Recall that the gravitational pull is given by
[tex]F=G\frac{m_{}\cdot M_E}{r^2}[/tex]Where m is the mass of the astronaut, ME is the mass of Earth, r is the distance between them, and G is the gravitational constant.
The above relation states that the force of gravitation is directly proportional to the mass of two objects and is inversely proportional to the square of the distance between them.
If the astronaut weighs 200 pounds and the radius of the Earth is 4000 miles then
[tex]\begin{gathered} 200=G\frac{m\cdot M_E}{4000^2} \\ G\cdot m\cdot M_E=200\cdot4000^2 \end{gathered}[/tex]When the astronaut moves 4000 miles above the earth's surface then the distance between them is
4000+4000 = 8000 miles
The distance is measured from the center of the earth so the radius must be included.
So, the new force of gravitation is
[tex]\begin{gathered} F=\frac{G\cdot m_{}\cdot M_E}{r^2} \\ F=\frac{200\cdot4000^2}{8000^2} \\ F=50\: lb \end{gathered}[/tex]Therefore, the astronaut weighs 50 pounds 4000 miles above the earth's surface.
This makes sense because as you go further away from the center of the Earth then your weight becomes less due to less force of gravity.
I am not sure if this is true or false. Please help
We have the formula of Newton's second law
[tex]F=ma[/tex]Where F is the force, m is the mass and a is the acceleration.
If we isolate the acceleration
[tex]a=\frac{F}{m}[/tex]As we can see if the mass increases the acceleration will decrease
Therefore the answer is FALSE
. In one day, the temperatures of a desert range from 110°F in the afternoon to 55°F at night. What
is this temperature range on the Kelvin scale?
Answer:
30.5555°K
Can be rounded to 30.56°K
Explanation:
The relationship between °C and °K is
°K = °C + 273.15
To convert °F to °K, first convert °F to °C and then add 273.15
°C = (°F - 32) x 5/9
So combining the two conversions we get
°K = (°F - 32) x 5/9 + 273.15
55°F = (55-32) x 5/9 + 273.15 = 285.9278°K
110°F = (110-32) x 5/9 + 273.15 = 316.4833°K
Temperature range in Kelvin scale
= 316.4833°K - 285.9278°K = 30.5555°K
What is the acceleration of a car,
moving along a straight line, that
increases its velocity from 0 to 15
m/s in 10 s?
An egg test dummy is fitted with a helmet, sealed in a plastic bag, and attached to a swing with a clamp. These items have a mass of 0.090 kg. This mass is pulled back to a height of 0.55m. The mass is then released and allowed to swing down and collide with a cement block. What is the speed of the mass at the moment before impact?
The speed of the mass at the moment before impact is 3.28 m/s.
What is the final speed of the egg?
The speed of the mass at the moment before impact is calculated from the principle of conservation of energy as shown below.
K.E(bottom) = P.E(top)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
v is the speed of the egg before the impacth is the height of the fall of the eggSubstitute the given parameters and solve for the speed of the egg before the impact.
v = √2gh
v = √(2 x 9.8 x 0.55)
v = 3.28 m/s
Thus, the speed of the mass at the moment before impact is determined by applying the principle of conservation of energy.
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Set the cannon to have an initial speed of 25 m/s. For which situation do you think the cannon ball will be in the air for the longest time: if it is set at a 25-degree angle, or if it is set at a 35-degree angle?
Question 5 options:
25 degree
35 degree
The cannon ball will travel the highest distance when the angle of projection is 35 degrees.
What is the maximum height of a projectile?The maximum height reached by a projectile is calculated using the following formula.
H = u²sin²θ/2g
where;
u is the initial velocity of the projectile θ is the angle of pojectiong is acceleration due to gravitywhen the angle of projection is 25 degrees;
H = (25² (sin 25)²) / (2 x 9.8)
H = 5.7 m
when the angle of projection is 35 degrees;
H = (25² (sin 35)²) / (2 x 9.8)
H = 10.5 m
Thus, the cannon ball will travel the highest distance when the angle of projection is 35 degrees.
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Can an object have a net negative charge of 2.00 x 10^-19
We will have that as long as the object is a conductor it will be able to have a net negative charge of 2.00*10^-9 C.
free fall is any motion of a body where is the only force acting upon it
When light is reflected, the incident rays are bent and change direction.
