Answers
Answer:
[tex]\huge\color{skyblue}\boxed{\colorbox{black}{Answer ☘}}[/tex]
[tex]total \: resistance \: ( R_{t} ) = (3 + 1)ohm \\ (since \: the \: resistors \: are \: connected \\ in \: series)[/tex]
[tex]current \: flowing \: through \: circuit(I) = 2A \\ \\ now... \: by \: ohms \: law \\ V = IR\\ V = (2)(4) \\ = > 8v[/tex]
therefore , option (b) is correct!!hope helpful~
Related Questions
A particle starts from the origin at t = 0 with a velocity of 6.0 m/s and moves in the xy plane with a constant acceleration of (-2.0 + 4.0) m/s2. At the instant the particle achieves its maximum positive x coordinate, how far is it from the origin
Answers
Answer:
9sqrt4
Explanation:
Assuming you mean 6.0i m/s and (-2.0i + 4.0j) m/s^2:
The maximum positive x coordinate is when the time is 3 seconds, because the horizontal velocity will be zero, and therefore will be a turning point, where after that point the x coordinate will only be more negative.
After 3 seconds the x coordinate is 6*3+1/2*-2*3^2=9, and the y coordinate will be 1/2*4*3^2=18.
The distance from the origin is sqrt(9^2+18^2) = 9*sqrt(1+4)
At the instant the particle achieves its maximum positive x coordinate, the displacement is 4.03 m.
Displacement of the particle
The displacement of the particle is calculated as follows;
v² = u² + 2as
where;
a is accelerationa = √(2² + 4²) = 4.47 m/s²
0 = u² + 2as
s = -u²/2a
s = -(6²)/(2 x 4.47)
s = -4.03 m
Thus, at the instant the particle achieves its maximum positive x coordinate, the displacement is 4.03 m.
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The potential difference between the (high-voltage) inner shell of a Van de Graaff accelerator and a point where the charge is injected into the moving belt is 3.4 MV. What is the minimum power required to pull the belt when the belt transfers the charge to the case at 2.8 mC/s?
Answers
Explanation:
this is the answer to the questions
when do we say a curvilinear motion is accelerated?
Answers
Answer:
There always is an acceleration in a curvilinear motion, as the velocity vector changes, so always.
14. Earthworms are crucial for forming soil. As they search for food by digging tunnels,
they expose rocks and minerals to the effects of weathering. Over time, this process
creates new soil. Worms are not the only living things that help to create soil. Plants
also play a part in the weathering process. As the roots of plants grow and seek out
water and nutrients, they help to break large rock fragments into smaller ones. Have
you ever seen a plant growing in a sidewalk? As the plants grows, its roots spread into
tiny cracks in the sidewalk. These roots apply pressure to the cracks, and, over time,
the cracks become larger, ice wedging can occur more readily. As the cracks expand,
more water can flow into them. When the water freezes, it expands and presses against
the walls of the cracks, which makes the cracks larger. Over time, the weathering
caused by water, plants, and worms help to form soil. QUESTION: Ice wedging, as
described in the passage, is an example of which of the following?
A mechanical weathering
B. Oxidation
C. chemical weathering
D. Hydrolysis
Answers
Ice wedging, as described in the passage, is an example of mechanical
weathering.
Mechanical weathering is also known as physical weathering and it
involves the breaking of rock into smaller particles without causing changes
in the chemical properties.Mechanical weathering is usually carried through
physical processes such as freezing and thawing etc.
In this scenario, we were told that water freezes, expands and presses
against the walls of the crack thereby breaking into smaller parts which is a
physical process hence mechanical weathering being present.
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Use the equation of motion to answer the question. Use the equation of motion to answer the question.
x=x0+v0t+12at2
An object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?
Answers
The final position of the object after 2 s is 11 m.
Motion: This can be defined as the change in position of a body.
⇒ Formula:
x = x₀+v₀t+1/2(at²)........................ Equation 1⇒ Where:
x = Final position of the objectx₀ = Starting positionv₀ = Starting velocityt = timea = accelerationFrom the question,
⇒ Given:
x₀ = 4.5 m/st = 2 sx₀ = 2ma = 0 m/s²⇒ Substitute these values into equation 1
x = 2+(4.5×2)+1/2(0²×2)x = 2+9+0x = 11 mHence, The final position of the object after 2 s is 11 m
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True or False. Isaac at first resisted his father's command to be the sacrifice.
Answers
What capacitance is needed to store 3μC of charge at a voltage of 120V?
