prime}s\text{ KE}}{boy^{\prime}s\text{ KE}}=2 \end{gathered}[/tex]The father's KE is twice the boy's kinetic energy
Screenshot:
Part 2:
Part 1:
An object starts at rest and experiences a constant acceleration of 4 m/s² for 3 seconds.
Sketch the acceleration-time graph for this object.
1. What was the initial velocity of the object?
2. What was the velocity of the object after 1 second?
3.What was the velocity of the object after 2 seconds?
4.What was the velocity of the object after 3 seconds?
5. Sketch the velocity-time graph for this object.
6. What was the average velocity of the 1st second?
7.What distance did the object travel in the 1st second?
8. What was the average velocity of the 2nd second?
9. What distance did the object travel in the 2nd second?
10.What was the average velocity of the 3rd second?
11. What distance did the object travel in the 3rd second?
12.Sketch the position-time graph for this object.
13.What was the displacement of the object?
14.What was the distance travelled by the object?
For the given acceleration and time, following are the different velocities.
Given:
acceleration a = 4 m/s²
time t = 3 sec
initial velocity u = 0 [ starts from rest ]
let final velocity be = v
Therefore according to the question,
velocity after 1 sec :
v = u + at
v = 0 + 4 x 1
v = 4m/s ( after 1 sec)
Velocity after 2 secs
v = 0 + 4 x 2
v= 8m/s (after 2 sec)
Velocity after 3 secs
v = 0 + 4 x 3
v = 12m/sec
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Determine the cross-sectional area of a copper conductor if its resistance is 0.2 ohm and its mass is 0.2 kg. So:
R=0.2 Ohm, m=0.2 kg, ρ=0.017 m²/m, S=?
The cross-sectional area of a copper conductor if its resistance is 0.2 ohm and its mass is 0.2 kg is 61.7 m²
Considering the conductor is a wire,
Density = m / V
V = A l
ρ = R A / l
m = Mass
V = Volume
l = Height / Length
R = Resistance
ρ = Resistivity
R = 0.2 Ω
m = 0.2 kg
ρ = 0.017 Ω m
Density of copper = 8.96 * 10³ kg / m³
V = 8.96 * 10³ / 0.2
V = 44.8 * 10³ m³
A l = 44.8 * 10³
l = 44.8 * 10³ / A
ρ = R A / l
0.017 = 0.2 A / l
l = 0.2 A / 0.017
Equating both the values of l,
44.8 * 10³ / A = 0.2 A / 0.017
761.6 = 0.2 A²
A² = 3808
A = 61.7 m²
Therefore, the cross-sectional area of a copper conductor is 61.7 m²
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please answer questions 15, 16, and 17 below for a 2m long steel coil spring with a diameter of 2cm in a passenger vehicle is exposed to a force of 2,000 n. if the length of the coil extends elastically to 2.2m upon this force, please calculate
The question is incomplete, however 7.1 X 10^6 N/m^2 is Young's Modulus of 2m long steel coil spring with a diameter of 2cm in a passenger vehicle is exposed to a force of 2,000 N. If the length of the coil extends elastically to 2.2m upon this force.
[tex][Y=Fl\pir^2e],[Y=4000 \cdot2/\pi0.1884/2\pi^2\cdot0.4)][/tex]
Y = 7.1 X 10^6 N/m^2
Young's modulus is a metric for determining how elastic a substance is. The ability of a body to resist attempts to deform it using an external shearing stress is referred to as its elastic property.
The internal force of a material that attempts to return the body to its former shape is known as a restoration force. Young's modulus of elasticity is the proportion of restorative stress generated and strain (deformations such an increase in length per unit length).
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you go out stargazing one night, and someone asks you how far away the brightest star we see in the sky without a telescope are. what would be a good, general response?
The brightest star's name within the nighttime sky is Sirius at value. It is also known as Alpha Canis Majoris and is typically referred to as the canine megastar.
