If a cheetah could maintain its top speed of 120 km/h for 20 minutes, how far would it run?

Answers

Answer 1
Alright. If it’s running at a constant speed of 120 km/h, in one hour it will have traveled 120 kilometers. hence “kilometers per hour”

20 minutes is 1/3 of an hour so 120/3 will be 40

therefore, in 20 minutes the cheetah would’ve ran 40km if it maintained 120km/h for 20 minutes.

Related Questions

Determine the slope of this graph from zero seconds to five seconds.

Answers

Explanation:

(m2-m1)/t

25-0/5

25/5

5m/s

5 m/s. For every second on the graph, the line meets up with each multiple of 5 on the y (up and down) axis

Explain the difference between the justice system laws and scientific laws

Answers

This is the answer
Ur welcome

What is correct regarding an ideal isotropic antenna? a. An ideal isotropic antenna is a highly efficient antenna used extensively in today’s communication systems b. An ideal isotropic antenna is a specialized antenna used to direct EM signal energy towards a specific direction c. An ideal isotropic antenna is a theoretical antenna that does not exist in practice, but is useful in explaining power density and unguided EM signal attenuation d. None of the above are correct statements

Answers

Answer:

C An ideal isotropic antenna is a theoretical antenna that does not exist in practice, but is useful in explaining power density and unguided EM signal attenuation

Explanation:

Because practically speaking there is no ideal isotropic antenna it is only imaginary radiating in all directions and use as an arbitrary point for antenna gain

Two positive charges q1 = q2 = 2.0 μC are located at x = 0, y = 0.30 m and x = 0, y = -0.30 m, respectively. Third point charge Q = 4.0 μC is located at x = 0.40 m, y = 0.What is the net force ((a)magnitude and (b)direction) on charge q1 exerted by the other two charges?

Answers

Answer:

 F = 0.111015 N

Explanation:

For this exercise the force is given by Coulomb's law

        F = k q₁q₂ / r₂₁²

we calculate the electric force of the other two particles on the charge q1

Charges q₁ and q₂

the distance between them is

          r₁₂ = y₁ -y₂

          r₁₂ = 0.30 + 0.30

          r₁₂ = 0.60 m

let's calculate

          F₁₂ = 9 10⁹ 2 10⁻⁶ 2 10⁻⁶ / 0.60 2

          F₁₂ = 1 10⁻¹ N

directed towards the positive side of the y-axis

Charges 1 and 3

Let's find the distance using the Pythagorean Theorem

             r₁₃ = RA [(0.40-0) 2 + (0-0.30) 2]

             r₁₃ = 0.50 m

            F₁₃ = 9 10⁹ 2 10⁻⁶ 4 10⁻⁶ / 0.50²

            F₁₃ = 1.697 10⁻² N

The direction of this force is on the line that joins the two charges (1 and 3), let's use trigonometry to find the components of this force

           tan θ = y / x

           θ = tan⁻¹ y / x

          θ = tan⁻¹ 0.3 / 0.4

           tea = 36.87º

    The angle from the positive side of the x-axis is

         θ ’= 180 - θ

        θ ’= 180 - 36.87

        θ ’= 143.13º

       sin143.13 = F_13y / F₁₃

           F_13y = F₁₃ sin 143.13

           F{13y} = 1.697 10⁻² sin 143.13

           F_13y = 1.0183 10⁻² N

            cos 143.13 = F_13x / F₁₃

           F₁₃ₓ = F₁₃ cos 143.13

           F₁₃ₓ = 1.697 10⁻² cos 143.13

           F₁₃ₓ = -1.357 10-2 N

Now we can find the components of the resultant force

          Fx = F13x + F12x

          Fx = -1,357 10-2 +0

          Fx = -1.357 10-2 N

          Fy = F13y + F12y

         Fy = 1.0183 10-2 + ​​1 10-1

          Fy = 0.110183 N

We use the Pythagorean theorem to find the modulus

         F = Ra (Fx2 + Fy2)

         F = RA [(1.357 10-2) 2 + 0.110183 2]

         F = 0.111015 N

Let's use trigonometry for the angles

         tan tea = Fy / Fx

          tea = tan-1 (0.110183 / -0.01357)

          tea = 1,448 rad

to find the angle about the positive side of the + x axis

           tea '= pi - 1,448

           Tea = 1.6936 rad

The magnitude of the net force on q1 exerted by the other two charges is 0.357 N.