Answers
Answer:
C = 0.025F
Explanation:
Charge =q=3×[tex]10^{-6}[/tex]C
Voltage=V=120V
Q=CV
C=Q/V
=3×[tex]10^{-6}[/tex]/120
=1/40×[tex]10^{-6}[/tex]
C = 0.025F
C=2.5 [tex]10^{-4}[/tex]C 0r 25 ×[tex]10^{-3}[/tex]F
Would you die if you take the car keys out of the ignition and throw them in the back seat while you coast down a mountain-side in an attempt to save fuel and look cool for the girl in said back seat.
Answers
Answer:
bro what.
Explanation:
... is this an actual physics question?
What are the two types of force
Answers
Answer:
Forces can be divided into primarily into two types of forces:
Contact Forces. Non-contact Forces.Explanation:
What is the relationship between and experiment and a hypothesis
Answers
Answer:
an experiment is a way to test a hypothesis. A hypothesis is a prediction. You predict that if you change one thing (the independent variable) the other thing (the dependent variable) will change.
The diagram below shows a child pulling a 50.-kg friend on a 20 kg sled by applying a 300. newton force on the sled rope at an angle of 40 degrees with the horizontal. The sled moves at constant velocity as the person pulls with the 300 N force.
Answers
The vertical component of the applied force on the sled is 192.84 N.
The given parameters:
Mass of the friend, M = 50 kgMass of the sled, m = 20 kgApplied force, F = 300 NInclination of the force, θ = 40 ⁰The vertical component of the 300 N force is calculated as follows;
[tex]F_y= F \times sin(\theta)\\\\F_y = 300 \times sin(40)\\\\F_y = 192.84 \ N[/tex]
Thus, the vertical component of the applied force on the sled is 192.84 N.
Your question is not complete, the missing part of the question is below:
The vertical component of the 300 N force is approximately?
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A 30.0 kg child, initially at rest, slides down a 2.0 m tall slide. The child reaches the bottom of the slide with a speed of 6 m/s. There is friction between the child and the slide. Write a Law of Conservation of Energy equation to represent the transfer of energy from the top of the slide to the bottom. a. b. Use the equation from part (b) to calculate the energy dissipated by friction between the slide and the child? (g = 9.81 m/s) = 13
Answers
Answer:
Explanation:
Total energy is constant
E = mgh + ½mv² + Fd
At the top of the slide, all energy is potential
E = mgh + 0 + 0
At the bottom of the slide, all potential energy has converted to kinetic and work of friction.
mgh = ½mv² + W
W = mgh - ½mv²
W = 30.0[(9.81)(2.0) - ½6²]
W = 48.6 J
Which combination of three concurrent forces acting on a body could not produce equilibrium?
1
1 N, 3N, EN
2
2 N, 2N, 2N
.
3.
3 N, 4N, EN
4.
4N, 4N, 5N
Answers
All the three concurrent forces acting on a body will not produce equilibrium.
The given parameters:
1. 1 N, 3 N and 5 N
2. 2N, 2N and 2 N
3. 3N, 4N and 5 N
4. 4N, 4N and 5 N
Concurrent forces lie on the same plane and their line of action pass through a common point.
A body under concurrent forces is in equilibrium if the resultant of the forces on the body is zero.
[tex]\Sigma F = 0\\\\F_1 + F_2 + F_3 = 0\\\\F_1 + F_ 2 = - F_3[/tex]
where;
[tex]F_3[/tex] is the equilibrant force
First set of concurrent forces;
[tex]1 \ N \ + \ 3\ N = 4 \ N\\\\F_ 3 = 5 \ N\\\\5 \ N > 4 \ N[/tex]
Second set of concurrent forces;
[tex]2 \ N \ + \ 2 \ N = 4 \ N\\\\F_ 3 = 2 \ N\\\\4 \ N > 2 \ N[/tex]
Third set of concurrent forces;
[tex]3 \ N \ + \ 4 \ N = 7 \ N\\\\F_ 3 = 5 \ N\\\\7 \ N > 5 \ N[/tex]
Fourth set of concurrent forces;
[tex]4 \ N \ + \ 4 \ N = 8 \ N\\\\F_ 3 = 5 \ N\\\\8 \ N > 5 \ N[/tex]
Thus, we can conclude that all the three concurrent forces acting on a body will not produce equilibrium.
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At the end of meiosis II, the new haploid cells in humans are known as which of the following?
