Answer:
2300 because 800 + 1500=2300
what makes it difficult to see Mercury
Answer:
Mercury is the planet nearest the Sun and is the most difficult to observe, because it is always quite close to the Sun in the sky. Because of its orbital motion, it appears to swing back and forth around the Sun, reaching a maximum angular distance of about 28°.
Explanation:
I hope that helps you
Answer:
Mercury is very close to the Sun which means its hard to see the planet without the Sun's brightness outshining it. It is also the smallest planet in the solar system.
Hope this helps!
what is the acceleration caused by gravity on earth
Answer:
Explanation:
It's 9.8 m/s^2
part 3 of 3
---
What is the velocity when t = 8 s?
Answer in units of m/s.
Answer in units of m/s
Answer:
1 m/s
(i think, *nervous sweat*)
Explanation:
We can tell this by looking at the graph. When t = 8, we will look at the time. We see that when the x (time) is 8, the velocity is 1 m/s.
whose geocentric model of the solar system was accepted for 1400 years
Answer:
Plato, Aristotle developed it further and used for 1400 years till Copernicus.
Explanation:
A fisherman notices that wave crests pass the bow of his anchored boat every 3.0 s. He measures the distance between two crests to be 7.0 m. How fast are the waves traveling?
Answer:
The time period is
T
=
3.0
s
.
The distance between two crests is
λ
=
8.0
m
.
The frequency of wave can be calculated as,
f
=
1
T
f
=
1
3.0
s
f
=
1
3
s
−
1
The speed of wave can be calculated as,
v
=
f
λ
v
=
(
1
3
s
−
1
)
(
8
m
)
v
=
2.67
m
/
s
a ball is thrown vertically down from the edge of a cliff with a speed of 5.2m/s how high is the cliff if it took 11s for the ball to reach the ground
[tex]\\ \sf\longmapsto h=ut+\dfrac{1}{2}gt^2[/tex]
[tex]\\ \sf\longmapsto h=5.2(11)+\dfrac{1}{2}(9.8)(11)^2[/tex]
[tex]\\ \sf\longmapsto h=57.2+4.9(121)[/tex]
[tex]\\ \sf\longmapsto h=57.2+592.9[/tex]
[tex]\\ \sf\longmapsto h=650.1m[/tex]
How many electrons have been removed from a positively charged electroscope if it has a net charge of 1.6× 10−13 C?
Answer:
Tu mujhe banaye ga face dekh aapna mirror me
Answer:
iloveyouuuuuuuuuuuuuuu
HOW WOULD SOUND REFLECT
Answer:
Reflection. If a sound is not absorbed or transmitted when it strikes a surface, it will be reflected. ... Reflection of a sound wave at a barrier, as if from an imaginary source at an equal distance behind the barrier. Sound reflection gives rise to DIFFUSION, REVERBERATION and ECHO.
Answer:
by a echo
Explanation:
if u are I a sound proof room you shout to the wall the echo will then reflect
2. Connect concepts on the left with a description on the right.
Concave lens A. Distance between two waves. Magnifier B. Can be captured on screen.Focal length. C. Light of a wavelength. Wavelength D. Scattered incident light. Infrared radiation E. Convex lenses. Real picture F. Distance to the focal point. Laser G. Light swinging in one direction. Polarized light. H. Heat radiation
3. Explain in as much detail as you can how a rainbow arises. a
plzzz explain me your questions
at a certain distance from a point charge the electric potential is 200V and electric field is 200V/m, what is this distance
a. 10m
b. 8m
c. 0.1m
d. 0.8m
Explanation:
0.1 m
i dont know how to explain but i know the ans so ............byee ...
Give a short introduction to alternative energy
Answer:
Alternative energy is energy sources other than fossil fuels, including renewable sources and nuclear energy. However, nuclear energy is not classified as a renewable energy source, because it is mined from uranium and thorium elements, which cannot be replenished. Hoped this helped!!!
A box collides with a ball as shown in the diagram below. After the collision, what
will the final momentum of the ball be?
BEFORE COLLISION
AFTER COLLISION
15 kgm/s
3 kgm/s
5 kgm/s
_kgm/s
O 18 kg * m/s
O 5 kg * m/s
O 10 kg * m/s
O 13 kg * m/s
The final momentum of the ball after collision is 13 kg.m/s.
