if a person weighs 600 n and the surface area of the bottom of both feet combined is 200 cm2, what is the pressure

the intensity level of the combined sounds is 67.76 dB

Calculation :

Sound Intensity level L= 63 dB

We know L = 10 log(I/Io)

63 = 10 log(I/Io)

6.3 = log (I/Io)

I /Io = [tex]10^{6.3}[/tex]

I = [tex]10^{6.3}[/tex] Io

= [tex]10 ^{6.3 }[/tex]x [tex]10 ^{-12}[/tex]

= [tex]10^{ -5.7}[/tex] W/m 2

  = 1.995 x[tex]10 ^{-6}[/tex] W/m 2

Sound Intensity level L '= 66 dB

We know L ' = 10 log(I '/Io)

66 = 10 log(I '/Io)

6.6 = log (I'/Io)

I ' /Io = [tex]10 ^{6.6}[/tex]

I ' =  [tex]10 ^{6.6}[/tex] Io

=  [tex]10 ^{6.6}[/tex] x [tex]10 ^{-12}[/tex]

= [tex]10 ^{-5.4}[/tex]W/m ^2

  = 3.981 x[tex]10 ^{-6}[/tex] W/m^ 2

Combined intensity I " = I + I ' = 5.976 x10 -6 W/m 2

the intensity level of the combined sounds L " = 10 log(I" / Io)

 L " = 10 log [( 5.976 x[tex]10 ^{-6}[/tex] )/([tex]10 ^{-12}[/tex] ) ]

      = 10 log [5.976 x10 6]

      = 10(6.776)

      = 67.76 dB

Intensity is the amount of energy a wave transports in one unit of area per unit time and is also equal to the energy density multiplied by the wave velocity. Usually measured in watts per square meter. Intensity depends on wave strength and amplitude.

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We use a construct that can be used in a shell script the read built-in Bash command to read user input. It assigns user input to the variable after receiving it. It simply takes one line from the Bash shell to read. The syntax for implementing it is listed below.

read <variable_name>  

A built-in tool in Bash allows you to read text from standard input. The utility provides a wide range of user input reading capabilities that assist make Bash scripts interactive. Through various examples and use situations, this article demonstrates how the Bash read command functions. access to a terminal or command line.

The "read" command in Bash scripting is used to get human input. It's essential to comprehend the "read" command if you want to make your code more interactive. The "read" command is used to retrieve user-inputted data. This article demonstrates how to communicate with users using Bash's "read" command.

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The magnitude of the average value of the emf induced in the loop is 2.26 V.

The initial area of wire loop is:

A(initial) = π d² / 4

             = 3.14 × ( 0.21 m )² / 4

             = 0.0346 m²

And, The wire loop's final location is at:

A(final) =  π d² / 4

           = 3.14 × ( 0.31 m )² / 4

           = 0.0754 m²

It is given that the magnetic field is normal to the loop of wire.

Therefore, angle made by the magnetic field with the normal to the loop

is :

θ = 0°

Applying Faraday's law, the average emf induced in the loop is:

ε = B × ( A(final) - A(initial) ) × cosθ / Δt

ε = 2.00 T × ( 0.0754 - 0.0346 ) m² × cos0° / 0.036 s

ε = 2.26 V

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If a = a1, a2, a3 and b = b1, b2, b3 . Then [tex]& \vec{a} \times \vec{b}=(-1)(\vec{b} \times \vec{a})[/tex] Or [tex]& \vec{a} \times \vec{b}=-\vec{b} \times \vec{a}[/tex]

As per the details share in the above question are as bellow,

The provided data are follow,

The product of two or more integers that remain the same, regardless of the sequence in which they are multiplied, is referred to as the commutative property formula for multiplication. The commutative property formula for multiplication is (A x B) = (B x A).

Let us consider, Let a = a1, a2, a3

And b=b1, b2, b3

We have the property that a × b = − b × a.

Then a × b = __ = (−1) __ =− b × a.