It resides in the constellation of Canis fundamental. Sirius is eight.6 mild years far away from us, close enough to be the brightest superstar in our night skies. When you examine a star, you are looking at the mild that got here from the megastar. due to the fact stars are so far away, it takes years for their mild to reach us. consequently, whilst you take a look at a star, you are surely seeing what it gave the impression of years in the past.
The brightest megastar inside the nighttime sky is the Sirius star. in keeping with NASA, it is over 20 instances brighter than our solar and two times as big, although it may not seem that manner to the bare eye. The maximum commonplace way to measure the distance to a celebrity is by way of the use of the parallax approach. this is wherein an astronomer will take note of the big name's role within the nighttime sky and then degree it again six months later.
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What do all living things constantly engage in
All living things are constantly engaged in Homeostasis.
Homeostasis is the capacity to sustain a comparatively constant internal condition that endures despite changes in the external environment. To consume energy and eventually live, all living things—from plants to puppies to people—must control their interior environments. For numerous reasons, the body sustains homeostasis. Body temperature, blood sugar levels, and varying pH levels are a few of them. Not merely at the level of the entire body as it is for temperature, homeostasis is maintained at several levels.
Homeostasis is a state that can be preserved by all living things. They have systems in place to regulate things like their internal temperature, water balance, and acidity. Normal cell functions that take place inside of them depend on homeostasis. Normal life processes are interfered with if an organism can't sustain equilibrium. Ailment or even death might follow.
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4. A ball is thrown horizontally with an initial velocity of 10 m/s off a cliff and spends 5 seconds in the air before hitting the ground. What is the height of the cliff? How far does the ball travel before hitting the ground.
The height of the cliff is 122.5 m and the farthest distance covered equals to 50 m.
What is projectile motion?
Projectile motion is a form of motion experienced by an object or particle that is projected near Earth's surface and moves along a curved path under the action of gravity only.
Given is a ball that is thrown horizontally with an initial velocity of 10 m/s off a cliff and spends 5 seconds in the air before hitting the ground.
Horizontal initial velocity = u[x] = 10 m/s
Vertical initial velocity = u[y] = 0 m/s
Vertical acceleration = a[y] = 9.8 m/s²
Using the second equation of motion along the vertical direction -
S[y] = u[y]t + 1/2a[y]t²
S[y] = 0 + 1/2 x 9.8 x 5 x 5
S[y] = 12.5 x 9.8
S[y] = 122.5 m
Horizontal distance covered = u[x] x t = 10 x 5 = 50 m
Therefore, the height of the cliff is 122.5 m and the farthest distance covered equals to 50 m.
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a long, thin solenoid has 700 turns per meter and radius 2.50 cm. the current in the solenoid is increasing at a uniform rate of 48.0 a/s. part a what is the magnitude of the induced electric field at a point near the center of the solenoid? express your answer with the appropriate units. e
The magnitude of the induced electric field at a point near the center of the solenoid is E =0 v/m at a point 0.500 cm from the axis of the solenoid is E = 1.05 × 10^-7 v/m.
formula for magnetic field due to solenoid is ,
B=μ₀nI
E=μ₀nI/2 dI/dt
E = 4π×10^-7 × 700 ×0×48/2
E=0v/m at center of the solenoid.
at r= 0.5cm
E=4π×10^-7 × 700 ×0.5×10^-2×48/2
E=1.05×10^-4 v/m
A long, thin wire loop that is frequently wrapped around a metallic core is referred to as a solenoid in physics. When an electric current is sent through it, the solenoid creates a magnetic field. Solenoids play a crucial role since they can generate precise magnetic fields and function as electromagnets. Its magnetic field has a form that is highly reminiscent to a bar magnet's field when a direct electric current is conducted through it. In a solenoid, the field is powerful and constant. A greater overall magnetic field is created as a result of the little magnetic fields that are produced by the current in each turn of the coil.
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in an elastic collision, a 400-kg bumper car collides directly from behind with a second bumper car traveling in the same direction. the mass of the leading bumper car is 30.0% greater than that of the trailing bumper car. the initial speed of the leading bumper car is 5.60 m/s and that of the trailing car is 6.00 m/s.