The direction of the net force on q1 is 50⁰.

The given parameters;

q1 = 2.0 μC located at (0, 0.3) mq2 = 2.0 μC located at (0, -0.3) mq3 = 4.0 μC located at (0.4, 0) m

The force on q1 due to q2 occurs only in y-direction and can be calculated using Coulomb's law as shown below;

[tex]F_1_2 = \frac{kq^2}{r^2}j = \frac{(9\times 10^9) \times (2\times 10^{-6})^2 }{(0.3 +0.3)^2} j \\\\\F_{12} = (0.1)j[/tex]

The force on q1 due to q3 occurs both in x-direction and y-direction, and it is calculated as follows;

[tex]distance \ between \ q1 \ and \ q3\ , r_{13} = \sqrt{0.3^2 \ + \ 0.4^2} = 0.5 \ m\\\\F_{13} = \frac{kq^2}{r_{13}^2} (\frac{0.4i}{0.5} \ + \ \frac{0.3j}{0.5} )\\\\F_{13} = \frac{kq^2}{r_{13}^2} (0.8i + 0.6j)\\\\F_{13} = \frac{9\times 10^9 \times (2\times 10^{-6}) \times (4\times 10^{-6})}{0.5^2} (0.8i + 0.6j)\\\\F_{13} = 0.288(0.8i + 0.6j)\\\\F_{13} = 0.23i + 0.173j[/tex]

The net force is calculated as follows;

[tex]F_{net} = F_{12} \ + \ F_{13}\\\\F_{net} = (0.1j) \ + \ (0.23i + 0.173j)\\\\F_{net} = (0.23i + 0.273j)[/tex]

The magnitude of the net force on q1 is calculated as follows;

[tex]|F| = \sqrt{(0.23^2) \ + \ (0.273^2)} \\\\|F| = 0.357 \ N[/tex]

The direction of the net force on q1 is calculated as follows;

[tex]tan(\theta )= \frac{F_y}{F_x} \\\\\theta = tan^{-1} (\frac{0.273}{0.23} )\\\\\theta = 50^0[/tex]

Learn more here:https://brainly.com/question/17132341

Can air make shadows

Answers

Answer:no

Explanation:the way to see air is by steaming something sometimes you might not see the air but you can see the shadow

Light travels at 3 × 108 m/s, and it takes about 8 min for light from the sun to travel to Earth. Based on this, the order of magnitude of the distance from the sun to Earth is g

Answers

Answer:

The order of magnitude of the distance from the sun to Earth is 10⁸ km.

Explanation:

The order of magnitude of the distance from the sun to Earth can be calculated as follows:

[tex] c = \frac{x}{t} [/tex]

Where:

c: is the speed of light = 3x10⁸ m/s

t: is the time = 8 min

Hence, the distance is:

[tex] x = c*t = 3 \cdot 10^{8} m/s*8 min*\frac{60 s}{1 min} = 1.44 \cdot 10^{11} m = 1.44 \cdot 10^{8} km [/tex]

Therefore, the order of magnitude of the distance from the sun to Earth is 10⁸ km.

I hope it helps you!

Why si unit develop all over the world?​

Answers

Answer:

SI unit is used in most places around the world, so our use of it allows scientists from disparate regions to use a single standard in communicating scientific data without vocabulary confusion.

Explanation:

hope it helps

Si unit is used almost all around the world, so our use of it allows

Scientist from disparate regions to use a single standered in communicating scientific data without vocabulary confusion

Circle all true statements:
a) Water at 90°C is warmer than water at 202°F
b) 40K corresponds to -40°C
c) Temperature differing by 25 on the Fahrenheit scale must differ by 45 on the Celsius scale.
d) Temperatures which differ by 10 on the Celsius scale must differ by 18 on the Fahrenheit scale.
e) 0°F corresponds to -32°C.

Answers

Answer:

The true statements are:

c) Temperature differing by 25 on the Fahrenheit scale must differ by 45 on the Celsius scale.

d) Temperatures which differ by 10 on the Celsius scale must differ by 18 on the Fahrenheit scale.

Explanation:

option a is false, 90°C is equal to 194°F which is not warmer than 202°F

option b is false, 40K is equal to -233°C

option e is false 0°F corresponds to -17.8°C.