[tex]& \vec{a}=a_1 i+a_2 j+a_3 k \\ \vec{b}=b_1 i+b_2 j+b_3 k[/tex]

Then,

[tex]$$\vec{a} \vec{x} \vec{b}=\left|\begin{array}{ccc}i & j & k \\a_1 & a_2 & a_3 \\b_1 & b_2 & b_3\end{array}\right|$$[/tex]

[tex]$$=i\left(a_2 b_3-a_3 b_2\right)+j\left(a_3 b_1-a_1 b_3\right)+k\left(a_1 b_2-a_2 b_1\right)$$[/tex]

So further we get,

[tex]& =i\left(b_2 a_3-a_2 b_3\right)+j\left(a_1 b_3-a_3 b_1\right)+k\left(a_2 b_1-a_1 b_2\right) \\& =-\left[i\left(a_2 b_3-a_3 b_2\right)+j\left(a_3 b_1-a_1 b_3\right)+k\left(a_1 b_2-a_2 b_1\right)\right.[/tex]

So, we get,

[tex]\vec{a} \times \vec{b}=\left[i\left(a_2 b_3-a_3 b_2\right)+j\left(a_3 b_1-a_1 b_3\right)+k\left(a_1 b_2-a_2 b_1\right)\right.[/tex]

We get,

[tex]& \vec{b} \times \vec{a}=-[\vec{a} \times \vec{b}][/tex]

Or [tex]& -\vec{b} \times \vec{a}=\vec{a} \times \vec{b}[/tex]

Then,

[tex]& \vec{a} \times \vec{b}=(-1)(\vec{b} \times \vec{a})[/tex]

Or [tex]& \vec{a} \times \vec{b}=-\vec{b} \times \vec{a}[/tex]

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The current north of the wire fliws upwards as of the electric current straight upward.

The proper-hand thumb rule suggests the path of the magnetic area for a recognise path of the modern-day. If the thumb of the proper-hand factors alongside the path of modern-day then the curled arms of that hand offers the path of the magnetic area because of the modern-day.

The path of the magnetic area is perpendicular to the twine and is withinside the path the arms of your proper hand might curl in case you wrapped them across the twine together along with your thumb withinside the path of the modern-day.A vertical twine wearing a modern-day withinside the upward path is located in a horizontal magnetic area directed toward north.

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The medium with the shortest wavelength, if a 5 MHz sound wave is going through fat, air, muscle, and bone, is air.

The slowest sound speed is in air. The density and elasticity of the medium through which sound travels affects its speed. In general, sound travels more quickly through solids than through gases and liquids. The faster sound travels through a medium, the more elastic and less dense it is. Solid objects transmit sound the fastest. This is because sound waves can travel faster than through a solid medium through a liquid or gas because its molecules are so close together. In actuality, sound waves move over 17 times more quickly in steel than air. So as speed increases wavelength increases. Hence the speed of sound in air is lowest compare to other mediums. Therefore the air will have shortest wavelength of sound.

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They travelled 20 meter while breaking. Hence, option (2) is correct.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Initial speed of the car is: u = 21 m/s.

Final speed of the car: v = 8 m/s.

Time interval: t = 1.4 second.

Deceleration of the car: a = (u-v)/t = (21 - 8)/1.4 m/s^2 = 9.29 m/s^2.

Hence, the car traveled during deceleration:

s = ut - at^2/2

= (21×1.4) - 9.29×(1.4)^2/2 meter

= 20 meter.

Hence, option (2) is correct.

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In particles, electrons circle in shells comparing to principle quantum number n. In expanding request of n, the shells are named K, L, M, N, O, P, ...

For a shell of guideline quantum number n, there are subshells comparing to orbital quantum numbers (lowercase L) l = 0, 1, 2, ... , n - 1. Their names are s,p,d,f,... in expanding request of l.

Besides, for every l, there are 2l+ 1 potential attractive quantum numbers ml = 0, ±1, ±2, ... , ±l.

Each state (n,l,[tex]m_l[/tex]) can be involved by up to 2 electrons greatest, which should have  opposite spins (Pauli Exclusion Principle).