Given
When light is reflected, the incident rays are bent and change direction
To find
Whether the given statement is true
Explanation
When we flash a light on the mirror, the light changes its direction and move in another way. So the incident light changes direction when reflected
Conclusion
The given statement is TRUE
A flowerpot falls from a window sill 34.6 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? Choose upwards to be
the positive y direction. The acceleration of
gravity is 9.81 m/s²
The velocityof the flowerpot when it strikes the ground is 26.04.
What is velocity.
velocity is the prime indicator of the position as well as the rapidity of an object. It can be defined as distances covered by an object in unit of the time. velocity can defined as the displacement of the object in unit of the time .
Sol- As we know when the object is simply falls it's initial velocity is 0.
Therefore u=0
Given question is flowerpot traveled 34.6 before striking the ground.
Therefore s=34.6
We have to find v?
v^2= u^2+2gs
v^2= 0+2gs
v=√2gs
v=√2×9.81×34.6
v=26.04
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You can buy 50 rolls of toilet paper for $12.50. Write a ratio showing the unit rate of rolls per $1.
Answer:
[tex]\frac{4R}{1D}\Rightarrow\text{ 4 rolls per \$1}[/tex]Explanation: We need to find the unit rate or rate of rolls per $1:
[tex]50\text{rolls }\Rightarrow\text{ 4=\$12.50}[/tex]To find the number of rolls per one dollar we simply need to take the ratio of the two as follows:
[tex]\frac{50R}{12.50D}\Rightarrow(1)[/tex]Simplifying (1) gives the answer as follows:
[tex]\begin{gathered} \frac{50R}{12.50D}=\frac{4R}{1D} \\ \end{gathered}[/tex]The answer therefore is:
[tex]\text{4 rolls per \$1}[/tex]2. A saucepan containing 2 kg of water is heated. 400 kJ of energy is transferred. Calculate the temperature
increase of the water.
The specific heat capacity of water is 4200 J/kg °C. Give your answer to four significant figures.
The temperature increase of the 2 kg water if 400 kJ of energy is transferred is 47.62 °C
q = m c ΔT
q = Heat
m = Mass
c = Specific heat
ΔT = Change in temperature
q = 400 KJ
m = 2 kg
c = 4200 J/kg °C
ΔT = q / m c
ΔT = 400 * 10³ / 2 * 4200
ΔT = 47.62 °C
The quantity of heat energy required to change the temperature of particle by 1 °C is known as heat capacity. Specific heat capacity is the heat capacity is calculated for 1 gram of matter.
Therefore, the temperature increase of water is 47.62 °C
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Which of the Figures correctly represents the force diagram to solve the problem?
ANSWER
Figure 1
EXPLANATION
We want to identify the correct force diagram acting on the object on the inclined plane.
When an object is moving on an inclined plane, there are four forces acting on it:
1. Friction force, Fr
2. Normal force, FN
3. Component of weight acting parallel to the inclined plane = Wsinθ
4. Component of weight acting perpendicular to the inclined plane = Wcosθ
Therefore, the correct option is Figure 1.
A tetherball leans against the smooth, frictionless
post to which it is attached (Figure 1). The string is
attached to the surface of the ball such that a line
along the string passes through the center of the
ball. The string is 1.40 m long, and the ball has a
radius of 0.110 m with mass 0.280 kg.
After thoroughly calculating we have come to find that, the tension in the string is 2.752 N
What is tension?In physics, tension is defined as the pulling force transmitted axially by a string, cable, chain, or other similar object, or by each end of a rod, truss member, or other similar three-dimensional object.
Tension can also be defined as the action-reaction pair of forces acting at each end of the aforementioned elements. Compression's opposite, tension, is possible.
We know that
Tension = (Mass × gravity) / cos∅
Here given that
Mass = 0.280kg
Gravity = 9.8 m/s²
∅ = 4.2°
Lets substitute the values and we get
Tension = (280g × 9.8 m/s²) / cos4.2°
Tension = 2.752 N
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Full question
A tetherball leans against the smooth, frictionless
post to which it is attached (Figure 1). The string is
attached to the surface of the ball such that a line
along the string passes through the center of the
ball. The string is 1.40 m long, and the ball has a
radius of 0.110 m with mass 0.280 kg. What is the
tension in the string?