According to momentum conservation momentum before collision is equal to momentum after collision. velocity of trailing care after collision v1=5.047 m/s velocity of leading can after collision v2=5.947 m/s .
In physics, a collision, which is also known as an impact, is the abrupt, violent coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer and a nail, two railroad cars when linked, or a falling object and a floor. The force and the amount of time the objects are in touch, in addition to the materials the two objects are made of, have an impact on the outcome of the impact. It is generally knowledge that a hard steel ball dropped on a steel plate would rebound almost to the original position from where it was dropped, while a ball made of putty or lead will not. In a collision, an object encounters a force for a predetermined period of time, which causes a change in the mass's velocity. Each object that collides with the other experiences a force. The two forces are at odds with one another but have equal power.
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A 10,000 N elevator is going upward and gaining speed. It is pulled upward by 4 steel cables, each exerting a 4,000 N tension force. What’s the net force?
The combined weight of the elevator box and the passenger riding inside it acts as the pulling force on the wires in an elevator. Therefore, in a perfect world, the cable's tension would match the elevator's weight when it is at rest.
How can I determine an elevator cable's tensile force?
Total tension is equal to the weight plus the force of acceleration when lift is upward. Total tension equals the difference between weight and force caused by acceleration as lift decreases.
In medium lengths, tension exerts its force, especially in flexible materials like rope or cord. The force of tension is still a gravitational force. When the body moves.
The net force is the total of all forces acting on an object. According to Newton's Second Law, there must be a net force exerted on an item in order for it to accelerate. If an object's net force is zero, it is said to be in equilibrium and not moving forward.
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A pilot drops a bottle out an airplane. If the plane was flying at an altitude of 500 m
and the bottle lands 400 m horizontally from the initial dropping point, how fast was
the plane flying when the bottle was released?
The plane was flying at 39.6 m/s when the bottle was released .
[tex]h = ut + 1/2at^2[/tex]
distance fallen h= 500m
Initial velocity u=0
a=98 m/s2
[tex]h = 1/2at^2[/tex]
[tex]t^2 = 2h/a[/tex]
[tex]t^2 = 1000/9.8 = 10.1s[/tex]
[tex]d_h = 400, t = 10.1s[/tex]
[tex]v = d_h/t\\v = 400/10.1[/tex]
v = 39.6 m/s
What is Altitude ?
Altitude or Height (also known as depth) is a measurement of the distance between a reference point and a point or object, usually in a vertical or "upward" direction. The exact definition and reference value varies depending on the context (eg, aeronautics, geometry, geodesy, sports, or barometric pressure). Although the term height is often used to refer to the height of a place above sea level, in geography the term height is often preferred for this use.
The vertical measurement of distance in the "down" direction is usually called depth.
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,,.........................
suppose that the stone is launched with a speed of 3 m/s and travels 40 m before coming to rest. what is the approximate magnitude of the friction force on the stone? 0 n 2 n 20 n 200 n
The approximate magnitude of the friction force of the stone is 2N.
Given values:
Mass(m)= 20 Kg
Velocity(v)= 3m/s
Distance(x)= 40m
Kinetic energy is given by the expression:
[tex]Ek=1/2mV^{2}\\ Ek=1/2*20Kg*(3m/s)^{2} \\Ek=90J[/tex]
If we divide the kinetic energy by the distance traveled we get the friction force:
[tex]Ff=Ek/x\\Ff=90J/40m\\Ff=2.25N[/tex]
Approximate magnitude of the friction force is: [tex]Ff=2N[/tex]
Result is 2N.
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21. Explain why a passenger who is not wearing a safety belt will likely hit the windshield in a head-on collision. please answer in full sentences
A hockey puck with an initial speed of 8.0 m/s coasts 45 m to a stop across the ice. If the force of friction on the
puck has a magnitude of 0.12 N, what is the puck's mass?