Likewise, there is a documentation called spectral notation for electron configuration. I'm certain you have seen it.

It is a succession of one metal more orbitals with their electron includes in the structure

[shell number][subshell name][tex]^[number of electrons][/tex]

Model, [tex]1s^22s^22p^6[/tex] for Neon implies 2 electrons in subshell s of the n=1 shell, 2 electrons in subshell s of the n=2 shell, and 6 electrons in subshell p of the n=2 shell. The just subshell for n=1 and both subshells for n=2 are completely filled and no electrons possess n>2 here, accordingly making  Neon inert (Noble gas).

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The net force acting on the cart is 2 N in left direction.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. Newton is the SI unit of force.

Jimi is pushing a large cart at work toward the left side of the store using 10N of force.

Jonah pushed the cart with 8 N of force toward the right side of the store.

Hence, the net force acting on the cart in left direction = ( 10 N - 8 N) = 2 N.

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A negative object so it takes in the charge object and nothing will happen until something else would touch it.

Electric charge is the property of a material that makes it feel a force when subjected to an electromagnetic field. Protons and electrons most typically carry positive and negative charges, which are the two forms of electric charges.

The basis of the SI system of physical units is the coulomb It is referred to as C. A coulomb is the unit of power that a one-ampere current can carry in one second.

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When we calculate a function's average rate of change over a certain interval, we are computing the average number of units that the function moves up or down per unit along the xx-axis.

Given the function and interval of interest (f(x)f(x) and [x ₁,x₂]), [x\s​₁,x₂ ]), our first step is to compute the value of our function at both ends of the interval. Then we plug those numbers and the interval's ends into our algorithm to calculate the average rate of change.

The average rate of change formula is

{x₂-x₁}

x f = x₂ x 1 f(x₂ )

​​within the interval [x₁,x ₂][x ₁,x ₂ ].

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Running slowly is a grandfather clock. Its pendulum has an excessively lengthy period. You can speed up the clock by cutting the period in half. To do this, reduce the pendulum's length.

In order to allow it to freely swing, a weight is suspended from a pivot like a pendulum. The restoring force from gravity will cause a pendulum to accelerate back toward its equilibrium position when it is sideways moved from its resting, equilibrium position. The pendulum swings back and forth about the equilibrium position after being freed due to the restoring force acting on its mass. The period is the length of time required for one full cycle, which includes both a left and right swing. The length of the pendulum and, to a lesser extent, its amplitude, or swing breadth, both affect the period.

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The internal shear in terms of x for [tex]$0 \leq x \leq 6 \mathrm{ft}$[/tex], where x is in ft. will be[tex]V_x & =A_y-400 \times x =1900-400 x[/tex]

A free-body diagram is a graphical representation used in physics and engineering to show the applied forces, moments, and consequent reactions on a body in a specific situation. It shows a body or group of connected bodies together with all the applied forces, times, and responses that the bodies experience.

Potential energy and equilibrium are related in that the body's potential energy is lower in such an equilibrium.

In this case, the state generates a force that does not resist the displacement when a little distance displaces the body.

Draw the free-body diagram as shown below.

Consider the moment equilibrium condition about B.

[tex]$$\begin{aligned}& M_B=0 \\& A_y \times 9-400 \times 6 \times\left(\frac{6}{2}+3\right)-900 \times 3=0 \\& A_y=1900 \mathrm{lb}\end{aligned}$$[/tex]

Write the internal shear force equation for [tex]$0 \leq x \leq 6 \mathrm{ft}$[/tex].

[tex]V_x & =A_y-400 \times x =1900-400 x[/tex]

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The complete question should be:

Express the internal shear in terms of x for [tex]$0 \leq x \leq 6 \mathrm{ft}$[/tex], where x is in ft.

Express your answer in terms of x. Express your answer using three significant figures.