If the lines in problem below, have a resistance of 100-Ω, calculate the change of voltage along each line. We are asked to determine the current given the power and the voltage. To do that we will use the following formula:P=IVWhere:P= powerI= currentV= voltageNow, we divide both sides by "V":PV=INow, we convert the power from "kW" to "W" using the following conversion factor:1kW=1000WMultiplying by the conversion factor we get:200kW×1000W1kW=200000WNow, we plug in the values in the formula:200000W48000V=ISolving the operations:4.2A=ITherefore, the current is 4.2 Amp.
Resistance 100
Current 4.2A
Based on the information of the last point, we know the current and now we have the resistance. With these two numbers we can calculate the drop of voltage generated by the resistance.
Is important to highlight that we asume the same current for each line because the current is constant in all the parallel lines.
[tex]\begin{gathered} V=IR \\ V=100\Omega\cdot4.2A \\ V=420V \end{gathered}[/tex]Given 2 concentric wheels; what weight will an applied force FA of 40.0N down and tangent to the 18.0 cm radius wheel will balance an unknown weight tangent and down on the 10.0 cm radius wheel? Draw the situation
The given problem can be exemplified using the following diagram:
We will determine the magnitude of the force "F" that will balance the concentric wheels.
To do that we will add the torques produced by the forces. If the torque is counterclockwise we will set it a positive and if it is clockwise it will be negative.
[tex]T_{40}-T_F=0[/tex]Where:
[tex]\begin{gathered} T_{40}=\text{ torque produced by the 40 N force} \\ T_F=\text{ torque produced by the unknown force. } \end{gathered}[/tex]The sum of toques adds up to zero because we want to determine the force "F" when the system is in equilibrium.
Now, we substitute the formula for the torques:
[tex]F_{40}r_{18}-Fr_{10}=0[/tex]Where:
[tex]\begin{gathered} r_{18}=\text{ 18 cm radius} \\ r_{10}=\text{ 10 cm radius} \end{gathered}[/tex]Now, we solve for the force "F":
First, we will add "Fr10" to both sides:
[tex]F_{40}r_{18}=Fr_{10}[/tex]Now, we divide both sides by r10:
[tex]\frac{F_{40}r_{18}}{r_{10}}=F[/tex]Now, we plug in the values:
[tex]\frac{(40N)(18\operatorname{cm})}{10\operatorname{cm}}=F[/tex]Solving the operations:
[tex]72N=F[/tex]Therefore, the required force is 72N.
A converging lens has a focal point of 3.93 cm. If you place an apple 19.24 cm away from the lens, where would the image be formed? Submit your answer in meter.
Given
The focal length , f=3.93 cm
The object distance, u=-19.24cm
To find
The image distance
Explanation
By lens formula we have,
[tex]\begin{gathered} \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ \Rightarrow\frac{1}{v}-\frac{1}{(-19.24)}=\frac{1}{3.93} \\ \Rightarrow\frac{1}{v}=0.202 \\ \Rightarrow v=4.95cm=0.0495\text{ m} \end{gathered}[/tex]Conclusion
The image distance is 0.0495 m
Which statement below best describes how scientists explain gravity's role in the formation of
our Solar System? and Why?
A. The combined gravitational attraction between our planets was so large that it pulled the
Sun away from a nearby star cluster into the center of our Solar System.
B.The eight planets in our Solar System were originally orbiting a nearby star, and the Sun's
gravity was large enough to pull those planets into orbit around the Sun.
C. Due to the expansion of neighboring solar systems, the gravitational attraction of our
planets to those solar systems forced the formation of the planets around our Sun.
D.As the Sun was forming, the force of gravity caused surrounding dust grains to collide and
stick together, forming dust granules into increasingly larger bodies that became planets.
D. As the Sun was forming, the force of gravity caused surrounding dust grains to collide and stick together, forming dust granules into increasingly larger bodies that became planets.
About 4.6 billion years ago, the Solar System was a cloud of dust and gas known as the Solar Nebula.
The gravitational forces of the planets push gases out of their atmospheres and form a star at the center of the solar system.Gravity compresses the gases in the center of the solar nebula until temperatures are high enough for nuclear fusion to occur.It collapsed the material in on itself as it began to rotate, forming the sun at the center of the nebula.As the sun rose, the remaining material began to clump together.Gravity is the force that pulls a body toward the center of the Earth or any other physical body that has mass.
Therefore "As the Sun was forming, the force of gravity caused surrounding dust grains to collide and stick together, forming dust granules into increasingly larger bodies that became planets", best describes scientists explain gravity's role in the formation of our Solar System.
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How many hours would it take a plane to fly 1,500 miles if it was moving at a constant speed of 300 miles/hour? Include units!