A ball easily moves but not a bus when we push them. why?

Answers

Answer: The amount of matter is higher in a bus than a ball.

Explanation:

The mass of a high speed train is 4.5×105 kg, and it is traveling forward at a velocity of 8.3×101 m/s. Given that momentum equals mass times velocity, determine the values of m and n when the momentum of the train (in kg⋅m/s) is written in scientific notation.

Answers

Answer:

The value of m = 3.735 and the value of n = 7.

Explanation:

The equation for the momentum of the train is,

                                          P = mv  

Here, m is the mass of the train and v is the speed of the train.

Substitute [tex]4.5 \times {10^5}{\rm{ kg}} , 8.3 \times {10^1}{\rm{ m/s}}[/tex] for m and v respectively in above equation.

[tex]\begin{array}{c}\\P = \left( {4.5 \times {{10}^5}{\rm{ kg}}} \right)\left( {8.3 \times {{10}^1}{\rm{ m/s}}} \right)\\\\ = 37.35 \times {10^6}{\rm{ kg}} \cdot {\rm{m/s}}\left( {\frac{{{{10}^1}{\rm{kg}} \cdot {\rm{m/s}}}}{{10\,{\rm{kg}} \cdot {\rm{m/s}}}}} \right)\\\\ = 3.735 \times {10^7}{\rm{ kg}} \cdot {\rm{m/s}}\\\end{array}[/tex]  

According to the scientific notation, here the value of m is 3.735 and the value of n is 7 in the final answer of the momentum.

                        The value of m = 3.735 and the value of n = 7.

Which lists the elements in order from most conductive to least conductive?

potassium (K), selenium (Se), germanium (Ge)
germanium (Ge), potassium (K), selenium (Se)
selenium (Se), germanium (Ge), potassium (K)
potassium (K), germanium (Ge), selenium (Se)

Answers

Answer:

Answer: potassium (K) germanium (Ge) selenium (Se)

Explanation:

I just took the test, the farther to the right on the periodic table you go the less conductive it gets.

Answer:

Answer: potassium (K) germanium (Ge) selenium (Se)

Explanation:

The most conductive to least conductive is from left to right

Scientists might use a diagram to model the water cycle. What are two
benefits of this model?

Answers

Answer:

B, and D

Explanation:

The two benefits of this model is it specify a process that is very complex. It can represent changes that occur very slowly. Thus option B and D is correct.

What is water cycle?

The water cycle is defined as a cycle of events that involves precipitation as rain and snow, drainage in streams and rivers, and return to the atmosphere by evaporation and transpiration. Water moves through this cycle between the earth's oceans, atmosphere, and land.

It can also be defined as the route all water takes as it travels around Earth in various conditions.

There are basically six stages of water cycle.

EvaporationSublimationCondensationPrecipitationInfiltrationRunoff

Thus, the two benefits of this model is it specify a process that is very complex. It can represent changes that occur very slowly. Thus option B and D is correct.

To learn more about water cycle, refer to the link below:

https://brainly.com/question/1151425

#SPJ5

Place gamma rays, infrared, microwaves, radio waves, ultraviolet, visible light, and x-rays in order from largest wavelength to smallest wavelength.

Answers

Answer:

Going by EM SPECTRUM WE HAVE

radio waves, microwaves, infrared, VISIBLE LIGHT, ultraviolet, X-rays, GAMMA RAYS

Explanation:

BECAUSE

V= WAVELENGTH/ FREQUENCY

AS FREQUENCY INCREASES WAVELENGTH DECREASE AN VICE VERSA

What is the latitude of the vertical (direct) rays of the sun?

Answers

Answer:

23.5 degree North

Explanation:

The latitude of the vertical (direct) rays of the sun is 23.5 degree North. This is however due to the sun's vertical rays being located directly above 23.5 degree South which is the position of the Tropic of Capricorn.

The sun ray is highest at this pap tion and it occurs during Summer solstice which happens between June 21 / 22 of every year.