The given parameters;
initial momentum of the box, P₁ = 15 kg.m/sinitial momentum of the ball, P₂ = 3 kg.m/sfinal momentum of the ball, P₃ = 5 kg.m/sLet the final momentum of the ball after collision = P₄
Apply the principle of conservation of linear momentum to determine the final momentum of the ball after collision;
total momentum before collision = total momentum after collision
P₁ + P₂ = P₃ + P₄
15 + 3 = 5 + P₄
18 = 5 + P₄
18 - 5 = P₄
13 = P₄
Thus, the final momentum of the ball after collision is 13 kg.m/s.
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l am so confused is it right?
Answer:
D
Explanation:
First,mg＞fv: It does a download acceleration,and the speed of the object increase.
Second,mg=fv: it hasn't a acceleration.
you can think the f is a constant.
Vector A has a magnitude of 8.0 m and points 30 degrees north of east; vector B has a magnitude of 6.0 m and points 30 degrees west of north; and vector C has a magnitude of 5.0 m and points 30 degrees west of south. The resultant vector A + B + C is given by:
A) 2.1 m at an angle 66 degrees east of north.
B) 5.9 m at an angle 74 degrees north of east.
C) 2.7 m at an angle 74 degrees north of east.
D) 5.1 m at an angle 74 degrees north of east.
E) 4.8 m at an angle 74 degrees east of north.
The resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.
To find the resultant vector A + B + C, we need to break down each vector into its horizontal (x) and vertical (y) components, and then add them together.
Given:
Vector A: magnitude = 8.0 m, angle = 30 degrees north of east
Vector B: magnitude = 6.0 m, angle = 30 degrees west of north
Vector C: magnitude = 5.0 m, angle = 30 degrees west of south
Let's calculate the x and y components for each vector:
For Vector A:
A_x = 8.0 m × cos(30°)
A_x = 8.0 m × 0.866
A_x ≈ 6.928 m
A_y = 8.0 m × sin(30°)
A_y = 8.0 m ×0.5
A_y = 4.0 m
For Vector B:
B_x = 6.0 m × sin(30°)
B_x = 6.0 m × 0.5
B_x = 3.0 m
B_y = 6.0 m × cos(30°)
B_y = 6.0 m × 0.866
B_y ≈ 5.196 m
For Vector C:
C_x = 5.0 m × sin(30°)
C_x = 5.0 m ×0.5
C_x = 2.5 m
C_y = 5.0 m × cos(30°)
C_y = 5.0 m × 0.866
C_y ≈ 4.33 m
Now, let's add up the x and y components:
Resultant x component = A_x + B_x + C_x
Resultant x component = 6.928 m + 3.0 m + 2.5 m
Resultant x component ≈ 12.428 m
Resultant y component = A_y + B_y + C_y
Resultant y component = 4.0 m + 5.196 m + 4.33 m
Resultant y component ≈ 13.526 m
Finally, we can find the magnitude and angle of the resultant vector:
Resultant magnitude = sqrt((Resultant x component)² + (Resultant y component)²)
Resultant magnitude = sqrt((12.428 m)^2 + (13.526 m)^2)
Resultant magnitude ≈ 18.015 m
Resultant angle = arctan(Resultant y component / Resultant x component)
Resultant angle = arctan(13.526 m / 12.428 m)
Resultant angle ≈ 48.413°
Considering the answer choices provided:
A) 2.1 m at an angle 66 degrees east of north.
B) 5.9 m at an angle 74 degrees north of east.
C) 2.7 m at an angle 74 degrees north of east.
D) 5.1 m at an angle 74 degrees north of east.
E) 4.8 m at an angle 74 degrees east of north.
The closest match to our calculated result is:
D) 5.1 m at an angle 74 degrees north of east.
Therefore, the resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.
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To hit a fish that he sees beneath the water, where should he aim?
Ok I guess you are gonna use arrow/spear. Ok so what I learned is that the best place to hit and fish is the gills or the eye(s) because without the gills fish won't be able to breath.If you hit it on the eye it will take a while to kill the fish.The fish will feel lots of pain and start swim like crazy and probably go away.So i will say the BEST way to kill a fish to to hit it's gills.