Best answer gets brainliest!
Answer:
5 hours
Explanation:
distance/speed= time
1500/300= 5
Which of the following examples is NOT an example of energy transfer?bringing water to a boilba boat being accelerated by the force of the enginecrain falling from a clouddwaves in the ocean
Rain falling from a cloud is not an example of energy transfer.
what is the acceleration of a car, moving along a straight line, that increases its velocity from 0 to 15 m/s in 10s?
Acceleration = Change in Velocity / Time Interval
So,
A=15/10
A=1.5m/s.
Acceleration is defined as the rate of change of velocity over time. Acceleration is a vector quantity because it has both magnitude and direction. It is also the second derivative of position with respect to time or the first derivative of velocity with respect to time. Acceleration is the name we give to the process of changing velocity. Because speed is speed and direction.
There are only two ways to accelerate. Either change speed change direction or change both. Acceleration is the rate of change of velocity. At any point in the orbit, the magnitude of the acceleration is given by the rate of change of magnitude and direction of velocity at that point. Velocity is the primary measure of object position and velocity. It can be defined as the distance traveled by an object in a unit of time.
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A. Thermal to Chemical to Electrical to MechanicalB. Mechanical to Chemical to Electrical to Thermal C. Electrical to Chemical to Mechanical to ThermalD. Chemical to Thermal to Mechanical to Electrical
Given:
Coal-fired power plant
Required:
Energy transformation in coal-fired power plant.
Explanation:
Coal has chemical energy.
When the coal is heated, the chemical energy transforms into thermal energy.
Thermal energy is used to rotate the blade of the turbine, so thermal energy transforms into mechanical energy.
The rotating blades produce electricity, so mechanical energy transforms into electrical energy.
Final Answer: The energy transformation of a coal-fired power plant is chemical to thermal to mechanical to electrical.
Jenny experiences an average downward force of 441 N anywhere she goes on Earth. Calculate her mass
Answer:
Given,
Force = 441 N
mass = ?
Keep in mind that acceleration due to gravity is constant 10m/s.
Force = mass × acceleration due to gravity
mass = Force / acceleration due to gravity
m = 411 N /10m/s
m = 41.1 kg
Therefore her Jenny mass is 41.1 kg.
A 5.9 x 104-kg space probe is traveling at a speed of 14000 m/s through deep space. Retrorockets are fired along the line of motion to
reduce the probe's speed. The retrorockets generate a force of 1.4 x 104 N over a distance of 3700 km. What is the final speed of the
probe?
Answer:
there are 6 circles and 2 triangles. what is the simplelest ratio of triangles to circles
A car of mass 1101 kg traveling at 18.39 m/s collides and sticks to a car with a mass of 1050 kg initially at rest. What is the resulting velocity of the two cars right after the collision, assuming that there's no friction present?
Answer: the resulting velocity of the two cars right after the collision is 9.41 m/s
Explanation:
The formula for calculating momentum is expressed as
momentum = mass x velocity
According to the law of conservation of momentum, initial momentum = final momentum
The formula for initial momentum is
m1u1 + m2u2
where
m1 = mass of first car
u1 = initial velocity of first car
m2 = mass of second car
u2 = initial velocity of second car
From the information given,
m1 = 1101
u1 = 18.39
m2 = 1050
u2 = 0 because it is at rest
Initial momentum = 1101 x 18.39 + 1050 x 0 = 20247.39
Since the cars stick together after collision, they would have a common velocity, V. Thus,
final momentum = (m1 + m2)V
final momentum = (1101 + 1050)V = 2151 V
Thus,
20247.39 = 2151 V
V = 20247.39/2151
V = 9.41
the resulting velocity of the two cars right after the collision is 9.41 m/s
To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets as shown in the figure (Figure 1). Suppose that the satellite has a mass of 1300 kg and a radius of 4.8 m , and that the rockets each add a mass of 250 kg.
a) What is the steady force required of each rocket if the satellite is to reach 46 rpm in 7.0 min , starting from rest?
The steady force required of each rocket is 27,875 N.
What is the steady force required for each rocket?