An isolated system contains two objects with charges q1q1 and q2q2. If the charge on object 1 is doubled, what is the charge on object 2? g

Answers

Answer:

The new charge on the second object is q₂ - q₁

Explanation:

Given;

charge on the first object,  q₁

charge on the second object, q₂

Since there is no external force on isolated system, the total charge in the system is given by;

Q = q₁ + q₂

q₂ = Q - q₁

When the charge on object 1 is doubled, q₁' = 2q₁

let q₂' be the new charge on object 2

q₂' = Q - q₁'

q₂' = (q₁ + q₂) - 2q₁

q₂' = q₁ + q₂ - 2q₁

q₂' = q₂ - q₁

Therefore, the new charge on the second object is q₂ - q₁

The charge on object 2 will be "q₂ - q₁".

Charge on object:

The charge's quantity on such an item represents the degree of imbalance between its electrons as well as protons.

Just to calculate the overall charge of a positively (+) charged item, divide the total no. of valence electrons by the overall number of protons.

According to the question,

Object 1's charge = q₁

Object 2's charge = q₂

Let,

New charge of object 2 be "q₂'".

 

The total charge in the system will be:

Q = q₁ + q₂

or,

q₂ = Q - q₁

hence,

The charge on object 2 be:

q₂' = Q - q₁'

By substituting the values,

        = (q₁ + q₂) - 2q₁

        = q₁ + q₂ - 2q₁

        = q₂ - q₁                

Thus the answer above is appropriate.

Find out more information about charge here:

https://brainly.com/question/25922783

How do you play Simon says?

Answers

This is how you play
One person is Simon
If the person who is Simon say “Simon say (direction)” you do it but if he doesn’t say Simon says don’t do it or your out

The acceleration of a piston is given by : rw^2 cos(wt-pi/4) find amplitude.

Answers

Given :

The acceleration of a piston is given by :

[tex]a=r\omega^2cos\ (\omega t-\dfrac{\pi}{4})[/tex]

To Find :

The amplitude of the acceleration of piston .

Solution :

Now , acceleration is :

[tex]a=r\omega^2cos\ (\omega t-\dfrac{\pi}{4})[/tex]

Now , amplitude is maximum of any function .

So , maximum value of [tex]cos\ \theta[/tex] is equal to 1 .

Therefore , amplitude of the acceleration of piston is :

[tex]A=r\omega^2[/tex]

Hence , this is the required solution .

[tex]\huge{\gray{\sf Question:} }[/tex]

A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is (a) 5 cm, (b) 3 cm and (c) 0 cm.​

Answers

Answer:

ANSWER

A = 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

plz give brainlist

hope this helped

Answer:

[tex]here \: amplitude = 5cm (convert \: to \: si \: unit) = .05m \\ t = .2sec \\ omega = \frac{2\pi}{t} \\ = \frac{2\pi}{.2 } = 10\pi \frac{rad}{s} \\ we \: want \: find \: a \: and \: v \\ we \: know \: that \: a = - {omega}^{2} x \\ v = omega \sqrt{ {r}^{2} - {x}^{2} } \\(1)x = .05m \\ a = - {10\pi}^{2} \times .05 = - 5 {\pi}^{2} \frac{m}{ {s}^{2} } \\ v = 10\pi \sqrt{ {.05}^{2} - {.05}^{2} } = 0 \\ 2)x = 3cm = .03m \\ a = {(10\pi)}^{2} \times .03 = - 3 {\pi}^{2} \frac{m}{ {s}^{2} } \\ v = 10\pi \sqrt{ {.05}^{2} - {.03}^{2} } = 10\pi \times .04 = .4\pi \frac{m}{s} \\ 3)x = 0 \\ a = - {(10\pi)}^{2} \times 0 = 0 \\ v = 10\pi \times \sqrt{ {.05}^{2} - {0}^{2} } = - 10\pi \times .05 = .5\pi \frac{m}{s} \\ thank \: you[/tex]

Convert the following to SI units:_______. a. 9.12μs9.12μs b. 3.42 km c. 44 cm/ms d. 80 km/h

Answers

Answer:

Explanation:

A. We know that 1microsecond= 10^-6s

So = 9.12*10^-6=9.12*10^-6s

B 1km= 1000m

So 3.42km= 3240m

C.1ms= 10^-3s

And 1cm= 10^-2m

So 44*10^-2m/10^-3s=440m/s

D. 80km/hr= 80*1000/3600= 22.2m/s

Because 1km= 1000m

1hr= 3600s

Given that the lines are parallel, what would be the value of angle "a" in the diagram found below?

