Given data:
* The mass of the roller coaster is m = 800 kg.
* The total mechanical energy is E = 392000 J.
* The kinetic energy at the particular height (let h') is K = 92000 J.
Solution:
The potential energy of the roller coaster at h' is,
[tex]\begin{gathered} U=E-K \\ U=392000-92000 \\ U=300000\text{ J} \end{gathered}[/tex]The potential energy in terms of height and mass is,
[tex]U=\text{mgh}[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} 300000=800\times9.8\times h \\ 300000=7840\times h \\ h=\frac{300000}{7840} \\ h=38.3\text{ m} \end{gathered}[/tex]Thus, the height of the roller coaster from the ground is 38.3 meters.
a current density of 4.50 10-13 a/m2 exists in the atmosphere at a location where the electric field is 133 v/m. calculate the electrical conductivity of the earth's atmosphere in this region.
This measurement demonstrates the conductivity of a certain material. When compared to rubber, which has poor electrical conductivity and high electrical resistance, metal, for instance, has high electrical conductivity and low electrical resistivity.
Electrical resistivity's physical opposite is electrical conductivity. This measurement demonstrates how well a certain material can conduct an electric current.
Rubber has a poor electrical conductivity and a high electrical resistivity, whereas metal has a high electrical conductivity and a low electrical resistance.
We are aware of the following thanks to the values that have been provided:
J = 6.00 10 13 A / m 2 and E = 100 V / m
The following equation provides the current density in terms of the electric field:
J = σ E
Here, E is the electric field, J is the current density, and is the electrical conductivity.
σ = J / E
The known values are then substituted.
σ = ( 6.00 × 10 − 13 A / m 2 ) / ( 100 V / m )
σ = ( 6.00 × 10 − 15 / m ) / ( 100 V )
The corresponding unit for V / A is.
Condense the units.
σ = 6.00 × 10 − 15 Ω − 1 m − 1.
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electricity iii goals define the concept of obstacle determine how obstacles combine when in series and in parallel. expand model of electricity to include effects of obstacle size
A circuit is necessary for electricity to flow. The same materials can be used in multiple ways to create a complete circuit.
Diffraction is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the obstruction or aperture. Effectively, the wave's secondary source is the diffracting element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise observations of the phenomena in 1660.
The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomenon in classical physics. [3] As seen in the enclosed figure, the distinctive bending pattern is most obvious when a wave from a coherent source (like a laser) comes into contact with a slit or aperture that is roughly the same size as its wavelength.
A circuit is necessary for electricity to flow. The same materials can be used in multiple ways to create a complete circuit. Electric circuits of various types exhibit varying behavior (parallel and simple circuits) Light, heat, and music can all be produced with the use of electricity electrical conductors and insulators.
This results from the addition or interference of various wavefront points (or, alternatively, each wavelet) that follow pathways to the registering surface of varying lengths. Multiple, closely spaced apertures (like those in a diffraction grating) can produce a complicated pattern with different intensities.
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An electic bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally.
Answer:
Explanation:
We have to use the equation p = I^2 x R. But we do not have the current.
To work out the current, we look at what we have. We have the voltage and power, therefore we will use the equation P = IV and rearrange to find the current.
I = P/V
I = 60/220
I = 0.2727272727 or round it to 2 dp to get = 0.27
we now have to rearrange the first equation to find the resistance.
R = P/I^2
R = 60/0.2727272727^2
R = 806.6666665501
R = 807 ohms (3sig)
The resistance of the filament is 806.67 ohms.
Electrical power is defined as the rate at which electrical energy is transferred by an electric circuit. The SI unit of power is Watt, 1 joule per second ( 1J/S).
The formula of electrical power is
P = V^2/R
where,
P = power
V = volts
R = resistance
from the above formula
60 = 220x220/R
R = 220x220/60
R = 806.67
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a spotlight on the ground is shining on a wall away. if a woman 2m tall walks from the spotlight toward the building at a speed of 0.6 m/s how fast is the length of her shadow on the building decreasing when she is 2m from the building?