In case you don't have any materials to kill fish:
IF you are in the wild with fish and you don't have a hook,spear,arrow, etc. I will recommend you to use a rock that his big but easy to grip.Hit the fish on top of its head just behind the eyes.Or get a stick no too thick or too skinny just like between those and start whittle it to a arrow then aim and shoot.
Hope this helps! =D
a physics student throws a stone horizontally off a cliff. one second later, he throws a second identical stone in exactly the same way. which of the following statements is true?
The second stone hits the ground exactly one second after the first.
The distance traveled by each stone down the cliff is calculated using second kinematic equation;
[tex]h = v_0_yt + \frac{1}{2} gt^2[/tex]
where;
t is the time of motion [tex]v_0_y[/tex] is the initial vertical velocity of the stone = 0[tex]h = \frac{1}{2} gt^2[/tex]
The time taken by the first stone to hit the ground is calculated as;
[tex]t_1 = \sqrt{\frac{2h}{g} }[/tex]
When compared to the first stone, the time taken by the second stone to hit the ground after 1 second it was released is calculated as
[tex]t_2 = \sqrt{\frac{2h}{g} } + 1[/tex]
[tex]t_2 = t_1 + 1[/tex]
Thus, we can conclude that the second stone hits the ground exactly one second after the first.
"Your question is not complete, it seems be missing the following information;"
A. The second stone hits the ground exactly one second after the first.
B. The second stone hits the ground less than one second after the first
C. The second stone hits the ground more than one second after the first.
D. The second stone hits the ground at the same time as the first.
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the chemical compositions of jupiter and saturn are most similar to those of:
5. What must occur for an object to exert a contact force on another object?
Answer:
An object must be touching another.
I WILL MARK U HELP PLZ
The free body diagram for an object is projected. Calculate the net force acting on the object. If this object is 10 kg, how/where will it accelerate?
Explanation:
By the end of the section, you will be able to:
Apply problem-solving techniques to solve for quantities in more complex systems of forces
Use concepts from kinematics to solve problems using Newton’s laws of motion
Solve more complex equilibrium problems
Solve more complex acceleration problems
Apply calculus to more advanced dynamics problems
through this steps you will get the answer.thank youa car travels at a uniform speed of 30 km per hour for 30 mins and then at a uniform speed of 60 km per hour for the next 30 minutes calculate the average speed of a car
PLEASE HELP ME WITH EDGE UNIT TEST!!!! EARTH AND SPACE SCIENCE!!!!!
At which location would an object’s weight be the greatest?
on Pluto
on Earth
on the Sun
on the moon
Answer:
on Pluto or earth go witH u guts mine is always right hope this helps
two children, A and B, fire identical 10.0g all bearings from a catapult. the elastic band of each catapult extended by 0.10m and then released to fire the ball bearings. Child A's elastic band has a spring constant of 144N/m. calculate the energy transferred to the kinetic energy store of the child A's ball bearing.
thanks soo much (:
WORTH 50 PTS
The energy transferred to the kinetic energy store of the child A's ball bearing is 0.72 J.
Energy transferred to the kinetic energy
The energy transferred to the kinetic energy store of the child A's ball bearing is determined from the principle of conservation of energy as shown below;
K.E = Ux = ¹/₂kx²
K.E = ¹/₂ x 144 x 0.1²
K.E = 0.72 J
Thus, the energy transferred to the kinetic energy store of the child A's ball bearing is 0.72 J.
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NEED HELP!!!! 10 POINTS!!
Paralysis is often the result of severe spinal injuries. Why is this often the case?
A.
All movement begins in the spine and radiates through the body.
B.
The spine in the only part of the body that is directly connected to the brain.
C.
The spine houses much of the central nervous system, which controls movement.
D.
The bones in the spine cannot regenerate and grow, unlike other bones in the body.
PLEASSE NO LINKS
Due to paralysis, the result is severe spinal injuries. This is often the case because the spine houses much of the central nervous system, which controls movement. Hence, option C is correct.
What is Paralysis?You might become paralyzed, and unable to move on your own when something interferes with the nerve impulses that muscles receive from the brain. Strokes, spinal cord injuries, and neurological diseases like multiple sclerosis are among the common causes of paralysis.
When you are unable to move your muscles voluntarily, you are said to be paralyzed. Paralysis results from nerve system issues.
Muscles receive messages from healthy nerves. This causes the muscles to contract. When you’re paralyzed, or have paralysis, you can’t move certain parts of your body.