Answer:
[tex]\boxed{m = 0.16875 \;kg}[/tex]
Explanation:
The work done by a constant force F Newtons on a mass of m kg over a distance of d m at an acceleration of a m/s² is given by the equation:
[tex]W = F\cdot d[/tex]
This should be equal to the kinetic energy expended
[tex]KE = \dfrac{1}{2}m v^2[/tex]
By the law of conservation of energy,
W = KE
[tex]F\cdot d = \dfrac{1}{2}m v^2[/tex]
Given v = 8 m/s, F = 0.12N and d = 45m
[tex]0.12 \times 45 = \dfrac{1}{2} \times m \times 8^2[/tex]
[tex]5.4 = 32m[/tex]
[tex]m = \dfrac{5.4}{32}\\\\\boxed{m = 0.16875 \;kg}[/tex]
A hockey puck with an initial speed of 8.0 m/s coasts 45 m to a stop across the ice. If the force of friction on the puck has a magnitude of 0.12 N the puck's mass is 0.16875 Kg
What is work?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the direction of motion.
The work done by a constant force F Newtons on a mass of m in kg over a distance of d in m at an acceleration of a m/s² is given by the equation:
This should be equal to the kinetic energy expended
K E = 1/2 m.v²
work, W = F.d
By the law of conservation of energy,
W = K E
Given v = 8 m/s, F = 0.12 N and d = 45 m
0.12* 45 = .5*m*8²
mass, m = 0.16875 Kg
A hockey puck with an initial speed of 8.0 m/s coasts 45 m to a stop across the ice. If the force of friction on the puck has a magnitude of 0.12 N the puck's mass is 0.16875 Kg
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Help me as pleasessss help with 1,2 and 3
an automobile of mass m is proceeding around a highway curve of 40-meter radius. the surface of the roadway is horizontal, and the coefficient of friction between the tires and the roadway is 0.50. the maximum speed with which the car can round the curve without slipping is...
The maximum speed with which the car can round the curve without slipping is 14m/s
Given the following:
The radius, r=40m
The coefficient of friction μ=0.5
Then from Newton's law:
μmg=mv^2/r
From the above equation, the speed, v of the car is:
v=√μrg, where μ=0.5, r=40m, and g=9.8m/s^2
v=√(0.5)(40m)(9.8m/s^2)
v=√196
v=14m/s
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What are the steps for using a compass and straightedge to construct an equilateral triangle? drag the steps and drop them in order from start to finish.
The first step would be to draw your circle using the compass, the second step would be to add the point to the circle, the third method would be to use the circle's radius to determine the compass's width.
You were instructed to draw a hexagon inside a circle and to list the points as you go. So, in order to pull up that image for your query, I'm going to use my snipping tool.
So, the first step would be to draw your circle using the compass, which would be step number 1. Step number 2 would then be to use the center to get the radius of your circle.
So first you would add the point on the circle, so that would be step number 2 step. Number 3 would be to use the circle's radius to set the width of the compass and then, after you have that point on the circle, you would put the compass on there and you create an arc with that compass that intersects the circle.
And then you would go ahead and mark that intersection with a point connect the consecutive points with a straight edge and then repeat the stips.
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galaxy fragments in the early universe formed before the first stars. in dark matter mini-halos. due to gravity from large dark matter halos. in places where the universe was slightly less dense than average.
Galaxy fragments originated in the early world due to the gravity of massive amounts of dark matter.
Dark matter is any substance that primarily interacts with visible matter through gravity (e.g., stars and planets). Therefore, in theory, it need not be made up of a brand-new form of fundamental particle but rather may be built up, at least in part, of typical baryonic matter, such as protons or neutrons.
The concept of dark matter, the invisible substance whose gravitational pull is assumed to hold galaxies together, may not be the most pleasing one in physics. According to a recent study, however, if you want to get rid of it, you'll need to switch it out for something more stranger: a gravitational force that at some distances pushes large objects apart and at others draws them together. The analysis highlights how difficult it is to rationalize away dark matter.
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Can you please help me with this question no 15 ?? Anyone please
The weight of the object in the newly heavenly body is 3000 N.
In science and engineering, the weight of an object is the pressure performed on the item due to gravity. a few widespread textbooks outline weight as a vector quantity, the gravitational pressure performed on the item. Others define weight as a scalar quantity, the significance of the gravitational pressure.