Answer: Fg = 265.68 N

Explanation:

Fg = m * g

m = Fg / g

m = 1607.2 N / 9.8 m/s^2

m = 164 kg

Fg = m * g

Fg = 164 kg * 1.62 m/s^2

Fg = 265.68 N

Answer:

To calculate the work done by the electrostatic field in moving a charge from one point to another, you can use the formula:

work = charge * (final potential - initial potential)

In this case, the charge is 2 coulombs, the initial potential is 20V, and the final potential is -5V. Plugging these values into the formula, we get:

work = 2 coulombs * (20V - (-5V))

= 2 coulombs * (25V)

= 50 Joules

Therefore, the work done by the electrostatic field in moving the charge from one point to another is 50 Joules.

If a ball is thrown at an initial horizontal velocity of 3.6 meters per second off of a cliff that is 19.6 meters high, it will land 35.28 meters away from the cliff.

The vectoral expression of a particle and object's motion with respect towards time is called its velocity. The recognized unit for measuring magnitude of velocity is indeed the meters per second (m/s), which is frequently referred to as speed. Velocity is the rate at which an object's position is changing as perceived from a particular point of view and so as measured by a certain unit of time. It refers to the direction speed of the an object in motion.

Average speed is calculated by dividing a quantity by the time required to obtain that quantity. Speed in the SI is expressed in m / sec. The average speed (S) is calculated using the equation S = d/t, where d is the entire distance traveled and t denotes the total time. One can determine an object's beginning velocity by dividing the time it took the thing to go a specific distance by the total distance.

D = (1/2) gt2 where g = 9.8 m/s2

It takes time to descend the 19.6-meter cliff.

19.6 = 1/2(9.8)t2

19.6/4.9 = t2

Square root 90.4 = about 9.8 sec.

3.6 m/s x 9.8 sec = 35.28 m

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Answer:

Below

Explanation:

Only the HORIZONTAL force ,  F cos 41.7   moves the spreader forward

 The acceleration = change in V / change in t = 1.39/1.7 = .818 m/s^2

F = m * a

F cos 41.7 = 12.9 * .818        shows F = 14.12  N

The coefficient of static friction when the speed of the disk is given, is calculated to be 0.065 / r.

The maximum velocity of an object moving in a curve beyond which it will slide off the curve is given by the relationship,

v = √(μ* g* r) ----(1)

where  is the coefficient of friction between the object and the surface of the curve, g is acceleration due to gravity and r is the radius of the curve.

Given that,

v = 0.8 m/s

g = 9.8 m/s²

r = ?

μ = ?

Making μ as subject, we have,

μ = v²/(g*r) ----(2)

As we were not given the value of r, we can just substitute other known values, then solve and leave the answer in terms of r.

μ = (0.8)²/(9.81* r) = 0.64/ (9.81* r) = 0.065 / r

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The work done by a force is 40.14 J

The work done is calculated to include both the force applied to the body and the overall movement of the body. There is a constant force F in front of this block. The purpose of this force is to move an object a certain distance d in a straight line in the direction of the force.

The cart is lifted to a height, h:

h = (10meters) ×sin(4) = 0.69 m

The force in the vertical direction is:

Fy = 12N×sin(29o) = 58.177N

Work = F×d = (58.177)×(0.69) = 40.14 joules

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They are so distant that the parallax is too small to be measured since parallax varies inversely with distance.

Parallaxes can be measured accurately out to distances of approximately 100 light-years. The nearest galaxies are about 50,000 to 80,000 light-years from the Sun. Therefore, there is no perceptible change in the apparent position of any galaxy as we view it from opposite sides of Earth's orbit.

Because of the influences of the Earth's atmosphere, it is highly challenging to estimate parallax angles of less than 0.01 arcsec from Earth. Due to this, telescopes on Earth can only measure the distances to stars that are 1/0.01 or 100 parsecs distant.

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The rest mass m of a particle traveling with the speed of light in the laboratory frame is 0.