The steady force required by each rocket along the circular path is calculated as follows;
F = ma
where;
m is the mass of the each rocketa is the centripetal acceleration of each rocketThe centripetal acceleration of each rocket is calculated as follows;
a = ω²r
where;
ω is the angular velocity of the rocketr is the radius of the circular pathω = 46 rpm = 46 rev/min x 2π rad/rev x 1 min/60s = 4.82 rad/s
t = 7 min = 7 x 60 s = 420 s
a = ω²r
a = (4.82²) x 4.8 m
a = 111.5 m/s²
The steady force is calculated as follows;
F = ma
F = 250 x 111.5
F = 27,875 N
Thus, the steady force required of each rocket is determined by applying the concept of centripetal force.
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A 55 kg skater rolls along a U-shaped half pipe starting at rest from a height of 15 m. The skater rolls to the other side of the half pipe at a height of 12 m before stopping. What is the work done by friction?
The work done by friction is -1617 J
What is work done?Work done is the product of force and distance moved in the direction of the force.
What is friction?Friction is the opposition to motion between two surfaces
What is the work done by friction?From the lwa of conservation of energy, the work done by friction, W equals the change in potential energy of the skater, ΔU.
So, ΔU = W
mgΔh = W
mg(h₂ - h₁) = W where
m = mass of skater = 55 kg, g = acceleration due to gravity = 9.8 m/s², h₁ = initial height of skater = 15 m and h₂ = final height of skater = 12 m.So, substituting the values of the variables into the equation for the work done, we have
W = mg(h₂ - h₁)
= 55 kg × 9.8 m/s²(12 m - 15 m)
= 55 kg × 9.8 m/s² × (-3 m)
= 539 kgm/s² × (-3 m)
= -1617 J
So, the work done is -1617 J
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What is the resistance (in Ω) of a 17.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter?
In order to calculate the resistance of this wire, we can use the formula below:
[tex]R=\frac{\rho d}{A}[/tex]Where p is the resistivity, d is the length and A is the cross-sectional area of the wire.
The resistivity of the copper is 1.72 * 10^-8 ohms*m, so we have:
[tex]\begin{gathered} R=\frac{1.72\cdot10^{-8}\cdot17.5}{\frac{\pi\cdot(1.15\cdot10^{-3})^2}{4}}\\ \\ R=\frac{30.1\cdot10^{-8}\cdot4}{\pi\cdot1.3225\cdot10^{-6}}\\ \\ R=\frac{120.4\cdot10^{-8}}{4.1547563\cdot10^{-6}}\\ \\ R=28.98\cdot10^{-2}\text{ ohms}\\ \\ R=0.2898\text{ ohms} \end{gathered}[/tex]how can earthquakes be more destructive than tsunamis
Buildings can be destroyed by earthquakes or knocked down, trapping people underneath.
Only regions close to the water are susceptible to tsunamis, but anybody may be affected anywhere by earthquakes. Buildings can be destroyed by earthquakes or knocked down, trapping people underneath. Uneven surfaces and damaged roadways can result from the shifting and cracking of the Earth during earthquakes. When two chunks of the ground abruptly slide past one another, an earthquake results. The fault or fault plane is the area where they slide. Sudden movement along Earth's fault lines causes earthquakes. The motion releases "elastic strain" energy that has been accumulated in the form of seismic waves, which travel through the Earth and cause the earth to tremble.
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What is the mass of a 37.0 Nweight?m =?] kgEnter
Answer:
m = 3.8 kg
Explanation:
The weight can be calculated as follows:
[tex]W=m\cdot g[/tex]Where m is the mass and g is the gravity. So, replacing the weight by 37 N and the gravity by 9.8 m/s², we get:
[tex]37\text{ N = m}\cdot9.8m/s^2[/tex]So, solving for m, we get:
[tex]\begin{gathered} \frac{37}{9.8}=\frac{m\cdot9.8}{9.8} \\ 3.8\operatorname{kg}\text{ = m} \end{gathered}[/tex]Therefore, the answer is m = 3.8 kg
Misrepresentations of physical stimuli are known as
Misrepresentations of physical stimuli are known as Absolute Threshold
What is stimulus?
A stimulus is a measurable change in the physical or chemical structure of an organism's internal or external environment in physiology. Sensitivity refers to an organism's or organ's ability to perceive external stimuli and respond appropriately (excitability). Sensory receptors can receive information from both inside and outside the body, such as touch receptors in the skin or light receptors in the eye, as well as chemoreceptors and mechanoreceptors. When a sensory receptor detects a stimulus, it can generate a reflex via stimulus transduction. A homeostatic control system's first component is frequently an internal stimulus. External stimuli, such as the fight-or-flight response, are capable of eliciting systemic responses throughout the body.
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