Answers

Explanation:

Hey there!!

a = 40° { corresponding angles on a parallel lines are equal}.

As A and B are parallel, a and 40° are corresponding angles.

Hope it helps...

The value of angle "a" will be 40°

What is corresponding angle ?

The angles which are on the same side of one of two lines cut by a transversal and are on the same side of the transversal is called corresponding angles.

since , angle a and angle B = 40° (given) are on the same relative position at the intersection where a straight line crosses two others and since both the lines are parallel to each other hence ,both the angles are said to be corresponding angles .This implies both the angles must be equal .

angle a = 40°

learn more about corresponding angles

https://brainly.com/question/12521848?referrer=searchResults

#SPJ3

How do scientists use the evidence they gather?

Answers

Answer:

When conducting research, scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a hypothesis (often in the form of an if/then statement), the results aiming to support or contradict a theory.

26.0 g of copper pellets are removed from a 300∘C oven and immediately dropped into 120 mL of water at 21.0 ∘C in an insulated cup.What will the new water temperature be?

Answers

Answer:

The new water temperature is 26.4 °C

Explanation:

Given;

mass of copper, [tex]M_{cu}[/tex] = 26 g = 0.026 kg

temperature of copper, t = 300 °C

volume of water, V = 120 mL = 0.12 L

temperature of water, t = 21 °C

density of water, ρ = 1 kg/L

mass of water = density x volume

mass of water = (1 kg/L) x 0.12 L = 0.12 kg

heat lost by copper = heat gained by water

Both copper and water reach final temperature, T

Heat gained by water, [tex]Q_w[/tex] = [tex]m_w[/tex]cΔθ = [tex]m_w C(T - t)[/tex]

[tex]Q_w = m_w C(T - t)\\\\Q_w = 0.12*4200(T-21)\\\\Q_w = 504(T-21)[/tex]

Heat lost by copper is given by;

[tex]Q_{cu} = m_{cu}C(300-T)\\\\Q_{cu} = 0.026*385(300-T)\\\\Q_{cu} = 10.01(300 - T)[/tex]

[tex]Q_{cu} = Q_w[/tex]

504(T- 21) = 10.01(300 - T)

504 T - 10584 = 3003 - 10.01 T

504 T + 10.01 T= 3003 + 10584

514.01 T = 13587

T = (13587) / 514.01

T = 26.4 °C

Therefore, the new water temperature is 26.4 °C

The new water temperature using the given parameters is;

26.49°C

We are given;

Mass of copper; m_cu = 26 g = 0.026 kg

Temperature; T_cu = 300 °C

Volume of water; V = 120 mL = 0.12 L

Temperature of water, T_w = 21 °C

Density of water; ρ = 1 kg/L

Let us find the mass of water from the formula;

m_w = ρ × V

m_w = 1 × 0.12

m_w = 0.12 kg

Now, from the principle of conservation of energy, we can say that the total heat lost by a hot body is equal to the total heat gained by a cold body.

The hot body here is copper while the cold body is water. Thus;

Heat lost by copper = Heat gained by water

Formula for heat lost by copper is;

Q_cu = m_cu * c_cu * (T_f - T_cu)

Formula for heat gained by water is;

Q_w = m_w * c_w * (T_f - T_w)

Where;

T_f is final temperature reached by copper and water

c_cu is specific heat capacity of copper = 385 J/kg.°C

c_w is specific heat capacity of water = 4200 J/kg.°C

Thus;

Q_cu = 0.026 × 385 × (300 - T_f)

Q_cu = 3030 - 10.01T_f

similarly;

Q_w = 0.12 × 4200 × (T_f - 21)

Q_w = 504T_f - 10584

Thus;

3030 - 10.01T_f = 504T_f - 10584

3030 + 10584 = 504T_f + 10.01T_f

13614 = 514.01T_f

T_f = 13614/514.01

T_f = 26.49°C

Read more at; https://brainly.com/question/20709851

Give three examples of unbalanced forces in your everyday life. HELP FAST PLZ

Answers

1. Kicking a soccer ball
2.Playing tug of war
3.Bouncing a Ball

Answer:

1.    Kicking a soccer ball

2.      Playing tug of war  

3.         Bouncing a Ball

Explanation:

Part A. 13 in Express your answer to two significant figures and include the appropriate units. SubmitPrev Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B. 77 ft/s Express your answer to two significant figures and include the appropriate units ,, ? Value m/s

Answers

Answer:

Part A

[tex]x = 0.33 \ m[/tex]

Part B

[tex]y = 23.49 \ m/s[/tex]

Explanation:

From the question we are told to convert

    13 inches to meters

Now

     1 in   =   0.0254 \  m

      13 \  in  =  x  m

=>  [tex]x = \frac{13 * 0.0254 }{1}[/tex]

=>     [tex]x = 0.33 \ m[/tex]

For  part B  we are told to covert 77ft/s  to meters /srconds

   So  

         1 ft/s  =  0.305 \ m/s  

         77 ft/s  =  y

=>      [tex]y = \frac{77 * 0.305 }{1}[/tex]

=>     [tex]y = 23.49 \ m/s[/tex]

An object is moving in a negative direction with a negative acceleration, for example an object dropped out a window. What does it mean that both velocity and acceleration are negative?

Answers

Answer:

yes bc they are falling :]

Explanation:

.A cart rolling down an incline for 5.0 seconds has an acceleration of 1.6 m/s2. If the cart has a beginning speed of 2.0 m/s, and its final velocity of 10 m/s, what was the car's displacement?

Answers

Use the formula,

[tex]\Delta x=v_it+\dfrac12at^2[/tex]

where [tex]\Delta x[/tex] is the cart's displacement (from the origin), [tex]v_i[/tex] is its initial speed, [tex]a[/tex] is its acceleration, and [tex]t[/tex] is time.

[tex]\Delta x=\left(2.0\dfrac{\rm m}{\rm s}\right)(5.0\,\mathrm s)+\dfrac12\left(1.6\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)^2[/tex]

[tex]\implies\boxed{\Delta x=30\,\mathrm m}[/tex]

Alternatively, since acceleration is constant, we have

[tex]\dfrac{v_f+v_i}2=\dfrac{\Delta x}t[/tex]

That is, we have these two equivalent expressions for average velocity, where [tex]v_f[/tex] is the cart's final velocity. Solve for [tex]\Delta x[/tex]:

[tex]\dfrac{10\frac{\rm m}{\rm s}+2.0\frac{\rm m}{\rm s}}2=\dfrac{\Delta x}{5.0\,\mathrm s}[/tex]

[tex]\implies\boxed{\Delta x=30\,\mathrm m}[/tex]

The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of the pebble above the water surface after t seconds is given by y = 235 − 16t^2.

Required:
a. Find the average velocity (in ft/s) of the pebble for the time period beginning when t = 2 and lasting the following amount of time.

1. 0.1 sec:________
2. 0.05 sec:_______
3. 0.01 sec:_______

b. Estimate the instantaneous velocity (in ft/s) of the pebble after 3 seconds. ft/s.

Answers

Answer:

(a) 1, average velocity = -65.6 m/s

   2, average velocity = -64.8 m/s

   3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given  by;

[tex]y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}[/tex]

(1)

[tex]y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s[/tex]

(2)

[tex]y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s[/tex]

(3)

[tex]y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s[/tex]

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

(a)The average velocity for the 0.1 sec,0.05 sec,0.01 sec will be  -65.6 m/s, -64.8 m/s and -64.16 m/s respectively.

What is the average velocity?

The total displacement traveled by an object divided by the total time taken is the average velocity.

Average velocity is given by;

[tex]\rm y(t_2,t_1)=\frac{y(t_2)-y(t_1)}{t_2-t_1} \\\\[/tex]

The average velocity for case 1;

[tex]\rm y(2.1,2)=\frac{(235-16\times 2\times 1^2)-(235-16 \times 2^2)}{2.1-2} \\\\ \rm y(2.1,2)=\-65.6 \ m/sec[/tex]

The average velocity for case 2;

[tex]\rm y(2.015,2)=\frac{(235-16\times 2.05^2)-(235-16 \times 2^2)}{2.05-2} \\\\ \rm y(2.1,2)=\-64.8 \ m/sec[/tex]

The average velocity for case 3;

[tex]\rm y(2.01,2)=\frac{(235-16\times 2.01^2)-(235-16 \times 2^2)}{2.01-2} \\\\ \rm y(2.1,2)=\-64.16 \ m/sec[/tex]

Hence the average velocity for the 0.1 sec,0.05 sec,0.01 sec will be  -65.6 m/s, -64.8 m/s and -64.16 m/s respectively.