The answer is dy/dt is equal to -(20/7)(1/14)(0.6) = -0.12245 m/s.
The negative sign shows that the rate is falling as y gets shorter
.Woman Height/ Distance Light To Woman equals
Shadow Height/Distance Light To Wall.
explanation?
Think of a huge triangle with the origin as the spotlight, a base of 20, and the height of the shadow on the wall as y. Inside the larger triangle, a comparable triangle that is x meters from the spotlight and 2 meters
tall—the woman's height—can be seen.
Woman Height/ Distance Light To Woman equals
Shadow Height/Distance Light To Wall.
The shadow height is y. Let x be the distance from the woman to the light.
xy = 40 or y/20 = 2/x
Take both sides' derivative:
XDY + YDX = 0 based on the product rule.
Solve for the desired result, dy/dy:
dy/dt = -(y/x)dx/dt, where dx/dt = 0.6 m/s.
The woman is 20 - 6 meters from the light when she is 6 meters from the wall, which is 14 meters, or x.
Keep in mind that y/20 = 2/x = 2/14 --> y = 40/14 = 20/7 from the related triangles.
So, dy/dt is equal to -(20/7)(1/14)(0.6) = -0.12245 m/s.
The negative sign shows that the rate is falling as y gets shorter.
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be sure to answer all parts.an fm station broadcasts classical music at 94.5 mhz (megahertz, or 106 hz). find the wavelength (in m, nm, and å) of these radio waves.
Thus, the wavelength is 3.21 m when the frequency fm station broadcasts classical music is at 93.5 mHz.
A waveform signal's wavelength is defined as the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or along a wire. This length in wireless systems is typically expressed in metres (m), centimetres (cm), or millimetres (mm) (mm). It is more common to specify the wavelength in nanometers (nm), which are units of 10-9 m, or angstroms (), which are units of 10-10 m, for infrared (IR), visible light (VL), ultraviolet (UV), and gamma radiation ().
Frequency, or the quantity of wave cycles per second, is inversely related to wavelength. The wavelength of a signal decreases in length as its frequency increases. An electric field and a magnetic field vibrate together, producing an electromagnetic wave. A wavelength can be determined by dividing a wave's velocity by its frequency.
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There are several methods of extrasolar planet detection currently in use. Which properties of a planet does each method discover? sort the following methods into the appropriate categories.
The complete box as per methods of extrasolar planet detection
Diameter of the
Transit methodMass of the planet
Microlensing methodRadial velocity methodAstrometry methodThis is further explained below.
What are the methods of extrasolar planet detection?Generally, The techniques for finding planets beyond the solar system
Microlensing caused by gravitational forces occurs when a star that contains a planet moves in front of another star. This causes the light to bend in a peculiar manner.
The transit method takes into account the varying luminosities of the stars. When a planet passes in front of a star, the star's apparent brightness decreases, which provides information about the planet's radius or diameter.
The radial velocity method analyzes the Doppler shift of a star to determine whether the star is moving closer or farther away from us.
Method of astronomy that is based on variations in the positions of stars in the sky.
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Object starts from rest. Dots are placed every second. What is the acceleration of the object?
The acceleration of the object is 4.48m/s².
From the graph we can see,
There are 5 dots placed over the line, it means that the object has moved for 5 seconds. The distance which the object has covered in 5 seconds is equal to about 56 meters.
As we know, the object is starting from rest, so the initial velocity is 0m/s.
Now, to find the acceleration a of the object, we can use the equations of motion.
So,
Using,
S = ut + 1/2at²
Where,
u is initial velocity,
S is the distance covered,
and t is the time period of motions of the object.
Putting all the values,
56 = 1/2a(5)²
(56 x 2)/25 = a
a = 4.48m/s²
Hence, the acceleration is 4.48m/s².