Given,
mass of earth = M
mass of new heavenly body = 12 M
the radius of the earth = r
the radius of the new heavenly body = 4r
mass of the object = m (mass always remains constant)
[tex]\frac{mM}{r^2}[/tex]
using the formula of gravity,
G₁ = g[tex]\frac{mM}{r^2}[/tex]
G₂ = g[tex]\frac{m12M}{4r^2}[/tex]
comparing G₁ and G₂
G₁ = 1000 N given
G₁ / G₂ = M × 4r² / 12 M r²
G₂ = 1000 × 12 / 4
= 3000 N
The measure of the pressure of gravity performing on a frame. The method for weight is given by using: w = mg. As weight is a force its SI unit is also the same as that of pressure, the SI unit of weight is Newton (N).
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An in-line skater first accelerates from 0.0m/s to 5.0m/s in 4.5s, then continues at this constant speed for another 4.5 s. What is the total distance by the in line skater
The total distance traveled by the in-line skater is equal to 33.75m.
What are equations of motion?Equations of motion are the collection of equations that depicts the relationship between the velocity, distance, time ad acceleration of an object. We can use these equations of motion to calculate these parameters for a body in motion.
Given, the initial speed of the skater, u = 0
The final speed of the skater, v = 5m/s
The distance covered by the skater is d₁ in the time t₁ and with d₂ in the in time t₂.
[tex]d = d_1 + d_2[/tex]
By using the first equation of motion to calculate the acceleration:
v = u + at
5 = 0 + (4.5)×a
a= 1.11 m/s²
The distance covered in time t₁ = 4.5 sec by the skater:
v² = u²+ 2ad₁
(5)² = 0 + 2×(1.11)×d₁
d₁ = 11.25m
In the second interval t₂ = 4.5 sec, distance: d₂= vt₂
d = (5)×(4.5) = 22.5 m
The total distance covered by in-line skater, d = 22.5 + 11.25 = 33.75 m
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The location of magnetic north changes over time in its relation to true north. This angular difference between magnetic north and true north is called.
Declination. As you can see, the position has a significant impact on the compass's direction. Declination, which is measured in degrees on your map and represents the angle between magnetic north and true north.
The compass does not always point precisely toward geographic north on the surface of the Earth. An angle known as "declination" describes the compass's departure from true north (or "magnetic declination"). If you were to stand at the north geomagnetic pole, your compass would be held horizontally as usual and would not have a preference to point in any specific direction. The same would be true if you were to stand at the south geomagnetic pole. The north-pointing end of your compass would point up at the south geomagnetic pole if you were to hold it on its side, and it would point down at the north geomagnetic pole.
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the timing device in an automobile’s intermittent wiper system is based on rc an time constant and utilizes 0.500 μf a capacitor and a variable resistor. determine the time constant if the resistance is 30 mω.
Our resistance is four mega houses at two seconds. Simply enter 15 seconds as R times 150.50 times 10 to the negative six digits for the calculation. We therefore have 30 Mega Ohms.
It is required to wipe the screen of an automobile on a regular basis when there is a light drizzle, when it is dirty, or when any of these conditions exist. There is a switch that uses an electrical circuit to wipe the screen. A main-wiper control circuit system and a relay control circuit are components of an intermittent wiper system. The relay control circuit uses a transistor and diode combination in an RC circuit.
According to what we've been told, our RC circuit's capacitance is 0.5 micro Farads, or 0.5 times ten to the minus six Farads. The resistance times the capacitance produces the time constant. And by multiplying both sides by C, we may find R's value. And when the time constant is divided by the capacitance, which is equal to 0.5 times ten to the minus six Farads, we have the minimum resistance, which is equal to 4.00 Mega Ohms.
The maximum time constant divided by capacitance occurs when the resistance is at its maximum. As a result, when we replace tau with 15 seconds, we obtain 30.0 Mega Ohms. To modify the frequency of the wiper blades' oscillation, the resistance must be able to shift between four and thirty megaohms.