(b) The instantaneous velocity will be -96 m/s.

The given equation in the problem is;

[tex]\rm y = 235 - 16t^2[/tex]

The instantaneous velocity is given as;

[tex]v = \frac{dy}{dt} \\\\ \frac{dy}{dt} = -32t\\\\ t = 3 s\\\\ v = -32\times 3\\\\ v = -96 m/s[/tex]

Hence the instantaneous velocity will be -96 m/s.

To learn more about the average velocity refer to the link;

https://brainly.com/question/862972

Question 1

When you stand on a floor the electrons surround your shoes and the floor. What is the force that prevents you from falling through a floor?


a) atomic direction

b) potential energy

c) atomic speed

d) electrical repulsion

Answers

Answer:

d) electrical repulsion

Explanation:

When you stand on a floor, the two different bodies i.e your shoes and the floor on which you stand, are in a very close contact, the electrons that surround your shoes and that of the floor exert a repulsive force on each other, also known as Coulomb's force of repulsion or  electrical repulsive force.

This electrical repulsive force prevents you from falling through the floor.

The position of a particle is given by the function x = \left(2t^3 - 6t^2 + 12\right) m, where t is in s. Question:At what time is the acceleration zero? (with working out)

Answers

Answer:

t = 1sec

Explanation:

Given the position of a particle  expressed by the equation x = (2t^3 - 6t^2 + 12)m, where t is in seconds, the acceleration function can be gotten by taking the second derivative of the function with respect to t as shown;

a = d/dt(dx/dt)

First let us get dx/dt

dx/dt = 3(2)t³⁻¹-2(6)t²⁻¹+0

dx/dt = 6t²-12t

a = d/dt(dx/dt)

a = d/dx(6t²-12t)

a = 2(6)t²⁻¹-12t¹⁻¹

a = 12t - 12t⁰

a = 12t-12

If the acceleration is zero, then;

12t-12 = 0

add 12 to both sides

12t-12+12 = 0+12

12t = 12

t = 12/12

t = 1sec

Hence the time when acceleration is zero is 1sec

A man standing on the top of a hill and sees a flagpole he knows is 45 feet high. The angle of depression to the bottom of the pole is 12 degrees, and the angle of elevation to the top of the pole is 16 degrees. Find his distance from the pole

Answers

Answer:

160.44 feet

Explanation:

check the attachment for the diagram of the set up for proper clarification.

From the diagram, the man's distance from the pole is labelled AB.

To get AB =, we need to get side CB first which is equal to ED i.e ED = CB.

From ΔCDE, opposite side = 45 feet and the adjacent is ED.

USing TOA, according to trig function SOH, CAH, TOA;

tan 16° = opp/adj = BD/ED

tan 16° = 45/ED

ED = 45/tan 16°

ED = 156.93 feet

Since ED = CB, hence CB = 156.93 feet

From ΔABC, adj = CB and hypotenuse = AB. According to CAH;