Hence, it concludes that option C is correct.
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A force of 20 N acts upon a 5 kg biock. Calculate the acceleration of the object.
Answer:
F=ma
Explanation:
Given required solution
F=20N a=? a=F/m
m=5kg a=20/5
a=4m/s^2
Based on the table, what is the advantage for using 16-inch spacing compared to 24-
inch spacing?
A. At a given load, the 16-inch spacing can support a smaller span
B. At a given load, the 16-inch spacing can support a larger span
C. At a given load, the 16-inch spacing requires less construction time
D. At a given load, the 16-inch spacing requires less construction costs
The advantage for using 16-inch spacing is that ; ( B ) At a given load, the 16-inch spacing can support a larger span
The spacing along a span in construction engineering is determined by the amount and mass of load the span will either carry or support during and after construction.
A smaller span spacing can support a given load more efficiently than a larger span spacing because when the spacing is smaller it can support a larger span better than a larger span spacing.
Hence we can conclude that the advantage for using 16-inch spacing is that At a given load, the 16-inch spacing can support a larger span.
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How many miles are present in 620 g of mercury
Answer:
620 grams Mercury (1 mole Hg/200.6 grams) = 3.09 moles Hg
Explanation:
Have an awesome day ;)
What is the relationship between the temperature of a star and its luminosity?
Not all the thermal energy from the hot object transferred to the cold water. Suggest ways that you could have improved your experimental design to increase the transfer of thermal energy from the hot object to the cold water.
Answer:foucovfirfvuhivufhijifs
Li Wei loves cardio and finds it very easy to fit into his schedule. Because he knows it is important to diversify his exercise routine, sometimes he runs and other days he rides his bike. What else should Li Wei consider regarding his routine?
OPTIONS:
A.
He should add some strength training.
B.
He needs to add one more form of cardio.
C.
He has too much cardio and should cut half of it.
D.
His program works for him, so he should not change it.
PLEASE NO LINKS
Answer:
D.
Explanation:
Li Wei loves cardio and finds it very easy to fit into his schedule. Li Wei should consider his routine is his program works for him, so he should not change it. The correct option is D.
What is cardio?Any form of exercise that raises your heart rate and keeps it there for a long time is considered cardio. As you start to breathe more quickly and deeply, your respiratory system will start to work harder.
The four components of a fitness program are flexibility, cardio, strength, and power.
The physical exercise that increases muscular strength and fitness is referred to as strength.The capacity to produce the most muscle contractions possible during a movement is referred to as power.Cardio refers to the capacity to handle various circumstances of various lengths.Flexibility is the characteristic that is linked to the range of motion offered by a particular joint.Therefore, the correct option is D. His program works for him, so he should not change it.
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A diver runs toward the edge of the cliff in Tobermory. This cliff is 44 m high (top of cliff to water level). They dive out, horizontally, at a velocity of 1.8 m/s [forward]. The sign below was posted for a reason. There is a section of rock right under the rough water extending from the cliff out for 4 m, as shown below. Does the diver hit the hidden rocks?
This question involves the concepts of the equations of motion for both the vertical motion and the horizontal motion.
The diver "does not" hit the rock.
First, we will calculate the time taken by the diver to land. For this purpose, we will use the second equation of motion for the vertical motion of the diver:
[tex]h = v_{iy}t+\frac{1}{2}gt^2[/tex]
where,
h = height of cliff = 44 m
[tex]v_{iy}[/tex] = vertical component of the initial velocity of the diver = 0 m/s
t = time taken to land = ?
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]44\ m=(0\ m/s)t+\frac{1}{2}(9.81\ m/s^2)(t)^2\\\\t = \sqrt{\frac{(44\ m)(2)}{9.81\ m/s^2}}[/tex]
t = 3 s
Now, we will calculate the horizontal distance where the diver landed. For this purpose, we will use the equation of motion for the horizontal motion of the diver. Assuming the air resistance to be zero the horizontal motion will be uniform. Hence:
[tex]s = vt\\s = (1.8\ m/s)(3\ s)\\[/tex]
s = 5.4 m
Since the section of the rock was 4 m away from the cliff. Hence, the diver crossed that rock section and safely laded at a distance of 5.4 m, which is 1.4 m ahead of the rock section.
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The attached picture shows the equations of motion for the horizontal motion and vertical motion.