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A rectangular loop of wire with a cross-sectional area of 2.936 m2 carries a current of 6.488 A. The loop is free to rotate about an axis that is perpendicular to a uniform magnetic field strength of 1.108 T. The plane of the loop is initially at an angle of 59.914o to the direction of the magnetic field. What is the magnitude of the torque on the loop ?
ANSWER:
10.58 Nm
STEP-BY-STEP EXPLANATION:
Given:
Area (A) = 2.936 m²
Current (i) = 6.488 A
Magnetic field (B) = 1.108 T
Angle (θ)= 59.914°
To calculate the torque we must resort to the following formula:
[tex]\begin{gathered} \tau=MB\sin\alpha \\ \\ \alpha=90\degree-\theta=90-59.914\degree \\ \\ \alpha=30.086\degree \end{gathered}[/tex]We need to know the magnetic moment, as follows:
[tex]\begin{gathered} M=NIA \\ \\ M=1\cdot6.488\cdot2.936 \\ \\ M=19.05\text{ A}\cdot m^2 \end{gathered}[/tex]In this way we can calculate the torque:
[tex]\begin{gathered} \tau=19.05\cdot1.108\cdot\sin(30.086\degree) \\ \\ \tau=10.58\text{ Nm} \end{gathered}[/tex]Therefore, the magnitude of the torque on the loop is 10.58 Nm
ASAP:You live on a part of Earth where the angle of the sun's rays are very high, and the latitude is low. Which temperatures do you experience quite often?'
If an airplane is flying 100 mph South but there is a crosswind pushing the airplane 30 mph to the West, then what would the resulting velocity be?
O 104.4 mph, NE
O 104.4 mph, SW
O 10900 mph, NE
O 11.4 mph, SW
The resultant velocity of the plane has a magnitude 104.4 mph and direction south of west .
What do you mean by velocity?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.The speed at which something moves in a specific direction is known as its velocity. as the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.The plane is flying south at a speed of 100 mph and is blown by a 30mps strong wind due west.
⇒ The angle between the direction of flight of plane and the direction of the wind is 90° .
⇒ By Pythagoras theorem, the resultant speed is
[tex]\sqrt{100^{2} +30^{2} } =\sqrt{10900}[/tex] =104.4 mph
⇒ The resultant velocity of the plane has a magnitude 104.4 mph and direction south of west
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If an object is at rest or stopped, what is its velocity, acceleration, or speed?
Answer:
Thus, even though the velocity of an object at rest must be zero, acceleration can clearly be non-zero for objects at rest. A particle that is thrown vertically upwards stops momentarily at the highest point of motion.
Answer:
Everything is zero. Because it's at rest.
the speed of car increase if the car's
If a force of 10 newtons acts on an object and an additional force of 6 newtons acts in the same direction, what will be the net force on the object?.
Two forces 10N and 6N acts on an object in same direction , then the net force will be:
16N .
What is net force?The sum of all the forces acting on an object is defined as the net force. A mass can be accelerated by net force. Another force acts on a body at rest or in motion. When there are a large number of forces in a system, the net force is used.When a body is in motion, many forces act on it, including gravitational force Fg, frictional force Ff, and the normal force. As a result, the net force formula is given by Fa + Fg + Ff + FN = FNet.When two forces act in the same direction on an object, the net force equals the sum of the two forces.So here net force : F= F1 + F2.
Here,
F1 = 6 N
F2 = 10 N
F = 6N + 10N
F = 16N
∴ Net force = 16N .
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A block of mass 290 kg slides on a frictionless plane inclined at 39◦ with the horizontal under the influence of a restraining force of 1643 N acting parallel to the incline and up the incline. The acceleration of gravity is 9.8 m/s^2
What is the magnitude of the acceleration of the block? Answer in units of m/s^2
The resulting motion is
1. down the plane, since the acceleration is positive.