cos 12° = adj/hyp = CB/AB

cos 12° =  156.93/AB

AB =  156.93/cos 12°

AB = 160.44 feet

Hence the man's distance from the pole is 160.44 feet

Other Questions
Meaning of De-peopled THIS IS TWO PARTS FOR A QUESTION, ANSWER BOTH PLEASE! Part A In A Cub Pilot, why does the narrator believe that it is so important for a steamboat pilot to have a good memory? Each boat that a pilot steers is bound to be quite different from others. All jobs that require great skill also require very keen memories. Memory is very closely related to judgment and courage. The rivers physical features are constantly changing and hard to keep straight. Part B Which statement from A Cub Pilot best supports the answer in Part A? One cannot easily realize what a tremendous thing it is to know every trivial detail of twelve hundred miles of river and know it with absolute exactness. To know the Old and New Testaments by heart . . . is no extravagant mass of knowledge, and no marvelous facility, compared to a pilots massed knowledge of the Mississippi. If you will take half of the signs in that long street, and change their places once a month, and still manage to know their new positions . . . you will understand what is required of a pilots peerless memory. By the time he has become a pilot, he cannot be unmanned by any danger a steamboat can get into; but one cannot quite say the same for judgment. If the optimal production lot size decreases, average inventory increases. A. TrueB. Fasle Which provider does not require a four-year degree?A. ObstetricianB. LPNC. OncologistD. Nurse practitioner What is the inverse of the function Who are the presidents that lost the popular vote, but won the presidency? How to find measurement of degree? Which one of these tribes is NOT a Nomadic Hunter-Gatherer tribe? (The kind to wander and not make a permanent home.)O KiowaO CoahuiltecansO ComancheO CaddoHurry "Prithvi Narayan Shah was an expert and far sighted politician and successful administrator." Explain. Why was the first draft of the Articles of Confederation revised?Question 10 options:It assured the independence of the states.It proposed a strong central government.It stated that the central government wouldn't control western lands.It proposed a limited function of the central government. can anyone write me all this in short?just to be shorter but all this, pleaseLiterature as a type of art was created in the process of work and was an integral part of the game and the song, that is. it had a syncretic form. Syncretism has survived in some arts to this day. That the permeation of two or more arts (syncretism) is present in these modern ones as well. times, can be shown by several examples. theatrical art is impossible to imagine without a literary work, acting, music that accompanies certain situations on the stage and marks the atmosphere, but also fine arts that provide solutions for the appearance of the stage. In the film, the permeation of more art is even more emphasized: literature, music, acting, architecture that evokes the time and space of the action. literature is closely related not only to theater, film and television, but also to music, painting and sculpture. Poetry, for example, is always about music, and in two ways. Music is, first, in the very being of poetry. It was sung with a lyre instrument, it always strived for rhythmic and melodic organization of the verse. Sometimes the melodic sound aspects are so emphasized that the song gets its own melody and becomes very famous - it starts to be sung. The connection between literature and music is becoming even more serious at the level of world classics. Many of their works served as librettos for operas: Schiller's, Byron's, Pushkin's, Shakespeare's works. There is nothing less than a connection between literature and painting. and in this relation there is a two-way relationship. Literature inspires the creation of works of art, but also works of art inspire the birth of exceptional poetic works. Paul Gustave Dora took motifs from the Bible as the starting point and inspiration for his famous artistic achievements. He translated almost the entire Bible into the language of painting. Her text inspired the great Michelangelo and many other artists in the world. In our literature, literary works are known that are inspired by paintings, frescoes, icons, statues. Each answer below contains an error. Select the example of the error known as a run-onsentence. (10 points)O They wanted popcorn. Got nachos instead.O Got nachos instead.O They wanted popcorn they got nachos instead.They wanted popcorn. Because they got nachos. A new furnace for your small factory will cost $45,000 and a year to install, will require ongoing maintenance expenditures of $1,400 a year. But it is far more fuel-efficient than your old furnace and will reduce your consumption of heating oil by 4,200 gallons per year. Heating oil this year will cost $2 a gallon; the price per gallon is expected to increase by $0.50 a year for the next 3 years and then to stabilize for the foreseeable future. The furnace will last for 20 years, at which point it will need to be replaced and will have no salvage value. The discount rate is 12%.a. What is the net present value of the investment in the furnace?b. What is the IRR? (Do not round intermediate calculations.c. What is the payback period? (Do not round intermediate calculations.d. What is the equivalent annual cost of the furnace? (Do not round intermediate calculations.e. What is the equivalent annual savings derived from the furnace?f. Compare the PV of the difference between the equivalent annual cost and savings to your answer to part (a). Are the two measures the same or is one larger? What do the stage directions in a play tell the reader?1. how long the play will be and how the plot is divided into sections2. who speaks each line of dialogue and in which order in a scene3. who will be appearing in each act of the play and who they are4. the setting, the characters' actions, and the characters' expressions what is the value of m (5m+100) There are 40 nickels in a roll. If you have 150 rolls of nickels, how many nickels do you have? Opportunity costs may be viewed only in terms of financial resources.a) trueb) false In the drawing above two rugby players start 41 meters apart at rest. Player 1 accelerates at 2.2 m/s^2 and player 2 accelerates at 1.7 m/s^2. How much time elapses before the players collide? which fund is Benzos currently invested in? Is if I were one of the adults, I would have looked both ways before crossing the road. Subjunctive or conditional