We know that, formula for mass of object can be given by:

m= [tex]\frac{m_{0} }{1-\sqrt{v^{2}/c^{2} } }[/tex]

where

m = mass of object

[tex]m_{0}[/tex] = rest mass

v = speed of the particle

c = speed of light

By Modifying this equation we get :

Given speed of particle is equal to speed of light.

i.e. v = c.

Putting this value in above equation we get [tex]m_{0}[/tex] =0.

Therefore, the rest mass  of a particle traveling with the speed of light in the laboratory frame is 0.

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The digits on the left side of the number 3 remain the same when it is less than 5, however the digits on the right side of the number 3 and 3 are replaced by zero. done work=-180 J

We are informed that

Constant force = F = (33 N)i - (41 N) j

Displacement=s=(-9.4m)i-(3.1m)j

We must locate the completed work.

Done work = F.s.

Using the equation

Working = (33i-41j).

(-9.4i-3.1j)

Work completed: 33. (-9.4)

i+41j.3.1j

Making use of the rules i.i=j.j=k.k=1, i.j=j.k=k.i=i.k=k.j=j.i=0, and

Finished work: -310.1+127.1

Finished work: 183.1 J

Answers must be written with two significant figures.

The digits on the left side of 3 remain the same when the unit's digit 3 is less than 5, however the digits on the right side of 3 and 3 will be replaced by 0.

done work=-180 J

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According to the given statement 11.38 T is the magnitude of the magnetic field inside the solenoid.

By using the symbol |v|, the strength of a vector theorem can be utilized to determine the length for such a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point. The range calculation, which we will go over in this section, is used to determine the vector's magnitude.

Length of solenoid, L = 2.5 cm = 0.025 m

Radius of solenoid, r = 0.55 cm = 0.0055 m

Number of turns, N = 45 turns

Current, I = 1.15 A

Magnetic field, B, is given as:

B = (N*r*I) /L

B = (45 * 0.0055 * 1.15)/0.025

B = 11.38 T

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The complete question is-

A solenoid of length 2.50 cm and radius 0.550 cm has 45 turns. If the wire of the solenoid has 1.15 amps of current, what is the magnitude of the magnetic field inside the solenoid?

The resistance of the resistor is 1.8Ω

Consider the voltage across the inductor 4 sec after the switch is closed is V(4)

The voltage across the inductor 4 sec after the switch is closed is 80%  of its maximum value, i.e., V(4)=0.8[tex]V_{0}[/tex]

Consider the expression for the voltage across the RL circuit.

V(t)=[tex]V_{0}e-\frac{t}{T}[/tex]

Where [tex]V_{0}[/tex] is the maximum voltage, t is the time, V(t) is the voltage at time

t and T is the time constant.

Substitute the values of ,[tex]V_{0}[/tex], V(t) and t in the above expression.

[tex]$$\begin{aligned}0.8 \mathrm{~V}_0 & =\mathrm{V}_0 \times \mathrm{e}^{-\frac{4}{\tau}} \\0.8 & =\mathrm{e}^{-\frac{4}{\tau}} \\\frac{1}{0.8} & =\mathrm{e}^{\frac{4}{\tau}}\end{aligned}$$[/tex]

Take natural log on both the sides.

[tex]$$\ln \left(\frac{1}{0.8}\right)=\frac{4}{\tau}$$[/tex]

Rearrange the above expression.

[tex]$$\begin{aligned}\tau & =\frac{4}{\ln \left(\frac{1}{0.8}\right)} \\& =17.9 \mathrm{~s}\end{aligned}$$[/tex]

Now consider the expression for time constant.

[tex]$$\tau=\frac{\mathrm{L}}{\mathrm{R}}$$[/tex]

Where R is the inductance and L is the resistance.

Rearrange the above expression.

R = [tex]\frac{L}{T}[/tex]

Substitute the values of T and L in the above expression.

[tex]R=\frac{34}{17.9}\\ R=1.8[/tex]Ω.

Therefore, the resistance of resistor is 1.8Ω

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The image will be formed beyond 2f if the object has been kept between f and 2f in a convex lens.

Any converging lens is referred to as a convex lens.