2. up the plane, since the acceleration is negative.
3. undetermined.
The magnitude of the acceleration is −0.50 m/s² of the block of mass 290kg that slides on a frictionless plane inclined at 39◦ with the horizontal under the influence of a restraining force of 1643 .
The resulting motion is
2. up the plane, since the acceleration is negative.
What is acceleration?Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an object or point moving straight ahead.
Due to the constant change in direction, motion on a circle accelerates even when the speed is constant. Both effects help to accelerate all other types of motion.
We have given that,
m = 290 kg
θ = 39◦
F = 1643 N
g = 9.8 m/s²
The force due to gravity
F₁ = m × g × sinθ
F₁ = 290 × 9.8 × sin 39°
F₁ = 1790.46 N
Lets take acceleration is a m/s²
Form Newtons second law
F - F₁ = m × a
1643 - 1790.46 = 290 x a
a = −0.50 m/s²
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a boy is running north with a speed of 5 m/s on a large, horizontal frozen lake. the coefficient of friction (both kinetic and static) between his shoes and the ice is ?
The coefficient of friction between the boy's shoes and the ice is 0.65.
The coefficient of static friction for ice is 0.65, so this means that 65% of the force needed to move an object from one place to another must be applied in order to get it moving across the ice at all—once it starts moving, however, there will be a lot less work required because we have already accounted for the initial force required to start moving it.
This means that if we want our boy running north at 5 meters per second across this large, flat lake with no wind or waves or anything else going on that might cause him trouble (or even help him), he'll need 10 meters per second or more just to get started.
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Which requires more work to do, using a force to lift a 50 kg. rock, 2 meters or lifting a 25 kg. rock, 4 meters? (1 kilogram=10 newtons)
Given data:
Mass of rock 1;
[tex]m_1=50\text{ kg}[/tex]Height rock 1 lifted;
[tex]h_1=2\text{ m}[/tex]Mass of rock 2;
[tex]m_2=25\text{ kg}[/tex]Height rock 2 lifted;
[tex]h_2=4\text{ m}[/tex]The work done in lifting the rock is given as,
[tex]W=mgh[/tex]Here, m is the mass of the rock, g is the acceleration due to gravity (g=10 m/s²) and h is the height the rock lifted.
The work done in lifting rock 1 is given as,
[tex]W_1=m_1gh_1[/tex]Substituting all known values,
[tex]\begin{gathered} W_1=(50\text{ kg})\times(10\text{ m/s}^2)\times(2\text{ m}) \\ =1000\text{ J} \end{gathered}[/tex]The work done in lifting rock 2 is given as,
[tex]W_2=m_2gh_2[/tex]Substituting all known values,
[tex]\begin{gathered} W_2=(25\text{ kg})\times(10\text{ m/s}^2)\times(4\text{ m}) \\ =1000\text{ J} \end{gathered}[/tex]On comparing the work done in lifting rock 1 and 2 we conclude that,
[tex]W_1=W_2=1000\text{ J}[/tex]Therefore, the same amount of work is done in lifting a 50 kg rock by 2 meters and lifting a 25 kg rock by 4 meters.
The question is in the picture please answer problem 8Thank you
According to the second law of Newton, the acceleration is directly proportional to the net force acting on the object:
[tex]F=m\cdot a[/tex]From this formula, we can also see that the acceleration is inversely proportional to the mass: For the same force, if the mass increases, the acceleration decreases.
Therefore the correct option is d.
a 77 kg man is riding on a 32 kg cart traveling at a speed of 3.8 m/s. he jumps off with zero horizontal speed relative to the ground. what is the resulting change in the cart's speed, including sign?