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The gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 K. If the pressure decreases to 3.20 atm, what is the temperature of the gas in kelvin? it need to be rounded by three significant figures to
The temperature of the gas rounded to three significant figures would be 244 Kelvin.
What is an ideal gas?
It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one.
As given in the problem, the gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 K. If the pressure decreases to 3.20 atm,
By using the constant volume for the ideal gas,
P₁/P₂ = T₁/T₂
3.90 /3.20 = 298 / T₂
T₂ = 244 Kelvin
Thus, the temperature of the gas rounded to three significant figures would be 244 Kelvin.
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a solenoid has 15 turns per centimeter of its length. the solenoid is twisted into a circle so that it becomes shaped like a toroid. what is the magnetic field at the center of each turn of the toroid? the current is 29 mama .
The magnetic field at the center of each turn of toroid is: 2.826×10⁻⁵ T
What is a magnetic field?Magnetic field is a vector field in surrounding of a magnet, electric current carrying conductor or a changing electric field, in which magnetic forces can be experienced.
Magnetic field of a toroid is calculated as (B): μ₀nI
Where, μ₀= permeability
n= Number of turns in toroid
I= Current
B= Magnetic field
In the given question,
n=15 turns/cm
I=15mA
Now turns per meter length is: 15/10⁻²=1500turns per meter
The magnetic field at the center of each turn of the toroid is(B): μ₀nI
B= (4[tex]\pi[/tex]×10⁻⁷)(1500)(15×10⁻³A)
B= 2826×10⁻⁸ T
B= 2.826×10⁻⁵ T
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What is the weight of a 179 kg football player?
A humming bird flies 1.m along a straight path at a height of 5.9 m above the ground. Upon spotting a flower below, the hummingbird drops directly downward 1.8 m to hover in front of a flower.
What is the magnitude of the hummingbird’s total displacement?
The hummingbird's total displacement is 6.168m, 16.96⁰ Southwest.
Construct a right-angled triangle from the bird's displacement
⇒From the diagram uploaded; we calculate the resultant/total displacement (R) of the bird using Pythagoras theorem,
R² = 5.9² + 1.8²
R² = 38.05
R = √38.05
R = 6.168 m
calculate the direction of the bird's displacement
From the vector diagram head-to-tail rule, we determine the cardinal direction;[tex]tan\alpha = \frac{1.8}{5.9}[/tex]
From the diagram; [tex]tan\alpha = 0.3050[/tex]
[tex]\alpha = tan^{-1} 0.3050[/tex]
[tex]\alpha = 16.96^{o}[/tex]
Therefore the hummingbird's total displacement is 6.168m, 16.96⁰ Southwest.
What is displacement?Displacement is defined as a change in the location of an object. It is a vector quantity and has direction and magnitude. It is represented as an arrow pointing from the starting position to the final position. For example - when an object moves from point A to point B, the position of the object changes.
Displacement (symbolized d or s ), also called length or distance, is a one-dimensional quantity representing the difference between two specified points. The standard SI unit of displacement is the meter (m).
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An automobile travels for 90 minutes along a highway. The graph shows the progress of the automobile, with its start point designated as distance = 0 km.
What is the automobile's instantaneous velocity at time = 60 seconds?
0.50 km/min
1.0 km/min
−0.40 km/min
0.33 km/min
Taking the gradient from point B to P, 0.33 km/min is the automobile's instantaneous velocity. Option D is the right answer.
What is Instantaneous Velocity ?Instantaneous velocity of a moving body is the velocity of the body at an instant of time or at a specific time.
Given that an automobile travels for 90 minutes along a highway. From the graph, it is shown that the velocity is constant at point B to point Point P.
The automobile's instantaneous velocity at time = 60 seconds can be calculated by using the gradient formula along the line BP since the velocity is constant from point B to point P
Gradient = Δ distance / Δtime
Velocity V = (30 - 15) / (75 - 30)
V = 15 / 45
V = 0.33 Km/min
Therefore, the automobile's instantaneous velocity at time = 60 seconds is 0.33 km/min
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