Diploid cells
Embryo
Zygotes
Gametes
Answers
3. How much power does an electric light installation draw at 120 V if it creates a current of 0.8 amps?
O A. 32 watts
O B. 120 watts
Q C. 48 watts
D. 96 watts
Answers
Answer:D
Explanation:
R =
V
I
=
120 volt
0.8 ampere
= 150 ohm (Ω)
P = V × I
= 120 volt × 0.8 ampere
= 96 watt (W)
An electric light installation can draw Power of 96 Watt at 120 V if it creates a current of 0.8 amps
What is electric power ?Electric power is the rate of electric energy transfer by an electric circuit per unit time . It is denoted by P and measured using the SI unit of power that is Watt (W)
since, Electric Power = voltage * current
Power = 120 V * 0.8 A
Power = 96 Watts
An electric light installation can draw Power of 96 Watt at 120 V if it creates a current of 0.8 amps
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A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point 6i-8j m. How much work is done by the given force during this displacement
Answers
Answer:
Explanation:
Only force in the direction of motion does work
The force acts in the x direction
The x change of position was 6 m
W = Fd = 12(6) = 72 J
The work done by the given force during this displacement is determined as 120 J.
Work done on the objectThe work done on the object is calculated as follows;
W = Fd
where;
d is the displacement of the objectd = √(6² + 8²)
d = 10 m
W = 12 x 10
W = 120 J
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The ability to do work and cause change is called
Answers
Answer:
I am pretty sure it is called energy.
An LED is useful because when a current passes through it, it gives out... what?
Enter your answer
Answers
An LED is useful because when a current passes through it, it gives out light.
An LED is useful because when a current passes through it, it gives out Light.
What is an LED?
LED, in full light-emitting diode, in electronics, a semiconductor device that emits infrared or visible light when charged with an electric current.
A light-emitting diode (LED) emits light by applying a forward current to the pn junction of a compound semiconductor.
When forward current is passed through the light-emitting diode, carriers (electrons and holes) move. The holes in the p-type region move to the n-type region and the electrons in the n-type region move to the p-type region. The injected carriers recombine, and the energy difference before and after recombination is released as light. The emitted light depends on the energy band gap (Eg) of the compound semiconductor.
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A stone of mass m = 1.05 kg is released from a height of h = 2.1 m into a pool of water. At a time of t = 1.83 s after hitting the surface of the water, the stone's velocity has decreased by 50%.
What is the magnitude of the average force the stone experiences, in newtons, during the time t?
Answers
Answer:
Explanation:
ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted
½mv² = mgh
v = √(2gh)
v = √(2(9.81)2.1) = 6.4188... m/s
after impact, an impulse will result in a change of momentum.
There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.
FΔt = mΔv
(F - mg)Δt = m(vf - vi)
(F - mg) = m(vf - vi)/Δt
F = m(vf - vi)/Δt + mg
F = m((vf - vi)/Δt + g)
F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)
F = 12.14198...
F = 12.1 N
The magnitude of the average force the stone experiences, will be 12.1 N.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The given data in the problem is;
m is the stone mass = 1.05 kg
The height is h, = 2.1 m i
The time is, t = 1.83 s
Velocity decreased by 50%.
From the law of conservation of energy the kinetic energy is equal to the potential energy;
[tex]\rm \frac{1}{2} mv^2 = mgh \\\\ v = \sqrt{2gh}\\\\ v = \sqrt{2 \times 9.81 \times 2.1 } \\\\ v= 64188 \ m/sec.[/tex]
From Newton's second law of motion, the impulsive force is equal to the change in momentum;
[tex]\rm F \triangle T = m \traingle v \\\\ (F - mg) = \frac{v_f-v_i}{\triangle t } \\\\ F = \frac{v_f-v_i}{\triangle t } + mg \\\\ F =m\frac{v_f-v_i}{\triangle t + g} \\\\ F= 12.14 98 \\\\ F=12.1 N[/tex]
Hence the magnitude of the average force the stone experiences, will be 12.1 N.
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Which is the answer
Answers
Answer:
no idea thanks you veryuch
Lisa runs up 4 flights of stairs in 22 seconds. She weighs 510 Newtons. If each flight rises 310 cm: (a) What is her change in potential energy? (b) What average power (watts) was required during the 22 s?
Answers
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
Potential energy is the amount of energy possessed by a body due to its position relative to another object.
a) Potential energy = weight * height = 510 N * 4 flight * 3.1 m per flight
Potential energy = 6324 Joules
b) Power = Energy / time = 6324 Joules / 22 seconds = 263.5 Watts
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
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As a truck rounds a curve, a box in the bed of the truck slides to the side farthest from the center of the curve. This movement of the box is a result of
Answers
Answer:
inertia .
because yes
Suppose a bulldozer is being hauled at 50 km/h to a construction site on the back of a flatbed truck. From which reference point would the bulldozer not appear to be moving?