Answer:
See below
Explanation:
Using conservation of momentum:
Initial momentum = (77+32 kg)* 3.8 m/s = 414.2 kg m/s
Jumping off with zero speed relative to ground (I think this is what zero horizontal speed MEANS) means all of his momentum is given to the cart ( think about jumping off of a skateboard)
final momentum of the cart
mv = 414.2
v = 414.2/32 = 12.94 m/s for a + 9.13 m/s change
Two objects in a closed system collide. After the collision, one object has lost speed, but the other object has gained speed. Explain what has happened. A. Total momentum in a closed system is conserved. B. Gravitation potential energy converts to kinetic energy. C. Kinetic energy converts to gravitational potential energy. D. Mass is conserved
A. Total momentum in a closed system is conserved
the law of momentum conservation states that The total amount of momentum before the collision is the same as the total momentum after the collision. Regardless of the change of momentum of each object.
Matt likes to get from the second floor of his house to the first floor by sliding
down the banister that is inclined at an angle of 30.0°to the horizontal. If Matt
has a mass of 50 kg and the coefficient of sliding friction between Matt and the
banister is 0.20, what is the force of friction impeding Martin's motion down the
banister?
The force of friction impeding Matt's motion is 49.05 N.
What is friction?
When two surfaces move relative to each other, friction between them turns kinetic energy into thermal energy (that is, it converts work to heat). As demonstrated by the utilisation of friction caused by rubbing pieces of wood together to start a fire, this feature can have severe repercussions. When motion with friction occurs, such as when a viscous fluid is churned, kinetic energy is transformed to thermal energy. Another significant effect of many types of friction is wear, which can lead to performance degradation or component damage. The science of tribology includes friction.
The force of friction impeding Matt's motion down the banister can be calculated using the equation:
Ff = μN
where μ is the coefficient of sliding friction and
N is the normal force.
The normal force can be calculated using the equation:
N = mg sinθ
where m is the mass of the object, g is the acceleration due to gravity, and θ is the angle of incline.
Plugging in the known values, we get:
Ff = μN
Ff = (0.20)(50 kg)(9.81 m/s2)(sin 30.0°)
Ff = 49.05 N
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a mouse of mass 27.0 g falls 200 m down a vertical mine shaft and lands at the bottom with a speed of 8.1 m/s. during its fall, how much work (in j) is done on the mouse by air resistance?
Work is done on the mouse by air resistance 25.574 Joule.
Work is done every time a force moves something over a displacement. you can calculate the electricity transferred, or paintings done, by using multiplying the force via the gap moved in the course of the force. strength transferred = work achieved = pressure x distance moved within the direction of the pressure.
Work to be accomplished, a force must be exerted and there must be motion or displacement in the route of the pressure. The work done by way of a force appearing on an object is the same as the significance of the pressure accelerated by way of the space moved within the route of the force.
given,
mass = 27.0 g = 0.027 kg
Height H = 200 m
initial speed u = 0 m/s
final speed V = 8.1 m/s
force = mg
= 0.027 × 9.8
= 0.2646 N
1/2mu² + mgh = mgh + 1/2mv²
0 + 0.027×9.8 ×100 = 0 + 1/2×0.027× (8.1)² + air reesistance
initial energy = 26.46 J
final energy = 0.886 J
air resistance = 26.46 J - 0.886 J
= 25.574 Joule
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Recognise cause and effect. Acceleration can occur when a car is moving at a constant speed what must cause this accelaration. please answer in full sentences
Answer:
The car must be moving at a changing velocity but at a constant speed. This is caused when an object is changing direction but not its speed.
Explanation:
Since velocity is a vector, it is measured with both magnitude (the numerical value) and direction. Acceleration is the change in velocity over a time period, which makes acceleration also a vector.
Speed is a scalar, so it is only measured by its magnitude (the numerical value). Speed only changes if you:
1. slow down
2. speed up
There are 3 ways an object can accelerate:
1. by slowing down
2. by speeding up
3. by changing direction (turning)
Since the speed is the same, that means the car can't be speeding up or slowing down. Therefore, the car must be turning direction with a constant speed.
When electricity to an electromagnet is stopped, what happens to the strength of the magnet?.