A lens that converges light rays that are moving parallel to its main axis is known as a converging lens or convex lens.

The distance between a lens's center and its focus is known as the focal length, or f, of a lens.

When an item is positioned along a line perpendicular to the center of the lens, between infinity and twice the object's distance from the focal point,

The image will be situated between the focal point, f, and twice the focal point's distance, 2f.

Consequently, for an object positioned along a line perpendicular to the center of the lens between infinity and 2f.

The image created by a convex lens when an item is positioned between F and 2F is magnified, real, inverted, and beyond 2F.

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You're in a boat with a big rock, in a swimming pool. You toss the rock overboard. Level of water will increase as of the mass of big rock to the level of the water in the pool.

The buoyancy of any floating object partially or totally submerged in a fluid can be computed thanks to Archimedes' principle. The weight of the thing alone exerts a downward mass on it. The upward or buoyant force acting on the object is what is meant by the aforementioned Archimedes' principle. The difference between the buoyant force and the object's weight is therefore the net force acting on it. In the event that this net force is positive, the item will rise; in the event that it is negative, the object will sink; and in the event that it is zero, the object will be neutrally buoyant, remaining stationary. Simply said, when a body is partially or entirely submerged in a fluid, the Archimedes' principle applies. Consider a cuboid submerged in a fluid, with its top and bottom facing in the direction of gravity, which is considered to be constant throughout the length of the cube. Each face of the fluid will experience a normal force, but only the normal forces on the top and bottom will result in buoyancy. The height directly affects the pressure difference between the top and bottom faces (difference in depth of submersion). A net force on the cuboid is created by multiplying the pressure difference by the area of a face.

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The kinetic energy of another body having three times the mass of the given object will be 108 J

Kinetic energy-In physics, the kinetic energy of an object is the energy  it has due to  motion. It is defined as the work required to accelerate a body from a given mass from rest to a specified speed.

The kinetic energy of a body is given by [tex]K.E= \frac{1}{2}Mv^{2}[/tex] (first equation)

Given K.E= 36J

Now the mass of second body is m=3M

also the second body is moving with the same speed v

So kinetic energy of second body K.E₂= [tex]\frac{1}{2}mv^{2} =\frac{1}{2}(3M)v^{2}[/tex]=36×3

=108J (from first equation)

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There is a transverse sinusoidal wave on a string that flows in a straightforward harmonic fashion and has an angular frequency that matches the wave. (Chose c.)

An energetic disturbance called a wave moves from one place to another. Every time a wave moves, energy is changed, regardless of the change. The substance through which a wave passes is known as the medium. Back and forth oscillations occur repeatedly in that medium.

A wave is a disruption or variation that progressively moves energy from one location in a medium to another. It could manifest as an elastomeric deformation or a shift in pressure, magnetic or electric field strength, electric potential, or temperature.

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For the distance between q 3 and q 1, the formula is: = 3 L 0 = 3 1 L = 3 1 10 cm 14 cm. Q3 should therefore be positioned at x=14 cm along the x-axis.

For q 3, there is no equilibrium position.

​between two fixed changes because one is pulling it and the other is pushing it

L is set at 10 cm, and L 0 is taken to be positive. We cancel k and q 3 and set this equal to zero as the problem specifies. As a result, we get L 0.

​∣q 1\s​\s ∣\s​\s − \s(L+L \s0\s​\s)\s∣q \s2\s​\s ∣\s​\s =0 ⇒(\sL \s0

​L+L \s0\s​

​\s ) \s2\s = \s∣\s∣\s∣\s∣\s∣\s​

q \s1\s​

q \s2\s​

∣\s∣\s∣\s∣\s∣\s​\s = \s∣\s∣\s∣\s∣\s∣

​+1.0 μC\s−3.0 μC

​=3.0 results in L 0 after taking the square root.

​L+L \s0\s​

For the distance between q 3 and q 1, the formula is: = 3 L 0 = 3 1 L = 3 1 10 cm 14 cm. Q3 should therefore be positioned at x=14 cm along the x-axis.

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