Answers
Answer:
from someone watching the bulldozer from the cab of the truck or from elsewhere on the flatbed.
Explanation:
A book is at rest on a flat table. The book is pushed across the table, causing it to move
and eventually come to rest again. How does the potential and kinetic energy change
during this process? (1 point)
The potential and kinetic energy will stay the same unless the book speeds
up or slows down
The potential energy increases as the book is pushed across the table.
The kinetic energy stays the same.
The potential energy will stay the same as long as the book stays on the
table. The kinetic energy increases as the book is pushed across the table.
The potential and kinetic energy decreases as the book comes to rest
again
Answers
Answer:
Explanation:
As no altitude or mass changed, the potential energy remained constant.
The potential energy will stay the same as long as the book stays on the
table.
Kinetic energy went from zero at rest to a positive value while moving, and then returned to zero when the book was at rest again.
The kinetic energy increases as the book is pushed across the table.
the book has a mass of 2.5 kg. What net force must act on the book to mak it accelerate to the left at a rate of 7.0m/s2?
Answers
Answer:
17.5 N
Explanation:
Given :Mass (m) = 2.5 kgAcceleration (a) = 7.0 m/s²To calculate :Force exerted (F)Calculation :• F = ma→ F = (2.5 × 7.0) N
→ F = 25/10 × 7 N
→ F = 5/2 × 7 N
→ F = (5 × 7)/2 N
→ F = 35/2 N
→ F = 17.5 N towards left
Hence, 17.5 N of net force must act on the book to make it accelerate to the left.
Consider the following force:
A horse is pulling forward on a wagon with a force of 200 N.
According to Newton's third law, what other force must be happening?
The horse is pushing backward on the wagon with a force of 200 N.
The ground is pushing backward on the horse with a force of 200 N.
The wagon is pulling backward on the horse with a force of 200 N.
Answers
Newton’s third law states that when two objects interact, they will exert an equal and opposite force on each other
So if the horse pulls the wagon, the wagon will also pull the horse
One indicator NOT related to domestic violence is
violent attitudes
good nutrition
violations of court orders
substance abuse
Answers
Answer:
good nutrition
Explanation:
I think that one's pretty self explanatory
1. The acceleration equation of a certain particle is a=2t, after 4s, its velocity reaches 20m/s, then the initial velocity of the particle movement is ) ms B Sms 2.
Answers
Answer:
Change in velocity is the integral of all the differential accelerations acting over the period of acceleration.
[tex]20 = u + \int\limits^4_0 {2t} \, dt[/tex]
20 = u + t²[tex]\left \{ {{4} \atop {0}} \right.[/tex]
20 = u + 4² - 0²
20 = u + 16
u = 4 m/s
Q1) Assertion : a vector can be resolved into maximum two components
Reason : in projectile motion the velocity is resolved into vertical and horizontal components
a) Both A and R are correct; R is the correct explanation of A
b) Both A and R are correct; R is not correct explanation of A
c) A is correct; R is not correct
d) A is not correct; R is correct
Q2) Assertion : speed is constant in uniform circular motion
Reason : acceleration is constant in uniform circular motion
a) Both A and R are correct; R is the correct explanation of A
b) Both A and R are correct; R is not correct explanation of A
c) A is correct; R is not correct
d) A is not correct; R is correct
Answers
Answer:
Explanation:
Q1) d) A is not correct; R is correct (sort of) but is not the reason for A.
A vector may be resolved into an infinite number of components.
Breaking a projectile motion into the vertical and horizontal components is the EASIEST way to solve it because acceleration can be assumed to be constant in both directions. Zero for horizontal and g(ravity) in the vertical. However it is not the ONLY way to do it. Other ways are much more complex.
Q2) a) Both A and R are correct; R is the correct explanation of A (sort of)
A is correct. Speed is constant in uniform circular motion.
R is correct if you call CENTRIPETAL acceleration constant. It is only constant in magnitude. The direction is always changing as the vector always points toward the center of rotation.
Transverse waves move particles back and forth along the same direction in which the waves travel.
True false question.
True
False
Answers
Answer:
False, I am pretty sure.
Explanation:
Transverse waves are always characterized by particle motion being perpendicular to wave motion. ... As a sound wave moves from the lips of a speaker to the ear of a listener, particles of air vibrate back and forth in the same direction and the opposite direction of energy transport.