When electricity to an electromagnet is stopped the magnetic strength of the magnet will be lost.
What is electromagnet and what happens to the strength of the magnet?An electromagnet is a device consisting of a core made up of magnetic material surrounded by a coil through which electric current can pass.So electricity is essential to the wire for the electromagnet to work in a proper manner.In the electromagnet the magnetic flux is varied , sometimes it is switched on and sometimes off.Inside the electromagnet moving charges create magnetic fields, when coil have the current passing through it. Hence the magnet will lose the magnetic strength when electricity to an electromagnet is stopped.To know more about electromagnet visit:
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How can manipulation of a model be done
A model can be altered in a number of ways, by importing a database, combining information, or erasing data.
The term "scientific manipulation" in behavior analysis describes the methodical organization of a variable under research in order to enable the objective analysis of the effects of the variable presence or absence on some other measurable behavior.
To manipulate data, build a database with information from many sources, clean and rearrange the content of the database, combine and remove redundant information, and then do an analysis to uncover important information.
Understanding your needs and goals, utilizing automation tools, filtering your data, and researching various manipulation tools are some strategies for manipulating data.
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Please select the best answer from the choices provided
Answer:
u got to provide all info in order to be answered
Explanation:
at midday, solar energy strikes the earth with an intensity of about 1000. w/m2. what is the area of a solar collector that could collect 150 mj of energy in 1 h? this is roughly the energy content of 1 gallon of gasoline.
41.67 m² is the area of a solar collector that could collect 150 mj of energy in 1 h.
Power received per unit surface is the definition of intensity.
[tex]I=P/A=1kW/m2(1)[/tex]
Power is simply defined as the rate at which energy changes over time.
[tex]P=\Delta E/\Delta t(2)[/tex]
ΔE = 150 MJ
Δt = 1 hour = 3600 sec.
[tex]P=150 MJ/3600 s=41.67 kW(3)[/tex]
Replacing (3) in (1), and solving for Area, we get:
Area = 41.67 m²
The measurement that indicates the size of a region on a plane or curved surface is called area. Surface area refers to the area of an open surface or the border of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.
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What is the frequency of light when the energy of a single photon is 2. 23 × 10-21 j?.
When a single photon has an energy of 2.23*10-21, light has a frequency of *E=hv 2.23 10-21 J = (6.626... 3.03 10-19 J (6.022*1023 photons).
A photon is a tiny energy packet of electromagnetic radiation, also referred to as a light quantum.
Given energy, what is a photon's frequency?A single photon's energy is determined by the equation E = h v, where E is its energy (measured in SI units of J), h is the Planck constant (6.626 x 10-34 J s), and is the frequency of the radiation (measured in SI units of s-1 or Hertz, Hz) (see figure below).E = h is the energy equation.In the formula, E stands for energy, h for Planck's constant (6.626 x 10 -34 J s), and v for frequency.Since frequency rises as energy falls, frequency and energy are related directly in the energy equation. Because h is a constant, this is conceivable. between frequency and energy since frequency and energy are inversely correlated. Because h is a constant, this is conceivable.To learn more about Photon frequency refer to:
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A block of mass 200g is oscillating on the end of a horizontal spring of spring constant 100 N/m and natural length 12 cm. When the spring is stretched to a length of 14 cm, what is the acceleration of the block? [F=ma=kx]
In order to determine the acceleration of the block, use the following formula:
[tex]F=ma[/tex]Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:
[tex]F=kx[/tex]Then, you have:
[tex]ma=kx[/tex]by solving for a, you obtain:
[tex]a=\frac{kx}{m}[/tex]In this case, you have:
k: spring constant = 100N/m
m: mass of the block = 200g = 0.2kg
x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m
Replace the previous values of the parameters into the expression for a:
[tex]a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}[/tex]Hence, the acceleration of the block is 10 m/s^2
two charges have a force of 8 n between them when the distance between them is suddenly increased by a factor of 2. the new force will be _________ n
When the distance between them is suddenly increased by a factor of 2. the new electrostatic force will be 2 N.
We need to know about electrostatic force to solve this problem. The electrostatic force is a force caused by two charges separated at a distance. It can be determined as
F = k . Q1 . Q2 / r²
where F is force, k is coulomb's constant (9 x 10⁹ Nm²/C²), Q is charge and r is radius.
From the question above, we know that
F1 = 8 N
r1 = r m
r2 = 2r1 = 2r
For this question, we can apply the ratio of initial and final force
F1 / F2 = k . Q . Q / r1² / k . Q . Q / r2²
F1 / F2 = r2² / r1²
F1 / F2 = (2r)² / r²
F1 / F2 = 4r² / r²
F1 / F2 = 4
F2 = 1/4 . 8
F2 = 2 N
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[2-d collision on a frozen pond] while doing physics experiments on a frozen pond's frictionless horizontal surface, sam, of mass 80.0 kg, is given a push and slides eastward. abigail, of mass 50.0 kg, is sent sliding northwards. they collide (whump!), and afterwards sam is moving at 37.0° north of east at 6.00 m/s, while abigail is moving 23.0° south of east at 9.00 m/s.
We could calculate the initial and final kinetic energy after computing the velocities prior to the impact. So, the total kinetic energy of the two people decrease during the collision by -638.73 J.
Since the velocity before to the collision is unknown, it is impossible to calculate the kinetic energy. So, we'll start by computing the velocities before to the impact.
If all external forces have a zero vector total, momentum is said to be conserved. In other terms, it may be said that the system's momentum prior to the collision and its after momentum should be identical.
This indicates that even if we know little or nothing about the internal forces of the system, we can still calculate the system's momentum.
The kinetic energy prior to and following the collision must be calculated in order to calculate the change in kinetic energy.
Due to the unknown velocity before to the contact, it is impossible to calculate the kinetic energy. As a result, we'll start by computing the velocities that existed before the impact.
The first step is to calculate the x and y components of the velocity following the collision. Sam might be represented by variable S, and Abigail by variable A.
v S = v S x + v S y = 6.00 m / s cos 37 + 6.00 m / s sin 37 v S = ( 4.79 I + 3.61 j ) m / s v A = v A x + v A y = 9.00 m/s cos 23 + 9.00 m/s sin 23 v A = ( 8.28 I + 3.52 j ) m / s
Then, keep in mind the equation for momentum conservation: p 1 = p 2
where p 1 represents the momentum prior to the collision and p 2 represents the momentum following the collision. Since Sam is sliding eastward before to the collision in the aforementioned scenario, we will only utilize the x component of the velocity after the collision of Sam and Abigail to compute the velocity of Sam before the collision, and we will also set Abigail's momentum to zero.
We could now calculate the initial and final kinetic energy after computing the velocities prior to the impact.
KE1=12mS(vS1)
2+12mA(vA1)
2=12(80 kg)(9.97 m/s)
2+12(50 kg)(2.26 m/s)
2KE1=4103.73 J
KE2=12mS(vS1)
2+12mA(vA1)
2=12(80 kg)(6.00 m/s)
2+12(50 kg)(9.00 m/s)
2\sKE2=3465 J
The difference between the end and starting kinetic energy could be used to calculate the change in kinetic energies.
KE= -638.73J
Complete question is:
You and your friends are doing physics experiments on a frozen pond that serves as a frictionless, horizontal surface. Sam, with mass 80.0 kg, is given a push and slides eastward. Abigail, with mass 50.0 kg, is sent sliding northward. They collide and after the collision, Sam is moving at 37.0 degrees north of east with a speed of 6.00m/s and Abigail is moving at an angle 23.0 degrees south of east with a speed of 9.00 m/s. By how much did the total kinetic energy of the two people decrease during the collision?
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